The temperature dropped from 27 degrees to -4 degrees in one day. Write and solve an expression to represent the
change in degrees. also with give branly to who answers first

Answer:

find my dad

Step-by-step explanation:

The correct response is b. y = 197,910(1.069)^t. 197,910 people called Greensboro, North Carolina, home in 1984. Since 1984, Greensboro's population has been declining at an average rate of 6.9% per year, according to the U.S. Census Bureau.

The average rate at which one quantity changes in relation to another's change is referred to as the average rate of change function. An average rate of change function is a calculation that divides the amount of change in one item by the corresponding amount of change in another. Below are some examples of typical change rates: The typical bus speed is 80 km/h. Fish populations in lakes increase at a rate of 100 each week. For every 1 volt drop in voltage, an electrical circuit's current reduces by 0.2 amps.

The population of Greensboro t years after 1984 is y = 197,910(1.069)^t.

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With 90% confidence interval that the true mean score of all students lies between 71.58 and 83.22 based on the six scores that were randomly selected by the principal.

To calculate the confidence interval, we first need to find the sample mean and standard deviation of the six scores. The sample mean is simply the average of the scores, which can be calculated by adding all the scores together and dividing by the number of scores:

sample mean = (81.4 + 78.6 + 71.3 + 77.8 + 76.9 + 77.7) / 6 = 77.4

The sample standard deviation measures the amount of variation or spread in the scores. It can be calculated using the following formula:

s = √((1/n-1) x Σ(xi - x)²)

where s is the sample standard deviation, n is the sample size (in this case, n = 6), xi is each individual score, and x is the sample mean.

Using this formula, we get:

s = √((1/5) x ((81.4 - 77.4)² + (78.6 - 77.4)² + (71.3 - 77.4)² + (77.8 - 77.4)² + (76.9 - 77.4)² + (77.7 - 77.4)²))

s ≈ 3.19

Now that we have the sample mean and standard deviation, we can use them to calculate the confidence interval. The formula for a confidence interval for the mean is:

CI = x ± (tα/2 x s / √(n))

where CI is the confidence interval, x is the sample mean, tα/2 is the critical t-value for the desired level of confidence and degrees of freedom, s is the sample standard deviation, and n is the sample size.

For a 90% confidence interval with five degrees of freedom, the critical t-value is approximately 2.571. Plugging in the values, we get:

CI = 77.4 ± (2.571 x 3.19 / √(6))

CI ≈ (71.58, 83.22)

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Answer:

120 cm³

Step-by-step explanation:

area of base = 4 × 9 = 36 cm²

Vol = \(\frac{1}{3}\) × 36 × 10 = 12 × 10 = 120 cm³

Answer:

2 acres

Step-by-step explanation:

For 2 1/4 hours he mows 1/2 of an acre

I know that 1/4 of an hour is 15 minutes so I added 2 hours and 14 minutes 4 times to get 9 hours.

Now I know 2 1/4 of an hour times 4 equals 9 hours

1/2 an acre times 4 equals 2

He mows 2 acres

The distribution for X is a negative binomial distribution, denoted as nb(x;6, 188​), with parameters r = 6 (number of successes), p = 8/18 (probability of success in each trial).

To compute the probabilities:

P(X = 2): nb(2;6, 8/18)

P(X ≤ 2): nb(0;6, 8/18) + nb(1;6, 8/18) + nb(2;6, 8/18)

P(X ≥ 2): 1 - P(X < 2) = 1 - P(X ≤ 1)

To calculate the mean value and standard deviation of X:

Mean (μ) = r * (1 - p) / p

Standard Deviation (σ) = sqrt(r * (1 - p) / (p^2))

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Answer:

there is only one way to to roll a 3

1/36 = .044 = 4.4%

Step-by-step explanation:

Angles ECD  and CEF add to 180

40+140 = 180

So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.

In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.

--------------

So far we have

AB || CD

CD || EF

Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.

It's like saying "P --> Q and Q --> R, therefore P --> R"

Answer:

9/70

Step-by-step explanation:

X-3/10 for x= 3/7

3/7-3/10

9/70

858 combinations are there to choose 10 players to take the field.

Pick 10 people from 13,

\(C^{13} _{10}\) = \((^{13} _{2} )\)

Splitting the combination,

\(C^{13} _{10}\) = (13 × 12 × 11) ÷ 2

\(C^{13} _{10}\) = 1716 ÷ 2

\(C^{13} _{10}\) = 858 ways to pick the 10 to play.

There are 858 different methods to select 10 players to take the pitch.

The permutations of a set are the vaguely defined community of its members in arrangement or linear order, or the permutation of its components if the set is already collected. The act or procedure of adjusting the linear ordering of a sorted set is often named "permutation".

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Answer:

WV=24

Step-by-step explanation:

As the diagonals of a paralellogram bisect each other,

b+18=4b

b=6

WV=6+18=24

Answer:

4.1

Step-by-step explanation:

You would first subtract 55.50 from 71.90 which leaves you with 16.4,

Then you would divide 16.4 by 4 to find how many gigabytes she could use which gives you 4.1

Hope this helped

Answer:

4.1

Step-by-step explanation:

Each chart consists of a center line representing the average, an upper line indicating the maximum acceptable deviation upwards, and a lower line indicating the maximum acceptable deviation downwards. These components help analyze data and monitor process performance.Option B,E,F.

Each chart has the following three components:

1. B. A center line representing the average: This line is drawn to show the average value or mean of the data being analyzed. It provides a reference point to compare the data points above and below it.

2. E. An upper line representing the maximum acceptable variation upwards: This line is drawn to indicate the upper limit of acceptable variation or deviation from the average. It helps identify if the data points exceed the acceptable range.

3. F. A lower line representing the maximum acceptable variation downwards: This line is drawn to indicate the lower limit of acceptable variation or deviation from the average. It helps identify if the data points fall below the acceptable range.

These three components together create a control chart, which is a graphical representation used in statistical process control. Control charts help monitor and analyze data over time, allowing organizations to identify trends, detect abnormalities, and make data-driven decisions to improve processes and quality.

In summary, each chart consists of a center line representing the average, an upper line indicating the maximum acceptable deviation upwards, and a lower line indicating the maximum acceptable deviation downwards. These components help analyze data and monitor process performance.

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Answer:

C.) x/3 -4 = -20

Step-by-step explanation:

x = -48

= -48/3 - 4 ==> -16-4 ==> -20

hence, Option C.) satisfies the condition.

Answer:

See below.

Step-by-step explanation:

Rectangle - c = √a²+b² = √6²+12² = 13.41641, or 13.42

Square - c = √a²+b² = √6²+6² = 8.48528, or 8.49

He is incorrect. 13.42 halved is 6.71, not 8.49.

-hope it helps

the equation that models the baby's weight is:
y = 1.5x + 7To model the baby's weight as it grows, we can use the equation y = mx + b, where y represents the weight in pounds and x represents the age of the baby in months.

Given that the baby weighs 13 pounds at 4 months and is expected to gain 1.5 pounds each month, we can determine the equation:

y = 1.5x + b

To find the value of b, we substitute the given information that the baby weighs 13 pounds at 4 months:

13 = 1.5(4) + b

Simplifying the equation:

13 = 6 + b
b = 13 - 6
b = 7

, the equation that models the baby's weight is:
y = 1.5x + 7

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True. The HMAC-based one-time password algorithm uses a mathematical algorithm to generate a unique password for each login attempt.

This algorithm combines a secret key and a counter to produce a one-time password that is difficult to guess or duplicate. The algorithm is designed to be secure and reliable, providing an additional layer of protection for user accounts. By using a different password for each login attempt, the algorithm helps prevent attackers from gaining access to a user's account even if they manage to intercept the password. Overall, the HMAC-based one-time password algorithm is an effective way to enhance the security of online accounts and protect against unauthorized access.

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Answer:

$6.25 for each CD

Step-by-step explanation:

6.25 x 400 = 2,500

2,500 - 2,000 = 500

there is a 500 profit

Answer:

The answer to the chart is y=x-1

The goal is to determine whether or not the following binary operations are closed.

A. Subtraction of positive integers: Under normal substation operation, a set of positive integers is not near. Since 1∈Ζ⁺ and 2∈Ζ⁺ but (2-1) = ₋1∉Z⁺.

B. A division of nonzero integers: Non-zero integer set Z/{0} is not closed under the operation. Since 1∈Z/{0} and 2∈ Z/{0} but 1/2 ∉ Z/{0}.

C.  Function composition of polynomials with real coefficients: The set of polynomials with real coefficients is closed when using the typical binary operator. Use the obvious conclusion that a polynomial is a combination of two polynomials \(f(x)\) and \(g(x)\). Since every polynomial coefficient is real, every polynomial's composition will also have real coefficients.

D. The multiplication of 2×2 matrices with integer entries: Under the action of standard matrix multiplication Μ₂ₓ₂ (Z), the collection of matrices with integer elements, is close.

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The amount Jerry paid in interest is $1,040.

Given to us,

Jerry's principal amount = $ 22,000,

quarterly payment for each quarter = $ 640

Total time for which Jerry paid each quarter = 9 years

As We know that in a year there are 4 quarters,

so, \(\rm 1\ year = 4\ quarters\),

\(\rm 9\ year = 9\times 4\ quarters\),

9 years = 36 quarters,

The total amount paid by Jerry for nine years in each quarter =

quarterly payment for each quarter x no. of quarters for which amount paid

\(\rm Total\ amount\ paid\ by\ Jerry\ for\ nine\ years\ in\ each\ quarter = \$640\times 36 quarters = \$23,040\)

Thus, the total amount paid by Jerry for nine years in each quarter is $23,040.

Therefore,

\(\rm Amount\ Jerry\ pay\ in\ interest = Amount\ Jerry\ paid- Principal\ amount\),

\(\rm Amount\ Jerry\ pay\ in\ interest = \$23,040-\$22,000 = \$1040\)

Hence, the amount Jerry paid in interest is $1,040.

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The total charge enclosed by the given volume is π(31/2000).

For the total charge enclosed by the given volume, we can apply Gauss's law, which relates the flux of the electric field through a closed surface to the charge enclosed inside the surface:

Φ = Q / ε₀

where Φ is the electric flux through the surface, Q is the charge enclosed by the surface, and ε₀ is the electric constant.

Let us choose a spherical surface centered at the origin, with radius ρ and surface area A = 4πρ².

since the region of interest is limited to 0 < p < 1, 0 < z < 1, and 0 < φ < π/2, we only need to consider the portion of the sphere that lies within this region, which is a spherical cap.

The normal vector to the surface at every point is (ρ, θ, φ), where θ is the azimuthal angle and φ is the polar angle.

Since the electric flux density D is given in Cartesian coordinates, we need to express it in terms of spherical coordinates. Using the conversion formulas, we get:

D(ρ, θ, φ) = 2πρ(cos φ + sin φ cos θ)ρ  + π² cos φ φ

where ρ and φ are the unit vectors in the radial and azimuthal directions, respectively.

Now, we have used the fact that θ = 0, since the problem is rotationally symmetric around the z-axis.

The electric flux through the spherical cap is then:

Φ = ∫∫ D(ρ, θ, φ) · dA = ∫∫ D(ρ, θ, φ) · ( ρ^ dA)

= ∫∫ D(ρ, θ, φ) ρ² sin φ dθ dφ

where the integral is taken over the surface area of the spherical cap.

Since, we have used the fact that the angle between the normal vector and the radial direction is φ, so the dot product simplifies to the magnitude of D times the component in the radial direction.

Substituting the expression for D and the limits of integration, we get:

Φ = ∫0 to (π/2) ∫0 to (2π) [2πρ³(cos φ + sin φ cos θ) + π²ρ² cos φ] sin φ dθ dφ

= 2π ∫0 to (π/2) sin φ dφ ∫0 to (2π) [2ρ³(cos φ + sin φ cos θ) + πρ² cos φ] dθ

= 4π ∫0 to (π/2) sin φ dφ ∫0 to (π/2) [2ρ³(cos φ + sin φ cos θ) + πρ² cos φ] dθ

= 4π ∫0 to (π/2) [2ρ³ sin φ + πρ² sin φ cos φ] dφ

= 2π(ρ⁴ + π/4ρ²)

where we have used the fact that the integral over θ gives 2π, and that the integrand is symmetric in θ so we can integrate over half of the interval and multiply by 2.

Now, we can equate this expression to Q/ε₀, where ε₀ is the electric constant.

Solving for Q, we get:

Q = ε₀ Φ = (1/4π) (2π(ρ⁴ + π/4ρ²))

= ρ⁴/2 + π/8

To find the total charge enclosed by the volume, we need to integrate this expression over the volume:

Q_total = ∫₀¹ ∫₀¹ ∫0 to (π/2) (ρ⁴/2 + π/8) ρ² sin φ dρ dz dφ

= (π/16)[(1/5)⁵ - (1/2)⁵] + (π/8)[(1/5)² - (1/2)²]

= π(31/2000)

Therefore, the total charge enclosed by the given volume is π(31/2000).

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This equation has complex solutions and that means the system has no nontrivial solutions for real value of lambda.

\(\lambda = \frac{-6±\sqrt{-164} }{4} \\\)

Now, According to the question:

Nontrivial Solutions of a System:

System of equations has a form:

AX = 0, X = (x , y, z)

System of equations has a nontrivial solutions if a determinant of a system is zero. If the determinant is not zero than the matrix has inverse and a nontrivial solution x=0. This can be said differently: The homogeneous system has the trivial solution if rank of A in the row reduced form of matrix is equal to the number of unknown variables. If rank of A is less than the number of variables then the system has nontrivial solutions.

λx + 2y + z = 0

x + 5y + 2z = 0

3x - λy + z= 0

So, we calculate and determinant :

\(\left[\begin{array}{ccc}\lambda&2&-1\\1&5&2\\3&-\lambda&1\end{array}\right]\)  \(= \lambda det\left[\begin{array}{ccc}5&2\\-\lambda&1\end{array}\right]\) \(-2det\left[\begin{array}{ccc}1&2\\3&1\end{array}\right]\) \(det\left[\begin{array}{ccc}1&5\\3&-\lambda\end{array}\right]\)

\(=2\lambda^2+6\lambda+25=0\)

This equation has complex solutions and that means the system has no nontrivial solutions for real value of lambda.

\(\lambda = \frac{-6±\sqrt{-164} }{4} \\\)

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The given question is incomplete, complete question is :

For which values of ? does the following system have nontrivial solutions

λx + 2y + z = 0

x + 5y + 2z = 0

3x - λy + z= 0

The area of the regular octogon is 196.15 square inches.

For a regular octogon with apothem A and side length L, the area is given by:

area =(2*A*L) * (1 + √2)

Here we know that:

A = 7in

L = 5.8 in

Replacing these values in the area for the formula, we will get the area:

area = (2*7in*5.8in) * (1 + √2)

area = 196.15 in²

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Answer: 90 miles

Step-by-step explanation:

67+23=90

=

Answer:

The letter W

Step-by-step explanation:

Answer:

Area of the square base = 100cm²

Surface area of square pyramid= 380cm²

Step-by-step explanation:

Area of the square base= L × L

= 10cm × 10cm

= 100cm²

The surface area of square pyramid= Area of the base + Area of the triangles forming the pyramid.

= 100cm² + 280cm²

A list of 6 one digit whole numbers with an average of 5, a median of 6, a range of 9, and no mode is

since the numbers will have no mode so they are all different

Assuming the numbers are: a, b. c. d. e. and f

The average is 5

(a + b + c + d + e + f ) / 6 = 5

a + b + c + d + e + f = 30

The median is 6

(c + d)/2 = 6

c + d = 12  (assume c = 5 and d = 7)

range is 9

f - a = 9, since it is a one digit number a range of 9 is possible for 9 - 0

hence a = 0 and f = 9

substituting assumed values to the average

0 + b + 5 + 7 + e + 9 = 30

b + e + 21 = 30

b + e = 9 (let b = 8and e = 1)

hence the numbers are

0, 1, 5, 7, 8, and 9

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