The main problem of solar and wind energy and its solutions

Answer:

2 m/s²

Explanation:

To calculate the acceleration of an object, we use the following formula:

\(\boxed{a = \frac{v - u}{t}}\),

where:

• a = acceleration

• v = final speed

• u = initial speed, and

• t = time taken

We are told in the question that the final speed of the helicopter is 40 m/s, its initial speed is 30 m/s, and that the time it took to get from 30 m/s to 40 m/s is 5 seconds.

Therefore, using this information, as well as the formula above, we can evaluate the acceleration of the helicopter:

\(a = \frac{40 - 30}{5}\)

  \(= \frac{10}{5}\)

  \(= \bf 2 \: m/s^2\)

So the acceleration of the helicopter is 2 m/s².

Answer:

where?

Explanation:

ill edit my answer when see it

Answer:

natural convection

............

Assuming no air restance the speed when the ball comes back to the starting point will be again 8ms but directed DOWNWARDS; we can express this by saying that it will equal to −8ms adding a minus to indicate the downward direction.

To find the time of flight we use:

vf=vi+at

Where:

a is the acceleration of gravity (downwards, −9.8ms2);

vi=+8ms

vf=−8ms

So, we get:

−8=8−9.8t

−16=−9.8t

t=169.8≈1.6s

The answer is "B"

Answer link

Answer:

4 degrees C

Explanation:

this is just a 'known'

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

A primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.

Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.

On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.

Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.

In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

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The total current that is drawn from the mains supply is 5 A.

The term current has to do with the flow of charges in a circuit. Now we have been told that A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. It was also said in the question that when the lights are switched on and working correctly, the current through each lamp is 0.25 A.

Now we have the following information;

Current passing through each lamp = 0.25 A

Number of lamps = 20 lamps

Hence;

Total current = 0.25 A * 20

= 5 A

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Given :

A baseball Is traveling with a momentum of 6.5kg m/s.

To Find :

The magnitude of the force stopping it If it gets stopped in 0.020 s.

Solution :

We know, force in terms of magnitude is given by :

\(Force = \dfrac{Momentum}{Time\ Taken}\\\\Force = \dfrac{6.5 \ kg\ m/s}{0.020\ s}\\\\Force = 325 \ kg \ m/s^2\)

Therefore, the magnitude of the force stopping it is 325 kg m/s² .

The average speed is 18.73 km/hour.It is found as the ratio of the total distance and the total time taken.

The total distance traveled by an object divided by the total time taken is the average speed.

The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

The given data in the problem is;

Distance (d₁) = 18 Kilometers

Time (t₁) =  2.5 hours

Distance (d₂) = 150 Km

Time (t₂)= 4 hours

Distance (d₃) =10 Km

Time (t₃)=3 hours.

The average speed is found as;

\(\rm v_{avg}= \frac{Total \ distance }{Total \ time } \\\\ V_{avg}=\frac{18+150+10}{2.5+4+3} \\\\ v_{avg}= 18.73 \ km/hours\)

Hence, the average speed is 18.73 km/hour.

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Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores

Explanation:

t = 1.406 seconds

The given equation representing the height as a function of time t is:

Note that:

• The speed of the object at time t, v(t) = dh/dt

• At maximum height, v(t) = 0

dh/dt = -32t + 45

v(t) = -32t + 45

0 = -32t + 45

32t = 45

t = 45/32

t = 1.406 s

Answer:

Explanation:

This question is part of a graded assignment given by a cyber school in Pennsylvania.  I know this to be true because I can see the next question as well in the screen shot.  Please remove this question and answer.  Signed, the teacher.

P.S.  The phase (when height is zero) was added to the original question provided by the curriculum provider so students solve for the time in the air, and not the time required to reach maximum height.

4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.

The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.

To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.

Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.

ΔE = 4×10^26 W

c = 3×10^8 m/s (speed of light)

Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².

Substituting the values, we have:

Δm = (4×10^26 W) / (3×10^8 m/s)²

Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.

This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.

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The amount of load lifted by the pulley when the efficiency is 60% and effort is 50 N is determined as 30 N.

The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;

E = L / E   x  100%

where;

The amount of load lifted by the pulley is calculated as;

60 = L / 50   x 100%

60 = 100L / 50

100L = 50 x 60

100 L = 3000

L = 3000 / 100

L = 30 N

Thus, the amount of load lifted by the pulley is 30 N.

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When an object is balanced (in equilibrium) the sum of the clockwise moments is equal to the sum of the anticlockwise moments.

The magnitude of the force at pin A and in cable BC needed to support the 500-lb load is 2,000 lbs, since the cable BC supports 1/4 of the load. The force in the cable is transferred to the pin A and distributed along the boom AB. The weight of the boom AB can be neglected in this calculation.

Load = 500 lb Boom AB = Neglected To determine :Magnitude of force at the pin A and in the cable BC needed to support the 500-lb load Formula used:ΣFx = 0ΣFy = 0

Considering point AΣFy = 0ΣFy = Ay - 500Ay = 500 lb Considering point CΣFx = 0∴T cos 45° = 0T = 0 lbΣFy = 0∴T sin 45° - B = 0B = T sin 45°B = T / √2By substituting the value of T in the above equation we get B = 0 lb Therefore, force required at pin A is 500 lb and force required in the cable BC is 0 lb to support the 500-lb load.

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We need Net resistance

solve from right words

\(\\ \rm\Rrightarrow R_1=20+10=30\Omega\)

\(\\ \rm\Rrightarrow \dfrac{1}{R_2}=\dfrac{1}{30}+\dfrac{1}{50}=\dfrac{5+3}{150}\)

\(\\ \rm\Rrightarrow R_2=\dfrac{150}{8}=18.75\Omega\)

\(\\ \rm\Rrightarrow \dfrac{1}{R_3}=\dfrac{1}{30}+\dfrac{1}{40}=\dfrac{4+3}{120}\)

\(\\ \rm\Rrightarrow R_3=\dfrac{120}{7}=17.14\Omega\)

\(\\ \rm\Rrightarrow R_{net}=17.14+18.75=35.89\Omega\)

Use ohm's law

\(\\ \rm\Rrightarrow I=\dfrac{V}{R}\)

\(\\ \rm\Rrightarrow I=\dfrac{9}{35.89}\)

\(\\ \rm\Rrightarrow I\approx 0.25A\)

The amplitude of wave A is +2 units and the amplitude of wave B is -1 units.

The amplitude of resultant pulse of the pulse can be calculated as,

Therefore, the amplitude of resultant wave is +1 unit which means option (a) is correct.

We have that for the Question "" it can be said that Calculate the moment which must be applied to the handle of the screw to raise the block is

From the question we are told

The vertical position of the 100-kg block is adjusted by the screw activated wedge. Calculate the moment which must be applied to the handle of the screw to raise the block. The single thread screw has square threads with a mean diameter of 30 mm and advances 10 mm each complete turn. The coefficient of friction for the screw threads is 0.24, and the coefficient of friction for all the mating surfaces of the block and the wedge is 0.40. Neglect friction at the ball joint A

Generally the equation for the Block is mathematically given as

\(\sum Fy=0\)

\(981cos21.80 = R_2cos53.6\\\\R_2=1535N\)

the equation for the Wedge is mathematically given as

\(\sum Fx=0\\\\1535cos36.4=Pcos21.8\\\\P=1331N\)

the equation for the Screw is mathematically given as

\(\beta = tan^{-1}*\frac{L}{2*\pi*r} \\\\\beta = tan^{-1}*\frac{10}{2*\pi*(15)} \\\\\\beta = 6.06\\\\\theta = tan^{-1}*0.25 \\\\\theta = 14.04\\\\\\Therefore\\\\\theta + \beta = 20.1\\\\\)

Therefore

\(M = Pr tan (\theta + \beta)\\\\M = 1331(0.015) tan20.09\\\\M = 7.30 N.m\)

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The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people

We'll begin by converting 175 cm to m. This can be obtained as illustrated below:

100 cm = 1 m

Therefore,

175 cm = (175 cm × 1 m) / 100 cm

175 cm = 1.75 m

Thus, 175 cm is equivalent to 1.75 m

The number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:

Number of people needed = Height of tower / height of a person

Number of people needed = 553 / 1.75

Number of people needed = 316 people

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The work done by the boy against the gravitational force is 240000J.

Here given that,

Mass of the box (m) = 300 g

Height of table (h) = 80cm

Acceleration due to gravity (g) = 10 m/s²

Work done against gravitational force will be calculated by formula,

W = mgh

By substituting the values,

   = 300 x 10 x 80

   = 240000J

Therefore the work done by the boy is 240000J.

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OB

mmnjnjlkdhfutydjfyiudtkcgvyftdcgvjyiluftgyiuyu  ( had to do that cuz it wouldn't let through)

Given that the distance from the wire is r = 30 cm = 0.3 m

The magnitude of the magnetic field is

We have to find the magnitude of the current.

The formula to find the magnitude of the current is

Substituting the values, the current will be

Thus, the magnitude of current is 60 A

The magnitude is 756.72 N and the coordinate direction angles of the resultant of the two forces acting at point A are alpha(\(149^{0}\)), beta(\(0^{0}\)), and gamma(\(59^{0}\)).

The resultant force is the overall force acting on an object, which is the vector sum of all the individual forces acting on the object. It is the net force that determines the motion of an object. In other words, it is the force that would have the same effect on the object's motion as all the individual forces combined. The direction of the resultant force is the direction of the net force and the magnitude is the sum of the magnitudes of the individual forces.

Given,

A = (5, 0, 0) m

B  = (0, 2, 3) m

C = (0, -2, 3) m

AB = B - A  = -5i + 2j + 3k

\(AB_{cap}\) = \(\frac{-5i+2j+3k}{\sqrt{5^{2}+2^{2}+3^{2} } } =\frac{-5i+2j+3k}{6.16}\)  

AC = C - A = -5i - 2j + 3k

\(AC_{cap} =\frac{-5i+2j+3k}{6.16}\)

Fb = 400 (-5i + 2j + 3k ) / 6.16\(F_{b} =\frac{400(-5i+2j+3k)}{6.16} =-324.44i+129.78j+194.67k \\F_{c}=\frac{400(-5i+2j+3k)}{6.16}= -324.44i-129.78j+194.67k\)

\(F_{net} =F_{b} +F_{c}\)= - 648.88i + 389.33k N

Magnitude = |\(F_{net}\)|  = \(\sqrt{648.88^{2}+389.33^{2} } =756.72N\) .......Ans

Coordination angles,

alpha = \(cos^{-1} \frac{F_{net} x}{|F_{net}| } =149^{0}\)

beta = \(cos^{-1}\frac{F_{net}y }{|F_{net} |} =0^{0}\)  

gamma = \(cos^{-1}=\frac{F_{net}z }{|F_{net} |} =59^{0}\)

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The complete question is given below:

The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.

Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).

From the given,

The capacitive reactance (Xc) = 375ω

capacitance (C) = 3.25μF

capacitive reactance Xc = 1/(2π×f×C)

Frequency (f) = 1/(2π×Xc×C)

                     = 1/(2×3.14×375×3.25×10⁻⁶)

                     = 131 s⁻¹.

Thus, the frequency of the capacitive reactance is 131 s⁻¹.

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Given data:

* The height of the window is 10 m.

* The angle of the incident velocity with respect to the horizontal is 60 degree.

Solution:

(a). The height of the projectile in terms of the initial velocity is,

where u is the initial velocity, g is the acceleration due to gravity, and

Substituting the known values,

The initial velocity of the projectile is,

Thus, the initial velocity of the bag is 16.2 m/s at an angle of 60 degree to the ground.

(b). The horizontal range of bag is,

Substituting the known values,

The position of the bag from the house is,

Thus, the lad is standing at the distance of 11.5 m from the house.

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Answer:

Your answers are A and C.

Explanation:

Have an amazing day/night. I am so sorry I do not have the explanation you are looking for. But I did get this right on the assignment.

Josh was blowing bubbles through a straw into a glass of tap water. As Josh exhaled into the straw, he blew carbon dioxide gas into the water. The harder he blew, the more bubbles entered the water. The more bubbles, the more saturated the solution gas/water solution.

This is because the bubbles increase surface area of gas-water Interface, allowing for more gas molecules to come into contact with  water and dissolve. As more gas dissolves,  concentration of the gas in the water increases, and the solution becomes more saturated . This effect is known as Henry's law, which states that amount of gas that dissolves in a liquid is directly proportional to the partial pressure of the gas above liquid.

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Answer:

hope this was good for u and I believe it would be solid