the primary benefit of using a collimator on a rinn bai instrument with the bisecting technique is

i believe the answer is B: both wind up at 60°C

but it's also reasonable to assume, given enough time, they wind up at 20°C because the water would heat up to cool the metal then slowly release the heat to the air untill they both reach 20°C

if it were me I'd answer B, apologies if I'm wrong

Answer:

yourmom.com

Explanation:

Ask your mom!!!!!!!

Answer:

3.24108 Raised to 23 I'm pretty sure

1a. The empirical formula of the compound is Fe₂O₃

1b. The molecular formula of the compound is Fe₂O₃

2a. The molecular formula of the anhydrous salt is MgSO₄

2b. The formula of the crystalline salt is MgSO₄.7H₂O

3i. The number of mole of carbon atoms in the compound is 6 moles

3ii. The number of mole of hydrogen atoms in the compound is 18 moles

3iii. The number of molecules in 3 moles of ethane is 1.806×10²⁴ molecules

Divide by their molar mass

Fe = 69.9 / 56 = 1.248

O = 30 / 16 = 1.875

Divide by the smallest

Fe = 1.248 / 1.248 = 1

O = 1.875 / 1.248 = 3/2

Multiply by 2 to express in whole number

Fe = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Fe₂O₃

Molecular formula = empirical × n = molar mass

[Fe₂O₃]n = 159.89

[(56×2) + (16×3)]n = 159.89

160n = 159.89

n = 159.89 / 160

n = 1

Molecular formula = [Fe₂O₃]n

Molecular formula = [Fe₂O₃] × 1

Molecular formula = Fe₂O₃

We'll begin by calculating the empirical formula

Divide by their molar mass

Mg = 20.0 / 24 = 0.83

S = 26.66 / 32 = 0.83

O = 53.33 / 16 = 3.33

Divide by the smallest

Mg = 0.83 / 0.83 = 1

S = 0.83 / 0.83 = 1

O = 3.33 / 0.83 = 4

Thus, the empirical formula of the anhydrous salt is MgSO₄

The molecular formula of the anhydrous salt can be obtained as follow:

Molecular formula = empirical × n = molar mass

[MgSO₄]n = 120

[24 + 32 + (16×4)]n = 159.89

120n = 120

n = 120 / 120

n = 1

Molecular formula = [MgSO₄]n

Molecular formula = [MgSO₄] × 1

Molecular formula = MgSO₄

Divide by their molar mass

MgSO₄ = 48.8 / 120 = 0.4

H₂O = 51.2 / 18 = 2.8

Divide by the smallest

MgSO₄ = 0.4 / 0.4 = 1

H₂O = 2.8 / 0.4 = 7

Thus, the formula of the crystalline salt is MgSO₄.7H₂O

1 mole of C₂H₆ contains 2 moles of carbon atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 2 = 6 moles of carbon atoms

1 mole of C₂H₆ contains 6 moles of hydrogen atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 6 = 18 moles of hydrogen atoms

From Avogadro's hypothesis,

1 mole of ethane = 6.02×10²³ molecules

Therefore,

3 moles of ethane = 3 × 6.02×10²³ molecules

3 moles of ethane = 1.806×10²⁴ molecules

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Complete question

2. A crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%. Ccalculate the molecular formula of the anhydrous and the crystalline salt. The molecular weight of the anhydrous salt is 120

Answer:

Magnesium, calcium and sodium.

Explanation:

Magnesium, calcium, sodium, and other beneficial minerals are the substances present in drinking water. Different regions have different fluoride concentration in their water such as in sea water, fluoride level is 1.1 mg/L while in surface water, the concentration is 0.01–0.3 ppm. Yes, fluoride is soluble in water. No, fluoride should not be added to drinking water because it harm for health. All the questions can be answered by science because it is related to chemistry.

Answer:

A. Corn has changed over time due to selective breeding.

Hope this helps :)

Answer:

the particles with a negative charge are protons

Answer:

d

Explanation:

it just makes sense

Answer:

Cold temperatures!

Explanation:

Both planets are very far from the sun, now to explain how the other answers would fit or just dont make sense, No rings, the answer isn't the best fitting answer for this question, 27 moons, this is wrong because neptune has 14 moons, only uranus has 27. No axis tilt, this answer is wrong because both planets have an axis.

Strand discrimination during the process of DNA replication is based on DNA methylation in E. coli.

Methylation is a process where a methyl group is added to the DNA molecule. In E. coli, this helps distinguish the newly synthesized DNA strand from the original parent strand, ensuring accurate replication and avoiding errors.

The strands, on the other hand, are made to aid in curriculum planning by concentrating on the outcomes of the course rather than the inputs, or what the student will gain from it and how we can help them achieve this.

MMR must be able to distinguish between the daughter and parental strands; otherwise, the mis-pair will become a mutation if excision and re-synthesis are improperly directed at the parental strand.

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Methylation of the H3K4 amino acid residue in histone H3 results in a transcriptionally active gene.

Histone methylation is an epigenetic modification that plays a crucial role in regulating gene expression. Methylation of specific lysine residues in the N-terminal tails of histones can either activate or repress gene transcription, depending on the position and degree of methylation.

Methylation of H3K4 is generally associated with transcriptional activation, whereas methylation of H3K9 and H3K27 is typically associated with transcriptional repression. Methylation of H3K4 is believed to facilitate the recruitment of transcriptional activators to the promoter region of genes, leading to an increase in gene expression.

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To find the moles present in 83.20 grams of manganese we must use the molar mass of manganese. This mass is equal to 54.94g/mol. So the moles of manganese (Mn) will be:

Answer: 83.20 grams of manganese are equivalent to 1.51 moles

The length of the object could be estimated to tenths of the smallest calibrations .

What is meter stick ?

A meter stick is a type of measuring tool that is used to measure length or distance. It is a straight, flat piece of wood or plastic, with markings along its length to indicate units of length, typically in centimeters and millimeters. At one end, it often has a metal tip or a hanging hook for hanging the meter stick in place. Meter sticks are commonly used in a variety of settings, such as schools, workshops, and laboratories. They are used to measure the length of objects, to lay out distances or to check measurements made with other tools, such as rulers or tapes.

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The number of reactants is less than the number of products in a decomposition reaction.

This is the type of chemical reaction which involves a reactant being broken down into two or more products.

This means the number of product is always greater than the reactant which is why option C was chosen.

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Answer:

hola no ablo inglés porfavor

The cat will be 367.72 centifingers tall.

1 finger = 3.1 inches

Recall that: centi =  \(10^-^2\)

Thus, 1 centifinger = \(10^-^2\) finger

The cat is 11.4 inches tall.

If 1 finger = 3.1 inches

Then, how many fingers will make 11.4 inches?

= 11.4 x 1/3.1 = 3.6772 fingers

3.6772 fingers = 3.6772 x  \(10^2\) centifinger

                          = 367.72 centifingers

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The characteristics of the graphs we can find the answer on how to draw the graph

The graphical representation is one of the best methods to visualize the relationships between a series of experimental data and to be able to find their functional relationships.

A graphic representation has several parts

The scales are found with the relationship between the variation of the data between the amount of paper or graph range, let's look for the scales for each axis.

x-axis

The variation of the data  Δx = Final value - initial value

Paper range, generally it is  x = 20cm (sheet size)

They indicate that the graph must start at zero, so the minimum value must be changed,

             initial value = 0

              Δx = 760 -0 = 760

             x scale  = 760/20

             x scale  = 38 mb / cm of paper

y-axis

Data range   Δy= 0.9 -0

Paper range  y= 20 cm (sheet size)

            y-scale  = 0.9 / 20

            y scale  = 0.045 mL / cm paper

One of the characteristics of the scale is that it must be comfortable for graphing, which is why it approximates the following units

Selected scales  

         x scale  = 40 mb / cm paper

         y scale = 0.05 mL / cm paper

The second part consists of marking values ​​equally spaced and facilitating readable in the two axes, see attached for a graph made in a computer program

Plot each experimental point as best as possible, there are always some approximations by the selected scales

Draw a curve that passes through most of the experimental points and those that remain outside are balanced above and below the curve, in this case the program draws a line between each point, but it is preferable to draw a smooth curve.

In conclusion with the characteristics of the graphs we can find the answer on how to draw the graph

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The process that correctly describes the growth in the number of ionized nitrogen molecules over time is D. The number of ionized molecules increases exponentially with each ionized molecule ionizing 3 other molecules every nanosecond.

Let's analyze the equation tN2 = 3⋅N, where N is the number of ionized molecules and t is the time in nanoseconds.

The equation states that the number of ionized molecules at time t is equal to 3 times the number of ionized molecules at the previous time step.

This implies that each ionized molecule ionizes 3 other molecules every nanosecond.

A physicist is studying the nature of static discharge by applying a voltage across a microscopic tube filled with nitrogen.

Static discharge is an event that takes place when there is a sudden flow of electric charge between two objects with different electrical potentials. This electric charge transfer results in a brief burst of electromagnetic energy (EMI or EMF), which can sometimes be observed as a visible spark in low-light conditions or heard as a crackling sound in high-quality audio systems.

The nature of static discharge is dependent on a variety of factors, including the composition of the material, the temperature and humidity, the electrical potential between the two objects, and the distance between the objects. Typically, static discharge occurs more frequently in environments with low humidity, such as during the winter months or in arid regions, as moisture acts as an insulator and prevents the buildup of electrical charge. In addition, materials that are good electrical conductors, such as metals, are more likely to experience static discharge than materials that are poor conductors, such as plastics or rubber.

Therefore, the correct description of the growth in the number of ionized nitrogen molecules over time is:

D. The number of ionized molecules increases exponentially with each ionized molecule ionizing 3 other molecules every nanosecond.

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Complete question is:

" physicist is studying the nature of static discharge by applying a voltage across amicroscopic tube filled with nitrogen molecules.Every nanosecond from then on, any ionized molecules willionize an additional number of molecules not already ionized, and ionization does not get lost.The equationtN2 3shows N, the number of ionized molecules, t nanoseconds after initiating a voltage.Which of thefollowing correctly describes the growth in the number of ionized nitrogen molecules over time?A.The number of ionized molecules increases linearly with each ionized molecule ionizing 2 other moleculesevery nanosecond.B.The number of ionized molecules increases linearly with each ionized molecule ionizing 3 other moleculesevery nanosecond.C.The number of ionized molecules increases exponentially with each ionized molecule ionizing 2 othermolecules every nanosecond.D.The number of ionized molecules increases exponentially with each ionized molecule ionizing 3 othermolecules every nanosecond."

Answer:

c i think

Explanation:

Answer:

siks creo que creo que siks

The sum of the electrical and chemical forces acting on an ion is known as its electrochemical gradient.

Correct option is D.

This gradient is a measure of the potential energy of an ion that is generated by the combined influence of the electrical and chemical forces. The electrical force is generated by the charge difference between the ions and their surrounding environment, while the chemical force is generated by the concentration gradient between the ions and their surrounding environment.

The electrochemical gradient influences the movement of ions across the membrane, which is the basis for many biological processes such as active transport, muscle contraction, and nerve impulse propagation. The electrochemical gradient also affects the rate of metabolic reactions, as it can drive the movement of molecules in and out of cells.

Correct option is D.

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A sea breeze occurs at the coast of oceans and other large water bodies during sunny days.

The term sea breeze defined as it describes a wind that blows from the ocean inland towards land. In daytime, the land surface heats up faster than the water surface.

The sea breeze occurs mostly in the spring and summer months because of the higher temperature differences between the ocean and nearby land, mostly in the afternoon when the land is at more heating from the sun.

Thus, A sea breeze occurs at the coast of oceans and other large water bodies during sunny days.

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If 3.7 grams of cl2 are used, HCl produced from the reaction is 7.4 grams.

A balanced chemical reaction formed when the number of the atoms involved in the reactants side is same to the number of atoms in the products side.

The balanced chemical equation is

H₂ + Cl₂ ⇒ 2HCl

From the balanced equation above,

1 gram of Cl₂ reacted to produce 2 gram of HCl

To determine the grams of HCl produced

From the balanced equation above,

1 gram of Cl₂ reacted to produce 2 gram of HCl

Therefore,

3.7 gram of Cl₂ will react to produce

= 3.7 × 2

= 7.4 grams of HCl

Thus, if 3.7 grams of cl2 are used, HCl produced from the reaction is 7.4 grams.

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Answer:

I believe the answer is C.

Answer:

C

Explanation:

green house gases effects increases global warming

Volume (in L) of Carbon dioxide : 23.6 L

Avogadro's hypothesis:  

In the same T,P and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

\(\tt \dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}\)

Combustion of ethane :

\(\tt 2C_2H_6+7O_2\Rightarrow 4CO_2+6H_2O\)

mol ratio of C₂H₆ : CO₂ ⇒ 2 : 4

so the volume of CO₂ :

\(\tt \dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}\\\\\dfrac{11.8}{2}=\dfrac{V_2}{4}\\\\V_2=\boxed{\bold{23.6~L}}\)

Answer:

23.6

Explanation:

Answer:

B) Shape

Explanation:

The property of shape provides the best evidence that both samples are liquids and not solids because liquids do not have a definite shape, in contrast to solids, which do.

The enzyme β-ketothiolase cleaves off the acetyl-CoA molecule from the 3-ketoacyl-CoA, releasing acetyl-CoA and the remaining fatty acid chain forms acyl-CoA, which is two carbons shorter than the original fatty acid chain.

The complete reaction scheme for the catabolism of Oleoyl-CoA is given below:Oleoyl-CoA is broken down into acetyl-CoA, releasing 150 ATP molecules by the process of Beta-oxidation. The complete reaction scheme for the catabolism of Oleoyl-CoA is given below:

Step 1: Oleoyl-CoA is transported to the mitochondria matrix from the cytoplasm with the help of the carnitine shuttle system.

Step 2: The enzyme Acyl-CoA dehydrogenase catalyzes the removal of two hydrogen atoms from the alpha and beta carbons in the fatty acid chain and oxidizes it. This process forms a double bond between the alpha and beta carbon atoms, leading to the formation of trans-Δ2-enoyl-CoA.

Step 3: The enzyme enoyl-CoA hydratase adds a water molecule to the trans-Δ2-enoyl-CoA, converting it into L-3-hydroxyacyl-CoA.

Step 4: The enzyme L-3-hydroxyacyl-CoA dehydrogenase oxidizes L-3-hydroxyacyl-CoA, releasing a hydrogen ion (H+) and two electrons (2e-) and converts it into 3-ketoacyl-CoA.

Step 5: The enzyme β-ketothiolase cleaves off the acetyl-CoA molecule from the 3-ketoacyl-CoA, releasing acetyl-CoA and the remaining fatty acid chain forms acyl-CoA, which is two carbons shorter than the original fatty acid chain.

The cycle starts again, and this process is repeated until the fatty acid chain is completely degraded.

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A) pH after adding 9 mL of NaOH is 6.91 ; B) pH after adding 100 mL of NaOH is 13.18 ; C) pH after adding 400 mL of NaOH is 8.42 ; D) pH after adding 500 mL of NaOH is 12.

pH is used to find out the the basicity and acidity of a solution

HA + NaOH -> NaA + H₂O

Ka = [NaA][H₃O⁺] / [HA]

moles of acid = initial concentration x initial volume = 0.2 M x 0.1 L = 0.02 moles

A.) We add 9 mL of 0.05 M NaOH to acid solution. The total volume of the solution is now 100 mL + 9 mL = 0.109 L.

moles of NaOH added = concentration x volume = 0.05 M x 0.009 L = 4.5 x 10⁻⁴ moles

moles of acid remaining = initial moles - moles of NaOH added = 0.02 moles - 4.5 x 10⁻⁴ moles = 0.01955 moles

moles of NaA formed = moles of NaOH added = 4.5 x 10⁻⁴ moles

moles of H₃O⁺ produced = moles of NaOH added = 4.5 x 10⁻⁴ moles

moles of HA remaining = moles of acid remaining - moles of NaA formed = 0.01905 moles

Ka = [NaA][H₃O] / [HA]

[ H₃O⁺] = Ka x [HA] / [NaA]

[ H₃O⁺] = 2.9 x 10⁻⁶  x 0.01905 / 4.5 x 10⁻⁴ = 1.22 x 10⁻⁷ M

pH = -log[H₃O⁺] = -log(1.22 x 10⁻⁷) = 6.91

Therefore, pH after adding 9 mL of NaOH is 6.91.

B.) 100 mL of 0.05 M NaOH, so all the acid has been neutralized.

moles of NaOH added = concentration x volume = 0.05 M x 0.1 L = 0.005 moles

moles of NaOH remaining = moles of NaOH added - moles of acid = 0.005 moles - 0.02 moles = -0.015 moles (negative value indicates excess NaOH)

[OH-] = moles of excess NaOH / total volume = 0.015 moles / 0.1 L = 0.15 M

pOH = -log[OH-] = -log(0.15) = 0.82

So pH= 14 -pOH = 14 -0.82= 13.18

Therefore, pH after adding 100 mL of NaOH is 13.18.

C.) We have added a total of 400 mL of 0.05 M NaOH.

moles of NaOH added = concentration x volume = 0.05 M x 0.4 L = 0.02 moles

moles of NaOH remaining = moles of NaOH added - moles of acid = 0.02 moles - 0.02 moles = 0 moles

[NaA] = moles of NaA / total volume = 0.02 moles / 0.5 L = 0.04 M

Kb = Kw / Ka = 1.0 x 10⁻¹⁴ / 2.9 x 10⁻⁶ = 3.45 x 10⁻⁹

[OH-] = √(Kb x [NaA]) = √(3.45 x 10⁻⁹ x 0.04) = 2.61 x 10⁻⁶ M

pOH = -log[OH-] = -log(2.61 x 10⁻⁶) = 5.58

So, pH= 14 -pOH = 14 -5.58 = 8.42

Therefore, pH after adding 400 mL of NaOH is 8.42.

D.) We have added a total of 500 mL of 0.05 M NaOH.

moles of NaOH added = concentration x volume = 0.05 M x 0.5 L = 0.025 moles

moles of NaOH remaining = moles of NaOH added - moles of acid = 0.025 moles - 0.02 moles = 0.005 moles

[OH-] = moles of excess NaOH / total volume = 0.005 moles / 0.5 L = 0.01 M

pOH = -log[OH-] = -log(0.01) = 2

So pH =14 -pOH =14 -2=12

Therefore, pH after adding 500 mL of NaOH is 12.

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Answer:

width of between 29 and 30 inches, a depth of between 15 and 16 inches, and a height of between 16 and 18 inches.