The sum of matrices A and B is C.

Answer:

152

Step-by-step explanation:

Edge 2020

The correct option regarding the exponential function is given as follows:

Amar is correct. Because 2% -0.02 and the base is 1-0.02 so the function has a decay rate of 2%.

The exponential function for this problem is defined as follows:

y = 230(0.98)^x.

The initial value is given as follows:

y = 230.

The base of the function is given as follows:

0.98.

As the base of the function is less than 1, this is a decay function, with a rate of 1 - 0.98 = 0.02 = 2%.

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Answer:

18.7

Step-by-step explanation:

Answer:

Step-by-step explanation:

The formula for finding the perimeter is 2w+2L (2*width + 2*length)

So, since we know the width is "w" and the length is "3w-2", we can just substitute those into the equation.

2(w)+2(3w-2)

From there, if needed, you can simplify to:

2w + 6w-4

Add like terms:

8w - 4

Hope that helps.

Answer:

8

Step-by-step explanation:

1 quart=4 cups so 4x2=8

Step-by-step explanation:

The key rule is: to round up the number one digit to the left has to be the number 5 or more, else it rounds down.

23.827 rounds up because the 8 is more than 5.

1.218 rounds down because 2 is less than 5.

24-1= 23

Answer:

TWO CRACKERS

Step-by-step explanation:

I'm assuming they want to find x. Here we see that these two are similar triangles, so the sides are reflective. 5x/5 should be equal to 4/x, so 5x/5 = 4/x. If we use cross multiplying we get 5x^2 = 20. divide both sides by 5 and we get x^2 = 4 or x = 2.

Hope this helped

To find the polar equation of a conic with focus at the pole, directrix y=3, and eccentricity of 2, we can use the definition of a conic in polar coordinates.

The general form of the polar equation for a conic with focus at the pole is given by:

r = \(\frac{ed}{1+e\cos(\theta-\theta_0)}\)

Where:

- r is the distance from the origin (pole) to a point on the conic.

- e is the eccentricity.

- d is the distance from the pole to the directrix.

- θ is the angle between the polar axis and the line connecting the pole to a point on the conic.

- θ_0 is the angle between the polar axis and the line connecting the pole to the focus.

In this case, the focus is at the pole, so θ_0 = 0. The directrix is y = 3, which means its distance from the pole is d = 3. The eccentricity is given as 2, so e = 2.

Substituting these values into the general equation, we get:

r =\(\frac{2\cdot3}{1+2\cos(\theta-0)}\)

Simplifying further:

r =\(\frac{6}{1+2\cos(\theta)}\)

Therefore, the polar equation of the conic with focus at the pole, directrix y=3, and eccentricity of 2 is:

r =\(\frac{6}{1+2\cos(\theta)}.\)

This equation describes the shape of the conic in polar coordinates, where r represents the distance from the origin to a point on the conic, and θ represents the angle between the polar axis and the line connecting the origin to the point.

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Answer:

9

Step-by-step explanation:

The \(n\)term is \(2n+1\).

\(S_n=\frac{3+2n+1}{2}(n)=99 \\ \\ \frac{n(2n+4)}{2}=99 \\ \\ n(n+2)=99 \\ \\ n^2+2n-99=0 \\ \\ (n+11)(n-9)=0 \\ \\ n=9 \text{ } (n>0)\)

The number of terms that needed to make the sum to 99 is 9

The first term of the arithmetic progression = 3

The common difference = 2

The sum of n term is = (n/2) [2a+(n-1)d]

Where a is the initial term

d is the common difference

Substitute the values in the equation

(n/2) [2(3)+(n-1)2] = 99

(n/2) [6 + 2n - 2] = 99

(n/2)[4+2n] = 99

n(2 + n) = 99

2n + \(n^2\) = 99

\(n^2\) + 2n - 99 = 0

Split the terms

\(n^2\) - 9n +11n - 99 =0

n(n -9) + 11(n - 9) = 0

(n + 11)(n - 9) = 0

n = -11 or 9

Since n cannot be a negative number, therefore n = 9

Hence, the number of terms that needed to make the sum to 99 is 9

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Answer:

Step-by-step explanation:

S = 12mm

r  = 8mm

What is the measure, in radians, of the circle or central angle?

