The precise way a researcher measures and defines a variable is know as the

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Answer:

30.3 meters, 172 degrees.

Explanation:

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Answer:

Therefore it is save to carry a 62kg adult

Explanation:

From the question we are told that:

Mass \(m=380kg\)

Height of supporting Rock \(X=85cm\)

Length of Board\(L_r=4.5m\)

Mass of board \(M_b=22kg\)

Mass of adult \(M_a=62\)  

Generally the moment of balance about wedge part about  is mathematically given by

\(N -Q + R = Mg + mg\)

\(0.85*N - Mg*2.25 - mg*(2.25 + x) = 0\)

\(0.85*N = + Mg*2.25 + mg*(2.25 + x)\)

where

\(N+R=4547\)

therefore

\(N = 570.70588 + 1608.3529 + 714.823 x\)

if N=0 at fallen person

\(x=3.04m\)

Therefore it is save to carry a 62kg adult

Answer:

Explanation:

From the given information:

mass = 64 kg

speed = 3.2 m/s

coefficient of friction \(\mu =\) 0.70

The mechanical energy touted relates to the loss of energy in the system as a result of friction and this can be computed as:

\(W = \Delta K.E\)

\(\implies \dfrac{1}{2}m(v^2 -u^2)\)

\(= \dfrac{1}{2}(64.0 \kg) (0 - (3.2 \ m/s^2))\)

Thus, the mechanical energy touted = 327.68 J

According to the formula used in calculating the frictional force

\(F_r = \mu mg\)

= 0.70 × 64  kg× 9.8 m/s²

= 439.04 N

The distance covered now can be determined as follows:

d = W/F

d = 327.68 J/  439.04 N

d = 0.746 m

From this data it is clear that the time require to complete ramp 3 is more than any other, hence it can be large ramp or there are more objectless or  turns. Ramp 2 requires least time to complete, it can be shorter or having less number of obstacles.

An inclined plane, also known as a ramp, is a flat supporting surface that is slanted at an angle from the vertical direction, with one end higher than the other, and is used to help raise or reduce a weight. The inclined plane is one of the six traditional basic devices established by Renaissance scientists. Inclined aircraft are used to transport big cargoes over vertical obstructions. Examples include a ramp used to load items into a truck, a person going up a pedestrian ramp, and an automobile or railroad train climbing a gradient. it can have obstacles in the path

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The mass of the metal ball is approximately equal to 0.1 kg.

Freefall is a type of motion in which an object falls with gravitational acceleration without resistance from air, surface, or medium. In a freefall, the only force acting on an object is the force of gravity. In a freefall, the acceleration of an object is given by the formula:  `g = 9.81 \(m/s^2`\)

The final velocity of a freefalling object can be calculated using the formula: `v = g*t `Where v is the final velocity, g is the gravitational acceleration, and t is the time taken to reach the final velocity. The force acting on an object is equal to the product of the mass of the object and the acceleration acting on the object. This is known as Newton's Second Law of Motion.

The formula for calculating force is:  `F = ma`.Where F is the force acting on the object, m is the mass of the object, and a is the acceleration acting on the object.Given that the velocity of the metal ball at the moment of striking the ground was 30 m/s, and that it stopped after penetrating the sand for 0.01 s, we can calculate the mass of the metal ball using the formula for force.

We can assume that the force acting on the metal ball is equal to the average resistance force of the sand against the motion of the ball.

The formula for calculating force is: `F = ma`.

Rearranging the formula, we get: `m = F/a` .

Substituting the given values, we get:  `

m = -3010/10`

Thus, the mass of the metal ball is approximately equal to 0.1 kg.

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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Answer:

C

Explanation:

Options A and B are not even pointing in the direction as the vectors in the question so they shouldn't even be considered.

Option C looks like the closes since vectors A and B are pointing in a similar direction (negative x-axis)

The best representation for the resultant vector representing the resultant R=A+B would be option C because the result is represented by the closing side of the triangle, therefore the correct answer would be C.

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem we have to find out the resultant vector from the sum of vector A and vector B,

The resultant of the vector can be calculated with the help of the triangle law of the vector addition in which the sum is given by the closing side of the triangle.

Thus, the correct answer is option C.

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prairie chickens organisms is not found in savannas. The correct option is c.

Savannas are typically characterized by the presence of tall grasses and a few scattered trees. The climate in this ecosystem is hot and dry, with a pronounced wet and dry season. Prairie chickens are not found in savannas.Here's why prairie chickens are not found in savannas:Savannas are typically found in tropical regions and are characterized by tall grasses and a few scattered trees. In contrast, prairies are found in temperate regions and are characterized by shorter grasses and a greater number of trees. Prairie chickens are a species of bird that are primarily found in prairie habitats. These birds are adapted to life on the open plains and feed on a variety of insects and seeds. While prairie chickens may share some similarities with the animals found in savannas, they are not typically found in this type of ecosystem.  

option C is the correct answer.

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This question involves the concept of  Newton's law of gravitation.

The force of gravity between the two spaceships is "1355.78 N".

According to Newton's Law of Gravitation:

\(F=\frac{Gm_1m_2}{r^2}\)

where,

Therefore,

\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)

F = 1355.78 N = 1.356 KN

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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,

The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.

The distance between spaceships (r) is 35 meters.

It is required to find the Force of gravity between these spaceships.

It is defined as the force which attracts any two masses in the universe.

By Newton's law of Gravitation:

\(\rm F= \frac{Gm_1m_2}{r^2}\)  , Where

\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)

Putting values in the above formula:

\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)

F = 1355.78 N = 1.356  KN

Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

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Answer:

40*C

Explanation:

Answer: Momentum applies to objects in motion and is the product of mass and velocity. It is not the energy, but the variables are the same. By contrast, "moment" is an expression of the "rotational force" caused by a force acting at some distance from a fulcrum.

Answer:

Efficiency = 65%

Explanation:

The formula of Efficiency applied to any circumstance is:

Efficiency = Useful Energy / Energy applied

Then replacing the values given its:

Efficiency = 25 J / 32 J

Efficiency = 0.65

0.65 written as percentage is 65%, then:

Efficiency = 65%

As you do 32 joules of work using a pair of scissors and the scissors do 25 joules of work cutting a piece of fabric, the efficiency of the scissors is 78.125%.

Efficiency is the proportion of work done by a machine or throughout a process to the overall amount of energy or heat used.

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Mathematically,

efficiency of a machine = (work output/work input)×100%

Given parameters:

Input work to the pair of scissors= 32 joules.

Output work from the pair of scissors= 25 joules.

Hence,

The efficiency of a machine = (work output/work input)×100%

= ( 25 joule/32joule)×100%

= 78.125%

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Answer:

Sound Energy

Explanation:

Good luck :)

The charge on the capacitor 2 (C₂) is 48μF.

In the circuit diagram, C₁ and C₂ are in series connection, while C₃ is parallel to C₁ and C₂.

\(Q_1 = Q_2 = Q\\\\V = \frac{Q}{C_1} + \frac{Q}{C_2} \\\\V = Q(\frac{1}{C_1}+ \frac{1}{C_2} )\\\\V = Q(\frac{C_2 + C_1}{C_1 C_2} )\\\\Q = V(\frac{C_1 C_2}{C_2+ C_1} )\\\\Q = 24 \times (\frac{6\times 10^{-6} \times 3 \times 10^{-6}}{6\times 10^{-6} \ + \ 3\times 10^{-6}} )\\\\Q = \frac{4.32 \times 10^{-10}}{9\times 10^{-6}} \\\\Q = 4.8\times 10^{-5} \ C\\\\Q = 48 \ \mu C\)

Thus, the charge on the capacitor 2 (C₂) is 48μF.

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Answer: Carbon dioxide (CO2), Carbon monoxide (CO), Methane (CH4)

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

Earth pulls the sun towards itself with a force equal to the ratio of the mass of the sun to the mass of Earth

The Earth pulls the sun toward itself with an equal force. (Option D)

According to the 3rd Newton's Law, forces existing in the universe are shown in pairs, that is to say, for all action force, there is a corresponding reaction force of equal magnitude and opposite direction. By the Newton's Law of Gravitation we understand that gravitation between the Sun and the Earth is done because of a gravitational field created by mutual interaction, in terms of their masses and distance among them. The pair of forces is not based on direct contact.

Hence, we conclude that the Earth pulls the sun toward itself with an equal force.

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Answer:

Explanation:

Moment of inertia of each wheel = 1/2 m R²

m is mass and R is radius of wheel

= .5 x 15.5 x .175²

= .2373 kg m²

moment of inertia of tyre

1/2 m ( r₁² + r₂² )

= 1/2 x 1.9 x ( .315² + .19²)

= 1/2 x 1.9 x ( .099+ .036)

= .12825 kg m²

moment of inertia of tread

= 1/2 m r²

= .5 x 12 x .335²

= .67335 kg m²

moment of inertia of axle

= 1/2 m r ²

= .5 x 14.5 x .0195²

= .00275

moment of inertia of drive shaft

= 1/2 x 32.5 x .029²

= .0137 kg m ²

Total moment of inertia of one tyre

=  1.05535 kg m²

total moment of inertia of two rear wheels

= 2.1107 kg m²

95 % of torque

= .95 x 180

= 171 Nm

angular acceleration

= torque / moment of inertia

= 171 / 2.1107

= 81.01 radian /s²

The distance CE is called the altitude of the triangle ABD.

In mathematics, the distance CE is called the altitude of the triangle ABD.

An altitude is a line segment drawn from the vertex of a triangle to the opposite side, and it is perpendicular to that side.The altitude CE divides the triangle into two smaller right triangles, ACE and BCE.

The length of the altitude can be found using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

To find the length of the altitude CE, you would use the Pythagorean theorem on either of the right triangles.

For example, using the right triangle ACE, you would have:

AC² + CE² = AE²

Where AC is the length of one of the legs of the triangle, CE is the length of the altitude, and AE is the length of the hypotenuse.

By rearranging this equation, you can solve for CE:

CE² = AE² - AC²CE = √(AE² - AC²)

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Answer:

I hope this helps

Answer:

Aluminum and steel are good conductors of electricity.

Explanation:

1) All materials are good conductors of electricity.

This is false because nonmetal materials such as plastic or wood cannot conduct electricity.

2) Aluminum and steel are good conductors of electricity.

This is true. All metals are conductors of electricity.

3) Gold and wood are poor conductors of electricity.

This is false. Although gold can conduct electricity, wood can't.

4) Plastic and copper are good conductors of electricity.

This is false. Although copper can conduct electricity, plastic can't.

I hope this helps!

Answer:

B) Aluminum and steel are good conductors

Explanation: