The scale on a map js 1cm : 6.6 km the distance between two cities on the map is 18cm what is the actual distance between the two cities

Answer:

488

Step-by-step explanation:

You divide 28453 by 58.3053278689 and get 488.

Answer: 1:2

Step-by-step explanation:

24 ÷ 12 = 2

12 ÷ 12 = 1

Answer to the question is 1:2

Answer:

see the anaiysis for details it can be seen in the title

Step-by-step explanation:

9(x) 2x-5 =2 fix)-5

91x =2fix) -5

Answer:

I want to say 5 lines are parallel to line FM.

Step-by-step explanation:

I can see that lines (or edges) AG, BH, CJ, DK, and EL are parallel to the edge FM. They don't intersect with each other and are all going straight up and down. A line (edge) that will never touch edge FM would be edge HJ. HJ is going straight left to right while FM is going straight up and down. These two edges are not parallel.

Answer:

B you need to divide the volume by the depth.

The arrow is at a height of 48 ft after approx. 3 - √6 s and after 3 + √6 s.

To find the time it takes for the arrow to reach a height of 48 ft, we can use the formula for the height of the arrow:

s = v0t - 16t^2

Here, s represents the height of the arrow, v0 is the initial velocity, and t is the time.

Given that the initial velocity, v0, is 96 ft/s and the height, s, is 48 ft, we can set up the equation:

48 = 96t - 16t^2

Now, let's solve this equation to find the time it takes for the arrow to reach a height of 48 ft.

Rearranging the equation:

16t^2 - 96t + 48 = 0

Dividing the equation by 16 to simplify:

t^2 - 6*t + 3 = 0

We now have a quadratic equation in the form of at^2 + bt + c = 0, where a = 1, b = -6, and c = 3.

Using the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values:

t = (6 ± √((-6)^2 - 413)) / (2*1)

t = (6 ± √(36 - 12)) / 2

t = (6 ± √24) / 2

Simplifying the square root:

t = (6 ± 2√6) / 2

t = 3 ± √6

Therefore, the arrow reaches a height of 48 ft after approximately 3 + √6 seconds and 3 - √6 seconds.

In summary, the arrow takes approximately 3 + √6 seconds and 3 - √6 seconds to reach a height of 48 ft, assuming an initial velocity of 96 ft/s.

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Note the complete question is

The height of an arrow shot upward can be given by the formula s = v0*t - 16*t², where v0 is the initial velocity and t is time.How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s?  

Solve (t-3)^2=6

The arrow is at a height of 48 ft after approx. ___ s and after ___ s.

Answer:

  x = 9 inches

Step-by-step explanation:

You want the value of x in the similar triangles shown.

Corresponding sides are proportional. This means the ratio of the horizontal side of the triangle to the vertical side is the same for both.

  6/4 = (6+x)/10

  15 = 6 +x . . . . . . . . multiply by 10

  9 = x . . . . . . . . . subtract 6

The measure of x is 9 inches.

__

Additional comment

You could also write the proportion ...

  6/4 = x/(10 -4)

  x = 36/4 = 9 . . . . . . . multiply by 6

You can see this if you draw a horizontal line through the figure at the top of the side marked 4 in.

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The measure of the arc of the sinkhole that falls within the restaurants property is -21°

Let x be the angle at the dollar store at the intersection

Now the angle of the grocery store at the intersection, y is 2/3 that of the dollar store. So, y = 2x/3

Since both x and y are supplementary,

x + y = 180°

x + 2x/3 = 180°

5x/3 = 180°

x = 180° × 3/5

x = 36° × 3

x = 108°

The gas station has the same angle at the intersection but has 88° more of the sinkhole edge to stabilize. So, the angle the gas station store subtends at the sinkhole is z = x + 88°

Also, since the grocery stores property has 2/3 of the angle in the intersection at the dollar store has, but has 5° more of the sinkhole edge to stabilize. The angle the grocery store subtends at the sinkhole is k = y + 5° = 2x/3 + 5°

Let k' be the angle subtended by the restuarant at the sinkhole.

Since the sinkhole is a circle, we have that

x + z + k + k' = 360°

x + x + 88° + 2x/3 + 5° + k' = 360°

8x/3 + 93° + k' = 360°

8x/3 + k' = 360° - 93°

8x/3 + k' = 267°

So, making k' subject of the formula, we have

k' = 267° - 8x/3

Substituting the values of the variables into the equation, we have

k' = 267° -  8 × 108°/3

k' = 267° - 288°

k' = -21°

So, the measure of the arc of the sinkhole that falls within the restaurants property is -21°

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The correct options are:

\(8(x^2 + 2x) = -3\\\\8(x^2 + 2x + 1) = -3 + 8\)

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).

Now, We have the quadratic equation is:

\(8x^2 + 16x + 3 = 0\)

We separate variables from constants

\(8x^2+16x = -3\)

Taking the common factor  8

\(8(x^2+2x)=-3\)

Completing squares in the brackets and balancing the equation in the right side

\(8(x^2+2x+1)=-3+8\)

Factoring the perfect square

\(8(x+1)^2=5\)

\((x+1)^2=\frac{5}{8}\)

\((x+1)=\) ± \(\sqrt{\frac{5}{8} }\)

x = -1 ± \(\sqrt{\frac{5}{8} }\)

The correct options are:

\(8(x^2 + 2x) = -3\\\\8(x^2 + 2x + 1) = -3 + 8\)

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

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The given question is incomplete, complete question is:

Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options.

8(x2 + 2x + 1) = –3 + 8

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

x = –1 Plus or minus StartRoot StartFraction 4 Over 8 EndFraction EndRoot

8(x2 + 2x + 1) = 3 + 1

8(x2 + 2x) = –3

Answer:

101.25

Step-by-step explanation:

75.00 x 35% = 26.25

26.25 + 75.00 = 101.25

Answer:

y=-3x+1

Step-by-step explanation:

Have a good one.

Answer:

Step-by-step explanation:

The line segment joining two points P and Q can be represented by the equation of a straight line in the form y = mx + b, where m is the slope and b is the y-intercept.

To find the equation of the line, we need to find the slope, which can be calculated using the formula:

m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the points P and Q, respectively.

In this case, the coordinates are:

P = (-3, 2) and Q = (5, 7)

So, the slope is:

m = (7 - 2) / (5 - (-3)) = 5 / 8

Next, we can use either of the points to find the y-intercept. Let's use point P:

b = y - mx, where y and x are the y and x coordinate of the point, respectively.

In this case,

b = 2 - m * (-3) = 2 - (5/8) * (-3) = 2 + 15/8 = 89/8

So, the equation of the line joining the points P and Q is:

y = (5/8)x + 89/8

Now, to find the point where the line crosses the y-axis, we need to find the x-coordinate of the point where y = 0.

So, we have:

0 = (5/8)x + 89/8

Solving for x, we get:

x = -(89/8) / (5/8) = -89 / 5

This means that the line crosses the y-axis at the point (-89/5, 0). To find the ratio in which the line segment is divided by the y-axis, we need to find the ratio of the distance from the y-axis to point P to the distance from the y-axis to point Q.

Let's call the point of intersection with the y-axis R. The distances are then:

PR = (3, 2) and QR = (5 - (-89/5), 7)

The ratio of the distances is then:

PR / QR = (3, 2) / (5 - (-89/5), 7) = 3 / (5 + 89/5) = 3 / (94/5) = 15/47

So, the line segment joining the points P and Q is divided by the y-axis in the ratio 15:47.

Answer:

Problem 1)

\(m\angle DEG = 38^\circ\)

Problem 2)

\(m\angle x =140^\circ \text{ and } m\angle y = 49^\circ\)

Problem 3)

\(m\angle EDG = 65^\circ\)

Step-by-step explanation:

Problem 1: ∠DEG

From the diagram, we know that ∠DFG intercepts Arc DG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\(\displaystyle \frac{1}{2}m\stackrel{\frown}{DG}=m\angle DFG\)

We know that m∠DFG = 38°. So:

\(\displaystyle \frac{1}{2}m\stackrel{\frown}{DG}=38\Rightarrow m\stackrel{\frown}{DG}=76^\circ\)

∠DEG also intercepts Arc DG. Hence:

\(\displaystyle m\angle DEG=\frac{1}{2}m\stackrel{\frown}{DG}\)

We know that Arc DG measures 76°. Hence:

\(\displaystyle m\angle DEG =\frac{1}{2}\left(76\right)=38^\circ\)

Alternate Explanation:

Since ∠DEG and ∠DFG intercept the same arc, ∠DEG ≅ DFG. So, m∠DEG = m∠DFG = 38°.

Problem 2: Circle with Centre O

(Let the bottom left corner be A, upper be B, and right be C.)

∠ACB intercepts Arc AC.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\(\displaystyle \frac{1}{2}m\stackrel{\frown}{AC}=m \angle ACB\)

Since m∠ACB = 70°:

\(\displaystyle \frac{1}{2}m\stackrel{\frown}{AC}=70\Rightarrow m\stackrel{\frown}{AC}=140^\circ\)

∠x is a central angle and also intercepts Arc AC.

The measure of a central angle is equal to its intercepted arc. Thus:

\(\displaystyle m\angle x =m\stackrel{\frown}{AC}=140^\circ\)

The sum of the interior angles of a polygon is given by the formula:

\((n-2)\cdot 180^\circ\)

Where n is the number of sides.

Since the inscribed figure is a four-sided polygon, its interior angles must total:

\((4-2)\cdot 180^\circ =360^\circ\)

Therefore:

\(21+70+y+(360-x)=360\)

Substitute and solve for y:

\(91+y+(360-140)=360\Rightarrow y +311=360\Rightarrow m\angle y = 49^\circ\)

Problem 3: ∠EDG

∠EFG intercepts Arc EDG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\(\displaystyle \frac{1}{2}m\stackrel{\frown}{EDG}=m\angle EFG\)

Since m∠EFG = 115°:

\(\displaystyle \frac{1}{2}m\stackrel{\frown}{EDG} = 115\Rightarrow m\stackrel{\frown}{EDG} = 230^\circ\)

A full circle measures 360°. Hence:

\(m\stackrel{\frown}{EDG}+m\stackrel{\frown}{EFG}=360^\circ\)

Since we know that Arc EDG measures 230°:

\(230^\circ + m\stackrel{\frown}{EFG}=360\)

Solve for Arc EFG:

\(m\stackrel{\frown}{EFG}=130^\circ\)

∠EDG intercepts Arc EFG.

Inscribed angles have half the measure of its intercepted arc. Therefore:

\(\displaystyle m\angle EDG = \frac{1}{2}m\stackrel{\frown}{EFG}\)

Since we know that Arc EFG measures 130°:

\(\displaystyle m\angle EDG = \frac{1}{2}(130)=65^\circ\)

Answer:

question 1:

38 degrees (explanation down below)

question 2:

y = 49 degrees!

question 3:

angle EDG = 65

Step-by-step explanation:

question 1: i'd say DFG is the same as DEG because the arc is the same angle, so angle DEG is 38 degrees because it is half of 76 degrees or the arc angle

question 2 isn't any harder: the arc angle for 70 is 140 degrees, so 140 degrees is equal to x. so angle O would be 220 degrees and because the triangle became a square, 360-220-70-21 equals y!

question 3: arc angles teaches you something that will make your question SO easy, arc angle GE is equal to 230 degrees because of 115 degrees doubled, so 360/230 equals 130 which divided by 2 equals 65

The simplified solution of the expression 5x²+6x+4+x²+x is 6x²+7x+4.

The given expression is 5x²+6x+4+x²+x

Simplifying the given expression

5x²+6x+4+x²+x

Firstly, put the similar terms together

5x²+x²+6x+x+4

Adding the similar terms

6x²+7x+4

∵ The expression cannot be solved further, 6x²+7x+4 is the final solution.

