The sum of three numbers is 35. The first number is three less than the second and the third is two more than four times the second. What are the numbers?

Answer:

The area of the rectangle is 22 m^2. The perimeter of the rectangle is 19.93

Step-by-step explanation:

The area of a rectangle is \(l*w\). The perimeter of a rectangle is \(2(l+w)\) or just adding up all 4 sides. Now, all you need to do is math.

\(A= 3.3 * (20/3) = 22\\P = 2 (3.3 + (20/3)) = 19.93\)

If your teacher has rounding rules, please follow it.

The smallest measurement used in the apothecary system for volume is the minim.

The apothecary system is an outdated system of measurements primarily used in pharmacy and medicine. It includes various units for measuring volume, weight, and other quantities.

In the apothecary system, the minim is the smallest unit of measurement for volume. It is equivalent to approximately 0.0616 milliliters.

The minim is a small unit of measurement and is typically used for precise dosing of liquids in the apothecary system. It is commonly used in pharmaceutical compounding and in the preparation of medications.

However, it's important to note that the apothecary system is no longer widely used in modern healthcare practices. The metric system, with units such as milliliters and liters, has become the standard for measuring volume in most countries.

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When a thesis test is being performed for a population mean, the probability of a type II error isn't dependent on the sample mean. Option B is the right answer.

A type II error occurs when a null thesis isn't rejected despite it being incorrect. It's worth noting that the threat of making a type II error is affected by several factors, including the sample size, the true population mean, the position of significance, and the variability of the data.

As a result, the larger the sample size, the lower the threat of making a type IIerror.The true population mean also has an impact on the liability of a type II error. As the difference between the true mean and the hypothecated mean grows, the threat of a type II error decreases.

The position of significance is also pivotal in determining the threat of a type II error. As the significance position increases, the threat of a type II error decreases.

So, the correct answer is B

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The smallest number of eggs that could have been in the box is 1134

The problem is to find the smallest number of eggs that could have been in the box, given the remainder when taking them out by different numbers. Here are the moves toward tackling it:

Allow n to be the quantity of eggs in the container. Then we have the accompanying arrangement of congruences:

n ≡ 1 (mod 2)

n ≡ 1 (mod 3)

n ≡ 1 (mod 4)

n ≡ 1 (mod 5)

n ≡ 1 (mod 6)

n ≡ 0 (mod 7)

For this problem, we have k = 6 k = 6, a i = {1,1,1,1,1,0} a_i = {1,1,1,1,1,0}, M i = {1260,840,630,504,420,720} M_i = {1260,840,630,504,420,720}, and y i = {−1,−2,−3,-4,-5,-6} y_i = {-1,-2,-3,-4,-5,-6}.

Plugging these values into the formula and simplifying modulo 5040, we get:

n = (−1260 + −1680 + −1890 + −2016 + −2100 + 0) mod 5040

n = (−8946) mod 5040

n = (−3906) mod 5040

n = 1134 mod 5040

Therefore, the smallest number of eggs that could have been in the box is 1134

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The difference in the medians is 1/3 times the IQR.

Mathematically, interquartile range (IQR) of a data set and it is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):

Interquartile range (IQR) for Speed Slide = Q₃ - Q₁

Interquartile range (IQR) for Speed Slide = 12 - 6

Interquartile range (IQR) for Speed Slide = 6.

For the interquartile range (IQR) for Wave Machine, we have:

Interquartile range (IQR) for Wave Machine = 14 - 8

Interquartile range (IQR) for Wave Machine = 6.

For the required expression, we have the following:

2 = 6x

x = 2/6

x = 1/3.

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Answer:

The difference in the medians is 1/3 times the IQR.

Step-by-step explanation:

hope this helps!

The solution for given equations are: z = 4, b = -12, w = 5, c = -11

An equation is a mathematical statement that expresses the equality of two expressions.

Variables are symbols or letters used to represent unknown values in equations.

To solve for a variable, one must first isolate the variable by performing the same operations on both sides of the equation until the variable is alone on one side of the equation.

