the truncation error from one step to step another, also called local truncation error, in a runge-kutta method is given to you as of o(h3). the global truncation error in the runge-kutta method then is of o(hn).the value of n is .

Answer:

  38,200,000

Step-by-step explanation:

Put the 3 in the 8th spot to the left of the decimal point and fill in the other digits to the right of it.

  38,200,000

__

The first spot immediately to the left of the decimal point has a place value of 10^0, so the location with a place value of 10^7 is the 8th spot left of the decimal point. You should be able to get the idea from the attached.

__

If you put your calculator in the appropriate display mode, it should show you the number in this form.

according to the national institute on drug abuse, a u.s. government agency, 17.3% of 8th graders in 2010 had used marijuana at some point in their lives . Since all three conditions are satisfied, we can use the normal model to represent the distribution of sample proportions

Randomness: The sample must be selected randomly from the population. The problem states that the health department for the district uses anonymous random sampling, so the randomness condition is satisfied.

Independence: The sample size must be less than 10% of the population size. The problem does not give us the population size, but since the sample size is 80 and we are dealing with eighth-graders in a district, it is reasonable to assume that the population size is much larger than 800.

Success-Failure: The number of successes and failures in the sample must be at least 10. The number of eighth-graders in the sample who have used marijuana is 0.1 x 80 = 8. Both of these numbers are greater than 10, so the success-failure condition is also satisfied.

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Answer:

x = 25.3

Step-by-step explanation:

83.49 = 3.3x

divide both sides by 3.3

x = 25.3

The total of animals is a prime number and hence the ratio can only be expressed as fraction.

To find the ratio in the given question, we must first of all add the total sum of the animals given and then find the ratio to each one.

Total number of items given

\(12 + 5 + 6 = 23\)

The ratio of spiders to mosquitoes to rats are

\(\frac{12}{23}:\frac{5}{23}:\frac{6}{23}\)

The total sum of animals is a prime number and can't be divided, however, the ratio is expressed as simple as possible.

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The sets are equivalent to (1, 2) is none of above (option d)

In this case, we are given the set (1, 2) and asked to determine which of the provided sets are equivalent to it: (1) (1, 20), (2) N1 U N2, (3) (1, 1), or (4) none of the above. Let's analyze each option in detail to find the correct answer.

(1, 20):

This set includes all numbers between 1 and 20, excluding the endpoints. The elements in this set are 2, 3, 4, ..., 19. Therefore, this set is not equivalent to (1, 2) since it does not contain only the numbers 1 and 2. Therefore, option (a) is not correct.

N1 U N2:

The notation N1 and N2 is not universally defined, so we can't make any assumptions about the elements in these sets without further clarification. However, it is important to note that the set (1, 2) contains the elements 1 and 2. Therefore, for option (b) to be correct, both N1 and N2 must contain 1 and 2 as well. If that is the case, then the union of N1 and N2 will indeed be equivalent to (1, 2). Without more information about the nature of N1 and N2, we cannot definitively say whether option (b) is correct.

To summarize, option (a), (b) and option (c) are not equivalent to (1, 2).

Hence the correct option is (d).

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Answer:

15 2/3

Step-by-step explanation:

1 x 2/3 + 15=2/3+15=15 2/3

Answer: 15 2/3

Step-by-step explanation:

1. Times the 1 and the two-thirds.

1 * 2/3 = 2/3

2. Add two-thirds and fifteen.

2/3 + 15 = 15 2/3

Answer:

9is an irrationalnfunction which would be 0=y^2+x^2 while 10 is y=-x^2+3

The solution of this inequality are x ≤ 2 and x ≥ 4 which is shown in the graph below.

In Mathematics and Geometry, an inequality is a relation that compares two (2) or more numerical data, number, and variables in an algebraic equation based on any of the inequality symbols;

In this scenario and exercise, we would solve and graph the given inequalities for x in parts as follows;

(x – 2)(x – 4) ≥ 0

(x – 2) ≥ 0

(x – 2) + 2 ≥ 0 + 2

x - 2 ≥ 0

x ≤ 2 (solid dot with an arrow that points to the left on a number line).

(x – 4) ≥ 0

(x – 4) + 4 ≥ 0 + 4

x - 4 ≥ 0

x ≥ 4 (solid dot with an arrow that points to the right on a number line).

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The smallest total possible is 0, and the biggest total possible is 294. The average per draw is 3, and the standard deviation per draw is approximately 2.08. The expected value of the sum of 49 random draws is 147, and the standard error of the sum is approximately 6.91.

The smallest total possible when drawing 49 times with replacement from the given box is 0. The biggest total possible is 294. The average per draw, also known as the average of the box, is 3. The standard deviation per draw, or the SD of the box, is approximately 2.08. The expected value of the sum of 49 random draws is 147, and the standard error of the sum is approximately 6.91.

To calculate the smallest total possible, we need to select the smallest number in the box (which is 0) in all 49 draws. Thus, the smallest total is 0.

To calculate the biggest total possible, we need to select the largest number in the box (which is 6) in all 49 draws. Multiplying 6 by 49 gives us the biggest total possible, which is 294.

To find the average per draw, we sum up all the numbers in the box (0 + 2 + 3 + 4 + 6 = 15) and divide it by the number of elements in the box (5). This gives us an average of 3.

To calculate the standard deviation per draw, we first calculate the variance. The variance is the average of the squared differences from the mean. For each number in the box, we subtract the average (3), square the result, and sum up the squared differences. Dividing this sum by the number of elements in the box gives us the variance. Finally, taking the square root of the variance gives us the standard deviation per draw, which is approximately 2.08.

The expected value of the sum of 49 random draws is the product of the expected value per draw (3) and the number of draws (49), which gives us 147. The standard error of the sum can be calculated by taking the square root of the product of the variance per draw and the number of draws.

Since the variance per draw is the square of the standard deviation per draw, we can calculate the standard error of the sum as the product of the standard deviation per draw (approximately 2.08) and the square root of the number of draws (7), which gives us approximately 6.91.

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Answer:

Solving the inequality we get: \(\mathbf{x>-7}\)

Step-by-step explanation:

We need to solve and graph the inequality \(3(7x+17) > -19 + 14x\)

Solving:

\(3(7x+17) > -19 + 14x\)

Step 1: Multiply  3 with terms inside the bracket

\(21x+51 > -19 + 14x\)

Step 2:Subtracting 51 on both sides

\(21x+51-51 > -19 + 14x-51\\21x>14x-70\\\)

Step 3: Subtract 14x on both sides

\(21x-14x>+14x-70-14x\\7x>-70\)

Step 4: Divide both sides by 7

\(\frac{7x}{7}>\frac{-70}{7}\\x>-10\)

Solving the inequality we get: \(\mathbf{x>-7}\)

The graph is attached in the figure below.

Answer:

The resistivity of the conductor can be calculated by multiplying the slope by the area.

Step-by-step explanation:

The theorem that proves that the triangles are congruent is the Side-Side-Side (SSS) Congruence Theorem.

The Side-Side-Side (SSS) Congruence Theorem states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent. This theorem is useful for proving that two triangles are congruent without having to use angles. The SSS Congruence Theorem is a useful tool for solving geometry problems involving triangles. It can be used to find the unknown side length of a triangle given the lengths of the other two sides, or in more complicated proofs involving multiple triangles. This theorem is also helpful in determining the area of a triangle, as the area is proportional to the product of the lengths of the sides.

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(a) To calculate the probability of exactly half of the spins landing on black, we need to consider the number of ways we can choose exactly five out of the ten spins to land on black. The probability of a single spin landing on black is 18/38, and the probability of a single spin landing on red (since there are only two possibilities) is 20/38.

We can use the binomial probability formula to calculate the probability:

P(X = k) = C(n, k) * p^k * q^(n-k)

where:

P(X = k) is the probability of exactly k successes,

C(n, k) is the number of combinations of n items taken k at a time,

p is the probability of success on a single trial, and

q is the probability of failure on a single trial.

For exactly half of the spins (k = 5), the probability can be calculated as:

P(X = 5) = C(10, 5) * (18/38)^5 * (20/38)^5

Calculating this expression will give us the probability that exactly half of the spins land on black.

(b) To calculate the probability of at least eight spins landing on black, we need to consider the probabilities of eight, nine, or ten spins landing on black and add them up.

P(X ≥ 8) = P(X = 8) + P(X = 9) + P(X = 10)

Using the same binomial probability formula, we can calculate each of these probabilities:

P(X = 8) = C(10, 8) * (18/38)^8 * (20/38)^2

P(X = 9) = C(10, 9) * (18/38)^9 * (20/38)^1

P(X = 10) = C(10, 10) * (18/38)^10 * (20/38)^0

By calculating these expressions and summing them up, we can determine the probability of at least eight spins landing on black.

Please note that the calculations provided are based on the assumption of a fair roulette wheel with 18 black spaces out of 38 total spaces.

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Answer:-3

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

Multiply it by 1/3 and it equals 16

Answer:

16

Step-by-step explanation:

48/3=16

Respuesta:

que es una igualdad?

R// es la proposición de equivalencia existenten entre dos exprisiones algebraicas conectadas a através del signo = en la cual, ambas expresan el mismo valor .

¿Qué relación hay entre una ecuación y una igualda?

R// una ecuación solo cumple el igual para determinados valores de la variable; mientras que la igualdad la cumple siempre, sea el valor de la variable.

perdón solo eso se

To calculate the difference in the number of tickets sold to Europe and Asia during the three-month period, we need to sum up the number of tickets sold to each region separately.

Tickets sold to Europe:

September: 1200

October: 2000

November: 1000

Total tickets sold to Europe: 1200 + 2000 + 1000 = 4200

Tickets sold to Asia:

September: 1400

October: 750

November: 900

Total tickets sold to Asia: 1400 + 750 + 900 = 3050

To find the difference, we subtract the total tickets sold to Asia from the total tickets sold to Europe:

Difference = Tickets sold to Europe - Tickets sold to Asia

Difference = 4200 - 3050

Difference = 1150

Therefore, during the three-month period, 1150 more tickets were sold to Europe than to Asia.

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The volume of the cylinder is 188.4m³.

It should be noted that from the diagram given, there is a cylinder. It should be noted that the volume of a cylinder is given as:

= πr²h

where,

r = radius = 4m/2 = 2m

h = height = 15m

Therefore, the volume of the cylinder will be:

=πr²h

= 3.14 × 2² × 15

= 188.4m³

Therefore, the volume of the cylinder is 188.4m³.

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The curve is y = In(sec(x)) and we have to find its length. We are given the range as 0 ≤ x ≤ π/4. So, the formula for the length of the curve is given as:

To solve for the length of the curve of y = In(sec(x)), we use the formula,

`L = ∫[a,b] √[1+(f′(x))^2] dx`.Where, `a = 0` and `b = π/4`. And `f′(x)` is the derivative of `In(sec(x))`.

We know that:`f′(x) = d/dx[In(sec(x))]`

Using the formula of logarithm differentiation, we can write the above equation as:

`f′(x) = d/dx[In(1/cos(x))]`

So,`f′(x) = -d/dx[In(cos(x))]`

Therefore,`f′(x) = -sin(x)/cos(x)`

Substituting the values, we get:

`L = ∫[a,b] √[1+(f′(x))^2] dx`

`L = ∫[0,π/4] √[1+(-sin(x)/cos(x))^2] dx`

`L = ∫[0,π/4] √[(cos^2(x)+sin^2(x))/(cos^2(x))] dx`

`L = ∫[0,π/4] sec(x) dx`

Now, `L = ln(sec(x) + tan(x)) + C` where `C` is a constant.

We calculate the constant by substituting the values of `a = 0` and `b = π/4`:

`L = ln(sec(π/4) + tan(π/4)) - ln(sec(0) + tan(0))`

`L = ln(√2 + 1) - ln(1 + 0)`

`L = ln(√2 + 1)`

Thus, the exact length of the curve is `ln(√2 + 1)` units.

Thus, the exact length of the curve of y = In(sec(x)), 0≤x≤π/4 is `ln(√2 + 1)` units.

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The values areas are:

Figure 1 = 69.81 in²

Figure 2 = 192.50 ft²

Figure 3 = 153.50 yd²

Figure 4 = 296.00 in²

Figure 5 = 126.00 ft²

Figure 6 = 26.30 ft²

This exercise requires your knowledge about the area of compound shapes. For solving this, you should:

The steps and solutions for each given figure are presented below.

The figure 1 is composed by a rectangle and a semicircle. Therefore, you should sum the area of these geometric figures.

Area of rectangle  - \(A_{rectangle}=l.w\), where:

l= length (12 in)and w=width (5 in).

\(A_{rectangle}=l.w=12*5=60 in^{2}\)

Area of semicircle- \(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*r^{2} }{2}\), where:

r= radius ( \(\frac{w}{2} =\frac{5}{2} =2.5\)) and π = 3.14

\(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*2.5^{2} }{2}=9.81 in^{2}\)

Therefore, \(A_{fig1}= 60 + 9.81=69.81 in^{2}\).

The figure 2 is composed by a parallelogram and a trapezoid. Therefore, you should sum the area of these geometric figures.

Area of parallelogram - \(A_{parallelogram}=b.h\), where:

b= length of the base (11 ft)and h=height (7 ft).

\(A_{parallelogram}=b.h=11*7=77ft^{2}\)

Area of trapezoid - \(A_{trapezoid}=\frac{(a+b)*h}{2}\), where:

a= long base (20-7=13 ft ), b = short base (8 ft) and height (11 ft)

\(A_{trapezoid}=\frac{(a+b)*h}{2}=\frac{(13+8)*11}{2}=\frac{21*11}{2}=\frac{231}{2}=115.50\)

Therefore, \(A_{fig2}= 77+ 115.5=192.50 ft^{2}\).

The figure 3 is composed by a triangle and a trapezoid. Therefore, you should sum the area of these geometric figures.

Area of triangle - \(A_{triangle}=\frac{b*h}{2}\), where:

b= length of the base (19 yd) and h=height (7 yd).

\(A_{triangle}=\frac{b*h}{2} =\frac{19*7}{2} =\frac{133}{2}= 66.5 yd^{2}\)

Area of trapezoid - \(A_{trapezoid}=\frac{(a+b)*h}{2}\), where:

a= long base (19 yd ), b = short base (10 yd) and height (13-7=6 yd)

\(A_{trapezoid}=\frac{(a+b)*h}{2}=\frac{(19+10)*6}{2}=\frac{29*6}{2}=29*3=87 yd^2\)

Therefore, \(A_{fig3}= 66.5+ 87=153.50 yd^{2}\).

The figure 4 is composed by two rectangles. Therefore, you should sum the area of these geometric figures.

Area of rectangle 1  - \(A_{rectangle}=l.w\), where:

l= length (16+5=21 in)and w=width (8 in).

\(A_{rectangle}=l.w=21 *8=168 in^{2}\)

Area of rectangle 2  - \(A_{rectangle}=l.w\), where:

l= length (16 in)and w=width (5 in).

\(A_{rectangle}=l.w=16*8=128 in^{2}\)

Therefore, \(A_{fig4}= 168+ 128=296.00 in^{2}\).

The figure 5 is composed by a square and a parallelogram. Therefore, you should sum the area of these geometric figures.

Area of square - \(A_{square}=l^2\), where:

l= length (9 ft).

\(A_{square}=l^{2}=9^2=81 ft^{2}\)

Area of parallelogram - \(A_{parallelogram}=b.h\), where:

b= length of the base (9 ft)and h=height (14-9=5 ft).

\(A_{parallelogram}=b.h=9*5=45ft^{2}\)

Therefore, \(A_{fig5}= 81+ 45=126.00 ft^{2}\)

The figure 5 is composed by a triangle and a semicircle. Therefore, you should sum the area of these geometric figures.

Area of triangle - \(A_{triangle}=\frac{b*h}{2}\), where:

b= length of the base (6 yd) and h=height (4 yd).

\(A_{triangle}=\frac{b*h}{2} =\frac{6*4}{2} =\frac{24}{2}= 12 yd^{2}\)

Area of semicircle- \(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*r^{2} }{2}\), where:

r= radius ( \(\frac{6}{2} =3\)) and π = 3.14

\(A_{semicircle}=\frac{Area circle}{2}=\frac{\pi*3^{2} }{2}=14.3 yd^{2}\)

Therefore, \(A_{fig6}= 12+ 14.3=26.3 yd^{2}\)

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Answer: A

Step-by-step explanation:

A. Cleaning windows more often is associated with vacuuming more often. This relationship most likely reflects correlation but not causation because it is possible that these two activities are related, but not necessarily because one causes the other. For example, it is possible that the increased frequency of vacuuming is unrelated to the increased frequency of window cleaning and is actually due to other factors such as the amount of time spent at home.

The statement 'A. Cleaning windows more often is associated with vacuuming more often' most likely represents correlation but not causation, as one activity does not necessarily lead to the other.

The statement 'A. Cleaning windows more often is associated with vacuuming more often' most likely reflects a correlation but not causation. This implies that although the two activities may happen together, one does not necessarily cause the other. For instance, a person could clean the windows without necessarily vacuuming more often.

Whereas, in option B and C, having more dogs and hosting dinner parties could possibly lead to vacuuming more often due to increased dirtiness and cleanliness needs, thus indicating a probable causation.

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The value of x based on the equation given as 3(4x + 6) = 9x + 12 is -2.

It should be noted that an equation shows that relationship between the variables that are given or illustrated in the data.

The value for x based on the equation will be:

3(4x + 6) = 9x + 12

Open bracket

12x + 18 = 9x + 12

Collect like terms

12x - 9x = 12 - 18

3x = -6

Divide

x = -6/3

x = -2

Therefore, x is -2.

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If we are to estimate the first derivative of f(x) = e-x-x2 at x= 5 using the step size h = 0.5, the correct statements are:

A) The result of the forward difference ≈ -9.5087.

B) The result of the central difference ≈ -10.0070.

D) Halving the step size h will halve the error of the backward and forward differences and quarter the error of the central difference.

To estimate the first derivative of f(x) = e^(-x-x^2) at x = 5 using the step size h = 0.5, we can calculate the forward difference, central difference, and backward difference approximations.

The forward difference approximation is given by:

f'(x) ≈ [f(x + h) - f(x)] / h

Substituting the values:

f'(5) ≈ [f(5 + 0.5) - f(5)] / 0.5

f'(5) ≈ [f(5.5) - f(5)] / 0.5

Similarly, the central difference approximation is given by:

f'(x) ≈ [f(x + h) - f(x - h)] / (2h)

Substituting the values:

f'(5) ≈ [f(5 + 0.5) - f(5 - 0.5)] / (2 * 0.5)

f'(5) ≈ [f(5.5) - f(4.5)] / 1

And the backward difference approximation is given by:

f'(x) ≈ [f(x) - f(x - h)] / h

Substituting the values:

f'(5) ≈ [f(5) - f(5 - 0.5)] / 0.5

f'(5) ≈ [f(5) - f(4.5)] / 0.5

To evaluate the statements:

A) The result of the forward difference is approximately -9.5087: We can calculate this approximation using the formula above.

B) The result of the central difference is approximately -10.0070: We can calculate this approximation using the formula above.

C) The result of the backward difference is approximately -10.5053: We can calculate this approximation using the formula above.

D) Halving the step size h will halve the error of the backward and forward differences and quarter the error of the central difference: This statement is correct. When we halve the step size h, the error in the forward and backward differences will decrease by a factor of 2, and the error in the central difference will decrease by a factor of 4.

Therefore, the correct statements are:

A) The result of the forward difference ≈ -9.5087.

B) The result of the central difference ≈ -10.0070.

D) Halving the step size h will halve the error of the backward and forward differences and quarter the error of the central difference.

Your question is incomplete but most probably your full question was

If We Are To Estimate The First Derivative Of F(X) = E-X-X2 At X= 5 Using The Step Size H = 0.5, Which Of The Following Statement Are Correct? (Select Multiple Answers) A) The Result Of Forward Difference ≈ -9.5087. B) The Result Of Central Difference ≈ -10.0070. C) The Result Of Backward Difference ≈ -10.5053. D) Halving The Step Size H Will Halve The

If we are to estimate the first derivative of f(x) = e-x-x2 at x= 5 using the step size h = 0.5, which of the following statement are correct? (Select multiple answers)

A) The result of forward difference ≈ -9.5087.

B) The result of central difference ≈ -10.0070.

C) The result of backward difference ≈ -10.5053.

D) Halving the step size h will halve the error of the backward and forward differences and quarter the error of the central difference.

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There is a significant relationship between y and both x1 and x2.

MSR = 306.625, MSE = 30.844b. F = 9.939 and p-value = 0.007. At a = 0.05, the overall model is significant.

tB₁ = 7.301 and p-value = 0.0009. At a = 0.05, there is a significant relationship between y and x1. d. tB₂ = 4.771 and p-value = 0.0008. At a = 0.05, there is a significant relationship between y and x2.

In a regression model, the F-test is used to determine whether the regression coefficient as a whole is statistically significant or not.

The p-value of the F-test is compared to the significance level (α) to determine statistical significance.

If the p-value is less than α, the regression coefficient as a whole is considered statistically significant. If it is greater than α, then it is not statistically significant.

t-test is used to determine whether each individual regression coefficient is statistically significant or not.

The p-value of the t-test is compared to the significance level (α) to determine statistical significance.

If the p-value is less than α, the regression coefficient is considered statistically significant.

If it is greater than α, then it is not statistically significant.

In this question, the F-test is significant at a = 0.05, and the t-test for both x1 and x2 is significant at a = 0.05.

Therefore, there is a significant relationship between y and both x1 and x2.

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Answer:

m = -5

Step-by-step explanation:

solve for x.

FILLER