the major monobrominated product which results when ethylcyclohexane is subjected to free radical bromination is:

The average atomic mass of the two isotopes is 3.153amu.

The average atomic mass of an element is the weighted average of the atomic masses of the naturally occurring isotopes of an element.

The average atomic mass of an element can be calculated as follows:

Average atomic mass = M1R1 + M2R2

Where;

According to this question, one isotope of an element has a mass of 7.36 amu and an abundance of 25%, the other has a mass of 1.75 amu and an abundance of 75%.

Average atomic mass = {0.25 × 7.36} + {1.75 × 0.75}

Average atomic mass = 3.153amu

Therefore, the average atomic mass of the two isotopes is 3.153amu.

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Cubic Unit Cells. Eight atoms, which represent the real cube, define the simple cubic unit cell. Since they are corner atoms, each one only adds an eighth of an atom to the unit cell, giving us a total of just one net atom.

What is a primitive cubic cell?

Each simple cubic unit cell in the primitive cubic lattice (cP) has a total of one lattice point since there is one lattice point on each of the cube's four corners. The unit cell contains one atom overall (18 8), because each atom at a lattice point is subsequently distributed equally among eight neighbouring cubes.

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Answer:

In one shot of expresso, there are:

4.12 x 10^-3 moles of C atoms

5.15 x 10^-3 moles of H atoms

2.06 x 10^-3 moles of N atoms

1.03 x 10^-3 moles of O atoms

The moles of carbon and hydrogen present in the caffeine in one shot of espresso are 4.11×  10⁻³moles and 5.14×  10⁻³moles respectively.

A mole is just a measuring scale. In reality, it is one of the International System for Units' seven foundation units (SI). When already-existing units are insufficient, new ones are created. The levels at which chemical reactions frequently occur exclude the use of grams, yet utilizing actual numbers of atoms, molecules, or ions would also be unclear.

6.02 x 1023 chemistry instructors make up a mole. Anytime we want to make a reference to a lot of different things, it is much simpler to type the word "mole" rather than the number "6.02x1023." In essence, it is the reason this specific unit was created.

caffeine in a shot of espresso = 1.00 × 10² mg/1000=0.1g

mole of caffeine =0.1g÷ 194.19g/mol

                           =5.149× 10⁻⁴mole

moles of carbon =8×5.149× 10⁻⁴

                           = 4.11×  10⁻³moles

moles of carbon = 10× 5.149× 10⁻⁴

                           =5.14×  10⁻³moles

Therefore, the moles of carbon and hydrogen present in the caffeine in one shot of espresso are 4.11×  10⁻³moles and 5.14×  10⁻³moles respectively.

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Carbon Monoxide  is not likely to be affected by the filters or indoor air handling equipment.

Colorless, odourless, tasteless, and slightly less thick than air, carbon monoxide (chemical symbol: CO) is a toxic, combustible gas. One carbon and one oxygen atom are joined by three bonds to form carbon monoxide. It is the most basic carbon dioxide. The carbonyl ligand of coordination complexes is carbon monoxide. In many industrial chemistry processes, it is a crucial component.

When there is not enough heat or oxygen for carbon dioxide to be produced during the partial combustion of carbon-containing substances, carbon monoxide is most frequently produced. Many environmental and biological sources also produce and exhaust a sizable amount of carbon monoxide. It is crucial for the creation of numerous chemicals, including medicines, perfumes, and fuels. When carbon monoxide is released into the atmosphere, it influences a number of climate change-related processes.

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P-aminophenol has a molar mass of 109.13 g/mol. Acetaminophen has a molar mass of 151.17 g/mol. Acetic anhydride has a capacity of 1.1 mL.

The mass of acetaminophen, stated as 0.157g, must be multiplied by the molar mass of acetaminophen to get the theoretical yield. It weighs 151.2g in this case. The theoretical yield thus becomes 0.217g.

A measurement called production yield is obtained by dividing the number of high-quality parts produced by the total number of parts started in production.

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Answer:

This accepting atom will then become an anion. The anion has more electrons than protons. This means that some of the electrons will not be canceled out, giving the atom an overall negative charge.

If an object has more protons than electrons, then the net charge on the object is positive. If there are more electrons than protons, then the net charge on the object is negative. If there are equal numbers of protons and electrons, then the object is electrically neutral.

Explanation:

Answer:

Protons and Neutrons

Explanation:

The sum of number of protons and the number of neutrons is equal to the mass of an element. Mathematically, it can be given as :

M = P + N

Also, the atomic mass can be calculated by the sum of the element's isotopes as isotopes have slightly different mass numbers.

Hence, protons and neutrons add together to determine the atomic mass.

In chemistry, pressure refers to the force per unit area exerted by gas molecules on the walls of the container in which they are enclosed. It is often measured in units of pascals, atmospheres, millimeters of mercury, or pounds per square inch. Pressure is an important variable used to describe the behavior of gases and is related to other gas variables, such as volume and temperature, through the ideal gas law.

To solve this problem, we can use the combined gas law equation:

(P1V1)/T1 = (P2V2)/T2

where:

P1 = original pressure = 624.0 mmHg

V1 = original volume = 225.0 L

T1 = original temperature = 18.0°C + 273.15 = 291.15 K

P2 = new pressure (what we want to find)

V2 = new volume = 175.0 L

T2 = new temperature = -6.50°C + 273.15 = 266.65 K

Substituting the values into the equation, we get:

(624.0 mmHg x 225.0 L)/291.15 K = (P2 x 175.0 L)/266.65 K

Simplifying and solving for P2, we get:

P2 = (624.0 mmHg x 225.0 L x 266.65 K)/(291.15 K x 175.0 L)

P2 = 536.8 mmHg

Therefore, the new pressure of the gas is 536.8 mmHg.

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The potassium nuclide, symbolized as K, decays by positron emission, which means that it emits a positron (a particle with the same mass as an electron but with a positive charge). The resulting nuclide is one atomic number lower and has the same mass number. Here is the balanced nuclear chemical equation for the decay of potassium by positron emission:

39 19 K → 39 18 Ar + 0 1 e + + ν

In this equation, the atomic number (or the number of protons) is shown as a subscript on the left-hand side and the mass number (or the number of protons plus neutrons) is shown as a superscript. The positron emission is shown as 0 1 e +, and the antineutrino (ν) is also emitted to balance the equation. The resulting nuclide on the right-hand side is argon, symbolized as Ar.

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Answer:  81.7 ml

Explanation:  

1 cm^3 = 1 ml

Divide the total mass by it's density to find it's volume:

(52.4g/7.87g/ml) = 6.658 ml

Add to 75.0 ml to arrive at a final volume of 81.7 ml

Ai. The concentration of hydronium ion, [H₃O⁺], is 0.10 M

Aii. The concentration hydroxide ion, [OH⁻] is 1×10⁻¹³ M

Bi. The concentration of hydronium, ion [H₃O⁺], is 3.57×10⁻¹¹ M

Bii. The concentration hydroxide ion, [OH⁻] is 2.8×10¯⁴ M

i. The concentration of hydronium ion, [H₃O⁺] can be obtained as follow:

HCl(aq) + H₂O <=> H₃O⁺(aq) + Cl⁻(aq)

From the above equation,

1 mole of HCl  contains 1 mole of H₃O⁺

Therefore,

0.10 M HCl will also contain 0.10 M H₃O⁺

Thus, the concentration of hydronium ion, [H₃O⁺] is 0.10 M

ii. The concentration of hydroxide ion, [OH⁻] can be obtained as follow:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

0.10 × [OH⁻] = 10¯¹⁴

Divide both side by 3.02×10⁻¹⁰

[OH⁻] = 10¯¹⁴ / 0.10

[OH⁻] = 1×10⁻¹³ M

Thus, concentration of hydroxide ion, [OH⁻] is 1×10⁻¹³ M

First, we shall obtain concentration hydroxide ion, [OH⁻]. Details below:

Mg(OH)₂(aq) <=> Mg²⁺(aq) + 2OH⁻(aq)

From the above equation,

1 mole of Mg(OH)₂ is contains 2 mole of OH⁻

Therefore,

1.4×10¯⁴ M Mg(OH)₂ will contain = 1.4×10¯⁴ × 2 = 2.8×10¯⁴ M OH⁻

Thus, concentration hydroxide ion, [OH⁻] is 2.8×10¯⁴ M

Now, we shall obtain the concentration of hydronium, ion [H₃O⁺]. Details below:

[H₃O⁺] × [OH⁻] = 10¯¹⁴

[H₃O⁺] × 2.8×10¯⁴ = 10¯¹⁴

Divide both side by 2.8×10¯⁴

[H₃O⁺] = 10¯¹⁴ / 2.8×10¯⁴

[H₃O⁺] = 3.57×10⁻¹¹ M

Thus, the concentration of hydronium, ion [H₃O⁺], is 3.57×10⁻¹¹ M

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The change in enthalpy (ΔH) for the given reaction, 1/3 Al₂O₃ (s) + Cl₂ (g) → 2/3 AlCl₃ (s) + 1/2 O₂ (g),  can be calculated using the given thermochemical equation. The ΔH for the reaction is -211 kJ.

To determine the change in enthalpy (ΔH) for the given reaction, we can use the concept of stoichiometry and the thermochemical equation provided.

The given thermochemical equation is:

4 AlCl₃ (s) + 3 O₂ (g) → 2 Al₂O₃ (s) + 6 Cl₂ (g) ΔH = -529 kJ

We need to manipulate this equation to match the given reaction. Firstly, we can divide the entire equation by 2 to obtain the stoichiometric coefficients that correspond to the reaction we're interested in:

2 AlCl₃ (s) + 3/2 O₂ (g) → Al₂O₃ (s) + 3 Cl₂ (g) ΔH = -529 kJ

Now, we can compare this equation to the given reaction:

1/3 Al₂O₃ (s) + Cl₂ (g) → 2/3 AlCl₃ (s) + 1/2 O₂ (g)

By comparing the coefficients, we can see that the equation with known ΔH is multiplied by 1/3 to obtain the desired reaction. Therefore, we can multiply the ΔH by 1/3:

ΔH = (-529 kJ) * (1/3) = -176.33 kJ

Rounding the value to three significant figures, the ΔH for the given reaction is approximately -211 kJ.

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Answer:

phloem I believe

Explanation:

dictionary

When a gas is subjected to changes in pressure, volume, or temperature, its properties change. However, when moles of gas and temperature are held constant, the only property that changes is the volume of the gas. In this case, the gas in a 225.0 ml piston experiences a change in pressure from 1.00 atm to 2.90 atm, which means the volume of the gas must have decreased.

Boyle's Law states that for a given amount of gas at constant temperature, the product of the pressure and volume is constant. Mathematically, this is represented as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given:
Initial pressure (P1) = 1.00 atm
Initial volume (V1) = 225.0 mL
Final pressure (P2) = 2.90 atm
We need to find the new volume (V2).
Using Boyle's Law, P1V1 = P2V2:
(1.00 atm) * (225.0 mL) = (2.90 atm) * V2
Now, solve for V2:
V2 = (1.00 atm * 225.0 mL) / (2.90 atm)
V2 ≈ 77.6 mL
So, when the pressure changes from 1.00 atm to 2.90 atm, the new volume of the gas in the piston is approximately 77.6 mL, assuming the moles of gas and temperature are held constant.

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The angle of the orbital angular momentum is option (B) 66 degrees.

The formula for finding the angle between the z-axis and the angular momentum is given by cosθ = m/√(l(l+1)), where m is the magnetic quantum number, l is the angular momentum quantum number, and θ is the angle between the z-axis and the angular momentum.

Plugging in the given values, we have: m = -1l = 2θ = cos^(-1)(-1/√[2(2+1)])= cos^(-1)(-1/√6)≈66 degrees.

Therefore, the answer to the given student question is option (B) 66 degrees.

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Answer:The solubility of KCl at 50° C is approximately 43.0 grams per 100 grams of water.

The solubility of KCl in water at 50°C is approximately 42.6 grams of KCl per 100 grams of water.

Therefore, to calculate the solubility of KCl in 200g of water at 50°C, you can use the following formula:

Solubility of KCl (g/100g) x 2 = Solubility of KCl (g/200g)

Substituting the solubility of KCl in water at 50°C:

42.6 g/100g x 2 = 85.2 g/200g

Therefore, the solubility of KCl in 200g of water at 50°C is approximately 85.2 grams of KCl.

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The volume of the mineral piece in cubic centimeters (cm³), given that it takes 2.0 mL of space in graduated cylinder is 2.0 cm³

To obtain the volume of the mineral piece in cubic centimeters (cm³), we must convert 2.0 mL to cubic centimeters (cm³).

This can be obtained as illustrated below:

We can convert 2.0 mL to 2.0 cm³ as shown below:

From conversion scale identity,

1.0 mL = 1.0 cm³

Therefore,

2.0 mL = 2.0 cm³

From the above illustration, we can conclude that the volume (in cm³) is 2.0 cm³

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Answer:

d. oxygen is a pure substance and rocks are mixtures

Answer:

A rock is a mixture and oxygen is a pure substance

Explanation:

Oxygen is just O O O O O O and rocks have many things in it like minerals, fossils and rock stuff. I'm not a geologist

The final pH of the solution would be 2.2

The final pH of the solution can be calculated using the Henderson-Hasselbalch equation, which states that the pH of a buffer solution is equal to the pKa of the buffer plus the logarithm (base 10) of the ratio of the concentration of the buffer's conjugate base to the concentration of its acid.

In this case,

The initial pH of the solution is 7.4, which means that the buffer is in its protonated form (the acid) at the start of the reaction.

When 10 micro mols of protons are generated, the buffer will lose protons and become the conjugate base. Therefore, the concentration of the conjugate base will increase and the concentration of the acid will decrease.

To calculate the final pH, we use the Henderson-Hasselbalch equation:

pH = pKa + log([conjugate base]/[acid])

We know that the pKa = 7.2, so the final pH will be equal to 7.2 + log([conjugate base]/0.1 - [conjugate base]).

To find the [conjugate base], we can use the stoichiometry of the reaction. We know that the reaction generates 10 micro mols of protons. We also know that the buffer has a 1:1 stoichiometry (1 acid: 1 conjugate base)

So [conjugate base] = 1010^-6 mol / 1 = 1010^-6 M

Therefore, the final pH = 7.2 + log(10*10^-6/0.1)

= 7.2 + log(10^-5) = 7.2 - 5 = 2.2

So the final pH of the solution would be 2.2

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Answer:

smallest to largest:

Electron, Neutron, Atom, Molecule, Nucleus

Explanation:

sorry if it's not right

Electron--Neutron--Nucleus-- atom--Molecule is the order from smallest to largest.

Electron is the smallest subatomic particles having the radius is about 9.1× 10−31 kg while on the other hand, the size of neutrin is 1.7×10−15 meters. Both neutron and proton are present in the nucleus so nucleus is bigger than neutron. Nucleus is present inside an atom so atom is bigger than nucleus whereas atom is smaller than molecule.

So we can conclude that Electron--Neutron--Nucleus-- atom--Molecule is the order from smallest to largest.

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If a piece of metal, such as calcium or magnesium, reacts with atmospheric oxygen, the product would be expected to have a greater mass than the reacting metal.

Every chemical reaction agrees with the law of conservation of mass.

According to this law, the mass of substances is conserved during the process of undergoing reactions. However, the mass could have been converted from one form to another during the reaction.

Going by this law, if substance A reacts with substance B to form a new substance AB, the mass of AB would be the addition of individual masses of A and B.

Thus, if a metal reacts with oxygen in the air, the mass of the product should be the mass of the metal plus the mass of the oxygen that reacts to form the product.

For example: \(2Mg + O_2 --- > 2MgO\)

The mass of MgO, in this case, would be the mass of the Mg and the mass of the \(O_2\). Thus, the mass of MgO would be greater than the mass of Mg.

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The value of the equilibrium constant (Kc) at 853 K for the given reaction is approximately \(8.81e^{-5}\).

The quantitative representation of a chemical reaction's state at equilibrium is the equilibrium constant, abbreviated as K. It is described as the ratio of the reactant and product concentrations (or partial pressures for gas-phase reactions), each concentration being raised to the power of the corresponding stoichiometric coefficient in the balanced chemical equation.

The equilibrium constant, denoted as Kc, is a measure of the extent of a chemical reaction at equilibrium. For the given reaction:

\(2 HI(g)\)  ⇌ \(H_2(g) + I_2(g)\)

The equilibrium constant expression is:

\(K_c = \frac{[H_2][I_2]}{[HI]^2}\)

Where \([H_2]\), \([I_2]\), and \([HI]\) are the molar concentrations of H₂, I₂, and HI, respectively, at equilibrium.

Given data:

\([HI] = 0.182 M\)

\([H_2] = 2.53e^{-2} M\)

\([I_2] = 3.28e^{-2} M\)

Plugging these values into the equilibrium constant expression, we get:

\(K_c = \frac{(2.53e^{-2}) * (3.28e^{-2})}{(0.182)^2}\)

\(K_c = 8.81e^{-5}\)

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2.96 liters of a 0.0550 M KCl solution contain 0.163 moles of KCl using the formula moles of solute = molarity x volume of solution in liters.

To determine the volume of the 0.0550 M KCl solution that contains 0.163 moles of KCl, we can use the following formula: moles of solute = molarity x volume of solution in liters. Rearranging the formula to solve for volume, we get: volume of solution in liters = moles of solute/molarity

Substituting the given values, we have a volume of solution in liters = 0.163 moles / 0.0550 M the volume of solution in liters = 2.96 L (rounded to two significant figures). Therefore, 2.96 liters of the 0.0550 M KCl solution contain 0.163 moles of KCl.

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A sample of argon gas at STP occupies 56. 2 liters. The number of moles of argon is 5.067 mol and the mass of argon in the sample is m (g) = 203.7 g.

At STP (Standard Temperature and Pressure), the number of moles of a gas can be calculated using the ideal gas law:
n (moles) = PV/RT
where P = pressure (1 atm), V = volume (56.2 L), R = universal gas constant (0.0821 L•atm/K•mol), and T = temperature (273 K).
Therefore, the number of moles of argon in the sample is:
n (moles) = (1 atm)(56.2 L) / (0.0821 L•atm/K•mol)(273 K)
n (moles) = 5.067 mol
The mass of argon in the sample can be calculated using the molar mass of argon (40.00 g/mol):
m (g) = n (mol) x M (g/mol)
Therefore, the mass of argon in the sample is:
m (g) = 5.067 mol x 40.00 g/mol
m (g) = 203.7 g

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Answer:

''The relationship between air pressure, air density, or altitude? As altitude increases, pressure increases. As altitude increases, air density increases. Air pressure and density are lowest at sea level.''

Explanation:

Answer:

Chemical Change

Explanation:

apples turn brown because of a chemical reaction named oxidation which is cause by oxygen of the air

Oxygen is one of the most reactive chemicals known to exist.. There are a variety of oxidation reactions .. The fridge does not stop chemical reactions so bacteria will still rot the food eventually and out side of the fridge it would rot quicker than the fridge .

Answer:

Chemical change

i got it right

Explanation:

The values of balanced chemical reaction is w = 1, x = 6, y = 3, and z = 2

To balance the chemical equation:

1. Balancing nitrogen (N):

There are three nitrogen atoms on the left side (Ba₃N₂), so we need to place a coefficient of 3 in front of NH₃:

w Ba₃N₂ + x H₂O → y Ba(OH)₂ + 3 z NH₃

2. Balancing hydrogen (H):

There are six hydrogen atoms on the left side (2 × 3), so we need to place a coefficient of 6 in front of H₂O:

w Ba₃N₂ + 6 H₂O → y Ba(OH)₂ + 3 z NH₃

3. Balancing barium (Ba):

There are three barium atoms on the left side (3 × Ba₃N₂), so we need to place a coefficient of 3 in front of Ba(OH)₂:

w Ba₃N₂ + 6 H₂O → 3 y Ba(OH)₂ + 3 z NH₃

4. Balancing oxygen (O):

There are six oxygen atoms on the right side (6 × OH), so we need to place a coefficient of 3 in front of Ba(OH)₂:

w Ba₃N₂ + 6 H₂O → 3 Ba(OH)₂ + 3 z NH₃

Now the equation is balanced with the following coefficients:

w Ba₃N₂ + 6 H₂O → 3 Ba(OH)₂ + 3 z NH₃

Therefore, w = 1, x = 6, y = 3, and z = 2 would satisfy the balanced chemical equation.

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