The system of equations y = 2x + 5 and y = –3x – 15 is shown on the graph below.According to the graph, what is the solution to this system of equations?

Answer:

C 6 loaves with flour left over

Step-by-step explanation:

Take the amount of flour and divide by the amount of flour per loaf

9/2 ÷ 2/3

Copy dot flip

9/2 * 3/2

27/4

Change to a mixed number

4 goes into 27 6 times with 3 left over

6 3/4

Answer:

He can make 6 loafs and he would have 1/6 cups of flour left

Step-by-step explanation:

Answer:

110

Step-by-step explanation:

a probabability of rolling a 2 on a dice is 1/6, and times that by 660 is 660/6 which equals 110

hope this helps!

please give brainliest. Thanks!

Answer:

110 times

Step-by-step explanation:

The probability (P) of rolling a 2 is

P(2) = \(\frac{1}{6}\)

expected number = \(\frac{1}{6}\) × 660 = 110

Answer:

1. 40 members

2. 4 cheerleaders

3. 40 marbles

4. 2 marbles

5. 8

6. 24

Step-by-step explanation:

1. cross multiply 12/x=30/100

2. cross multiply 12/x=10/100

3. 18/x=45/100

4. x/40=5/100

5. we know 5% is 2 marbles. multiply by 4 to get 8 marbles.

6. 20%=8 marbles. 60/20= 3. 3 x 8= 24 marbles.

Step-by-step explanation:

Angle c + angle d = 180° ( linear pair)

given,

angle c = 5x + 9

angle d = 5x - 6

now,

5x + 9 + 5x - 6 = 180

10x + 3 = 180

10x = 180 - 3 = 177

10x = 177

x = 177/10 = 17.7

so,

angle C = 5x + 9 = 5(17.7) + 9 = 97.50°

angle D = 5x - 6 = 5(17.7) - 6 = 82.50°

Hope this answer helps you dear! take care!.

False, r2adj is the adjusted coefficient of determination that can exceed r2 if there are several weak predictors.

R2adj is the adjusted coefficient of determination and takes into account the number of predictors in the model. It penalizes the addition of insignificant predictors that do not improve the model fit.

R2, on the other hand, is the coefficient of determination and measures the proportion of variability in the dependent variable that is explained by the independent variables in the model.

It is possible for R2 to increase when weak predictors are added, but this increase is not necessarily mean that the predictors do not have a significant impact on the outcome.

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The question is -

R2adj can exceed R2 if there are several weak predictors. true or false?

Answer:

B=88 C=44

Step-by-step explanation:

x+48+x-44=180

2x=176

x=87

angle B= 88

angle C= 88-44=44

Step-by-step explanation:

number of boys=25

number of girls =16

ratio of boys to girl is 25:16

and the fraction is =25/16

Answer:

y = 2(x + 4)² - 6

General Formulas and Concepts:

Step-by-step explanation:

Step 1: Define function

y = 2x² + 16x + 26

Step 2: Find vertex form

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

Flipping a coin to determine which participants in a study are in the control group versus the treatment group is a form of: blinding.

Step-by-step explanation:

The series solution corresponding to the indicial root Y=0 is given by Y(x) = x.

To solve the differential equation XY"-xy' + y = 0, we assume a series solution of the form Y(x) = Σᵢ aₙxⁿ.

Indicial Equation:

Substituting the series solution into the differential equation, we get XY" - xy' + y = Σᵢ aₙxⁿ(Xn(n-1) - nx + 1) = 0.

Equating the coefficients of like powers of x to zero, we obtain the indicial equation Xn(n-1) - nx + 1 = 0.

Indicial Roots:

The indicial equation is a quadratic equation. To find the roots, we solve for n using the quadratic formula:

n = (-(-1) ± √((-1)² - 4X(1)(X)))/(2X) = (1 ± √(1 - 4X²))/(2X).

The indicial roots are the values of n that satisfy the indicial equation. Since we are given the indicial root Y = 0, we substitute n = 0 into the indicial equation:

(0 - 0 + 1) = 0,

which is true. Hence, n = 0 is an indicial root.

Recurrence Relation:Since the indicial root is 0, we have one recurrence relation of the form: Cₖ₊₁(k + r + 1) - cₖz(k + r) = 0.

Solution Corresponding to Indicial Root:

To determine the series solution corresponding to the indicial root Y = 0, we substitute n = 0 into the assumed series solution:

Y(x) = Σᵢ aₙxⁿ = a₀.

Thus, the series solution corresponding to the indicial root Y = 0 is Y(x) = x.

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Answer:

Distance Formula is

Step-by-step explanation:

d=√((x_2-x_1)²+(y_2-y_1)²)

Answer:

that is the formula for you!!!

Answer 26550

Step-by-step explanation:

The answer of the given question based on the code is , the output of the code will be: The root of x³ + 2x - 2 between 0 and 1 is 0.771

MATLAB code:
To show that `x³ + 2x - 2` has a root between 0 and 1 and,

to find the root to 3 significant digits using the Newton Raphson Method,

we can use the following MATLAB code:  

Defining the function

f = (x)x³ + 2*x - 2;

Plotting the function

f_plot (f, [0, 1]);

grid on;

Defining the derivative of the function

f_prime = (x)3*x² + 2;

Implementing the Newton Raphson Method x0 = 1;

Initial guesstol = 1e-4;

Tolerance for erroriter = 0; % Iteration counter_while (1)

Run the loop until the root is founditer = iter + 1;

x1 = x0 - f(x0)

f_prime(x0);

Calculate the next guesserr = abs(x1 - x0);

Calculate the error if err < tol

Check if the error is less than the tolerancebreak;

else x0 = x1;

Set the next guess as the current guessendend

Displaying the resultfprintf('The root of x³ + 2x - 2 between 0 and 1 is %0.3f\n', x1));

The output of the code will be: The root of x³ + 2x - 2 between 0 and 1 is 0.771

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When you run the above code in MATLAB, it will display the root of x^3 + 2x - 2 to 3 significant digits.

MATLAB code:

Show that x^3 + 2x - 2 has a root between 0 and 1:

Here is the code to show that x^3 + 2x - 2 has a root between 0 and 1.

x = 0:.1:1;y = x.^3+2*x-2;

plot(x,y);

xlabel('x');

ylabel('y');

title('Plot of x^3 + 2x - 2');grid on;

This will display the plot of x^3 + 2x - 2 from x = 0 to x = 1.

Find the root to 3 significant digits using the Newton Raphson Method:

To find the root of x^3 + 2x - 2 to 3 significant digits using the Newton Raphson Method, use the following code:

format longx = 0;fx = x^3 + 2*x - 2;dfdx = 3*x^2 + 2;

ea = 100;

es = 0.5*(10^(2-3));

while (ea > es)x1 = x - (fx/dfdx);

fx1 = x1^3 + 2*x1 - 2;

ea = abs((x1-x)/x1)*100;

x = x1;fx = fx1;

dfdx = 3*x^2 + 2;

enddisp(x)

When you run the above code in MATLAB, it will display the root of x^3 + 2x - 2 to 3 significant digits.

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Answer: a) -1, 0, 1, 2 b) 14, 15, 16

a)

We want to find the value of "b" that makes the inequality 28 < 18 - 5b true.

We'll start by adding 5b to both sides to isolate "b".

Then, we'll simplify the equation to get 5b < -10.

Dividing both sides by 5 (and flipping the inequality because we're dividing by a negative number) gives b > -2.

So, b > -2, which means any value of "b" that is greater than -2 will make the inequality true.

b)

we want to isolate the variable "y" on one side of the inequality.

First, we'll simplify the left-hand side by dividing both sides by -3:

y/17 < 1

Next, we'll multiply both sides by 17 to isolate "y":

y < 17

So, y < 17. This means that any value of "y" less than 17 will make the inequality true.

Answer:

25 mph

Step-by-step explanation:

The formula for speed is s = d/t.

s - speed

d - distance

t - time

For your problem, 375 mi is the distance and 15 hrs is the time. When you divide 375/15, you get an answer of 25. The unit of measure is miles per hour or mph. In the end, Taylor's speed is 25 mph. Hope this helps!!

Let's say you are approved for a credit card with a $1500 limit and a 19.99% annual interest rate. Assume that your credit card was maxed out and that your minimum monthly payment is $50. The answer is (b) 41.92 months.

To calculate the time it takes to pay off a credit card with only the minimum payment, we can use the following formula:

\(\begin{equation}Number\ of\ months = \frac{Total\ balance}{Minimum\ payment} \div \frac{1 - (1 + Interest\ rate)^{-(Number\ of\ months)}}{1}\end{equation}\)

In this case, the total balance is $1500, the minimum payment is $50, and the interest rate is 19.99%. Plugging these values into the formula, we get:

\(\begin{equation}Number\ of\ months = \frac{1500}{50} \div \frac{1 - (1 + 0.1999)^{-(Number\ of\ months)}}{1}\end{equation}\)

Solving for the number of months, we get:

Number of months = 41.92 months

Therefore, it would take 41.92 months to pay off the credit card with only the minimum payment.

If you only make the minimum payment, you will pay a lot of interest over time. In this example, you will pay $1278.98 in interest. If you can afford to pay more than the minimum payment, you will save money on interest and pay off your debt faster.

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Answer:

A gardener harvested 20 tomatoes from 5 plants.

A gardener harvested 12 tomatoes from 3 plants.

Step-by-step explanation:

Answer:

Rdfff

Step-by-step explanation:

The profit margins (return on sales) for each division are approximately :Division A = 10.85%,Division B = 9.11% and The calculations for the year would be:Net Income = $85,428,Return on Assets = 18.9%.

To compute the profit margins (return on sales) for each division, we divide the profit by the sales and multiply by 100 to express the result as a percentage.

For Division A:

Profit Margin = (Profit / Sales) * 100

Profit Margin = ($230,000 / $2,120,000) * 100

Profit Margin ≈ 10.85%

For Division B:

Profit Margin = (Profit / Sales) * 100

Profit Margin = ($34,700 / $381,000) * 100

Profit Margin ≈ 9.11%

To calculate the net income and return on assets for Polly Esther Dress Shops Inc., we use the given information.

Net Income = Profit Margin * Sales

Net Income = 7% * $1,220,400

Net Income = $85,428

Return on Assets = Profit Margin * Asset Turnover

Return on Assets = 7% * 2.7

Return on Assets = 18.9%

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Answer:

W = 7.25H - 10

Answer:

-20 mph per second.

Step-by-step explanation:

The amount of each quarterly payment is approximately $146.73.

To calculate the amount of each quarterly payment, we can use the formula for the quarterly payment of an annuity

P = \(A * (1 - (1 + r)^(-n)) / r,\)

where P is the quarterly payment, A is the loan amount, r is the quarterly interest rate, and n is the number of quarters.

First, we need to convert the semiannual interest rate of 8% to a quarterly interest rate. Since there are two quarters in each semiannual period, the quarterly interest rate would be 8% divided by 2, which is 4%.

Next, we substitute the values into the formula

P = \(1400 * (1 - (1 + 0.04)^(-12)) / 0.04\),

 = \(1400 * (1 - (1.04)^(-12)) / 0.04,\)

 ≈\(146.73.\)

Therefore, the amount of each quarterly payment is approximately $146.73.

An annuity is a series of regular payments made over a specific period of time. In this case, the loan of $1400 is to be repaid with quarterly payments. The interest on the loan is charged at a rate of 8% convertible semiannually, which means the interest is compounded twice a year. To determine the amount of each quarterly payment, we use the annuity formula and the quarterly interest rate, which is obtained by dividing the semiannual interest rate by 2. By substituting the values into the formula, we find that each quarterly payment amounts to approximately $146.73.

An annuity payment consists of both principal and interest components. In the beginning, a larger portion of each payment goes towards paying off the interest, while the remaining portion is applied towards the principal. As the loan is gradually repaid, the interest portion decreases, and the principal portion increases. The formula allows us to determine the fixed amount required for each payment, ensuring that the loan is fully repaid within the specified period.

It's important to note that the calculated amount of $146.73 is an approximation, and the actual payment may differ slightly due to rounding or any additional fees associated with the loan.

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Answer: There are 11 dimes and 17 nickels.

Step-by-step explanation:

Answer:

Explanation:

Answer:

70

Step-by-step explanation:

Answer:

\(y = -x + 115\)

Step-by-step explanation:

Given

See attachment for graph

Required

The equation of best fit

First, we pick two corresponding points on the graph,

We have:

\((x_1,y_1) =(55,60)\)

\((x_2,y_2) =(45,70)\)

Calculate slope (m)

\(m = \frac{y_2 -y_1}{x_2 - x_1}\)

This gives:

\(m = \frac{70 - 60}{45 - 55}\)

\(m = \frac{10}{-10}\)

\(m = -1\)

The equation is the calculated using:

\(y = m(x - x_1) + y_1\)

This gives

\(y = -1(x - 55) + 60\)

Open bracket

\(y = -x + 55 + 60\)

\(y = -x + 115\)