a. The solubility of AgIO₃ and La(IO₃)₃ was calculated in a 0.285 M solution of NaIO₃.
b. The solubility of AgIO₃ was found to be 2.53 x 10⁻⁸ M, while the solubility of La(IO₃)₃ was found to be 5.54 x 10⁻⁷ M.
c. The solubility of AgIO₃ is lower than that of La(IO₃)₃, it is the more insoluble compound.
a. First, we need to write the balanced chemical equation for the dissolution of AgIO₃ in water:
AgIO₃ (s) ⇌ Ag⁺(aq) + IO₃⁻(aq)
The Ksp expression for this reaction is:
Ksp = [Ag⁺][IO₃⁻]
We can assume that the amount of AgIO₃ that dissolves is x, which gives us:
[Ag⁺] = x M
[IO₃⁻] = x M
Substituting these values into the Ksp expression and solving for x gives us:
Ksp = x²
x = √(Ksp)
x = √(3.0 x \(10^{-8}\)) = 5.48 x \(10^{-5}\) M
Now we need to account for the presence of NaIO₃. Since NaIO₃ is a soluble ionic compound, it will dissociate completely in the water:
NaIO₃ (s) ⇌ Na⁺(aq) + IO₃⁻(aq)
The concentration of IO₃⁻ in the solution is therefore:
[IO₃⁻] = 0.285 M
However, we already know that [IO₃⁻] = [x], so we need to subtract the amount of IO₃⁻ that comes from NaIO₃ from the total [IO₃⁻]:
[IO₃⁻] = 0.285 M - x = 0.285 M - 5.48 x \(10^{-5}\) M = 0.2849 M
Therefore, the solubility of AgIO₃ in a 0.285 M solution of NaIO₃ is 5.48 x \(10^{-5}\) M.
b. The balanced chemical equation for the dissolution of La(IO₃)₃ in water is:
La(IO₃)₃ (s) ⇌ La³⁺(aq) + 3IO₃⁻(aq)
The Ksp expression for this reaction is:
Ksp = [La³⁺][IO₃⁻]³
As before, we can assume that the amount of La(IO₃)₃ that dissolves is x. Then:
[La³⁺] = x M
[IO₃⁻] = 3x M
Substituting these values into the Ksp expression gives us:
Ksp = x(3x)³ = 27x⁴
x = \((Ksp/27)^{(1/4)}\)
x = \((7.5 * 10^{-12/27})^{(1/4)}\) = 2.43 x \(10^{-4}\) M
Again, we need to account for the presence of NaIO₃. The concentration of IO₃⁻ in the solution is still 0.285 M, but now we have to divide by 3 to get the concentration of IO₃⁻ that comes from La(IO₃)₃:
[IO₃⁻] = 0.285 M / 3 - x = 0.095 M - 2.43 x \(10^{-4}\) M = 0.0948 M
Therefore, the solubility of La(IO₃)₃ in a 0.285 M solution of NaIO₃ is 2.43 x \(10^{-4}\) M.
c. Since the solubility of AgIO₃ is lower than the solubility of La(IO₃)₃ in a 0.285 M solution of NaIO₃, AgIO₃ is the more insoluble compound.
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a 17.21 gram sample of an organic compound containing c, h and o is analyzed by combustion analysis and 16.83 grams of co2 and 3.445 grams of h2o are produced. in a separate experiment, the molar mass is found to be 90.04 g/mol. determine the empirical formula and the molecular formula of the organic compound.
The empirical formula of the given organic compound is C2H2
The molecular formula of the given organic compound is C6H6, which is three times the empirical formula.
The empirical formula of the organic compound can be determined by finding the ratio of the elements in the compound from the combustion analysis results.
First, convert the CO2 and H2O produced to their corresponding elements (carbon and hydrogen) using their respective molecular weights:
• CO2: 16.83 g CO2 x (1 mol CO2/44.01 g CO2) = 0.382 mol CO2 = 0.382 mol C
• H2O: 3.445 g H2O x (1 mol H2O/18.015 g H2O) = 0.191 mol H2O = 0.191 mol H
The ratio of carbon to hydrogen in the sample can be determined as: 0.382 mol C / 0.191 mol H = 2
The empirical formula of the organic compound is C2H2.
The molecular formula of the organic compound can be determined by dividing the molar mass of the sample by the molar mass of the empirical formula: 90.04 g/mol ÷ 28.03 g/mol = 3.21
The molecular formula of the organic compound is C6H6, which is three times the empirical formula.
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Which statement best describes the chart? Heat was removed from the activation energy to create the product. Heat was added to create the product. The products have less energy than the reactants. The products have the same energy as the reactants.
Answer:
A. Heat … Get the answers you need, now! ... A. Heat was removed from the activation energy to create the product. ... C. The products have less energy than the reactants. D. The products have the same energy as the reactants.
Explanation:
Answer:
its B. Heat was added to create the product.
Explanation:
just took the test on edg2020 :)
PLEASE ANSWER ASAP!!! What are examples of Exothermic or Endothermic processes found at home?
Answer:
Explanation:
Example for Endothermic include melting ice cubes, cooking eggs, or baking breads.
Example for Exothermic include Burning candles, lighting match, or hot packs
Why is it necessary to research your experiment before starting it?
Answer: by researching the experiment, it helps you make sure you get everything right. If you didn't research it, there's a possibility you can get the experiment wrong.
Which organelle makes useable energy for the cell? What type of fuel did your ship need in order to work?
Answer:
Mitochondria -uses glucose!!
Explanation:
Explain why I2 is a solid, Br2 is a liquid but Cl2and F2 are gases even though they are all Halogens
I₂ is a solid, Br₂ is a liquid, while Cl₂ and F₂ are gases because of their increasing molecular size and decreasing strength of their intermolecular forces.
The main factor influencing the physical states of halogens is the strength of the intermolecular forces (Van der Waals forces) between their molecules.
As you move down Group 17 in the periodic table (from F₂ to I₂), the size and mass of the halogen molecules increase. Larger molecules have a greater number of electrons, leading to stronger dispersion forces (a type of Van der Waals forces) between molecules.
For I₂, these forces are strong enough to hold the molecules together in a solid form. For Br₂, the forces are slightly weaker but still strong enough to form a liquid. However, in Cl₂ and F₂, the forces are weaker, allowing the molecules to be in a gaseous state at room temperature.
In summary, the physical states of the halogens depend on the strength of their intermolecular forces, which is influenced by the size and mass of the molecules.
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An ionic bond occurs between what particles?
two neutral atoms
a positive and negative ion
two negative ions
two positive ions
Answer:
a positive and negative ion
Explanation:
An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. Ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal. A covalent bond involves a pair of electrons being shared between atoms.
Answer:
A positive and negative Ion. I took the test!
Explanation:
An ionic bond occurs between what particles?
two negative ions
a positive and negative ion
two neutral atoms
two positive ions
A student is building an electrical circuit.
Which material should she choose for the wires, and why?
O A. A metal such as copper, because its atoms have very mobile
electrons
O B. A metalloid such as germanium, because only some of its atoms
have mobile electrons
O c. A noble gas such as krypton, because its atoms are far apart and
it is nearly inert
O D. A nonmetal such as carbon, because its atoms have tightly bound
electrons
Answer:
A a metal such as copper
Explanation:
Answer:
A metal such as copper, because its atoms have very mobile electrons
Explanation:
PLEASE HELP ILL GIVE BRAINLIST!!!
How does the energy of the different waves of the spectrum vary with frequency? With wavelength?
Answer:
The greater the frequency means the more energy transferred.
The greater the wavelength means the less energy transferred
A hydrate of zinc nitrate has the formula Zn(NO3)2 . xH2O. If the mass of 1 mol of anhydrous zinc nitrate is 63.67% of the mass of 1 mol of the hydrate, what is the value of x?
MM Zn(NO₃)₂ = 189.36 g/mol
mass 1 mol Zn(NO₃)₂ = 189.36 g
mass hydrate = 100 / 63.67 x 189.36 = 297.409 g
mass 1 mol hydrate = 297.409 g
MM hydrate = 297.409 g/mol
MM hydrate = MM Zn(NO₃)₂ + MM xH₂O
297.409 = 189.36 + x(18)
x = 6
Gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane (CH4) and liquid water
When gaseous carbon monoxide reacts with hydrogen gas to form gaseous Methane and liquid water we call it a displacement reaction.
The chemical equation that will take place on the combination of carbon monoxide and hydrogen gas is given as,
CO+H₂ → CH₄ + O₂
The reason why calling this reaction as a displacement reaction is because the oxygen from the carbon monoxide is being replaced by the hydrogen gas and the formation of Methane is taking place separated from the carbon monoxide molecule is left out to remain in the form of liquid water.
This reaction can also be stated as a redox reaction because the oxidation of the hydrogen molecule and the reduction of the carbon monoxide molecule is taking place in this reaction simultaneously.
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Which liquid substance would evaporate most quickly in the open air at 20°C? Explain our answer
Answer:
mp -5; bp 30
Explanation:
That will be a liquid at room temperature, and it will evaporate quite quickly. Room temperature is generally considered 20 degrees Celsius. Choice B melts from a solid to a liquid at -5 degrees, so it's a liquid at room temperature as long as the boiling point is higher than 20 degrees.
What volume of a 2. 000 m hcl solution is needed to generate 100. 0 ml of a 0. 1000 m solution of hcl?.
The supplied statement states that 5 drops of HCl is needed to make a 100ml solution containing 0.1M.
What is the solution described?Any combination of one or maybe more solutes that have been hydrated is referred to as a solution. To create a homogenous mixture, a solute must dissolve in a solvent. To create a homogenous mixture, a solute must dissolve in a solvent.
Briefing:
Given that now the molar concentration of the HCl solution is 2M, a solution with the a molar concentration of 0.1M needs to be generated in a volume of 100ml. We now need to calculate the volume that will be required to make the 100ml 0.1M solution. The formula below must be used for that.
M₁V₁ = M₂V₂
When we enter the specified values through into formula, we obtain
2 x V₁ = 0.1 x 100
2V₁ = 10
V₁ = 10/2
V₁ = 5ml
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Select the options that correctly reflect the steps required to calculate the molar solubility of PbCl2 in 0.15 M NaCl if Ksp for PbCl2 = 2.4 x 10-4.
The molar solubility of PbCl₂ in 0.15 M NaCl is 0.0026 M.
To calculate the molar solubility of PbCl₂ in 0.15 M NaCl, the following steps should be taken:
1. Write the balanced chemical equation for the dissolution of \(PbCl_2\) in water:
PbCl₂(s) ⇌ Pb²⁺(aq) + 2Cl⁻ (aq)
2. Write the expression for the solubility product constant (Ksp) for \(PbCl_2\):
Ksp = [Pb²⁺][Cl⁻]²
3. Substitute the given value of Ksp and the unknown concentration of Pb²⁺ into the Ksp expression:
2.4 * 10⁻⁴ = x[0.15 + x]²
Here, x represents the molar solubility of PbCl₂.
4. Simplify the equation by assuming that the concentration of NaCl (0.15 M) does not change significantly upon addition of PbCl₂. This allows us to neglect the x term in the denominator:
2.4 * 10⁻⁴ = x[0.15}²
5. Solve for x, the molar solubility of PbCl₂:
x = √(2.4 * 10⁻⁴ / 0.15²) = 0.0026 M
Therefore, the molar solubility of PbCl₂ in 0.15 M NaCl is 0.0026 M.
In summary, to calculate the molar solubility of PbCl₂ in 0.15 M NaCl, the solubility product constant (Ksp) expression is used with the given value of Ksp and unknown concentration of Pb²⁺. The concentration of NaCl is assumed to be constant, and the resulting equation is solved for the molar solubility of PbCl₂.
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Complete Question:
Select the options that correctly reflect the steps required to calculate the molar solubility of PbCl2 in 0.15 M NaCl if Ksp for PbCl2 = 2.4 x 10-4.
Three students were asked to weigh 3.5 g of NaCl. The recorded readings were 3.4 g, 3.6 g, and 3.3 g. How can these readings BEST be interpreted? + or - 0.3 g is considered the range for precise measurements in this instance.
A. not accurate and not precise
B. not accurate but precise
C. accurate and precise
D. accurate but not precise
The reading from the three students can best be interpreted as not accurate but precise.
What are accuracy and precision?In measurements, accuracy is described as the closeness of a single or average measurement to the true value of what is measured.
On the other hand, the precision of measurements refers to the closeness of repeated measurements to each other.
Now, let us look at the readings from the three students.
The range of the reading can be calculated as:
3.6 - 3.3 = 0.3
Since a range of + or -0.3 is considered to be precise, the readings from the students is said to be precise.
Let us look at the average of the readings:
3.3 + 3.4 + 3.6/3 = 3.4 g
Since the actual weight of the salt is 3.5 g, the reading from the student is said to be inaccurate.
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What will happen to the gas molecules in the container as thermal energy is applied?
a-The movement, kinetic energy, and pressure of the molecules will increase.
b-The movement, kinetic energy, and pressure of the molecules will decrease.
c-The movement, kinetic energy, and pressure of the molecules will stay the same.
d-The movement of the molecules will increase, but the kinetic energy and pressure of the molecules will stay the same.
PLZ HELP I HAVE A BENCHMARK TEST!!!!
Decreased because we all know what happen if we put it with thermal energy
When thermal energy is supplied to gas molecules in the container, the movement, kinetic energy, and pressure of the molecules will increase.
Gas molecules are in constant random motion. They collide frequently which other and the walls of the container.
When thermal energy is applied, the gases move faster (acquire higher velocity). The kinetic energy also increases accordingly.
As a result of the increase in thermal energy, gas molecules collide with the walls of the container more frequently (pressure increases).
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When a hydrogen atom is part of a molecular structure, it is always a ___________ atom.
Answer:
terminal
Explanation:
When a hydrogen atom is part of a molecular structure, it is always a terminal atom.
OK I dont need an answer for this I just need help understanding what the heck the question means :
Do the businesses serve as exemplars of businesses that comply with the general rules and regulations that govern finance and marketing? Note two examples for each business.
Answer:
affected business many example
Usually scientists do not specialize and study one aspect of the
natural world, but will focus on many aspects to understand
why and how things happen.
TRUE
FALSE
Why is aspirin sometimes buffered? Will give brainliest.
Answer: the aspirin also contains a buffering agent—usually MgO—that regulates the acidity of the aspirin to minimize its acidic side effects.
Explanation:
Because the acid residences of aspirin may be complex, many aspirin manufacturers provide a "buffered aspirin" form of the drug. In these cases, the aspirin additionally includes a buffering agent-normally MgO-that regulates the acidity of the aspirin to minimize its acidic aspect consequences.
Why may a buffer be added to aspirin?Buffering agents are utilized in tablet formulations to grow the dissolution and absorption of vulnerable acid pills together with salicylic acid, aspirin, and p-aminosalicylic acid as well as to lower gastric infection of lively ingredients.
Why is buffered aspirin not a buffer?So-called "buffered aspirin" isn't surely a buffer, because it does no longer face up to acids and bases. it's miles sincerely aspirin mixed with a primary compound, consisting of magnesium carbonate or aluminum hydroxide, which neutralizes some belly acid.
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How many grams are equal to 413kg ?
Answer:
413000 grams
Explanation:
from model
Under what conditions will a precipitate not form when an aqueous solution of AgNO3 is added to an aqueous solution of NaCl
When an aqueous solution of AgNO₃ is added to an aqueous solution of NaCl, a precipitate of AgCl typically forms. However, there are certain conditions under which a precipitate may not form.
One condition is if the concentration of either the AgNO₃ or NaCl solution is too low. In order for a precipitate to form, the concentration of both ions must be high enough to exceed their solubility product constant (Ksp). If the concentration of one or both solutions is too low, then the ions may not reach the saturation point necessary for precipitation.
Another condition is if the temperature of the solution is too high. As the temperature increases, the solubility of most solids increases as well. Therefore, if the temperature is high enough, the solubility of AgCl may exceed its Ksp, and a precipitate will not form.
Additionally, if the solution is agitated vigorously or stirred too quickly, the Ag⁺ and Cl⁻ ions may not have enough time to combine and form a solid precipitate. The ions need time to come into contact with one another in order for the AgCl crystals to form.
Finally, if there are impurities present in either solution, they may interfere with the formation of the precipitate. For example, if there are other anions present in the NaCl solution, they may compete with the Cl⁻ ions for the Ag+ ions, leading to the formation of other compounds instead of AgCl.
In conclusion, the conditions under which a precipitate will not form when an aqueous solution of AgNO₃ is added to an aqueous solution of NaCl include low concentrations of either solution, high temperatures, overly-agitated solutions, and the presence of impurities.
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1. How many grams of sodium chloride is produced when 3.4 g of sodium reacts with 8.9 g of chlorine in
this balanced equation?
2Na+ Cl₂ → 2NaCl
The Answer to the question is 14 grams approximately.
Atomic mass of Na = 23 u
Given mass of Na = 3.4 gm
Moles of Na = given mass of Na / molar mass of Na
Moles of Na = 3.4 / 23 moles = 0.15 moles approximately
So, 0.15 moles of Na approximately
Molar mass of Cl₂ = 35.45 × 2 = 70.9 u
Given mass of Cl₂ = 8.9 gm
Moles of Cl₂ = given mass of Cl₂ / molar mass of Cl₂
Moles of Cl₂ = 8.9 / 70.9 moles = 0.12 moles approximately
So, 0.12 moles of Cl₂ approximately
Balanced chemical equation
2Na + Cl₂ → 2NaCl
Ratio of Moles to Stoichiometric coefficients
0.15/2 0.12/1
0.075 < 0.12
So, as ratio of Na is less then it will be our Limiting reagent.
Which means that Cl₂ will consume complete in the reaction.
It is clear from the reaction that 1 moles of Cl₂ are making 2 mole of NaCl
1 moles of Cl₂ → 2 mole of NaCl
0.12 moles of Cl₂ → 2 × 0.12 mole of NaCl
0.12 moles of Cl₂ → 0.24 mole of NaCl
So, 0.12 moles of Cl₂ will make 0.24 mole of NaCl
0.24 mole NaCl = mass formed NaCl / molar mass of NaCl
mass formed NaCl = 0.24 × molar mass of NaCl
mass formed NaCl = 0.24 × 58.44
mass formed NaCl = 0.24 × 58.44
mass formed NaCl = 14 grams (approximately)
14 grams of NaCl will be formed.
So, approximately 14 grams NaCl is formed from 3.4 grams of Na and 8.9 grams of Cl.
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The mass of sample X is 20.Og. It was placed in a graduated cylinder and the water level rose from A (14 mL) to B (19 mL). What is the density of sample X? Pay close attention to significant figures. g/mL
The density of sample X is 4 g/ml.
The given parameters;
Mass of sample X = 20 gInitial volume of water before the sample was placed = 14 mlFinal volume of water after the sample was placed = 19 mlThe volume of the sample X is the increase in the volume of water after it was placed in the cylinder.
Volume of sample X = 19 ml - 14 ml = 5 mlMass of sample of X = 20 gThe density is obtained by dividing the mass of sample X by its volume as shown below;
\(Density = \frac{mass}{volume} = \frac{20}{5} = 4 \ g/ml\)
Thus, the density of sample X is 4 g/ml.
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Why do you think the size of a white dwarf affects its visual luminosity?
Reward
_________
Brainliest
Thanks
Points
_________
Thank you so much!
Answer:
the bigger the size the more easier to see from a distance and the smaller the harder to see.
Explanation:
starting with lead(II)oxide describe how you would prepare a solid sample of lead(II)Carbonate
The reaction involved is the reaction of PbO with sodium carbonate (Na2CO3) to produce lead(II) carbonate (PbCO3) and sodium oxide (Na2O).
To prepare a solid sample of lead(II) carbonate, we can start with lead(II) oxide (PbO) as the starting material. The chemical equation for the reaction is:
PbO + Na2CO3 → PbCO3 + Na2O
To carry out the reaction, we first need to weigh out the required amount of PbO and Na2CO3 based on the stoichiometry of the reaction. The PbO and Na2CO3 are then mixed thoroughly and placed in a crucible. The mixture is heated in a furnace at a temperature of around 600-700°C for a few hours until the reaction is complete and the mixture has turned into a solid mass.
Once the reaction is complete, the crucible is removed from the furnace and allowed to cool to room temperature. The solid mass of PbCO3 is then carefully removed from the crucible, crushed to a fine powder, and stored in an airtight container for further use. This method is a simple and efficient way to prepare a solid sample of lead(II) carbonate from lead(II) oxide.
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Explain how a mutation becomes an adaptation.
Answer:
An adaptation occurs if a mutation helps an individual survive and reproduce.
Explanation:
Over generations, the mutation will become more common. An adaptation occurs if a mutation isn't passed on to offspring. Hope this helps! xx
Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (Ka for HF is 6.8×10−4.)
Part A: 0.230 M
Part B: 0.0470 M
Part C: 0.0260 M
For Part A. pH of 2.68, For Part B pH of 3.22, For Part C pH of 3.51.
To determine the pH of an HF solution of each concentration, we first need to write out the equation for the dissociation of HF: HF + H2O ⇌ H3O+ + F-. The Ka value for HF is 6.8×10−4. We can use the formula Ka = [H3O+][F-]/[HF] to solve for [H3O+].
For Part A, plugging in [HF] = 0.230 M and Ka = 6.8×10−4, we get [H3O+] = 2.1×10−3 M. Taking the negative logarithm, we get a pH of 2.68.
For Part B, plugging in [HF] = 0.0470 M and Ka = 6.8×10−4, we get [H3O+] = 6.0×10−4 M. Taking the negative logarithm, we get a pH of 3.22.
For Part C, plugging in [HF] = 0.0260 M and Ka = 6.8×10−4, we get [H3O+] = 3.1×10−4 M. Taking the negative logarithm, we get a pH of 3.51.
We can make the simplifying assumption that x is small when [HF] is much larger than Ka. However, for Part C, where [HF] is close to Ka, we cannot make this assumption and must solve for x using the quadratic formula.
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what are the 5 benefits of changing colour/paint of the
laboratories and auditoriums?
Answer:
AestheticsImproved Focus and ConcentrationStress ReductionPositive ImpressionIncreased CreativityExplanation:
What is the difference between heat of formation and heat of reaction? Give examples and units
Answer:
The main difference between the heat of formation and heat of reaction is that heat of formation is the amount of energy either absorbed or released during the formation of a compound whereas heat of reaction is the amount of energy either absorbed or released during any chemical reaction.