The various possible standing waves on a string are called harmonics. Harmonics are the various possible standing waves on a string. The standing waves are so-called because they appear to be stationary or standing.
The waves result from interference between the incident wave and its reflection from the fixed end of the string. The waves are of two types: transverse waves and longitudinal waves. A transverse wave is where the vibrations of the particles of the wave are perpendicular to the direction of propagation of the wave. On the other hand, a longitudinal wave is where the vibrations of the particles of the wave are parallel to the direction of propagation of the wave. These waves are used in musical instruments such as guitar strings to produce different notes.
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Can frictional forces ever increase an object’s kinetic energy?
Explanation:
friction opposes the relative motion between two bodies,hence it decreases the kinetic energy but, in the view that friction supplies the force that accelerates the object , for example friction helps in walking we can say that friction causes an increase in kinetic energy
Answer:
In most situations, frictional forces tend to reduce the kinetic energy of an object. However, frictional forces can sometimes increase an object's kinetic energy.
At what time does the oscillator shown below first reach its Equilibrium Position?
1864+7397=8199436 thats it
Answer:0.45s
Explanation:
Trust me
28,800 C of charge flow through a lamp every hour. Calculate the current used by this lamp
This lamp's estimated current consumption is 8 amperes.
What is electric current ?Electric current is the rate of charge (electron) passing in a conductor. The SI unit for electric current is the ampere. As current does not obey vector addition, it is a scalar quantity.
Given information:
amount of charge flowing through the lamp, Q = 28800 C;
The charge flow time was t = 1 hour = 3600 seconds.
Hence, the current passing through the bulb as a result.
I = Q/t
= 28800/3600 ampere,
= 8 ampere
Therefore, this lamp consumes 8 amperes of current.
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Haile's plane travels forward for a few feet and then begins to fall. What would explain the plane's ability to travel forward for a few feet without falling?
Answer:
Aircraft never crash because of one single issue. It's almost always a combination of factors that lead to an accident. Whilst flying is extremely safe, typical reasons why planes crash include pilot error, technical failures, bad weather, terrorism, and pilot fatigue.
Answer The force of the air pushing up on the plane is
equal to the force of gravity pulling down on the
plane.
when are electrical forces between charges normally strongest?
Electrical forces between charges are normally strongest when the charges are close together.
The repulsive or attractive interplay among any charged bodies is known as an electric-powered force. just like any pressure, its effect and effects on the given frame are defined by means of Newton's laws of motion. the electric force is one of the diverse forces that act on gadgets.
Electric-powered force is the attractive pressure between the electrons and the nucleus. Now, a nice price or a bad price creates a field inside the empty space around it, and we call that empty area an electric field. electrical forces result from mutual interactions between prices. In situations involving three or greater expenses, the electric force on a single charge is merely the result of the blended results of every character fee interplay of that price with all different charges.
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What percentage of electricity is generated by renewable energy in 2050?
By 2050, according to the International Renewable Energy Agency (IRENA), 90 percent of the world's electricity can and ought to come from renewable sources.
What is the anticipated 2050 electricity consumption?Through 2050, the EIA predicts that the world's electricity production will increase by 1.8% year. According to EIA estimates, global electricity production would increase by approximately 20 trillion kWh from 2018 levels to nearly 45 trillion kWh by 2050.
How much (%) of the electricity produced worldwide comes from renewable sources?This energy is required for electrical production, heating, and transportation. The world's electricity is generated by renewable sources, such as hydroelectric, solar, and wind energy, for about 30% of the time.
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What is the gravitational potential energy stored in a 60 kg boy sitting at the top of a 2 m high slide? (g = 10 N/kg)?
Answer:
1200 Joules
Explanation:
PE = mgh
PE = 60 * 10 * 2
PE = 1200 Joules
The gravitational potential energy stored in a \(60 Kg\) boy sitting at the top of a \(2 m\) high slide is \(1200 J\).
What is potential energy?Potential energy is the energy possessed by a body by virtue of its position relative to others.
\(U = mgh\)
Where,
\(U =\) potential energy
\(m =\) mass
\(h =\) height
\(g =\) acceleration due to gravity
It represents the potential an object has to do work as a result of being located at a particular position in a gravitational field.
The energy that a ball has when placed at a top of a steep hill while it is about to roll down is an example of potential energy.
Given:
\(m = 60 Kg\)
\(h = 2m\)
Potential energy is
\(U = mgh\\U = 60*10*2\\U = 1200 J\)
Potential energy is \(U = 1200 J\)
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9. A bicyclist is moving down a hill. Her position on the hill gives her 720 J of potential energy, and her
movement gives her 680 J of kinetic energy. What is her total mechanical energy?
A. 260 J
B. 1400 J
C. 2648 J
D. 2.86×105 J
The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.
The total mechanical energy of a moving object is the sum of its kinetic energy and potential energy. Kinetic energy is defined as the energy an object has due to its motion, whereas potential energy is the energy an object has due to its position or configuration.Therefore, the total mechanical energy of the bicyclist is calculated by adding her kinetic energy and potential energy. According to the question, the bicyclist has 720 J of potential energy and 680 J of kinetic energy.Total mechanical energy = Potential energy + Kinetic energy = 720 J + 680 J = 1400 JTherefore, the total mechanical energy of the bicyclist is 1400 J. Therefore, the correct answer is option B.For more questions on mechanical energy
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The table below shows some common animals and their hearing range in Hertz (Hz). Animal Hearing Range in Rate of Vibrations per Seconds (Hz) : Human: 20–20,000 Bat: 2,000–110,000 Elephant: 16–12,000 Dolphin: 90–105,000 Chicken: 125–2,000 Which animal has a hearing range most similar to that of a Human? *
A. Bat
B. Chicken
C. Dolphin
D. Elephant
Answer:
D
Explanation:
If you list and compare, the elephants hearing range is the closest to a humans.
Humans: 20-20,000
Elephant: 16-12,000
While the others are either too much more or less than a humans.
Bat: 2,000-110,000
Dolphin: 90-105,000
Chicken: 125-2,000
Which of the following most likely describes a Group 10 element?
O Good conductor of heat
O Gas at room temperature
O A member of the carbon group
O Poor conductor of electricity
Answer:
A. Good conductor of heat
Explanation:
The group 10 elements are a group of chemical elements as part of VIII elements and they include nickel, platinum, palladium etc. These group of chemical elements are all d-block transition metals, highly ductile and lustrous and are mostly white to light grey in color.
The statement which most likely describes a Group 10 element is that they are good conductor of heat because they have some of the chemical and physical properties of metals.
After a point charge, 7 Q, is placed inside the cavity of a conductor, electrostatic equilibrium is attained. After an additional charge of amount, -5Q, is placed on the surface of the inner cavity, electrostatic equilibrium is attained once again. What is the net charge on the inner and outer surfaces of the conductor, respectively
The net charge on the inner surface of the conductor is 7Q, while the net charge on the outer surface of the conductor is -5Q.
In electrostatic equilibrium, charges distribute themselves on the surface of a conductor in such a way that the electric field inside the conductor is zero. Based on this principle, we can analyze the situation step by step:
1. Initially, when the point charge of 7Q is placed inside the cavity of the conductor, the charge redistributes itself on the inner and outer surfaces of the conductor. In order to achieve electrostatic equilibrium, the charges on the inner and outer surfaces of the conductor must be such that the electric field inside the conductor is zero.
2. Since the conductor is electrically neutral, the net charge on the outer surface of the conductor will be equal in magnitude but opposite in sign to the charge inside the cavity. Therefore, the net charge on the outer surface is -7Q.
3. When an additional charge of -5Q is placed on the surface of the inner cavity, the charge redistributes again to achieve electrostatic equilibrium. The charge on the inner surface of the conductor will now be equal in magnitude but opposite in sign to the additional charge placed on the inner cavity. Hence, the net charge on the inner surface is -(-5Q), which simplifies to +5Q.
The net charge on the inner surface of the conductor is 5Q, while the net charge on the outer surface of the conductor is -7Q.
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Where in the galaxy are the most stars born?
Answer: Stars are formed in dust clouds and are found in most galaxies.
Explanation:
Answer: Stars form inside relatively dense concentrations of interstellar gas and dust known as molecular clouds.
Explanation:
a car cruising at 30 m/s (about 68 mph). if the kinetic friction coefficient between the tires and the road is 0.70 (when the road is dry), when the driver hits the brake, how far (approximately) will the car slide before it comes to a full stop? (g
The distance travelled by the car before it comes to a full stop is 65.59m if its initial velocity is 30m/sec.
Now, we need to find the distance of a car travelled, so we can use third equation of motion which is
v² - u² =2aS
where v is final velocity ,
u is the initial velocity
a is the acceleration
and S is the displacement of object
Since, final velocity of object is zero because car comes to rest
=>v=0,u=30m/sec, a=?,S=?
Now, we know that force applied by kinetic friction on car is given by =μmg where μ is coefficient of kinetic friction, m is the mass and g is the acceleration due to gravity
=>F=μmg ------eq1
Now,μ=0.70,m=?,g=9.8m/sec²
We also know that F=ma------eq2
Comparing eq1 and eq2
=>μmg=ma
=>a=μg
=>a=0.70ˣ9.8
=>a=6.86m/sec²
Now, 0² - (30)² = 2ˣ(-6.86)ˣS
=>900=2ˣ6.86ˣS
=>S=900/13.72
=>S=65.59m
Hence, car will travel 65.59m before coming to rest
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Blank is a good way to for me to see where I am going while
dribbling
Answer:
???
Explanation:
11.
2.4 g/mL x 15.82 mL
Answer:
The final solution is 38 g.
Explanation:
(2.4 (g / mL)) x 15.82 mL
= 37.96800 grams
When rounded, we get 38, so 38 g is the final solution.
Answer:
38 g is the answer
Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
A ______ focal length lens makes the background and foreground appear closer together.
Short focal length lens makes the background and foreground appear closer together.
What is a short focal length made lens?Short focal length lenses are sometimes known as wide-angle or wide-field lenses, which accurately defines their key characteristic—they view a larger angle of a scene than is typical.
When your eyes are fixed in one place and you look at a scene, a lens with a typical focal length captures what you see.
Are shorter focal lengths preferable?The angle of view is narrower, and the magnification is higher the longer the focal length.
What are short lenses used for?A shorter focal length results in a wider angle of view and a lower magnification.
Because they provide a broad field of view, short focal length lenses are frequently utilized in architectural, documentary, and landscape photography. These telephoto lenses enable
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Convert 1 metre per second square into 1 kilo metre per second square
1 meter per second squared is equivalent to 0.001 kilometer per second squared.
To convert 1 meter per second squared (m/s²) into kilometer per second squared (km/s²), we need to consider the conversion factor between meters and kilometers.
1 kilometer is equal to 1000 meters, so we can use this conversion factor to convert the units.
First, let's convert the acceleration from meters per second squared to kilometers per second squared:
1 m/s² = (1/1000) km/s²
Therefore, 1 meter per second squared is equal to 0.001 kilometer per second squared.
So, 1 m/s² = 0.001 km/s².
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The figure below shows electrons moving along an electric current towards and away from the light bulb. Electrons traveling along an electric current. Arrow under electrons points right and left both towards and away from the light bulb. Does this figure show a direct or alternating current?
The figure below showing electrons moving along an electric current towards and away from the light bulb with arrows pointing right and left in both directions, indicates that the current is alternating.
What is Electric Current?
It is the rate at which electric charges move through a circuit, measured in amperes (A). Electric current is caused by the movement of electrons, which carry a negative charge, and it flows from a region of higher electric potential to a region of lower electric potential.
Electric current can be produced by a variety of sources, including batteries, generators, and power plants. The amount of current that flows through a circuit depends on the voltage, or electric potential difference, and the resistance of the circuit. Ohm's law describes the relationship between these variables: current is equal to voltage divided by resistance (I = V/R).
In an alternating current (AC), the flow of electric charge changes direction periodically, typically 50 or 60 times per second (50 or 60 Hertz). The direction of the current reverses periodically, causing the electrons to move back and forth, as shown in the figure. In a direct current (DC), the flow of electric charge is always in one direction, and the electrons move in one direction only.
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3. What is the force acting on an object with a mass of 50kg and an acceleration of
10m/s2?
I
Answer:
500 Newtons
Explanation:
50 kg x 10 m/s squared
The figure shows the path of a charged particle moving in a magnetic field directed into the screen. What is the particle's charge? neutral positive negative
Based on the information, the particle is negatively charged.
What are magnetic field?Magnetic fields exert forces on other moving charge. The force a magnetic field exerts on a charge q moving with velocity v is called the Lorentz force.
It is given by F = qv × B.
To find the direction of the force, use the right-hand rule. Let the fingers of your right hand point in the direction of v. Orient the palm of your hand, so that as you curl your fingers, you can sweep them over to point into the direction of B. Your thumb points in the direction of the vector product v × B. If q is positive then this is the direction of F. If q is negative, your thumb points opposite to the direction of F.
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How does the 2-stroke engine work?
A two-stroke engine is a type of internal combustion engine that completes a power cycle in just two strokes of the piston instead of four as in a four-stroke engine.
The engine works by first drawing in a mixture of air and fuel into the cylinder through an intake port. As the piston moves upwards, it compresses the mixture, which is then ignited by a spark plug. This ignition causes a rapid combustion of the fuel mixture, generating a high-pressure wave that drives the piston downwards. As the piston moves back up, it expels the exhaust gases through an exhaust port. The cycle then repeats as the piston moves back down to draw in a new mixture of air and fuel. Two-stroke engines are lightweight, powerful, and commonly used in small vehicles like motorcycles, boats, and chainsaws.
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A small spherical object carries a charge of 8.00 nC. At what distance from the center of the object is the potential equal to 100-V, 50.0-V, 25.0-V? Is the spacing of the equipotentials proportional to the change in voltage?
The distances from the center of the spherical object for the given potentials are (a) 7.19 mm , (b) 14.4 mm , (c) 28.8 mm
determine the distance from the center of the spherical object at which the potential is equal to a specific value, we need to use the equation for the electric potential of a point charge:
V = k * (Q / r),
where V is the electric potential, k is the electrostatic constant (k ≈ 8.99 ×\(10^9\) N m²/C²), Q is the charge of the object, and r is the distance from the center of the object.
We can rearrange the equation to solve for r:
r = k * (Q / V).
Charge of the object (Q) = 8.00 nC = 8.00 × 10^(-9) C.
Electric potentials:
(a) V = 100 V
(b) V = 50.0 V
(c) V = 25.0 V
Using the values, we can calculate the distances for each potential:
(a) r = (8.99 × \(10^9\) N m²/C²) * (8.00 × \(10^{(-9)\) C) / 100 V = 7.19 × \(10^{(-3)\) m
(b) r = (8.99 × \(10^9\) N m²/C²) * (8.00 × \(10^{(-9)\) C) / 50.0 V = 1.44 × \(10^{(-2)\) m
(c) r = (8.99 × \(10^9\)N m²/C²) * (8.00 ×\(10^{(-9)\) C) / 25.0 V = 2.88 × \(10^{(-2)\) m
The distances from the center of the spherical object for the given potentials are :
(a) 7.19 mm
(b) 14.4 mm
(c) 28.8 mm
Consider the spacing of the equipotentials . The spacing of the equipotential surfaces is not directly proportional to the change in voltage.
We can see, the spacing between the equipotential surfaces is not constant.
The distances between the equipotential surfaces decrease as the voltage decreases. This implies that the spacing of the equipotentials is inversely proportional to the change in voltage.
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5. LaPlace's Law relates wall tension (γ) to the pressure (P) and radius (R) of cylindrical and spherical structures. (a) Write the form of LaPlace's equation that is used to calculate tension in spherical structures such as aneurysmal vessel segments and alveoli. ( 1.5pts) (b) Use LaPlace's Law for cylindrical structures to estimate the tension on the surface of a femoral artery having a diameter of 0.00660 m if the blood pressure is 15990 Pa (3.5 pts)
LaPlace's Law relates wall tension (γ) to the pressure (P) and radius (R) of cylindrical and spherical structures.
(a) The form of LaPlace's equation that is used to calculate tension in spherical structures is γ = (P * R) / 2.
(b) The tension on the surface of a femoral artery having a diameter of 0.00660 m if the blood pressure is 15990 Pa is 26.4675 Pa m.
(a) LaPlace's equation for tension in spherical structures, such as aneurysmal vessel segments and alveoli, is given by:
γ = (P * R) / 2
γ represents the wall tension,
P is the pressure inside the structure, and
R is the radius of the structure.
(b) To estimate the tension on the surface of a cylindrical structure, like a femoral artery, we can use LaPlace's Law for cylindrical structures:
γ = (P * r) / 2
γ represents the wall tension,
P is the pressure inside the structure, and
r is the radius of the structure.
Given:
Diameter of the femoral artery = 0.00660 m
Blood pressure = 15990 Pa
Convert the diameter to radius:
Radius (r) = Diameter / 2 = 0.00660 m / 2 = 0.00330 m
Now, we can substitute the values into LaPlace's Law for cylindrical structures:
γ = (15990 Pa * 0.00330 m) / 2
γ = 26.4675 Pa m
Therefore, the tension on the surface of a femoral artery having a diameter of 0.00660 m if the blood pressure is 15990 Pa is 26.4675 Pa m.
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An ion rocket engine produces 1 newton of thrust. What acceleration can it give to a space probe with a mass of 1000kg?.
By using the thrust force, the acceleration is 0.001 m/s².
We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as
F = m . a
where F is force, m is mass and a is acceleration
From the question above, we know that
F = 1 N
m = 1000 kg
By substituting the given parameters, we can calculate the acceleration
F = m . a
1 = 1000 . a
a = 1/1000
a = 0.001 m/s²
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Collisions in Two Dimensions: A 1500-kg car traveling at 90 km/h toward the east suddenly collides with a 3000-kg car traveling at 60 km/h toward the south. The two cars stick together after the collision. What is the speed of the cars after collision
The speed of the cars after the collision is approximately 19.47 m/s.
To determine the speed of the cars after the collision, we need to apply the principle of conservation of momentum.
The momentum of an object is given by the product of its mass and velocity: momentum = mass × velocity.
Given:
Mass of the first car (m₁) = 1500 kg
Velocity of the first car (v₁) = 90 km/h toward the east
Mass of the second car (m₂) = 3000 kg
Velocity of the second car (v₂) = 60 km/h toward the south
To use the principle of conservation of momentum, we need to convert the velocities to a common unit. Let's convert them to m/s.
Converting velocities:
v₁ = 90 km/h = (90 × 1000) / 3600 = 25 m/s (eastward)
v2 = 60 km/h = (60 × 1000) / 3600 = 16.7 m/s (southward)
The total momentum before the collision is equal to the total momentum after the collision, as momentum is conserved.
Total momentum before collision = Total momentum after collision
(m₁ × v₁) + (m₂ × v₂) = Total mass × Final velocity
(1500 kg × 25 m/s) + (3000 kg × 16.7 m/s) = (1500 kg + 3000 kg) × Final velocity
Simplifying the equation:
37500 kg·m/s + 50100 kg·m/s = 4500 kg × Final velocity
87600 kg·m/s = 4500 kg × Final velocity
Dividing both sides by 4500 kg:
Final velocity = 87600 kg·m/s / 4500 kg
Final velocity ≈ 19.47 m/s
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what must a uranium-235 nucleus absorb before fission will happen
Answer:
The arrangement of particles within uranium-235 is somewhat unstable and the nucleus can disintegrate if it is excited by an outside source. When a U-235 nucleus absorbs an extra neutron, it quickly breaks into two parts. This process is known as fission
Answer:
a nuetron
Explanation:
In a nuclear reactor , a neutron is absorbed into a nucleus (typically uranium-235). ... The fast moving neutrons carry most of the energy from the reaction with them (99%) but before the neutrons can collide with fresh uranium nuclei, they need to be slowed down
Part A
Which yoga poses did you perform best? Which poses do you still need to improve on?
Answer:
Knees to Chest
Be consistent. Setting and committing to a regular practice of yoga is absolutely essential if you want to make improvements. ..
Answer: Dog pose was really easy, but tree pose was really difficult because it was hard to balance.
A toy car move around a loop-the-loop track. The loop i 0. 5 high. What i the minimum peed of the car at the top of the loop for it to tay on track?
Pleae work it!!
I found all the anwer are 1. 57m/ but it i
0. 78m/
The minimum speed of the car at the top of the loop for it to stay on track be 1.57 m/s.
What is speed?The speed of an item, which is a scalar quantity in everyday usage and kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time.The speed at which an object's location changes in any direction.The distance traveled in relation to the time it took to travel that distance is how speed is defined.As a result, the fundamental unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.To learn more about speed refer to:
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A gas turbine power plant operating on a Brayton cycle takes in atmospheric air at 10°C. The temperature of the air rises by 200°C over the compressor, and by a further 722°C over the combustion chamber. If the heating value of the fuel burned in the turbine is 43 MJ/kg, calculate the rate in kg/s at which fuel must be burned for each MW of output from the power plant. Give your answer to three decimal places. Take the specific heat capacity cp of air to be 1.005 kJ/(kg K), and the ratio of specific heats k to be 1.4. You may also assume that changes in the properties of the air due to the addition and combustion of fuel are negligible.
The work done by the turbine per unit mass of air is given by,
\(W = c p (T 3 - T 4 ) \\= c p (T 2 - T 1 )Here, \\T1 = 283 K, \\T2 = T1 + 200 \\= 483 K, \\T3 = T2 + 722 \\= 1205 K, \\T4 = T1 + 273 \\= 556 Kc \\p = 1.005 kJ/(kg K)\)
Thus, the work done by the turbine is,
\(W = 1.005 (1205 - 556) \\= 680.745 kJ/kg\)
The fuel used by the turbine has a heating value of 43 MJ/kg. Thus, the fuel required per unit of work is given by, Fuel per unit of work \(= 43 × 10⁶ / 680.745\\ = 63034.8 kJ/kg\)
Answer: The fuel flow rate required for 1 MW output is 0.026 kg/s. The rate in kg/s at which fuel must be burned for each MW of output from the power plant is 0.026 kg/s.
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