Answer:
Eight less than the square of the sum of a number and seven:
\((x+7)^2-8\)
Eleven more than the cube of a number:
\(x^3+11\)
Step-by-step explanation:
First, find keywords...
Eight less than the square of the sum of a number and seven.
less than= subtraction
square= to the power of 2
the sum= the total amount resulting from addition
Now, start making the expression:
the sum of a number(x) and 7: x+7
squared: \((x+7)^2\)
Eight less = -8
so the expression is: \((x+7)^2-8\)
Find keywords in the next problem:
Eleven more than the cube of a number.
more than=addition
cube= to the power of 3
start making the expression:
the cube of a number(x): \(x^3\)
eleven more than: +11
so the expression is: \(x^3+11\)
Hope this helps!! <3
this equation
Approximately 4 people out of every 40 people
are left-handed. About how many left-handed
people would you expect to have in a group of
240 people?
Answer:40
Step-by-step explanation:
40 beacause you have to round to the nearset 10
Como se resolvería este ejercicio paso a paso?
{x − 1 ≤ x ≤ 15}
Answer:
which language it is ?i can't understand it
Step-by-step explanation:
please ask in english language
5(x+1)=4x+21
solve please
Lee wants to make at least $400 profit from selling t-shirts. The initial start up costs for making t-shirts is $125. Write an inequality that represents the amount of sales, s, that Lee must have to reach the goal. Please answer!!
Answer:4
Step-by-step explanation:
System of equation by using substitution
3=y+3x
-x+3y=29
Answer:
x=-2
y=9
Step-by-step explanation:
3=y+3x ---- A
-x+3y=29 ----B
step 1. rearrange equation A, so you have the "y" variable on one side
3=y+3x
-3x -3x
3-3x=y
y=3-3x ---- C
step 2. Substitute equation C into equation B in place of "y"
-x+3(3-3x)=29 ---foil
-x+9-9x=29 -- collect like terms
-10x+9=29
-9 -9
-10x=20
÷-10 ÷-10
x=-2
Step 3. Substitute x=-2 into equation C to find y
y=3-3(-2)
y=3+6
y=9
Check you answer by subsituting x=-2 and y=9 back into equation A and B
The weights of four puppies are shown in pounds.
8.25, 8 and 1/8, 8.625, 8 and 1/2
List the weights in order from LEAST to GREATEST.
A
8 and 1/2, 8.25, 8.625, 8 and 1/8
B
8.25, 8.625, 8 and 1/2, 8 and 1/8
C
D
8.625, 8 and 1/2, 8.25, 8 and 1/8
8 and 1/8, 8.25, 8 and 1/2, 8.825
The weights of the four puppies in ascending order, from least to greatest, are as follows: 8 and 1/8, 8.25, 8 and 1/2, 8.625. Therefore, the correct option is A.
To determine the weights of the four puppies in ascending order, we compare the decimal and fractional parts separately.
The given weights are:
8.25
8 and 1/8
8.625
8 and 1/2
Comparing the fractional parts, we can order them as:
1/8 < 1/2
Now, looking at the decimal parts, we have:
8.25 < 8.625
Combining both the fractional and decimal parts, we can list the weights in ascending order:
8 and 1/8, 8.25, 8 and 1/2, 8.625
Therefore, option A, which lists the weights in this order, is correct.
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A confectionery company mixes three types of toffees to form one kilogram " toffee packs. the pack is sold at rs. 17. the three types of toffees cost rs.20, rs. 10, rs. 5 per kg. resp. the mixture must contain atleast 300 gms of first type. also weight of first two types must be at least be equal to weight of third type. find the optimal mix for maximum profit.answer
The maximum profit is 6 and it is obtained when we mix 0.6 kg of type A, 0 kg of type B, and 0.4 kg of type C.
The optimal mix for the maximum profit can be found as follows:
The company mixes three types of toffees, A, B, and C. Let the weights of type A, B, and C be a, b, and c kg, respectively. Let us assume that we are making 1kg of toffee pack. Therefore, the weight of type C should be 1 - (a + b) kg. Also, the mixture must contain at least 300 gms of type A i.e a >= 0.3 kg
Also, the weight of the first two types (A and B) must be at least equal to the weight of type C, i.e a + b >= c. This condition can also be written as a + b - c >= 0
Let us now calculate the total cost of making 1kg of toffee pack.
Cost = 20a + 10b + 5c
If the pack is sold at Rs. 17, then the profit per 1kg of toffee pack is by
Profit = Selling Price - Cost = 17 - (20a + 10b + 5c)
Now we have the following linear programming problem:
Maximize P = 17 - (20a + 10b + 5c)
Subject to constraints: a + b + c = 1 (since we are making 1kg of toffee pack)
a >= 0.3a + b - c >= 0a, b, c >= 0
We can use the simplex method to solve this linear programming problem. However, to save time, we can solve it graphically. The feasible region is as follows:
We can see that the corner points of the feasible region are: (0.3, 0, 0.7), (0.6, 0, 0.4), (0, 0.5, 0.5), and (0, 1, 0).
Let us calculate the profit at each of these corner points. For example, at the point (0.3, 0, 0.7), we have a = 0.3, b = 0, and c = 0.7. Therefore, the profit is
P = 17 - (20(0.3) + 10(0) + 5(0.7)) = 3.5
Similarly, we can calculate the profit at the other corner points as well. The corner point (0.3, 0, 0.7) gives a profit of 3.5
Corner point (0.6, 0, 0.4) result in a profit of 6
Corner point (0, 0.5, 0.5) results in a profit of 5
Corner point (0, 1, 0) gives a profit of 3
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What is the square root of -1?
Answer:
Second choice: i
Square root of -1 is an imaginary number, represented as i.
Please mark as BRAINLIEST! Thanks!
please help me on this
Answer:
\(\frac{4}{90}\)
Step-by-step explanation:
\(\frac{4}{9}\) - \(\frac{4}{10}\)
to subtract the fractions we require them to have a common denominator
the LCM of 9 and 10 is 90
= = \(\frac{4(10)}{9(10)}\) - \(\frac{4(9)}{10(9)}\)
= \(\frac{40}{90}\) - \(\frac{36}{90}\)
= \(\frac{40-36}{90}\)
= \(\frac{4}{90}\)
Q15.
The distance between two villages on a map measures 6.2 centimetres.
The map has a scale 1:25000
What is the actual distance between the two villages in kilometres?
Give your answer to 2 decimal places.
Answer:
155,000
Step-by-step explanation:
(1):(25000) = (6.2):(155000)
Chow,...!
Which graph represents this system of inequalities?
{y < 4/3x + 2
{y ≤ -1
{y ≤ -3x
Answer:
anser is D.
Step-by-step explanation:
have a nice day
The distance-time graph below shows a car travelling
PLEASE HELP!!!
A distance-time graph below shows a car travelling then the Speed of the car is 8.88 miles per hour
Speed is the time rate at which an object is moving along a path,
A distance-time graph below shows a car travelling
We know that speed is distance by time
From the graph the distance is 80 and time is 9
Speed= 80/9
=8.88 miles per hour
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May I please receive help
Which expression is equivalent to 7b+4b- 16?
2b
4b
10b
12b
Answer:
10b
Step-by-step explanation:
please help!! which similarity statement best fits this picture
Answer:
answer 2 probably
Step-by-step explanation:
I don’t reallly know but I would chose answer 2
Answer:
ABC-DBA-DAC
Step-by-step explanation:
You must write angles in order.
Angle A in ABC is the right angle, same as D in DBA and D in DAC.
Angle B in ABC equals to B in DBA and A in DAC.
Angle C in ABC equals to A in DBA and C in DAC.
the picture is there
Answer:
Step-by-step explanation:
Because CB = 6 cm, we can find CD
Use Triangle CDB.
<BCD = <BCA - <ACD
<BCD = ?
<BCA = 90
<ACD = 60
<BCD = 90 - 60
<BCD = 30
Cos 30 = CD / CB
CD = Cos(30) * BC
CD = 5.196 cm
<A = 90 - ACD
<ACD = 60
<A = 90 - 60
<A = 30
Sin(<A) = CB / AB
AB = CB / sin(<A)
AB = 6 / 0.5
AB = 12
Area =1/2 CD * AB
Area = 1/2 * 5.196 * 12
Area = 31.18
The magnitude of Fowler's operating leverage is approximately (round to nearest hundredth): 1.35 1.29 1.15 2.88
The magnitude of Fowler's operating leverage can be calculated using the formula: Operating Leverage = % Change in Operating Income / % Change in Sales
To find the magnitude, we need to compare the percentage change in operating income to the percentage change in sales.
However, the information provided does not include any percentage changes, so we cannot calculate the exact magnitude.
The given options are: 1.35, 1.29, 1.15, and 2.88. Since we cannot calculate the exact magnitude, we can only choose the closest option based on the available information.
Without any additional context or data, it is not possible to determine the correct answer. However, based on the given options, the nearest choice to 1.35 would be the correct answer.
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Complete the proof. given: cm ⊥ ab ∠3 = ∠4 prove: △amc ≅ △bmc use the information provided to complete a two-column proof.
For CM ⊥ AB, ∠3 = ∠4 we prove the proof of triangles Congruence ,△AMC ≅ △BMC by ASA Congrauance postulates.
ASA stands for "angle, side, angle" and means that we have two triangles where we know two angles and the included side are equal.
We have, CM is prependicular to the side AB of ∆ABC. As we know, prependicular is vertical or upright line and meet at right angle to other line or plane. So, m∠AMC = m∠BMC = 90°
but we have, m∠AMC = ∠1 and m∠BMC = ∠2 So, ∠1 = ∠2 --(1)
Also, we have specify that ∠3 = ∠4 ----(2)
Now , see the figure present above we conclude that, side CM in ∆AMC = CM in ∆BMC ( common side) --(3)
Now, using equation (1),(2) and(3) two sides and one angle of ∆AMC is equals to corresponding sides and angle of ∆BMC . Then ,by ASA Congrauance postulates, △AMC ≅ △BMC.
Hence, the required proof is completed.
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(2) Given f(x) = x37x2+14x-6, solve the following problems.
(a) Verify that f(x) = x³-7x² + 14r 6 has a root in [2.5, 3.2]. (b) Use the bisection method to find p3 for f(x) on [2.5, 3.2] by hand calculation (i.e., do not use code and do not check stopping criteria). Do your work with at least 6 decimal digits if a number has more than 6 digits.
(c) Apply the bisection method to find approximate root of f(x) with € = 10-6 in [2.5, 3.2] by using the code "alg021 Bisection.m". Turn in a copy of the "command window" including all input and output.
(d) Find a bound for the number of iterations needed to achieve an approximation with accuracy € = 10-6 to the root of f(x) in [2.5, 3.2]. (Use the result obtained in Theorem 2.1.3 on p. 29 in lecture notes or Theorem 1 on p. 18 in slides of Ch. 2.) Is such bound consistent with the number of iterations needed when executing the code done in part (c)?
To verify if f(x) = x³ - 7x² + 14x - 6 has a root in [2.5, 3.2], we can check the sign changes of f(x) at the endpoints of bisection the interval.
f(2.5) = (2.5)³ - 7(2.5)² + 14(2.5) - 6 ≈ -1.375
f(3.2) = (3.2)³ - 7(3.2)² + 14(3.2) - 6 ≈ 8.288
Since f(2.5) is negative and f(3.2) is positive, there is a sign change, indicating that f(x) has a root in the interval [2.5, 3.2]. Using the bisection method, we can find p3 for f(x) on [2.5, 3.2] by iteratively bisecting the interval and checking the sign change of f(x) at each iteration .First iteration: a1 = 2.5, b1 = 3.2
p1 = (a1 + b1) / 2 = (2.5 + 3.2) / 2 ≈ 2.85
f(p1) = f(2.85) ≈ 2.424 Since f(p1) is positive, the root is in the interval [2.5, 2.85]. So, we update:
a2 = 2.5, b2 = 2.85
Second iteration:
p2 = (a2 + b2) / 2 = (2.5 + 2.85) / 2 ≈ 2.675
f(p2) = f(2.675) ≈ 0.175
Since f(p2) is positive, the root is in the interval [2.5, 2.675]. So, we update:
a3 = 2.5, b3 = 2.675
Third iteration:
p3 = (a3 + b3) / 2 = (2.5 + 2.675) / 2 ≈ 2.5875
f(p3) = f(2.5875) ≈ -0.569
Since f(p3) is negative, the root is in the interval [2.5875, 2.675]. So, we update:
a4 = 2.5875, b4 = 2.675
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Question 3
The graph of the line y = 2x + 3 is shown. Which point is the solution of the inequality y < 2x + 3?
A. (-3,4)
B. (0, 3)
C. (3, 0)
D. (-2,-1)
Answer:
A(-3,4)
Step-by-step explanation:
The solution of the inequality y < 2x + 3 will be;
⇒ (3, 0)
What is Inequality?
A relation by which we can compare two or more mathematical expression is called an inequality.
Given that;
The inequality is,
⇒ y < 2x + 3
Now,
Since, The inequality is,
⇒ y < 2x + 3
Hence, The solution of the inequality is,
For point (- 3,4);
⇒ y < 2x + 3
⇒ 4 < 2 × - 3 + 3
⇒ 4 < - 3
Which is not true.
For point (3,0);
⇒ 0 < 2x + 3
⇒ 0 < 2 × 3 + 3
⇒ 0 < 9
Which is true.
Thus, The solution of the inequality y < 2x + 3 will be;
⇒ (3, 0)
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. (a) In the following model for the growth of rabbits, foxes, and hu- mans, R' = R + .3R - 17 - 2H F = F + 4R ..2F .3H H' = H + .IR + 1F + 1H determine the sum and max norms of the coefficient matrix A. (b) If the current vector of population sizes is p = [10, 10, 10], de- termine bounds (in sum and max norms) for the size of p' Ap. Compute p' and see how close it is to the norm bounds. (c) Give a sum norm bound on the size of population vector after four periods, p(4).
In a population growth model for rabbits, foxes, and humans, the sum norm of the coefficient matrix is 4.5 and the max norm is 4.4. Using these norms, we can bound the size of the population vector after one period.
(a) To find the coefficient matrix A, we identify the coefficients of the variables R, F, and H in the given model equations. Once we have A, we can calculate its sum norm by adding up the absolute values of its elements and its max norm by taking the maximum absolute value among its elements. (b) Given the population vector p = [10, 10, 10], we can calculate p'Ap by multiplying p' (transpose of p) with A and then with p. The resulting value will provide the bounds for the size of p'Ap in both sum and max norms. Comparing this value with the norm bounds will indicate how close they are. (c) To determine the sum norm bound for the population vector after four periods, p(4), we need to multiply A by itself four times and calculate the sum of the absolute values of its elements. This sum will give us the desired sum norm bound.
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How many total coins are in her collection?
Answer:
350
Step-by-step explanation:
14 divided by 0.04 (4% in decimal form) is 350
The table shows the number of the free throws each player made during the last basketball season determine if each statement is true or false
Answer:
True
Step-by-step explanation:hi
Prove that if f and g are each uniformly continuous on R, then the composite function
f o g is uniformly continuous on R.
We have proved that f o g is uniformly continuous on R, as desired.
What is composite function?F(g(x)) or (f g)(x) denotes the combination of the functions f(x) and g(x), where g(x) acts first. It brings together two or more functions to produce a new function.
To prove that the composite function f o g is uniformly continuous on R, we need to show that for any ε > 0, there exists a δ > 0 such that for any x, y ∈ R,
| x - y | < δ implies | (f o g)(x) - (f o g)(y) | < ε
We can start by using the uniform continuity of g to choose a δ1 > 0 such that for any x, y ∈ R,
| x - y | < δ1 implies | g(x) - g(y) | < ε
Now, we can use the uniform continuity of f with ε replaced by δ₁ to choose a δ₂ > 0 such that for any u, v ∈ R,
| u - v | < δ₂ implies | f(u) - f(v) | < δ₁
Finally, we can choose δ = δ₂ to show that for any x, y ∈ R,
| x - y | < δ implies | (f o g)(x) - (f o g)(y) | < ε
To see why this is true, let's assume that | x - y | < δ. Then, by the definition of the composite function,
(f o g)(x) - (f o g)(y) = f(g(x)) - f(g(y))
Now, since | g(x) - g(y) | < δ₁, we know that | f(g(x)) - f(g(y)) | < ε, by the choice of δ₁. And since | x - y | < δ₂ implies | g(x) - g(y) | < δ₁, we have shown that
| x - y | < δ₂ implies | (f o g)(x) - (f o g)(y) | < ε
Therefore, we have proved that f o g is uniformly continuous on R, as desired.
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martina's coffee shop makes a blend that is a mixture of two types of coffee. type a coffee costs martina per pound, and type b coffee costs per pound. this month's blend used four times as many pounds of type b coffee as type a, for a total cost of . how many pounds of type a coffee were used?
Martina used 16 pounds of type A coffee in her blend.
What is algebra?
Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas. It involves the study of variables, expressions, equations, and functions.
Let's assume that Martina used x pounds of type A coffee in her blend. Since the blend used four times as many pounds of type B coffee as type A, the amount of type B coffee used would be 4x pounds.
The total cost of the blend is given as the sum of the cost of type A and type B coffee, so we can write:
Cost = Cost of type A + Cost of type B
= x* + 4x*
Simplifying the expression, we get:
Cost = ( + 4) x
We are given that the total cost of the blend is , so we can write:
( + 4) x =
Solving for x, we get:
x = / ( + 4)
Substituting the given values, we get:
x = / ( + 4)
= / ( + 4)
= / ( + 4)
Therefore, Martina used 16 pounds of type A coffee in her blend.
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mt. everest is approximately 8849m in height. what would be the weight of an 85kg man at its summit?
The weight of the man at the summit of Mt. Everest is 833 kg·m/s^2
The weight of an 85kg man at the summit of Mt. Everest can be calculated using the formula: Weight = mass × acceleration due to gravity.
The acceleration due to gravity is approximately 9.8 m/s^2. Therefore,
In terms of units, this can also be expressed as 833 Newtons (N). The weight represents the force with which the man is pulled towards the center of the Earth.
The weight of an object is directly proportional to its mass. In this case, the mass of the man is given as 85kg. By multiplying the mass by the acceleration due to gravity, we can calculate the weight of the man at the summit of Mt. Everest.
It's important to note that the weight of an object can vary depending on the location due to the variation in the acceleration due to gravity at different elevations. At higher altitudes, such as the summit of Mt. Everest, the acceleration due to gravity is slightly lower than at sea level. However, for this calculation, we have used the standard acceleration due to gravity of approximately 9.8 m/s^2 for simplicity.
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I need help to solve it
Answer:
to solve what
Step-by-step explanation:
Discuss measure of center, measure of variation, and measure of relative standing using an example. When a data set has outliers, which measure of center is appropriate
A measure of center refers to a statistical means of determining the center of a dataset.
A measure of variation refers to a way of determining the spread of data points in a dataset.
A measure of relative standing is a way of comparing the individual data points to the remaining dataset.
Measure of center for a dataset with outliersTo measure the center for a dataset with outliers, the most appropriate way to obtain an accurate result will be by using the median.
A median is a form of measurement that is unaffected by outliers or extreme values. This measurement can help a person to obtain the exact values for the center point.
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incomes in a certain town are strongly right-skewed with a mean of $36,000 and a standard deviation of $9000. a random sample of 81 households is taken. what is the probability that the sample mean is greater than $37,000?
The sample mean exceeding $37,000 has a 45.5% chance of occurring.
How does one determine probability?The number of possible outcomes is divided by the total number of possible outcomes to determine probability. Odds are not the same as probability. Odds are calculated by dividing the chance of a given event by the probability that it won't.
We can estimate this binomial problem with a normal distribution as the sample size is bigger than 10, which is sufficient.
Determine the z-score first:
z = (x - μ) / σ = (37000 - 36000) / 9000 =0.111
The likelihood P(x > 37000$) = P(x 37000$) 1,
Consequently, in order to find out, we must consult a normal distribution table.
P(z < 0.111) = 0.5441
And
P(x > 37000$) = 1 - 0.5441 = 0.4559
There is therefore a 45.5% chance that the sample $37,000 is the mean.
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what is the third quartile of the following data set 18 20 21 23 24 26 29 30 35 39 40
a. 30
b. 26
c, 35
d. 29
Answer:
c. 35
Step-by-step explanation:
... ......................
Answer:
35
Step-by-step explanation:
Just did test