Answers
Answer:
Approximately \(3.9\times 10^{-11}\; {\rm m}\).
Explanation:
By the Heisenberg Uncertainty Principle:
\(\displaystyle \Delta p\, \Delta x \ge \frac{h}{4\, \pi}\),
Where:
\(\Delta p\) is the uncertainty in momentum, \(\Delta x\) is the uncertainty in position, and\(h \approx 6.626 \times 10^{-34}\; {\rm kg \cdot m^{2}\cdot s^{-1}}\) is Planck's Constant.In this question, the measured velocity of this electron is \(3.15 \times 10^{6} \pm 0.15\times 10^{6}\; {\rm m\cdot s^{-1}}\). The uncertainty of this measurement is \(\Delta v = 1.5 \times 10^{5}\; {\rm m\cdot s^{-1}}\).
Assume that the mass of this electron is the same as that of a stationary electron: \(m = m_{e} \approx 9.11 \times 10^{-31}\; {\rm kg}\).
With an uncertainty in velocity of \(\Delta v = 1.5 \times 10^{5}\; {\rm m\cdot s^{-1}}\), the uncertainty in the momentum of this electron would be:
\(\begin{aligned}\Delta p &= m\, \Delta v \\ &\approx (9.11 \times 10^{-31}\; {\rm kg})\, (1.5 \times 10^{5}\; {\rm m\cdot s^{-1}}) \\ &\approx 1.3665 \times 10^{-24}\; {\rm kg\cdot m\cdot s^{-1}} \end{aligned}\).
Rearrange the Uncertainty Principle to find the uncertainty in position:
\(\begin{aligned}\Delta x &= \frac{h}{4\, \pi\, \Delta p} \\ &\approx \frac{6.626 \times 10^{-34}\; {\rm kg\cdot m^{2}\cdot s^{-1}}}{4\, \pi\, (1.3665 \times 10^{-24}\; {\rm kg\cdot m\cdot s^{-1}})} \\ &\approx 3.86 \times 10^{-11}\; {\rm m}\end{aligned}\).
Related Questions
Which two statements are true for reversible reactions that reach dynamic
equilibrium?
I A. The products of the forward and backward reactions remain
constant at equilibrium.
B. The products of the forward reaction form more quickly than its
reactants.
C. The rate of the forward reaction is greater than the rate of the
backward reaction.
- D. The rate of the forward reaction is equal to the rate of the
backward reaction at equilibrium.
Answers
Answer:
Explanation:
In a reversible reaction which has reached dynamic equilibrium , rate of forward reaction is equal to rate of backward reaction .
Following is a reversible chemical reaction .
A + B = C + D
Rate of forward reaction = k₁ x [ A ] x [ B ]
Rate of backward reaction = k₂ x [ C ] x [ D ]
k₁ x [ A ] x [ B ] = k₂ x [ C ] x [ D ]
[ A ] x [ B ] = k₂ / k₁ [ C ] x [ D ]
[ A ] x [ B ] = k [ C ] x [ D ]
The products of the forward and backward reactions remain
constant at equilibrium.
Hence option A and D are correct statement .
An Eagar resident is driving down the road late at night at a velocity of 14 m/s. Suddenly an elk runs out in front of the car and the driver slams on the brakes. If the car comes to a stop (velocity final = 0 m/s) in 32 m, what is the acceleration of the car?
Answers
The acceleration of the car is approximately -3.06 m/s^2.
To find the acceleration of the car, we can use the kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity = 0 m/s
u = initial velocity = 14 m/s
a = acceleration (to be determined)
s = displacement = 32 m
Plugging in the values into the equation, we can solve for acceleration:
0^2 = 14^2 + 2a(32)
Simplifying:
0 = 196 + 64a
Rearranging the equation:
64a = -196
Dividing both sides by 64:
a = -196/64
a ≈ -3.06 m/s^2
This means that every second, the car's velocity decreases by 3.06 meters per second. The negative sign indicates that the acceleration is in the opposite direction of the initial velocity, opposing the car's motion and bringing it to a stop.
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CAN YOU HELP MEEEEEEEEEE PLEASEEEE
Answers
Answer:
What are your options? also i believe the answer may be ecosystem.
Explanation:
There are both biotic and abiotic factors in an ecosystem. Be cause living organisms Are Biotic. While water and rocks are abiotic which are needed to form an ecosystem.
6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
Answers
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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A uniform beam of length L = 2.2 m and mass M = 49 kg has its lower end fixed to pivot at a point P on the floor, making an angle θ = 18° as shown in the diagram. A horizontal cable is attached at its upper end B to a point A on a wall. A box of the same mass M as the beam is suspended from a rope that is attached to the beam one-fourth L from its upper end.
