Tina pays $38.50 for 14 boxes of Girl scout cookies. What is the unit price?​

Sample mean in sample b to be less variable and more representative of  population mean than sample mean in sample a.

Standard error measures the variability of sample means around the population mean.

It decreases as sample size increases.

Using the formula for the standard error of the mean,

Calculate the standard errors for each sample,

Standard error of sample a

= s/√(n)

= 850/√(9)

= 283.33

Standard error of sample b

= s/√(n)

= 850/√(36)

= 141.67

Where s is the sample standard deviation

And n is the sample size.

The standard error of sample b is smaller than the standard error of sample a.

Sample mean in sample b is more likely to be closer to true population mean than sample mean in sample a.

Therefore, sample mean b is more surprising as larger sample size makes it more likely and accurately represents population mean.

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The pairwise comparisons that need to be made for this anova result will be b.3

In order to determine the number of pairwise comparisons needed for a one-way between-subjects ANOVA with three groups, we can use the formula:

N = (k * (k-1)) / 2

Where N represents the number of pairwise comparisons and k represents the number of groups. In this case, k = 3.

Plugging in the values:

N = (3 * (3-1)) / 2

N = (3 * 2) / 2

N = 6 / 2

N = 3

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Answer Put the equations in Standard Form.

Step-by-step explanation:

Step 1: Put the equations in Standard Form. Step 2: Determine which variable to eliminate. Step 3: Add or subtract the equations. Step 4: Plug back in to find the other variable.

Answer:

Addition

Step-by-step explanation:

if you just add 32 to both sides you'll get h=3+g

0.68 is the variable is normally distributed when standard deviation is r29. 44.

What is standard deviation in math?

μ = 146.21   σ = 23.44         x ~ n

P{ x < 160 } = ρ{ x - μ/σ < 160 - 146.21/29.44 }

                   = ρ{ z < 0.47 }

                    = 0.6808

                    ≈ 0.68

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Concave hexagon with two pairs of congruent sides is:

   /\

   /  \

  /    \

 /      \

/        \

/_____\

\        /

\      /

 \    /

  \  /

   \/

A hexagon is a six-sided polygon. A concave hexagon is a hexagon with at least one interior angle greater than 180 degrees.

We can start with a regular hexagon, which has six congruent sides and six interior angles of 120 degrees each.

We can then extend two opposite sides of the regular hexagon outwards to create two pairs of congruent sides. The extended sides should not be parallel to each other, but rather at an angle, so that the resulting hexagon is concave.

Here is an example of a concave hexagon with two pairs of congruent sides:

   /\

   /  \

  /    \

 /      \

/        \

/_____\

\        /

\      /

 \    /

  \  /

   \/

In this hexagon, sides AB and CD are congruent, and sides EF and GH are also congruent. However, the angles at vertices A and H are greater than 180 degrees, making this a concave hexagon.

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The true statements are 0.04b +  0.05s = 320, b + s = 7000, and Amber invests $3,000 in bonds and $4,000 in stocks. Then the correct options are A, C, and F.

Simple interest is the concept that is used in many companies such as banking, finance, automobile, and so on.

The formula for interest is written as,

I = (PRT)/100

Where P is the principal, R is the rate of interest, and T is the time.

Amber invests $7,000 in bonds and stocks.

Then the equation is given as,

b × 0.04 + s × 0.05 = $320

0.04b +  0.05s = 320         ...1

b + s = 7000                       ...2

From equations 1 and 2, then we have

0.04(7000 - s) + 0.05s = 320

0.01s = 40

s = 4000

Then the value of 'b' is given as,

4000 + b = 7000

b = 3000

The true statements are 0.04b +  0.05s = 320, b + s = 7000, and Amber invests $3,000 in bonds and $4,000 in stocks. Then the correct options are A, C, and F.

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The complete question is attached below.

Answer:

The answer is 15

Step-by-step explanation:

15*3=45-5=40

If the intended margin of error equals 4 less than with a 0.95 probability, the sample size is 126.

The \(\alpha\) level is calculated by subtracting 1 from the confidence interval and dividing by 2.

\(\alpha\) = (1 - 0.95) ÷ 2

\(\alpha\) = 0.025

Find z inside the Z-table because it has a p-value of 1 - \(\alpha\).

So, z = 1.96 with a p-value = 1 - 0.025 = 0.975.

Now, consider that margin of error M.

M = z × (σ ÷ √n)

The standard deviation is determined as the square root of variance.

σ = √522 = 22.84

With a 0.95 probability, the sample size that requires to be accepted if the expected margin of error is 4 or less is,

The sample size of at least n, in which n is encountered when M = 4. So,

M = z × (σ ÷ √n)

4 = 1.96 × (22.84 ÷ √n)

4√n = 1.96 × 22.84

√n = (1.96 × 22.84) ÷ 4

√n = 11.1916

n = (11.1916)²

n = 125.25 ≈ 126

A sample size of at minimum 126 people is required.

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Based on the diagram which shows the ratio of winning spaces to non-winning spaces, the missing values in the table are;

Total spaces = 5 + 6

= 11

Find total spaces if winning spaces is 10

5 : 6 = 10 : x

5/6 = 10/x

5×x = 10×6

5x = 60

x = 60/5

x = 12

Non-winning spaces = 12

Total spaces = 10 + 12

= 22

If total spaces = 33

Winning spaces ;

5 / 11 = x/33

5 × 33 = 11×x

165 = 11x

x = 165/11

x = 15

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Answer:

34/99

Step-by-step explanation:

To prove that \(\(8e^x\)\) is equal to the sum of its Maclaurin series, we can start by writing the Maclaurin series expansion for \(\(e^x\)\). The Maclaurin series for \(\(e^x\)\) is given by:

\(\[e^x = 1 + x + \frac{{x^2}}{{2!}} + \frac{{x^3}}{{3!}} + \frac{{x^4}}{{4!}} + \frac{{x^5}}{{5!}} + \ldots\]\)

Now, let's multiply each term of the Maclaurin series for \(\(e^x\)\) by 8:

\(\[8e^x = 8 + 8x + \frac{{8x^2}}{{2!}} + \frac{{8x^3}}{{3!}} + \frac{{8x^4}}{{4!}} + \frac{{8x^5}}{{5!}} + \ldots\]\)

Simplifying the expression, we have:

\(\[8e^x = 8 + 8x + 4x^2 + \frac{{8x^3}}{{3}} + \frac{{2x^4}}{{3}} + \frac{{8x^5}}{{5!}} + \ldots\]\)

We can see that each term in the expansion of \(\(8e^x\)\) matches the corresponding term in the Maclaurin series for \(\(e^x\).\) Thus, we can conclude that \(\(8e^x\)\) is indeed equal to the sum of its Maclaurin series.

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The hyperbolic equations can be represented as the second-order partial differential equations, which have two different characteristics in nature. These equations can be obtained by finding the solution for the Laplace equation with variable coefficients, which are used to describe the behavior of a certain physical system such as wave propagation, fluid flow, or heat transfer.

The second-order wave equation δu²/δt² = c² δ²u/δx² is a hyperbolic equation since it can be obtained by finding the solution of the Laplace equation with variable coefficients. The wave equation is a second-order partial differential equation that describes the behavior of waves. It has two different characteristics in nature, which are represented by two independent solutions.The first solution is a wave traveling to the right, while the second solution is a wave traveling to the left.

The equation is hyperbolic since the characteristics of the equation are hyperbolic curves that intersect at a point. This intersection point is known as the wavefront, which is the location where the wave is at its maximum amplitude.The wave equation has many applications in physics, engineering, and mathematics.