Therefore, the simplified solution of the expression 5x²+6x+4+x²+x is 6x²+7x+4.

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Answer:

1= A

2= C

Step-by-step explanation:

I think this is right I'm not sure but I think it is.

hope this helps :)

1. If he chooses to make interest-only payments until the monthly loan payments are due, Jim will make interest-only payments for 1 year and 6 months or 1¹/₂ years.

2. The total amount of Jim's interest-only payments is $978.12.

3. If Jim begins the loan repayment with no interest capitalization, the total interest he has to pay on the student loan after the grace period is $6,520.80.

The grace period is a period of six months after graduation from college when a student may not start repaying their student loan.

The purpose of the grace period is to enable the graduate to be gainfully employed and earn income.

Unsubsidized student's loan = $15,200

Interest rate = 4.29%

Loan period = 10 years

Length of interest-only payments = Senior Year + 6 months Grace Period

= 1 + ¹/₂

= 1¹/₂ years 0r 18 months

Interest-only amount during the 1¹/₂ years = $978.12 ($15,200 x 4.29% x 1.5)

Interest payments after the grace period = $6,520.80 ($15,200 x 4.29% x 10)

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The maximum height reached by the ball is 908.5 feet.

Using the given values, we can substitute v0 = 152 and h0 = 6 into the equation:

\(h(t) = -16t^2 + 152t + 6\)

This quadratic function models the height of the ball at any time t after it is thrown.

To find the maximum height of the ball, we need to find the vertex of the parabolic curve described by the quadratic function. The vertex can be found using the formula:

t = -b / 2a

where a = -16 and b = 152 are the coefficients of the quadratic function.

t = -152 / 2(-16) = 4.75

So the maximum height is reached after 4.75 seconds. To find the maximum height, we can substitute this value back into the equation:

\(h(4.75) = -16(4.75)^2 + 152(4.75) + 6 = 908.5\)feet

Therefore, the maximum height reached by the ball is 908.5 feet.

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Question

A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 152 feet per second. Write a quadratic function to model the vertical motion of the ball, given that the height of the ball at time t is given by: h(t) = -16t^2 + v0t + h0

Answer: 2252.25 - 1018.50 = P58.75

Step-by-step explanation:

Answer:

I'm not too sure but:

L = (-2,-3)

M = (-9,-3)

K = (-2,-8)

J = (-9,-8)

Step-by-step explanation:

What we know:

We know that we go through the x axis then the y axis hence the saying "Along the corridor, Up the stairs".

Due to us knowing this we use where the letters (L, M, K & J) are placed on the diagram and use the "Along the corridor, Up the stairs" technique to figure out the answer.

This means that L is (-2,-3), M is (-9,-3), K is (-2,-8) & J is (-9,-8).

Yet again as I said at the top i'm not too sure but this is what I think is correct.

I hope it helps! :)

Answer:

SOHCAHTOA.

We are to use SOH in this question because we have the opposite which is 15 and the hypotenuse which is 17.

which will be Sin theta =15/17.

Sin theta =0.8823~1.

then Sin theta =1.

which is theta = (inverse of sin) sin^-1(1).

theta =90°.

Answer:x = theta =90°.

Step-by-step explanation:

Answer:34.2

Step-by-step explanation: I just did it in delta math

Answer:

Conversely, if n is divisible by 5, then n is the sum of five consecutive integers. In particular, this gives n = 5m + 10 = 5(m + 2) and, since m + 2 is an integer, this shows n is divisible by 5

Answer:

To calculate Karl Pearson's coefficient of skewness, we need to use the formula:

Skewness = 3 * (Mean - Mode) / Standard Deviation

Given the Mean = 73.19, Mode = 79.56, and Variance = 16, we need to find the Standard Deviation first.

Standard Deviation = √Variance = √16 = 4

Now we can substitute the values into the formula:

Skewness = 3 * (73.19 - 79.56) / 4

Skewness = -6.37 / 4

Skewness = -1.5925

Rounded to four decimal places, the Karl Pearson's coefficient of skewness for the given values is approximately -1.5925.

