The visible light portion of the electromagnetic spectrum of light is often subdivided into the colors of red, orange, yellow, green, blue, indigo, and violet (sometimes referred to as ROY G BIV). Using the words greatest, least, highest, lowest, fastest, slowest, longest, and shortest, write a sentence or two that describes how light at the red end of the spectrum and light at the violet end of the visible light portion of the spectrum compare in terms of their energy, frequency, speed and wavelength.
Light at the red end of the visible portion has the least energy, lowest frequency, same speed, and longer wavelength compared to the violet end.

The net torque acting on it hen inserted into a player, the cd starts from rest and accelerates to an angular velocity of 21 rad/s in 0.52 s are 2.059[/tex.

The net torque is the force applied that is usually quite different from normal acting force.

Here solid disk =Torque\(Iα\)

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The overall amount of atomic orbitals that go into creating a molecular orbital is equal to that number. Two H protons make up a chemical H2, which is.

The sun is one of most significant energy sources. Almost all of the energy on earth comes from the sun, which is where it all began. Sunlight provides us with solar thermal energy and can also be used by solar (photovoltaic) cells to generate electricity.

Because it is a core human requirement, power plays a significant role in our daily lives. Our living thing constructions are not only heated by energy, but also cooled by it.

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The centripetal acceleration of the car driving at a constant speed of 21 m/s around a circle with a radius of 100 m is calculated to be 4.41\(m/s^2.\)

To find the centripetal acceleration of the car, we can use the formula:

a = \(v^2\) / r

where "a" represents the centripetal acceleration, "v" is the velocity of the car, and "r" is the radius of the circular path.

Given that the car drives at a constant speed of 21 m/s and the radius of the circle is 100 m, we can substitute these values into the formula to calculate the centripetal acceleration.

a = (21\(m/s)^2\)/ 100 m

a = 441 \(m^2/s^2\)/ 100 m

a = 4.41 \(m/s^2\)

Therefore, the centripetal acceleration of the car is 4.41\(m/s^2.\) This centripetal acceleration represents the inward acceleration that keeps the car moving in a circular path, and its magnitude is determined by the square of the velocity divided by the radius of the circle.

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Answer:

Explanation:

F = -kΔx

Since the spring constant is given in N/m, we need to convert the stretch to meters as well.

12 cm = .12 m

Now we can solve the problem:]

F = -55(-.12) so

F = 6.6N

The force required to stretch the spring is 6.6 N

The force acting on a spring is given by:

Force (F) = spring constant (K) × Extention (e)

F = Ke

With the above formula, we can obtain the force required to stretch the spring as follow:

F = Ke

F = 55 × 0.12

F = 6.6 N

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The main and basic action of any single muscle that would have on a body would be the fact that it would contain "contraction" to which your muscle would practically contract each other, which would then give to power to force, push, push, and to make work, and also, to move.

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Answer:

The person above is correct, The Answer is "CONTRATION" just verified it by ap.ex ;)

Explanation:

The speed is 33.43 m/s and it traveled 189.06 meters in this time.

We can use the equation of motion for an object moving at constant acceleration to determine the speed after 7.50 seconds.

"v = v0 + at" 

where "v" stands for "final speed," "v0" for "starting speed," "a" for "acceleration," and "t" for "time."

The mass and net force can be used to compute the acceleration:

a = F/m = 4.30 x 105 N/3.5 x 10⁵ kg = 1.23 m/s²

Inputting the values into the previous equation results in:

v = 27 m/s + 1.23 m/s² x 7.50 s = 33.43 m/s

After 7.50 seconds, the speed is 33.43 m/s.

b. The following formula can be used to calculate the distance covered during this period of time: d = v0t + (1/2)². 

Thus, in 7.50 seconds, the 747 covered 189.06 meters.

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Answer:

no

Explanation:

Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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Answer:

Answer:120700.8

Explanation:

The power required to do all the work above is 2756.25 J / 20.5 s = 134.3 W.

To lift the 22.5 kg bag of trash 2.5 m off the ground, you did work against gravity. The work done can be calculated using the formula W = mgh, where m is the mass of the object, g is the acceleration due to gravity (\(9.8 m/s^2\)), and h is the height lifted. Therefore, W = \((22.5 kg)(9.8 m/s^2)(2.5 m)\) = 551.25 J.
To carry the bag of trash up a flight of stairs that are 10 m tall, you did work against gravity as well. The work done can be calculated using the same formula. Therefore, W = \((22.5 kg)(9.8 m/s^2)(10 m)\) = 2205 J.
The total work done on the bag of trash is the sum of the work done to lift it off the ground and the work done to carry it up the stairs. Therefore, the total work done is 2756.25 J.
To calculate the power required to do all the work above, we can use the formula P = W/t, where P is power, W is work done, and t is time.

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Answer:

the car you are in the cars have the same time frame and one covers more ground so on a possition time graph the slope will be greater

The resultant of the forces is 29 N. Option D

The resultant force is the force that acts in a given direction. Now we have two forces as enumerated in the question.

Thus;

Resultant = √(10)^2 + (20)^2 - [2 * 10 * 20 * cos (60 - 30))

Resultant = 29 N

Thus, the resultant of the forces is 29 N.

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Missing parts;

Two forces of magnitude 10N and 20N act on a body in directions making angles 30° and 60° respectively with x-axis what is the resultant force

A.17N

B. 19N

C. 23N

D. 29N

E. 37N​

When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:

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Answer:

3. Work

Explanation:

Number 1 isn't correct because you are not using efficiency to hold books and walk across the room.

Number 2 could be correct but isn't in this situation because you use power only to hold the books but not to walk across the room.

Number 4 is not correct because you need to do work to do something.

The true statement regarding the transverse waves should be option D. the direction at which the energy and the matter should be travel in the perpendicular direction.

It is the waves where the motion in which all the points should be on the wave oscillate along the paths at the right angles with respect to the wave of the direction. The example of this kind of waves should be electromagnetic, etc. In this, the directions where the energy and the travel of matter should be perpendicular to each other

Hence, the correct option is d.

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Explanation:

The average speed is equal to total distance over total time

The formula for distance is s=v×t

So the average speed would be:

v=(v1×t1)+(v2×t2)+(v3×t3)/t1+t2+t3

Now we can solve:

v=(54×20)+(36×30)+(18×10)/60s

v=2340/60

v=39km/h

If you need to convert to m/s, divide by 3.6 and you get 10.8333 m/s

Hope this helps!

The magnitude of the total acceleration for the race car is approximately 8.51 m/s^2.

A race car traveling with a constant tangential speed of 75.8 m/s around a circular track of radius 677 m experiences both centripetal and tangential acceleration. To find the magnitude of the total acceleration, we first need to determine the centripetal acceleration.

Centripetal acceleration (a_c) can be calculated using the formula:

a_c = v^2 / r

Where v is the tangential speed (75.8 m/s) and r is the radius of the track (677 m).

a_c = (75.8 m/s)^2 / 677 m ≈ 8.51 m/s^2

Since there is no change in the car's tangential speed, its tangential acceleration (a_t) is 0.

Now, to find the magnitude of the total acceleration (a_total), we use the Pythagorean theorem:

a_total = sqrt(a_c^2 + a_t^2)

a_total = sqrt((8.51 m/s^2)^2 + (0 m/s^2)^2) ≈ 8.51 m/s^2

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Explanation:

I hope this really can help you...

well done friend...

An object weighing 254.4 N and inclined at a 40° angle has a gravitational pull of 2380.5.

The formula of a Force is F=Mg.

Where M is the mass of an object, and g is the gravity.

\(F_{1}\)=254.4× 10, Value of gravity ≈ 10.

  = 2544

Here F ≠ Mg, due to an angle of 40°.

∴ \(F_{ax}= mass. cos \alpha\) .

 =  254.4× cos 40

As cos40 =0.766

=  254.4 ×  0.766

= 194.88

To find a Normal force, use the formula of  Gravitational pull.

\(F_{total} = F_{1}-F_{bx}\) , here \(F_{bx} = M. sin\alpha\) =163.5

= 2544-163.5

=2380.5

Hence Gravitational pull is 2380.5

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Answer:

the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.

Explanation:

a)  q_shell = -Q ,  b)  q_shell = -Q

a) We can solve this exercise using Gauss's law

Ф = ∫ E. dA =  /ε₀

For this we use a Gaussian surface that takes advantage of the symmetry of the problem, we select a sphere where this force of the spherical plastic shell.

In this case, the electric field lines coincide with the radii of the sphere and the scalar product reduces to the algebraic product, the area of ​​the sphere

     A = 4 π r²

fi = E 4π r² = q_{int} /ε₀

apply this formula to our case, we have that the charge inside the Gaussian sphere is

   q_{int} = q_sphere + q_shell

the charge of the sphere is Q and the requirement is that there is no electric field outside the Gaussian sphere, for this, the net charge inside it must be zero

      0 = Q + q_shell

      q_shell = -Q

b) In Gauss's law, only the charge inside the Gaussian surface matters, not its position, therefore if the charge is not in the center the result remains the same.

     q_shell = -Q

Please check the attached attachment for the detailed answer.

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The light travelling from sun to Jupiter in 43.33 minute.

Light can be define as, that it is electromagnetic radiation that can be detected by the human eye.

We are given that,

The distance from sun to Jupiter = d = 780 × 10⁵ km = 7.80 ×10¹¹m

The speed of light from the sun to Jupiter = v = 3.0 × 10⁸m/s

Therefore , to get the value of distance from sun to Jupiter by the equation is given as,

v = x/t

t = x/v

Where, t is the time taken by light from sun to Jupiter and x is the distance and v is shown speed of light from sun to Jupiter.

Then by putting the values in above equation we get,

t = (7.80 ×10¹¹m)/(3.0 × 10⁸m/s)

t = 2.6 ×10³ sec

t = (2.6 ×10³)/60 minutes

t = 43.33minutes

Thus, the light travelling from sun to Jupiter in 43.33minutes.

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To calculate the change in gravitational potential energy, we need to consider the initial and final potential energy of the four-particle system.

Initial potential energy (PE_initial): In this configuration, there are 6 unique pairs of particles, each separated by a distance d = 0.700 m. The gravitational potential energy for each pair can be calculated using the formula:

PE = -(G * m1 * m2) / r

where G is the gravitational constant (6.674 x 10^-11 N*(m/kg)^2), m1 and m2 are the masses of the particles (45.0 g = 0.045 kg), and r is the distance between the particles. Then, sum the potential energy of all 6 pairs.

Final potential energy (PE_final): When d is reduced to 0.150 m, we follow the same procedure, calculating the gravitational potential energy for each pair and summing the results.

Change in gravitational potential energy = PE_final - PE_initial

Use the given values and the formula to find the change in gravitational potential energy of the four-particle system.

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16.77m is the lemming's change in height when it reaches the water.

A thing is said to be in projectile motion when it has been fired into the air. After the initial force that launches the object, it only experiences the force of gravity. It is what it is—a projectile—and the path it took to get there is what it was.

You can tell from the situation that this projectile is a Type 1 projectile, or a horizontal projectile. Before you can resolve this issue, you will need a few things.

You must first examine the information you were given:

Vix = 2.87 m/s

dx = 5.32m

Your height or vertical distance are what you need. The following is the usual formula for projectile displacement:

d = Vit +1/2gt²

Specifically, you only need to enter the y-components to obtain the vertical distance. Now keep in mind that a horizontal projectile initially moves only forward and not vertically. Your vi = om/s, leaving you with the following equation:

dy = Viyt + 1/2 gt²

dy = (0m/s)t + 1/2 gt²

dy = 1/2 gt²

However, if you examine your issue, you will discover that no time has been allotted. You can resolve it using the information provided by deriving it from the x component formula:

dx = Vixt

Plug in your knowledge and find a solution for your ignorance.

dx = Vixt

5.32m = (2.87m/s)t

5.32/2.87= t

t = 1.85s

You can solve for your vertical distance/displacement now that you know the time:

dy = 1/2 gt²

dy = 1/2 (9.8 × 1.85²)

dy = 16.77m.

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Answer:

the answer is -16.8

Explanation:

it’s negative because your going down and you have to round off to match the significant digits.

Answer:

v = 10 m/s

Explanation:

We have,

Our initial velocity is 20 m/s

Our acceleration, \(a=-5\ m/s^2\)

It is required to find the velocity after 2 seconds. It is a concept based on equation of kinematics. Using first equation:

\(v=u+at\)

Plugging all the known values

\(v=20+(-5)(2)\\\\v=10\ m/s\)

So, our final velocity is 10 m/s.

Answer:

1. Fleming's left hand rule

2. It must be projected towards the east

Explanation:

Fleming's left-hand rule states that; When a current-carrying conductor is placed in an external magnetic field, the conductor experiences a force perpendicular to both the field and to the direction of the current flow. This rule was first put forward by John Ambrose Fleming in the later part of the nineteenth century.

Hence if the thumb, fore finger and middle finger of the lefthand are held mutually at right angles to each other; the thumb shows the direction of motion, the fore finger shows the direction of the field while the middle finger shows the direction of the current.

Hence, if the alpha particle is projected eastwards(at right angles) to the uniform magnetic field, it will be deflected southwards in the magnetic field.

Answer:

check explanation

Explanation:

Whenever we talk about velocity ,it means that we r telling them the speed of the object+the direction of the motion of object but here direction isn't mentioned. That's the fault in the statement

Efficiency of a system can never be greater than 100% as it is a ratio of the output work to the input work. In a situation where the efficiency is greater than 100%, this suggests that the output work is greater than the input work, which is impossible.

Calculation of the work done on the bucket of water The work done by the hand crank, W = Fd, where F is the force used to lift the bucket, and d is the distance over which the force is applied. The work done on the bucket is given by the equation W = mgΔh, where m is the mass of the bucket and water, g is the acceleration due to gravity, and Δh is the height the bucket is lifted. To determine the efficiency of the system, we must first calculate the work done on the bucket and then calculate the work done by the hand crank. To do so, we use the following equations:

The calculated efficiency is 196.61%, which is greater than 100%. However, this result is incorrect because it violates the first law of thermodynamics, which states that energy cannot be created or destroyed. As a result, the calculated value of efficiency is impossible. The error in the calculation is most likely due to the incorrect measurement of one of the parameters used in the calculation.

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