True or False? A recursive method should always have at least one base case.
true

Answer:

1 35°

2 20°

3 50°

..............

The principle involved is the conservation of momentum, where the boat moves in the opposite direction to maintain total momentum zero.

The physics principle involved in the movement of the boat as the man jumps onto the jetty is the principle of conservation of momentum. According to this principle, the total momentum of an isolated system remains constant if no external forces act on it.

In this scenario, the boat and the man can be considered as an isolated system since there are no external forces acting on them. Initially, when the man is standing on the boat, the system is at rest, and the total momentum is zero.

When the man jumps off the boat and onto the jetty, he exerts a force on the boat in one direction. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. As the man pushes off the boat, the boat experiences an equal and opposite force that propels it in the opposite direction.

Due to the conservation of momentum, the momentum gained by the boat in one direction is equal to the momentum lost by the man in the opposite direction. As a result, the boat moves away from the jetty, exhibiting a backward motion.

This principle can be mathematically expressed as:

Initial momentum of the system = Final momentum of the system

Since the initial momentum is zero, the final momentum of the system (including the man and the boat) must also be zero. The momentum gained by the boat ensures that the total momentum of the system remains conserved.

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Answer:

Igneous rocks form beneath Earth's surface.

Explanation:

Igneous rocks form beneath the Earth's surface

If the force F applied to pull a crate up a smooth inclined plane is doubled, the acceleration a of the crate will also double.

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the force F is being applied to overcome the gravitational force pulling the crate down the inclined plane.

When F is doubled, the net force acting on the crate also doubles. Since the mass of the crate remains constant, the acceleration of the crate will increase proportionally. This means that the acceleration a will also double.

Therefore, if the force F is doubled, the acceleration a of the crate moving up the inclined plane will also double.

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Answer:

trueeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

The theory is true that psychosocial development emphasizes that development occurs by overcoming an emotional crisis.

The term "psychosocial development" refers to how a human's personality changes during childhood and adulthood, as well as how social skills are acquired. The eight phases of psychosocial development were first described by psychologist Erik Erikson in the 1950s. According to Erikson, each stage is marked by a "psychosocial crisis" that can either have a good or negative impact on a person's personality.

Erikson asserts that a person's personality and social abilities change over the course of eight stages that span the entirety of their life. A person encounters a psychosocial crisis—critical issues—at each level, which must be overcome.

The way a person handles each of these crises has an impact on their personality. If people respond favorably, they acquire virtue (moral behavior).

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Answer:

The heat from the water deforms the sides because it melts the plastic

An object is placed at a distance of 27.0 cm away from a thin convex lens with a focal length of 9.00 cm. The image is located at a distance of 6.75 cm from the lens and the image formed is real and inverted.  

To find the distance of the image formed by a convex lens, we can use the lens formula:
1/f = 1/u + 1/v
where f is the focal length of the lens, u is the object distance, and v is the image distance.
Given:
Object distance (u) = -27.0 cm (negative because it's on the same side as the object)
Focal length (f) = 9.00 cm
Plug in the values into the lens formula:
1/9 = 1/(-27) + 1/v
Now, let's solve for v:
1/v = 1/9 + 1/27
1/v = 3/27 + 1/27
1/v = 4/27
v = 27/4
The image distance (v) = 6.75 cm. The positive value of v indicates that the image is formed on the opposite side of the lens compared to the object.
Since the image is formed on the opposite side and has a positive image distance, it is a real and inverted image.

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Using the thin lens formula:

1/f = 1/d0 + 1/di

where f is the focal length of the lens, d0 is the object distance from the lens, and di is the image distance from the lens.

Plugging in the given values:

1/9 = 1/27 + 1/di

Simplifying the equation:

1/di = 1/9 - 1/27 = (3 - 1)/27 = 2/27

di = 27/2 = 13.5 cm

The image is formed 13.5 cm away from the lens.

To determine the type of image formed, we can use the following rules:

If di is positive, the image is real and located on the opposite side of the lens from the object.

If di is negative, the image is virtual and located on the same side of the lens as the object.

If di is infinite, the image is formed at infinity and is said to be a "point image."

If di is zero, the image is formed at the same location as the object and is said to be a "coincident image."

In this case, since di is positive, the image is real and located on the opposite side of the lens from the object.

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Answer:

Transverse

Explanation:

Just took quiz

Answer: A 3600 kg boat is moving with a speed of 2.4 m/s. A much smaller 100 kg jet ski has the same amount of kinetic energy. The is the speed of the jet ski is 14.4 m/s².

Explanation: To find the correct answer to the question given, we need to know more about the Kinetic energy.

                        \(KE=\frac{1}{2} mv^2\)

                        \(\frac{1}{2}m_1v_1^{2} =\frac{1}{2}m_2v_2^2\\ Thus, \\v_2^2=\frac{m_1v_1^{2}}{m_2} =207.36\\v_2^2=14.4 m/s^2\)

Thus, we can conclude that, the is the speed of the jet ski is 14.4 m/s².

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Answer:

Elastic potential energy

Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.

Explanation:

becuse

Answer:10

Explanation:

Answer:375N

Explanation:

pressure =15 pascal

Length =5 m

Area=length x length

Area=5 x 5

Area=25 m^2

Force=pressure x area

Force=15 x 25

Force=375N

Answer:

0.03 T

Explanation:

The magnetic field B at the center of a solenoid is given by B = μ₀Ni/L where

μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid = 5000 turns, i = current in solenoid = 5 A and L= length of solenoid. Since we are not given length of solenoid, let us assume it is 1 meter. So, L = 1 m

So, B = μ₀Ni/L

=  4π × 10⁻⁷ H/m × 5000 turns × 5 A/1m

= 4π × 10⁻⁷ H/m × 25000 A-turns/m

= 314159.27 × 10⁻⁷ T

= 0.031415927 T

≅ 0.03 T

Answer:

\(10 \: m.\)

Explanation:

\(his \: position \:is \: his \: distance \: from \: the \: \\ point \: of \: motion \: and \: is \: given \: by : \\ v = \frac{s}{t} \\ s = vt =2 \times 5 \\ s = 10 \: m.\)

The Weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.

Answer:

Work = Work out

Work in = 5 N * d     where d is the distance the handle travels

Work out = 50 N * 7 m = 350 Joules

d = 50 N * 7m / 5 N = 70 m

This is the distance traveled by the force of 5 N

A man lifts a bucket of water from a well that is 7 meters deep. The bucket and water together weigh 50 Newtons. He turns the crank handle with a force of 5 Newtons. The effort force is 70 Newtons.

If a force is applied for a machine to move or change the position of the object is known as Effort force.

The effort force formula can be described as,

Fe = Fl. dl / de

Fe is effort force (N, lb)

Fl is load force (N, lb) (note that weight is a force)

dl is distance from load force to fulcrum (m, ft)

de is distance from effort force to fulcrum (m, ft)

Here, the given data to find the effort force is,

Fl =50 Newtons

dl = 7 meters

de = 5 Newtons.

Substituting all the values, we get,

Fe = 350/5

Fe = 70 Newtons.

Thus, the effort force is 70 Newtons.

Hence, Option A is the correct answer.

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Answer:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

Explanation:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

The graph that correctly gives the variation of the electric field as a function of r is the third graph.

The electric field inside a conducting shell is zero. This is because the charges on the shell distribute themselves so that the electric field is zero everywhere inside the shell.

The electric field outside a conducting shell is radial and directed away from the center of the shell. The magnitude of the electric field is inversely proportional to the square of the distance from the center of the shell.

Therefore, the graph of the electric field as a function of r is a horizontal line at zero for r < a, a vertical line at r = a, and a decreasing curve for r > a.

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Option d is correct.

2 spring tides and 2 neap tides will be experienced by the tide-recording station in a given month.

Tides are the rise and fall in sea levels brought on by the combined effects of the Moon's (and the Sun's, to a much lesser extent) gravitational pulls, as well as by the Earth and Moon circling one another. The monthly tides on Earth are influenced by the gravitational pull of the moon and the sun together.

The solar tide adds to the lunar tide when the sun, moon, and Earth are aligned (during a new or full moon), resulting in extremely high tides and extremely low tides, both of which are known as spring tides.

The solar tide largely cancels out the lunar tide one week later when the sun and moon are at right angles to one another, resulting in the mild tides known as neap tides. Two sets of spring tides and two sets of neap tides take place twice each lunar month.

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The lunar phases are caused by the relative positions of the Earth, Moon, and Sun. The Moon orbits the Earth once every 29.5 days, and as it does so, we see different portions of the illuminated side of the Moon. These different portions of the Moon are called phases. There are eight primary phases of the Moon: New Moon, Waxing Crescent, First Quarter, Waxing Gibbous, Full Moon, Waning Gibbous, Third Quarter, and Waning Crescent.

An eclipse occurs when one celestial object moves into the shadow of another. There are two types of eclipses: solar and lunar. A solar eclipse occurs when the Moon passes between the Earth and the Sun, blocking the Sun's light and casting a shadow on the Earth. A lunar eclipse occurs when the Earth passes between the Sun and the Moon, casting a shadow on the Moon.

To explain these phenomena, teachers can use different methods such as diagrams, animations or models. For example, teachers can use a lamp to represent the Sun, a small ball to represent the Moon and a larger ball to represent the Earth. By moving the Moon around the Earth, the phases of the Moon can be demonstrated. To show eclipses, the Moon can be moved between the Earth and the Sun, or the Earth can be moved between the Sun and the Moon.

Using these methods can be an effective way of demonstrating the phases and eclipses to students. Teachers can also use animations and videos to help students visualize these events. It is important to note that these models and demonstrations are not perfect representations of the actual events, as they simplify the complex motions and distances involved in the interactions between celestial bodies.

Name of person taught: John

John said: "I learned a lot from the model that my teacher showed me. It was very helpful to see how the phases of the Moon and eclipses occur. The demonstration with the lamp and the balls really helped me understand the concepts. I also appreciated the videos that my teacher showed me, as they helped me see the events from different perspectives."

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Answer:FASTEST AND BEST ANSWER GETS BRAINLIEST AND THANKS!

Include a picture, video, or diagram of your model of lunar phases or eclipses.

Provide a description of how you made your model and how it demonstrates eclipses or lunar phases.

Include a one-paragraph reflection on the success of your model in explaining your event.

Include the name of the person you taught about your event and that person's description of what they learned from your model.

Explanation:

wawa wawa

The magnitude of the resultant displacement from the cave entrance is approximately 343.0667 m, and the direction is 30.0° south of east.

To find the resultant displacement from the cave entrance, we need to add up the individual displacements in both magnitude and direction.

1. The first displacement is 75.0 m north. Since it is a straight northward movement, the magnitude of this displacement is 75.0 m, and the direction is 0° (north is 0°).

2. The second displacement is 250 m east. Since it is a straight eastward movement, the magnitude of this displacement is 250 m, and the direction is 90° (east is 90°).

3. The third displacement is 108 m at an angle 30.0° north of east. To find the eastward and northward components of this displacement, we use trigonometry. The eastward component can be found by multiplying the magnitude (108 m) by the cosine of the angle (30.0°). The northward component can be found by multiplying the magnitude (108 m) by the sine of the angle (30.0°).

Eastward component: 108 m * cos(30.0°) = 93.5307 m
Northward component: 108 m * sin(30.0°) = 54.0 m

So, the eastward component is approximately 93.5307 m and the northward component is 54.0 m.

4. The fourth displacement is 166 m south. Since it is a straight southward movement, the magnitude of this displacement is 166 m, and the direction is 180° (south is 180°).

To find the resultant displacement, we add up the eastward and northward components calculated in step 3 and subtract the southward displacement.

Eastward component: 93.5307 m
Northward component: 54.0 m
Southward displacement: 166 m

To add the vectors, we add their magnitudes and subtract their directions:
Resultant magnitude = sqrt((93.5307 m)^2 + (54.0 m)^2 + (166 m)^2) = sqrt(87209.5636 + 2916 + 27556) = sqrt(117681.5636) = 343.0667 m

To find the direction of the resultant displacement, we can use inverse tangent (arctan) of the ratio of the northward component to the eastward component:

Resultant direction = arctan(54.0 m / 93.5307 m) = 30.0° north of east

Therefore, the magnitude of the resultant displacement from the cave entrance is approximately 343.0667 m, and the direction is 30.0° south of east.

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The ball reaches a maximum height of approximately 42.83 ft.  the ball lands at a horizontal distance of approximately 81.36 ft. he average value of f(x)= x³8 +9x on the interval is 10.5.

To determine the maximum height and horizontal distance traveled by the ball shot at an angle of 45 degrees with an initial velocity of 41 ft/sec and neglecting air resistance, we can use basic kinematic equations.

Maximum Height:

The maximum height reached by the ball can be calculated using the equation for vertical displacement:

y_max = (v₀² * sin²θ) / (2g),

where v₀ is the initial velocity, θ is the launch angle (45 degrees), and g is the acceleration due to gravity (32 ft/s²).

Plugging in the values, we get:

y_max = (41² * sin²45°) / (2 * 32) = 42.83 ft.

Therefore, the ball reaches a maximum height of approximately 42.83 ft.

Horizontal Distance:

The horizontal distance traveled by the ball can be calculated using the equation for horizontal displacement:

x = v₀ * cosθ * t,

where x is the horizontal distance and t is the time of flight.

Since the ball goes up and then comes back down, the total time of flight can be calculated as:

t_total = 2 * (v₀ * sinθ) / g.

Plugging in the values, we get:

t_total = 2 * (41 * sin45°) / 32 ≈ 2.88 s.

Using this total time, we can find the horizontal distance:

x = 41 * cos45° * 2.88 ≈ 81.36 ft.

Therefore, the ball lands at a horizontal distance of approximately 81.36 ft.

Moving on to the second question:

To find the position of a particle at time t = 14, given its acceleration, initial position, and initial velocity, we can use the equations of motion.

The position function s(t) can be obtained by integrating the acceleration function twice with respect to time. Since the given acceleration is a linear function, we have:

s(t) = (1/6)at³ + (1/2)v₀t² + s₀,

where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.

Plugging in the given values, we get:

s(14) = (1/6)(24)(14)³ + (1/2)(15)(14)² + 12 ≈ 546.67.

Therefore, the position of the particle at time t = 14 is approximately 546.67.

Lastly, for the average value of f(x) = x³ + 9x on the interval [1, 2], we can use the formula for the average value of a function on an interval:

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx,

where [a, b] represents the interval.

Plugging in the values, we have:

Average value = (1 / (2 - 1)) * ∫[1, 2] (x³ + 9x) dx.

Evaluating the integral, we get:

Average value = (1 / 1) * [(1/4)x⁴ + (9/2)x²] evaluated from 1 to 2,

Average value = (1/4)(2⁴ + 9(2²)) - (1/4)(1⁴ + 9(1²)),

Average value = (1/4)(16 + 36) - (1/4)(1 + 9),

Average value = (1/4)(52) - (1/4)(10),

Average value = 13 - 2.5,

Average value ≈ 10.5

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Answer:

I) 0.5

ii) 5

iii) T=1/f

f=1/T

=1/5

=0.2Hz

iv) v=frequency × amplitude

=0.2×5

=1

Answer:

C.

Explanation:

It's just C.

If the gravitational potential energy decreases, then the kinetic energy of the pendulum must increase. Therefore, option (C) is correct.

Gravitational potential energy is the energy acquired by an object in a gravitational field due to a change in its position. Gravitational potential energy is an energy that is related to gravity or gravitational force.

When a body of mass (m) is moved inside the gravitational influence of a source mass (M) without accelerating it. The work done is stored in the form of potential energy is known as gravitational potential energy.

The law of conservation of mechanical energy indicates that the mechanical energy of a pendulum remains constant when all the forces acting on it are conservative.

Therefore, if the gravitational potential energy of the pendulum decreases, the kinetic energy will increase. Therefore, option (c) is correct.

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Answer:

increase I think this is right answer ok

enlarges same as the size of a person. or you could say remains the same

Neptune:

Mercury:

The shape of Mercury's orbit is an ellipse.

