Two blocks, stacked one on top of the other, slide on a frictionless horizontal surface. The surface between the two blocks is rough, however, with a coefficient of static friction equal to 0.40. The top block has a mass of 2.9 kg, and the bottom block's mass is 5.8 kg. If a horizontal force F is applied to the bottom block, what is the maximum value F can have before the top block begins to slip?

Robert Nozick opines that individuals own themselves and hence have a right to own property.

The term utilitarianism refers to the philosophical ideology that in the use of commodities, the best options is that which maximizes utility or satisfaction derived from the commodity.

In the position of Robert Nozick, utilitarianism means that individuals own themselves and hence have a right to own property.

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Answer:

The motion of the object between 0 and 8 seconds, as represented by the graph above, can be broken down into four segments:

For the first 4 seconds, the object experiences an increased velocity. This means that the object is accelerating downwards due to the force of gravity. During this time, the velocity increases at a constant rate of 9.8 m/s^2.

Between 4 and 6 seconds, the object experiences a constant velocity. This means that the object continues to fall with a steady speed, without any further increase in its velocity.

Between 6 and 7 seconds, the object again experiences a constant velocity. This means that the object continues to fall with the same steady speed as before.

Finally, between 7 and 8 seconds, the object experiences a decreased velocity. This means that the object is decelerating, or slowing down, as it approaches the ground. This could be due to air resistance or other factors.

So, to summarize, the motion of the object between 0 and 8 seconds is characterized by an initial increase in velocity for 4 seconds, followed by two periods of constant velocity for 2 seconds and 1 second respectively, and finally a decrease in velocity for 1 second.

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For a 2-kg ball moving with a constant speed of 5 m/s in a horizontal circle whose radius,  the magnitude of the net force on the ball is 50 cm. is mathematically given as

F= 100 N

Generally, the equation for the Net force   is mathematically given as

F = m*r*w^2

Where

w = angular velocity

w= 5/r

w= 10 rad/s

Therefore

F = 2/0.5/10^2

F= 100 N

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Answer:

2 atoms of oxygen in carbon dioxide

Explanation:

Answer:

There are stars in our galaxy that appear to be over 15 billion years old.

Explanation:

Answer:

there are 2188 people at the game

Explanation:

Given the data in the question;

we know that decibel is defined as; dB = 10log(l/l₀)

so if one produces an intensity l₁, it results in 69.6 dB

69.6 = 10log(l₁/l₀) ---- equ1

also. if x number of people produces this intensity, it result to 103 dB

103 = 10log(xl₁/l₀)

103 = 10( log(l₁/l₀) + log(x) )

103 = 10log(l₁/l₀) + 10log(x) ----- equ2

input equation 1 into to equation 2

103 = 69.6 + 10log(x)

10log(x) = 103 - 69.6

10log(x) = 33.4

divide both side by 10

log(x) = 3.34

x = \(10^{3.34}\)

x = 2187.76 ≈ 2188

Therefore, there are 2188 people at the game

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Answer:

27%

Explanation:

15.999 divided by 58.32 = .27433128

Move the decimal place over 2 places.

27%

Make use of percentages. Given that the molecular mass of magnesium hydroxide (MOH.) is 58.32 amu and the atomic mass of an oxygen atom is 15.999 amu, oxygen accounts for 27% of this compound.

Chemical substances known as molecular compounds assume the shape of distinct molecules. Examples include common compounds like carbon dioxide (CO2) and water (H2O) (Figure 3.1.1 ).

These substances differ significantly from ionic substances like sodium chloride (NaCl). When metal atoms give up one or more of their electrons to non-metal atoms, ionic compounds are created. The cations and anions that result

Therefore,

58.32 / 15.999 (27.3%) =.27433128

Add two places to the decimal place.

27%

The molar mass, which is stated in g/mol, is defined as the mass of a specific material divided by the amount of a substance. In light of this, the molar mass is average. Amu, short for atomic mass units, is the unit used to quantify molecular mass.

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Answer:

Cl2 + Sb → SbCl3

Cl2 + Sb → SbCl5

Cl2 + Sb → SbCl

Cl2 + Sb → SbCl2

Cl2 + Sb → SbCl3 + SbCl5

Explanation: Hope it will help

To balance the chemical equation Sb + Cl₂ → SbCl₃ on further simplification The final balanced chemical equation is Sb + 3Cl₂ → SbCl₃.

Let's start by balancing the antimony (Sb) atoms:

On the left side, we have 1 Sb atom, and on the right side, we also have 1 Sb atom. The antimony is already balanced.

Next, let's balance the chlorine (Cl) atoms:

On the left side, we have 2 Cl atoms, and on the right side, we have 3 Cl atoms. To balance the chlorine, we need to multiply the Cl₂ on the left side by 3:

Sb + 3Cl₂ → SbCl₃

Now, the chlorine atoms are balanced.

The final balanced chemical equation is:

Sb + 3Cl₂ → SbCl₃

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Answer:

HBr- polar covalent

Cl2 - nonpolar covalent

H2O - polar covalent

Explanation:

Covalent bonds are chemical bonds that holds atoms of elements in such a way that electrons are shared between the atoms. However, based on the electronegativity differences between elements, compounds can either be polar covalent or nonpolar covalent.

Polar covalent bonds are formed when electrons are unevenly shared between two atoms based on difference in their electronegativities i.e. the more electronegative atom pulls more of the electrons. For example, in the case of HBr and H2O, Bromine and Oxygen atoms are more electronegative, hence, they pull more electrons making the electron sharing unequal, hence, a POLAR COVALENT BOND forms.

Non polar covalent bonds, contrarily, occurs when electrons are shared equally or evenly. This is so because the atoms of the elements involved have the same electronegativity. For example, Cl2 contains two atoms of Chlorine (Cl), which has the same electronegativity, hence, electrons between the two atoms are shared equally to form a NONPOLAR COVALENT BOND

HBr is polar covalent, Cl₂ - nonpolar covalent and H₂O is polar covalent in nature.

When atoms with differing electronegativities share electrons in a covalent link, the result is a polar covalent bond.

Consider the molecule of hydrogen chloride (HCl). In order to generate an inert gas electron configuration, each atom in HCl requires one extra electron.

Covalent bonds are chemical bonds that keep atoms of different elements together while sharing electrons.

Compounds can be polar covalent or nonpolar covalent depending on the electronegativity variations between components.

When electrons are unevenly divided between two atoms due to differences in their electronegativities, polar covalent connections are created.

The more electronegative atom draws more electrons. In the case of HBr and H2O, for example, the Bromine and Oxygen atoms are more electronegative,

Therefore they draw more electrons, causing the electron sharing to be uneven, resulting in the formation of a polar covalent bond.

Hence HBr is polar covalent, Cl₂ - nonpolar covalent and H₂O is polar covalent in nature.

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Answer:

a short note on exercise

Explanation:

exercise is good for the health

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Answer:

the correct answer is c

Explanation:

In this exercise we seek the momentum

          I = F t

this value is set because forces and time are given.

Now we can use the relationship between linear momentum and momentum

         I = p_f - p₀

         I = m v_f - m v₀

suppose that the two spheres depart with the same initial velocity

Let's analyze these results, the value of the impulse is the same, so the body of lower mass must acquire greater speed or momentum

consequently the lighter sphere acquires more final speed, but the change of momentum is the same in the two spheres

Consequently the correct answer is c

The velocity of the third piece 2/11. (13 j - 15i)

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Graham's law states that the rate of diffusion or effusion of two gases is inversely proportional to the square root of their molar masses

For diffusion:-

\(\\ \sf\longmapsto \dfrac{V_x}{V_y}=\sqrt{\dfrac{m_y}{m(x}}\)

For effusion

\(\\ \sf\longmapsto \dfrac{R_x}{R_y}=\sqrt{\dfrac{m_y}{m_x}}\)

A. The electric field is null at the point C; located in the middle of the

segment AB.

Electric field is the region of space where the influence of electric force is felt.

E = kq/r²

where;

E(+6μC) = (9 x 10⁹ x 6 x 10⁻⁶) / (0.5²)

E(+6μC) = +216,000

E(-6μC) = (9 x 10⁹ x 6 x 10⁻⁶) / (0.5²)

E(-6μC) = -216,000

E(net) = E(+6μC) + E(-6μC)

E(net) = 216,000 - 216,000 = 0

Thus, the electric field is null at the point C; located in the middle of the

segment AB.

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Answer:

Visible light intensity at the surface of the bulb (I) = 331 W/m²

Explanation:

Given:

Energy = 75 W

Radius = 6 /2 = 3 cm = 3 × 10⁻² m

Energy goes to visible light = 5% = 0.05

Find:

Visible light intensity at the surface of the bulb (I)

Computation:

Visible light intensity at the surface of the bulb (I) = P / 4A

Visible light intensity at the surface of the bulb (I) = (0.05)(75) / 4π(3 × 10⁻²)²

Visible light intensity at the surface of the bulb (I) = 3.75 / 4π(9 × 10⁻⁴)

Visible light intensity at the surface of the bulb (I) = 331 W/m²

Offspring get two alleles for each trait – one from each parent.

Answer: 0.50 m/s

Explanation: it’s on khan academy this was the correct answer

An energetic child runs forward and backward. Its motion is shown on the following graph of horizontal position x vs. time t.

What is the instantaneous speed of the child at t = 10 s?

Answer:

Answer: 0.50 m/s

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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The coefficient  of static  friction between the book and the coin is the tangent of the angle of inclination. Hence, the coefficient  is 6.4.

Friction is the resistive force acting on an object. Static friction is the opposing force acting on a stationary object. It is always negative. The coefficient of friction is the ratio of frictional force to the normal force.

Here, the angle of inclination  θ = 30°

The normal force acting in the x direction of the coin  = Fx = Mg Sinθ

normal fore from y direction is  = Fy = Mg cosθ

Now, frictional force Fs = μ Fx = Fy

then  μ cos θ  = sin θ.

Then, the  coefficient  of static  friction μ = sin θ/cos θ

μ = tan 30 = 6.4 .

Therefore, the  coefficient  of static  friction between the book and the coin is 6.4.

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Answer: True

Explanation:

Cardiopulmonary resuscitation (CPR) is a medical procedure involving repeated compression of a patient's chest in an attempt to restore the blood circulation and breathing of a person who has suffered cardiac arrest.

From the given stem plot of the heights of students in inches, the height of a student will be 51 inches, i.e., option C.

Each data value in a stem and leaf plot is divided into a “stem” (the first number of the digit) and a “leaf” (often the final digit).

The “leaf” values follow the “stem” values to the right (or left) in a list format.

Each “leaf” displays the individual scores within each group, while the “stem” is used to categorize the results.

The list of heights (in inches) of students from the following stem plot graph is as follows – 51, 53, 56, 57, 57, 58, 58, 60, 62, 67, 69, 72, 73

So, the height corresponding to a student from the given list is 51 inches. Therefore, the correct option is C, 51 inches.

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Answer:

Assumption: there is no object between this point charge and the observer.

Explanation:

The electric field of a point charge is inversely proportional to the square of the distance from that point charge.

Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:

\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).

Convert the magnitude of the point charge in this question to standard units:

\(q = 1\; \rm nC = 10^{-9}\; \rm C\).

Apply that equation to find the magnitude of the electric field due to this point charge:

\(r = 1\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 2\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 3\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).

The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.

Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.

Answer:

10 degrees

Explanation:

I took the test :D

Answer:

\(\omega '=-13.5rad/s\)

Explanation:

From the question we are told that:

Time \(t=4sec\)

Angular displacement \(\theta= 161 rad\)

Final Angular velocity  \(\omega = 100 rad / s\)

Let

Angular acceleration \(\alpha\)  

Generally the equation for Initial Angular velocity  \(\omega '\) is mathematically given by

\(-\omega '^2=2 \alpha \theta -\omega^2\)

\(\omega '^2= \alpha 328 +11236\)

Also,Initial Angular velocity  \(\omega '\) is mathematically given by

\(\omega '=\omega - \alpha t\)

Therefore substitution

\(-\omega '^2=2 \alpha \theta -\omega^2\)

\(\omega '=\omega - \alpha t\)

\((\omega - \alpha t)^2=2 \alpha \theta -\omega\)

\(-16\alpha^2+848\alpha+11236= \alpha 328 -11236\)

\(16\alpha^2-520\alpha=0\)

\(\alpha=29.875rads/s^2\)

Substitution in the 2nd equation for Initial Angular velocity  \(\omega '\)

\(\omega '=106-(29.875rads/s^2*4)\)

\(\omega '=-13.5rad/s\)

Answer:

There are three main cloud types.

The foundation consists of 10 major cloud types. In addition to cirrus, stratus, cumulus, and nimbus clouds, there are cirrostratus, cirrocumulus, altostratus, altocumulus, stratocumulus, nimbostratus, and cumulonimbus clouds. The following table places these cloud types into the four major cloud groups.

Explanation:

So false, depends what you have learned and your grade level ig

Answer:

it is double the temperature change of iron

Answer:

Whenever one body exerts a force on a second body, the first body experiences a force that is equal in magnitude and opposite in direction to the force that it exerts

Explanation:

Answer: According to Khan Academy "Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Explanation: This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. We sometimes refer to this law loosely as action-reaction, where the force exerted is the action and the force experienced as a consequence is the reaction.

We can readily see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool, as illustrated below.

A swimmer pushes on the wall with her feet, which causes the wall to push back on her feet due to Newton's third law."

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