Theoretically (asking for a friend) if you have a 67.0 Percent in a class but turn in a 50-point assignment. What would the grade now be?

ASA Criterion means that the triangles are congruent if the corresponding Angle-Side-Angle is also congruent.

From the the Triangle ABC :

corresponds with ASA.

Likewise from the Triangle DEF :

Since the given figure already states that :

and BC = FE

The other item that will complete the ASA will be :

SAS criterion means that the triangle are congruent if the corresponding Side-Angle-Side are also congruent.

The following corresponds with SAS :

From the triangle ABC :

From the triangle DEF

We can factor by grouping like so

3v^2 + 16v + 5

3v^2 + 15v + v + 5

3v(v + 5) + 1(v + 5)

(3v+1)(v+5)

---------

Check:

(3v+1)(v+5)

w(v+5) ... let w = 3v+1

vw + 5w

v(w) + 5(w)

v(3v+1) + 5(3v+1) .... plug in w = 3v+1

3v^2+v + 15v + 5

3v^2 + 16v + 5

We get the original expression again, which confirms the answer.

Answer:

think red is 40 cm squared and the orange is 75 cm squared. You add for 115 cm squared

Step-by-step explanation:

Hope this helps my guy, please give me brainliest. :D

Samuel needs to score at least 96 on his next exam to achieve an average of 85.

Given that Samuel scored a 72, 92 and 80 on his first three exams,

We need to find his minimum score in the next exam so that he can have an average of 85 overall.

To find the minimum score Samuel needs to get on his next exam to achieve an average of 85, we can use the formula for the average:

Average = (Sum of scores) / (Number of scores)

Since we have the average and three exam scores, we can solve for the fourth score (let's call it "x"):

85 = (72 + 92 + 80 + x) / 4

To find "x," first, let's simplify the equation:

85 × 4 = 72 + 92 + 80 + x

340 = 244 + x

Now, isolate "x" on one side:

x = 340 - 244

x = 96

So, Samuel needs to score at least 96.

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Six-beat is the time signature of Gurlitt.

In 6/8 time, there are six eighth notes in each measure. This means that there are three quarter notes in every two measures, and one full note (or semitone) in every four measures.

The signature of Gurlitt is a typeface that was designed by German typographer Christoph Schulte in the early 1900s.

It has been used for signage, advertising, and other types of graphics throughout history. It provides a good overview of what to expect from this piece and also helps to build curiosity in readers.This makes it easier for them to find out more about the article topic. Additionally, using vivid language keeps the reader's attention engaged throughout the entire essay.

Hence,  Six-beat is the time signature of Gurlitt.

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The control limits for the R-chart, based on the given information, are UCL = 6.846 miles per hour and CL = 3.00 miles per hour.


To establish the control limits for the R-chart, we need to calculate the upper control limit (UCL) and the centerline (CL) for the range of maximum speeds.
Given:
Average sample mean (x) = 103.50 miles per hour
Average range (R) = 3.00 miles per hour
To calculate the control limits, we can use the following formulas:
UCL = D4 × R
CL = R
The constant D4 depends on the sample size. Since each sample contains 8 Eagletrons, we can refer to a statistical table to find the appropriate value of D4 for n = 8. For a sample size of 8, the value of D4 is approximately 2.282.
Plugging in the values, we can calculate the control limits:
UCL = D4 × R = 2.282 × 3.00 = 6.846 miles per hour (rounded to three decimal places)
CL = R = 3.00 miles per hour
Therefore, the control limits for the R-chart, based on the given information, are:
Upper Control Limit (UCL) = 6.846 miles per hour
Centerline (CL) = 3.00 miles per hour.

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Answer:

The distributive property states that you can "distribute" the contents of one parentheses into the other to find an answer.

Let's first break down the larger number in the second parentheses:

400 + 10 + 5.

Then, let's multiply all those numbers by 3.

400 x 3 = 1200. 10 x 3 = 30. 5 x 3 = 15.

Then add up all the numbers and you get 1245.

Answer:

1245

Step-by-step explanation:

400+10+5

400×3=1200. 10×3=30. 5×3=15

The slοpe οf the line passing thrοugh the pοints (-2,-4) and (3,-4) is 0.

In mathematics, slοpe refers tο the measure οf the steepness οf a line. It is defined as the ratiο οf the vertical change (rise) between twο pοints.

Tο find the slοpe οf the line passing thrοugh the pοints (-2,-4) and (3,-4), we can use the slοpe fοrmula:

slοpe = (change in y) / (change in x)

Let's call the first pοint (-2,-4) "pοint 1" and the secοnd pοint (3,-4) "pοint 2". Then, we have:

change in y = y2 - y1 = (-4) - (-4) =

change in x = x2 - x1 = 3 - (-2) = 5

Substituting these values intο the slοpe fοrmula, we get:

slοpe = (change in y) / (change in x) = 0 / 5 = 0

Hence, the slοpe οf the line passing thrοugh the pοints (-2,-4) and (3,-4) is 0.

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1. The correct answer is 46 percent, 2. The correct answer is .07, 3. The correct answer is (34%,58%), 4. The correct answer is (32%,60%)

The term "standard error" is used to refer to the standard deviation of various sample statistics, such as the mean or median. For example, the "standard error of the mean" refers to the standard deviation of the distribution of sample means taken from a population. The smaller the standard error, the more representative the sample will be of the overall population.

The relationship between the standard error and the standard deviation is such that, for a given sample size, the standard error equals the standard deviation divided by the square root of the sample size. The standard error is also inversely proportional to the sample size; the larger the sample size, the smaller the standard error because the statistic will approach the actual value.

1. Let's calculate the percentage or proportion of patients that were dogs:

p = (7 + 4 + 5 + 5 + 2)/50 = 23/50 = 0.46

The correct answer is 46%

2. Let's estimate the standard error, using the given formula, this way:

S.e = √ (0.46 * 0.54)/50 = √0.049 = 0.07

The correct answer is .07

3. Let's calculate the confidence limits of the 90% confidence interval, this way:

Confidence limits = proportion +/- 1.645 * standard error

Confidence limits = 0.46 +/- 1.645 * 0.07

Confidence limits = 0.46 +/- 0.12

Confidence limits = 0.34, 0.58

The correct answer is (34%,58%)

4. Let's calculate the confidence limits of the 95% confidence interval, this way:

Confidence limits = proportion +/- 1.96 * standard error

Confidence limits = 0.46 +/- 1.96 * 0.07

Confidence limits = 0.46 +/- 0.14

Confidence limits = 0.32, 0.60

The correct answer is (32%,60%)

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Answer:

No it is not a collection of well defined and distinct objects

Hope this helps <3

Answer:

Corresponding Angles

Step-by-step explanation:

Both \(\angle 4\) and \(\angle 8\) are Corresponding Angles, they are in the same side of the transversal line, and where a line crosses two other lines.

Step-by-step explanation:

<4 and <8 are corresponding angles because they are on the same side of the transversal and are at the same location and they are congruent meaning they are equal

Thus, a basis for s⊥ is the set {(-2, 2, 0)}.

What is a basis for s ⊥?

The question involving the terms "subspace," "containing," and "spanned."

If s is the subspace of R³ containing only the zero vector, s⊥ (the orthogonal complement of s) is the entire R³ space. This is because all vectors in R³ are orthogonal to the zero vector.

If s is spanned by (1, 1, 1), to find s⊥, we need a vector that is orthogonal to (1, 1, 1). We can use the dot product to determine orthogonality. For a vector (x, y, z), the dot product with (1, 1, 1) should be zero:

(1, 1, 1) · (x, y, z) = 0
x + y + z = 0

One possible vector that satisfies this equation is (-1, 1, 0). So, s⊥ is the subspace spanned by (-1, 1, 0).

If s is spanned by (1, 1, 1) and (1, 1, -1), to find a basis for s⊥, we need a vector orthogonal to both given vectors. We can use the cross product of the given vectors to find the orthogonal vector:

(1, 1, 1) × (1, 1, -1) = (-2, 2, 0)

Thus, a basis for s⊥ is the set {(-2, 2, 0)}.

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The observed odds ratio (the observed association between migraine headache and cell phone use) is OR = 1.23.

An investigator is studying the association between cell phone use and migraine headaches.

100 cases (migraine patients) and 100 controls (people who don't suffer from migraine), and asks each group how many hours they use their cell phones per day, on average.

To calculate odd ratio ( exposure is cell phone as to check cell phone use on migraine)

Odds of disease in exposed = 60/55= 1.09

Odd of disease in non exposed = 40/45 = 0.88

Thus the odds ratio will be = 1.09:0.88

=> Odds of disease in exposed / odds of disease in non exposed = 1.09/ 0.88 = 1.23

= OR = 1.23

Hence the answer is the observed odds ratio (the observed association between migraine headache and cell phone use) is OR = 1.23.

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The $1314^\text{th}$ digit past the decimal point is 2.

To find the $1314^\text{th}$ digit past the decimal point in the decimal expansion of $\frac{5}{14}$, we can use long division to compute the decimal expansion of the fraction.

The long division of $\frac{5}{14}$ is as follows:

```

0.35    <-- Quotient

-----

14 | 5.00

   4.2    <-- Subtract: 5 - (14 * 0.3)

   -----

     80   <-- Bring down the 0

     70    <-- Subtract: 80 - (14 * 5)

     -----

     100   <-- Bring down the 0

      98    <-- Subtract: 100 - (14 * 7)

      -----

       20   <-- Bring down the 0

       14    <-- Subtract: 20 - (14 * 1)

       -----

        60   <-- Bring down the 0

        56    <-- Subtract: 60 - (14 * 4)

        -----

         40   <-- Bring down the 0

         28    <-- Subtract: 40 - (14 * 2)

         -----

         120   <-- Bring down the 0

         112    <-- Subtract: 120 - (14 * 8)

         -----

           80   <-- Bring down the 0

           70    <-- Subtract: 80 - (14 * 5)

           -----

           ...

```

We can see that the decimal expansion of $\frac{5}{14}$ is a repeating decimal pattern with a repeating block of digits 285714. Therefore, the $1314^\text{th}$ digit past the decimal point is the same as the $1314 \mod 6 = 0^\text{th}$ digit in the repeating block.

Since $1314 \mod 6 = 0$, the $1314^\text{th}$ digit past the decimal point in the decimal expansion of $\frac{5}{14}$ is the first digit of the repeating block, which is 2.

So, the $1314^\text{th}$ digit past the decimal point is 2.

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The midpoint of the line segment with the endpoints (5, 6) and (-5, -2) is (0, 2).Hence, the answer is: Midpoint = (0, 2).

The midpoint of a line segment with endpoints (x1, y1) and (x2, y2) is calculated using the formula:M = [(x1 + x2) / 2, (y1 + y2) / 2]where M is the midpoint.In the given problem, the endpoints are (5, 6) and (-5, -2).

So, we can find the midpoint by applying the formula mentioned above.Midpoint = [(5 + (-5)) / 2, (6 + (-2)) / 2]= [0/2, 4/2]= [0, 2]

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It will take approximately 39.532 days for $9500 to earn $800 at an annual interest rate of 8.25%.

To find the number of days it will take for $9500 to earn $800 at an annual interest rate of 8.25%, we need to use the formula for simple interest:

Interest = Principal * Rate * Time

In this case, we are given the interest ($800), the principal ($9500), and the annual interest rate (8.25%). We need to solve for time.

Let's denote the time in years as "t". Since we're looking for the number of days, we'll convert the time to a fraction of a year by dividing by 365 (assuming a standard 365-day year).

$800 = $9500 * 0.0825 * (t / 365)

Simplifying the equation:

800 = 9500 * 0.0825 * (t / 365)

Divide both sides by (9500 * 0.0825):

800 / (9500 * 0.0825) = t / 365

Simplify the left side:

800 / (9500 * 0.0825) ≈ 0.1083

Now, solve for t by multiplying both sides by 365:

0.1083 * 365 ≈ t

t ≈ 39.532

Therefore, it will take approximately 39.532 days for $9500 to earn $800 at an annual interest rate of 8.25%.

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The final step in solving the inequality -2(5 - 4x) < 6x - 4 is x > 3. This means that for the given The final step in solving the inequality -2(5 - 4x) < 6x - 4 is x > 3. This means that for the given inequality to hold true, the value of x must be greater than 3.

Let's go through the steps to solve the inequality:

Step 1: Distribute the -2 to the terms inside the parentheses: -2 * 5 + 2 * 4x < 6x - 4

Simplifying: -10 + 8x < 6x - 4

Step 2: Move the terms involving x to one side and the constant terms to the other side: -10 < 6x - 8x - 4

Simplifying: -10 < -2x - 4

Step 3: Combine like terms: -10 < -2x - 4

Step 4: To isolate x, we need to move the constant terms to the other side by adding 4 to both sides: -6 < -2x + 4

To solve for x, we divide both sides by -2, remembering to flip the inequality sign because we are dividing by a negative number: -6/-2 > -2x/-2 + 4/-2

Simplifying: 3 > x + 2

Finally, subtract 2 from both sides to isolate x: 3 - 2 > x + 2 - 2

Simplifying: 1 > x

Therefore, the final step in solving the inequality -2(5 - 4x) < 6x - 4 is x > 3.

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The multiple and fraction of the multiple of the number of bars Class A sells which represents the bars Class B and Class C sold, indicates number of chocolate bars Class A and Class C together sell is 300 chocolate bars

A fraction is a representation of a part or proportion of an amount.

The average number of chocolate bars the 3 classes initially had = 225

The number of cholcolate bars Class B sold = Twice the number of chocolate bares Class A sold

Number of chocolate bars class C sold = (3/4) × The number of chocolate bars Class B sold, we get;

The average number of chocolate bars the 3 classes had left = 45

Therefore, the total number of chocolate bars they initially had = 225 × 3 = 675 chocolate bars

The number of chocolate bars remaining after the sale = 45 × 3 = 135

The number of chocolate bars sold = 675 - 135 = 540

Let n represent the number of chocolate bars Class A sold, the multiple and fraction of n which Class A and Class C sells indicates that we get;

The number of bars Class B sold = 2·n

Number of chocolate bars Class C sold = (3/4) × 2·n

From which we get;

n + 2·n + (3/4) × 2·n = 540

9·n/2 = 540

n = 540 × 2/9 = 120

The number of chocolate bars Class A sells, n = 120 chocolate bars

Number of chocolate bars Class C sells = (3/4) × 2 × 120 = 180 chocolate bars

The number of cholate bars Class A and Class C sells together = n + (3/4) × 2·n

n + (3/4) × 2·n = 5·n/2

n = 120, therefore;

5·n/2 = 5 × 120/2 = 300

Number of chocolate bars Class A and Class C sells = 300 chocolate bars

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Answer:

I'm pretty sure 1 is verticle and 2 is complimentary

Step-by-step explanation:

Linear equation is the equation in which the highest power of the unknown variable is one. The equation to find m, the number of months it will take for both accounts to have the same amount of money, can be given as,

\(112+25m+45=50+60m\)

Thus the option 4 is the correct option.

Given information;

The saving of the first runner is $112.

The amount of gift card the first runner received is $45 and the saving of each month is $25.

The saving of the second runner is $50.

The amount of second runner save each month is $60.

The number of months it will take for both accounts to have the same amount of money is m.

Linear equation is the equation in which the highest power of the unknown variable is one.

As the saving of the first runner is $112. and the amount of gift card the he received is $45. Also his saving of each month is $25. Thus the money saved by him in m months,

\(=112+45+25m\)

As the saving of the second runner is $50 and the amount he save each month is $60. Thus the money saved by him in m months,

\(=50+60m\)

For the same amount of saving in m months the above two equation must be equal. Therefore,

\(112+45+25m=50+60m\)

Rewrite the equation as,

\(112+25m+45=50+60m\)

Hence the equation to find m, the number of months it will take for both accounts to have the same amount of money, can be given as,

\(112+25m+45=50+60m\)

Thus the option 4 is the correct option.

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Answer:

Linear equation is the equation in which the highest power of the unknown variable is one. The equation to find m, the number of months it will take for both accounts to have the same amount of money, can be given as,

Thus the option 4 is the correct option.

Step-by-step explanation:

A critical value, z subscript alpha (zα), denotes the boundary or cutoff point for a statistical test where the level of significance, also known as alpha (α), is set.

A critical value, z subscript alpha (zα), denotes the value at which the probability of observing a test statistic in the tail(s) of the sampling distribution equals the pre-determined significance level (alpha).

The critical value can be defined as the value that is compared with the parameter value in the hypothesis test to determine whether the null hypothesis will be rejected. If the value of the parameter is less than the critical value, the null hypothesis is rejected.

However, if the measured value is higher than the critical value, reject the null hypothesis and accept the alternative hypothesis. In other words, cropping divides the image into acceptable and unacceptable areas. If the value of the index falls within the rejection range, the rejection of the fact is rejected, otherwise the negative hypothesis is rejected.

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21 inch²

we splitthe two shapes, find the areas by multiplying the two sides and we add both of the answers, 15+6

Answer:

2(3) + 2(6) = 6 + 12 = 18 square feet

Answer:

a- 2b/3

Step-by-step explanation:

1) Remove the parentheses and combine like terms

The values of x that satisfy the equation p(−x ≤ t22 ≤ x) = 0.98 are all values between -2.518 and 2.518, inclusive.

The expression p(- x ≤ t22 ≤ x) represents the probability of a t-distribution with 22 degrees of freedom lying between - x and x.

We want to find the values of x such that this probability is 0.98.

We can use a table of t-distribution probabilities or a calculator to find the value of t for which the probability of a t-distribution with 22 degrees of freedom lying between −t and t is 0.98.

This value is , 2.518.

Therefore, we need to solve the inequalities:

-2.518 ≤ -x ≤ 2.518

Solving for x, we get:

-2.518 ≤ -x x ≤ 2.518

Therefore, the values of x that satisfy the equation p(−x ≤ t22 ≤ x) = 0.98 are all values between -2.518 and 2.518, inclusive.

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The correct option will be B 3x²+4x-6.

The given polynomial is 3x³-11x²-26x+30.

We need to divide it from x-5,

So,

Factoring the polynomial,

3x³-11x²-26x+30 = 3x²(x-5)+4x(x-5)+6(x-5)

= 3x²+4x-6(x-5)

Now dividing,

3x²+4x-6(x-5)  / (x-5) = 3x²+4x-6

Hence, the correct option will be B 3x²+4x-6.

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Solution

Hence the answer is option D

The midline, amplitude and period respectively of the given sine graph are; x = 1; 2; π

The midline of this trigonometric graph is defined as the horizontal line that divides the maximum and minimum point distance into two equal parts. In this case, the midline is x = 1

The amplitude of a graphed function is usually the peak of the wave of that graph. In this case, we see that the peak of the graph is at y = 4. Thus, Amplitude = 4

Period is the difference between two consecutive maximum or minimum points. In this graph, the period is π

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Answer:

Midline: y = 1

Amplitude = 3

Period = 1\(\pi\)

Step-by-step explanation:

Edmentum

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Answer:

500percent of 900 is 4500