the sun can fuse hydrogen for over ten billion years, while a star twice as massive runs out of hydrogen in

Answers

Answer 1

The sun can fuse hydrogen for over ten billion years, while a star twice as massive runs out of hydrogen in two billion years.

Given that they have more fuel than stars with smaller masses, you may assume that big stars would endure longer. However, the cores of these monsters burn through fuel more quickly because they are much hotter and fuse elements at far faster rates.

For more than 10 billion years, a star like a sun can happily burn hydrogen into helium. But in under two billion years, a star twice as massive as the sun exhausts its supply of hydrogen. In just a few hundred million years, a star eight times as massive as the Sun will run out of fuel. Additionally, the speed of each phase in the fusion process increases over time.

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Related Questions

A freighter needs to travel up the savannah River to the port, moving against the flow of the water. if theriver flows at 3 m/s relative to the shore, and the maximum speed of the freighter relative to the river is 7 m/s, what is the maximum velocity of the freighter relative to the shore

Answers

The maximum velocity of the freighter relative to the shore is 4 m/s.

To determine the maximum velocity of the freighter relative to the shore, we need to consider the velocities of the river and the freighter separately and then combine them. Since the freighter needs to travel against the flow of the water, we subtract the velocity of the river from the maximum speed of the freighter relative to the river.

Given that the river flows at 3 m/s relative to the shore, and the maximum speed of the freighter relative to the river is 7 m/s, we can subtract the river's velocity from the maximum speed of the freighter:

Max velocity of freighter relative to shore = Max velocity of freighter relative to river - Velocity of river

Max velocity of freighter relative to shore = 7 m/s - 3 m/s

Max velocity of freighter relative to shore = 4 m/s

This means that the freighter can travel upstream at a maximum speed of 4 meters per second relative to the stationary shore while overcoming the 3 m/s current flowing downstream in the Savannah River.

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In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of the effect resulting from evacuating air from a container. It is the basis for this problem. Two steel hemispheres of radius 0.380 m (1.25 feet) with a rubber seal in between are placed together and air pumped out so that the pressure inside is 17.00 millibar. The atmospheric pressure outside is 950 millibar. Calculate the force required to pull the two hemispheres apart.

Answers

Answer:

F = 42325.17 N

Explanation:

We are given;

Radius of hemispheres; r = 0.38 m

Inner pressure; P_i = 17 milli bar

Outside Pressure; P_o = 950 milli bar

Now, net pressure; P_net = P_o - P_i

P_net = 950 - 17

P_net = 933 milli bar

From conversion rates, we know that;

1 milli bar = 100 N/m²

Thus;

P_net = 933 × 100

P_net = 93300 N/m²

Surface Area of hemisphere; A = πr²

A = π × 0.38²

Now, formula for pressure is;

P = F/A

Where F is force.

Thus making F the subject;

F = P × A

Plug in P_net and A to get;

F = 93300 × π × 0.38²

F = 42325.17 N

Which of the following is most likely the caption for the illustration that was scratched out of the textbook?

A. An electrically-charged object can attract an uncharged object with magnetic properties.

B. An electrically-charged object is stronger than a magnet.

C. A dry cell battery has magnetic properties.

D. An electric circuit can only have one dry cell battery.

IMAGE DOWN BELOW OR UP

Which of the following is most likely the caption for the illustration that was scratched out of the

Answers

The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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A plane is cruising at 100 m/s when suddenly the pilot turnsthe engines up to full throttle. After traveling 2.0 km, the jet ismoving with a speed of 200 m/s. What is the jet’s acceleration asit speeds up?

