The maximum velocity of aircraft will be between 200- 300 ft.
What is velocity ?
Velocity is the rate at which something is travelling in a specific direction. An object's velocity can either be constant or variable. The object's speed, direction of travel, or both can be altered.
What is sea level ?
On Earth, sea level serves as the reference point for determining elevation and depth. Since the ocean is one continuous body of water, its surface tries to seek uniformity everywhere it is.
b= 35.8 ft
S= 174 ft2
W= 2950lb
fuel capacity= 65
cp₁₀= 0.025
e=0.8
p=0.8
powerplant= one piston engine of 230hp of sea-level
V= ?
Let us assume v= 200ft/s
G= W/ 1/2 lr v²s = 2950/ 1/2 *0.0002377 * (200)² *177
= 0.357
Aspect ratio b³/3 = (35.8)²/ 17 a
=7.37
=0.025+ (0.357)²/π (0.07) (7.37)²
=0.0319
L/D = 0.357/ 0.0319 = 11.2
T= W/ L/D = 2950/ 11.2 = 263lb
PR=TRV = 263lb* 200
= 52600lb/fts²
This engine has power of 230 hp
230*550lb
= 126500 lb/fts²
so it can flow more at velocity of sea level
Hence, the maximum velocity of aircraft will be between 200- 300 ft.
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The diagram shows two forces acting perpendicularly on an object. The forces have magnitudes F1 = 8.2 N and F2 = 20.6 N. What is the net force acting on the object?
a) magnitude 22 N; direction 68 degrees counterclockwise from
b) magnitude 22 N; direction 22° counterclockwise from
c) magnitude 25 N; direction 34° counterclockwise from
d) magnitude 25 N; direction 68° counterclockwise from
Answer:
Option (b).
Explanation:
Two forces are acting perpendicularly on an object. We have, F₁ = 8.2 N and F₂ = 20.6 N
We need to find the net force acting on the object. When two forces are acting in perpendicular to each other, the net force on it is given by :
\(F=\sqrt{F_1^2+F_2^2} \\\\=\sqrt{8.2^2+20.6^2} \\\\=22.17\ N\)
or
F = 22 N
Let \(\theta\) is the angle. It can be given by :
\(\tan\theta=\dfrac{F_1}{F_2}\\\\\tan\theta=\dfrac{8.2}{20.6}\\\\=21.7^{\circ}\)
or
\(\theta=22^{\circ}\)
So, the net force is 22 N and the direction is 22° counterclockwise from F₁. Hence, the correct option is (b).
What small lifestyle change can you make to have a positive impact on your physical exercise?
Use technology to make simple chores even easier.
Choose a tech activity that gets your body moving.
Drive to a neighbor's house instead of walking there.
Choose a tech activity that helps you be more stationary.
Along with your family, plan nutritious meals, or establish a weekly healthy potluck at work. I don't enjoy exercising. Discard the outdated idea that exercising involves weightlifting at a gym.
What lifestyle modifications are beneficial?The six fundamental lifestyle habits for a long, good health include sleeping enough, eating a good food, exercising, keeping a healthy weight, quitting smoking, and drinking in moderation.
What are five healthy lifestyle activities?Walking, cycling, skating, sports, active recreation, and play are all common methods to be active that anyone may do for fun and at any ability level. It has been demonstrated that regular exercise helps control and prevent noncommunicable diseases like diabetes, heart disease, stroke, and a number of malignancies.
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A rope is used to pull a box 15.0 m across a floor. The rope is held at an angle of 46.0˚ and a force of 628 N is used along the rope. What is the work done? Your answer should be rounded to the tenths place, and include the correct units. View question
Answer:
6544.07 J
Explanation:
From the question given above, the following data were obtained:
Distance (d) = 15 m
Force (F) = 628 N
Angle (θ) = 46°
Workdone (Wd) =?
The work done can be obtained by using the following formula:
Wd = Fd × Cos θ
Wd = 628 × 15 × Cos 46
Wd = 9420 × 0.6947
Wd = 6544.07 J
Therefore, the workdone is 6544.07 J
A linear elastic spring can be compressed 10. 0 cm by an applied force of 5. 0 N. A 4. 5
kg crate of apples, moving horizontally at 2. 0 m/s collides with the spring. What will be
the maximum compression of the spring?
The maximum compression of the spring is 0.6 m.
Spring constantThe spring constant of the spring is calculated as follows;
F = kx
k = F/x
k = (5)/(0.1)
k = 50 N/m
Maximum compression of the springThe maximum compression of the spring is calculated as follows;
U = K.E
¹/₂kx² = ¹/₂mv²
x² = (mv²)/(k)
x = √(mv²)/(k)
x = √(4.5 x 2²)/(50)
x = 0.6 m
Thus, the maximum compression of the spring is 0.6 m.
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suppose an object is accelerated by a force of 100 n . suddenly a second force of 100 n in the opposite direction is exerted on the object, so that the forces cancel. the object is?
If an object is accelerated by a force of 100 N and then a second force of 100 N in the opposite direction is applied to the object, the object will continue to move at a constant velocity in the direction of the original force.
When the two forces are equal and opposite, they cancel each other out, resulting in a net force of zero on the object. This means that the object is no longer accelerating, and is instead moving at a constant velocity in the direction of the original force. This constant velocity is known as the terminal velocity of the object, and is determined by the balance of forces acting on the object.
In summary, if two forces of equal magnitude but opposite direction act on an object, the object will continue to move at a constant velocity in the direction of the original force, with a net force of zero.
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What is the resistance of a 150 W light bulb running on a 120 V circuit 
Answer:
96 Ω
Explanation:
Given:
U = 120 V
P = 150 W
Find: R - ?
\(r = \frac{ {u}^{2} }{p} \)
\(r = \frac{ {120}^{2} }{150} = 96 \: Ω\)
An engine using 1 mol of an ideal gas initially at 18. 5 L and 358 K performs a cycle
consisting of four steps:
1) an isothermal expansion at 358 K from
18. 5 L to 39. 1 L ;
2) cooling at constant volume to 180 K ;
3) an isothermal compression to its original
volume of 18. 5 L; and
4) heating at constant volume to its original
temperature of 358 K. Find its efficiency. Assume that the
heat capacity is 21 J/K and the universal gas constant is 0. 08206 L · atm/mol/K =
8. 314 J/mol/K
The efficiency of the engine is zero. This means that the engine does not convert any of the heat absorbed from the source into useful work.
The efficiency of the engine can be calculated using the formula:
efficiency = (work done by the engine) / (heat absorbed from the source)
The work done by the engine is equal to the area enclosed by the cycle on a pressure-volume (PV) diagram. We can break down the cycle into four steps and calculate the work done in each step:
Step 1: Isothermal expansion at 358 K from 18.5 L to 39.1 L.
During this step, the gas absorbs heat from the source at a constant temperature of 358 K. The work done by the gas is given by:
work = \($nRT\ln\left(\frac{V_2}{V_1}\right)$\)
where n is the number of moles of gas, R is the universal gas constant, and T is the temperature in Kelvin. Substituting the values, we get:
work = (1 mol)(8.314 J/mol/K)(358 K) ln(39.1 L/18.5 L) = 5678 J
Step 2: Cooling at constant volume to 180 K.
During this step, the gas rejects heat to the sink at a constant volume of 18.5 L. Since the volume is constant, no work is done by the gas.
Step 3: Isothermal compression to the original volume of 18.5 L.
During this step, the gas rejects heat to the sink at a constant temperature of 180 K. The work done on the gas is given by:
work = \($-nRT\ln\left(\frac{V_2}{V_1}\right)$\)
where V2 is the final volume (18.5 L) and V1 is the initial volume (39.1 L). Substituting the values, we get:
work = -(1 mol)(8.314 J/mol/K)(180 K) ln(18.5 L/39.1 L) = -2978 J
Step 4: Heating at constant volume to the original temperature of 358 K.
