The volume of a sphere is given by the equation =4/33, where is the radius. Calculate the volume of a sphere with a radius of 345 pm in cubic meters.

Answer:

S= 32, or the total number of valence electrons for silicon tetrachloride

Explanation:

I drew the lewis dot structure to solve this

The total number of valence electrons for silicon tetrachloride is 32. There are 4 valence electrons in Si and valence electrons for each Cl atom.

Lewis dot structure of an element or compound represents the valence electrons, bonded electrons and unpaired electrons as dots around each atom. Thus, it must satisfy the rule of octet.

According to rule of octet the atoms lose or gain electrons or share electrons in order to make octet in valence shell and leads to stability. The number of electrons shared/ lost or gained depends on  the number of valence electrons.

Si is 14th element. It contains 4 valence electrons. Cl is 17th element and contains 7 valence electrons. Therefore there are 28 valence electrons for 4 Cl atoms and with the 4 electrons from Si there are a total of 32 valence electrons in silicon tetrachloride.

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Answer:

Mouthing is the answer to your question

Answer:

The chalcogens are the elements that belong to group 16 of the modern periodic table (or the oxygen family). Chalcogens consist of five elements – oxygen, sulfur, selenium, tellurium, and polonium.

The chalcogens (ore forming) are the chemical elements in group 16 of the periodic table. This group is also known as the oxygen family. Group 16 consists of the elements oxygen (O), sulfur (S), selenium (Se), tellurium (Te), and the radioactive elements polonium (Po) and livermorium (Lv).Explanation:

Answer: copper gold silver

Explanation: They are in the same group.

Answer:

If electronegativity difference is greater than 1.7 then ionic bond other wise covalent bond

Explanation:

Acetic acid only partially ionizes in water as it is a weak acid.

Weak Acids are the acids that do not completely dissociate into their constituent ions when dissolved in solutions.

When dissolved in water, an equilibrium is established between the concentration of the weak acid and its constituent ions.

Acetic acid, also known as ethanoic acid, is a weak acid with the chemical formula CH₃COOH. It is known to be the active component of vinegar.

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Here in all the compounds we see covalent bonds, that is to say that the atoms are sharing electrons with each other. Now, covalent bonds are divided into single, double or triple according to the number of electrons they share.

When they share a pair of electrons, a line is drawn that represents a bond. If it has only one it will be a simple bond, if it has two it will be a double bond and if it has 3 it will be a triple bond.

Here we see simple covalent bonds and double covalent bonds.

Now, to calculate the enthalpy change we can do it starting from the bond energies, applying the following formula:

The bonds to take into account for the calculation of enthalpy will be:

Ethanol:

5 bonds C-H

1 bond C-O

1 bond O-H

Oxygen:

1 bond O=O, but there are 3 moles of O2, so it will be 3 bonds O=O

Carbon dioxide:

2 bonds O=C, there are 2 moles of CO2, so it will be 2x2= 4 bonds O=C

Water:

2 bonds O-H, there are 3 moles of H2O, so it will be 2x3=6 bonds O-H

Answer:

D. -1882J

Explanation:

We can solve the energy released in a chemical reaction in an aqueous medium using the equation:

Q = -m*C*ΔT

Where Q is energy (In J),

m is mass of water (45.00g)

C is specific heat of water (4.184J/g°C)

And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)

Replacing:

Q = -45.00*4.184J/g°C*10.00°C

Q = -1882J

Right answer is:

Balance the following chemical equations:

1. N2 + 3 H2 → 2 NH3

Ex: Synthesis reaction

2. 2 KClO3 → 2 KCl + 3 O2

Single Replacement reaction

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Decomposition reaction

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Double Replacement reaction

5. 2 H2 + O2 → 2 H2O

Combustion reaction

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Synthesis reaction

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Decomposition reaction

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Combustion reaction

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Double Replacement reaction

10. 4 P + 5 O2 → 2 P2O5

Synthesis reaction

11. 2 Na + 2 H2O → 2 NaOH + H2

Single Replacement reaction

12. 2 Ag2O → 4 Ag + O2

Decomposition reaction

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Combustion reaction

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Double Replacement reaction

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Double Replacement reaction

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Combustion reaction

17. 4 Al + 3 O2 → 2 Al2O3

Synthesis reaction

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Single Replacement reaction

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CH3CH2CH2CH3 i.e., butane having more boiling point among the all given .