The measure of a circle in radians is 2 radians.  I think you want the central angle thata.

theta = S/r  radians

theta = 12/8  radians

theta = 1.5 radians  for the central angle

The measure in radians of the circle is 1.5π   radians

The angle between two radii of a circle is known as the central angle of the circle.

given: S = 12 mm

r  = 8 mm

circumference of a circle=2π radians

Since, 16π=2π radians.

1π= 2π /16

for,

12π =2π /16 *12

       = 3/2*π

       = 1.5π

\(\theta\) = 1.5π   radians

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Answer:

I did the whole thing

Step-by-step explanation:

How you do them is you just take each number, and multiply by the number that both fractions can multiply into. I showed how in the picture.

Answer:

1.23

30

2.24

35

3.25

36

4.11

10

5.13

14

6.662

1143

7.19

15

8.11

12

Step-by-step explanation:

tama po ba answer ko

Answer:

62.92

Step-by-step explanation:

21 percent of 52$ is 10.92 then add em together hope it helps

69

Step-by-step explanation:

angles 111 and 3 are the same. in a trapezoid bottom base angles are the same and the top base angles are the same. so in order to find angle 2 you must subtract 111 from 180 because the top angles are supplementary to the bottom

180 - 111 = 69

Answer:

The answer will be 69

This is because angle 3 would also be 111

Angles in a quadrilateral add up to 360

So, 360-(111+111)

=138

there are two angles left, angle 1 ND 2, THEY ARE THE SAME VALUE. So DIVIDE 138 by 2, and you would get your answer 69 degrees.

Hope this helps!!

Answer:

  48.8 lbs

Step-by-step explanation:

The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:

  a/sin(A) = c/sin(C)

  x/sin(26°) = 80/sin(134°)

  x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds

The larger component force is about 48.8 pounds.

The four steps for solving linear systems are;

A variety of ways for solving linear systems exist which include;

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Answer:

graphing

algebraic methods

using inverse matrices

transforming an augmented matrix to reduced row echelon form

Cramer’s rule

Step-by-step explanation:

Answer:

4 5/8

Step-by-step explanation:

Rewriting our equation with parts separated

=4+12+18

Solving the fraction parts

12+18=?

Find the LCD of 1/2 and 1/8 and rewrite to solve with the equivalent fractions.

LCD = 8

48+18=58

Combining the whole and fraction parts

4+58=458

A data collected from 35 recent calls on users to perform routine preventive maintenance service :

a) A simple linear regression model is y = b₀ + b₁x.

b)The least-squares method, the value of regression coefficients ,b₁ =14.674 and b₀=1.456.

c) Yes, we have an evidence to support the two variables, X and Y have a meaningful linear connection.

d) The coefficient of determination is, r ²= 0.9524

e) The standard error of the estimate is 9.5693..

f) The expected total service time is , y = 96.84 when the number of copiers x = 6.5..

The study taken by company wants to know the relationship between the number of copiers serviced and the total service time required to repair the copiers.

a) Here, Y is the total amount of service minutes and X is the number of copiers. X and Y are the independent and dependent variables, respectively. A straight forward regression model is , y = b₀ + b₁x

where b₀ is the intercept and b₁ is the slope of the regression line.

b) Using least squares method ,

b₁ = ∑( (xᵢ - X-bar)(yᵢ - Y-bar)/ ∑(xᵢ - X-bar)²)

=14.674

b₀ = Y-bar - b₁ X-bar

=1.456

c) The P value <α = 0.05 , Consequently, we disprove the null hypothesis. Therefore, there is enough data to draw the conclusion that the two variables have a meaningful linear connection. A sizable linear effect of X on Y exists.

d) The coefficient of determination r ² = 0.9524

This means that 95.24% The variation in Y is explained by the regression line.

e) The standard error of the estimate is 9.5693

This means that the average distance the observed valued falls from the regression line is 9.5693

f) H₀ : b₁ =0

Hₐ : b₁ ≠0

The test statistic, t= b₁/SE

=14.674/0.5711

=25.6943

Using the t-table, the critical value for t statistic is tc = 2.0345 , t > tc

Therefore we reject the null hypothesis, H₀.

g) When x = 6.5

y = 1.456+(14.674 6.5)

y = 96.84

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Answer:

The equation \(x=4\) represents in R^2 c) a line

The equation \(x=4\) represents in R^3 a) a plane

The equation \(y+3x=2\) represents in R^3 a) a plane

The equation \(z-4y=8\) represents d) a plane

The pair of equations \(y=2,z=8\) represents a) a line

Step-by-step explanation:

Let's start by studying each question :

1)

In R^2 , \(x=a\) with \(a\) ∈ IR is the equation of all vertical lines

In this case, the only free variable is the variable ''y''

R^2 has two dimensions (x and y) so if we set \(x=4\) we will have only one free variable in R^2 (which is a line in R^2). Therefore, \(x=4\) represents a line in R^2

Now, in R^3 we have three dimensions (x, y and z) so if we set \(x=4\) we will have only two free variables (y and z) and \(x=4\) will represent a plane (which have two dimensions) in R^3.

2) The equation \(y+3x=2\) in R^3 has the free variable ''z'' and given that we select a value (for example for ''x'') the another value from the variable ''y'' is determined. Finally, we have the free variables ''z'' and ''x'', and the variable ''y'' restricted for our choice of the variable ''x''.

The equation \(y+3x=2\) in R^3 (given that we have two free variables) represents a plane.

Using the same reasoning, the equation \(z-4y=8\) represents a plane (given that it has two free variables : ''y'' and ''x'')

Finally, the pair of equations \(y=2,z=8\) set values for ''y'' and ''z'' leading us ''x'' as the free variable. With only one free variable we will have a ''one dimensional'' geometric form. The one dimensional forms in R^3 are lines.

The final answer is a) a line.

The value of y is 48

y= kx

let's solve for k which is the constant

y= 8 , x= 4

k= 8/4

k= 2

Next is to calculate the value of y when x is 24

y = 2 × 24

y= 48

Hence the value of y is 48

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Answer:

6-n

Step-by-step explanation:

Just put that down for your answer

Answer:

A) 8

Step-by-step explanation:

The average of two numbers is 7.

6 and x have an average of 7.

sum of terms / number of terms = average

(6 + x)/2 = 7

6+x = 14

x = 8

The number is 8.

Answer: a 8

i forgot how I got that answer

The relation that can not be supported by the evidence in the image is option B

Corresponding angles are those that are located on the same side of the transversal and in identical relative positions to the parallel lines. Angles that correspond to one another have the same measure.

Alternate interior angles are those that are located on the transverse and within the area between the parallel lines, respectively. Congruent alternate interior angles exist.

Alternate external angles are those that are outside of the space between the parallel lines and on the opposing sides of the transversal. Congruent external angles exist between the two.

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I assume the radius is 6 cm.

Diameter = 2 times the radius.

D = 12 cm.

We now use C = pi•D.

C = pi•12cm

C = 12pi cm

Done!

Answer:

1.25 feet

Step-by-step explanation:

5/4=1.25

Answer:

\({ \tt{x + 30 \degree = 90 \degree}} \\ { \tt{x = 90 \degree - 30 \degree}} \\ { \tt{x = 60 \degree}}\)

If the point you end up at is coordinate (0.25, 0) then you would have ran one full lap around the track.

1. The given track is a circular track with a radius of 0.25 miles, and the center of the track is at (0, 0).

2. If you end up at the point (0.25, 0), then you would have ran one full lap around the track. This is because the coordinates of the point you end up at, (0.25, 0), are the same as the coordinates of the circumference of the track, which is located 0.25 miles from the center of the track.

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well, we know that 37.5% have finished it, that leaves unaccounted for 100% - 37.5% = 62.5%.

now, of those 62.5% fellows only 40% have finished only half of it, how many are those?

well, what's 62.5% of 32?   what's 40% of that much?

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{62.5\% of 32}}{\left( \cfrac{62.5}{100} \right)32}\implies 20 ~\hfill \stackrel{\textit{40\% of 20}}{\left( \cfrac{40}{100} \right)20}\implies \text{\LARGE 8}\)

Answer:

e-5=2f

take '-5' to the other side where '2f' is

e=2f+5