The specific heat of copper is 0. 385 j/g °c. How much thermal energy is required to increase the temperature of a 20g sample of copper from 20°c to 50°c?.

Human activities can increase landslide chances because it is responsible for clear-cutting, mining and quarrying, bad agricultural practices, and construction activities.

Yes, in some cases, human activities can give to causing landslides. Many human-caused landslides can be kept away from or mitigated. They are usually a result of building roads and structures without adequate grading of slopes, badly planned alteration of drainage patterns and disturbing old landslides.

In the study area, landslides seriously threaten the safety of people's lives and things and endanger transportation infrastructures. huge rainfall, an earthquake, or a combination of both commonly trigger a landslide.

So we can conclude that Some human activities, especially road construction, farmland allowance for building construction, and agricultural reclamation.

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The final speed of the go-cart in this inelastic collision is 70 m/s. The result is obtained by using the concept of inelastic collision.

The inelastic collision of two objects occur when some of the kinetic energy is lost, converted to other forms. It means that the law of conservation of kinetic energy doesn't apply.

In this case, both objects will stick together and move together with the same speed. The law of conservation of momentum applies.

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

Where

The 4-wheeler collides with the go-cart in inelastic collision.

Find the final speed of the go-cart!

Note that this is an inelastic collision. In this case, the 4-wheeler and go-cart will stick together and move with the same speed.

The formula for conservation of momentum will be

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

m₁v₁ + m₂v₂ = (m₁ + m₂)v'

It means that

v₁' = v₂' = v'

The final speed of the go-cart is the same with the final speed of the 4-wheeler.

v₂' = v₁' = 70 m/s

Hence, the go-cart will have the final speed of 70 m/s.

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The normal force is less than the 10 N

Since we are given a box weight that is  10 N  tilted at 45⁰, so the formula we refer  from the figure to for calculating the normal force is:

N=mg⋅cos θ , where mg is the weight of the  box and θ is the angle at which the box is shifted.

The flatter the incline to be,  the normal force becomes greater. The littler an angle gets to be making the greater the esteem of cosine gets to be, and along these lines the greater the normal force becomes.

So, we get that the normal force will be

= 10 cos 45 (Since the value of mg  is 10 N and θ = 45⁰)

= 7.07 N

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Based on the given informations, the orbital period of the outer edges of the primordial disk was calculated to be approximately 1515 years.

Assuming that the mass of Neptune is 17 times that of the Earth and that the distance of Neptune from the Sun is about 30 astronomical units (AU), we can use Kepler's third law of planetary motion to solve for the period of the outer edges of the primordial disk.

Using the equation P² = (4π²/GM) x a³, where P is the period, G is the gravitational constant, M is the mass of the Sun, and a is the semi-major axis of the orbit, we can rearrange the equation to solve for P:

P = sqrt((4π²/GM) x a³)

Since the matter that made up the planetesimals was spread out evenly on the edges of the primordial disk, we can assume that the semi-major axis of their orbit was about 35.5 AU (the radius of the disk).

Plugging in the values, we get:

P = sqrt((4π²/6.6743 x 10⁻¹¹ x 1.9885 x 10³⁰) x (35.5 x 1.496 x 10¹¹)³)

P = 1515 years (approx.)

Therefore, the orbital period of the outer edges of the primordial disk was approximately 1515 years.

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Answer:

5.76 N/m

Explanation:

From the question,

F = BILsinФ...................... Equation 1

and then,

F/L = BIsinФ.................. Equation 2

Where F/L = force per meter, I = current, B = magnetic field, Ф = angle.

Given: B = 0.9 T, I = 6.4 A, and Ф = 90° (Perpendicular)

Subtitute these values into equation 2

F/L = 0.9(6.4)(sin90°)

F/L = 5.76 N/m

The force per meter of length on a straight wire will be 5.76 N/m.

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. the magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem si;

B is the megnetic field=0.9 T

I is the current = 6.4 A,

Ф is the angle = 90° (Perpendicular)

The megnetic field is found as;

\(\rm F= BILsin \phi \\\\ \frac{F}{L} =BIsin\phi \\\\ \frac{F}{L} =0.9 \times 6.4 \times sin 90^0\\\\ \frac{F}{L} =5.76 / N/m\)

Hence the force per meter of length on a straight wire will be  5.76 N/m.

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A parallel plate capacitor has a surface charge density of 88.5 C/m2 on each of its plates.

The Surface Charge Density is defined as: =qA, where q is the charge and A is the surface area. It is quantified in electromagnetism as the amount of electric charge per unit volume of a one-, two-, or even three-dimensional space.

Surface charge density is represented by the Greek letter sigma (). Coulombs per square meter (Cm-2) is the standard unit of measurement, and the dimensional formula is [M0L-2T1I1].

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While a car travels around a circular track at a constant speed, its speed is changing with direction.

The acceleration of an object is the rate of change of velocity of the object with time.

The acceleration of an object moving in a circular track is known as centripetal acceleration.

a = v²/r

where;

The speed of an object is a scalar quantity without direction, but when it occurs in a circular track, the speed occurs in different direction, so acceleration for constant speed in a circular track cannot be zero.

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Answer:

Velocity

Explanation:

hope this helps

Answer:

Speed in a given direction is called velocity.

Explanation:

Answer:

Zacharias Janssen

Explanation:

Answer:

Zacharias Janssen;

Explanation:

Zacharias Janssen; also Zacharias Jansen or Sacharias Jansen; 1585 – pre-1632 was a Dutch spectacle-maker who lived most of his life in Middelburg. He is associated with the invention of the first optical telescope and/or the first truly compound microscope, but these claims may be fabrications put forward by his son

hope this helps

Answer:

Option 2

Explanation:

Since they want to know kinetic energy being increased, it cannot be Options 1 or 3. So now we're left with 2 and 4. 4 seems to be decreasing, so we can eliminate that. So, our answer is Option 2.

To find the magnitude of the electric field at a distance from the center of an atomic nucleus with a charge of 40e, we need to use Coulomb's law and the formula for the electric field.

Coulomb's law states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this is expressed as F = k(q1q2)/r^2, where F is the force, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the charges, and r is the distance between them.

The electric field is defined as the force per unit charge, so we can rearrange Coulomb's law to get E = F/q2 = k(q1/r^2).

Substituting the values given in the question, we get E = (9 x 10^9 Nm^2/C^2)(40e)/(r^2). We need to convert the charge to Coulombs since the value of e is the charge of an electron, not a proton or a nucleus. 1 e = 1.6 x 10^-19 C, so 40e = 40(1.6 x 10^-19) C = 6.4 x 10^-18 C.

Thus, the magnitude of the electric field at a distance r from the center of the nucleus is given by E = (9 x 10^9 Nm^2/C^2)(6.4 x 10^-18 C)/(r^2). The answer will depend on the value of r, which is not given in the question. However, we can see that the electric field will decrease rapidly with increasing distance since it is proportional to 1/r^2.

To calculate the magnitude of the electric field at a distance "r" from the center of an atomic nucleus with a charge of 40e, we can use the formula:

E = k * Q / r²

Here, E is the electric field, k is Coulomb's constant (8.99 × 10⁹ N·m²/C²), Q is the charge of the nucleus, and r is the distance from the center of the nucleus.

Given the charge of the nucleus is 40e, we can substitute the elementary charge value (1.6 × 10⁻¹⁹ C) for "e":

Q = 40 * (1.6 × 10⁻¹⁹ C) = 6.4 × 10⁻¹⁸ C

Now, substitute the known values into the formula:

E = (8.99 × 10⁹ N·m²/C²) * (6.4 × 10⁻¹⁸ C) / r²

E = 57.53 × 10⁻⁹ N·m²/C / r²

To find the magnitude of the electric field at a specific distance "r", just substitute the value of "r" into the equation and solve for E.

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The width of the central maximum is approximately 11.44 cm.

None of the given options match the calculated value exactly, but the closest option is A. 0.34 cm.

Diffraction is a fundamental phenomenon in physics that occurs when waves encounter obstacles or pass through narrow openings. It refers to the bending, spreading, and interference of waves as they interact with objects or apertures.

To find the width of the central maximum in a single-slit diffraction pattern, we can use the formula:

\(w = ({\lambda * D) / a\)

Where:

w is the width of the central maximum,

λ is the wavelength of light,

D is the distance between the slit and the screen, and

a is the width of the slit.

Given:

\(\lambda = 610 nm = 610 * 10^{(-9) m\) (converting from nanometers to meters)

\(D = 1.5 m\\a = 0.20 mm = 0.20 * 10^(-3) m\)(converting from millimeters to meters)

Substituting the values into the formula, we get:

\(w = (610 * 10^(-9) m * 1.5 m) / (0.20 * 10^(-3) m)\\w = 457.5 * 10^(-9) m / 0.20 * 10^(-3) m\\w = 457.5 * 10^(-9) m / 2 * 10^(-4) m\\w = 457.5 * 10^(-9) / 2 * 10^(-4) m\\w = 2.2875 * 10^(-5) / 2 * 10^(-4) m\\w = 0.114375 m\)

Converting the width to centimeters:

\(w = 0.114375 m * 100 cm/m\\w = 11.4375 cm\)

Therefore, the width of the central maximum is approximately 11.44 cm.

None of the given options match the calculated value exactly, but the closest option is A. 0.34 cm.

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Answer:

7.99 or 8 depends where you round.

Explanation:

Distance divided by time so 1246/156=7.98717948718

The Q need to be to make the magnitude of the electric field 0.00264 meters away from the surface equal to 1.43 nC is 1.07 × 10⁻⁹ C.

The  magnitude of the electric field at the point near the charged surface is as :

E = Q / (4 × π × ε × A)

Q = E ( 4 × π × ε × A)

Where

E = 1.43 nC

ε = 8.85 x 10⁻¹² C²/N m²

A = 6.77 m²

Q = E ( 4 × π × ε × A)

Q  = 1.43 × 4 × 3.14 × 8.85 x 10⁻¹² × 6.77

Q = 1.07 × 10⁻⁹ C

Thus, the charge is  1.07 × 10⁻⁹ C.

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Remember the formula

\(\\ \rm\Rrightarrow A(t)=A_o(0.5)^{\frac{t}{h}}\)

\(\\ \rm\Rrightarrow A(7.82\times 10)=A(78.2)\)

\(\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{\frac{78.2}{3.91\times 10^{5}}}\)

\(\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{20\times 10^{-5}}\)

\(\\ \rm\Rrightarrow 4.11\times 10^{76}(0.5)^{0.0002}\)

\(\\ \rm\Rrightarrow 4.11\times 10^{76}(0.998)\)

\(\\ \rm\Rrightarrow 4.10178\times 10^{76}\)

Why no options matched?

That time given in end i.e 7.82×10

The number of nuclei  of calcium-47 left after 7.82 x 10⁵s is 1.03 x 10¹⁶.

This can be found out using half life and laws of radioactive disintegration.

The Law of radioactive disintegration states  the number of  radioactive decay per unit time is proportional to the number of nuclei present in the sample initially.

So,  ΔN/Δt = λN

Where, ΔN = number of radioactive nuclei decayed

Δt = time taken for decay

N = No of nuclei present initially

λ= decay constant

Half life is the time taken for the radioactive nuclei to reach half of its initial value.

Half life is given by

 \(t_{1/2}\) =  λ/t

Given here,  \(t_{1/2}\) =  3/91 x 10.⁵s

N = 4.11 x 10¹⁶.

t = 7.82 x 10.⁵s

We see  here that  t = 2(\(t_{1/2}\))

Now, number of radioactive nuclei left undecayed in  one half life is N/2

So number of nuclei left undecayed in 2 half lives will be 1/2(N/2) = N/4

So number of nuclei left in the sample will be N/4 = (4.11 x 10¹⁶.)/4

So Number of nuclei left in the sample = 1.03 x 10¹⁶.

Hence 1.03 x 10¹⁶is the correct answer.

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Answer:If you mean how much heat it can transfer as a thermal mass - in order to move heat from one place to another:

Typically the relationships are given by specific heat capacity (at different temperatures) and latent heats, plus the end-point temperatures to determine which of these conversion factors are relevant.

If time comes into it, you are looking at including shape and thermal conductivity at the minimum, so you really would need to be more specific

Explanation:

The situation in which a person would lose heat by conduction is a. Sitting on cold metal bleachers at a football game. Conduction occurs when heat is transferred through direct contact with a cooler object, in this case, the cold metal bleachers.

In situation a, sitting on cold metal bleachers at a football game, a person would lose heat by conduction. Conduction is the transfer of heat through direct contact between objects, so sitting on a cold metal surface would transfer heat from the body to the bleachers. In situation b, wearing wet clothing in windy weather, a person would lose heat by both conduction and convection. Convection is the transfer of heat through movement of air or fluid, so the wind would increase the rate of heat loss. In situation c, breathing, heat loss would occur through respiration, which is a form of evaporation. In situation d, going outside without a coat during a cold but calm day, a person would lose heat primarily through radiation and convection, but not as much through conduction.

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Answer:

D. circumpolar

Explanation:

A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.

-Wikipedia

Answer:

i dont undertsnad what do u ned hep wit?

Explanation:

The angle at which the red light has the first-order bright band is 0.053 degrees.

The diffraction angle for red light with a wavelength of 634.3 nm can be found using the formula:

\(\theta = sin^-1 (n\lambda/L)\),

where n is the order of diffraction (1 for first-order), λ is the wavelength, and L is the number of lines per centimeter.

Therefore,

n = 1

λ = 634.3 nm = 634.3 * 10^(-9) m

L = 12300 lines/cm = 12300 * 10^(-2) lines/m

Plugging in the values, we get:

\(\theta = sin^-1 (1 * 634.3 * 10^{-9} / (12300 * 10^{-2} ))\)

Converting the result from radians to degrees gives us approximately 0.053 degrees.

This is the angle at which the first-order bright band for red light will occur in the spectrometer using a grating with 12300 lines/cm.

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Given:

The mass on the table is,

The hanging mass is,

THe coefficient of friction is,

let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.

we can write,

Adding these equations we get,

Substituting the values we get,

Hence the acceleration is 6.66 m/s^2.

Answer:

50 kmph

Explanation:

300 / 6 = 50

Answer:

They are known as isotopes

Answer:

i don`t get it

Explanation:

The gain in momentum of vehicle B is 4000 kg•m/s

The total change in momentum due to the collision is zero.

According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

As no external force applied, total momentum during collision remains conserved.

Hence, the gain in momentum of vehicle B = the loss  in momentum of vehicle C

=  4000 kg•m/s

And,  the total change in momentum due to the collision is zero.

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When the momentum of an object is increased by a factor of 4 in magnitude, the kinetic energy of the object is changed by a factor of 16. Here option A is the correct answer.

The kinetic energy of an object is given by the equation KE = (1/2)mv², where m represents the mass of the object and v represents its velocity.

The momentum of an object is defined as p = mv, where p represents the momentum, m is the mass, and v is the velocity.

If the momentum of an object is increased by a factor of 4 in magnitude, it means the new momentum is 4 times larger than the original momentum. Mathematically, we can write this as p' = 4p, where p' is the new momentum and p is the original momentum.

Since p = mv, we can substitute this into the equation above to obtain p' = 4mv.

Now, let's consider the kinetic energy. The original kinetic energy is KE = (1/2)mv², and the new kinetic energy is KE' = (1/2)m(v')², where v' is the new velocity.

We know that p' = 4mv, so we can rewrite it as 4mv = m(v').

Dividing both sides of the equation by m, we get 4v = v'.

Now, substituting this into the equation for kinetic energy, we have KE' = (1/2)m(4v)².

Simplifying the equation, we have KE' = (1/2)m(16v²).

Notice that v² appears in both the original and new kinetic energy equations. Since the mass (m) is the same for both cases, we can cancel it out.

Therefore, the ratio of the new kinetic energy to the original kinetic energy is (1/2)(16v²)/(1/2)(v²) = 16.

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Complete question:

The momentum of an object is increased by a factor of 4 in magnitude. By what factor is its kinetic energy changed?(a) 16 (b) 8 (c) 4 (d) 2(e) 1

Given that a constant force F=⟨2,8⟩ moves an object along a straight line from the point (2,5) to the point (12,10), the work done is 1.54 ft-lb.

We are to find the work done if the distance is measured in feet and the force is measured in pounds. Let d be the distance from (2, 5) to (12, 10).The distance can be calculated as d = √( (x2 - x1)² + (y2 - y1)²)

d = √( (12 - 2)² + (10 - 5)²)

d = √( 10² + 5²)d = √( 100 + 25)

d = √125

d = 11.18 ft

The force can be expressed in magnitude form as |F| = √(F₁² + F₂²)|F| = √(2² + 8²)|F| = √(4 + 64)|F| = √68|F| = 8.246 lb

The work done, W is given by W = F·d·cosθ where F is the force, d is the distance moved and θ is the angle between F and d W = F·d·cosθW = ⟨2, 8⟩ · 11.18 · cos(θ)W = (2)(11.18) + (8)(11.18) · cos(θ)W = 22.36 + 89.44 · cos(θ)

When using the given force vector, we find the angle between the force vector and the direction of motion of the object as: tan(θ) = F₂ / F₁tan(θ) = 8 / 2tan(θ) = 4θ = 76.04°Thus,W = 22.36 + 89.44 · cos(76.04)W = 1.54 ft-lb

Therefore, the work done is 1.54 ft-lb.

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Answer:

1. Privacy

-The state or condition of being free from being observed or disturbed by other people.

2. Commitment

-The state or quality of being dedicated to a cause, activity, etc.

3. Profile

-There are multiple answers for this word so I'm not sure which is the one you need.

4. Widow

-A woman who has lost her spouse by death and has not remarried.

5. Aristocrat

-A member of the aristocracy.

6. Affordable

-Inexpensive; reasonably priced.

7. Variable

-A symbol for a value we don't know yet. It is usually a letter like x or y.

Explanation:

Answer:

First fall Resistor mean passive two terminal electrical components that implements electrical resistance as a circuit an then is function are used to reduce current flow , adjust single level to divide voltage ,terminate transmission.