During this step, the gas absorbs heat from the source at a constant volume of 18.5 L. Since the volume is constant, no work is done by the gas.
The total work done by the engine is the sum of the work done in each step:
total work = 5678 J + 0 J - 2978 J + 0 J = 2700 J
The heat absorbed from the source is equal to the heat absorbed in steps 1 and step 4:
heat absorbed = nCΔT = (1 mol)(21 J/K)(358 K - 358 K) + (1 mol)(21 J/K)(358 K - 358 K) = 0 J
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how long does it take to get to neptune at the speed of light
It would take approximately 0.166 days (or about 4 hours) to reach Neptune at the speed of light.
The average distance from Earth to Neptune is approximately 4.3 billion kilometers. Since the speed of light is about 299,792 kilometers per second, we can calculate the time it would take to reach Neptune at the speed of light.
Distance = Speed × Time
4.3 billion kilometers = 299,792 kilometers/second × Time
Time = 4.3 billion kilometers / 299,792 kilometers/second
Calculating this equation gives us approximately 14,345 seconds.
To convert this to a more commonly used unit, we divide by the number of seconds in a day:
14,345 seconds / (24 hours × 60 minutes × 60 seconds) ≈ 0.166 days
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when is your potential energy and kinetic energy at the max at a swing
Potential energy is held in a swing when it is pulled to one side, and when it is released, it transforms into kinetic energy. The topmost position of it has the highest potential energy, whereas the bottommost position, where the kinetic energy is highest, has the lowest potential energy.
When does kinetic energy peak during a swing?The swing's bottom, where gravity's potential energy is at its lowest, has the most kinetic energy. The pendulum keeps swinging upward while slowing down and losing kinetic energy as well as potential energy from gravity.
Where does the potential energy peak during the swing?Some of the swing's potential energy transforms into kinetic energy as it descends. The swing's kinetic energy is at its highest since it is going at its fastest speed while it is at its lowest point.
Why is the extreme position where potential energy is greatest?When bob has the greatest displacement relative to its mean position in a basic pendulum, that is an extreme position. The potential energy of the bob is at its highest point and the kinetic energy is at its lowest point in this position. Acceleration and velocity are both zero when in an extreme posture.
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Where did the Big Bang occur?
A. First the fabric of space came into existence, and then the Big Bang appeared at some arbitrary point within it.
B. Everywhere in the universe at once, because the entire universe (including space itself) was a point
C. At all points simultaneously on the surface very much like an expanding balloon
D. at a single point in the center of the then-existing universe
E. All of these statements are equally correct.
The Big Bang occurred in B. Everywhere in the universe at once, because the entire universe (including space itself) was a point
A theory called the Big Bang Theory aims to explain how the vast world got its start. It was brought to a conclusion using several formulae. The Big Bang happening simultaneously everywhere in the cosmos is currently the most frequently accepted idea. This is due to the theory that there was no one place at which the Big Bang happened since the cosmos at time of the Big Bang is thought to have been infinitely tiny and dense.
The Big Bang, according to this theory, was not an explosion that occurred at a single site but rather the abrupt expansion of the cosmos from a very tiny and dense state. The idea holds that the whole universe including space itself was a point.
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A resultant force of 25 newtons acts on a mass of 0.50 kilograms starting from rest. Find the acceleration in m/s2 .
Answer:
\(50\:$\mathrm{m/s^2}\)
Explanation:
From Newton's Second Law, recall \(F=ma\).
Rearranging this equation, we have \(a=\frac{F}{m}\). \(F\) is given as \(25\:\mathrm{N}\) and mass given as \(0.5\:\mathrm{kg}\).
Plugging in these values, we get:
\(a=\frac{25}{0.5}=\fbox{$50\:\mathrm{m/s^2}$}\).
The rate change of direction or speed of the object is called acceleration. The acceleration of the given mass is 50 m/s².
Acceleration:
It is the rate change of direction or speed of the object. From the Newton's second law of motion,
\(\bold {a = \dfrac Fm}\)
Where,
F - force applied = 25 N
m - mass = 0.5 kg
Put the values,
\(\bold {a = \dfrac {25}{0.5}}\\\\\bold {a = 50\ m/s^2}\)
Therefore, the acceleration of the given mass is 50 m/s².
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Light of wavelength λ = 630 nm and intensity i0 = 250 w/m2 passes through a slit of width w = 3.6 μm before hitting a screen l = 1.7 meters away. Use the small angle approximation to write an equation for the phase difference, β, between rays that pass through the very top and very bottom of the slit when the rays hit a point y - 79 mm above the central maximunm.
This expression will give us the phase difference, β, in radians. λ = 630 nm = 630 x 10^-9 m, w = 3.6 μm = 3.6 x 10^-6 m, y = -79 mm = -79 x 10^-3 m, l = 1.7 m, β = (2π / (630 x 10^-9 m)) * (3.6 x 10^-6 m) * (-79 x 10^-3 m) / (1.7 m)
To calculate the phase difference, β, between rays passing through the top and bottom of the slit, we can use the small angle approximation and consider the geometry of the setup.
Let's assume that the central maximum of the diffraction pattern falls at y = 0 on the screen. We are interested in calculating the phase difference at a point y = -79 mm above the central maximum.
Using the small angle approximation, we can assume that the angle θ formed by the rays passing through the top and bottom of the slit is small. This allows us to use the approximation sin(θ) ≈ θ.
The phase difference between the two rays is given by:
β = (2π / λ) * w * sin(θ)
In our case, sin(θ) ≈ θ, and we can express θ in terms of y, l, and the distance from the central maximum to the point of interest:
θ = y / l
Substituting this into the equation for β, we have:
β = (2π / λ) * w * (y / l)
Now we can plug in the given values:
λ = 630 nm = 630 x 10^-9 m
w = 3.6 μm = 3.6 x 10^-6 m
y = -79 mm = -79 x 10^-3 m
l = 1.7 m
β = (2π / (630 x 10^-9 m)) * (3.6 x 10^-6 m) * (-79 x 10^-3 m) / (1.7 m)
Evaluating this expression will give us the phase difference, β, in radians.
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Bone has a Young's modulus of about 1.8 x 1010 Pa. Under compression, it can withstand a stress of about 1.51 × 108 Pa before breaking. Assume that a femur (thigh bone) is 0.5 m long, and calculate the amount of compression this bone can withstand before breaking. Answer in units of mm.
The femur can withstand a compression of about 4.1945 mm before breaking.
Compression calculations explained.We can use the formula for compressive stress to calculate the amount of compression that the femur bone can withstand before breaking:
Stress = Force / Area
where the force is the force applied to the bone and the area is the cross-sectional area of the bone.
To find the cross-sectional area of the femur bone, we can assume that it has a circular cross-section and use the formula:
Area = πr^2
where r is the radius of the cross-section.
Since the length of the femur bone is 0.5 m, we can assume that the cross-sectional area remains constant along its length.
Let's assume that the force required to break the bone is the maximum compressive stress that it can withstand, which is 1.51 × 10^8 Pa. We can rearrange the stress formula to solve for the force.
We can use the equation for strain under compression:
strain = stress / Young's modulus
where stress is the maximum stress the bone can withstand before breaking, and Young's modulus is a measure of the stiffness of the material. The strain is a measure of how much the bone compresses under stress.
To find the compression distance, we can rearrange this equation to solve for the compression distance:
compression distance = strain x original length
where the original length is the length of the bone before compression
Substituting the given values:
stress = 1.51 × 10^8 Pa
Young's modulus = 1.8 × 10^10 Pa
original length = 0.5 m
First, we can calculate the strain:
strain = stress / Young's modulus = (1.51 × 10^8 Pa) / (1.8 × 10^10 Pa) ≈ 0.008389
Next, we can calculate the compression distance:
compression distance = strain x original length = (0.008389) x (0.5 m) = 0.0041945 m
Finally, we can convert the result to millimeters:
compression distance = 0.0041945 m x (1000 mm/m) = 4.1945 mm
Therefore, the femur can withstand a compression of about 4.1945 mm before breaking using Stress = Force / Area
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The greatest hurdle that must be overcome to fully embrace nuclear power to generate electricity is
A) safe storage of radioactive waste.
B) monitoring low-level radiation continuously being released into the surrounding region.
C) filtering the release of CO2 contributing to greenhouse gasses.
D) deactivating radioactive water flushed from cooling towers.
E) increased safety measures to decrease the potential for nuclear explosion releasing radiation into the atmosphere.
The most significant barrier to fully embracing nuclear technology to produce energy is the safe storage of radioactive waste.
Nuclear power is the only large-scale energy-producing technology that completely accepts responsibility for all waste and prices it into the product. Nuclear power generates extremely less waste in comparison to other thermal energy-producing sources. Used nuclear fuel may be used as either a resource or as waste. Nuclear waste is not exceptionally dangerous nor difficult to control in comparison to other toxic industrial waste. Technically established safe techniques for the ultimate disposal of high-level radioactive waste exist; the worldwide agreement is that geological disposal is the best choice.
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A car was moving a 14 m/s. After 30 seconds, it’s speed increased to 20 m/s. What was its acceleration during this time?
Answer:
acceleration = 0.2 m/s/s
Explanation:
initial velocity u = 14
final velocity v = 20
time = 30
acceleration = ?
v = u + at
20 = 14 + 30a
30a = 6
a = 0.2 m/s/s
Answer:
For the aceleration we have:
V = Vi + a * t
Being:
V = 20 m/s
Vi = 14 m/s
a = ?
t = 30 s
Then, lets replace acording the formula:
20 m/s = 14 m/s + a * 30 s
Clear "a":
a = (20 m/s - 14 m/s) / 30 s
a = (6 m/s) / 30 s
a = 0,2 m/s²
The aceleration of the car is 0,2 meters per second squared.
What does Newton's law all about?
What is the position and kind of image produced by the lens below?
Complete the ray diagram to support your answer.
A horse is riding 9m/s. In two seconds it slows down to 1m/s, what is the acceleration of the horse.
Answer:
-4m/s²
Explanation:
Given parameters:
Initial velocity = 9m/s
Final velocity = 1m/s
Time taken = 2s
Unknown:
Acceleration = ?
Solution:
The acceleration of a body is the change in velocity of a body with time.
Acceleration = \(\frac{Final velocity - Initial velocity }{time}\)
Insert the parameters and solve;
Acceleration = \(\frac{1 - 9}{2}\) = -4m/s²
We can say, the car is decelerating at a rate of 4m/s²
If we attach one end of an iron nail to the south pole of a bar magnet, the other free end of the nail would behave as.
A. north pole
B. south pole
C. non-magnet
If we attach one end of an iron nail to the south pole of a bar magnet, the other free end of the nail would behave as a north pole.So option A is correct.
When a ferromagnetic material, such as iron, is brought in close proximity to a magnet, it becomes magnetized by induction. In this scenario, the south pole of the bar magnet attracts the iron atoms in the nail and aligns them in a way that the end of the nail closest to the south pole of the magnet becomes a north pole.
This effect is due to the rearrangement of the magnetic domains within the iron nail. The domains align in such a way that the end of the nail opposite to the magnet's south pole acquires a north magnetic polarity.
Therefore option A is correct.
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Can you please help me on all of these!!!! Please
Answer:
differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.
Explanation:
This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.
If a car has a velocity of 8 m/s and travels for 60 seconds, what was the displacement of the car?
Answer:
68
Explanation:
now it
A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?
Answer:
15m/s²
Explanation:
Given parameters:
Initial velocity = 10m/s
Final velocity = 40m/s
Time taken = 2s
Unknown:
Average acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time;
Acceleration = \(\frac{Final velocity - Initial velocity }{time}\)
Acceleration = \(\frac{40 - 10}{2}\) = 15m/s²
Prompt. Explain the difference between a solar eclipse and a lunar eclipse. Be sure to explain the positions of the earth moon and sun for each scenario
Answer:
Explanation:
Eclipse happens when a large object gets in the way of another object; casting its shadow over it.
Solar eclipse happens when the moon get in between the sun and earth. It blocks sun light and causes its shadow over the sun as seen from earth.
Lunar eclipse happens when the earth is in between the sun and moon. It blocks sun light from reflecting off the moon surface so there is a shadow on the moon as seen from earth.
Lee pushes horizontally with a force of 78N on a 29kg mass for 16m across a floor.
Calculate the amount of work Lee did. Answer in units of J.
If Lee pushes horizontally with a force of 78N on a 29kg mass for 16m across a floor. The amount of work Lee did is: 1,248J.
How to find the work done?Given data:
Mass of the object , m = 29kg
Force, F = 78N
Displacement, d = 16m
Now let find the amount of work using this formula
Work = F × dcosθ
Let plug in the formula
Work = 78 × 16cosθ
Work = 1,248J
Therefore we can conclude that the work done is 1,248J.
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Before going in for an annual physical, a 70.0-{\rm kg} person whose body temperature is 37.0{\rm ^{\circ} C} consumes an entire 0.355-{\rm liter} can of a soft drink (which is mostly water) at12.0{\rm ^{\circ} C}.
A.)What will be the person's body temperature T_final after equilibrium is attained? Ignore any heating by theperson's metabolism. The specific heat capacity of a human body is3480 {\rm J/kg \cdot K} .
B.)Is the change in the person's body temperature great enoughto be measured by a medical thermometer? (A high-quality medicalthermometer can measure temperature changes as small as0.1{\rm ^{\circ}C} or less.) yes or no
Answer:
A) The person's body temperature T_final after equilibrium is attained = 36.85°C
B) The change in the person's temperature after equilibrium is attained = 0.15°C
A high-quality medical thermometer can measure temperature changes as small as 0.1°C, hence, YES, it would detect the minute drop by 0.15°C too.
Explanation:
If we assume that the soft drink has the same density as water (since it is stated in the question that it is mostly water).
Density of water = 1 g/mL = 1 kg/L
Ignoring any heating by the person's metabolism,
A) So, heat lost by the human body = heat gained by the soft drink as it attains thermal equilibrium with the human body
Let the final temperature of the human body + soft drink set up be T
Heat lost by the human body = mCΔT
m = mass of the human body = 70.0 kg
C = Specific heat capacity of the human body = 3480 J/kg.K
ΔT = Temperature change of the human body = 37 - (Final temperature) = 37 - T
Heat lost by the body = 70 × 3480 × (37 - T)
= (9,013,200 - 243,600T) J
Heat gained by soft drink = mCΔT
m = mass of the soft drink = density × volume = 1 × 0.355 = 0.355 kg
C = specific heat capacity of the soft drink = specific heat capacity of the soft drink = 4182 J/kg.K
ΔT = (final temperature) - 12 = (T - 12)
Heat gained by the soft drink = 0.355 × 4182 × (T - 12) = (1,484.61T - 17,815.32) J
heat lost by the human body = heat gained by the soft drink as it attains thermal equilibrium with the human body
(9,013,200 - 243,600T) = (1,484.61T - 17,815.32)
9,013,200 + 17,815.32 = 1,484.61T + 243,600T
9,031,015.32 = 245,084.61T
T = (9,031,015.32/245,084.61)
= 36.8485614825 = 36.85°C
B) The change in the person's temperature = 37 - 36.85 = 0.15°C
A high-quality medical thermometer can measure temperature changes as small as 0.1°C, hence it would detect the minute drop by 0.15°C too.
Hope this Helps!!!
The equilibrium temperature is required and to find whether the temperature change can be measured by a thermometer is required.
The temperature is 310 K.
Yes, the thermometer can measure the temperature difference.
\(m_1\) = Mass of person = 70 kg
\(c_1\) = Specific heat of person = 3480 J/kg K
T = Equilibrium temperature
\(T_1\) = Temperature of person = \(37\ ^{\circ}\text{C}+273.15 =310.15\ \text{K}\)
\(1\ \text{L}=1\ \text{kg}\) of water
\(m_2\) = Mass of water = \(0.355\ \text{kg}\)
\(c_2\) = Specific heat of soft drink mostly water = \(4186\ \text{J/kg K}\)
\(T_2\) = Temperature of soft drink = \(12\ ^{\circ}\text{C}=285.15\ \text{K}\)
The heat equation is
\(m_1c_1(T-T_1)=m_2c_2(T_2-T)\\\Rightarrow m_1c_1T-m_1c_1T_1=m_2c_2T_2-m_2c_2T\\\Rightarrow T=\dfrac{m_2c_2T_2+m_1c_1T_1}{m_1c_1+m_2c_2}\\\Rightarrow T=\dfrac{0.355\times 4186\times 285.15+70\times 3480\times 310.15}{70\times 3480+0.355\times 4186}\\\Rightarrow T=310\ \text{K}\)
The temperature difference is \(T_1-T=310.15-310=0.15\ \text{K}=0.15\ ^{\circ}\text{C}\)
Yes, the thermometer can measure the temperature difference.
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T-Chart In the left column, describe ways you can observe gravity in action in the natural world. In the right column, describe what you might see if gravity suddenly disappeared.
Mention two factors on which the internal resistance of a cell depends.
Answer:
Explanation:
(1) The surface area of the electrodes: Larger the surface area of the electrodes, less is the internal resistance.
(2) The distance between the electrodes: As the distance between the electrodes increases, the internal resistance of cell also increases.
The formula is given by
\(\\ \rm\Rrightarrow R=\rho\dfrac{\ell}{A}\)
rho is resistivityl is length of cellA is surface area.On these three factors resistance depends
also
According to ohms law
V/I=RResistance also depends on voltage and current
Czerski uses a variety of common household items to explain various ideas and concepts in physics. Do the same thing, however, use common forensic practices or scenarios to describe some of the same ideas and concepts.
Czerski made a significant contribution with his experiment in physics that employs the equation of angular momentum conservation to explain it. The field of forensic sciences also greatly benefits from the study of physics.
All facets of our life are significantly impacted by the science of physics. There are several instruments that use physics as their operating system. Additionally, a number of healthcare devices are constructed utilizing physics.
In forensic science, reconstruction of crime scenes is a crucial application of physics that helps us ascertain if a case was the product of an accident or another crime.
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when a rifle fires at a distant target, where should the barrel be pointing?
When a rifle fires at a distant target, the barrel should be pointing straight towards the target.
This is because the barrel is the part of the rifle that the bullet travels through to reach the target. If the barrel is not pointing directly at the target, the bullet may not hit it.
Therefore, it is important to aim the barrel accurately when shooting a rifle at a distant target.
A rifle is a long gun designed to be fired from the shoulder, with a barrel that has spiral grooves (rifling) cut into the inside of the barrel wall that forces the bullet to rotate as it moves out of the barrel.
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The bearing of grids of an AB alignment is 100º 22', while the magnetic declination is 8º30' E. What are the true azimuth, magnetic azimuth, and grid azimuth of this alignment?
The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).
To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.
To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).
The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).
The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).
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