What is the y-component Py of the force, in newtons, exerted by the pivot on the beam?
Write an expression for the tension T in the horizontal cable AB.
What is the x-component Px of the force, in newtons, exerted by the pivot on the beam?
I cannot figure part C
Answers
Hi there!
Part A.
To solve this part, all we need to do is a summation of vertical forces.
We have the following acting on the beam :
- Force of gravity (Fg, down)
- Force of tension from the rope holding the box (T, down)
- Force exerted by pivot (Py, up)
These sum to zero because the beam is not accelerating vertically.
\(\Sigma F = -F_g - T + P_y = 0\)
\(P_y = F_g + T\)
The tension force is equal to the box's weight because the forces on the box are balanced. Let's use values and solve.
\(P_y = 49(9.8) + 49(9.8) = \boxed{960.4N}\)
Part B.
We must begin by doing a summation of torques. Placing the pivot point at the pivot, we have the following present:
- Force of gravity acting at the center of mass of the rod (CC, at L/2)
- The tension of the horizontal cable acting at the end of the rod (CCW, at L)
- The force of tension in the rope holding the box (CC, at 3L/4)
Since the rod is not rotating, these torques sum to zero.
The equation for torque is:
\(\tau = r \times F\)
This is a cross-product, and you must find the lever arm (perpendicular distance between pivot and line of action of force). We will need to use trigonometry for this.
Now, let's find the torque from all three of these forces.
- Force of gravity at center:
The perpendicular distance between the force of gravity and the pivot point is the cosine with respect to the angle made with the floor.
\(\tau = Mg\frac{L}{2}cos(\theta) = 49(9.8)*\frac{2.2}{2} cos(18) = 502.367 Nm\)
- Tension of horizontal cable:
The lever arm is the sine with respect to the angle. We will still have to solve for the value of 'T'.
\(\tau = TLsin\theta = T(2.2)sin(18) = 0.68T\)
- Tension of rope holding box:
The tension is equal to the weight of the box since the box isn't accelerating. Thus, the torque would be:
\(\tau = Mg(\frac{3L}{4}) = 49(9.8)*\frac{3(2.2)}{4}cos(18) = 753.55 Nm\)
Summing with clockwise torques + and counterclockwise -:
\(\Sigma \tau = 502.367 + 753.55 - 0.68 T = 0 \\\\1255.917 = 0.68T\\T = \boxed{1847.38 N}\)
Part C.
This part is a lot easier than it seems. All we need to do is a summation of horizontal forces.
We only have two:
- The horizontal tension in the cable to the left (1847.38 N)
- The horizontal force exerted by the pivot on the beam to the right
These two balance out because there is no acceleration of the beam horizontally, so:
\(\Sigma F = P_x - T = 0 \\\\P_x = T\\\\P_x = \boxed{1847.38 N}\)
**to the right
Answer:
a) 960.4 N
b) T= 5/4 Mg CotanΘ
c) 1847. 38
Explanation:
a) Py= 2Mg
=2(49 x 9.8)
= 960.4
b) T= (Mg x 1/2 x cos Θ + Mg x 3/4 x cos Θ) / sin Θ
T= 5/4 X Mg cotanΘ
c) T= (5/4) x (49 x 9.8) cotan (18)
T= 1847.37954
= 1847.38
PLS HELP
Which sentence correctly explains the process and conditions needed for sleet to form?
During thunderstorms and extremely cold temperatures, water droplets freeze in layers and form balls or chunks of ice.
Both the temperature of the cloud and the temperature of the air must be below freezing in order for the flakes to fall from the sky.
A liquid form of precipitation that is formed in above freezing temperatures becomes heavier as it falls the ground in the form of raindrops.
Ice crystals melt as they fall through a warm layer of air and then refreeze into small ice pellets as they pass through a colder layer of air.
Answers
The statement 'Ice crystals melt as they fall through a warm layer of air and then refreeze into small ice pellets as they pass through a colder layer of air' is correct.
Describe the characteristics of a thunderstorm.A cloud that produces both rain & lightning is called a thunderstorm. Thunderstorms are dangerous in general. All thunderstorms produce lightning as a byproduct. In the United States, lightning annually results in an estimated of 300 injuries & 80 fatalities.
What occurs when a thunderstorm strikes?A thunderstorm is the small-scale storm that includes both thunder and lighting. Moreover, it frequently delivers heavy rain as well as violent gusts. Certain thunderstorms have a chance of producing hail and/or tornadoes. Localized big snow showers during the winter may also include thunder and lightning.
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how many times larger than a centigram is a dekagram
Answers
Answer:
A dekagram is thousand (1000) times larger than a centigram.
Explanation:
→ [1 dekagram = 1,000 centigrams]
→ 1 dekagram = 10 grams
→ 10 grams = 100 decigrams
→ 100 decigrams = 1,000 centigrams
Four forces of magnitude 10N 5N 4N and 6N act on an object in the direction of north west east and south respectively find the magnitude and direction of their resultant
Answers
The magnitude and direction of the resultant force (F=10N+5N+4N+6N) when four forces of magnitude 10N, 5N, 4N, and 6N operate on an object in the directions of north, west, east, and south, respectively, is 25N.
What do you mean by magnitude?In terms of physics, magnitude is just "distance or quantity." It displays an object's size, direction, or motion in absolute or relative terms. It is employed to indicate the size or scope of something. The word "magnitude" in physics frequently denotes a size or quantity.. Something's magnitude is determined by its size. For example, a car moves faster than a bike with terms of speed. The speed difference between the car and the bike in this case is greater. It reveals the absolute or relative size or direction that an object moves when in motion.
What is magnitude of speed?Speed is defined as the magnitude of velocity, and the magnitude of the slope of the displacement-time graph provides the speed. Since the slope gets steeper as we move from A to B, Speed is increased as a result between points A and B.
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A mass of 0.250 kg is attached to a spring and undergoes simple harmonic oscillations with a period of 0.640 s. What is the force constant of the spring?
Answers
Answer:
Force constant of the spring (k) = 24.07 N/m
Concept/Theory:
The period \( \sf (T_s) \) of a spring-mass system is proportional to the square root of the mass (m) and inversely proportional to the square root of the force constant of the spring (k).
Equation of period:
\( \boxed{ \bf{T_s = 2 \pi \sqrt{\dfrac{m}{k}}}}\)
Explanation:
Mass = 0.250 kg
Period = 0.640 s
By substituting values in the equation, we get:
\( \rm \longrightarrow 0.640 = 2 \pi \sqrt{\dfrac{0.250}{k}} \\ \\ \rm \longrightarrow 2 \times 3.14 \sqrt{ \dfrac{0.25 0}{k} } = 0.640 \\ \\ \rm \longrightarrow 6.28 \sqrt{ \dfrac{0.250}{k} } = 0.640 \\ \\ \rm \longrightarrow \sqrt{ \dfrac{0.250}{k} } = \frac{0.640}{6.28} \\ \\ \rm \longrightarrow \frac{0.250}{k} = { \bigg(\frac{0.640}{6.28} \bigg) }^{2} \\ \\ \rm \longrightarrow \frac{k}{0.250} = \bigg( { \frac{6.28}{0.640} \bigg) }^{2} \\ \\ \rm \longrightarrow k = \bigg( { \frac{6.28}{0.640} \bigg) }^{2} \times 0.250 \\ \\ \rm \longrightarrow k = 24.07 \: N/m\)
The force constant of the spring is approximately 24.038 newtons per meter.
As we are talking about Simple Harmonic Motion. In this exercise we need to determine the Spring Constant (\(k\)), in newtons per meter, from the equation of the Period (\(T\)), in seconds, which is described below:
\(T = 2\pi\cdot \sqrt{\frac{m}{k} }\) (1)
Where \(m\) is the mass of the moving element, in kilograms.
If we know that \(T = 0.640\,s\) and \(m = 0.250\,kg\), then the spring constant of the spring is:
\(0.640 = 2\pi\cdot \sqrt{\frac{0.250}{k} }\)
\(\sqrt{\frac{0.250}{k} } \approx 0.102\)
\(\frac{0.250}{k} \approx 0.0104\)
\(k \approx 24.038\,\frac{N}{m}\)
The force constant of the spring is approximately 24.038 newtons per meter.
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A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?
Answers
Answer:
1km west
Explanation:
Because if the cyclist is going back 2km then its 3-2=1km
Hector stretches a spring with a spring constant of 3 N/m until it is extended by 50 cm. What is the elastic potential energy stored by the spring?
Answers
The elastic potential energy stored in the spring is 0.375 J.
The formula for elastic potential energy is:
E = 1/2 * k * x^2
where:
* E is the elastic potential energy in Joules
* k is the spring constant in N/m
* x is the distance the spring is stretched or compressed from its equilibrium position in meters
In this problem, we have:
* k = 3 N/m
* x = 0.5 m (50 cm)
Substituting these values into the formula, we get:
E = 1/2 * 3 * 0.5^2 = 0.375 J
Therefore, the elastic potential energy stored in the spring is 0.375 J.
A hockey puck of mass 150 g is sliding south along the ice and slows at a rate of 1.2 m/s². What is the net force acting on the puck?
Answers
Answer:
0.18 N or 180 N
Explanation:
Mass,m = 150g
acceleration,a = 1.2m/s2
CHANGE FROM g TO kg
1kg =1000g
so 150g =150/1000 = 0.15kg
But Force, F = mass,m × acceleration,a
F=ma
F=0.15×1.2
F= 0.18 N
A concave lens causes light to diverge. Is this true or false?
Answers
True
Explanations:Another name for a concave lens is diverging lens.
Light rays that pass through a concave/diverging lens diverge from their axes.
Images formed by a concave lens are virtual, upright, and diminished. They are also formed between the focal point and the lens
Therefore, it is true to say that a concave lens causes light to diverge
Which statements describe kinetic and potential energy? Check all that apply.
Energy can be stored in the position of an object.
Energy is not present in a moving object.
Energy can be stored in the position of the particles that make up a substance.
Energy exists as movement of the particles of a substance.
Energy is greater in faster-moving particles than in slower-moving particles.
Energy is lower in objects with greater mass than in objects with less mass.
Answers
Answer:
First option, third option, fourth option, and the fifth option.
Explanation:
Kinetic energy is energy an object has when it's motion, the greater the speed the greater the kinetic energy. For example, a car moving and increasing in speed is kinetic energy since the object is in motion. If the car stops and parks in a parking lot that is potential energy. Potential energy is the amount of energy an object has when it's at rest or not in motion.
So, the answer for this question is as followed first option or "energy can be stored in the position of an object." Third option or "Energy can be stored in the position of the particles that make up a substance." Fourth option or "Energy exists as movement of the particles of a substance." The last answer will be the fifth option or "Energy is greater in faster-moving particles than in slower-moving particles."
Hope this helps.
How do I find the mass in kg
Answers
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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A book is at rest on a table identify the correct free body diagram for the situation
Answers
Answer: 3rd one
Explanation:
3rd diagram is the correct free body diagram for the situation.
What is Free body diagram?Free-body diagrams are used to display the relative strength and direction of all forces that are being applied to an item in a certain scenario.
A unique illustration of the vector diagrams that were covered in a previous lesson is the free-body diagram. We will make use of these graphics throughout our study of physics. In a free-body diagram, the size of the arrow indicates the strength of the force.
The force is acting in the direction indicated by the arrow's direction. The exact type of force is labeled next to each force arrow in the diagram. In a free-body diagram, it is common practice to depict the item as a box and to draw the force arrow from the box's center outward in the direction.
Therefore, 3rd diagram is the correct free body diagram for the situation.
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The potential at location A is 570 V. A positively charged particle is released there from rest and arrives at location B with a speed vB. The potential at location C is 1180 V, and when released from rest from this spot, the particle arrives at B with twice the speed it previously had, or 2 vB. Find the potential at B.
Answers
Answer:
Potential at B, VB = 367 V
Explanation:
The explanation is found in the attachment below
Two small plastic spheres are given positive electric charges. When they are 15 cm apart the repulsive force between them has magnitude 0.22 N. What is the charge on each sphere?
Answers
The charge on each sphere is 742 n
What is Charge?In physics, Charge, also known as electric charge is a electrical charge, or electrostatic charge and symbolized q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.
According to the question,
Distance = 15cm or 0.15m
Force = 0.22N
\(K=9*10^{9} kgm^2/c^2\) ( this is a constant value of K)
By using the formula,
F = \(\frac{kQq}{d^{2} }\)
0.220 N = 8.99
N·m²/C² * Q² / (0.15m)²
Q = 7.42e-7
C = 742 n
C is the charge of each sphere .
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3) If the displacement of an object, x, is related to velocity, v, according to the relation .x = Av,
the constant, A, has the dimension of which of the following?
a) acceleration
b) length
c) time
d) area
Answers
If the displacement of an object, x, is related to velocity, v, according to the relation .x = Av the dimension of which of the following is time.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.
A = x/v
since x is displacement and v is velocity
x/v = m/(m/s) = s
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NEED HELP WITH PHYSICS< WILL NAME BRAINLIEST
Answers
Answer:
c
Explanation:
A certain net force acting on a 5kg mass produces an acceleration of 2 m/s2 calculate the force
Answers
Answer:
10 N
Explanation:
Newton's Second Law equation: Fnet = ma
Assuming no frictional force, plug in the values to get your answer!
Fnet = 5kg x 2m/s^2 = 10 N
Experiments carried out on the television show Mythbusters determined that a magnetic field of 1000 gauss is needed to corrupt the information on a credit card's magnetic strip. (They also busted the myth that a credit card can be demagnetized by an electric eel or an eelskin wallet.) Suppose a long, straight wire carries a current of 5.0 A .
How close can a credit card be held to this wire without damaging its magnetic strip?
Answers
Answer:
his distance is too small (r = 0.01 mm), therefore the cut can be at any distance
Explanation:
For this exercise let's use the ampere law.
Let's use a cylinder as the circulating surface
∫ B. ds = μ₀ I
in this case the field is circular and ds is circular therefore the angle between them is zero and cos 0 = 1
B 2π r = μ₀ I
r = \(\frac{\mu_o I}{2\pi B}\)
The field needed to demagnetize the card is B = 1000 gauss = 0.1 T
r = \(\frac{4\pi 10^{-7} 5.0 }{2\pi \ 0.1}\)
r = 2 10⁻⁷ 5.0/0.1
r = 1 10⁻⁵ m
this distance is too small (r = 0.01 mm), therefore the cut can be at any distance
50 POINTS!!! PLEASE!!!!!! Pls help me with this been stuck on it in like FOREVER!! PLSS.
Answers
Answer:
it will move in 356.5g in diagonal direction(resultant or between the both direction)
Explanation:
285+428/2=356.5g
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Help pleaseeee need the answers ASAP
Answers
Answer:
- 670 kg.m/s
Explanation:
Newton's third law states that to every action, there is equal and opposite reaction force. Since the force will be same but different in direction and acted in the same time then the impulses ( force multiply by time) of the two car be same in magnitude but different in direction - 670 kg.m/s
Using conservation of momentum, explain how two vehicles can collide and the final location is the same as their spot of collision.
Answers
Answer:
Hope this is helpful!
Explanation:
In every form of collision the momentum is conserved and it is the same before and after the collision, but in perfectly elastic collision, there is no loss of kinetic energy in the collision. In an inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision. Any macroscopic collision between objects will convert some of the kinetic energy into internal energy and other forms of energy.
4. A 40.0 kg child swings in a swing supported by two chains, each 3.00 m long. If the tension in each at the lowest point is 350N, find (i) The child’s speed at the lowest point ,
Answers
The child's speed at the lowest point is 5.42 m/s.
At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.
Using the conservation of mechanical energy, we can write:
Potential energy at highest point = Kinetic energy at lowest point
mgh = (1/2)mv²
where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.
First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:
h = (1/2)3.00 m = 1.50 m
Next, we can solve for the child's speed at the lowest point:
mgh = (1/2)mv²
40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²
588 J = 20.0 kg * v²
v² = 29.4 m²/s²
v = 5.42 m/s
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State Newton’s Universal Law of Gravitation.
Answers
Answer:
This law states that every particle attract every other particle in the universe with a force that is directly proportional to the product of their mass and inversely proportional to the square of the distance between the center
6a. A special lamp can produce UV radiation. Which two statements
describe the electromagnetic waves emitted by a UV lamp? *
They have a higher frequency than X-rays.
They have the same wave speed as visible light
They have a longer wavelength than microwaves.
They have a lower frequency than gamma rays.
They have a greater wave speed than radio waves.
Answers
Answer:
The correct options are:
B) They have the same wave speed as visible light
D) They have a lower frequency than gamma rays.
Explanation:
B) Ultraviolet rays, commonly known as UV rays, are a type of electromagnetic ways. As electromagnetic waves, in the layman's term, are all kinds of life that can be identified, all electromagnetic waves (UV rays, visible light, infrared, radio etc) all travel with the same velocity, that is the speed of light, given as v = 3 × 10⁸ m/s
D) The frequency of all electromagnetic rays can be found by electromagnetic spectrum (picture attached below).
We can clearly see in the picture that the frequencies of UV rays lie at about 10¹⁵ - 10¹⁶ Hz which is lower than the frequency of Gamma ray, which lie at about 10²⁰ Hz.
does altitude has an effect on weight? HELP
Answers
Answer: lose weight at high altitudes.
Explanation:
Answer:
Just a week at high altitudes can cause sustained weight loss, suggesting that a mountain retreat could be a viable strategy for slimming down. Overweight, sedentary people who spent a week at an elevation of 8,700 feet lost weight while eating as much as they wanted and doing no exercise
9. Which of these tissues hold bones together at movable joints? O ligaments O cartilage O tendons O disks
Answers
Answer:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Explanation:
The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.
Answer:
The answer is ligaments!
Explanation:
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