Answer:
its b
Step-by-step explanation:
trust mee
A beach has two floating docks. One is 650 meters east of the lifeguard stand. The other is 60° southeast and 750 meters from the lifeguard stand. Law of cosines: A triangle is created between a lifeguard stand and 2 floating docks. The distance from the lifeguard stand to one dock is 750 meters, and the distance to the second dock is 650 meters. The angle between the 2 sides is 60 degrees. Rounded to the nearest meter, what is the distance between the docks? Round to the nearest meter. 589 meters 705 meters 792 meters 861 meters
Answer:
705 meters
Step-by-step explanation:
\(cos~60=\frac{650^2+750^2-d^2}{2 \times 650 \times 750} \\2 \times 650 \times 750 \times \frac{1}{2}=50^2(13^2+15^2)-d^2 \\487500=2500(169+225)-d^2\\487500=2500(394)-d^2\\487500=985000-d^2\\487500-985000=-d^2\\d^2=497500\\d=\sqrt{497500}\\or~d\approx705.337 \approx 705~meters\)
Answer:
7 0 5 M E T E R S !!!!!
Step-by-step explanation:
Find the slope plzzzzzzzzzzzzzzzzzzzzz
Answer:
-3/5
Step-by-step explanation:
Go down 3 and over 5
1. A tennis ball is hit from a height of 1.1 m above the ground. The function h(d) = -0.12d² +0.22d+
1.1 models the path of the tennis ball, where d is the horizontal distance, in metres, and h(d) is the height,
in metres.
How far has the tennis ball travelled horizontally, to the nearest tenth of a metre, when it lands on the
ground? [A5]
The tennis ball has traveled a horizontal distance of 3.717 m, to the nearest tenth of a metre, when it lands on the ground. Hence, the correct option is (A) 3.7.
The given function is h(d) = -0.12d² +0.22d+1.1.
It models the path of a tennis ball hit from a height of 1.1 m above the ground.
Here, d represents the horizontal distance in meters, and h(d) represents the height in meters.
To find how far the tennis ball travelled horizontally when it lands on the ground, we need to find the value of d when h(d) = 0, because the ball will hit the ground when its height is zero.
Substituting h(d) = 0 in the given function, we get:
0 = -0.12d² +0.22d+1.1
Simplifying, we get: 0.12d² - 0.22d - 1.1 = 0
We can solve this quadratic equation using the quadratic formula, which is given by:
-b ± sqrt(b² - 4ac) / 2a, where a, b, and c are the coefficients of the quadratic equation.
Here, a = 0.12, b = -0.22, and c = -1.1.
Substituting the values, we get:
d = [0.22 ± sqrt(0.22² - 4(0.12)(-1.1))] / 2(0.12)
Simplifying,
We get:
d = [0.22 ± sqrt(0.5964 + 0.528)] / 0.24d
= [0.22 ± sqrt(1.1244)] / 0.24d
= [0.22 ± 1.0604] / 0.24
We get two values of d as follows:d = 3.717 m, -1.598 m
Since the ball cannot travel a negative distance, the only possible solution is d = 3.717 m.
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Figure 12.6 England's and Portugal's trading posibilitoes lines. If Portugal sends out 30 units of wine, it will get back ________ units of cloth.
England's and Portugal's trading possibilities lines, it is not possible to determine the exact number of units of cloth that Portugal would get back when sending out 30 units of wine.
The trading possibilities lines represent the trade-offs between different goods in a given economy and provide information about the exchange ratios between those goods.
Without the specific data from the figure, it is not possible to calculate the exact exchange ratio or determine the number of units of cloth Portugal would receive in return for 30 units of wine.
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Please help ………………… Me
Answer:
The answer is the second answer.
Step-by-step explanation:
FG:
\(\frac{4}{5}\) = \(\frac{12}{x}\) Since I have to multiply 3 x4 to get 12, I will multiply 5 by 3 to get 15
GH:
\(\frac{4}{5}\) = \(\frac{16}{x}\) Since I have to multiply 4 by 4 to get 16, I will multiply 5 by 4 to get 20.
HF:
\(\frac{4}{5}\) = \(\frac{8}{x}\) Since I have to multiply 4 by 2 to get 8, I will multiply 5 by 2 to get 10
What is the weight of an object that has a mass of 60 slugs
The formula is weight of object = mass x gravity
if you punch the numbers in the formula correctly the mass in kg is 875.634 kg x 9.8 m/s = 8,581.2132
At one of George Washington's parties, each man shook hands with everyone except his spouse, and no handshakes took place between women. If $13$ married couples attended, how many handshakes were there among these $26$ people
In this scenario, each man shakes hands with all the other men (excluding himself) and with all the women (excluding his spouse). Therefore, each man shakes hands with \($25$\) people in total.
Since there are \($13$\) married couples, there are \($13$\) men and \($13$\) women. Hence, the total number of handshakes involving men is \($13 \times 25 = 325$\).
As for the women, they do not shake hands with each other, so we only need to consider the handshakes involving men. Therefore, the total number of handshakes among these \($26$\) people is \($325$\).
If you would like to represent this solution using LaTeX code, you can use the following snippet:
\(\text{Number of handshakes involving men} \\\\= \text{Number of men} \times \text{Number of handshakes per man} \\\\= 13 \times 25 = 325\)
Therefore, the total number of handshakes among the \($26$\) people is \($325$\).
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the sum of 10 and 15 divide by the difference 8 and 3 how to translate
We have the following:
\(\frac{10-5}{8-3}=\frac{5}{5}=1\)Lilia wants to rewrite 10/25 as a percent she decided to represent 10/25 first in a picture a.)how many sets of 25 will she need to make 100 how many sets of shaded squares will she need how many shaded squares is that in total
Answer:
4 sets of 25
Step-by-step explanation:
100/25 = 4
Not sure what you are asking in the end.
I need an answer immediately!!!!!!!
Answer:
y = 3x - 8
Step-by-step explanation:
_______________
A two digit number is 11 times its units digit. The sum of the digits is 12. Find the number
According to the given condition the two-digit number is 66.
To find the two-digit number that is 11 times its units digit and has a sum of digits equal to 12, we can use the following steps:
1. Let's represent the two-digit number as XY, where X is the tens digit and Y is the units digit.
2. The number is 11 times its units digit, so we can write the equation: 10X + Y = 11Y.
3. The sum of the digits is 12, which means X + Y = 12.
4. Now, we have two equations with two variables:
- 10X + Y = 11Y
- X + Y = 12
5. We can solve for X from the second equation: X = 12 - Y.
6. Substitute the value of X in the first equation: 10(12 - Y) + Y = 11Y.
7. Simplify and solve for Y: 120 - 10Y + Y = 11Y.
8. Combine the Y terms: 120 - 9Y = 11Y.
9. Move all the Y terms to one side: 120 = 20Y.
10. Divide by 20 to get Y: Y = 6.
11. Now, substitute the value of Y back into the X equation: X = 12 - 6.
12. Solve for X: X = 6.
So, the two-digit number is 66.
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I need help with this
SOLUTION
In this question, we are going to solve each expression one after the other, and after we arrive at the solution, we will compare it to A, B, and C to see which matches. That will be the correct option to choose.
First expression calculation:
\(\begin{gathered} (3x^2-6x+11)-(10x^2-4x+6) \\ 3x^2-6x+11-10x^2+4x-6 \\ \end{gathered}\)Collect like terms:
\(\begin{gathered} 3x^2-10x^2-6x+4x+11-6 \\ -7x^2-2x+5 \end{gathered}\)The first expression is equivalent to the expression A
Second expression calculation:
\(\begin{gathered} (-3x^2-5x-3)-(-10x^2-7x+2) \\ -3x^2-5x-3+10x^2+7x-2 \\ C\text{ollect like terms} \end{gathered}\)\(\begin{gathered} -3x^2+10x^2-5x+7x-3-2 \\ 7x^2+2x-5 \end{gathered}\)The second expression is equivalent to the expression C
Third expression calculation:
\(\begin{gathered} (12x^2+6x-5)-(5x^2+8x-12)_{} \\ 12x^2-5x^2+6x-8x-5+12 \\ 7x^2-2x+7 \end{gathered}\)The third expression is equivalent to the expression B
A triangle has sides with lengths of 8 meters, 17 meters, and 20 meters. Is it a right triangle
Yes
No
Maybe
Answer:
yes coz in a right angled triangle all the sides are never equal
Step-by-step explanation:
yes coz in a right angled triangle all the sides are never equal
Answer:
No, they do not make a right triangle.
Step-by-step explanation:
Use the Pythagorean Theorem to see if the sides form a right triangle.
\(a^2+b^2=c^2\)
'20' will be 'c'. It is the largest number in the sides given.
'8' will be 'a' and 17 will be 'b'.
\(8^2+17^2=20^2\\\rightarrow 8^2=64\\\rightarrow 17^2 = 289\\\rightarrow 20^2=400\\64+289=400\\\boxed{353\neq 400}\)
The sides do not make a right triangle. They do not satisfy the theorem.
Karly owns a lawn service. During the month
of May she averaged 47 customers the first week, 38
the second week, 55 the third week, and 60 the fourth
week. How many customers did she average per week?
There are 50 customers per week.
Since average can be calculated by dividing the sum of observations by the number of observations.
Average = Sum of observations/the number of observations
We are given that During the month of May she averaged 47 customers the first week, 38 the second week, 55 the third week, and 60 the fourth
week.
therefore, consider that w represent the number of customers in the 1st week, x represent the number of customers in the 2nd week, y represent the number of customers in the 3rd week and z represent the number of customers in the 4th week.
Then the average would be;
w + x + y + z= 4A
47 + 38 + 55 + 60 = 4A
A = 200/4
A = 50
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Consider the following model : Y = Xt + Zt, where {Zt} ~ WN(0, σ^2) and {Xt} is a random process AR(1) with [∅] < 1. This means that {Xt} is stationary such that Xt = ∅ Xt-1 + Et,
where {et} ~ WN(0,σ^2), and E[et+ Xs] = 0) for s < t. We also assume that E[es Zt] = 0 = E[Xs, Zt] for s and all t. (a) Show that the process {Y{} is stationary and calculate its autocovariance function and its autocorrelation function. (b) Consider {Ut} such as Ut = Yt - ∅Yt-1 Prove that yu(h) = 0, if |h| > 1.
(a) The process {Yₜ} is stationary with autocovariance function Cov(Yₜ, Yₜ₊ₕ) = ∅ʰ * σₓ² + σz² and autocorrelation function ρₕ = (∅ʰ * σₓ² + σz²) / (σₓ² + σz²).
(b) The autocovariance function yu(h) = 0 for |h| > 1 when |∅| < 1.
(a) To show that the process {Yₜ} is stationary, we need to demonstrate that its mean and autocovariance function are time-invariant.
Mean:
E[Yₜ] = E[Xₜ + Zₜ] = E[Xₜ] + E[Zₜ] = 0 + 0 = 0, which is constant for all t.
Autocovariance function:
Cov(Yₜ, Yₜ₊ₕ) = Cov(Xₜ + Zₜ, Xₜ₊ₕ + Zₜ₊ₕ)
= Cov(Xₜ, Xₜ₊ₕ) + Cov(Xₜ, Zₜ₊ₕ) + Cov(Zₜ, Xₜ₊ₕ) + Cov(Zₜ, Zₜ₊ₕ)
Since {Xₜ} is an AR(1) process, we have Cov(Xₜ, Xₜ₊ₕ) = ∅ʰ * Var(Xₜ) for h ≥ 0. Since {Xₜ} is stationary, Var(Xₜ) is constant, denoted as σₓ².
Cov(Zₜ, Zₜ₊ₕ) = Var(Zₜ) * δₕ,₀, where δₕ,₀ is the Kronecker delta function.
Cov(Xₜ, Zₜ₊ₕ) = E[Xₜ * Zₜ₊ₕ] = E[∅ * Xₜ₋₁ * Zₜ₊ₕ] + E[Eₜ * Zₜ₊ₕ] = ∅ * Cov(Xₜ₋₁, Zₜ₊ₕ) + Eₜ * Cov(Zₜ₊ₕ) = 0, as Cov(Xₜ₋₁, Zₜ₊ₕ) = 0 (from the assumptions).