\(\text{Find which car would be cheaper over 5 years of ownership }\\\\\text{Diesel car:}\\\\\text{ The buying price is 29515}\\\\\text{Then it cost 1200 to run per year}\\\\\text{Calculate:}\\\\1200\cdot5=6,000\\\\\text{Add:}\\\\29515+6,000=35,515\\\\\text{Petrol car:}\\\\\text{Buying price is 26775}\\\\\text{Running cost for 5 years is 8000}\\\\\text{Add:}\\\\26775+8000=34,775\\\\\boxed{\text{The Petrol car is the better value for the price}}\)

To determine how the surface area of a rectangular prism changes when all dimensions are quadrupled, we need to compare the original surface area to the new surface area.

The original surface area of the rectangular prism is given by:

SA_original = 2lw + 2lh + 2wh

where l, w, and h represent the length, width, and height of the prism, respectively.

In this case, the dimensions of the original box are:

Length (l) = 3 ft

Width (w) = 6 ft

Height (h) = 5 ft

Substituting these values into the formula, we have:

SA_original = 2(3)(6) + 2(3)(5) + 2(6)(5)

            = 36 + 30 + 60

            = 126 square feet

Now, if we quadruple all the dimensions of the box, the new dimensions would be:

Length (l_new) = 4(3) = 12 ft

Width (w_new) = 4(6) = 24 ft

Height (h_new) = 4(5) = 20 ft

The new surface area of the enlarged box is given by:

SA_new = 2(l_new)(w_new) + 2(l_new)(h_new) + 2(w_new)(h_new)

       = 2(12)(24) + 2(12)(20) + 2(24)(20)

       = 576 + 480 + 960

       = 2016 square feet

Comparing the original surface area (SA_original = 126 sq ft) to the new surface area (SA_new = 2016 sq ft), we can see that SA_new is 16 times greater than SA_original.

Therefore, the correct answer is:

1. The new surface area would be 16 times the original surface area.

Answer:

d=3

Step-by-step explanation:

multiply 2 to d and 2 then you'll have 2D + 4 = 10 then you subtract 4 to 10 you'll have six you divide 6 by 2 and then you'll have three which, d equals 3

Answer:

See attached

Step-by-step explanation:

The answers are in the picture below

Answer:

1) 11-y= -9

2)41+w= 26

3)r/6= 4

4)18×p= 54

5)v/-4= 13=>v= -54; yes

6)108= -36z=>z= 108/(-36)=>z= -3; yes

7)27=n-16=>n=27+16=>n=43;not a solution

8)84=78+t=>t= 84-78=>t= 6; not a solution

9)a/2=36------------B. What number divided by 2 equals 36?

10)2a=36------------C. 2 times what number equals 36?

11)2+a=36-----------D. 2 plus what number equals 36?

12)a-36=2-----------A. What number minus 36 equals 2?

We can say that the tree's height increased by 12.5% over the course of the six-week experiment.

To calculate the percent increase in the tree's height, we need to find the difference between its new height and its old height, and then express that difference as a percentage of the old height.

We start with the formula:

percent increase = (new value - old value) / old value * 100%

In this case, the old value is the height of the tree at the beginning of the experiment, which is 32 inches. The new value is the height of the tree six weeks later, which is 36 inches.

So, plugging in those values, we get:

percent increase = (36 - 32) / 32 * 100%

Simplifying this expression gives us:

percent increase = 4 / 32 * 100%

And when we evaluate that expression, we get:

percent increase = 12.5%

Therefore, the percent increase in the tree's height is 12.5%.

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Answer:

I would choose AT MOST 188 ROLLS but i can be wrong

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

The length of the semi-major axis of the ellipse is 7.

What is the semi-major axis of an ellipse?

The semi-major axis of an ellipse is the half of the longest diameter passing through its vertex and focus.

The general equation of an ellipse is :

⇒ x²/a²+y²/b²=1, where a is the semi-major axis and b, is the semi-minor axis

x²/49+y²/36=1

x²/(7²)+y²/(6²)=1

x²/a²+y²/b²=1

a=7

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