Answers

Answer:

The acceleration of the jet when it speeds up = 7.5 m/s²

Explanation:

The initial speed, u = 100 m/s

Distance travelled, s = 2. km

s = 2 x 1000m

s = 2000 m

Final speed, v = 200 m/s

The acceleration is found by using the equation of motion below

\(v^2=u^2+2as\)

Substitute v = 200 m/s, u = 100 m/s, s = 2000 m

\(\begin{gathered} 200^2=100^2+2\times a\times2000 \\ 40000=10000+4000a \\ 4000a=30000 \\ a=\frac{30000}{4000} \\ a=7.5m/s^2 \end{gathered}\)

The acceleration of the jet when it speeds up = 7.5 m/s²

Does solar/light energy explain why/how thing keep going?
O Yes, solar/light energy can convert into other kinds of energy that makes things go, such as TE, ELE, and CE
O No, solar/light energy canonly power solar panels, so it cannot serve as a source of why things go
.

Answers

Answer:

​​In 1954 modern solar cells were invented at Bell Labs with the intent of powering satellites. For many years solar remained expensive but today prices have come down and solar electricity is everywhere. Our satellites and the Mars rover are solar powered, as are homes, toys, outdoor lighting and solar battery packs to charge our electronic devices. Importantly solar electricity is bringing light to the one billion people around the world who live without power. Often these solar lights are replacing kerosene or candles as light sources in the home. Let’s look at some frequently asked questions about solar lights and how they are changing the world.

What are solar lights made of? Solar lights are made up of four main components: the solar photovoltaic (PV) panel, battery, control electronics and the light fixture. When the sun is out, a solar panel takes the light from the sun and produces electrical energy. The energy can then be used immediately or stored in a battery. The goal of most solar lights is to provide power at night, so they will definitely contain a battery, or be capable of attaching to a battery. The battery itself may not need to have a large capacity, due to the availability of solar energy, but it should be long lasting to account for difficulties replacing batteries in many places across the globe.

The advent of the Light Emitting Diode (LED) for the light fixture has drastically reduced the capacity needs of both the solar panels and the batteries. They use significantly less energy than other types of lighting, so the solar panel and battery can be smaller (more transportable and less expensive). The control electronics are required to move the energy around the system, keep the system safe, and potentially switch on or off your light, depending on the level of light it’s exposed to. Solar lights made for outdoor lighting will often turn on automatically when it gets dark outside. Some solar lights made for reading will turn off during daylight hours to preserve the solar charge, but won’t turn on until they are powered on by a user.

How is solar energy produced? Let’s look a little more deeply into the science behind solar electricity. Solar energy is produced due to the photovoltaic effect. A photovoltaic panel (also known as solar cell) converts sunlight into electrical energy. The solar cell is made up of multiple layers of crystalline silicon and chemicals that create layers of negatively-charged electrons and positively-charged spaces. When light passes through the solar cell, it excites the negatively-charged electrons and pushes them into the positively-charged spaces. Those spaces then transfer the electron stream as direct current of electricity through the wires in the solar cell for use or to a battery where the power is stored until it is needed.

Explanation:

Name 1. Consider positive and negative charges of a copper wire all moving horizontally within the time interval 10 us. What can you say about the magnitude and direction of the current?​

Answers

When positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of charge movement.

In the given scenario, if positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds (10 μs), we can infer the following about the magnitude and direction of the current:

1. Magnitude of the Current: The magnitude of the current is determined by the total charge passing through a given point in the wire per unit time. Since both positive and negative charges are moving, the total charge passing through a point will be the sum of the magnitudes of the charges. If the number of positive and negative charges is equal, the magnitudes of their charges will also be equal. Therefore, the total charge passing through the point will be the sum of equal positive and negative charges, resulting in a net charge of zero. In this case, the magnitude of the current will be zero.

2. Direction of the Current: The direction of the current is determined by the flow of positive charges. In a copper wire, the positive charges are not free to move. Instead, it is the negatively charged electrons that are free to move. Due to conventional current flow convention, the direction of the current is considered opposite to the direction of the electron flow. Therefore, even though both positive and negative charges are moving horizontally, the direction of the current will be in the opposite direction to the movement of the charges.

In summary, in the given scenario, where positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of the charge movement.

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. Which of the following is the best description about cancer cells?

Answers

Cancer cells are cells that divide relentlessly, forming solid tumors or flooding the blood with abnormal cells. Cell division is a normal process used by the body for growth and repair.

4. In 1994, element 111 was discovered by an international team of physicists. Its
provisional name was unununium (Latin for “one-one-one”). Find the distance between
two equal and opposite charges, each having a magnitude equal to the charge of 111
protons, if the magnitude of the electric force between them is 2.0  1028 N. (q =
1.602x10-19 C)

Answers

The distance between the similar charges is 0.753 m. The electric force is the inverse of the square of the distance.

What is electric force?

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is;

q₁,q₂ are the charges = 1.6 ×10⁻¹⁹ C

R is the distance

F is the electric force=2.0×10²⁴ N

The electric force is found as;

\(\rm F = \frac{Kq_1q_2}{R^2} \\\\ \rm 2.0 \times 10^{28}= \frac{9\times 10^9 \times 1.6 \times 10^{-19}1.6\times 10^{-19} }{R^2} \\\\ R =0.753 \ m\)

Hence, the distance between the similar charges is 0.753 m.

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The Earth's plates moved over millions of years, bringing continents and other
features of the Earth to their present arrangement.
How is this movement of the lithosphere explained?
continental drift
• the principle of superposition
• the theory of plate tectonics
nuclear fusion

Answers

Answer:

theory of plate tectonics

Explanation:

Answer:

What he said above me

Explanation:

I did the test and it was right

How do nutritional needs change when a person increases their activity level to gain muscle mass?

Answers

When a person increases their activity level to gain muscle mass, their nutritional needs change.

How utritional needs change when a person increases their activity level to gain muscle mass?

The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.

Individual variations exist, so seeking personalized guidance from a professional is recommended.

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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Makala arrives late to class and misses the first few minutes of the lecture. These are the notes she takes:

-Only applies to very small particles
-subatomic particles
-atoms
-nano-size systems
-Only applies over very short distances
-Causes different behavior than the physics observed in
large objects

What should Makala title her notes?

A: Nanotechnology
B: Quantum Mechanics
C: Microtechnology
D: Newtonian Physics

Answers

Answer:

B. Quantum Mechanics

Explanation:

Quantum mechanics is the foundation of all quantum physics including quantum chemistry, quantum field theory, and quantum information science.

Answer:

B. Quantum Mechanics

Explanation:

Edge 2021

Find the magnitude and direction of an electric field that exerts a 1.38 * 10^-18N northward force on a proton.

Find the magnitude and direction of an electric field that exerts a 1.38 * 10^-18N northward force on

Answers

Given:

Force = 1.38 x 10⁻¹⁸ N northward.

Let's find the magnitude and direction of the electric field

To find the magnitude, apply the formula:

\(E=\frac{F}{q}\)

Where:

E is the electric field

F is the force = 1.38 x 10⁻¹⁸ N

q is the charge of proton = -1.60 x 10⁻¹⁹ C

Input the values in the equation and solve for E:

\(\begin{gathered} E=\frac{1.38\times10^{-18}}{-1.60\times10^{-19}} \\ \\ E=-8.625\text{ N/C} \end{gathered}\)

The magnitude of the electric field is -8.625 N/C.

Since the direction of the force is Northward and the polarity of the charge is negative, the direction of the electric field will be opposite the direction of the force.

Therefore, the direction of the electric field is downward.

ANSWER:

8.625 N/C Southward

Answer:

8.625 N/C northward

Explanation:

The electric force can be related to the electric field and charge with which that field interacts via the equations found in Module 7 Section 1.3 and Chapter 18.4 in College Physics.

https://openstax.org/books/college-physics/pages/1-introduction-to-science-and-the-realm-of-physics-physical-quantities-and-units

A charge q1 of -6.00 × 10^-9 C, a charge a2 of -3.00 × 10^-9 C, and charge q3 of -1.10^-9 C. Q1 and a2 are separated by a distance of 60.0 cm, q2 and q3 are separated by distance 60.0 cm. What is the net charge on the q2?

Answers

The net charge on q2 is estimated at -4.00 × 10^-9 C.

How do we calculated?

We apply  Coulomb's law to solve this:

The Force is  = (k * q1 * q2) / r^2

For q1 and q2:

F1-2 = (k * q1 * q2) / r^2 = (9.0 × 10^9 N·m^2/C^2) * (-6.00 × 10^-9 C) * (-3.00 × 10^-9 C) / (0.60 m)^2 = 1.35 × 10^-3 N

For q2 and q3:

F2-3 = (k * q2 * q3) / r^2 = (9.0 × 10^9 N·m^2/C^2) * (-3.00 × 10^-9 C) * (-1.10 × 10^-9 C) / (0.60 m)^2 = 2.25 × 10^-4 N

The net force on q2 is the vector sum of the forces on q2 from q1 and q3:

Fnet = F1-2 + F2-3 = 1.35 × 10^-3 N + 2.25 × 10^-4 N = 1.58 × 10^-3 N

Fnet = (k * q2 * qtot) / r^2

qtot = the net charge on q2

qtot = (Fnet * r^2) / (k * q2) = (1.58 × 10^-3 N) * (0.60 m)^2 / (9.0 × 10^9 N·m^2/C^2) / (-3.00 × 10^-9 C) =  -4.00 × 10^-9 C

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the student applies a net force of 4.5 N to the 1.5 kg textbook.
Calculate the magnitude of the textbook's acceleration.

Answers

Answer:

3 m/s²

Explanation:

acceleration = Force / mass;  4.5/1.5 = 3

When a student applies a net force of 4.5 Newtons to the 1.5-kilogram textbook, then the magnitude of the acceleration would be 3 meters/second².

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As given in the problem, when a student applies a net force of 4.5 Newtons to the 1.5-kilogram textbook, then we have to find the magnitude of the acceleration,

the applied force on the textbook = 4.5 Newtons

the mass of the textbook is 1.5 kilograms

acceleration of the textbook = force / mass

                                             =4.5 Newtons /1.5 kilograms

                                             =3 meters/second²

Thus, the magnitude of the acceleration would be 3 meters/second².

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A 12.0-kg block is pushed across a rough horizontal surface by a force that is angled 30.0◦ below the horizontal. The magnitude of the force is 75.0 N and the acceleration of the block as it is pushed is 3.20 m/s2. What is the magnitude of the contact force exerted on the block by the surface?

Answers

Answer:

157.36 N

Explanation:

Contact force is the force which is created due to contact and it is applied on the contact point . The force applied by body on the surface is its weight .

If R be the reaction force of the ground

R = mg + F son30

= 12 x 9.8 + 75 sin 30

= 117.6 + 37.5

= 155.10 N .

friction force = f

Net force in forward direction = F cos 30 - f  = ma

75cos 30 - f = 12 x 3.2

f = 65 - 38.4

= 26.6 N  

Total force on the surface =√( f² + R² )

√ (26.6² + 155.1²)

= √707.56 + 24056²

=√ 24763.57

= 157.36 N.

contact force = 157.36 N .

A 1kg cannon ball.is fired horizontally with an initial velocity of 5m/s. If the cannon was atop a wall 20m above the ground, what is the total
change in KE?

Answers

Answer:

Ek = 196.2 [J]

Explanation:

The question concerns the KE kinetic energy.

That is, we must find the kinetic energy at the moment the cannon is fired and the kinetic energy of when the ball hits the ground after having fallen 20 meters.

At the moment when the ball is fired it is 20 meters above ground level. If the ground level is taken as the reference level of potential energy, where it is equal to zero, in this way when the ball is at the highest (20 meters) you have the maximum potential energy.

In this way, the energy in the initial state is equal to the sum of the kinetic energy plus the potential energy. As the energy is conserved this same energy will be present when the ball hits the ground, where the potential energy is zero and will have only kinetic energy.

\(E_{1}=E_{2}\\E_{k1}+E_{p1}=E_{k2}\\\frac{1}{2} *m*v^{2} +m*g*h=E_{k2}\\E_{k2}=0.5*1*(5)^{2} +1*9.81*20\\E_{k2}=208.7[J]\)

The kinetic energy in the initial state can be easily calculated by means of the following equation.

\(E_{k1}=\frac{1}{2} *m*v^{2}\\E_{k1}=0.5*1*(5)^{2}\\E_{k1}=12.5 [J]\)

Therefore the change in KE

\(E_{k} = 208.7 - 12.5\\E_{k} = 196.2 [J]\)

Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2​

Answers

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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PLEASEEEEEEEEE HELPPPPPPPPPP

Describe what determines magnetism.

Answers

Answer:

Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. ... Their movement generates an electric current and causes each electron to act like a microscopic magnet.

Explanation:

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.32 cm. A compressive force of F = 5000 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Answers

The length of the stack shortens by 4.88 x 10-6 m.

What is Young's brass modification?

Brass and steel have Young's modules of 1.0 and 2 respectively, 1010N/m2. Under the same force, a brass wire of the same length and a steel wire with radii of RB and RS, respectively, are both expanded by 1 mm.

The change in length of each cylinder due to the compressive force can be found using the formula:

ΔL = (F * L) / (A * E)

First, let's find the cross-sectional area of each cylinder:

A = π * r² = π * (0.32 cm)² = 0.3217 cm²

L = Lcopper + Lbrass

L = 2 * Lcopper

Ftotal = Fbrass + (-Fcopper) = Fbrass - Fbrass = 0

Since the total force on the stack is zero, the amount by which the length of the stack decreases is the same as the amount by which the length of the brass cylinder decreases:

ΔL = (Fbrass * Lbrass) / (Abrass * Ebrass)

ΔL = (5000 N * Lbrass) / (0.3217 cm²* 9.0 x 10¹⁰ N/m²)

ΔL = (1.554 x 10⁻⁴ m/N) * Lbrass

V = π * r² * Lbrass

Lbrass = V / (π * r²)

Lbrass = 1 cm / (π * (0.32 cm)^2)

Lbrass = 3.14 cm

Finally, we can substitute this value into the equation for ΔL:

ΔL = (1.554 x 10⁻⁴ m/N) * 3.14 cm

ΔL = 4.88 x 10⁻⁶ m

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Why does atmospheric blurring cause objects with smaller true angular diameters to have larger percent errors

Answers

The atmospheric blurring can negatively affect the view of objects and requires a larger separation to distinguish forms. It is caused by turbulent air in motion.

What is atmospheric blurring?

The atmospheric blurring is a natural phenomenon caused by turbulent air in motion, which negatively affects the view of astronomical objects.

The atmospheric blurring may lead to larger percent errors in objects with smaller angular diameters because in these cases it is required a larger separation to distinguish forms.

Smaller angular diameters produce larger squared visibility, thereby increasing the effects of distortion caused by atmospheric blurring.

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Need help with this assignment please

Need help with this assignment please

Answers

Torque is a measure of the turning force applied to an object about a rotational axis. It is calculated as the product of the force applied to the object and the distance from the axis of rotation at which the force is applied.

How to explain the information

Use the equation slope = mod to calculate the unknown mass (mo) for parcels A and C, setting d = 1.0 m, and parcels G and H, setting d = 1.5 m.

Record all data, tables, and four graphs for analysis.

The experiment demonstrates the application of torque in determining unknown masses and provides valuable insights into the concept of torque in physics.

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true/false. develop an expression for the pressure variation in a liquid in which the specific weight increases with depth, h, as where k is a constant and is the specific weight at the free surface.

Answers

Develop expressions for variations in pressure in fluids ⇒  p = K\(\frac{h^2}{2}\) + γ₀h

Since we are given a function of specific weight value, which varies with height, we have to define a differential change in pressure over an infinitesimally small change in height:

dp = γdh

Substitute the function:

dp = (Kh+γ₀) dh

This relationship allows us to integrate pressure changes, over small height changes, and obtain the total pressure change:

p = ∫(Kh+γ₀)dh

p = \(\int\limits^h_0\)Khdh + \(\int\limits^h_0\)γ₀dh

p = Kh²/2\(]_0^h\) + γ₀h\(]_0^h\)

p = K\(\frac{h^2}{2}\) + γ₀h

Your question is incomplete but most probably your full question was:

Develop an expression for the pressure variation in a liquid in which the specific weight increases with depth, h, as γ = Kh+γ₀ where K is a constant and yo is the specific weight at the free surface.