Similarly, Cov(Zₜ, Xₜ₊ₕ) = 0.
Thus, we have:
Cov(Yₜ, Yₜ₊ₕ) = ∅ʰ * σₓ² + σz² * δₕ,₀,
where σz² is the variance of the white noise process {Zₜ}.
The autocorrelation function (ACF) is defined as the normalized autocovariance function:
ρₕ = Cov(Yₜ, Yₜ₊ₕ) / sqrt(Var(Yₜ) * Var(Yₜ₊ₕ))
Since Var(Yₜ) = Cov(Yₜ, Yₜ) = ∅⁰ * σₓ² + σz² = σₓ² + σz² and Var(Yₜ₊ₕ) = σₓ² + σz²,
ρₕ = (∅ʰ * σₓ² + σz²) / (σₓ² + σz²)
(b) Consider the process {Uₜ} = Yₜ - ∅Yₜ₋₁. We want to prove that the autocovariance function yu(h) = 0 for |h| > 1.
The autocovariance function yu(h) is given by:
yu(h) = Cov(Uₜ, Uₜ₊ₕ)
Substituting Uₜ = Yₜ - ∅Yₜ₋₁, we have:
yu(h) = Cov(Yₜ - ∅Yₜ₋₁, Yₜ₊ₕ - ∅Yₜ₊ₕ₋₁)
Expanding the covariance, we get:
yu(h) = Cov(Yₜ, Yₜ₊ₕ) - ∅Cov(Yₜ, Yₜ₊ₕ₋₁) - ∅Cov(Yₜ₋₁, Yₜ₊ₕ) + ∅²Cov(Yₜ₋₁, Yₜ₊ₕ₋₁)
From part (a), we know that Cov(Yₜ, Yₜ₊ₕ) = ∅ʰ * σₓ² + σz².
Plugging in these values and simplifying, we have:
yu(h) = ∅ʰ * σₓ² + σz² - ∅(∅ʰ⁻¹ * σₓ² + σz²) - ∅(∅ʰ⁻¹ * σₓ² + σz²) + ∅²(∅ʰ⁻¹ * σₓ² + σz²)
Simplifying further, we get:
yu(h) = (1 - ∅)(∅ʰ⁻¹ * σₓ² + σz²) - ∅ʰ * σₓ²
If |∅| < 1, then as h approaches infinity, ∅ʰ⁻¹ * σₓ² approaches 0, and thus yu(h) approaches 0. Therefore, yu(h) = 0 for |h| > 1 when |∅| < 1.
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Kiara baked 52 cookies with 4 scoops of flour. With 9 scoops of flour, how many cookies can Kiara bake? Assume the relationship is directly proportional.
Answer:
117 cookies
Step-by-step explanation:
52 ÷ 4 = 13
1 scoop of flour = 13 cookies
13 × 9 = 117
9 scoops of flour = 117 cookies
Answer:
117 cookies
Step-by-step explanation:
Using a ratio
52 cookies x cookies
-------------- = --------------
4 scoops 9 scoops
Using cross products
52*9 = 4x
Divide each side by 4
52*9/4 =x
117 cookies
Tank B, which initially contained 80 liters of water, is being drained at a rate of 2.5 liters per minute. How many liters of water remain in the tank after 30 seconds?
Answer:
78.75 ?
Step-by-step explanation:
calculator..
The volume of water remain in the tank after 30 seconds is 78.75 liters.
The given parameters;
initial volume of water in Tank B, V₀ = 80 litersrate at which water is being drained, R = 2.5 liters per minute.time of water drain, t = 30 secondsThe amount of water drained after 30 seconds is calculated as follows;
\(V_1 =2.5 \ \frac{liters}{\min} \times \frac{1 \min}{60 \ s} \times 30 \ s\\\\V_1 = 1.25 \ liters\)
The volume of water remain in the tank after 30 seconds is calculated as follows;
V₂ = V₀ - V₁
V₂ = 80 liters - 1.25 liters
V₂ = 78.75 liters
Thus, the volume of water remain in the tank after 30 seconds is 78.75 liters.
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Find out which operation must be done on both sides of these equations in order to solve them. 1 ) x + 9 = 11
2) x - 4 = 9
3) 8 x = 24
4) x / 6 = 3
Operations that must be done on both sides of the equation are:
SubtractionAdditionDivision MultiplicationMathematical Operations-Mathematical operations are the actions that can be performed on numbers or variables. Some common mathematical operations include addition, subtraction, multiplication, division, and exponentiation. These operations are often represented using symbols such as +, -, *, /, and ^. Other mathematical operations include roots, logarithms, trigonometric functions, and more. These operations can be used to solve a wide range of problems in mathematics, science, engineering, and other fields.
Now according to the question,
1. In order to solve the equation x + 9 = 11, we must subtract 9 from both sides,
⇒ x + 9 - 9 = 11 - 9
⇒ resulting in x = 2.
2. To solve the equation x - 4 = 9, we must add 4 to both sides,
⇒ x - 4 + 4 = 9 + 4
⇒ resulting in x = 13.
3. To solve the equation 8x = 24, we must divide both sides by 8,
⇒ 8x / 8 = 24 / 4
⇒ resulting in x = 3.
4. To solve the equation x / 6 = 3, we must multiply both sides by 6,
⇒ x/6 * 6 = 3 * 6
⇒ resulting in x = 18.
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Mrs.Smith stacked 6 cubes on top of one another to make a tower. If the tower is sitting on the floor, how manyof the cubes faces can Mrs.Smith see?
Answer: 25 faces
Step-by-step explanation:
Given
6 cubes are stacked over each other
Mr. Smith wants to count the number of faces
The faces which are in contact with each other are not visible to Mr. smith i.e. there will be 5 cubes with only 4 faces available and only one cube with 5 faces available, that is placed on the top.
No of visible faces
\(\Rightarrow 4\times 6+1\quad \quad [\text{6 cubes with 4 faces visible+face of top cube}]\\\Rightarrow 25\ \text{faces}\)
Anyone know this? Ill give brainliest if right pls help ^^!!!
Select the correct answer.
What are the roots of 12x = 9 + 5x2?
Answer:
12x=9+5x^{2}
12x=9+5x2
Step-by-step explanation:
is dz = 2x2y3dx 3x3y2dy an exact or inexact differential?
The differential dz = 2x2y3dx + 3x3y2dy is an inexact differential.
To determine if a differential is exact or inexact, we need to compare the partial derivatives of the two terms. If the partial derivative of the first term with respect to y is equal to the partial derivative of the second term with respect to x, then the differential is exact.
For the first term, the partial derivative with respect to y is:
∂(2x2y3)/∂y = 6x2y2
For the second term, the partial derivative with respect to x is:
∂(3x3y2)/∂x = 9x2y2
Since these two partial derivatives are not equal, the differential is inexact.
Therefore, the differential dz = 2x2y3dx + 3x3y2dy is an inexact differential.
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How do I graph y=3sin(x+pi/3)-2 and what are the amplitude, asymptotes/ phase shift and critical points and period
Step-by-step explanation:
amplitude is 3. so the sin will start at zero and go up to 3 and down to -3. asymptote are at 3 and -3
it's period didn't change it's 2π
it's phase shifted horizontally π/3 to the left
it's phase shifted vertically 2 units down
(5 ^ 11)/(5 ^ ?) = 5 ^ 4
Answer:
200
Step-by-step explanation:
55 / 5x = 20
5x=1100
x=200
what is the answer is what =
Answer: 6
Step-by-step explanation:
14-8=6
Answer:
the answer is 6 since it says fewer we'll be using subtraction or the minus sign so 14-8=6
Solve |y-2|<10
please
Wouldnt the answer be anything above 12? Because if Y is unknown, and you're taking 2 away from it, and it still has to be greater than 10, then it should be anything above 12. Unless it's saying that the number is greater than 10, and you are just taking away 2 from a number and it doesn't have to be greater than 10.
describe these uses for the const keyword const distance d( 1, 2.2 )
The main use of the `const` keyword in the given code snippet is to declare a constant object named `d` of the class `distance`. This means that the object `d` cannot be modified once it is initialized.
In C++, the `const` keyword is used to define constants or variables that cannot be modified. When applied to an object, it ensures that the object's state remains constant and cannot be changed. In the context of the code snippet, the object `d` is declared as a constant object of the class `distance` with initial values of 1 and 2.2 for its member variables.
By declaring `d` as a constant object, the code expresses the intention to prevent any modifications to its values throughout the program execution. This can be useful in scenarios where the object represents a fixed measurement or a constant value that should not be altered accidentally or intentionally.
The `const` keyword provides benefits such as code clarity, as it clearly indicates the immutability of the object, preventing accidental modifications. It also helps enforce good programming practices by ensuring that the object's state remains constant, reducing potential bugs or unintended side effects.
Additionally, using the `const` keyword enables the compiler to perform optimizations, as it knows that the object's state won't change, allowing for potential code optimizations and improved performance.
Overall, the `const` keyword is used to declare constant objects, providing immutability and promoting code clarity and optimization.
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what is the standard error of the number (same as sum) of evens you'd get in 36 draws? (hint: use the sd you've already calculate) submit answer incorrect. tries 3/5 previous tries what is the expected value of the average of the 36 draws from the 0-1 box in question 1? (hint: this is just the average of the box) submit answer incorrect. tries 1/5 previous tries what is the standard error of the average of the 36 draws from the 0-1 box in question 1? (you already computed the sd.) round answer to three decimal places.
The answer to the standard error of the average, rounded to three decimal places, will be provided. The expected value of each draw will be the average of these values, which is (0 + 1) / 2 = 0.5.
The standard error of the number (or sum) of evens in 36 draws is not provided, and it seems there was an error in calculating the expected value of the average of the draws. However, we can calculate the standard error of the average based on the previously computed standard deviation.
To calculate the standard error of the number (or sum) of evens in 36 draws, we need additional information that is not provided. Without the data or probabilities associated with the draws, we cannot determine the standard error for this specific question.
Regarding the expected value of the average of the 36 draws from the 0-1 box in question 1, it appears there was an error in calculating the expected value in the previous tries. However, given that the box contains values ranging from 0 to 1, the expected value of each draw will be the average of these values, which is (0 + 1) / 2 = 0.5.
To compute the standard error of the average, we can divide the standard deviation (already computed) by the square root of the number of draws. Since the standard deviation has been previously calculated but is not provided, we cannot give an exact value. However, if you have the standard deviation, you can compute the standard error by dividing it by the square root of 36, which is 6. The standard error is a measure of how much the sample means are expected to vary from the population mean, and it helps assess the precision of the sample estimate. By rounding the result to three decimal places, you can obtain the desired value.
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perform the indicated operation and simplify. assume that all variables result in nonzero denominators.
The answer for the given question i.e. \(\frac{6x}{x-5} -\frac{30}{x-5}\) by simplification is 6
Given that a equation \(\frac{6x}{x-5} -\frac{30}{x-5}\) and asked to simplify it by asuming that all variables result in non zero denominator.
simplify:
simplify implies to simplify something. In mathematics, simplifying an equation, fraction, or problem means taking it and making it simpler. It simplifies the issue through mathematics and problem-solving
Given \(\frac{6x}{x-5} -\frac{30}{x-5}\)
\(\frac{6x}{x-5} -\frac{30}{x-5}\)=\(\frac{6x-30}{x-5}\)
=\(6(\frac{x-5}{x-5})\)
=6
The value of given question i.e. \(\frac{6x}{x-5} -\frac{30}{x-5}\) is 6
Complete question:
Perform the indicated operation and simplify asumes that all variables result in non zero denominators \(\frac{6x}{x-5} -\frac{30}{x-5}\)
The answer for the given question i.e. \(\frac{6x}{x-5} -\frac{30}{x-5}\) by simplification is 6
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please help me!! 8th grade math, Pythagorean Theorem 19 pts!
Answer:
do 70 divded by two and that is 35. and then 15^2 (squared) + 35^2 (squared) and then whatever that equals but the square root around it and that is your answer.
Step-by-step explanation: