The radiation pressure exerted by the Sun on the Earth counteracts the gravitational attraction and puts the Earth into an orbit that is farther from the Sun than if there were no radiation pressure. It can be shown that the distance added to Earth's orbital radius is given by (Frad/Fg)r, where Frad is the radiation force exerted on Earth by the Sun, Fg is the gravitational force between the Earth and Sun, and r is the average orbital radius.
Part A Part complete If the intensity of sunlight that strikes Earth is 1260 W/m2, what is Frad, assuming the Earth is a perfect absorber? Express your answer to three significant figures and include appropriate units. 5.35×108 N Correct
Part B Assuming r=1.50×1011m, what is Fg? Express your answer to three significant figures and include appropriate units.
Part C What is the additional distance added to Earth's orbital radius by the radiation pressure? Express your answer to three significant figures and include appropriate units.

Answer:

the total flight time is 1.29 s

Explanation:

The computation of the total flight time is given below:

The initial velocity is 15 m/s = v

And, the angle from horizontal is \(\theta = 25\ degrees\)

Now the total time is

\(t = \frac{2\times v\times \sin \theta }{g} \\\\= \frac{2\times 15\times sin 25^{\circ}}{9.8} \\\\= 1.29 s\)

Hence, the total flight time is 1.29 s

It accelerates at about 32 feet per second every second, so it starts falling at zero feet per second and, one second later it is traveling at 32 feet per second. That means that its average speed is 16 feet per second, so it will fall 16 feet in the first second.

The sum of the kinetic and potential energies of a system of objects is conserved only when no external force acts on the objects.

The principle of conservation of mechanical energy states that the total mechanical energy of an isolated system (absence of external force) is always constant.

M.A = P.E + K.E

where;

P.E is potential energy

K.E is kinetic energy

Thus, the sum of the kinetic and potential energies of a system of objects is conserved only when no external force acts on the objects.

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,Paige does 182.9 J of work on the crate as it slides 3.3 m down the ramp.

To determine the work done by Paige on the crate as it slides down the ramp, we need to calculate the component of Paige's force that is parallel to the direction of motion of the crate. This component will do work on the crate by exerting a force in the same direction as the crate's displacement.

We can first calculate the weight of the crate, which is given by

W = mg

where m is the mass of the crate and g is the acceleration due to gravity. We can assume that the crate is on a frictionless surface, so the force of friction is zero. Therefore, the weight of the crate is the only force acting on it parallel to the ramp. Using the angle of the ramp, we can calculate the component of the weight that is parallel to the ramp:

F_parallel = mg sin θ

where θ is the angle of the ramp, which is 20∘. We can also calculate th

m = W/g

where g is the acceleration due to gravity, which is 9.81 m/s^2.

Substituting the values, we get:

m = (F_parallel/sin θ)/g

m = (mg sin θ/sin θ)/g

m = g

Therefore, the mass of the crate is equal to g.

Next, we can calculate the force applied by Paige, which is given by:

F_applied = 69 N

Since Paige is pushing back on the crate, her force is in the opposite direction of the crate's motion, so we need to calculate the negative of F_parallel. Therefore, the net force acting on the crate is:

F_net = F_applied - F_parallel

F_net = 69 N - g sin θ

Finally, we can calculate the work done by Paige on the crate using the formula:

W = F_net d

where d is the distance traveled by the crate, which is 3.3 m. Substituting the values, we get:

W = (69 N - g sin θ) x 3.3 m

Using the value for g and θ, we get:

W = (69 N - 9.81\(m/s^2\)x sin 20∘) x 3.3 m

W = 182.9 J

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To draw the circuit diagram with four 15 ohm resistors connected in a series to a 45-v battery, along with an ammeter and voltmeter, follow the steps below:Step 1: Place the batteryTo begin with, draw the 45 V battery at the top of the page, as shown in the figure below.  Step 2: Add resistorsNext, add the four 15 ohm resistors in a series circuit after the battery, as shown in the figure below.  

Step 3: Add the ammeterIn the circuit, an ammeter is placed in series with the resistors to calculate the total current in the circuit. Connect the ammeter between the last resistor and the negative terminal of the battery, as shown in the figure below.Step 4: Add the voltmeter. Finally, a voltmeter is placed in parallel with the resistors to determine the voltage across them.

Connect the voltmeter in parallel with each resistor, as shown in the figure below. [Figure]Hence, this is how the circuit diagram with four 15 ohm resistors connected in a series to a 45-v battery looks like, along with an ammeter and voltmeter.

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Answer:

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Answer:

The appropriate solution is "61.37 s".

Explanation:

The given values are:

Boat moves,

= 10 m/s

Water flowing,

= 1.50 m/s

Displacement,

d = 300 m

Now,

The boat is travelling,

= \(10+1.50\)

= \(11.5 \ m/s\)

Travelling such distance for 300 m will be:

⇒ \(v = \frac{d}{t} \ sot \ t\)

      \(=\frac{d}{v}\)

On putting the values, we get

      \(=\frac{300}{11.5}\)

      \(=26.08 \ s\)

Throughout the opposite direction, when the boat seems to be travelling then,

= \(10-1.50\)

= \(8.5 \ m/s\)

Travelling such distance for 300 m will be:

⇒ \(v=\frac{v}{t} \ sot \ t\)

      \(=\frac{d}{v}\)

On putting the values, we get

      \(=\frac{300}{8.5}\)

      \(=35.29 \ s\)

hence,

The time taken by the boat will be:

= \(26.08+35.29\)

= \(61.37 \ s\)

(c) The potential energy at A is the same as the kinetic energy at B. So

m g h = 1/2 m v²

where m is the mass of the object at the end of the pendulum, g is the magnitude of the acceleration due to gravity, h is the height of the object at point A relative to B, and v is the object's maximum speed. So

(3.8 kg) (9.80 m/s²) h = 140 J

h = (140 J) / ((3.8 kg) (9.80 m/s²))

h ≈ 3.8 m

(f) You know the kinetic energy at B, so just solve for v :

140 J = 1/2 (3.8 kg) v²

v² = (280 J) / (3.8 kg)

v² ≈ 73.684 m²/s²

v ≈ 8.6 m/s

Puck mass (m) and J (impulse), initial and ultimate velocities are the known and unknown quantities, respectively.

The integral of a force, F, over the time period over which it acts, t, is known as an impulse in classical mechanics and is denoted by the letters J or Imp. Since force is a vector quantity, impulse also belongs to this category. An object experiences an impulse, which results in an equivalent vector change in its linear momentum along with the subsequent direction. The kilogram meter per second (kg m/s) and newton second (N s), are dimensionally equal units of momentum and impulse, respectively. In the British Gravitational System, the unit is the slug-foot per second (slugft/s), but the equivalent English engineering measure is the pound-second (lbfs). As long as it is acting, a resulting force accelerates the body and alters its velocity.

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The quantities that were held constant in this experiment are:the mass of water,The mass of the iron sample
and the initial temperature of water

The independent variables that were manipulated in this experiment are:
1. The initial temperature of the iron

The dependent variables in this experiment, which were measured but not directly manipulated, are:
1. The final temperature of the mixture of water and iron

A dependent variable is a variable whose value depends on another variable, whereas An Independent variable is a variable whose value never depends on another variable.

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Answer:

11900 meters

Explanation:

Use the Potential energy = mgh formula, substituting these in to get 11.1x10^6 = 95 x 9.81 x h.

Rearrange to make h the subject and the answer given is 11900 (3sig.fig.)

The maximum height to which he can climb will be 1.168 x 10⁴ meters.

The potential energy of a body is the energy of the body due it position. The potential energy always exist for two bodies which are in mutual interaction with each other for example by a force. For body a on earth, the potential energy of the body - earth system is -

E[P] = mgh

Given is a mountain climber that has a mass of 95 kg.

We can write -

Mass of climber = [M] = 95 kg

Energy gained by eating the chocolate = [E] = 11.1 MJ = 1.11 x 10⁷ joules

Assume that the height achieved achieve by the climber is [h] meters

Therefore, the potential energy gained at that height will be equal to 11 MJ

Therefore -

mgh = 1.11 x 10⁷

95 x 10 x h = 1.11 x 10⁷

95 x 10 x h = 1110 x 10⁴

h = (1110 x 10⁴)/950

h = 1.168 x 10⁴ meters

Therefore, the maximum height to which he can climb will be 1.168 x 10⁴ meters.

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Answer:

1.08 x 10⁷N

Explanation:

Given parameters:

Mass of freight train  = 270700kg

Acceleration = 40m/s²

Unknown:

Force acting on the train = ?

Solution:

From Newton's second law of motion, we know that:

       Force  = mass x acceleration

So;

        Force  = 270700 x 40   = 1.08 x 10⁷N

An accelerating universe is currently the most accepted in light of the discovery of dark energy.

A hypothesized energy known as "dark energy" acts in opposition to gravity by exerting a repellent, negative pressure. It has been proposed to explain the observable characteristics of far-off type Ia supernovae, which reveal the universe is expanding at a faster rate than usual.

Saul Perlmutter, Brian Schmidt, and Adam Riess are the recipients of the 2011 Nobel Prize in Physics. They made the stunning conclusion that the universe's expansion is speeding up as a result of their observations of far-off stars exploding.

The distance measurements utilizing type Ia supernovae (SN Ia) for the galaxies at high redshift provide the most direct and compelling evidence for the expanding cosmos powered by dark energy.

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We can verify the Newton's second law of motion mathematically by using the momentum impulse relation.

The rate of change of a body's momentum is directly proportional to the applied force and occurs in the direction in which the force operates, according to Newton's Second Law of Motion. where F is the applied force, M is the body's mass, and A is the resulting acceleration.

One way to state Newton's second law of motion is as follows:

Force is inversely correlated with change in momentum and time.

Now, F is directly proportional to mv-mu t or m(v-u) t [where (v-u) represents the acceleration, or change in velocity].

As a result, we discover that F is inversely proportional to m.

By using a constant k, this relationship F is directly proportional to ma can be transformed into an equation.

Thus, F=kma (where k is constant)

The preceding equation is now F=ma or Force= Mass*Acceleration because the value of k in SI units is 1.

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Answer:

Velocity

Explanation:

Objects in motion usually have a speed which is scalar or velocity which is a vector.

A scalar quantity is one with magnitude but has no directional attribute.

A vector quantity is one with both magnitude and directional attribute.

Speed is a scalar quantity that describes the magnitude of motion a body accrues.

Velocity is a vector quantity that describes both the magnitude of motion and the direction of motion in a body.

The frequency of the sound wave is 1.07 × 10⁹ Hertz

Wavelength is simply the distance over which the shapes of waves are repeated.

From the wavelength, frequency and speed relation,

λ = v ÷ f

Where λ is wavelength, v is velocity/speed and f is frequency.

Given that:

Plug values into the above formula.

λ = v ÷ f

f = v / λ

f = ( 343 m/s ) / ( 3.2 × 10⁻⁷ m )

f = 1.07 × 10⁹ Hz

Therefore, the frequency is 1.07 × 10⁹ Hz.

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Answer:

1) Given acceleration due to gravity as 10N/kg

N/kg is the same as m/s². From W=mg

making g subject ... you have g = W/m

where m is in kg and W is in N

hence we have N/kg

So g=10ms-²

Gravitational Potential Energy=mgh

At height 4m

PE=6 x 10 x 4

=240J.

At height 6m

PE=6 x 10 x 6

=360J.

2) KE=1/2mv²

=1/2 x 6 x 5² =75J

When the speed is doubled... it becomes 2x

so V = 2x5=10ms-¹

KE=1/2 x 6 x 10² =300J.

3) KE=1/2mv²

KE is given as 100J

mass=0.5kg

Making V the subject

you have v² =2KE/m

v²=2 x 100/0.5

v²=400

taking square root

v=20ms-¹.

Have a great day✌

Answer:

Explanation:

Refraction of a light ray may be defined as:

D. changing direction while crossing a boundary ​

Work applying a force over a distance.

Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance traveled for a constant force directed in the direction of motion.

Work = force x distance. In units, Joules = Newtons x meters.

Work applying a force over a distance.

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There are three different methods to calculate the standard Gibbs free energy change (ΔG⁰) for a reaction:

Standard Gibbs Free Energy of Formation (ΔG⁰f): This method involves calculating the ΔG⁰ of each individual reactant and product based on their standard Gibbs free energy of formation values. The ΔG⁰f values can be found in thermodynamic tables. The ΔG⁰ for the reaction is then determined by subtracting the sum of the ΔG⁰f of the reactants from the sum of the ΔG⁰f of the products.

Standard Gibbs Free Energy Change (ΔG⁰): This method involves using the standard Gibbs free energy change values for known reactions and applying them to the desired reaction by appropriately balancing the stoichiometric coefficients. The ΔG⁰ for the desired reaction is determined by the algebraic sum of the ΔG⁰ values of the known reactions.

Equilibrium Constant (K) and ΔG⁰: This method involves using the equilibrium constant (K) of the reaction and the relationship between ΔG⁰ and K. ΔG⁰ can be calculated using the equation ΔG⁰ = -RT ln(K), where R is the gas constant and T is the temperature in Kelvin.

If calculating ΔG⁰ for a reaction at a temperature other than 25 ⁰C, I would choose the third method using the equilibrium constant and ΔG⁰ equation. This method allows for the calculation of ΔG⁰ at any given temperature by taking into account the temperature-dependent equilibrium constant.

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None of the options listed is a negative externality. A negative externality is an unintended consequence of an economic activity that affects a third party who is not directly involved in the activity.

If I were to choose: Businesses would not necessarily increase hiring rates.

This could be considered a negative externality because the grant funding is intended to fund job training in order to increase employment opportunities, but if businesses do not increase their hiring rates despite having a pool of trained workers, then the intended benefit of the grant may not be fully realized. This could result in a loss of resources and a missed opportunity to address unemployment in the community.

Answer:

Its temperature

Explanation:

Answer:

The stars age

Explanation:

As stars age, they run out of hydrogen to burn, decreasing the amount of energy they give off. So the younger stars can look bluer while older ones look more red.

Hope this helps :3

Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

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In Bohr's model of the atom, electrons make transitions between orbitals of specific energies. They do not move from orbit to orbit in many small steps or spread uniformly through a large, positive mass. They also cannot be halfway between orbits or not confined to specific orbits.

Bohr explained that the addition of energy can move electrons into various orbits. A photon, or quantum of light, is produced when the electrons return to their ground state following the removal of the energy. The theory that came to be known as quantum theory was based on this.

In July of 1913, physicist Niels Bohr distributed the first of a progression of three papers presenting this model of the particle, which became referred to just as the Bohr molecule.

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The mass of a ball is 3.5 kg. It moves down a slope that is inclined at 40 degrees with respect to the horizontal. The base of the slope has a length of 4.8 meters.the ball loses 106.2 Joules of gravitational potential energy when it rolls down the slope.

It is required to determine how much gravitational potential energy the ball loses when it rolls down the slope.For this, we need to use the following formula:ΔPE = mghwhere m = mass of the ball = 3.5 kgg = acceleration due to gravity = 9.81 m/s2h = height from which the ball rolls downLet's analyze the situation. The ball moves down a slope. The potential energy (PE) of the ball at the top of the slope is converted into kinetic energy (KE) as it moves down the slope. The ball gains KE, and it loses PE.The height from which the ball rolls down the slope is given by the following expression:h = length of slope × sin θh = 4.8 × sin 40°h = 3.086 metersSubstitute the given values into the formula for ΔPE.ΔPE = mghΔPE = 3.5 × 9.81 × 3.086ΔPE = 106.2 JoulesTherefore, the ball loses 106.2 Joules of gravitational potential energy when it rolls down the slope.

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The statement "Geothermal heat pumps may be used to exploit the temperature difference between the earth's surface and underground in the earth's mantle." is True because Geothermal heat pumps utilize the temperature difference between the Earth's surface and the underground

Geothermal heat pumps utilize the temperature difference between the Earth's surface and the underground to provide heating and cooling for buildings. The Earth's crust acts as a natural heat source or heat sink depending on the season.

The temperature of the Earth's surface experiences variations throughout the year due to the changing weather conditions, but at a certain depth, the temperature remains relatively constant. This stable temperature is typically found in the Earth's mantle.

Geothermal heat pumps work by extracting heat from the ground during the winter and transferring it to the building for heating purposes. During the summer, the process is reversed, and heat is extracted from the building and transferred to the cooler ground.

This efficient method takes advantage of the Earth's natural heat storage capacity to provide heating and cooling with reduced energy consumption.

Therefore, it is true that geothermal heat pumps can exploit the temperature difference between the Earth's surface and underground in the Earth's mantle.

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Viscosity of the fluid affects the settling velocity of the droplets travelling in a desalter.: As the viscosity of a fluid increases, so does the settling velocity of the droplets.

In a desalter, settling is the most common mechanism used to remove water droplets from the oil. The settling velocity of droplets in the desalter is affected by the viscosity of the fluid. Here are some ways how viscosity of the fluid affects the settling velocity of the droplets travelling in a desalter:

1. In general, as the viscosity of a fluid increases, so does the settling velocity of the droplets. This is because as the fluid becomes more viscous, the drag forces on the droplets decrease and they fall faster. The droplets settle more quickly in a viscous fluid.

2. The settling velocity of a droplet also depends on its size. Larger droplets fall faster than smaller droplets. Therefore, the size of the droplets in the desalter is an important factor to consider in determining their settling velocity.

3. Additionally, the density of the fluid also plays a role in the settling velocity of droplets. Denser fluids typically have higher settling velocities than less dense fluids.

In conclusion, the viscosity of the fluid in a desalter affects the settling velocity of droplets in many ways.

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Answer:

The answer is B.

Explanation:

Since they are made up of soft tissues, they decompose become they become fossils.