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Part A
The goal of your paper is to describe the history of the discovery and research of Proxima Centauri. Another goal is to find the possibilities of traveling to this star. Some questions that your paper should answer are:

When was Proxima Centauri discovered?
How was Proxima Centauri discovered?
How have scientists researched Proxima Centauri?
What technologies have they used? What types of data do these technologies collect?
Have spacecraft ever reached this star?
What are the limitations of sending spacecraft to Proxima Centauri?
What accommodations would humans need to travel to Proxima Centauri?
Now write down two more questions you have about Proxima Centauri that you plan to answer in your paper.

Answers

Answer:

Proxima Centauri was discovered in 1915.

Robert Innes used a blink comparator to examine a photographic plate showing an area of 60 square degrees around Alpha Centauri.

The sixty-four-meter radio telescope at Parkes Observatory in Australia.

they used the James Webb Space Telescope and The sixty-four-meter radio telescope.

no nothing as been to Proxima Centauri it would take about 54,400 years to get there.  

getting to Proxima Centauri, our solar system's nearest star, would take four years and three months. And that is travelling at light speed, a velocity well beyond our reach. The quickest we could currently get to Proxima Centauri, using our fastest rockets, is 80,000 years.

Explanation:

can someone give me a 5 day fitness plan with all the reps and sets for 3 only and 4 exercises a day

Answers

Answer:

Classic 5 Day Split

Day 1 – Chest

Day 2 – Legs

Day 3 – Rest

Day 4 – Back

Day 5 – Arms

Day 6 – Shoulders

Day 7 – Rest  

Upper Lower Push Pull Legs

Day 1 – Upper

Day 2 – Lower

Day 3 – Rest

Day 4 – Push

Day 5 – Pull

Day 6 – Legs

Day 7 – Rest  

5 Day Split Variation

Day 1 – Chest

Day 2 – Legs & Shoulders

Day 3 – Back

Day 4 – Biceps & Triceps

Day 5 – Core & Cardio

Day 6 – Rest

Day 7 – Rest

Explanation:

When a light strikes a smooth, flat mirror, the angle od incidence equals the angle of _____ (A) deception (B) refraction (C) distraction (D) reflection​

Answers

Answer:

D

Explanation:

An object undergoes simple harmonic motion along the x-axis shown above, where x = 0 is the object's equilibrium position. Which of the following graphs best shows the relationship between the object's acceleration a and its displacement x from equilibrium? (Assume positive acceleration to be directed to the right.)

An object undergoes simple harmonic motion along the x-axis shown above, where x = 0 is the object's

Answers

Answer:

  see below

Explanation:

Simple harmonic motion is described by a differential equation in which acceleration is proportional to the opposite of displacement. The displacement-acceleration graph looks like a line with negative slope.

An object undergoes simple harmonic motion along the x-axis shown above, where x = 0 is the object's

A unit used to measure force is a
a. newton.
b. newton-meter.
c. joule.
d. watt.

Answers

Answer:

Newton

Explanation:

Newton's are the standard unit of force.

You want to lift a heavy box with a mass L = 56.0 kg using the two-ideal pulley system as shown. With what minimum force do you have to pull down on the rope in order to lift the box at a constant velocity? One pulley is attached to the ceiling and one to the box.

Answers

The minimum force required to lift the box at constant velocity is determined as 274.4 N.

Minimum force required

The minimum force required to lift the box at constant velocity is the tension in one of the pulleys, and the magnitude is calculated as follows;

2T = mg

where;

m is mass of the boxT is the minimum force required

2T = mg

T = mg/2

T = (56 x 9.8)/2

T = 274.4 N

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Acceleration refers to any changes in

Answers

Answer:

speed

Explanation:

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