to the original buffer solution, what is the ph of the buffer solution after adding in 0.0300 mol of hbr (assume no volume change)?

Answer:

The law of conservation of mass states that in a closed system, the whole mass is conserved.

But the law of conservation of mass is not accurate sometimes in lab because in every chemical reaction, mass is converted into energy and not the whole mass can be conserved. Energy in chemical reaction can be created only by destroying the mass and not from any other means.

This is why,  sometimes in a lab it seems like the conservation of mass isn’t accurate.

Answer:

c = 0.0432moldm ^−3

Explanation:

The first step would be to find the molar ratio in the reaction. Now generally, one can simplify strong acid-strong base reaction by saying:

Acid+Base ->Salt+ Water

They give us the balanced equation of the reaction. To know the ratios of each relationship we must see the coefficients that accompany the molecules, these will be the terms of the ratio. As follows:

2C4H10

13O2

8CO2

10H2O

Now we will replace these values according to the requested relation and simplify to the minimum possible expression:

Answer:

both are eukaryotic

Explanation:

both has nucleus so

An isotope undergoing radioactive decay by emitting radiation that has a -1 charge is most likely an electron, which is commonly known as a beta particle. Beta particles have a negative charge and are emitted by the nucleus during beta decay.

Here, correct option is A.

Beta particles have a small mass compared to other types of particles, such as alpha particles and neutrons, but they do have mass. Therefore, option (b) "no mass" is incorrect.

Beta particles have a moderate penetrating power and can be stopped by a few millimeters of aluminum or a few centimeters of wood or other materials. Therefore, option (d) "high penetrating power" is also incorrect.

Thus, the correct answer to this question is option (a) "some shielding required," which means that some amount of material is required to shield against the beta radiation. Beta particles can penetrate some distance into materials, but they can be stopped by a layer of material of sufficient thickness.

Know more about Beta particles here

https://brainly.com/question/3580345#

#SPJ11

The ester can polymerize if both the acid and the alcohol have different functional groups.

A molecule is the smallest unit of any material that is composed of one or more elements and is capable of existing independently while maintaining all of the substance's physical and chemical properties. Further atom division occurs within molecules. For instance, the symbols for the oxygen atom and molecule are O and O2, respectively.

The smallest component of a substance which possesses both its chemical and physical characteristics. One or even more atoms make up molecules.

To know more about Molecules visit:

https://brainly.com/question/19556990

#SPJ4

The equilibrium air concentration of benzene in the given solution is 0.569 mol/L when 10 mL of a 100 ppm solution of benzene (dissolved in water) is placed in a 40 mL vial at 20 °C.

The question is asking us to find out the equilibrium air concentration when 10 mL of a 100 ppm solution of benzene (dissolved in water) is placed in a 40 mL vial at 20 °C.

We can use Henry's law to solve the problem. Henry's law states that the amount of a gas dissolved in a liquid is proportional to the partial pressure of the gas above the liquid. The proportionality constant is called Henry's law constant (kH). The equation for Henry's law is given as:

Cg = kH Pg

Where,Cg is the concentration of gas in solution, kH is the Henry's law constant, Pg is the partial pressure of the gas above the solution

To use Henry's law, we need to know the Henry's law constant for benzene at 20 °C. According to the given table, the Henry's law constant for benzene at 20 °C is 1.79 × 10⁴ Pa·L/mol.

Now, we can calculate the equilibrium air concentration as follows:

Let the equilibrium air concentration be Cg. The initial concentration of benzene in the vial is:

Cb = (100 ppm) (10 mL) / (40 mL) = 25 ppm

Since the vial is closed, the partial pressure of benzene in the vial is equal to its vapor pressure at 20 °C. According to the given table, the vapor pressure of benzene at 20 °C is 7.90 kPa. We can convert this pressure to Pa as follows:

7.90 kPa × (1,000 Pa / 1 kPa) = 7,900 Pa

Therefore, the partial pressure of benzene in the vial is 7,900 Pa.

Now, we can use Henry's law to find the equilibrium air concentration:

Cg = kH PgCg = (1.79 × 10⁴ Pa·L/mol) (7,900 Pa) / (8.31 J/mol·K × 293 K) Cg = 0.569 mol/L

Therefore, the equilibrium air concentration of benzene is 0.569 mol/L.

Learn more about Henry's Law visit:

brainly.com/question/30636760

#SPJ11

Answer:

5.52atm

Explanation:

Using the pressure law formula:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question, the following information were provided;

P1 = 4.72 atm

P2 = ?

T1 = -3.50°C = -3.50 + 273 = 269.5K

T2 = 42°C = 42 + 273 = 315K

Using P1/T1 = P2/T2

4.72/269.5 = P2/315

CROSS MULTIPLY

4.72 × 315 = 269.5 × P2

1,486.8 = 269.5P2

P2 = 1,486.8 ÷ 269.5

P2 = 5.52atm

Answer:

Raise

Explanation:

One calorie (cal) is the amount of heat needed to raise the temperature of one gram of water one degree Celsius.

The possible term states for an excited carbon atom with the electronic configuration 1s²2s²2p¹4f¹ are:

Among these possible term states, the term state likely to have the lowest energy is 2S+1S.

In atomic physics, term symbols are used to represent the total angular momentum, spin, and orbital angular momentum of an electron configuration. The term symbol is given by 2S+1L, where S is the total spin angular momentum and L is the total orbital angular momentum.

In this case, the electronic configuration of the excited carbon atom is 1s²2s²2p¹4f¹. The total spin angular momentum (S) is given by the sum of the individual electron spins, which in this case is 1/2 + 1/2 = 1. The total orbital angular momentum (L) is determined by the highest energy level electron, which is in the 2p orbital. Since the 2p orbital has an orbital angular momentum of 1, L = 1.

Therefore, the term symbol for the lowest energy state is 2S+1S, where S = 1 and L = 1. This corresponds to the singlet S state, which is the ground state of the carbon atom. The other term states have higher energy levels due to the presence of higher orbital angular momentum or higher spin.

To learn more about electronic configuration, here

https://brainly.com/question/29184975

#SPJ4

a. The formation of a precipitate indicates the presence of \(Ca^{2+}\) ; \(Mg^{2+}\)  ; \(Cu^{2+}\) ions.

b. If a soluble complex ions forms color then it is an indication of the presence of \(Cu^{2+}\) ions.

c. \(Na^{+}\),  \(NK^{+}\), \(Ca^{2+}\), and \(Cu^{2+}\)   ions gives characteristic color during flame test.

d. \(NH_4^{+}\) ions releases gas.

The Qual 1 cations that are confirmed present in a reference solution are \(Na^{+}\), \(K^{+}\),  \(NH_4^{+}\) ,  \(Ca^{2+}\) ; \(Mg^{2+}\)  and \(Cu^{2+}\). You can identify their presence using the following methods:

a. The formation of a precipitate: This can indicate the presence of cations like \(Ca^{2+}\) ; \(Mg^{2+}\)  and \(Cu^{2+}\)  when reacting with specific anions in a solution.

b. The color of a soluble complex ion: Some cations, like \(Cu^{2+}\), can form colored complex ions when they react with certain ligands.

c. The characteristic of a flame test: This method is used to identify cations like \(Na^{+}\) (yellow flame),  \(NK^{+}\) (purple flame), \(Ca^{2+}\) (orange-red flame), and \(Cu^{2+}\)  (green flame) based on their distinctive flame colors.

d. The evolution of gas: This can be used to confirm the presence of \(NH_4^{+}\)  cation, as it releases ammonia gas (\(NH_{3}\)) when heated with a strong base or when reacting with certain reagents.

To know more about Qual 1 cations:

https://brainly.com/question/24788203

#SPJ11

In a radioactive decay, the number of atoms decaying at any time is proportional to the number 'N' of such atoms present at that instant. This is the characteristic of the first order reactions. Here the remaining atoms is 125000.

The half life period of a radionuclide is defined as the time required for the decay of one half of the amount of the species. The half life period is a characteristic of a radionuclide. The half lives of different radionuclides vary from fractions of seconds to billions of years.

The substances whose nucleus is unstable are called as the radioactive substances. They achieve stability through changes in the nucleus.

Here original amount (N₀) = 500,000

Number of half-lives (n) = 2

N = N₀ / 2ⁿ

N = 500,000 / 4

N = 125000

So the number of remaining atoms are 125000.

To know more about half life period, visit;

https://brainly.com/question/27758377

#SPJ2

The molecular weight of the 6 ethoxycarbonyl 3 5 diphenyl 2 cyclohexenone is 318.4 g/mol.

The formula for the compound, 6 ethoxycarbonyl 3 5 diphenyl 2 cyclohexenone is :

The molecular formula = C₂₁H₁₈O₃

The molar mass of the C = 12 g/mol

The molar mass of the H = 1.008 g/mol

The molar mass of the O = 16 g/mol

The molecular weight of the compound is :

The molecular weight of C₂₁H₁₈O₃ = ( 21 × 12 + 18 × 1.008 + 3 × 16 )

The molecular weight of C₂₁H₁₈O₃ = 318.4 g/mol.

The molecular weight of C₂₁H₁₈O₃ is 318.4 g/mol.

To learn more about molecular weight here

https://brainly.com/question/20380323

#SPJ4

This question is incomplete, the complete question is :

6 ethoxycarbonyl 3 5 diphenyl 2 cyclohexenone. calculate the molecular weight of the given compound.

Answer:

They breathe

Explanation:

If you then increase the intensity of the 4.5 eV light, you will notice that the photons would come off at higher speeds.

Light intensity refers to the strength or amount of light produced by a specific lamp source.

Intensity of light measures of the wavelength-weighted power emitted by a light source.

Mathematically, the intensity of light source is given as;

I = P/A

where;

Increasing the light intensity (photon energy per second per unit area) increases the rate at which electrons leave the metal, and the electrons have more kinetic energy.

Thus,  if you then increase the intensity of the 4.5 eV light, you will notice that the photons would come off at higher speeds.

Learn more about intensity of light here: https://brainly.com/question/28145811

#SPJ1

Sweat evaporates quickly at low relative humidity, the amount of water vapor in the atmosphere, so it makes the body feel cooler. If the humidity is high that means there is a lot of water vapor in the air and thus the sweat cannot evaporate and forms pools on our skin making us feel uncomfortable.

Hope that helps!

The current process is not accurate enough to meet the target contaminant level of 380 ppm. Two modifications can be proposed to improve the process.

Firstly, increasing the average purity index of component 1 (P1) to 0.85 will reduce the contaminant level. Secondly, reducing the average temperature (T) to the minimum value of 120°C will also decrease the contaminant level. These modifications can be justified based on the given equations for the contaminant level and standard deviation.

In the equation for the contaminant level, a higher P1 value will result in a lower contaminant level. By increasing P1 from 0.80 to 0.85, the contaminant level will decrease. Similarly, by reducing the average temperature from its current value, the contaminant level can be further reduced.

To meet the customer's requirement of 99% of the products having a contaminant level between 350 and 410 ppm, additional modifications are needed. Firstly, decreasing the standard deviation of the purity index for both components (P1 and P2) will reduce the process variability and bring the contaminant levels closer to the target range.

Secondly, reducing the standard deviation of the temperature (T) will also help in reducing the variability of the contaminant levels. These modifications will improve the precision of the process and increase the likelihood of meeting the customer's requirement.

In conclusion, the current process is not accurate enough to meet the target contaminant level and the precision requirement of the customer. Modifying the average purity index of component 1, average temperature, and the standard deviations of purity indices and temperature can improve both accuracy and precision.

Learn more about contaminant

brainly.com/question/28328202

#SPJ11

Answer:

Elements

Explanation:

I just did this

5761.09L

According to the ideal gas equation

where:

• P is the ,pressure ,of the gas in atm

• V is the, volume ,in litres

• n is the mole of hydrogen gas

• R is the ,gas constant

• T is the, temperature ,in Kelvin

Given the following parameters

P = 1.05atm

R = 0.082057 L*atm/mol*K

T = 55 + 273 = 328K

Determine the mole of hydrogen

Determine the required volume

Hence the required volume of the gas is approximately 5761.09L

Answer:

4.70 grams of NH4Cl is needed to prepare 350 mL of a 0.25 M ammonium chloride solution.

We need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

To determine the mass of NH4Cl needed to prepare the solution, we us use the formula:

m=M x V x MM ... (i)

where,

m= mass in grams

M=molarity of solution

MM= molar mass of compound

V= volume in litres

The number of moles of NH4Cl needed can be calculated using:

  Moles = Molarity x Volume ...(ii)

  Moles = 0.25 mol/L x 0.350 L

  Moles = 0.0875 mol

Hence we can replace M x V with number of moles in equation i.

The molar mass of NH4Cl is :

  Molar mass of NH4Cl = (1 x 14.01 g/mol) + (4 x 1.01 g/mol) + (1 x 35.45 g/mol)

  Molar mass of NH4Cl = 53.49 g/mol

We have all the variables

Putting them in equation i.

Hence,

  Mass (g) = Moles x Molar mass

  Mass (g) = 0.0875 mol x 53.49 g/mol

  Mass (g) = 4.68 g

Therefore, you would need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

To learn more about Stoichiometry,

https://brainly.com/question/16060223

Answer: Atoms contain tiny, negatively charged electrons

Explanation: Thomson's experiments with cathode ray tubes helped him to discover the electron (which Dalton did not know about). Dalton thought that atoms were indivisible particles, and Thomson's discovery of the electron proved the existence of subatomic particles.

In the reaction of 2.92 g of carbon dioxide (CO2) with water (H2O) during photosynthesis, approximately 2.54 g of water is consumed.

To determine the mass of water consumed in the reaction, we need to use the stoichiometry of the balanced chemical equation for photosynthesis:

6 CO2 + 6 H2O → C6H12O6 + 6 O2

According to the balanced equation, 6 moles of carbon dioxide react with 6 moles of water to produce 1 mole of glucose and 6 moles of oxygen.

Calculate the molar mass of carbon dioxide (CO2):

Molar mass of CO2 = 12.01 g/mol + 2(16.00 g/mol) = 44.01 g/mol

Convert the given mass of carbon dioxide to moles:

Moles of CO2 = mass / molar mass = 2.92 g / 44.01 g/mol = 0.0663 mol

Determine the moles of water consumed using the mole ratio from the balanced equation:

Moles of H2O = (6 mol H2O / 6 mol CO2) * 0.0663 mol CO2 = 0.0663 mol H2O

Calculate the mass of water consumed:

Mass of H2O = moles of H2O * molar mass of H2O

= 0.0663 mol * 18.02 g/mol = 1.193 g

Rounding the answer to 3 significant digits, the mass of water consumed is approximately 2.54 g.

To learn more about molar click here:

brainly.com/question/31545539

#SPJ11

The mass of methane is required to produce 1.130 kg of carbon dioxide during combustion is 0.40 kg.

The balanced equation is given as :

CH₄   +   2O₂   ----->   CO₂  +  2H₂O

mass of carbon dioxide = 1.130 kg = 1130 g

moles of carbon dioxide = mass / molar mass

                                         = 1130 / 44

                                         = 25.6 mol

1 mole of carbon dioxide produce by 1 mole of methane

moles of methane = moles of carbon dioxide

mass of CH₄ = moles × molar mass

                     = 25.6 × 16

                    = 409.6 g = 0.40 kg

Thus, The mass of methane is required to produce 1.130 kg of carbon dioxide during combustion is 0.40 kg.

To lean more about moles here

https://brainly.com/question/15209553

#SPJ4

Magnesium or metal reacts with oxygen to produce magnesium oxide or metal oxide. The mass of oxygen needed to completely react with magnesium is 64 g.

Mass is the weight or the quantity of the substance that is estimated in grams and kilograms.

The balanced reaction can be given as:

\(\rm 2Mg + O_{2} \rightarrow 2MgO\)

From the balanced reaction, 2 moles of magnesium and 1 mole of oxygen are required to produce 2 moles of magnesium oxide.

If 2 mol Mg requires 1 mol oxygen then, 4 mol Mg will need 2 mol of oxygen.

The mass of oxygen can be calculated as:

\(\begin{aligned}\rm mass &=\rm molar\; mass \times moles \\\\&= 32 \times 2\\\\&= 64 \;\rm gm\end{aligned}\)

Therefore, option B. 64 gm of oxygen are required.

Learn more about mass and moles here:

https://brainly.com/question/26035415

No, the Law of Conservation of Mass does not hold true for this case because the mass of reactant is not equal to the mass of product.

What is Law of Conservation of Mass?

To learn more about Law of Conservation of Mass from the given link

https://brainly.com/question/15289631

#SPJ1

Sodium is an example of an alkali metal that reacts with water to form hydrogen gas and an alkaline solution.

Alkaline metals are lithium, sodium (Na), rubidium, potassium, cesium. They have low ionization energy and lose one electron very easy.

Atomic number of sodium is 11, it means that it has 11 protons and 11 electrons, so atom of sodium is neutral.

Electron configuration of the sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

Balanced chemical equation for the reaction of sodium with water:

2Na + 2H₂O → 2NaOH + H₂

NaOH is strong alkaline base.

H₂ is the hydrogen gas

More about sodium: brainly.com/question/25597694

#SPJ4

Answer: The water will taste sour.

Explanation:

Answer: D. The water will taste sour (Edmentum)

Explanation: