the infinite, straight wire shown in the accompanying figure carries a current the rectangular loop, whose long sides

,∆FGH reflected across the x-axis and then translated 3 units to the right, the result is ∆F'G'H'.Statement 1 is false. Statement 2 is true. Statement 3 is false.

∆FGH is reflected across the x-axis and then translated 3 units to the right. The result is ∆F'G'H'.Statement 1: If F is reflected across the x-axis, its image is (-x, y)FalseThis statement is false. If F is reflected across the x-axis, its image is (x, -y).Statement 2: If G is reflected across the x-axis, its image is (-x, y)TrueThis statement is true. If G is reflected across the x-axis, its image is (x, -y).Statement 3: The image of H after the translation is 3 units to the left of H'.FalseThis statement is false. The image of H after the translation is 3 units to the right of H'.Therefore, ∆FGH reflected across the x-axis and then translated 3 units to the right, the result is ∆F'G'H'.Statement 1 is false. Statement 2 is true. Statement 3 is false.

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Answer:

118/25 as a fraction hope it helps

Answer:

1 72/100 or 1 18/25 as simplified.

Step-by-step explanation:

100% is 100/100. 172/100 would be the fraction for this, but it is an improper fraction.

Answer:

B

Step-by-step explanation:

If it’s for khan positive , negative, negative, positive

Answer:

f(x)=y

5x+4=y

5x=y-4

x=y-4/5

inverse of x=(x-4)/5

Answer:

b=69 degrees

Step-by-step explanation

Use the remote interior angle theorem which states that the sum of the two remote interior angles is equal to the exterior angle. Basically, b=(b-36)+(b-33). That will give you b=2b-69. Then b=69. There's ur answer.

These forecasts illustrate bias.

Therefore, these forecasts illustrate bias.

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Because A-CAC activities tend to blow molten metal considerable distances, it is important to station a Fire watch in the A-CAC work area.

The A-CAC method is primarily used to gouge weld grooves and prepare cracks for welding.

The ACAC technique employs compressed air jets to blast molten metal away.

When compared to shielded metal arc welding electrodes of the same size, the currents employed with ACAC electrodes are.

Hence, it is right to conclude that Because A-CAC activities tend to blow molten metal considerable distances, it is important to station a Fire watch in the A-CAC work area.

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Answer:

? = 11.3

Step-by-step explanation:

This figure is a parallelogram which indicates that TW is parallel as well as congruent to UV, so;

TW ≅ UV

So if TW = 11.3 then, so would be UV

Hope this helps!

The main difference between the 2D and 3D coordinate systems is that the 3D coordinate system adds a third axis (Z) to the two axes of the 2D coordinate system.

A coordinate system is a two-dimensional or three-dimensional system which is used to identify the location of a point or object in the space. It is represented by a set of axes, which are perpendicular and equally spaced from each other to form a grid-like structure. The coordinates of a point or object are determined by the intersection of the two or three axes. Common coordinate systems used in mathematics and science include the Cartesian, polar, and spherical coordinate systems.

A 2D coordinate system is a system in which two axes (X and Y) are used to define a point in a two-dimensional space. This system is used to describe the position of a point in relation to the origin, which is located at the intersection of the two axes. The two axes form a coordinate plane, which provides a visual representation of the system.

A 3D coordinate system is a system in which three axes (X, Y, and Z) are used to define a point in a three-dimensional space. This system is used to describe the position of a point in relation to the origin, which is located at the intersection of the three axes. The three axes form a coordinate space, which provides a visual representation of the system.

This third axis allows points in the 3D coordinate system to be represented in the third dimension. Additionally, the 3D coordinate system provides a more detailed representation of points, as it can represent points in all three dimensions.

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Answer:

< B = 180-30-65=85°

< E = 85°

< D = 30°

< C = 65°

BC = 20/35 × 28 = 16

Answer:

<D = 30

< C = 65

<B = <E = 85

16 = BC

Step-by-step explanation:

ABC ~ Triangle DEF

<A = <D = 30

< C = <F = 65

Since they are similar triangles

A+ C + B = 180 since the angles of a triangle = 180

30+65+B =180

95+ B = 180

<B = 180 -95 = 85

<B = <E = 85

The triangles are similar so the sides are proportional

AB      BC

----  = ---------

DE      EF

20      BC

----  = ---------

35      28

Using cross products

20*28 = 35 BC

Divide each side by 35

20*28/35 = 35/35 BC

16 = BC

The probability that at least 25 of the 29 customers have looked at their credit score in the past six months is:

P(X ≥ 25) = sum(P(X = i)) i = 25 to 29

This is a question of probability and statistics, specifically in the area of binomial distributions. The probability of a single event can be calculated using the binomial probability formula:

P(X = k) = (n choose k) * p^k * (1-p)^(n-k)

X = the number of successful outcomes (in this case, the number of customers who have looked at their credit score in the past six months)

k = the number of successful outcomes we want to know the probability of (in this case, 25)

n = the total number of trials or customers (in this case, 29)

p = the probability of a successful outcome (in this case, 0.67 or 67%)

        P(X ≥ k) = sum(P(X = i)) i = k to n

        P(X ≥ 25) = sum(P(X = i)) i = 25 to 29

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Answer:

29.) y = -1.5x - 20

30.) y = 6 - 3x

Step-by-step explanation:

29.) For parallel lines; M1 = M2

put the equation in the form y = mx + c

the equation becomes 2y = 14 - 3x

therefore y = 7 - 1.5x.

For the points, introduce another point; (x,y) and the initial (-6,-11)

(y - - 11) ÷ ( x - - 6) = -1.5

y+11 = -1.5x - 9

y= -1.5x - 20

30.) still following the same procedure, only that M1 × M2 = -1

M1 = 1/3, M2 = -3

(y + 9)/(x - 5) = -3

y + 9 = 15 - 3x

y = 6 - 3x

Answer:

true

Step-by-step explanation:

5/8 + 1/3= 23/24

We need to get a common denominator of 24

5/8 *3/3 = 15/24

 1/3*8/8= 8/24

15/24 + 8/24 = 23/24

This is true

Answer:

Step-by-step explanation:

\( \huge \boxed{\mathbb{QUESTION} \downarrow}\)

\( \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}\)

\( \sf \: 2 \left( 4- \frac{ 1 }{ 3 } u \right) = -u+2\)

Use the distributive property to multiply 2 by \(\sf 4-\frac{1}{3}u\).

\( \sf \: 8+2\left(-\frac{1}{3}\right)u=-u+2 \)

Express \(\sf2\left(-\frac{1}{3}\right)\) as a single fraction.

\( \sf \: 8+\frac{2\left(-1\right)}{3}u=-u+2 \)

Multiply 2 and -1 to get -2.

\( \sf \: 8+\frac{-2}{3}u=-u+2 \)

Add u to both sides.

\( \sf \: 8-\frac{2}{3}u+u=2 \)

Combine \(\sf-\frac{2}{3}u\) and u to get \(\sf\frac{1}{3}u\).

\( \sf \: 8+\frac{1}{3}u=2 \)

Subtract 8 from both sides.

\( \sf\frac{1}{3}u=2-8 \)

Subtract 8 from 2 to get -6.

\( \sf\frac{1}{3}u=-6 \)

Multiply both sides by 3, which is the reciprocal of 1/3.

\( \sf \: u=-6\times 3 \)

Multiply -6 and 3 to get -18.

\( \boxed{ \boxed{\bf \: u=-18 }}\)

Answer:

D

Step-by-step explanation:

Answer:

x > 8

Step-by-step explanation:

-6x + 18 < 2 - 4x

-2x + 18 < 2

-2x < -16

x > 8

Answer:

45%

Step-by-step explanation:

Counting the marbles, there are 5 green, 6 blue and 9 red.

Which means the odds of drawing a red to a non red are 11:9

In fraction form that would be 9 marbles out of 20 are red. 9/20

Since the fraction cannot be simplified, we can go to decimal form.

9/20=.45

.45=45%

The answer is 45%.

Answer:

45%

Step-by-step explanation:

Total = 20

Red = 9

9/20 = 0.45

Therefore 45 % is the correct option :))

G is abelian, then the argument is even simpler.

G is abelian, we have \((h_1k_1)(h_2k_2) = h_1h_2k_1k_2 = h_2h_1k_2k_1 = (h_2k_2)(h_1k_1)\),

HK is closed under the group operation.

The statement "if H and K are subgroups of a group G, then HK is a subgroup of G", we need to check if HK satisfies the three criteria for being a subgroup:

Closure under the group operation, the existence of an identity element, and the existence of inverse elements.
First, let's consider the case where G is not necessarily abelian.

HK is closed under the group operation, we need to show that for any \(h_1, h_2\) in H and \(k_1, k_2\) in K, the element \((h_1k_1)(h_2k_2)\) is also in HK.

The fact that H and K are subgroups to write \(h_1h_2\)in H and \(k_1k_2\) in K, and then use the associativity of the group operation to write\((h_1k_1)(h_2k_2) = h_1(h_2k_1)k_2\).

Since H and K are subgroups, \(h_2k_1\) is in HK, and therefore \((h_1k_1)(h_2k_2)\) is in HK.
Next, we need to show that HK has an identity element.

Since H and K are subgroups, they both contain the identity element of G, which we'll denote by e.

Then, for any h in H and k in K, we have \(h k e = h (k e) = h k\), which shows that HK contains the identity element.
HK has an inverse in HK. Let hk be an element of HK.

Since H and K are subgroups, \(\(h^{-1}\)\)is in H and \(k^{-1}\) is in K.

Then, \((hk)^{-1 }= k^{-1}h^{-1}\), which is in HK since H and K are subgroups.
H and K are subgroups of a group G, then HK is a subgroup of G, regardless of whether G is abelian or not. .  

The identity element of HK is still the same as in the non-abelian case, and inverses can be computed as before.
H and K are subgroups of a group G, then HK is always a subgroup of G, regardless of whether G is abelian or not.

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Answer:

Rectangle

Step-by-step explanation:

First, we gotta graph it!

It's down below.

Now, what shape is that?

It's a rectangle!

Answer:

Step-by-step explanation:

43 students in drama (D)

43D

52 doing dance

If

21 students do both drama and

dance, how many students are at

the meeting each month given

that everyone attend?

43+52=95

95+21+21=137 students are at the meeting.

Answer: $117

Step-by-step explanation: 1st subtract 3 then divide by 2 then subtract 3 again and divide by 2 again

The nth derivative of f(x) = e^(-yx) - 1 is (-1)^(n+1)y^ne^(-yx).

(a) Let's find the first few derivatives of f(x) = e^(-x^n):

f(x) = e^(-x^n)

f'(x) = -nx^(n-1)e^(-x^n)

f''(x) = (-n(n-1)x^(2n-2) + nx^n)e^(-x^n)

f'''(x) = (n(n-1)(2n-2)x^(3n-3) - 2n(n-1)*x^(2n-1))e^(-x^n)

From these first few derivatives, we can observe the pattern that the nth derivative is given by:

f^(n)(x) = e^(-x^n)P_n(x)

where P_n(x) is a polynomial of degree n-1 in x, given by the recurrence relation:

P_1(x) = -n

P_k(x) = -n(k-1)P_(k-1)(x) + nx^n(k-1)!

Therefore, the nth derivative of f(x) = e^(-x^n) is e^(-x^n)*P_n(x).

(b) Let's find the first few derivatives of f(x) = e^(-yx) - 1:

f(x) = e^(-yx) - 1

f'(x) = -ye^(-yx)

f''(x) = y^2e^(-yx)

f'''(x) = -y^3*e^(-yx)

From these first few derivatives, we can observe the pattern that the nth derivative is given by:

f^(n)(x) = (-1)^(n+1)y^ne^(-yx)

Therefore, the nth derivative of f(x) = e^(-yx) - 1 is (-1)^(n+1)y^ne^(-yx).

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Answer:

$19

Step-by-step explanation:

first subtract 3 from 51 and that =48

then divide 48 between the 3 people and that equals 16

lastly add Kadens tip of 3$ which will equal $19.

Answer:

if you break it down into stages it flows logically and clearly. Try minusing starting with the largest number (or the smallest- however you prefer):

665.25 - 600 = 65.25

65.25 - 30 = 35.25

35.25 - 0.75 = 34.50

Final answer is: 34.50

The system of linear equations has no solutions for any value of k except when k = 2, where it has infinitely many solutions.

(a) To reduce the augmented matrix for the system of linear equations to row-echelon form, we can write the system of equations as:

2 - y = kx

-y = k

To eliminate y in the first equation, we can multiply the second equation by (-1) and add it to the first equation:

(2 - y) - (-y) = kx - k

2 = kx - k

This gives us a new system of equations:

2 = kx - k

Now, we can represent this system in augmented matrix form:

[1 -k | 2]

(b) To find the values of k, we can examine the augmented matrix.

If the system has no solutions, it means that the rows of the augmented matrix result in an inconsistent equation, where the last row has a leading nonzero entry. In this case, for the system to have no solutions, the augmented matrix should have a row of the form [0 0 | c], where c ≠ 0. In our case, the augmented matrix [1 -k | 2] doesn't have this form, so there are no values of k that lead to no solutions.

If the system has exactly one solution, the augmented matrix should be in row-echelon form, with each row having at most one leading nonzero entry. In this case, the augmented matrix should not have any rows of the form [0 0 | c], where c ≠ 0. In our case, the augmented matrix can be reduced to row-echelon form as follows:

[1 -k | 2]

From this form, we can see that there are no restrictions on the value of k. For any value of k, the system will have exactly one solution.

If the system has infinitely many solutions, the augmented matrix should have at least one row of the form [0 0 | 0]. In our case, the augmented matrix can be reduced to:

[1 -k | 2]

From this form, we can see that if k = 2, the last row becomes [0 0 | 0]. Therefore, for k = 2, the system will have infinitely many solutions.

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The circumference of the circle in terms of π whose radius is given would be = 63π. That is option D.

To calculate the circumference of a circle, the formula that should be used would be given below.

That is;

circumference of circle= 2πr

The radius = 31½

circumference = 2×π × 31½

= 2×π× 63/2

= 63π

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The area of kite ABCD is equal to half the product of the sum of its diagonals and the height between them.

Since kite ABCD is divided into two triangles by its diagonals, we can find the area of the kite by finding the sum of the areas of these two triangles.

Let AC and BD be the diagonals of the kite, intersecting at point E. Then triangle ABE and triangle CDE are the two triangles formed by the diagonals.

The area of a triangle can be found using the formula: Area = (base x height) / 2

For triangle ABE, the base is AB and the height is the distance from E to the line containing AB. Similarly, for triangle CDE, the base is CD and the height is the distance from E to the line containing CD.

Since the diagonals of a kite are perpendicular and bisect each other, the distance from E to the line containing AB is the same as the distance from E to the line containing CD.

Therefore, the heights of the two triangles are equal.

So, we can find the area of ABCD as follows:

Area of ABCD = Area of triangle ABE + Area of triangle CDE

= (AB x height)/2 + (CD x height)/2

= (AB + CD) x height / 2

Therefore, the area of kite ABCD is equal to half the product of the sum of its diagonals and the height between them.

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Answer:

option A : about 2.8 units

Step-by-step explanation:

To find the distance from P to RQ , Find the distance from ( 1 , 1) to (3 , 3).

 \(Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

                 \(= \sqrt{(3-1)^2 + (3-1)^2}\\\\= \sqrt{2^2 + 2^2 }\\\\= \sqrt{4 + 4 }\\\\= \sqrt{8}\\\\=2\sqrt{2}\)

                 = 2.83 units

Answer:

A

Step-by-step explanation:

Remark

The distance you want is the point P to the (3,3). Then two lines meet as these two do, the shortest distance is the right angle distance. And that is how distance is defined.

Formula

d = sqrt( (x2 - x1)^2 + (y2 - y1)^2  )

Givens

x2 = 1

x1 = 3

y2 = 1

y1 = 3

Solution

d = sqrt( (1 - 3)^2 + (1  - 3)^2 )

d = sqrt( (-2)^2 + (-2)^2 )

d = sqrt ( 4 + 4)

d = sqrt(8)

d = 2√2

d = 2.8