The charge on capacitor C1 is 1000 μC, the charge on capacitor C2 is 1500 μC, and the charge on capacitor C3 is 3000 μC. When capacitors are connected in parallel, the voltage across each capacitor is the same.
So, the voltage across capacitor C1 is 500 V,
the voltage across capacitor C2 is 500 V,
the voltage across capacitor C3 is 500 V.
Calculating the charge on each capacitor
The charge on a capacitor is equal to the capacitance of the capacitor multiplied by the voltage across the capacitor. So,
the charge on capacitor C1 = 2.0 μF * 500 V = 1000 μC,
the charge on capacitor C2 = 3.0 μF * 500 V = 1500 μC,
the charge on capacitor C3 = 6.0 μF * 500 V = 3000 μC.
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Convert 149 °F into a °C, (b) Kelvin
Answer:
a.149 °F into °C
149 - 32 = 117
117 x 5 = 585
585 / 9 = 65
149 °F = 65 °C
b.149 °F into Kelvin
(149°F − 32) × 5/9 + 273.15 = 338.15K
What conditions are necessary for a lunar or solar eclipse?
Both lunar and solar eclipses occur due to the alignment of the Sun, Moon, and Earth, but the specific conditions required for each type of eclipse are slightly different.
For a lunar eclipse to occur, three conditions are necessary:
Full Moon: A lunar eclipse can only occur during a Full Moon when the Moon is on the opposite side of the Earth from the Sun.
Alignment: The Earth, Moon, and Sun must be aligned in a straight line, with the Earth in the middle.
Angle: The Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, for a lunar eclipse to occur, the Moon must pass through the Earth's shadow, which only happens when the alignment is just right.
For a solar eclipse to occur, three different conditions are necessary:
New Moon: A solar eclipse can only occur during a New Moon, when the Moon is between the Earth and the Sun.
Alignment: The Earth, Moon, and Sun must be aligned in a straight line, with the Moon in the middle.
Distance: The Moon's distance from the Earth can affect whether or not a solar eclipse occurs. The Moon's orbit around the Earth is elliptical, meaning that it is not always the same distance from Earth. If the Moon is too far away, it appears smaller in the sky and cannot completely block the Sun's disk, resulting in an annular solar eclipse. If the Moon is closer to the Earth, it appears larger and can fully block the Sun, resulting in a total solar eclipse.
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The Tesla Model S Electric vehicle can go from 0 to 60 mi/hr (26.8 m/s) in only 1.9 seconds! How far does it move from rest until it reaches 60 mi/hr? Round your answer to the nearest whole meter.
Answer:
The Tesla moves approx. 25 meters from rest before reaching 60 mi/hr
Explanation:
Given:
Initial velocity = 0 m/s
Final velocity = 26.8 m/s
Time = 1.9 seconds
Acceleration = change in velocity/time
\(a = \frac{26.8}{1.9}\)
The equation to find displacement (Δx) with given starting and final velocity, time, and acceleration is:
\(x = x_{0} + v_{0}t + \frac{1}{2} at^{2}\)
Starting position and initial velocity both equal 0, so
\(x = \frac{1}{2} at^{2}\)
\(x=\frac{1}{2} (\frac{26.8}{1.9})(1.9)^{2}\)
x = 25.46m
Rounded to the nearest whole number, x = 25m
What is the main problem with this model if it were going to be used to study the dimensions of the solar system?
A.The planets are represented in different sizes.
B.The planets are placed at the same distance from each other.
C.The planets are shown as having different shapes.
D.The planets are depicted in different colors.
Answer:
It's B
Explanation:
Have a good day
The planets are placed at the same distance from each other, therefore the correct answer is option B.
What is a solar system?It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.
Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.
The main problem with this model, if it were going to be used to study the dimensions of the solar system is that the planets are placed at the same distance from each other, but in our solar system all the revolving planets are at variable distances from the Sun and not equidistant from each other as shown in the figure.
Thus, the correct answer is option B.
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The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be
The exact same. gravity has no effect on mass.
Answer:
The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be LessExplanation:
Transistors are 3-terminal semiconductor devices which can act as switches or
amplifiers. An NP-transistor can be switched "ON" by:
A. Applying large negative potential to the collector and small positive potential to
the base
(B. Applying small positive potential to the collector and large positive potential to
the base.
(C. Applying small positive potential to the emitter and large negative potential to
the base. D. Applying small negative potential to the emitter and large negative potential to
the base.
In an NP-transistor (NPN transistor), the base is typically made of p-type semiconductor material, while the emitter and collector are made of n-type semiconductor material.
To switch the transistor "ON" and allow current to flow through it, the base-emitter junction needs to be forward-biased. This means that the base terminal should have a higher positive potential than the emitter terminal.
By applying a small positive potential to the base (relative to the emitter) and a large NP-transistor to the collector, the base-emitter junction is forward-biased, allowing current to flow through the transistor and switching it "ON".The correct answer is (A) Applying large negative potential to the collector and small positive potential to the base.
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how does temperature change as you go higher and higher in the stratosphere?
As you go higher and higher in the stratosphere, the temperature actually increases.
The stratosphere is a layer of Earth's atmosphere that lies above the troposphere and below the mesosphere. It starts at about 10 to 13 kilometers (6 to 8 miles) above the Earth's surface and extends up to approximately 50 kilometers (31 miles).
The stratosphere contains the ozone layer, which absorbs the sun's ultraviolet radiation and converts it into heat. The higher you go in the stratosphere, the more ozone there is, and the more heat is generated.
Therefore, the temperature increases as you go higher in the stratosphere. This is in contrast to the troposphere, the layer of the atmosphere closest to the Earth's surface, where the temperature decreases as you go higher.
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What does it mean when the wave
crests of a transverse wave move
closer together?
A. The amplitude is getting bigger.
B. The amplitude is getting smaller.
C. The wavelength is getting smaller.
D. The wavelength is getting bigger.
When the wave crests of a transverse wave move closer together it means the wavelength is getting smaller.
Briefing :The wavelength of a transverse wave is the distance from one peak to the next or from one dip to the next. The wavelength gets shorter as the crests or troughs get closer together. The wavelength increases as the distance between the crests and troughs increases.
How wavelength affect a transverse wave?One way to gauge the size of waves is by their wavelength. It is the separation of two matching waves' neighboring points. In a transverse wave, the medium's particles vibrate up and down perpendicular to the wave's path of propagation. A longitudinal wave's wavelength can be calculated as its length. A crest and a trough make up a transversal. The largest upward displacement is at the crest, while the maximum downward displacement is at the dip.
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Answer:
C. The wavelength is getting smaller.
Explanation:
Can someone help me
Answer:
C?
Explanation:
what is the horizontal distance dforearm between the elbow and the point where the weight of the forearm acts?
The horizontal distance (d_forearm) between the elbow and the point where the weight of the forearm acts is known as the center of mass of the forearm.
The center of mass represents the average position of the weight distribution of an object. In the case of the forearm, this point is important in biomechanics as it helps determine the force exerted by the muscles and the stability of the arm during various movements. To find the center of mass, one can use various techniques including mathematical calculations, experimental measurements, and observation of the anatomy.
Generally, the center of mass for the human forearm is located approximately at the midpoint between the elbow and the wrist, making it roughly 50% of the total length of the forearm. However, this location may vary among individuals due to differences in body proportions, muscle mass, and bone density. In summary, the horizontal distance (d_forearm) between the elbow and the point where the weight of the forearm acts is the center of mass, typically located around the midpoint of the forearm, this point plays a significant role in the biomechanics and stability of the arm during various movements.
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define simple machine
Answer:
simple machine, any of several devices with few or no moving parts that are used to modify motion and the magnitude of a force in order to perform work. ... The simple machines are the inclined plane, lever, wedge, wheel and axle, pulley, and screw.
How could you design a system of ramps to get a marble to land in a cup on an elevated platform
Answer
use a steep ramp
Explanation:
light of wavelength 79 nmnm ionizes a hydrogen atom that was originally in its ground state. what is the kinetic energy of the ejected electron?
The kinetic energy of the ejected electron due to ionization by 79 nm light is approximately 1.24 eV.
When a hydrogen atom is ionized by a 79 nm wavelength light, the electron is ejected from the ground state. The energy required for this process can be calculated using the formula E = hc/λ,
where,
E is energy,
h is Planck's constant,
c is the speed of light, and
λ is wavelength.
Substituting the given values, we get E = (6.626 x \(10^-^3^4\) J s x 3 x \(10^8\) m/s) / (79 x\(10^-^9\) m) = 2.49 x\(10^-^1^8\)J.
This energy corresponds to a kinetic energy of approximately 1.24 eV using the conversion factor 1 eV = 1.6 x \(10^-^1^9\) J.
Therefore, the kinetic energy of the ejected electron is approximately 1.24 eV.
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The ejected electron has a kinetic energy of 2.1 electron volts. The ionization of a hydrogen atom by a light of wavelength 79 nm is a process where the photon transfers enough energy to the electron of the hydrogen atom, causing it to escape from the atom.
The amount of energy required to ionize a hydrogen atom is called the ionization energy, and for hydrogen, it is 13.6 electron volts (eV).
To find the kinetic energy of the ejected electron, we need to use the conservation of energy principle, which states that the energy of the system before and after the interaction remains constant. In this case, the energy of the photon is equal to the sum of the ionization energy and the kinetic energy of the electron.
The energy of a photon of wavelength 79 nm can be calculated using the formula E=hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, we get E = 15.7 eV.
Therefore, the kinetic energy of the ejected electron can be calculated as the difference between the energy of the photon and the ionization energy of the hydrogen atom. So, KE = E - 13.6 eV = 2.1 eV. This means that the ejected electron has a kinetic energy of 2.1 electron volts.
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Please help me with a speech.The topic of my speech is Passion.
Answer:
Explanation:
Passion
For me, standing on the summit of Mt Everest was the result of following a process. The process of mountaineering. I love mountaineering. I am passionate about it. I love the months of planning for an expedition, the months of sweating and training to prepare my body physically. The meticulous preparation of my equipment. Most of all I love the huge mental challenge I have to overcome before each climb to confront my own fear. All these reasons are why I climb, they are why I climbed Mt Everest and that is why I continue to climb.
Passion is an enormously powerful force. It gives us the strength to get through hard times and setbacks. It gives us strength to overcome our fears, to ignore what other people think of us, to be disciplined and make sacrifices in pursuit of our dreams. Passionate people do not want to take shortcuts – they consider that ‘learning the process’ is an important part of the journey.
In mountaineering it’s easy to spot those who are not passionate about the process. They want to stand on top of the mountain but they are not really interested in the process of climbing the mountain. I feel for these people. Success without hard work is a hollow, empty feeling. They never last long in the sport.
Just as in life, successful mountaineers are the ones who are passionate. They are not there just to stand on the summit. Their passion gives them the energy to work the hardest, fight the longest, and in the words of Winston Churchill “never, never. never give-up”.
after landing on mars, you drop a marker from the door of your landing module and observe that it takes 2.1 s to fall to the ground. when you dropped the marker from the module door on earth, it took 1.3 s to hit the ground. part a what is the magnitude of the acceleration due to gravity near the surface of mars? express your answer with the appropriate units. activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type gm
The acceleration due to gravity near the surface of Mars is 3.7 m/s^2.
The time it takes for the marker to fall to the ground on Mars is longer than on Earth, indicating that the acceleration due to gravity is weaker on Mars.
Using the formula for acceleration due to gravity, g = (2d/t^2), where d is the distance traveled and t is the time it took to fall, we can calculate the magnitude of the acceleration due to gravity on Mars.
Plugging in the values, we get g = (2 x 1.52 m) / (2.12 s)^2 = 3.7 m/s^2.
Therefore, the acceleration due to gravity near the surface of Mars is 3.7 m/s^2, which is about 0.38 times the acceleration due to gravity on Earth.
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If force is made to act on a smaller area, then the pressure will be ______________
Which of the following three-step processes correctly describes how we use Cepheids as a tool to make cosmic distance measurements? In all cases, assume that the Cepheid's apparent brightness has been carefully measured through observations.PART F
Astronomers have measured the separations between other galaxies using studies of Cepheid variables. They contrast the apparent and intrinsic brightness of the Cepheid variable. The distance is determined by the discrepancy between the observed and real brightness.
Why do astronomers value Cepheid variable stars so highly?Pulsating stars known as cephoid variables periodically carry I brightness. They are crucial because the period-brightness law, which is a crucial tool for calculating distance, shows that the cepheid period's luminosity increases with length.
Cepheid variables pulse between dim and brilliant phases over a predictable period of time, often between one and 70 days, making them useful for mapping objects in space. The star's brightness may be calculated using the interval between its successive brightest spots.
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Ball X is dropped from a height of 1.25 meters above the ground. At the same time and from exactly the same height, Ball Y is shot out
horizontally at an initial velocity of 8.0 m/s. Air resistance is negligible and assume g =-10 m/s?
How far away from Ball X will Ball Y hit the ground?
Answer: The distance between Ball X and Ball Y is 4.0 meters
Explanation:
First we have to use the information we have from Ball Y to find time as well as it’s distance.
Ball Y’s Given:
Vx=8.0m/s
ax=0m/s^2
x=?
y=1.25m
ay=-10m/s^2
To find the time, use the equation t=(2y/g)^1/2.
t=(2(1.25)/10)^1/2
t=(2.5/10)^1/2
t=(0.25)^1/2
t=0.5s
Now we have to calculate how far away Ball Y fell from the base of the cliff. To do this use the equation x=(Vx)(t) and plug in the values.
x=(8.0m/s)(0.5s)
x=4.0m
Because Ball X is dropped from the cliff, we can conclude that the ball is 0meters away from the cliff. With this in mind, we can assume that the distance between Ball X and Ball Y is 4.0m.
Total Distance = Ball Y - Ball X
Total Distance = 4.0 m - 0 m
Total Distance = 4.0 m
is there a distinction between thermal energy and internal energy? which term do physicists prefer?
Physicists generally prefer to use the term internal energy, as it is a more general concept that encompasses various forms of energy such as thermal energy and potential energy.
Yes, there is a distinction between thermal energy and internal energy. Thermal energy is a type of internal energy that is associated with the temperature of an object or system, while internal energy is the total energy stored within a substance due to the motion, position, and interactions of its atoms and molecules. Internal energy is also easier to quantify and measure through thermodynamic equations and experiments. It's important to note that thermal energy and internal energy are closely related and often used interchangeably in everyday language. However, in scientific contexts, it's important to be precise with terminology to avoid confusion and ensure accurate communication.
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.Which limb electrode is used as a reference point and is not part of the ECG recording?
Left Leg (LL)
Right Arm(RA)
Left Arm (LA)
Right Leg(RL)
The Right Leg (RL) electrode is typically used as a reference point and is not part of the ECG recording.
The Right Leg (RL) electrodes serve as the ground or neutral electrode for the ECG machine, and its purpose is to provide a reference point for the other limb electrodes (RA, LA, LL) to ensure that the electrical signals from the heart are properly recorded and interpreted. The RL electrode is usually placed on the patient's right leg, just above the ankle, and is connected to the ground or neutral lead of the ECG machine.
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solved the question belowCalculate the force of attraction between a cation with a valence of +3 and an anion with a valence of -2, the centers of which are separated by a distance of 2.8 nm.
F= _____Calculate the force of attraction between a cation( eV , N , J , nm ) Choose One
the attraction between a +3 valence cation and a -2 valence anion, whose centres are separated by a distance of 2.8 nm. The attraction between two cations is 1.76×10⁻¹⁰ forces.
given,
number of cations,n₁=3
number of anions,n₂=2
center distance between cation and anion,r=2.8 nm=2.8×10⁻⁹m
write the equation force of attraction:
\(F=\dfrac{kq_1q_2}{r^2}.\)..............(1)
Here,K is coulombs constant ,K=9×10⁹ Nm²/C²,q =n×e ,e is electronic charge,e=1.60×10⁻¹⁹ coulombs. the attraction between a +3 valence cation.
calculate the value of cation charge q₁
q₁=n₁×e
q₁=3×1.60×10⁻¹⁹
calculate the value of cation charge q₂
q₂=n₂×e
q₂=2×1.60×10⁻¹⁹
substitute the values in equation 1
\(F=\frac{(9*10^{9})*(3*1.602*10^{-19}) *(2*1.602*10^{-19} )}{(2.8*10^{-9})^{2} }\)
F=1.76×10⁻¹⁰
The force of attraction between cation is 1.76×10⁻¹⁰.
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An object with a mass of 10kg accelerates 16 m/s2 when an unknown force is
applied to it. What is the amount of force?
160 N
9.8 m/s2
165.8 kg
1.6 N
Answer:
The answer is 160 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 10 × 16
We have the final answer as
160 NHope this helps you
A 6.8 kg cannon ball leaves a canon with a speed of 188 m/s. Find the average net force applied to the ball if the cannon muzzle is 4.2 m long.
i want the answer with the steps
Answer:
its not long dummy, its your imagination
Explanation:
Help uhh i need to know this answer
Answer:
Explanation:
2. 330.63 ft because v*t=d and 3.09*107=330.63
3. 4.2 because 10/2.4=4.1666
4. 130 miles because 2 hours times 65mph= 130
5. 62.3 seconds because 480000/7700=62.33766233
8. 60 meters, because 0.5 *120 (because 2 minutes converted to seconds is 120) is equal to 60.
a spotlight on the ground is shining on a wall away. if a woman 2m tall walks from the spotlight toward the building at a speed of 0.6 m/s how fast is the length of her shadow on the building decreasing when she is 2m from the building?
The answer is dy/dt is equal to -(20/7)(1/14)(0.6) = -0.12245 m/s.
The negative sign shows that the rate is falling as y gets shorter
.Woman Height/ Distance Light To Woman equals
Shadow Height/Distance Light To Wall.
explanation?
Think of a huge triangle with the origin as the spotlight, a base of 20, and the height of the shadow on the wall as y. Inside the larger triangle, a comparable triangle that is x meters from the spotlight and 2 meters
tall—the woman's height—can be seen.
Woman Height/ Distance Light To Woman equals
Shadow Height/Distance Light To Wall.
The shadow height is y. Let x be the distance from the woman to the light.
xy = 40 or y/20 = 2/x
Take both sides' derivative:
XDY + YDX = 0 based on the product rule.
Solve for the desired result, dy/dy:
dy/dt = -(y/x)dx/dt, where dx/dt = 0.6 m/s.
The woman is 20 - 6 meters from the light when she is 6 meters from the wall, which is 14 meters, or x.
Keep in mind that y/20 = 2/x = 2/14 --> y = 40/14 = 20/7 from the related triangles.
So, dy/dt is equal to -(20/7)(1/14)(0.6) = -0.12245 m/s.
The negative sign shows that the rate is falling as y gets shorter.
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what does the i-v characteristic plotted by the dc sweep illustrate about diodes?
The i-v characteristic plotted by the dc sweep illustrates the relationship between the current flowing through a diode and the voltage across it.
This graph shows that when the voltage across the diode is below a certain threshold voltage, the diode has very low current flow.
However, once the voltage across the diode reaches this threshold voltage, the current flow through the diode increases exponentially. This is because a diode is a type of semiconductor that allows current to flow in one direction only.
The i-v characteristic shows that when a diode is forward-biased (i.e., when the voltage across it is greater than the threshold voltage), it allows a large amount of current to flow through it. Conversely, when the diode is reverse-biased (i.e., when the voltage across it is less than the threshold voltage), it has very low current flow.
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With speeds up to 90 miles per hour, what is the fastest sport on ice?.
Answer:
Luge
Explanation:
A sled with mass 11.00 kg moves in a straight line on a frictionless horizontal surface. At one point in its path, its speed is 4.00 m/s; after it has traveled a distance 3.00 m beyond this point, its speed is 7.00 m/s. Use the work-energy theorem to find the force acting on the sled, assuming that this force is constant and that it acts in the direction of the sled's motion.
Answer:
The magnitude of the force acting on the sled is 60.5 newtons.
Explanation:
The Work-Energy Theorem states that the work done by the external force applied on the sled (\(W\)), in joules, is equal to the change of its translational kinetic energy (\(\Delta K\)), in joules:
\(W = \Delta K\) (1)
By definitions of work and translational kinetic energy we expand the equation above:
\(F\cdot s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})\) (1b)
Where:
\(F\) - External force applied on the sled, in newtons.
\(s\) - Travelled distance, in meters.
\(v_{1}, v_{2}\) - Initial and final velocities, in meters per second.
If we know that \(m = 11\,kg\), \(v_{1} = 4\,\frac{m}{s}\), \(v_{2} = 7\,\frac{m}{s}\) and \(s = 3\,m\), then the external force applied on the sled is:
\(F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot s}\)
\(F = \frac{(11\,kg)\cdot \left[\left(7\,\frac{m}{s} \right)^{2}-\left(4\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3\,m)}\)
\(F = 60.5\,N\)
The magnitude of the force acting on the sled is 60.5 newtons.
Please help with this!
On the way down the ball's velocity is Positive 9.8.
Option A) is the correct answer.
What is velocity:?
This refers to the speed at which an object moves in a given direction. It unit is meters per secocond, m/s.
What is acceleration?
This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².
What is Gravity?
This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.
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What travels by vibrating particles? Mechincal Waves or ElecrtoMagnetic Waves.
Answer:mechanical waves.
Explanation:
Mechanical waves require the particles of the medium to vibrate in order for energy to be transferred. For example, water waves, earthquake/seismic waves, sound waves, and the waves that travel down a rope or spring are also mechanical waves.