For example, if the equation is 2x + 4 = 10, the first step would be subtracting 4 from both sides of the equation to get 2x = 6. The next step would be to divide both sides of the equation by 2 to get x = 3. This is how one would solve for the variable in this equation.

According to question:-

A. 3(7z-6)=-(-18z+6)

21z - 18 = 18z - 6

3z = 12

z = 4

B. -8b+2(-5b-2)=212

-8b - 10b - 4 = 212

-18b - 4 = 212

b = -12

C. 4/5w+5 = 1/5w+8

4/5w-1/5w = 8-5

3/5w = 3

w = 5

D. (-c-8)-(7c-6)= 18c+284

-c-8-7c+6 = 18c + 284

18c + 8c = -2-284

26c = -286

c = -11

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Answer:

A

Step-by-step explanation:

(y + 7) - (-8y + 14) = y + 7 + 8y - 14 = 9y - 7

Answer:

wddfgfgjgfccvnjjxcvbfx bff

Answer:

as attached image shows

Step-by-step explanation:

It is well known that utilizing a zip file is an effective method for reducing the size of the document in order to boost storage and sharing possibilities. A zipped folder may be smoothly moved from one place (the transmitter) to another without any issues (the receiver).

One or more files can be compressed and stored together in one location using the ubiquitous ZIP file format. As a result, the file size is less and is simpler to transport and store. After transmission, the receiver can use the files in their original form by unzipping (or extracting) her ZIP file.

In order to increase storage and sharing capabilities by lowering the size of the document, it is known that using a zip file is an efficient technique. A zipped folder may be effortlessly transferred without any hiccups from one location (the transmitter) to another (the receiver). Using Zip files has the primary benefit of reducing the time required to send large files over email. The document's quality is unaffected and is identical to the original file when it is compressed using a zip file.

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The probability of iii-2 and iii-3 having 2 colorblind children and 5 normal children is approximately 0.16, or 16%.

To calculate the probability of having 2 colorblind children and 5 normal children, we need to use the binomial probability formula, which is:

P(X=x) = (n choose x) x pˣ x (1-p)ⁿ⁻ˣ

where:

P(X=x) is the probability of getting k successes in n trials

(n choose k) is the binomial coefficient, which is the number of ways to choose k items from a set of n items

p is the probability of success in each trial

(1-p) is the probability of failure in each trial

x is the number of successes we want to have

In this case, we want to find the probability of having 2 colorblind children and 5 normal children, so we can plug in the values:

P(X=2) = (7 choose 2) * 0.25² * 0.75⁵

Using a calculator or computing by hand, we get:

P(X=2) = 0.16 or 16%.

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Yes, the given linear equation 9x+2y=8 is a linear line.

An equatiοn which has the maximum degree οf 1 is knοwn as a linear equatiοn. which means that there is nο such variable in a linear equatiοn that has a variable whοse expοnent is greater than 1. The graph οf a such kind οf equatiοn always fοrms a straight line.

The given linear equation is  9x+2y=8

         It can be written in the form y= (8- 9x)/2

                                                       y= -9x/2+ 4

The linear equation can be compared to y= mx + c where m is the slope  of the line  and c is the constant term. we get m= -9/2 and c=4.

Also comparing with linear equation Ax+ by+ c=0 where A and B not equals to zero we get A= 9 , B= 2.

so the given linear equation can be formed as a linear line.

Hence, it is a linear line.

A graph is attached below.

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Answer:

See below.

Step-by-step explanation:

counting: 1, 2, 3, 4, ...

whole: 0, 1, 2, 3, 4, ...

integers: ... , -3, -2, -1, 0, 1, 2, 3, ...

rational: all numbers that can be written as a ratio of integers

irrational: all numbers that cannot be written as a ratio of integers

real: all the numbers listed above

Answer:

porcupine

Step-by-step explanation:

6300g = 6.3 kg

Step-by-step explanation:

the porcupine has more mass

Answer:

D. x = 3

Step-by-step explanation:

\( {x}^{3} = 27\)

\(x = \sqrt[3]{27} = 3\)

Answer:

if $700 is sales then answer would be $513.50

Step-by-step explanation:

5.5% of 700 = 38.5

475+38.5=513.50

Answer:

   120 possible combinations

Step-by-step explanation:

We have to find the combination of 10 students in 3 positions, where the order does not matter.

\(n=10\\r=3\\\)

Then, the combination can be calculated as :

\(C(n.r)= \frac{n!}{(n-r)!r!} \\C(10,3)=\frac{10!}{10-3)!3!} =\frac{10!}{7!.3!} = \frac{10.9.8}{3.2} =\frac{720}{6} =120\)

Answer : 120 possible combinations

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Without the specific information about the production rate and flow rate of the process, it is not possible to provide a precise calculation of the WIP inventory accumulation between steps a and b in 16 hours.

To determine the number of units of work-in-process (WIP) inventory that will accumulate between steps a and b in 16 hours, we need additional information regarding the production rate and the flow rate of the process. The accumulation of WIP inventory depends on the production rate and the time it takes for a unit to flow from step a to step b.

Without specific information about the production rate or the time it takes for a unit to flow from step a to step b, it is not possible to provide an accurate calculation of the WIP inventory accumulation.

However, I can explain the concept of WIP inventory and its accumulation in a manufacturing process.

WIP inventory refers to the partially completed units that are in the production process at any given time. It includes all the materials, components, and partially completed products that are at various stages of the production process.

The accumulation of WIP inventory occurs when the production rate exceeds the flow rate of the process. In other words, if the rate at which new units enter the process is higher than the rate at which units move from one step to another, WIP inventory will accumulate.

To calculate the accumulation of WIP inventory, we need to know the production rate, the flow rate, and the time period over which we want to measure the accumulation. With this information, we can determine the net inflow rate and the outflow rate of units from the process.

Once we have the inflow and outflow rates, we can calculate the net accumulation of WIP inventory by subtracting the outflow rate from the inflow rate. Multiplying this net accumulation rate by the given time period will give us the total accumulation of WIP inventory.

However, without the specific information about the production rate and flow rate of the process, it is not possible to provide a precise calculation of the WIP inventory accumulation between steps a and b in 16 hours.

In conclusion, to determine the number of units of WIP inventory that will accumulate between steps a and b in 16 hours, we need additional information about the production rate and the flow rate of the process. These factors are essential in calculating the net accumulation of WIP inventory. Without this information, it is not possible to provide an accurate answer.

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The formula relating the monetary multiplier and the reserve ratio shows that as the monetary multiplier increases, the reserve ratio decreases. If the monetary multiplier is 6, the reserve ratio must be 0.167.

To determine the reserve ratio given the monetary multiplier, we can use the formula:

Monetary Multiplier = 1 / Reserve Ratio

Given that the monetary multiplier is 6, we can substitute this value into the formula:

6 = 1 / Reserve Ratio

To isolate the reserve ratio, we can take the reciprocal of both sides of the equation:

1 / 6 = 1 / (1 / Reserve Ratio)

1 / 6 = Reserve Ratio

Therefore, the reserve ratio must be 1/6 or approximately 0.167.

Among the given options, b) 0.167 represents the correct answer.

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Answer:

72% are not freshmen.

Step-by-step explanation:

The not freshmen students are,

→ 50 - 14

→ 36 students

Then percent of not freshmen,

→ (36/50) × 100

→ 0.72 × 100

→ 72%

Hence, the answer is 72%.

Answer:

G. 14:5 is the correct answer.

Step-by-step explanation:

a:b = 4:5

a:c = 2:7

so,

here in first ratio a = 4

in second ratio a = 2

making them equal:

Taking LCM of 2 and 4 = 4

so

a:c = 2/7 = (2×2)/(7×2) = 4/14

so,

a = 4

c = 14

b = 5

so ratio c : b = 14:5

Answer:

\(9*5\)

Step-by-step explanation:

9(5s) are 9*5.

The main purpose of the article in the AJN: American Journal of Nursing is to provide nurses with up-to-date and pertinent information that supports evidence-based practice in their profession.

AJN: American Journal of Nursing is a reputable publication that focuses on providing up-to-date information and research findings relevant to the nursing profession. The purpose of the article within this journal is to disseminate knowledge and explore various aspects of nursing practice, education, research, and healthcare delivery.

The information presented in this article can be implemented into nursing practice in several ways. First, it can enhance the knowledge base of nurses by providing them with current evidence-based practices, interventions, and guidelines. By staying informed about the latest research and developments in the field, nurses can ensure that their practice aligns with the best available evidence, ultimately leading to improved patient outcomes.

Additionally, the article may introduce new techniques, technologies, or interventions that nurses can incorporate into their practice. It may offer insights into emerging trends or address challenges commonly encountered in nursing care. By adapting and implementing these strategies, nurses can enhance the quality of care they provide to patients.

Rationale for using this information in nursing practice lies in the importance of evidence-based practice. As healthcare evolves rapidly, it is crucial for nurses to remain knowledgeable and updated. By referring to reputable sources like AJN: American Journal of Nursing, nurses can access reliable information that has undergone rigorous review and vetting processes. This ensures that the information is trustworthy and can be applied safely and effectively in clinical settings.

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\(\cfrac{x^2-9}{3x^2+8x-3}\div\cfrac{x-3}{x+2}\implies \cfrac{x^2-9}{3x^2+8x-3}\cdot \cfrac{x+2}{x-3}\implies \cfrac{\stackrel{\textit{diff. of squares}}{x^2-3^2}}{(x+3)(3x-1)}\cdot \cfrac{x+2}{x-3} \\\\\\ \cfrac{~~\begin{matrix} (x-3)(x+3) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} (x+3) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(3x-1)}\cdot \cfrac{x+2}{~~\begin{matrix} x-3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\implies \cfrac{x+2}{3x-1}\)

Answer:

if you simplify the expression you will get

\(20c^{7}d - 20 {c}^{6} {d}^{2} \)

Answer:

20c/d

Step-by-step explanation:

I got it right. Hope this helps.

Answer:        6

Step-by-step explanation:

18 Roses were bought lets now split 18

        | | | | | | | | |           | | | | | | | | |

We split 18 into 6

WHPH - WORK HARD PLAY HARDER

Answer:

There are 33 cows and 26 chickens

Step-by-step explanation:

Problem Solving

This problem can easily be solved by using equations, but it's more fun to solve it through pure reasoning and arithmetics.

Let's imagine there are no cows on the farm. Just chickens. 59 chicken heads mean 59*2 = 118 legs.

Now let's take one chicken out and one cow in. The number of heads will remain the same, but now there are two more legs: 120 legs.

We are closer to the answer. The trick is to calculate how many chickens we have to exchange for cows knowing each change means two more legs.

Since we initially had 118 legs, we need to add 184 - 118 = 66 more legs.

62 more legs are 66/2 = 33 changes or 33 cows.

The number of chickens is 59 - 33 = 26

Answer: There are 33 cows and 26 chickens

The required solution is,

1. Gardner can put a maximum of 4 flowers in each row

2. At 150 minutes both the student will meet each other

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

Here,

1. For the planting of trees in even rows,

The greatest number of plants he can have in each row to keep the rose bushes and tulips in their own rows,

Taking HCF of number of plants 24 and 28

HCF of 24 and 28 is 4

Thus, Gardner can put a maximum of 4 flowers in each row.

2.

Time taken by the first student to complete one lap is 25 minutes,

So,

1 lap = 25 minute

1 minute = 1 / 25 lap

For the second student,

1 lap = 30 minute

1 minute = 1/30 lap

At time x minute both will meet each other,

x/25 -x/30 = 1

5x/750 = 1

x = 750/5

x = 150 minute

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Answer:

4

Step-by-step explanation: