the surface of a 50-mm-diameter, thin-walled tube is maintained at 100 oc. in one case, air is in cross flow over the tube with a temperature of 25 oc and a velocity of 30 m/s. in another case, air is in fully developed flow through the tube with a temperature of 25 oc and a mean velocity of 30 m/s. compare the heat flux from the tube to the air for the two cases.

In an AC circuit, electrons move back and forth due to a signal from the generating station, which travels at a speed close to that of light as an electromagnetic wave.

In an AC circuit, electrons are moving back and forth at a frequency.

The signal that the electrons receive to change direction comes from the generating station.

The speed of that signal is: b) very close to the speed of light.

The signal travels as an electromagnetic wave, which propagates at a speed close to the speed of light, allowing the electrons to oscillate in response to the changing electric field.

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During the overhaul, reciprocating engine exhaust valves are checked for **valve clearance**.

During the overhaul process of a reciprocating engine, one of the important checks performed on the exhaust valves is to ensure proper valve clearance. Valve clearance refers to the gap between the valve stem and the rocker arm or tappet when the valve is in the closed position. Over time, due to wear and thermal expansion, the valve clearance may change, leading to improper valve operation and potential engine performance issues.

To check the valve clearance, the engine is typically rotated to a specific position where the valve being inspected is in the closed position. Using feeler gauges, the clearance between the valve stem and the rocker arm or tappet is measured. If the measured clearance is outside the manufacturer's specified range, adjustments can be made by either adding or removing shims or adjusting the rocker arm/tappet position.

Checking and adjusting the valve clearance during overhaul ensures proper valve operation, optimal engine performance, and can help prevent issues such as valve leakage or valve seat damage.

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Answer:

a) annual thermal energy delivered to the house is 6.3 × 10⁹ J

b) corresponding electricity consumption is 3.15 × 10⁹ J

c) volume is needed if there are no losses from storage is 20.895 m³

d) E = 335 MJ

Explanation:

a)

Given that 1 ton refrigeration is 3.5 kw

so Annual thermal energy delivered to the house is

Energy = power × time

E = 3.5 × ( 500×3600)

we converted 500 hrs to seconds

E = 6.3 × 10⁶ kJ

E = 6.3 × 10⁹ J

therefore annual thermal energy delivered to the house is 6.3 × 10⁹ J

b)

corresponding electricity consumption {Cop = 2}

Electricity consumption = Refrigeration effect / work input

∴ EC = 6.3 × 10⁹J / 2

EC = 3.15 × 10⁹ J

∴ corresponding electricity consumption is 3.15 × 10⁹ J

c)

we know that latent heat of ice is 335 kj/kg = 335 × 10³ J/kg

now let m represent the mass of ice needed for required refrigeration

E = mL

6.3 × 10⁹ j  = m × (335 × 10³J/kg)

m = 6.3 × 10⁹ J / 335 × 10³J/kg

m = 18805.97 kg

Given that density of ice = 0.9ton/m³ = 900 kg/m³

NOW

Volume of ice needed V = mass / density

v = 18805.97 kg / 900 kg/m³

v = 20.895 m³

volume is needed if there are no losses from storage is 20.895 m³

d)

cooling energy of 1 ton ( m = 1000 kg) ice

we know L = 335 kJ

E = mL

E = 1000 × 335KJ

E = 335 MJ

Both technicians A and B are correct. On most front wheels the replaceable sealed bearing is pressed between the hub and the wheel flange and is the more difficult to replace. Hence it is usually replaced as a unit.

The unitized wheel hub includes a sealed wheel bearing, a removable wheel hub, and possibly the wheel flange that can be unbolted.

Hence both technicians are correct.

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Answer:

This problem has been solved!

See the answer

7. The voltage that must be less than the breakdown voltage of the diode in order to prevent damage to the diode is the ________.

peak inverse voltage

maximum diode voltage

reverse surge voltage

maximum peak voltage

8. Assume the input signal to a rectifier circuit has a peak value of Vm = 12 V and is at a frequency of 60 Hz. Assume the output load resistance is R = 2kΩ and the ripple voltage is to be limited to Vr= 0.4 V. Determine the capacitance required to yield this specification for a (a) full-wave rectifier and (b) half-wave rectifier. Show all work.