It is used to describe the behavior of electromagnetic waves, acoustic waves, seismic waves, and many other types of waves. The equation is also used in the study of fluid dynamics, heat transfer, and other fields of science and engineering. Overall, the second-order wave equation is a hyperbolic equation due to its characteristics, which are hyperbolic curves intersecting at a point.

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The price per pound of sand is 35 cents.

Given: 3 tons of sand cost $2,100.

To find the price per pound, we have to convert 3 tons to pounds.

We know that 1 ton is equal to 2000 pounds.

So, 3 tons = 3 x 2000 = 6000 pounds.

Now we can find the price per pound by dividing the total cost by the number of pounds.

We have,

Total Cost = $2,

100Number of Pounds = 6,000Price per Pound = ?

To find the price per pound, we will use the formula,

Cost per pound = Total cost / Number of pounds

Plugging in the given values,

Price per Pound = 2,100 / 6,000Price per Pound = 0.35 dollars.

Now we have to convert the price per pound into cents because 1 dollar equals 100 cents.

Therefore, the price per pound is 0.35 x 100 = 35 cents per pound.

Therefore, the price per pound of sand is 35 cents.

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Answer:

Well first he can only make 3 full pieces of wood. The correct way would be dividing 8 1/2 by 2 1/3 to get 51/14, simplifed would be 3 9/14 and sinc e only full pieces its 3.  The thing she did wrong was when dividing she converted the mixed fraction wrong when converting it into an improper. 8 1/2 converts to 17/2 not 16/2. 16/2 doesn’t make sense becuase if you covert it back you’d only get 8, theres still a 1/2 in there too, the 1/2 doesn’t just disappears. You gotta multiply the denominator by the whole number then ADD the numerator to it to make the numeratorfor the improper fraction.

Answer:

814 + 64 = 878

Step-by-step explanation:

just take the # from the previous day and add the 64.

When it says more, add when it says less, subtract.

The midpoint of a line segment is known as the midpoint in geometry. It is the centroid of the segment and of the ends, and it is equally distant from both of them. It cuts the section in half.

The midpoint is the point on the middle of the line that is equally distant from the two points if a line is drawn connecting the two points. The midpoint is the point B that lies halfway between any two points, let's say A and C.

The middle value in a group of numbers that are arranged numerically is the median. It is also referred to as the midpoint because it represents the centre of the data collection. You can expect that half of the values on your list will be lower and half will be higher than the median.

To prove x =1.25

H is midpoint of FG

2x +7=12x-5.5

2x+12.5 =12x

12.5 = 10x

1.25 =x

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The given statement is true which is x = 1.25.

To prove x =1.25

H is midpoint of FG

2x +7=12x-5.5

2x+12.5 =12x

12.5 = 10x

1.25 =x

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The expected number of boxes to be produced is given as 3,000 boxes. So, the correct answer is 0.3, indicating that the takt time in minutes is 0.3 minutes.

The production line operates for two eight-hour shifts each day, which means there are 16 hours of production time available. Since there are 60 minutes in an hour, the total available time in minutes would be 16 hours multiplied by 60 minutes, which equals 960 minutes.

The expected number of boxes to be produced is given as 3,000 boxes.

To calculate the takt time in minutes, we divide the total available time (960 minutes) by the expected number of boxes (3,000 boxes):

\(Takt time = Total available time / Expected number of boxes\)

\(Takt time = 960 / 3,000\)

By performing the calculation, we find that the takt time is approximately 0.32 minutes, which is equivalent to 0.3 minutes rounded to one decimal place.

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The simplified form of expression is \(14x^3y^{-5}(49x^5y^2)^{-\frac{1}{2}}=\frac{2x^{\frac{1}{2}}}{y^6}\)

The correct answer is an option (B)

We know that the rule of exponents.

\((ab)^m=a^mb^m\)

\((a^m)^n=a^{m\times n}\)

Consider an expression.

\(14x^3y^{-5}(49x^5y^2)^{-\frac{1}{2}}\)

We need to simplify this expression.

\(14x^3y^{-5}(49x^5y^2)^{-\frac{1}{2}}\)

We know that rule of exponent that \(a^{-m}=\frac{1}{a^m}\)

Using this rule we can write \((49x^5y^2)^{-\frac{1}{2}}\) as \(\frac{1}{(49x^5y^2)^{\frac{1}{2}}}\)

so, our expression becomes,

\(14x^3y^{-5}(49x^5y^2)^{-\frac{1}{2}}\\\\=\frac{14x^3y^{-5}}{(49x^5y^2)^{\frac{1}{2}}}\)

We know that any number to the 1/2 means the square root of that number.

\((49x^5y^2)^{\frac{1}{2}}=\sqrt{(49x^5y^2)}}\)

so, our expression becomes,

\(=\frac{14x^3y^{-5}}{\sqrt{(49x^5y^2)} } \\\\=\frac{14x^3y^{-5}}{7x^2\sqrt{x} ~ y}\)                                 ...............(simplify)

\(=\frac{14~x~ x^{-\frac{1}{2} }}{7~y~ y^5}\)

We know that the exponent rule while multiplying the two numbers if the base of exponents is same then we add the powers.

i.e., \(a^m\times a^n=a^{m+n}\)

So, our expression becomes,

\(=\frac{2x^{(1-\frac{1}{2})}}{y^6}\)                    

\(=\frac{2x^{\frac{1}{2}}}{y^6}\)

This is the simplified form of expression \(14x^3y^{-5}(49x^5y^2)^{-\frac{1}{2}}\)

Therefore, the correct answer is an option (B)

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Answer:

x=1

Step-by-step explanation:

4.3x + 0.7 = 5

Subtract .7 from each side.

4.3x + 0.7.-.7 = 5-.7

4.3x = 4.3

Divide each side by 4.3

4.3x /4.3 = 4.3/4.3

x =1

Answer:

Volume of the sphere = 902 cm³ (Approx.)

Step-by-step explanation:

Given:

Diameter of circle = 12 centimeter

Find:

Volume of the sphere

Computation:

Radius of circle = Diameter of circle / 2

Radius of circle = 12 / 2

Radius of circle = 6 centimeter

Volume of the sphere = [4/3]πr³

Volume of the sphere = [4/3][22/7][6]³

Volume of the sphere = [4/3][22/7][216]

Volume of the sphere = [1.33][3.14][216]

Volume of the sphere = [216][4.1762]

Volume of the sphere = 902.05

Volume of the sphere = 902 cm³ (Approx.)

Answer: they meet at \(20\) months. Bear: \(50x20=1000\) \(1000+500=1500\) Mrs. Killcrease: \(30x20=600\) \(900+600=1500\)

Step-by-step explanation:

There are two possible values for 'lll': 0 and 1.

When the principal quantum number of an electron is n = 2, there is only one value of l possible. The value of l is equal to 0 or 1 in this case. The values of l that an electron can have are given by the angular momentum quantum number. The value of l ranges from 0 to n - 1. When n = 2, there are only two possible values of l: 0 and 1. The different values of l correspond to different subshells, which are designated by the letters s, p, d, and f. When l = 0, the subshell is designated as s. When l = 1, the subshell is designated as p. Because there are only two values of l, there are only two subshells available for an electron in this situation. As a result, there are two distinct values of l possible for an electron with a principal quantum number of n = 2. One subshell is the 2s subshell, which corresponds to l = 0, and the other is the 2p subshell, which corresponds to l = 1. As a result, the answer to the question is 2.
There are 2 different values of 'lll' possible for an electron with the principal quantum number 'nnn'_1 = 2.

To express the answer as an integer: recall that the angular momentum quantum number 'lll' is related to the principal quantum number 'n' by the following rule:

0 ≤ l ≤ (n - 1)

For a given principal quantum number 'n', the value of 'l' can range from 0 to (n - 1). In this case, since n = 2:

0 ≤ l ≤ (2 - 1)

0 ≤ l ≤ 1

Thus, there are two possible values for 'lll': 0 and 1.

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The evolution of the function call (things '(11 -2 31)) is as follows:

(things '(11 -2 31)) -> (things '(-2 31)) -> (things '(31)) -> (things '()) -> '() the final result of the given call is '().

The given function is a recursive function called "things" that takes a list as input. It checks if the list is empty (null), and if so, it returns an empty list. Otherwise, it checks if the first element of the list (car x) is greater than 10. If it is, it adds 1 to the first element and recursively calls the "things" function on the rest of the list (cdr x). If the first element is not greater than 10, it subtracts 1 from the first element and recursively calls the "things" function on the rest of the list. The function then returns the result.

Now, let's see the evolution resulting from the call (things '(11 -2 31)):

1. (things '(11 -2 31))

  Since the list is not empty, we move to the next if statement.

  The first element (car x) is 11, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '(-2 31)).

2. (things '(-2 31))

  Again, the list is not empty.

  The first element (car x) is -2, which is not greater than 10, so we subtract 1 from it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '(31)).

3. (things '(31))

  The list is still not empty.

  The first element (car x) is 31, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '()).

4. (things '())

  The list is now empty, so the function returns an empty list.

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Answer: 1 x 10^3

Step-by-step explanation:

a. The diagram that represents this situation is given by the image shown at the end of the answer.

b. The height of the building is of: 33.4 feet.

The three trigonometric ratios are defined as follows:

As shown by the diagram given at the end of the answer, this situation is represented by a right triangle in which:

Then the height of the building is calculated as follows:

tan(24º) = x/75

x = 75 x tangent of 24 degrees

x = 33.4 feet. -> height of the building.

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Answer:

We know that the equation of the circle in standard form is equal to (x-h)² + (y-k)² = r² where (h,k) is the center of the circle and r is the radius of the circle.

We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :

1 - We first group terms with the same variable :

(x²+8x) + (y²+22y) + 37 = 0

2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)

(x²+8x) + (y²+22y) = - 37

3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process "completing the square".

x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²

y²+22y = (y²+22y+11²)-11² = (y+11)²-11²

4 - We plug the new values inside our equation :

(x+4)² - 4² + (y+22)² - 11² = -37

(x+4)² + (y+22)² = -37+4²+11²

(x+4)²+(y+22)² = 100

5 - We re-write in standard form :

(x-(-4)²)² + (y - (-22))² = 10²

And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)

Answer:

Subtract y from both sides of the equation.

x=8−y

2x+2y=16

Replace all occurrences of x with 8−y in each equation.

16=16

x=8−y

Remove any equations from the system that are always true.

x=8−y

Step-by-step explanation:

Answer:

324πcm³

Step-by-step explanation:

Volume=⅓πr²h

⅓*π*9²*12

=324πcm³

To find the volume of a triangular prism with a right angle, multiply the area of the base triangle by the height of the prism.

Start with a triangular prism that has a right angle. The base of the prism is a right-angled triangle.

Measure the lengths of the two perpendicular sides of the right-angled triangle, which are typically referred to as the base (b) and the height (h) of the triangle.

Calculate the area of the base triangle using the formula: Area = (1/2) * base * height.

Measure the height (H) of the prism, which is the perpendicular distance between the two parallel bases.

Multiply the area of the base triangle by the height of the prism to find the volume:

Volume = Base Area * Height = (1/2) * base * height * H.

If the dimensions are given in different units, make sure to convert them to the same unit before performing the calculations.

The volume of a triangular prism with a right angle can be found by multiplying the area of the base triangle by the height of the prism. Ensure that the base dimensions and the height are measured accurately and in the same unit.

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