Tossing of a fair coin infinitely many times. Define (1, if head shows, X(t)= for nT

Answer:

Stephen gets £147

Step-by-step explanation:

Given

Let

\(S = Stephen; B = Bridget; R = Richard\)

So:

\(S + B + R = 490\)

\(R = 2S\)

\(S = 3B\)

Required

Find S

Make B the subject in \(S = 3B\)

\(B = \frac{S}{3}\)

Substitute: \(R = 2S\) and \(B = \frac{S}{3}\) in \(S + B + R = 490\)

\(S + \frac{S}{3} + 2S = 490\)

Take LCM

\(\frac{3S + S + 6S}{3}= 490\)

\(\frac{10S}{3}= 490\)

Solve for S

\(S = \frac{490 * 3}{10}\)

\(S = 49 * 3\)

\(S = 147\)

Stephen gets £147

Answer:

The second term becomes the reciprocal and then you multiply the first term by the second term

Answer:

A. second

Step-by-step explanation:

When dividing fractions, we always take the second term and flip that. In other words, we convert the second term into its reciprocal. Remember the phrase "flip the guy, and multiply!" Essentially, the "guy" just refers to the second term.

For example, if we have 1/3 ÷ 2/5, in order to solve this, we flip the second term, which is 2/5 so that it becomes 5/2 and then multiply:

1/3 ÷ 2/5 = 1/3 × 5/2 = 5/6

The answer is thus A.

~ an aesthetics lover

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 3 , thus

y = - 3x + c ← is the partial equation

To find c substitute (7, 8) into the partial equation

8 = - 21 + c ⇒ c = 8 + 21 = 29

y = - 3x + 29 → A

Graph 1:

(-infinity, 2) U [3, infinity)

Graph 2:

{-8, -2} U (3, 8]

Graph 3:

(-infinity, 3) U (3, infinity)

Graph 4:

(-8, -2) or {3}

Graph 5:

(-8, -2) U (-2, infinity)

Hope this helps!

The true statement about RR and AR measure is that all of the given options (A, B, C, and D) are accurate. Therefore, the correct answer is E, "NONE of the above."

A. Relative Risk (RR) is indeed a useful measure in etiologic studies of disease. It quantifies the association between a specific exposure and the risk of developing a particular disease or condition. By comparing the risk of disease between exposed and unexposed individuals, researchers can assess the strength of the relationship.

B. Attribute Risk (AR) is a measure of the proportion of disease risk that can be attributed to a specific exposure. It indicates the excess risk of disease associated with the exposure. AR is valuable in understanding the impact of a particular factor on the occurrence of a disease and can aid in making informed decisions regarding prevention and control strategies.

C. Attributable Risk (AR) has significant applications in clinical practice and public health. It helps identify modifiable risk factors and guides interventions to reduce the burden of disease. AR estimates can be used to allocate resources effectively, implement targeted prevention programs, and develop public health policies.

D. Relative Risk (RR) does indicate the strength of association between disease and exposure. It compares the risk of disease in exposed individuals to the risk in unexposed individuals. The magnitude of RR reflects the degree of association, with higher values indicating a stronger relationship between the exposure and the disease outcome.

Since all of the statements provided in the options (A, B, C, and D) are true, the correct answer is E, "NONE of the above."

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Changing the significance level cutoff to 10% would increase the likelihood of making a type I error, as the threshold for rejecting the null hypothesis is now higher.

The significance level cutoff (alpha) is the probability of rejecting the null hypothesis when it is true. In hypothesis testing, we aim to reject the null hypothesis if the p-value is less than the alpha level, which is typically set at 5%. This means that there is a 5% chance of rejecting the null hypothesis when it is true, also known as a type I error.

If the alpha level is increased to 10%, this means that the threshold for rejecting the null hypothesis is now higher, and it is easier to obtain significant results. This could lead to an increased likelihood of rejecting the null hypothesis, even if it is true, and making a type I error.

Therefore, changing the significance level cutoff to 10% would increase the likelihood of making a type I error, as the threshold for rejecting the null hypothesis is now higher.

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Answer: 168 people have to attend

Step-by-step explanation: 2520÷15= 168...just divide it to get it, if it help pls mark as brainliest ^-^, Thank you!

Answer:

See explanation.

Step-by-step explanation:

Since no choices were given I'll do my best to provide equivalent options.

Let's say all the terms with x in them were moved to the left side of the equation, and the rest were moved to the right.

-6+2x = 6x-9

2x-6x = -9+6

Simplifying these gives:

-4x = -3

4x = 3

Based on your question you should look for functions arranged similarly to

-4x = -3

The options for this question might include:

-4x = -3

4x = 3

2x - 6x = -9 + 6

-6 + 9 = 6x - 2x

3 = 4x

Answer:

3. 7680

4. 18630

Step-by-step explanation:

3. solution:

200 * 38.4 = 200 *38 + 200 * 0.4

= 7600 +80

=7680

4. solution:

900 * 20.7 = 900 *20 + 900 * 0.7

= 18000 + 630

= 18630

Answer:

a=8, b=8.14

Step-by-step explanation:

2^3 is the same as 2•2•2 which is 8.

If you cube root of 540 it is 8.14325 but I left it off with the second decimal which you could add or take off whichever you need.

Answer: 108 cm^2

Step-by-step explanation:

1. Find the area of all sides

From bottom to top:

6*3 = 18

4*3 = 12

4*3 = 12

6*4 = 24

6*4 = 24

6*3 = 18

2. Add up all areas of each side, resulting in 108

Answer:

true

Step-by-step explanation:

if you rewrite \(sec\left(\frac{\pi }{2}\:-x\right)\) with trigonometric identities:

\(sec\left(\frac{\pi }{2}\:-x\right)\)    \(=\frac{1}{\sin \left(x\right)}\)

\(\frac{1}{\sin \left(x\right)}\)  \(=\csc \left(x\right)\)

so, yes,  \(sec\left(\frac{\pi }{2}\:-x\right)\)  \(=\csc \left(x\right)\)

hope this helps!!

the answer is: Impossible to know given the information provided.

Based on the information provided, we can determine the probability of committing a Type II error (false negative) given that the results showed no significant difference in performance between the two conditions.

In hypothesis testing, a Type II error occurs when the null hypothesis is not rejected, even though it is false (i.e., there is a difference or effect). The probability of committing a Type II error is denoted by β (beta).

In this case, since the study showed no significant difference, it means that the null hypothesis was not rejected. Therefore, the probability of committing a Type II error is equal to the probability of not rejecting the null hypothesis when it is false. This is also known as the "power" of the test, which represents the ability to detect a true effect.

The information provided does not specify the power of the test or any other relevant details that would allow us to calculate the probability of a Type II error. Therefore, it is impossible to know the exact probability of committing a Type II error given the information provided.

Hence, the answer is: Impossible to know given the information provided.

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Complete question is below

The results of the study showed no significant difference in performance between the two conditions. Assuming that a non- directional test was used, and that alpha was set to .05, what is the probability that they committed a Type Il error?

2.5%

5%

95%

Impossible to know given the information provided

Answer:

h

Step-by-step explanation:

Angles π/2 and 3π/2 and for  0 and π are not in domain of secant function and cosecant function on given interval [0, 2).

The secant function is defined as the reciprocal of the cosine function, which means it is not defined when the cosine function is equal to zero.

In the interval [0, 2), the cosine function is equal to zero at π/2 and 3π/2.

The angles π/2 and 3π/2 are not in the domain of the secant function on the given interval [0, 2).

The cosecant function is defined as the reciprocal of the sine function, which means it is not defined when the sine function is equal to zero.

In the interval [0, 2), the sine function is equal to zero at 0 and π.

The angles 0 and π are not in the domain of the cosecant function on the given interval [0, 2).

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Since x²+y²+z²=0, we must have x=y=z=0, which satisfies the first three equations as well. However, this point does not satisfy the condition x+y+z=1, so it cannot be an extreme point. Therefore, there are no extreme points for the given function subject to the given conditions.

To find the extreme points of the function f(x,y,z)=xyz subject to the two conditions x+y+z=1 and x²+y²+z²=0, we need to use the method of Lagrange multipliers. Let λ be the Lagrange multiplier, then we have the following system of equations:

y*z = λ + 2λ*x
x*z = λ + 2λ*y
x*y = λ + 2λ*z
x + y + z = 1
x² + y² + z² = 0

We can solve this system by eliminating λ and getting the following equations:

x(y²+z²) = -2xyz
y(x²+z²) = -2xyz
z(x²+y²) = -2xyz
x + y + z = 1
x² + y² + z² = 0

Since x²+y²+z²=0, we must have x=y=z=0, which satisfies the first three equations as well. However, this point does not satisfy the condition x+y+z=1, so it cannot be an extreme point. Therefore, there are no extreme points for the given function subject to the given conditions.

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Complete Question:

Find the extreme points of\(f: R^{3} \rightarrow R\)

f (x, y, z) = xyz

subject to the two conditions

\(\begin {aligned}x+y+z & = 1 \\x^{2} +y^{2} +z^{2} & = 0\\\end {aligned}\)

Answer:

a=-3

Step-by-step explanation:

Answer: 0.0043

Step-by-step explanation:

4/932 = 0.004291845494 but if you round you get 0.0043

Hey there!

=> 4 ÷ 932

=> 4/932

=> 0.004291845493562

=> 0.0043

Therefore, 4÷932 is 0.004{3 dp}

Answer:

The slope is 30, and the y-intercept is 75.

Step-by-step explanation:

Use two points from the table, and find the equation of a line given two points.

Point 1: (1, 105)

Point 2: (3, 165)

y = mx + b

slope = m = (y_1 - y_1)/(x_2 - x_1)

m = (165 - 105)/(3 - 1) = 60/2 = 30

y = 30x + b

Use point (1, 105) for x and y.

105 = 30(1) + b

105 = 30 + b

b = 75

y = 30x + 75

The slope is 30, and the y-intercept is 75.

In the trash can, there are 648 bricks. when the measurements are 8 by 4 by 2 The right response is so (C).

This same total mass of a three-dimensional shape is referred to as its porous structure. A cuboid with six rectangular faces has a surface area equal to the sum of the areas of each face. The cuboid's length, width, and height can also be labeled, and indeed the surface area (SA) can indeed be calculated using the equation SA=2lw+2lh+2hw.

Based on this equation, surface area is equivalent to two times overall combination of width and length, two times its products of length and height, and two times the ratio of both height and width.

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Answer: The absolute value is -7 and is -7 far away from 0.

Step-by-step explanation:

Answer:

The probability that a letter at random is from V is 5/26 or 19.23%

Answer:

196 miles

Step-by-step explanation:

To find the distance that the bus drives, we can use the formula:

distance = rate x time

where rate is the average speed and time is the duration of the trip.

In this case, the average speed of the bus is 56 mph and the duration of the trip is 3 1/2 hours. However, it is easier to work with time in terms of a single unit, so let's convert 3 1/2 hours to 7/2 hours:

3 1/2 hours = (2 x 3) + 1/2 hours = 7/2 hours

Now we can plug in the values into the formula:

distance = rate x time

distance = 56 mph x 7/2 hours

We can simplify by multiplying 56 by 7 and then dividing by 2:

distance = (56 x 7) / 2 = 196 miles

Answer:

-31>v

Step-by-step explanation:

look above there

hope it helps

Hello.

The first step is to subtract 14 from both sides:

\(\mathrm{33-14 > \frac{v}{3} +14-14}\)

\(\mathrm{33-14 > \frac{v}{3} }\)

\(\mathrm{19 > \frac{v}{3} }\)

Now, multiply both sides by 3 in order to get rid of the fraction:

\(\mathrm{19*3 > \frac{v}{3} *3}\)

\(\mathrm{57 > v}\)

Since 57 is greater than v, v is less than 57:

\(\mathrm{v < 57}\)

Therefore, your answer is

\(\mathrm{v < 57}\)

I hope this helps.

Have a nice day.

\(\boxed{imperturbability}\)

Answer:

13/18

Step-by-step explanation:

The two negatives cancel out.

1/6 * 4 1/3 is 13/18, first turn 4 1/3 to 13/3.

Hope this helps

Answer:

MEAN = 14 (AS PER ESTIMATION)

MEDIAN = 17

Step-by-step explanation:

Mean=Sum of terms/No.of terms

Then,

→13+16+14+17+17+8+16/ = 101/7 = 14.428571....…

Median = The middle number

= 17

Answer:

  C. Exactly one solution

Step-by-step explanation:

You want to know the number of solutions of the system of equations shown in the graph.

A solution to a system of equations is the set of points on a graph where all of the equations are satisfied simultaneously. For a system of two linear equations, it will be the point(s) where the lines intersect.

Here, the lines intersect at one point, so there is exactly one solution.

Answer:

Surface Area = 560.41 cm2

Volume (if it's a sphere) = 9979.71 cm3 or around 10 liters

Step-by-step explanation:

1. The circunference formula is C = 2 * π * R

2. If C = 83.92cm, R is 13.356 cm --> R = C / (2π)

3. The surface area formula is A = π * R * R

4. For R = 13.356 cm, A = 560.41 cm2

5. Sphere volume is V = (4/3) * π * R * R

6. For R = 13.356 cm, V = 9,979.71 cm3

7. 1,000 cm3 = 1 liter, so V is aprox. 10 Liters

Based on the given information, the researcher should not reject the null hypothesis if using an alpha level of 0.05.

In hypothesis testing, the null hypothesis is typically assumed to be true until there is sufficient evidence to reject it. To determine whether to reject the null hypothesis, researchers often compare the calculated F-value from an ANOVA test with the critical F-value. The critical F-value is based on the significance level (alpha) chosen for the test. In this case, the given F-value is 3.47 with degrees of freedom (3, 32), indicating that there are three groups and a total of 32 observations. To make a decision, the researcher needs to compare the calculated F-value to the critical F-value. If the calculated F-value is greater than the critical F-value, the null hypothesis is rejected. However, if the calculated F-value is less than or equal to the critical F-value, the null hypothesis is not rejected. Since the critical F-value corresponding to alpha = 0.05 is not provided in the question, we cannot determine whether the null hypothesis should be rejected.

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