9.A full-wave rectifier is to be designed to produce a peak output voltage of 12 V, deliver 120 mA to the load, and produce an output with a ripple of not more than 5 percent. An input line voltage of 120 V (rms), 60 Hz is available. Consider a bridge type rectifier. Specify the transformer ratio and the size of the required filter capacitor. Show all work.

Explanation:

You would expect each of the following to have a lower p50 qualitative effect on hemoglobin (5 pts) a) Raising the pH from 7.0 to 7.4.

On the forecasts, there is a "qualitative influence." Reliability and accuracy are two characteristics of forecasts. The dependability or accuracy of the forecasts may improve or worsen, depending on the qualitative effect.

Acitric Acids As an illustration, amino acid monomers make up proteins. A functional protein is created by folding a chain of linked polypeptides into a three-dimensional (3D) structure.

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Answer:

multimeter

Explanation:

there's several devices that are used to measure power. the most common one is a multimeter. there's also the voltmeter and ammeter or the oscilloscope.

The cable that is attached exactly above the centre of gravity of the beam and has the length L = sqrt(x2 + h2) = sqrt((W/F)2) = sqrt(0.5) sqrt(W) = sqrt(700) sqrt(0.5) 18.7 ft. is the shortest cable that may be used to raise the beam.

The standard weight is determined as follows: G is equal to L * mweight, where L is the length of the beam determined as the separation between the extreme points of the beam body measured along the direction of the beam axis, with all features except holes taken into consideration.

We may express L2 in terms of x and F using the equations above as follows:

L² = x² + h²

= x² + (T/F)²

Substituting T = W + F, we get:

L² = x² + ((W+F)/F)²

Expanding and simplifying, we get:

L² = x² + (W/F)² + 2W/F + 1

d(L²)/dx = 2x

Setting this equal to zero, we get:

x = 0

This tells us that the minimum value of L² is obtained when x = 0, which means that A and B are vertically aligned. In other words, the cable should be attached directly above the center of gravity of the beam.

When we apply the derivative to F, we obtain:

d(L²)/dF = 2(W/F)² - 2W/F²

Setting this equal to zero, we get:

F = sqrt(2W)

Substituting W = 700 lb, we get:

F = sqrt(1400) lb

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Answer:

the correct answer for the question is A. Agonizer. David is an agonizer as he agonizes while making decisions.

Explanation:

Answer:

A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.

I dont know I asked this to

Explanation:

When using the hammer and driver method, the driver or mandrel must be of a material that is softer than the material of the shaft.

This is because using a harder mandrel could damage the shaft or cause it to deform. The softer mandrel will absorb the force of the hammer blows and help to evenly distribute the force across the surface of the shaft, allowing the part to be installed or removed without damage. It is also important to ensure that the mandrel fits tightly over the shaft to prevent slippage during the installation or removal process.

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The way that chain branching affects a) degree of crystallinity, b) strength, and c) elongation of polyethylene is given below.

Polyethylene is a type of polymer that is made up of long chains of repeating units of ethylene. The properties of polyethylene can be influenced by the size and shape of these chains, as well as the way that the chains are organized within the polymer. One way to alter the properties of polyethylene is to introduce chain branching into the polymer.

a) Degree of crystallinity: Chain branching can have a significant effect on the degree of crystallinity of polyethylene. Crystallinity refers to the degree to which the polymer molecules are organized in a regular, repeating pattern. In general, the more crystalline a polymer is, the stronger and stiffer it will be. In unbranched polyethylene, the molecules are able to pack together tightly, which leads to a high degree of crystallinity.

b) Strength: The strength of a polymer is related to its degree of crystallinity. As a result, the strength of polyethylene will typically be lower when chain branching is present. This is because the chain branches disrupt the regular, repeating pattern of the polymer molecules, making it more difficult for the polymer to resist deformation.

c) Elongation: Elongation refers to the ability of a polymer to stretch or elongate before breaking. Polymers that are more crystalline tend to be less elongation, while polymers that are less crystalline tend to be more elongation. Therefore, when chain branching is present in polyethylene, the polymer will tend to be more elongation. This is because the chain branches disrupt the regular, repeating pattern of the polymer molecules, making it easier for the polymer to stretch.

Therefore, note that properties of Polyethylene can vary depending on the type of polyethylene and the way the polymerization process is carried out, thus the effects of chain branching on it's properties may be different depending on the context.

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Answer:

Explanation:

From the given information:

Strain fracture toughness \(K_k\)= 75 MPa\(\sqrt{m}\)

Tensile stress \(\sigma\) = 361 MPa

Value of Y = 1.03

Thus, the minimum length of the critical interior surface crack which will result to fracture can be determined by using the formula:

\(a_c = \dfrac{1}{\pi} ( \dfrac{k_k}{\sigma Y})^2 \\ \\ a_c = \dfrac{1}{\pi} \Big [ \dfrac{75 \times \sqrt{10^3}}{361 \times 1.03 } \Big]^2 \\ \\ a_c = \dfrac{1}{\pi} \Big [ 6.378474693\Big]^2 \\ \\ \mathbf{ a_c = 12.95 \ mm}\)

Answer:

yes answer d is correct

Communication Process are actions that create physical solutions to problems. The correct option is d.

Human existence and organisational survival both depend on effective communication. It is a process of generating and disseminating thoughts, facts, opinions, and sentiments from one place, individual, or group to another. The Management function of Directing depends on effective communication.

The sending party, message encoding, channel selection, message receipt by the recipient, and message decoding are all aspects of the communication process.

Feedback is when the recipient communicates something back to the original sender. These procedures are actions that result in tangible fixes for issues.

Thus, the correct option is d.

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As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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Double-pane windows often contain inert gases, such as argon or krypton, rather than regular air (which primarily consists of nitrogen and oxygen).

The purpose of using these gases is to enhance the insulating properties of the window and improve energy efficiency.

Inert gases have lower thermal conductivity compared to regular air, meaning they are better at reducing heat transfer. When trapped between the two panes of glass, these gases act as insulators, reducing the conduction of heat and cold through the window.

Nitrogen, despite being a common component of air, is not typically used in double-pane windows because it has a slightly higher thermal conductivity compared to other inert gases like argon and krypton. Argon and krypton have lower thermal conductivities, making them more effective at reducing heat transfer and improving the insulating properties of the window.

By using inert gases like argon or krypton instead of air or nitrogen, double-pane windows can provide better insulation, reduce energy loss, and improve overall comfort and energy efficiency in buildings.

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i] The density of the pellet is 0.977 g/cm^{3}. ii] The macropore volume in cm^{3}/g is 0.205 cm^{3}/g. iii] The macropore void fraction in the pellet is 25.1%.iv] The micropore void fraction in the pellet is 49.0%. v] The solid fraction of the pellet is 25.9%. vi] The density of the particles is 1.222 g/cm^{3}.

i] To determine the density of the pellet, we can use the formula:

Density = Mass / Volume

Given that the mass of the pellet is 3.15 g and the volume is 3.22cm^{3}, we can calculate the density as follows:

Density = 3.15 g / 3.22 cm^{3}≈ 0.977 \(g/cm^{3\)

ii] The macropore volume in cm3/g can be calculated by dividing the macropore volume of the pellet (0.645 cm3) by the mass of the pellet (3.15 g):

Macropore volume = 0.645 cm^{3} / 3.15 g ≈ 0.205 \(cm^{3} /g\)

iii] The macropore void fraction in the pellet can be calculated using the formula:

Macropore void fraction = Macropore volume / Total volume of the pellet

Total volume of the pellet = Volume - Macropore volume = 3.22 cm^{3}- 0.645 cm^{3} = 2.575 cm^{3}

Macropore void fraction = 0.645 cm^{3} / 2.575 \(cm^{3}\)≈ 0.251 or 25.1%

iv] The micropore void fraction in the pellet can be calculated using the given micropore volume of the particles (0.40 cm^{3} /g) and the mass of the pellet (3.15 g):

Micropore volume in the pellet = Micropore volume/g x Mass

Micropore volume in the pellet = 0.40 \(cm^{3} /g\) x 3.15 g = 1.26 cm3

Micropore void fraction = Micropore volume in the pellet / Total volume of the pellet

Micropore void fraction = 1.26 \(cm^{3}\) / 2.575 \(cm^{3}\) ≈ 0.490 or 49.0%

v] The solid fraction of the pellet can be calculated by subtracting the sum of macropore and micropore void fractions from 1:

Solid fraction = 1 - (Macropore void fraction + Micropore void fraction)

Solid fraction = 1 - (0.251 + 0.490) ≈ 0.259 or 25.9%

vi] The density of the particles can be determined using the mass of the pellet (3.15 g) and the total volume of the particles:

Total volume of the particles = Volume - Macropore volume = 3.22 \(cm^{3}\)- 0.645 \(cm^{3}\) = 2.575\(cm^{3}\)

Density of the particles = Mass / Total volume of the particles

Density of the particles = 3.15 g / 2.575\(cm^{3}\) ≈ 1.222 \(g/cm^{3}\)

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Answer:

For most applications, it is simple, dependable, efficient, and straightforward to apply - a simple trigger signal may be provided, with appropriate processing if necessary. This implies that an appropriate trigger signal may be generated using other electrical circuits and then applied to the SCR.

Explanation:

To set PD2 as input the value of DDRD must be = 0x00. Note that DDRD is the direction register for Port D.

Port D is a bidirectional 8-bit I/O port with inbuilt pull-ups. The orientation of this pin is determined by the DDDn bit in the DDRD register; if DDDn is set (one), PDn is configured as an output pin. If DDDn is set to zero, PDn is set to be an input pin.

DDR makes use of the clock signal's falling and rising edges. The distinction from SDRAM and DDR is not one of speed, but rather of the number of times data is sent with each cycle. DDR transports data twice every clock cycle, whereas SDRAM sends signals only once. Both employ the same frequency.

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Answer:

metal step-flashing flashing is commonly used to waterproof joints between sloping roofs and vertical walls.

Hope its helpful!

Answer:

step-flashing is the answer.

Explanation:

Answer:

The issues related to the privacy are:

1. Informational privacy

2. Discrimination factors

3. Biased grouping on the basis of Data mining

4. Lack of consent

5. Morally wrong

6. Illegal distribution of information risks

7. Possibility of threat to life

Let's look at some major concerns:

1. Informational privacy : The concept of privacy of the personal information is totally nullified when the information is being used for a purpose other than the intended one for which it was given. This unethical use of information even for general purposes is not correct and is a matter of concern. It is more like using the sensitive data of others for personal benefit which is purely objectionable and raises security issues. Sometimes the data is also shared with the potential employers which might have certain impacts we are unaware of.

2. Data mining issues : The process of using a certain information to arrive and understand the trend and outcomes is called data mining. In this case, the consumer's data undergoes grouping and might get placed in the wrong group rather than the actual one. Also, there can be a case of biasing towards the groups which are not be focused on, or are not a part of the intended audience. This leads to the discrimination factors if we see it from a social point of view.

3. Lack of consent : Use of information without the consent or awareness of the consumers raises concern over the business ethics followed by the company. No one deserves the right to misuse information for his personal benefits without any of its information to the consumer. It is morally wrong and againt the work ethics. Moreover, it raises trust issues between the two involved, and hence is socially unacceptable.Explanation:

Answer:

Answer is. (d) all of the above

Answer:

my answer is D

Explanation:

all of the above

Answer:

Lack of fluid oil – lack of fluid oil in your vehicle, or a fluid leakage, can lead to heavy steering. If there is a lack of fluid oil, or a leak, this can reduce the pressure in the system, meaning the steering wheel does not receive enough supply of fluid to perform freely.

