the speed of an electron in a particle accelerator is 0.93 c . find its de broglie wavelength. (use relativistic momentum.)

Answers

Answer 1

The de Broglie wavelength of the electron is 0.038 nm.

The de Broglie wavelength of a particle is given by λ = h/p, where h is the Planck's constant and p is the momentum of the particle. In relativistic mechanics, the momentum of a particle is given by p = γmv, where γ is the relativistic factor, m is the rest mass of the particle, and v is the velocity of the particle.

First, we need to calculate the relativistic factor γ. It is given by γ = 1/√(1-(v/c)²), where c is the speed of light. Here, the speed of the electron is given as 0.93c, so we have γ = 1/√(1-(0.93)²) = 2.73.

Next, we can calculate the momentum of the electron using p = γmv, where m is the rest mass of the electron, which is 9.11 x 10⁻³¹ kg. Thus, p = (2.73)(9.11 x 10⁻³¹ kg)(0.93c) = 2.38 x 10⁻²² kg m/s.

Finally, we can calculate the de Broglie wavelength using λ = h/p, where h is the Planck's constant, which is 6.63 x 10^-34 J s. Thus, λ = 6.63 x 10⁻³⁴ J s / 2.38 x 10⁻²² kg m/s = 0.038 nm.

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Related Questions

how can empiricism assist you as a teacher to achieve your goals in a classroom​

Answers

Empiricism is the notion that all ideas are derived from experience, that all ideas may be relevant or are about experiences, or that all prepositions and beliefs that are seen to be reasonable are known or justified largely by experience. The main function of experience is explained by empiricism. Empiricism maintains that experience serves as the foundation for all knowledge.

Empiricism plays a major role in the psychological history of America and Britain. Psychology is unjustified in light of human-made scientific knowledge. Empiricism was a key component of ancient, medieval, and contemporary philosophy. The popular sense of the day seemed to be empiricist (Britannica). Empiricism was seen to be a crucial force resisting the pretense of speculative rationalist philosophy. Even if they accepted the majority of the significant information that was nonempirical, most medieval philosophers adopted the empiricist approach, at least in terms of concepts.

Empiricism, therefore, takes on many forms. Their relaxation is the major factor that separates them. According to the widely accepted explanation, people's perceptions of their physical environment are influenced by their experiences. According to the phenomenalist interpretation, assistance merely benefits a person's sensory experience.

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Identrying the speed of the Cart
Complete the statements using data from Table A of your Student Guide.
cm/s.
The speed of the cart after 3 seconds of Low fan speed is
The speed of the cart after 5 seconds of Medium fan speed is
The speed of the cart after 2 seconds of High fan speed is
cm/s.
cm/s.

Answers

The speed of the cart after 3 seconds of Low fan speed is equal to 54 cm/s.

How to calculate the speed?

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

At Low fan speed after 3 seconds, the distance covered is 162 cm:

Speed = 162/3

Speed = 54 cm/s.

At Medium fan speed after 5 seconds, the distance covered is 600 cm:

Speed = 600/5

Speed = 120 cm/s.

At High fan speed after 2 seconds, the distance covered is 128 cm:

Speed = 128/2

Speed = 64 cm/s.

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Identrying the speed of the CartComplete the statements using data from Table A of your Student Guide.cm/s.The

The speed of the cart after 3 seconds of Low fan speed is 55 cm/s.

The speed of the cart after 5 seconds of Medium fan speed is 120 cm/s.

The speed of the cart after 2 seconds of High fan speed is 63 cm/s.

What is speed?

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.

The graph in the attachment may be used to estimate the cart speed for various fan speeds.

Blue letters indicate the low fan speed. When the line drawn from x hits the blue line, the elapsed time is indicated on the x-axis cart speed after three seconds.

This is equivalent to 55 cm/s.Yellow markings indicate the medium fan speed. After 5 seconds, the line drawn from the point marked 5 on the x-axis crosses the yellow line, marking the time that has passed.

The intersection of the yellow line with the line drawn from the point marked 5 on the x-axis indicates the cart speed five seconds later. The y-axis measurement is roughly 120 cm/s.

Green markings indicate the high fan speed. On the x-axis is the elapsed time. Cart speed at the place where the green line and the line drawn from the x-point axis 2 connect. The y-axis reading is roughly 63 cm/s.

Hence, after the specified seconds, the cart's estimated speeds at low, medium, and high speeds are 55 cm/s, 120 cm/s, and 63 cm/s, respectively.

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What four things
are required for photosynthesis?

What four thingsare required for photosynthesis?

Answers

Explanation:

carbon dioxide, chlorophyll, water and light

Two whistles emit sounds of wavelength 3.2 m and 2.9 m which produce a beat frequency of about? a) 2 hertz b) 3 hertz c) 4 hertz d) 7 hertz e) 11 hertz

Answers

Two whistles emitting sound of wavelength 3.2 m and 2.9 m would produce a beat of frequency 11 Hertz, hence option e.

The beat frequency (f_beat) is given by the difference in frequency (f) between the two whistles,

f_beat = |f₁ - f₂ |, frequencies of the two whistles are f₁ and f₂ . The frequencies can be calculated from the wavelengths (λ) using the formula,

f = c/λ, speed of sound in air is c, which is approximately 343 m/s at room temperature and atmospheric pressure. For the first whistle with a wavelength of 3.2 m,

f₁ = c/λ₁

= 343/3.2

= 107.1875 Hz

For the second whistle with a wavelength of 2.9 m,

f₂ = c/λ₂

= 343/2.9

= 118.2759 Hz

The difference in frequency is,

f_beat = |f_1 - f_2|

= |107.1875 - 118.2759| ≈ 11.1 Hz

Therefore, the beat frequency is approximately 11 hertz.

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Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.

Answers

Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

How do we explain?

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and

In Hooke's law, Fspring=kΔx, what does the ∆x stand for

Answers

Answer:

Change in Displacement

Explanation:

delta/triangle = change

x = displacement

formula (if needed): final x - initial x

Answer:

the distance the spring stretches

Explanation:

i go to K12

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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How does something(the big bang) come from nothing by nothing i mean the first universe although we don't know where the first universe is but we do know that nothing can't come from something.

Answers

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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A 2000 kg car traveling at a speed of 34 m/s skids to a halt on wet concrete where μk = 0.40. How long are the skid marks?

Answers

The skid marks are about 295m long

The formula for calculating the frictional force is expressed as;

\(F=\mu R\)

Since the car is travelling at a speed, the expression becomes

\(\frac{mv^2}{r}=\mu R\)

m is the mass = 2000kg

v is the velocity = 34m/s

r is  the distance taken to skid

μ is coefficient of friction = 0.4

R is the normal reaction = mg = 2000 (9.8)

R = 19600N

Substitute the given values to get "r"

\(\frac{2000(34)^2}{r}=0.4 \times 19600\\\frac{2312000}{r} = 7840\\r=\frac{2312000}{7840}\\r= 294.89m\)

Hence the skid marks are about 295m long.

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Please help meeeeeeeeeee

Please help meeeeeeeeeee

Answers

Answer:

C

Explanation:

But I’m not quite sure

Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s2 .
A force acts on a 1.5 kg , mass, giving it an acceleration of 3.0 m/s2 .
1. If the same force acts on a 3.0 kg mass, what acceleration would be produced?
2. What is the magnitude of the force?

Answers

Answer:

1) 1.5 m/s^2

2) 4.5 N

Explanation:

From Newton's Second Law of motion, we know

\(F=m*a\)

Which states that to calculate the force acting on an object, you multiply its mass and acceleration.

So, we know an object of mass 1.5 kg has an acceleration of 3 m/s^2, then

\(F=m*a=1.5*3=4.5\)

A force of 4.5 N is acting on the object.

If a force of 4.5 N acts on a mass of 3kg we have

\(a=\frac{F}{m}=\frac{4.5}{3}=1.5\)

So, it would give it an acceleration of 1.5 m/s^2.

A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?

Answers

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.

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Make a poem about waves with 12 Lines and 3 Stanzas.

Answers

In a ocean full of storms

A new wave was born

Deep into that darkness flooding

Suddenly, I heard some pummeling

By the grave I saw the winds

And the sun just shined

Answer:

a friendly face that comes with waves,

the waves of all the memorial days,

and with these days we smile with pride,

as for the waves we used to ride,

given up the day has passed,

how it went away like an hour glass,

as if we knew the world was right,

just like the waves, oh so bright,

the time has come the days have passed,

the waves ashore the waves alast,

as if the friendly face was right,

the waves that rode, oh goodnight.

B6. [9 Marks] 30⁰ 20140X20 DE Ofe OTO A stainless-steel orthodontic wire is applied to a tooth as shown in the diagram below. The wire has an unstretched length of 3.1 cm and a diameter of 0.22 mm. If the wire is stretched by 0.10 mm during the procedure, find the magnitude and direction of the force on the tooth. Disregard the width of the tooth and assume Young's modulus for stainless-steel is 18 × 10¹0 Nm-². ​

Answers

The magnitude of the force on the tooth is approximately 0.022 N.

To find the magnitude and direction of the force on the tooth, we can use Hooke's Law, which states that the force exerted on an object is directly proportional to the change in length of a material when it is stretched or compressed.

First, we need to calculate the strain (ε) of the stainless-steel wire.

Strain is defined as the change in length divided by the original length:

ε = ΔL / L₀

Given that the change in length (ΔL) is 0.10 mm \((0.10 \times 10^{-3} m)\) and the unstretched length (L₀) is 3.1 cm \((3.1 \times 10^{-2} m)\), we can calculate the strain:

\(\epsilon=(0.10 \times 10^{-3} m)/(3.1 \times 10^{-2} m)=0.003225\)

Next, we can use Young's modulus (E) to calculate the stress (σ) in the wire.

Stress is defined as the force per unit area:

σ = E * ε

Given that Young's modulus (E) for stainless-steel is 18 × 10¹⁰ N/m², we can calculate the stress:

σ = (18 × 10¹⁰ N/m²) * 0.003225 = 5.805 × 10⁸ N/m²

Now, we can find the force (F) on the tooth by multiplying the stress by the cross-sectional area (A) of the wire:

F = σ * A

The cross-sectional area (A) can be calculated using the formula for the area of a circle:

A = π * (d/2)²

Given that the diameter (d) of the wire is 0.22 mm\((0.22 \times 10^{-3} m)\), we can calculate the cross-sectional area:

\(A = \pi * (0.22 \times 10^-3 m / 2)^{2} = 3.802 \times 10^{-8} m^2\)

Finally, we can calculate the force:

\(F = (5.805 \times 10^{8} N/m^{2}) * (3.802 \times 10^-8 m^{2}) \approx 2.206 \times 10^{-2} N\)

Therefore, the magnitude of the force on the tooth is approximately 0.022 N.

Since the wire is stretched, the force is pulling the tooth in the direction opposite to the stretching.

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1. Read the paragraph and choose a sentence that describes it best. Experiencing occasional anxiety is a normal part of life. However, people with anxiety disorders frequently have intense, excessive and persistent worry and fear about everyday situations. Often, anxiety disorders involve repeated episodes of sudden feelings of intense anxiety and fear or terror that reach a peak within minutes (panic attacks).

a) Anxiety episodes are normal, during them people experience worry about every situation
b) Panic attacks are connected to people being worried too much, these episodes are a part of normal human behavior
c) Anxiety disorders and anxiety are not the same
d) Fear and terror are a part of feeling anxious

Answers

The sentence that describes anxiety best is a) Anxiety episodes are normal, during them people experience worry about every situation

The paragraph explains that while having the odd attack of anxiety is natural, anxiety disorders are characterised by severe, excessive, and chronic concern and terror over ordinary events. It also clarifies how anxiety disorders can cause recurrent episodes of extremely severe panic.

A sensation of worry, dread, and unease is known as anxiety. Sweating, agitation, and tension may be experienced, along with a quick heartbeat. It might be a typical response to stress. For instance, while dealing with a challenging issue at work, one can have anxiety prior to a test or when making a crucial choice. A person may find it useful for coping. For some with anxiety disorders, the terror can be incapacitating and last for a long time.

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The tidal lung volume of human breathing, representing the amount of air inhaled and exhaled in a normal breath, is 500 cm3. (Assume atmospheric pressure.)(a) What is the number of molecules of air inhaled with each human breath when the air temperature is 18.0°C?________molecules(b) If the molar mass of air is 28.96 g/mol, what is the mass of air molecules inhaled with each breath? (Assume the air temperature is 18.0°C.)(c) It has been calculated that all of the air in Earth's atmosphere could be collected into a sphere of diameter 1,999 km at a pressure of 1.00 atm. What is the mass of the air in Earth's atmosphere? (Assume the density of air used in this calculation was 1.225 kg/m3.)(d) If all 7 billion humans on Earth inhaled simultaneously, what percentage of the atmosphere would be inhaled during this process? (Assume the air temperature is 18.0°C everywhere on Earth.)

Answers

Answer:

Explanation:

Temperature of air = 18°C = 273 + 18 = 291 K .

volume = 500 cc = 0 .5 litre .

pressure = one atmosphere ( atm) .

From gas equation , we can calculate this volume at NTP  as follows.

volume = .5 x ( 273 / 291  ) litre

= 0.469 litre .

In any gas at NTP , 22.4 litre contains 6.02 x 10²³ molecules

.469 litre will contain  6.02 x 10²³ x .469 / 22.4 molecules

= 126 x 10²⁰ molecules .

b )

one mole = 6.02 x 10²³ molecules

6.02 x 10²³ molecules  has weight of 28.96 grams

126 x 10²⁰ molecules has weight of 28.96 x 126 x 10²⁰ / 6.02 x 10²³ grams

= .606 gram .

c )

volume of all the air in the atmosphere = volume of sphere

=  4 / 3 x π  x R³

= ( 4 / 3) x 3.14 x (999.5 x 10³ )³ m³

= 4.18 x 10¹⁸ m³

density of air = 1.225 kg / m³

mass of air = 1.225 x 4.18 x 10¹⁸ kg

= 5.12 x 10¹⁸ kg

d )

volume of air inhaled by 7 billion people

= . 5 x 7 x 10⁹ litre

= 3.5 x 10⁶ m³ .

Total volume of air in atmosphere = 4.18 x 10¹⁸ m³

required percentage

= 3.5 x 10⁶ x 100 /  4.18 x 10¹⁸

= .8373 x 10⁻¹⁰ % .

Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3
Which statement describes the transformation of the graph of function f onto the graph of function g?
O The graph shifts 2 units right and 7 units down.
O The graph shifts 7 units left and 2 units up.
O
e graph shifts 7 units right and 2 units down.
O The graph shifts 2 units left and 7 units up.

Given the functions f(x)=(1/x-3)+1 and g(x) = (1/1+4)+3Which statement describes the transformation of

Answers

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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What is potential energy

Answers

Answer:

Potential Energy is when the energy is kept in place the object isnt moving so it isnt creating Kinetic energy.

Answer:

\(\boxed{\mathrm{view \ explanation}}\)

Explanation:

Potential energy is the energy stored in a body due to the body’s positioning or state.

A 135 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 63.7 kg person stands on the platform at a distance of 1.05 m from the center, and a 30.1 kg dog sits on the platform near the person 1.33 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis.

Answers

Answer:

the  moment of inertia is 380.14 kg-m^2

Explanation:

The computation of the moment of inertia is as follows:

The net moment of inertia is

= MR^2 ÷ 2 + m_p d_p^2 + m_d d_d^2

= 135 × 1.95^2 ÷2 + 63.7 ×  1.05^2 + 30.1 × 1.33^2

= 380.14 kg-m^2

hence, the  moment of inertia is 380.14 kg-m^2

We simply applied the above formula so that the correct value could come

And, the same is to be considered

The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?

Answers

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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A toy car rolls down a slope. If it takes 5.94 s to accelerate from 3.22 m/s to 12.4 m/s, what is the value of the acceleration?

2.01 m/s2

1.35 m/s2

1.55 m/s2

0.219 m/s2

Answers

Answer:

a = 1.55m/s²

Explanation:

a = (v_f-v_0)/t

a = (12.4m/s-3.22m/s)/5.94s

a = 1.55m/s²

03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.​

Answers

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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15. Which tectonic boundary would have many normal faults associated
with it?
A. Convergent
B. Divergent
C. Transform

Answers

Answer: A. Convergent

PLEASE HELP WILL MARK BRAINLIEST!!
A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is moving to the left at 2.0 m/s. If after collision the two
masses join together, what is their velocity after collision?
O-0.33 m/s
O-0.20 m/s
O +1.4 m/s
O +2.3 m/s

Answers

Answer:

- 0.33 m/s

Explanation:

An illustration is shown above,

In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,

m1u1 - m2u2 = (m1 + m2)v

Where,

m1 = mass of the first object

u1 = initial velocity of the first object

v1 = final velocity of the first object

m2 = mass of the second object

u2 = initial velocity of the second object

v2 = final velocity of the second object

Therefore,

(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v

12 - 16 = 12v

-4 = 12v

Divide both sides by 12,

-4 / 12 = 12v / 12

-1 / 3 = v

v = -0.33 m/s

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If an astronaut weighs 148 N on the Moon and 893 N on Earth, then what is his mass on Earth? In kg
Use g = 9.81 m/s

Do not plagiarize (copy or paste), give nonsensical answers (ones that don't answer the question)

I will report unnecessary answers that are for points only

Answers

Considering the definition of weight, the mass of the astronaut on Earth is 91.03 kg.

Definition of weight

Weight is the force that a certain body exerts on the point where it is supported. That is, the weight of a body is the gravitational force acting on that body.

Weight is calculated as the product of the object's mass and the value of the gravitational acceleration:

W= m×g

Mass of an astronaut

In this case, you know:

Weight on Earth: W= 893 Ng= 9.81 m/s²

Replacing in the definition of weight:

893 N= m× 9.81 m/s²

Solving:

m=893 N÷ 9.81 m/s²

m= 91.03 kg

Finally, the mass is 91.03 kg.

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Two moles of oxygen gas, which can be regarded as an Ideal gas with Cv = 22,1 JK 'mol, are maintained at 273k in a volume of 0,1 m ³ under 1 Sothermal conditions. Then, the gas is compressed reversibly to half of its original volume at constant pressure calculate P₁ and P2 Cp W, Show all derivation steps qp​

Answers

Answer:

P1 = 45,174 Pa

P2 = 90,348 Pa

W = 2,259 J

Q = 2,259 J

ΔS = 0

Explanation:

We can use the ideal gas law, PV = nRT, to solve this problem. Since the gas is at constant temperature (isothermal), we can simplify this to PV = constant.

Given that there are two moles of oxygen gas in a volume of 0.1 m^3 at 273 K, we can calculate the initial pressure as follows:

P1V1 = nRT

P1 = nRT/V1

P1 = (2 mol)(8.31 J/mol.K)(273 K)/(0.1 m^3)

P1 = 45,174 Pa

Next, we compress the gas reversibly to half of its original volume (i.e. V2 = 0.05 m^3) at constant pressure. We can use the same equation, PV = constant, and the fact that the pressure is constant to solve for the final pressure:

P1V1 = P2V2

P2 = P1V1/V2

P2 = (45,174 Pa)(0.1 m^3)/(0.05 m^3)

P2 = 90,348 Pa

Now, we can calculate the work done during the compression process using the equation:

W = -PΔV

where ΔV is the change in volume (i.e. V2 - V1 = -0.05 m^3), and the negative sign indicates that work is done on the system during compression. Substituting the values, we get:

W = -(45,174 Pa)(-0.05 m^3)

W = 2,259 J

Finally, we can calculate the heat added to the system using the first law of thermodynamics:

ΔU = Q - W

where ΔU is the change in internal energy (which is zero since the temperature is constant), Q is the heat added to the system, and W is the work done on the system (which is negative). Solving for Q, we get:

Q = ΔU + W

Q = 0 J + 2,259 J

Q = 2,259 J

Since the temperature is constant, the heat added to the system is equal to the change in enthalpy:

ΔH = Q = 2,259 J

We can also calculate the change in entropy using the equation:

ΔS = nCv ln(T2/T1)

where Cv is the molar heat capacity at constant volume (which is given as 22.1 J/K.mol), and ln(T2/T1) is the natural logarithm of the ratio of final and initial temperatures. Since the temperature is constant, ΔS = 0.

Therefore, the final answers are:

P1 = 45,174 Pa

P2 = 90,348 Pa

W = 2,259 J

Q = 2,259 J

ΔS = 0

What happens to the temperature of a substance while it is changing state?
A. It decreases first and then remains constant.
B. It increases first and then decreases.
C. It remains constant.
D. It varies randomly.

Answers

The temperature remains constant while the substance is changing state.The correct answer is option C.

When a substance undergoes a change of state, such as melting, boiling, or condensing, the temperature of the substance remains constant during the phase transition. The process of changing state requires the absorption or release of heat energy without a change in temperature.

For example, when a solid is heated, its temperature increases until it reaches the melting point. At this point, the substance starts to change from a solid to a liquid, but the temperature remains constant until all the solid has melted.
The absorbed heat energy is used to break the intermolecular forces holding the particles together, rather than increasing the kinetic energy of the particles.

Similarly, during the process of condensation or freezing, a substance releases heat energy as it changes state. This released energy is used to form intermolecular forces and convert the substance from a gas to a liquid or a liquid to a solid. The temperature remains constant until the phase transition is complete.
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in a simple machine the input work is 187.5 N and output work is 125N. If load distance is 25 cm and effort distance is 75 cm calculate value of load and effort ​

Answers

Answer:

1. Laod = 500 N

2. Effort = 250 N

Explanation:

From the question given above, the following data were obtained:

Input work = 187.5 J

Output work = 125 J

Load distance = 25 cm

Effort distance = 75 cm

1. Determination of the load.

Output work = 125 J

Load distance = 25 cm = 25/100 = 0.25 m

Load =?

Output work = Load × Load distance

125 = Load × 0.25

Divide both side by 0.25

Load = 125 / 0.25

Laod = 500 N

2. Determination of the effort.

Input work = 187.5 J

Effort distance = 75 cm = 75/100 = 0.75 m

Effort =?

Input work = Effort × Effort distance

187.5 = Effort × 0.75

Divide both side by 0.75

Effort = 187.5 / 0.75

Effort = 250 N

base your answer to the following question on the cross section below, which shows the type of seismic waves recorded at various locations after an earthquake has occurred. point a is a location on earth's surface and x is the epicenter of the earthquake. syvum

Answers

The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer.

Seismic waves, which are vibrations caused by the movement of the Earth's crust, are recorded at various locations after an earthquake has occurred. The type of seismic waves recorded at a particular location depends on its distance from the epicenter (point X) of the earthquake.

There are two main types of seismic waves: body waves and surface waves. Body waves, such as P-waves and S-waves, travel through the Earth's interior and can be recorded at any location. Surface waves, such as Love waves and Rayleigh waves, travel along the Earth's surface and are typically recorded closer to the epicenter.

The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer. The S-waves are the secondary waves that are slower and arrive later than P-waves.

In general, the closer a location is to the epicenter, the stronger and more frequent the seismic waves will be.

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A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey​

Answers

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

What is the initial deceleration of the car?

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacement

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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