Compounds composed of molecules joined by chemical bonds arranged so that their charge distributions are symmetrical are called non-polar compound

Compounds composed of molecules joined by asymmetric polar bonds.

Polar compounds exhibit polarity. This is a property characterized by two opposite charges or poles. As such, it can be converted into a water-soluble ion, which is a polar molecule.

Reason :

while increasing the number of carbons in the chain, the boiling point also increases. The alkanes having intractions with the neighbour alkanes will be Van der Waals dispersion forces, these intractions are very less in the small molecule such as methane. The the force of attraction between the molecules increases as the molecule gets longer and has more electrons.

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It is to be noted that Rahul Kumar the biologist came to India to find problems that he can solve using his knowledge in Biology.

Rahul Kumar, an Indian and the son of a migrant worker from Bihar, graduated with honors from IIT Roorkee and is currently on his way to the United States to pursue his PhD at the University of Utah.

A biologist is a scientist who undertakes biological study. Biologists are interested in researching all forms of life on Earth, whether they be single cells, multicellular organisms, or communities of interacting individuals. They often specialize in a single field of biology and have a specialized research emphasis.

The majority of biologists work full-time at government agencies, private research laboratories, medical testing facilities, higher education institutions, or other research facilities.

Physician's assistants, radiation and nuclear medicine technologists, and registered nurses are among the hospital employment available to those with a bachelor's degree in biology. These positions can also be found in clinics, physicians' offices, nursing homes, rehabilitation institutions, government organizations, the military, and other settings.

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Answer:

The net ionic equation is  \(ZnCO_3 _{(s)} + 4 OH^{-}_{(aq)} \to [Zn(OH)_4]^{2-} _{(aq)} + CO_3^{2-} _{(aq)}\)

The equilibrium constant is  \(K = 4.06 *10^{4}\)

Explanation:

From the question we are that

      The  \(K_f = 2.9 *10^{15 }\)

The ionic equation is chemical represented as

    Step 1

         \(ZnCO_3 _{(s)}\)  ⇔   \(Zn^{2+} _{aq} + CO_3^{2-} _{aq}\)   The  solubility product constant for stage is     \(K_{sp} = 1.4*10^{-11}\)

 Step 2

        \(Zn^{2+} _{(aq)} + 4 0H^{-} _{(aq)}\)    ⇔  \([Zn(OH_4)]^{2-} _{(aq)}\)  The formation constant for this step is given as \(K_f = 2.9 *10^{15 }\)

 The net reaction is  

           \(ZnCO_3 _{(s)} + 4 OH^{-}_{(aq)} \to [Zn(OH)_4]^{2-} _{(aq)} + CO_3^{2-} _{(aq)}\)

The equilibrium constant is mathematically evaluated as

         \(K = K_{sp} * K_f\)

substituting values

         \(K = 1.4*10^{-11} * 2.9 *10^{15}\)

        \(K = 4.06 *10^{4}\)

The perfect gas equation of state is a fundamental law in thermodynamics that describes the relationship between the pressure, volume, and temperature of a gas. It is given by the equation:

PV = nRT

where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, R is the universal gas constant, and T is the temperature of the gas in kelvin.

The perfect gas equation of state can be derived by combining three laws:

Boyle's law: This law states that the pressure of a gas is inversely proportional to its volume at a constant temperature. Mathematically, it can be expressed as:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume of the gas, and P2 and V2 are the final pressure and volume.

Charles's law: This law states that the volume of a gas is directly proportional to its absolute temperature at constant pressure. Mathematically, it can be expressed as:

V1/T1 = V2/T2

where V1 and T1 are the initial volume and temperature of the gas, and V2 and T2 are the final volume and temperature.

Avogadro's principle: This principle states that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules. Mathematically, it can be expressed as:

V1/n1 = V2/n2

By combining these three laws, we can derive the perfect gas equation of state. First, we can rearrange Boyle's law to express pressure in terms of volume:

P = P1V1/V

Next, we can substitute this expression for P into Charles's law:

V1/T1 = V2/T2

V1/T1 = V1(P1V1)/(T2V)

T2 = (P1V1T1)/(V)

Similarly, we can rearrange Avogadro's principle to express volume in terms of the number of moles:

V = nRT/P

Substituting this expression for V into the equation we obtained from Charles's law, we get:

T2 = (P1V1T1)/(n1R)

Finally, we can rearrange this equation to isolate the pressure term, which gives us the perfect gas equation of state:

PV = nRT

Thus, by combining Boyle's law, Charles's law, and Avogadro's principle, we can derive the perfect gas equation of state, which is a fundamental law in thermodynamics that describes the behavior of ideal gases.

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Answer: 1) \(RCOO^-\)

2) \(H_2PO_4^-\)

3) \(RNH_2\)

4) \(HCO_3^-\)

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

1) \(RCOOH\rightarrow RCOO^-+H^+\)

Here, \(RCOOH\) is loosing a proton, thus it is considered as an acid and after losing a proton, it forms \(RCOO^-\) which is a conjugate base.

2) \(H_3PO_4\rightarrow H_2PO_4^-+H^+\)

Here, \(H_3PO_4\) is loosing a proton, thus it is considered as an acid and after losing a proton, it forms \(H_2PO_4^-\) which is a conjugate base.

3) \(RNH_3^+\rightarrow RNH_2+H^+\)

Here, \(RNH_3^+\) is loosing a proton, thus it is considered as an acid and after losing a proton, it forms \(RNH_2\) which is a conjugate base.

4) \(H_2CO_3\rightarrow HCO_3^-+H^+\)

Here, \(H_2CO_3\) is loosing a proton, thus it is considered as an acid and after losing a proton, it forms \(HCO_3^-\) which is a conjugate base.

Boyle's law states that, at a certain temperature, a gas's pressure and volume are inversely related, meaning that as the volume falls, the pressure rises and vice versa.

According to Boyle's law, the volume of the container has an inverse relationship to the gas's pressure. In other words, a big volume container will have low pressure, and a low volume container will have high pressure. Breathing is a biological example of how this law operates.

According to Boyle's law, a gas's pressure and volume are inversely proportional. When the temperature stays the same, pressure rises as volume rises and vice versa.

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The collected data/information in scientific investigations is often in the form of continuous measurements for quantitative variables.

Quantitative variables, also known as continuous variables, are those variables expressed in the form of interval range values and therefore do not have a specific value.

Conversely to quantitative variables, discrete variables are those expressed as a single value, but both type of variables can be used as empirical evidence.

In conclusion, the collected data/information in scientific investigations is often in the form of continuous (range value) measurements for quantitative variables.

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Answer:

The Awnser is True. Hope that helps.

Answer:

true

Explanation:

Answer:

Your answer is 209 J.

Explanation:

First find △T by subtraction of two temperatures.

△T = 18°C - 13 °C

= 5°C.

Q=mc△t

where,

m= mass.

c = Specific Heat .

t = temperature.

As, Specific Heat capacity of water is 4.18 J/g°C

= 10 × 4.18× 5

= 209 Joules.

When a 10g sample of liquid water increases in temperature from 13°C to 18°C, then the amount of gained energy is 209 joules.

The amount of energy which is gained by any sample will be calculated as:

Q = mcΔT, where

Q = gained energy

m = mass of sample = 10g

c = specific heat of water = 4.18 J/g°C

ΔT = change in temperature = 18 - 13 = 5°C

On putting values we get

Q = (10)(4.18)(5)

Q = 209 Joules

Hence required amount of energy is 209 joules.

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Answer:

none of the liquid is purple

Answer:

It's a heterogeneous mixture.

Explanation:

Diamond is made of just one element: carbon. Each carbon atom in diamond is connected to four other carbon atoms, in a crystal that extends on and on. There are other forms of pure carbon where the atoms are bonded differently, notably charcoal and graphite.

Answer:

It's a heterogeneous mixture.

Explanation:

Diamond is made of just one element: carbon.

Answer: Density means the compactness of an object

I hope this helps, and Happy Holidays! :)

Answer:

dwarf planets lack the gravitational forces needed to pull in and accumulate all of the material found in their orbits

Explanation:

Answer:

Thermal energy comes from heat sources that provide energy from it's temp.

Explanation:

Produced when a rise in temperature causes atoms and molecules to move faster and collide with each other. The energy that comes from the temperature of the heated substance is called thermal energy. 6 min, 47 sec Heat Energy.

(If this doesn't help let me know in the comments, I'll try to explain better :> )

Moles of gas=19.75

The gas equation can be written  

\(\large {\boxed {\bold {PV = nRT}}}\)

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

V=150 L

P=4.2 atm

T=389 K

\(\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{4.2\times 150}{0.082\times 389}\\\\n=19.75\)

Approximately 766.08 grams of oxygen are required to completely react with 240g of C₂H₆.

To determine the amount of oxygen required to completely react with 240g of C₂H₆ (ethane), we need to set up a balanced chemical equation for the combustion of ethane.

The balanced equation for the combustion of ethane is as follows:

C₂H₆ + O₂ → CO₂ + H₂O

From the balanced equation, we can see that the stoichiometric ratio between C₂H₆ and O₂ is 1:3. This means that for every one mole of C₂H₆, three moles of O₂ are required for complete combustion.

To calculate the amount of oxygen required, we need to convert the given mass of C₂H₆ to moles using its molar mass, and then use the stoichiometric ratio to determine the moles of O₂ required. Finally, we can convert the moles of O₂ back to grams using the molar mass of oxygen.

The molar mass of C₂H₆ is calculated as follows:

(2 x atomic mass of carbon) + (6 x atomic mass of hydrogen)

(2 x 12.01 g/mol) + (6 x 1.01 g/mol) = 30.07 g/mol

Now, we can proceed with the calculation:

Calculate the moles of C₂H₆:

moles of C₂H₆ = mass of C₂H₆ / molar mass of C₂H₆

moles of C₂H₆ = 240 g / 30.07 g/mol ≈ 7.98 mol

Determine the moles of O₂ using the stoichiometric ratio:

moles of O₂ = moles of C₂H₆ x (3 moles of O₂ / 1 mole of C₂H₆)

moles of O₂ = 7.98 mol x 3 ≈ 23.94 mol

Convert moles of O₂ to grams:

mass of O₂ = moles of O₂ x molar mass of O₂

mass of O₂ = 23.94 mol x 32.00 g/mol = 766.08 g

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Answer : The mass of \(H_2\) is, 9.64 grams.

Explanation : Given,

Mass of \(NH_3\) = 54.6 g

Molar mass of \(NH_3\) = 17 g/mol

Molar mass of \(H_2\) = 2 g/mol

First we have to calculate the moles of \(NH_3\).

\(\text{Moles of }NH_3=\frac{\text{Given mass }NH_3}{\text{Molar mass }NH_3}\)

\(\text{Moles of }NH_3=\frac{54.6g}{17g/mol}=3.21mol\)

Now we have to calculate the moles of \(H_2\)

The balanced chemical equation is:

\(2NH_3(g)\rightarrow 3H_2(g)+N_2(g)\)

From the balanced reaction we conclude that

As, 2 mole of \(NH_3\) react to give 3 moles of \(H_2\)

So, 3.21 mole of \(NH_3\) react to give \(\frac{3}{2}\times 3.21=4.82\) mole of \(H_2\)

Now we have to calculate the mass of \(H_2\)

\(\text{ Mass of }H_2=\text{ Moles of }H_2\times \text{ Molar mass of }H_2\)

\(\text{ Mass of }H_2=(4.82moles)\times (2g/mole)=9.64g\)

Therefore, the mass of \(H_2\) is, 9.64 grams.

9.6 grams of H₂ can be formed from 54.6 grams of NH₃ in the following reaction: 2NH₃(g) → 3H₂(g) + N₂(g).

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