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Related Questions
A pickup truck, parked on a hill that is 11.8 m high, is accidently left in neutral without the parking brake applied.
The truck begins rolling down the hill. At the bottom, it continues rolling along a horizontal road. A 104.3-kg man jumps in the back, causing the truck's speed to reduce to 14.5 m/s. What is the mass of the truck? Ignore friction
Answers
The mass of the truck is equal to (104.3 kg x 14.5 m/s) / 11.8 m/s, which is approximately 119.4 kg.
What is mass?Mass is a measure of the amount of matter contained in an object. It can be measured using scales, balances or other measuring instruments. Mass is a fundamental property of all matter, and its measurement is the basis for many scientific and engineering calculations. Mass is not the same as weight, which is a measure of the force exerted by gravity on an object. Mass is often expressed in units such as kilograms or grams.
The mass of the truck can be determined using the law of conservation of momentum. Momentum is defined as the product of mass and velocity, so the momentum of the truck before the man jumps in is equal to the momentum of the truck and man after the man jumps in.
The momentum of the truck before the man jumps in is equal to the truck's mass multiplied by its velocity, which is 11.8 m/s. The momentum of the truck and man after the man jumps in is equal to the mass of the truck plus the man, multiplied by the reduced velocity of 14.5 m/s.
Therefore, the mass of the truck is equal to (104.3 kg x 14.5 m/s) / 11.8 m/s, which is approximately 119.4 kg.
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Un objeto tiene una velocidad de vi=3i-4j m/s, luego duplica su velocidad en 12 segundos, calcula la magnitud de la distancia que recorre en metros.
Answers
Answer:
Explanation:
This is an exercise in kinematics, the speed they give is in two dimensions, let's work on each component
X axis
initial velocity v₀ₓ = 3 m / s in a time of t = 12 s, the velocity is doubled, the final velocity is vₓ = 6 m / s
acceleration is
vₓ = v₀ₓ + aₓ t
aₓ = \(\frac{v_x - v_{ox}} {t}\)
aₓ = 6 - 3/12
aₓ = 0.25 m / s²
the distance traveled is
vₓ² = v₀ₓ² + 2 aₓx x
x = vx² - vox² / 2a
x = 6² - 3² / 2 0.25
x = 54 m
Y axis
we look for acceleration
v_y = v_{oy} + a_y t
a_y = \(\frac{v_y - v_{oy} }{t}\)
a_y = \(\frac{8 -4} {12}\)
ay = 0.3333 m / s²
the distance is
v_y² = v_{oy}² + 2 a⁷y
y = vy² - voy² / 2 0.25
y = 8² - 4² / 2 0/3333
y = 72 m
the distance traveled is
r = (54 i + 72j) m / s
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
Answers
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Why would you want to slow down the movement of heat?
Answers
Answer: heat is transferred to and from objects -- such as you and your home -- via three processes: conduction, radiation, and convection.
Explanation:
Hopes this helps!
what is the force when ur pulling heavy furniture that wont budge
Answers
Answer:
Gravity? is it multiple choice?
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
Answers
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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“Jonny pulls his sister Jane (weight 28 lbs), who is sitting in a wagon, up an incline ramp (θ = 17°) with a steady speed. If the coefficient of kinetic friction is 0.18, the wagon has a mass of 14 kg, and the length of the ramp is 2.4 m, find: a) the work done by the frictional force. b) the work done by the gravitational force.“
Answers
(a) The work done by the frictional force is -33.1 J.
(b) The work done by the gravitational force is 175.58 J
Work done by frictional force
The work done by frictional force is calculated as follows;
W = -μmgsinθ x L
W = -μmgsinθ x L
where;
m is mass of Jane and wagonW = -0.18 x (12.7 + 14)9.8 x sin(17) x 2.4
W = -33.1 J
Work done by the gravitational forceW = mgh
W = mgcosθ x h
W = mgcosθ x Lsinθ
W = (26.7)(9.8)cos(17) x 2.4 x sin(17)
W = 175.58 J
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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
Answers
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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The image shows a diagram explaining a concept.
Which concept does the diagram show?
A. tempature
B. Altitude
C. air density
D. air pressure
Answers
Answer:
D.
Explanation
Air pressure.
Answer:air pressure
Explanation:
A sleigh is being pulled horizontally by a train of horses at a constant speed of 6.38 m/s. The magnitude of the normal force exerted by the snow-covered ground on the sleigh is 7.50 ✕ 103 N.
(a) If the coefficient of kinetic friction between the sleigh and the ground is 0.26, what is the magnitude of the kinetic friction force experienced by the sleigh?
N
(b) If the only other horizontal force exerted on the sleigh is due to the horses pulling the sleigh, what must be the magnitude of this force?
N
Answers
Answer:
(a). The kinetic friction force is 1950 N.
(b). The magnitude of force will be equal of friction force
Explanation:
Given that,
Constant speed = 6.38 m/s
Force \(F=7.50\times10^{3}\ N\)
Kinetic friction = 0.26
(a). We need to calculate the friction force
Using formula of friction force
\(f_{k}=\mu F_{N}\)
Put the value into the formula
\(f_{k}=0.26\times7.50\times10^{3}\)
\(f_{k}=1950\ N\)
(b). If the only other horizontal force exerted on the sleigh is due to the horses pulling the sleigh,
We need to calculate the magnitude of this force
According to given data,
The same force will be applied to keep constant velocity.
Hence, (a). The kinetic friction force is 1950 N.
(b). The magnitude of force will be equal of friction force.
(a). The kinetic friction force is 1950 N.
(b). The magnitude of force will be equal of friction force
The calculation is as follows;a. The magnitude of the kinetic friction force experienced by the sleigh is
\(= 0.76 \times 7.50 \times 10^3\)
= 1950 N
b. It should be equivalent to the friction force.
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An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
Answers
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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A machine part consists of three heavy disks linked by struts of negligible weights as shown in the figure. Calculate the moment of inertia of the body about an axis through the centre of disk A and the kinetic energy, if the body rotates about an axis through A perpendicular to the plane of the diagram, with angular speed ω = 6.0 rads-1..
Answers
if the values of mass (m) and radius (R) are provided, the moment of inertia of the body about an axis through the center of disk A can be calculated as (3/2) * m * R^2, and the kinetic energy of the rotating body would be 162 * m * R^2 Joules.
To calculate the moment of inertia of the body about an axis through the center of disk A, we need to consider the moment of inertia contributions from each individual disk and add them up.
Let's denote the moment of inertia of each disk as I_A, I_B, and I_C, respectively. The moment of inertia of a disk rotating about its center can be calculated using the formula:
I = (1/2) * m * r^2
Where m is the mass of the disk and r is its radius.
Since the struts have negligible weight, we can assume that each disk has the same mass.
Let's assume the mass of each disk is m and the radius of each disk is R.
The moment of inertia of disk A (I_A) is given by:
I_A = (1/2) * m * R^2
The moment of inertia of disk B (I_B) and disk C (I_C) will be the same since they have the same mass and radius:
I_B = I_C = (1/2) * m * R^2
The total moment of inertia of the body about the axis through the center of disk A (I_total) is the sum of the individual moment of inertias:
I_total = I_A + I_B + I_C
= (1/2) * m * R^2 + (1/2) * m * R^2 + (1/2) * m * R^2
= (3/2) * m * R^2
To calculate the kinetic energy of the rotating body, we can use the formula:
Kinetic Energy = (1/2) * I_total * ω^2
Substituting the given values:
Kinetic Energy = (1/2) * ((3/2) * m * R^2) * (6.0 rad/s)^2
Simplifying further, if the values of m and R are given, we can calculate the moment of inertia and kinetic energy.
Assuming that the values of mass (m) and radius (R) are given, we can calculate the moment of inertia (I_total) and kinetic energy.
For the given values of ω = 6.0 rad/s and the previously calculated I_total:
I_total = (3/2) * m * R^2
Kinetic Energy = (1/2) * I_total * ω^2
= (1/2) * [(3/2) * m * R^2] * (6.0 rad/s)^2
= (9/2) * m * R^2 * (36.0 rad^2/s^2)
= 162 * m * R^2 Joules
Therefore, if the values of mass (m) and radius (R) are provided, the moment of inertia of the body about an axis through the center of disk A can be calculated as (3/2) * m * R^2, and the kinetic energy of the rotating body would be 162 * m * R^2 Joules.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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HELP URGENT- will give brainliest if correct
Answers
Answer:
6 km is the right answer
hope it helps you
Explanation:
please mark me as brainliest
Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air?
Answers
Answer:
Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.
Which equation describes the sum of the vectors plotted below?
Answers
The equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
What is vector quantity?A physical quantity that has both directions and magnitude is referred to as a vector quantity.
A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.
According to the final position of the vector as shown in the figure, The final x co-ordinate is 4 and the final y co-ordinate is 2.
the equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
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Rhea, with a radius of 7.63 x 105 m, is the second-largest moon of the planet Saturn. If the mass of Rhea is 2.31 x 1021kg, what is the acceleration due to gravity on the surface of this moon?
Answers
The acceleration due to gravity on the surface of this moon:
Solution:
R = 7·63x105 m m
M = 2·31x10² 1 kg
g= GM/R2
= 6.67x10" x 2.3 x \(10^{21}\)/\((7.63*10^{5} )^{2}\)
=g = 15.4077 x \(10^{10}\)/\((7.63)^{2} * 10^{10}\)
= g = 0·2646 m/s².
An object on the Moon weighs 1/6 of its weight on the Earth's surface. This is because the gravitational acceleration on the Moon is six times that of Earth. The value of g is determined by the mass of the gigantic body and its radius. It depends on your body. The value of g is constant for months. g is called gravitational acceleration. The acceleration of an object in free fall under the influence of gravity. Expressed as the rate of increase in velocity per unit time, it is assigned a standard value of 980.665 centimeters per second per second.
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What is the car’s average velocity (in m/s) in interval between t=1.0s to t=1.5s?
Answers
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, the formula for velocity is;
Velocity (in m/s) = distance/time
The distance the car covered in the completed question is divided by the difference in the time interval
The difference in the time interval will be = 1.5s - 1.0s = 0.5s
NOTE: the distance must be in meters or be converted to meters
hi good afternoon pls I need solution to a problem the question goes like this : The horizontal floor of a water reservoir is said to be 1.0m deep when viewed vertically from above .if the refractive index of water is 1.35 calculate the real depth of the reservoir a)2.35mb)1.35mc)1.00md)0.35m
Answers
First, you have to use Snell's law to calculate the refractive angle. Remember the light enters at a 90 angle and the refractive index of air is 1.
\(\begin{gathered} h\cdot sin\theta2=1m \\ h=\frac{1}{sin(47.79)}=1.35m \end{gathered}\)
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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A pendulum of mass 12 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 19 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that: g = 9.8 m/s²)
20 m
A35
B186
C78
D112
Answers
The energy lost to friction and air resistance is 186 J.
option B.
What is the energy lost to friction and air resistance?The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.
The initial potential energy of the pendulum at the initial position is calculated as;
PEi = mghi
where;
m is the massg is gravityh is the initial heightP.Ei = 12 kg x 9.8 m/s² x 20 m
P.Ei = 2,352 J
The final kinetic energy of the pendulum is calculated as follows;
K.Ef = 0.5 x 12 kg x (19 m/s)²
K.Ef = 2,166 J
ΔE = 2,166 J - 2,352 J
ΔE = -186 J
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Which of the following correctly explain why the pressure of a gas in a rigid container increases with increasing temperature? SELECT TWO ANSWERS The average molecular speed increases with temperature, so the molecules collide with the walls of the container more frequently. The average molecular kinetic energy increases with temperature, so the molecules exert a larger average force on the walls of the container when they collide with the walls of the container. The average molecular kinetic energy increases with temperature, so the molecules exert a larger average force on each other when they collide with each other. The average molecular speed increases with temperature, so the molecules collide with each other more frequently.
Answers
Find the direction of this vector.
80.0°
B-18.6 m
0 = [?]°
Hint: Remember, 0 is the direction of the
vector and is measured from the +x-axis.
![Find the direction of this vector.80.0B-18.6 m0 = [?]Hint: Remember, 0 is the direction of thevector](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/TftG9dcWZmYdQkNf07Csr1pYOmEQ1s0Q.png)
Answers
The direction of the given vector B of 18.6 m that is 80° left of the positive y-axis is 170°
Angle of the vector made with positive y-axis = 80°
Angle between positive x and y axis = 90°
Direction of B, θ = 90° + 80°
θ = 170°
Direction of a vector is the angle of the vector that is made with positive x-axis. A vector with a certain direction of certain degrees means that the vector is rotated that much degrees in counter-clockwise direction relative to positive x-axis.
Therefore, the direction of the vector B is 170°
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explain why electric discharge through a gas take place at low pressure
Answers
answer:
electric discharge takes place at low pressure because a small electric field is required.
explanation:
it was found that cathode when an electric field was applied perpendicular to the length of the discharge tube the cathode rays were found to be moving in a direction opposite of electric fieldcredits: onlineWhat is the mass of an object accelerated at 2 m/s2 by a net force of 12 N?
Please help I’m struggling !!
Answers
Answer: the answer is 6kg.
Explanation:
Mass= force divided by acceleration, which would be 12 divided by 2.
3. Suppose you take a pendulum with length L and mass m having a period T to a
planet where the value of g is 176 of the value on Earth. What would be the period
of the pendulum on the planet? *
T/6
OT
O 1.6T
2.4 T
4.6 T
help fast
Answers
(C)
Explanation:
\(t = 2\pi \sqrt{ \frac{l}{g} } \)
If g is only 1/6 on another planet, then
\(t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } = 2\pi \sqrt{ \frac{6l}{g} } \)
\( = \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4 \times t(on \: earth)\)
A golf ball is hit at an angle of 85° above the horizontal. What is the acceleration of the golf ball when it reaches the
highest point of its path?
3 pts for correct answer with units
Answers
Hi there!
When the ball reaches the highest point of its trajectory, it is experiencing an acceleration due to gravity of 9.8 m/s² DOWNWARD.
Keep in mind, the ball is experiencing this downward acceleration at ALL points of its trajectory, resulting in a change in its VERTICAL velocity.
A combination of two identical resistors connected in series has an equivalent resistance of 12. ohms. What is the equivalent resistance of the combination of these same two resistors when connected in parallel?
Answers
Answer:
R1 + R2 = R = 12 for resistors in series - so R1 = R2 if they are identical
2 R1 = 12 and R1 = R2 = 6 ohms
1 / R = 1 / R1 + 1 / R2 for resistors in parallel
R = R1 * R2 / (R1 + R2) = 6 * 6 / (6 + 6) = 3
The equivalent resistance would be 3 ohms if connected in parallel
When a cold air mass catches up with a warm air mass, the resut is often
a(n)
front.
Answers
Answer:
a cold front i think
Explanation:
A ball is projected with an initial velocity 50m/s at an angle 30 degree from the top of a tower 55m high.calculate the total time the ball was on the air and the maximum horizontal distance
Answers
Time of flight = 1.6 s
Horizontal distance = 64 m
What is a projectile motion?Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.
For the given case,
h = vt + ¹/₂gt²
h = height of tower
v = initial velocity
t = time of flight
55 = 50sin30t + ¹/₂9.8t²
55 = 25t + 4.9t²
4.9t² + 25t - 55 = 0
t = 1.6 s
X = vₓt
X = horizontal distance
vₓ = horizontal velocity
t = time of flight
X = (50 x cos30) x 1.6
X = 64 m
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