Answer:

L = 75.25 mm

Explanation:

First we need to find the lateral strain:

Lateral Strain = Change in Diameter/Original Diameter

Lateral Strain = (20.025 mm - 20 mm)/20 mm

Lateral Strain = 1.25 x 10⁻³

Now, we will find the Poisson's Ratio:

Poisson's Ratio = (E/2G) - 1

where,

E = Elastic Modulus = 105 GPa

G = Shear Modulus = 39.7 GPa

Therefore,

Poisson's Ratio = [(105 GPa)/(2)(39.7 GPa)] - 1

Poisson's Ratio = 0.322

Now, we find longitudinal strain by following formula:

Poisson's Ratio = - Lateral Strain/Longitudinal Strain

Longitudinal Strain = - Lateral Strain/Poisson's Ratio

Longitudinal Strain = - (1.25 x 10⁻³)/0.322

Longitudinal Strain = - 3.87 x 10⁻³

Now, we can fin the original length:

Longitudinal Strain = Change in Length/L

where,

L = Original Length = ?

Therefore,

- 3.87 x 10⁻³ = (74.96 mm - L)/L

(- 3.87 x 10⁻³)(L) + L = 74.96 mm

0.99612 L = 74.96 mm

L = 74.96 mm/0.99612

L = 75.25 mm

Answer:

Executive Summary

Explanation:

It is Executive Summary because I used process of elimination. Constraints are set backs. Project objectives are the goals that you want to achieve. Project development cycle are basically the steps that will be used.

Answer:

A) 3 m

Explanation:

The major head loss is calculated by using the expression: \(f \dfrac{L}{D}( \dfrac {U^2}{2g})\)

here:

U = Q/A

Using the continuity equation:

\(U = \dfrac{Q}{\dfrac{\pi}{4}D^2}\)

\(U = \dfrac{5/60 \ m^3/s}{\dfrac{\pi}{4}(0.2)^2}\)

U = 2.65 m/s

Reynolds no = \(\dfrac{\rho U D}{\mu}\)

\(= \dfrac{998 \ kg/m^3 \times 2.65 \ m/s \times 0.2 m}{8.93 \times 10^{-4} \ Pa^-s}\)

= 594,894

Thus, this implies that the flow is turbulent.

Using Moddy's diagram at 5.94 × 10⁻⁵ &;

the relative roughness of 0.01

f = 0.038

Thus, the major head loss = \(f \dfrac{L}{D}( \dfrac {U^2}{2g})\)

\(=0.038 \times (\dfrac{45\ m }{0.2\ m } )\times \dfrac{(2.65 \ m/s) ^2}{2(9.81 \ m/s^2)}\)

= 3.06 m

\(\simeq\) 3 m

The values obtained for R and E1 after solving the given circuit will be equal to 1 ohm and 38 V.

Charged material experiences a force when exposed to an electromagnetic field because of the fundamental characteristic of electric charge. It's conceivable for electrical ions to be positive or negative. Two charges that are opposed to one another repel one another.

As per the given data in the question,

Vp= 26V and,

E₂ = 24V

V₂ = 26-24

= 2V

Given, R will lose 345.6KJ of energy in a day.

We must determine the energy wasted by R in 1 second in order to determine the power dissipated across R.

So,

PR = (345.6x103)J / (24x3600)sec

= 4 Watts

Also,

PR = I₂ x R

4 = I₂R          (1)

V₂ = Voltage across R = 2V

2 = I x R

I = 2/R          (2)

Substitute equation (2) in equation (1) we get

4 = 4/R

R = 1 ohm.

I = 2 ampere

Six ohms of resistance will not block the same current. So,

V₁ = 2X6

= 12 Volts

So,

Now, Apply KVL in the circuit,

E₁ = V₁ + Vp

= 12 + 26

E₁ = 38 V

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