There are 3 questions one is 2 parts I will mark brainliest on the right answer please dont put in an answer unless it's a real answer

Answer:

Step-by-step explanation:

A = 4 + 3x6/48

A = 4 + 18/48

A = 4 + 3/8

A = (4*8+3)/8

A = 35/8

D = (7+3)-9x2

D = 10-18

D = -8

B = (4x3+6)/48

B = (12+6)/48

B = 18/48

B = 3/8

(4+3)x6÷48

7x6÷48

42÷48

7/8

E = (-5+3-4)-(-4+6)x2

E = (-6)-(-8)

E = 2

Therefore, the results are:

A = 35/8

D = -8

B = 3/8

E = 2

When Marcus tests a hair sample from the telogen stage. The result likely to be true about this sample is there will be a nuclear DNA present.

DNA (Deoxyribonucleic acid) is a polymer comprised of two polynucleotide chains that loop around each other to form a double helix having genetic instructions for the development, functioning, growth and reproduction of all known organisms and many viruses. DNA and ribonucleic acid both are nucleic acids.

Moreover, DNA is the information molecule. It holds the instructions for creating other large molecules, called proteins. These instructions are kept inside each of our cells, distributed among 46 long structures called chromosomes.

Hence, DNA is made of chemical structures called nucleotides. These structures are made of three parts: a sugar group, a phosphate group, and one of four types of nitrogen bases.

Hence the correct option is c.

--The given question is incomplete, the complete question is

''Marcus is testing a hair sample from the telogen stage. What is likely to be TRUE about this sample?

A. There will be several medullas present.

B. There will be mitochondrial DNA present.

C. There will be nuclear DNA present.

D. There will be very little DNA present."--

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The proababilities are: i) P(Aᶜ) = 0.6, ii) P(Bᶜ) = 0.4

iii) Probability that exactly one of the events A, B occurs = 0.7

Let A and B be any two disjoint events such that P(A) = 0.4 and P(A ∪ B) = 0.7. We need to find the following probabilities:

i) P(Aᶜ): This is the probability of the complement of event A, which represents the probability of not A occurring. Since A and B are disjoint, Aᶜ and B are mutually exclusive and their union covers the entire sample space.

Therefore, P(Aᶜ) = P(B) = 1 - P(A) = 1 - 0.4 = 0.6.

ii) P(Bᶜ): This is the probability of the complement of event B, which represents the probability of not B occurring. Since A and B are disjoint, Bᶜ and A are mutually exclusive and their union covers the entire sample space.

Therefore, P(Bᶜ) = P(A) = 0.4.

iii) Probability that exactly one of the events A, B occurs: This can be calculated by subtracting the probability of both events occurring (P(A ∩ B)) from the probability of their union (P(A ∪ B)).

Since A and B are disjoint, P(A ∩ B) = 0.

Therefore, the probability that exactly one of the events A, B occurs is P(A ∪ B) - P(A ∩ B) = P(A ∪ B) = 0.7.

To summarize:

i) P(Aᶜ) = 0.6

ii) P(Bᶜ) = 0.4

iii) Probability that exactly one of the events A, B occurs = 0.7

Note: The provided values of P(A), P(A ∪ B), and the disjoint nature of A and B are used to derive the above probabilities.

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Answer:

it should be cost, because when there is more quantity of something there will be less price.

Answer:

18 kilometres

Step-by-step explanation:

Speed of the car is 72 kilometres per hour

means the car runs 72 kilometers within 60 minutes

so, the car will travel in 15 mins,

72×15/60

= 72/4 = 18 kilometres

The value of kˣ for the exponential function is \(27^{(1/x)}.\)

We can use the properties of exponents to solve this problem and determine the value of kˣ.

To find the value of h(3x), we can use the property that \((a^b)^c = a^{bc}\) for any real numbers a, b, and c. This is shown in the solution below.

h(3x) = 3³ˣ    (since h(x) = 3ˣ)

= (3³)ˣ

= 27ˣ

Therefore, we have:

kˣ = 27ˣ

To find the value of kˣ, we can take the x-th root of both sides:

\(k = 27^{(1/x)}\)

So, the value of kˣ is \(27^{(1/x)}\).

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The value of x that makes 25x^2 + 70x + c a perfect square trinomial is c = 1225.

To make the quadratic expression 25x^2 + 70x + c a perfect square trinomial, we need to determine the value of c.

A perfect square trinomial can be written in the form (ax + b)^2, where a is the coefficient of the x^2 term and b is half the coefficient of the x term.

In this case, a = 25, so b = (1/2)(70) = 35.

Expanding (ax + b)^2, we have:

(25x + 35)^2 = 25x^2 + 2(25)(35)x + 35^2

= 25x^2 + 70x + 1225.

Comparing this with the given quadratic expression 25x^2 + 70x + c, we can see that c = 1225.

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The price of one donuts, if you can buy 6 donuts and two kolaches for $8.84 and one kolache and 4 donuts would cost $5.36 is  $0.94.

Let's represent the price of one donut with "d" and the price of one kolache with "k". Then we can write two equations based on the information given:

6d + 2k = 8.84 (equation 1)

4d + 1k = 5.36 (equation 2)

We can use equation 2 to solve for k:

k = 5.36 - 4d

Now we can substitute this expression for k into equation 1:

6d + 2(5.36 - 4d) = 8.84

Simplifying and solving for d:

6d + 10.72 - 8d = 8.84

2d = 1.88

d = 0.94

Therefore, the price for one donut is $0.94.

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Answer:

15 x 20 x 4 = 1,200

6 x 4 = 24, 24 divided by 2 ( x 1/2 ) = 12

12(area of 1 triangle) x 12(width) = 144

Formula area of a triangle:

B(base) x H(height) x 1/2(basically just dividing by 2)

Formula volume of a rectangular prism:

L x W x H

Answer:

1) 1200

2) 144

Step-by-step explanation:

1:

Volume Of A Cube: L * W * H

Substitute: 25 * 20 * 4

2:

Volume Of A Triangular Prisism: 0.5 * B * A * H

Substitute: 0.5(6 * 4) * 12

Answer:

97.5 miles

Step-by-step explanation:

you would take 65 and multiply by 1.5

Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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the equation of the line is y = 3x - 5

Answer:

WOOF WOOF

Step-by-step explanation:

i love getting extra points :)

The water level is rising at a rate of 0.0075 ft/min when the depth at the deepest point is 5 ft.

Let's call the depth at the deepest point of the pool "y" and the volume of

the water in the pool "V".

We want to find the rate at which the water level is rising, which is the

rate of change of "y" with respect to time.

We know the rate at which the pool is being filled, which is 0.9 ft3/min,

and we can find the rate at which the volume of the water is increasing

using the formula for the volume of a rectangular prism:

V = lwh

where l is the length, w is the width, and h is the height.

Since the pool is not rectangular, we can find the volume of the water as

a function of "y" using similar triangles:

h/y = (9 - 3)/(40 - 20) = 0.3

where h is the height of the pool at the deepest point. Solving for h, we get:

h = 0.3y

Substituting this expression for h into the formula for the volume, we get:

V = lw(3 + 0.6y)

Taking the derivative with respect to time, we get:

dV/dt = lw(0.6 dy/dt)

Now we need to find the values of l and w. The width is given as 20 ft,

and the length is a function of "y":

l = 40 - 2(40 - y) = 2y

Substituting these values into the expression for dV/dt, we get:

dV/dt = 40y(0.6 dy/dt)

Finally, we can find the rate at which the water level is rising when y = 5 ft

by plugging in the values:

0.9 = 40(5)(0.6 dy/dt)

Solving for dy/dt, we get:

dy/dt = 0.9/(4050.6) = 0.0075 ft/min

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The evaluation of the function with which the number of players leading and informed can be found, is prevented as follows;

(a) The stage of the information

(d) The number of leaders and players informed

(c) The function using function notation is P(x) = 2 × 3⁽ˣ⁻¹⁾

(d) We can say that the number of players and leaders depend on the stage of the information

(e) The statement P(4) = 54 indicates that in stage 4, 54 people are informed

(f) Domain; [1 , ∞)

Range; [2, ∞)

(g) The shape of the graph is the curved shape of an exponential function un which the asymptote is an horizontal line

An exponential function is a function in which the argument is an index of a constant of the form f(x) = a·bˣ

(a) The independent variable is the input variable, which is the stage of the calling process

(b) Dependent variable is the output variable, which is the number of leaders and players who are informed

(c) The specified function that represents the number of players who are informed, is presented as follows;

P = 2 × 3ˣ⁻¹

Where;

P = The number of players informed

x = The of information of the players

Expressing the above function using function notation, we get;

P(x) = 2 × 3ˣ⁻¹

(d) We can say that the number of players and leaders informed is a function of the stage of the information

(e) The meaning of the equation P(4) = 54 is that at stage 4, the number of layers and leaders informed is 54

(f) The domain of the function P(x) = 2 × 3ˣ⁻¹ is the set of all positive integers equal to or larger than 1 or Z⁺ {1, 2, 3, ...}

The range of the function is the set of integers, such that 2 ≤ x ≤ ∞

(g) Please find attached the graph of the function created with MS Excel

The attached graph of the function indicates that the shape of the graph is the graph of an exponential function, which is non linear and has a horizontal asymptote , but does not have a vertical asymptote.

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Answer:

x = 2

Step-by-step explanation:

CDEF is a parallelogram.

CE and FD are its diagonals.

Diagonals of a parallelogram bisects each other.

Therefore,

10x - 5 = 4x + 7

10x - 4x = 7 + 5

6x = 12

x = 12/6

x = 2

Thus, for x = 2, CDEF is a parallelogram.

In the quadrilateral CDEF, the value of x is 2.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Quadrilateral CDEF is a parallelogram.

Here, CE and FD are its diagonals.

We know that;

Diagonals of a parallelogram bisects each other.

Therefore, We can formulate;

⇒ 4x + 7 = 10x - 5

Solve for x as;

⇒ 7 + 5 = 10x - 4x

⇒ 12 = 6x

⇒ x = 12/6

⇒ x = 2

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Answer:

The opposite of -3 5/8 is on the right (or opposite) side of zero on the number line as -3 5/8. The opposite of 4 2/9 is on the left (or opposite) side of zero on the number line as 4 2/9.

Step-by-step explanation:

hope this helps. . .<3

good luck!    UwU

Answer:

168 cubic inches

Step-by-step explanation:

The parameters given are:

four 2 in. platys, seven 1 in. guppies, and a 3 in. loach, 

Four 2 inches platys = 4 × 2 = 8 inches

Seven 1 inches guppies = 7 × 1 = 7 inches

A 3 inches leach = 3 inches

The smallest capacity tank you can buy will be

V = 8 × 7 × 3

V = 168 cubic inches

Therefore, the smallest capacity of tank you can buy is 168 cubic inches

Answer: 22 Gallons

Step-by-step explanation:

Answer:

The answer on Acellus is y=1 cos(3)

Step-by-step explanation:

Answer:

Your answer should be 3 1/3

Step-by-step explanation:

:)

Answer

it's 1 9/20. hope this helps :)

Answer:

9?

Step-by-step explanation:

find dy/dx

x= t sin(t); (Given in the question)

y= t²+8t; (Given in the question)

then, x= t sin(t)

dx/dt = sin t + t cos t ;

y= t²+8t

dy/dt = 2t + 8;

then, dy/dx = dy/dt x dx/dt

dy/dx = (2t+8)/(sin t + t cos t)

dy/dx = 2(t+4)/(sin t + t cos t)

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The component form of the linear combination of the two vectors is u - 2v = &lt; -5, 20&gt;

Here we have the two vectors: u = &lt;-3, -2&gt; and v = &lt;1, -5&gt; We want to determine the value of the linear combination:

u - 2v

To do that we just add the correspondent components, then we get:

u - 2v = &lt;-3, -2&gt; - 2*&lt;1, -5&gt;          

= &lt;-3, -2&gt; - &lt;2*1, 2*-5&gt;          

= &lt;-3, -2&gt; -  &lt;2, -10&gt;          

= &lt; -3 - 2, -2 -(-10)&gt;          

= &lt; -5, 20&gt;

That is the component form of the linear combination.

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The values of x will be 2 and -1.

Given that:-

\(14x+17=2(x+3)^2-5\)

We have to find the value of x.

As it is a quadratic equation, there will be two values of x.

Opening the bracket and solving the equation further, we get,

\(14x+17=2(x^2+9+6x) -5\\14x+17 = 2x^2 +18+12x-5\\2x^2-2x-4 = 0\\2(x^2-x-2) =0\\x^2-x-2 = 0\)

Using middle-term split theorem to solve the quadratic equation, we get,

\(x^2-x-2 = 0\\x^2+x-2x-2=0\\\)

x(x + 1) - 2(x + 1) = 0

(x + 1)(x - 2) = 0

Hence, either x + 1 = 0 or x - 2 = 0 or both of them are 0.

x + 1 = 0

x = -1

and,

x - 2 = 0

x = 2

Hence, the values of x are 2 and -1.

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Answer:

I think your answer will be 21 cause you timeing the 3 by 7

Answer:1.5 x 2=3 teaspoons vanilla

Step-by-step explanation: simply double the 1.5 teaspoons which is 3 teaspoons of vanilla