TRUE/FALSEeach pigment has a characteristic rate of movement

Answer: A-: Mg BELONGS TO Group 2, B:- O belongs to Group 16 and C-: Fe belongs to Group 8

Explanation:

A -              Mg:

Electronic distribution: 1s² 2s² 2p⁶ 3s²

Group in the periodic table: Magnesium (Mg) belongs to Group 2 (or Group IIA), also known as the alkaline earth metals group.

B -         O:

Electronic distribution: 1s² 2s² 2p⁴

Group in the periodic table: Oxygen (O) belongs to Group 16 (or Group VIA), also known as the chalcogens.

C -      Fe:

Electronic distribution: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

Group in the periodic table: Iron (Fe) belongs to Group 8 (or Group VIIIB), also known as the transition metals.

Vegetable oil has a higher intermolecular force than acetone. This is due to the difference in the types of molecules present in each substance.

Acetone consists of molecules with only a single carbon-oxygen bond, while vegetable oil consists of molecules with multiple carbon-carbon and carbon-hydrogen bonds. The multiple bonds in vegetable oil create stronger intermolecular forces due to the increased number of electron-pair bonds between each molecule.

This is because more electrons are shared between molecules, creating a stronger attraction. The result is a greater intermolecular force, which is why vegetable oil has stronger intermolecular forces than acetone.

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correct question is :

what molecule has stronger intermolecular forces acetone or vegetable oil? and Why?

Answer:

Yes, because the water solvent is better

Explanation:

Hope this helps

Answer:

Rust is brittle and fragile, while iron is solid and malleable and oxygen is a gas in its natural state. Rust is orange in color while iron is silver-gray and oxygen is colorless.  

Explanation:

Physical properties are traits that can be observed. Physical traits include color, malleability, texture, odor, etc.

Answer:

Answer D

Explanation:

The water must reach 100 degrees Celsius in order for the water to start boiling. So the boiling point is an intensive property. Likewise, melting point is also an intensive property. Other examples of intensive properties include density , solubility, color, luster, freezing point and malleability.

The percent composition of nitrogen and hydrogen in the sample is approximately 4.696% and 95.304%. To find the percent composition of nitrogen and hydrogen in the sample, we first need to determine the mass of hydrogen in the sample.

We know that the mass of the sample is 125 g and the mass of nitrogen is 5.87 g. Therefore, the mass of hydrogen can be calculated by subtracting the mass of nitrogen from the total mass of the sample:

Mass of hydrogen = Total mass of sample - Mass of nitrogen

Mass of hydrogen = 125 g - 5.87 g

Mass of hydrogen = 119.13 g

Now we can calculate the percent composition of nitrogen and hydrogen:

Percent composition of nitrogen = (Mass of nitrogen / Total mass of sample) x 100%

Percent composition of nitrogen = (5.87 g / 125 g) x 100%

Percent composition of nitrogen = 4.696%

Percent composition of hydrogen = (Mass of hydrogen / Total mass of sample) x 100%

Percent composition of hydrogen = (119.13 g / 125 g) x 100%

Percent composition of hydrogen = 95.304%

Therefore, the percent composition of nitrogen and hydrogen in the sample is approximately 4.696% and 95.304%, respectively.

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Answer:

Big False

Explanation:

As the magnets get closer, the stronger the magnetic field. The farther away, the less strength the field exhibits.

Resonance is a phenomenon in which the delocalization of electrons within a molecule creates multiple resonance structures. This delocalization of electrons in aromatic rings results in a more stable system, reducing the overall energy of the molecule.

The stability of aromatic rings arises from the concept of resonance. Aromatic compounds possess a cyclic structure with a conjugated system of π-electrons. This arrangement allows for the delocalization of π-electrons over the entire ring, resulting in a distribution of electron density throughout the system.

In aromatic compounds, such as benzene, the π-electrons are not localized between specific carbon atoms but are instead spread out across the entire ring. This delocalization of electrons leads to the formation of multiple resonance structures, where the π-electrons can freely move within the ring.

The presence of resonance stabilizes the aromatic ring by distributing the electron density evenly, preventing the accumulation of charge in any one area. This results in a lower overall energy for the molecule, making aromatic compounds more stable compared to non-aromatic compounds.

The increased stability of aromatic rings contributes to their characteristic resistance to reactions, high boiling points, and low reactivity towards addition reactions. The concept of resonance plays a crucial role in explaining the enhanced stability observed in aromatic compounds.

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Answer:

molecule is a group of atoms bonded together representing the smallest fundamental unit of a chemical reaction

Answer:

Salt and water

Explanation:

The reaction of an acid and a base forming a salt and water.

The amount of heat is 288 kJ  needed to increase the temperature of 300g of water (specific heat 4.18J/g°C) from 27°C to 50°C

Heat is the transfer of kinetic energy from one medium to the object from another medium

Here given data is

Temperature = 27°C to 50°C

Specific heat =  4.18J/g°C

Mass = 300g

WE have to calculate the amount of heat =?

The formula is

the amount of heat

Q = mCΔT

Q = 300g × 4.18J/g°C × (27°C - 50°C)

Q =  300g × 4.18J/g°C × 23

Q = 288 kJ

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Answer: a, 1 b,1 c,0

Explanation:

Answer:

A= 1

B= 1

C= 0

Explanation:

Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

Substitute the values into the formula.

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

The units of Kelvin cancel, so we are left with the units of mL.

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

The volume of the balloon at 250 K is approximately 416.7 milliliters.

B, electrons in the outermost level of each atom :)

If there are 10800000000 collisions per second in a gas of molecular diameter 3.91E-10 m and molecular density 2.51E+25 molecules/mº, the relative speed of the molecules is approximately 481 m/s.

The formula to calculate the relative speed of molecules is given by : v = (8RT/πM)^(1/2) where

v is the relative speed

R is the universal gas constant

T is the temperature

M is the molecular weight

π is a constant equal to 3.14159.

Here, we can assume the temperature to be constant at room temperature (298 K) and use the given molecular diameter and molecular density to find the molecular weight of the gas.

Step-by-step solution :

Given data :

Molecular diameter (d) = 3.91 × 10^-10 m

Molecular density (ρ) = 2.51 × 10^25 molecules/m³

Number of collisions per second (n) = 10,800,000,000

Temperature (T) = 298 K

We can find the molecular weight (M) of the gas as follows : ρ = N/V,

where N is the Avogadro number and V is the volume of the gas.

Here, we can assume the volume of the gas to be 1 m³.

Molecular weight M = mass of one molecule/Avogadro number

Mass of one molecule = πd³ρ/6

Mass of one molecule = (3.14159) × (3.91 × 10^-10 m)³ × (2.51 × 10^25 molecules/m³) / 6 = 4.92 × 10^-26 kg

Avogadro number = 6.022 × 10²³ mol^-1

Molecular weight M = 4.92 × 10^-26 kg / 6.022 × 10²³ mol^-1 ≈ 8.17 × 10^-4 kg/mol

Now, we can substitute the known values into the formula to find the relative speed :

v = (8RT/πM)^(1/2) = [8 × 8.314 × 298 / (π × 8.17 × 10^-4)]^(1/2) ≈ 481 m/s

Therefore, the relative speed of the molecules is approximately 481 m/s.

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Answer:

42.2075 grams

Explanation:

Answer:

Molar Mass of Calcium Carbonate = 100g

given mass = 50g

Number of mole of Calcium Carbonate =50/100 = 0.5 mole

Molarity = mole per litre of volume

Molarity = 0.5 /0.25 = 2mole/litre

Explanation:

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Answer:

\(mass \: of \: solute = 50 g \\ volume \: of \: the \: solution = 250ml \\ molar \: mass \: of \: solute \: = 100 \frac{g}{mol} \\ molarity = \frac{mole}{volume} \\ = \frac{ \frac{50}{100} }{250 \times {10}^{ - 3} } \\ = \frac{.5 \times {10}^{3} }{250} \\ = \frac{500}{250} \\ = 2mol \\ thank \: you\)

Answer: A molecule of hydrochloric acid, for example, is composed of a hydrogen atom and a chlorine atom. When these molecules dissolve into water, they separate into a positively charged hydrogen ion and a negatively charged chlorine ion. ... Only some of the molecules of weak acids disassociate when added to water.

Explanation:

Answer:

0.14 M

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 35 mL

Molarity of stock solution (M₁) = 3 M

Volume of diluted solution (V₂) = 750 mL

Molarity of diluted solution (M₂) =?

The molarity (i.e concentration) of the diluted solution can be obtained as follow:

M₁V₁ = M₂V₂

3 × 35 = M₂ × 750

105 = M₂ × 750

Divide both side by 750

M₂ = 105 / 750

M₂ = 0.14 M

Therefore, the concentration of the diluted solution is 0.14 M

The specific heat of gases can be taken roughly as a constant for differences in the order of 100⁰ C from ambient. Variation is crucial and cannot be disregarded for temperatures of more than, let's say 500 ⁰C or 1000⁰C.

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The preferred fixative for a gouty tophus is buffered formalin.  

A gouty tophus is a deposit of uric acid crystals in the tissues, and buffered formalin is effective in preserving the tissue structure and preventing the loss of uric acid crystals during processing and staining. Bouin solution and B-5 solution are commonly used fixatives for histology, but they may not be optimal for preserving the integrity of a gouty tophus. Absolute alcohol is a dehydrating fixative and may not be suitable for preserving tissue structure in a gouty tophus.A gouty tophus is a buildup of uric acid crystals in the body's soft tissues and joints that results in swelling and discomfort. It is a defining characteristic of chronic gout, a kind of arthritis brought on by an excess of uric acid in the blood that causes needle-like crystals to accumulate in the joints and soft tissues.

These uric acid crystals can accumulate over time and develop into a tophus, which is a lump that can be felt beneath the skin. The body's different parts, including the fingers, hands, toes, feet, elbows, and ears, can all develop tophi.

Tophi is a symptom of severe gout that, if addressed, can lead to serious joint damage and deformity.

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Answer:

Industrial activity increases the emission of greenhouse gases in the atmosphere, especially carbon dioxide (CO2), and it negatively affects climate by increasing global warming.

Two actions to face the global warming:

1- To substitute the use of fossil fuels by alternative clean energy sources such as, for example, hydroelectric, geothermal, solar and wind energy resources.  

2- The government's policies decided to develop electric cars and to stimulate healthy habits such as walking instead of the use of conventional fossil-fueled transport modes.

Answer: B

Explanation:

Answer: \(1409.55\)

Remove the 0's from each decimal number

\(3.7500 ---> 3.75\\9.7100 ---> 9.71\)

Multiply

\(3.75*104=390\\9.71*105=1019.55\)

Add

\(930+1019.55=1409.55\)

The wavenumber of the R-branch line with J = 2 is 50.16 cm^(-1). The Morse potential-energy function describes the potential energy (V) of a diatomic molecule with parameters De (dissociation energy), Re (equilibrium bond length), and a (width parameter).

For the first question:

The wavenumber (ν) of the R-branch line originating from the rotational state with J = 2 can be calculated using the formula:

ν = 2B(J+1)

where B is the rotational constant.

Given that the rotational constant (B) of H81Br is 8.360 cm^(-1), we can substitute the values into the formula:

ν = 2 * 8.360 * (2+1)

ν = 2 * 8.360 * 3

ν = 50.16 cm^(-1)

So, the wavenumber of the R-branch line originating from the rotational state with J = 2 is 50.16 cm^(-1).

For the second question:

The Morse potential-energy function is given by VR(R) = De {1 - e^(-a(R-Re))}^2

- De is the dissociation energy, which represents the energy required to dissociate the molecule completely into its constituent atoms.

- Re is the equilibrium bond length, which represents the internuclear separation at which the potential energy is minimized.

- a is the "width" parameter, which determines the steepness of the potential energy curve near the equilibrium position.

In the sketch of the function, the potential energy (V) is plotted against the internuclear separation (R). At R = Re, the potential energy is at its minimum (De). As R deviates from Re, the potential energy increases, and the curve becomes steeper as determined by the value of a.

De, Re, and a are important parameters in the Morse potential-energy function as they describe the shape and behavior of the potential energy curve for a diatomic molecule. They provide insights into the stability, bond strength, and bonding characteristics of the molecule.

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Answer:

#2 is the answer

Bcuz 2 times 2 = 4

The pressure of a rigid plastic container after removing 6.41 g of propane at constant temperature is 554.4 torr.

The pressure of a gas in a container depends on its volume and number of moles of gas, as described by the ideal gas law:

PV = nRT

where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature (assumed constant).

So, if 6.41 g of propane is removed from the container, the number of moles of gas will decrease, and the pressure will decrease as well.

To calculate the new pressure, we need to calculate the number of moles of propane in the container both before and after the removal, and then use the ideal gas law to find the new pressure.

First, we calculate the number of moles of propane before the removal:

n = m/M

where m is the mass of propane (40.29g) and M is its molar mass (312.01 + 81.01 = 44.09 g/mol).

n = 40.29 g / 44.09 g/mol = 0.9107 mol

Next, we calculate the number of moles of propane after the removal:

n = 6.41 g / 44.09 g/mol = 0.1455 mol

Finally, we use the ideal gas law to find the new pressure:

P1V1 = n1RT

P2V2 = n2RT

V1/V2 = n1/n2

P2 = P1 (n1/n2)

P2 = 860.6 torr × (0.9107 mol / 0.1455 mol)

P2 = 554.4 torr

The pressure after 6.41 g of propane is removed will be 554.4 torr.

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The bowling ball pendulum didn’t hit Bill Nye in the face because the amount of kinetic energy can never be more than the amount of potential energy, some of the energy is transferred to heat. This statement is true.

The bowling ball pendulum did not hit Bill Nye in the face because potential energy will always be greater than kinetic energy. When a force (a push or a pull) acts on something over a long distance, this occurs.

For instance, if the object is positioned at a higher height, its kinetic energy will be higher. Potential energy is not transferable and varies with object mass, height, and distance.

Thus, The bowling ball pendulum didn’t hit Bill Nye in the face because the amount of kinetic energy can never be more than the amount of potential energy, some of the energy is transferred to heat.

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