The Sun is not at the center of Mercury's orbit because the orbit is not a perfect circle, and the gravitational pull of other planets affects the orbit of Mercury.

Mercury's motion in its orbit appears irregular because it moves faster when it is closer to the Sun and slower when it is farther away.

Earth:

The orbit of the Earth is also an ellipse.

Yes, the Sun is at the center of the Earth's orbit.

The motion of the Earth throughout its orbit is not at a constant speed. It moves faster when it is closer to the Sun (perihelion) and slower when it is farther away (aphelion).

Mars

The orbit of Mars is an ellipse.

Yes, the Sun is at the center of Mars's orbit.

Mars moves at varying speeds throughout its orbit, but it is generally faster when it is closer to the Sun.

Saturn:

The orbit of Saturn is an ellipse.

Yes, the Sun is at the center of Saturn's orbit.

Saturn moves at varying speeds throughout its orbit, but it is generally faster when it is closer to the Sun.

Comet:

The orbit of a comet is an ellipse.

Yes, the Sun is at the center of the comet's orbit.

The motion of the comet throughout its orbit is not at a constant speed. It moves faster when it is closer to the Sun (perihelion) and slower when it is farther away (aphelion). Additionally, the gravitational pull of other planets may affect the motion of the comet.

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A beam of blue light causes photoelectrons to be emitted from a photoemissive surface. An increase in the intensity of the blue light will cause an increase in the number of photoelectrons emitted. Therefore, an increase in the intensity of blue light will cause an increase in the light intensity.

What is light? Light is a type of electromagnetic radiation that travels in waves at a velocity of 299,792 kilometers per second (km/s) in a vacuum. It is a form of energy and, like all forms of energy, can be transferred. Light, like other electromagnetic waves, has both electric and magnetic fields that oscillate perpendicularly to one another at right angles.Light has a very important property, which is its intensity. The amount of light that passes through a given area or space per unit time is known as light intensity. It is the amount of light energy that falls on a unit area in a given time. The energy of light, like all energy, can be described in terms of photons.

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During the first 10 hours, the client should receive 120 milliliters of I.V. fluid per hour.

The client is to receive half of the total infusion of 2,400 ml over the first 10 hours from the physician. Therefore, the amount of I.V. fluid to be infused during the first 10 hours is,

2400 ml/2 = 1200 ml

To find the rate of infusion in ml/hour during the first 10 hours, we divide the amount of I.V. fluid to be infused (1200 ml) by the duration of infusion (10 hours),

1200 ml / 10 hours = 120 ml/hour

Therefore, the client should receive 120 ml/hour of I.V. fluid during the first 10 hours of the prescribed 24-hour infusion.

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Light phenomena can be better explained by a transverse wave model because light exhibits the characteristics of polarization, it is better described as a transverse wave, since only transverse waves exhibit polarization (option B).

Light is an electromagnetic wave that is made up of both electrical and magnetic fields oscillating perpendicular to each other. These waves travel in the form of transverse waves with an oscillation plane that is perpendicular to the direction of the wave's travel.

Light is always polarized, which means that the oscillations of its electric field are all in the same direction. The phenomenon of polarization can be explained in a transverse wave model, since only transverse waves can be polarized. The polarization of light is used in a variety of applications, including glare-reducing sunglasses, three-dimensional cinema, and some microscopes. Because light is an electromagnetic wave, it travels at the speed of light.

However, if light were a longitudinal wave, it would be unable to exhibit the polarization phenomenon, and therefore option D) Because light is an electromagnetic wave, it is better described as a longitudinal wave, since electromagnetic waves propagate at the speed of light is incorrect.

Option A) Because light can undergo refraction, the light is better described as a longitudinal wave, since only transverse waves are refracted and Option C) Because light can undergo reflection, the light is better described as a transverse wave, since only transverse waves are reflected by a surface are also incorrect.

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Answer:

Because of gravity

Explanation

The moon has 1.62m/s2

Answer:

the speed of light, the difference in frequency between the radio waves that receive back by the gun.

Explanation: