Answer:
its B y=e^x+3
Step-by-step explanation:
Mark me as brainliest!
∠A and ∠B are complemntry angles. If m∠A = (3x+18) and m∠B = (2x+17) then find the measure of ∠A
Work Shown:
Complementary angles add to 90 degrees.
A+B = 90
(3x+18)+(2x+17) = 90
5x+35 = 90
5x = 90-35
5x = 55
x = 55/5
x = 11
Then we can determine each angle:
angle A = 3x+18 = 3*11+18 = 33+18 = 51 degrees is the final answerangle B = 2x+17 = 2*11+17 = 22+17 = 39 degreesAs a check: A+B = 51+39 = 90 to confirm the answer.
ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.
Answer:
A. x - 3
Step-by-step explanation:
Set it up like this:
(3x - 2) - (2x + 1)
Combine like terms:
3x - 2 - 2x - 1
3x - 2x = x
-2 - 1 = -3
Put it together:
x - 3
Classify the real numbers as rational or irritational numbers
Answer:
god loves you <3 .
Step-by-step explanation:
Solve for the value of q
Answer:
\(q=45\)
Step-by-step explanation:
Notice that \((q+2)^{\circ}\) and \((3q-2)^{\circ}\) form a linear pair, that is, they sum to \(180^{\circ}\) as follows:
\((q+2)^{\circ}+(3q-2)^{\circ}=180^{\circ}\\(q+2+3q-2)^{\circ}=180^{\circ}\\(4q)^{\circ}=180^{\circ}\\4q=180\\q=\frac{180}{4}\\q=45\)
A field is in the shape of a square. The length of the field is 5x^3y^5. What is the area of the field in terms of x and y? Write the variables in alphabetical order.
How would I go about solving this? I’m completely lost, help would be very much appreciated.
The area of the square field, given that the length is \(5x^3y^5\), is found by squaring the length. The area then becomes \(25x^6y^10\).
Explanation:The field is a square, so all the sides have the same length. Given that the length is \(5x^3y^5\), the area of a square equals the length of one side squared. So to find the area of the square, you square the length \((5x^3y^5)\) which is \((5x^3y^5)^2\)
The formula to square a binomial \((a+b)^2\) is a² + 2ab + b². To square \((5x^3y^5)^2\), you may square each term separately. 5² = 25, (x³)² = \(x^6\) and \((y^5)\)² =\(y^{10\). Now, multiply these results together: \(25x^6y^10\). This is the area of the field in terms of x and y, written in alphabetical order.
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Answer:
25x⁶y¹⁰
Step-by-step explanation:
You want the area of a square that has a side length of 5x³y⁵.
Rules of exponentsThe relevant rules of exponents are ...
(ab)^c = (a^c)(b^c)
(a^b)^c = a^(bc)
AreaThe area of a square is the square of the side length:
A = s²
For the given square, the area is ...
A = (5x³y⁵)² = (5²)(x³)²(y⁵)² = 25(x⁶)(y¹⁰)
The area of the square field is 25x⁶y¹⁰.
__
Additional comment
An exponent signifies repeated multiplication:
x³ = x·x·x
The square of that will be ...
(x³)² = (x·x·x)·(x·x·x)
The outside exponent tells you the value inside parentheses is multiplied by itself that many times. An exponent can be used to represent that product: x⁶.
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share £54 into the ratio 1:3
Answer:
£13.5
£40.5
Step-by-step explanation:
Let the amount of shares be x and 3x
Therefore,
\(x + 3x = 54 \\ \\ 4x = 54 \\ \\ x = \frac{54}{4} \\ \\ x = 13.5 \\ \\ 3x = 3 \times 13.5 = 40.5\)
A large company event was held in a park on a hot day. Afterward, many of the employees got sick. Some blamed the potato salad. To investigate, a random sample of 20 sick employees and a random sample of 20 non-sick employees are selected. Each selected individual is asked if they ate the potato salad. The results are displayed in the table.
Management would like to know if there is convincing evidence that the distribution of responses about eating the potato salad differs for all employees who are sick versus those who are not sick. What are the appropriate hypotheses for this test?
H0: There is no difference in the distribution of responses among those who are and are not sick.
Ha: There is a difference in the distribution of responses among those who are and are not sick.
H0: There is a difference in the distribution of responses among those who are and are not sick.
Ha: There is no difference in the distribution of responses among those who are and are not sick.
H0: There is no difference in the distribution of responses for the 20 employees who are sick and the 20 employees who are not sick.
Ha: There is a difference in the distribution of responses for the 20 employees who are sick and the 20 employees who are not sick.
H0: There is a difference in the distribution of responses for the 20 employees who are sick and the 20 employees who are not sick.
Ha: There is no difference in the distribution of responses for the 20 employees who are sick and the 20 employees who are not sick.
The appropriate hypotheses for this test are: H0: There is no difference in the distribution of responses. Ha: There is a difference in the distribution of responses.
The chosen hypotheses are based on the objective of the investigation, which is to determine if there is convincing evidence that the distribution of responses about eating the potato salad differs between employees who are sick and those who are not sick.
The null hypothesis (H0) assumes that there is no difference in the distribution of responses about eating the potato salad between the sick and non-sick employees. This means that the proportion of employees who ate the potato salad would be the same in both groups, and any observed difference in the distribution of responses is due to random chance or factors unrelated to being sick or not sick.
On the other hand, the alternative hypothesis (Ha) proposes that there is a difference in the distribution of responses about eating the potato salad between the sick and non-sick employees. This suggests that the proportion of employees who ate the potato salad would be significantly different in the two groups, indicating a possible association between consuming the potato salad and getting sick.
By formulating these hypotheses, the investigation aims to evaluate whether the data provides convincing evidence to reject the null hypothesis in favor of the alternative hypothesis, indicating a meaningful relationship between eating the potato salad and falling sick.
Therefore, the correct answer is:
H0: There is no difference in the distribution of responses about eating the potato salad among those who are and are not sick.
Ha: There is a difference in the distribution of responses about eating the potato salad among those who are and are not sick.
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HoW in THe WoRld do I solVE THIs MAth PRoblEM 5a+2/3= -1/6 (the 1/6 sixth fraction is all negative)
Answer:
Subtract
23
\frac{2}{3}32
from both sides of the equation
5+23=−16
5a+\frac{2}{3}=-\frac{1}{6}5a+32=−61
5+23−23=−16−23
The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and 128 m high. The parabola y equals 0.00035 x squared gives a good fit to the shape of the cables, where StartAbsoluteValue x EndAbsoluteValue less than or equals 605, and x and y are measured in meters. Approximate the length of the cables that stretch between the tops of the two towers.
Answer:
The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Step-by-step explanation:
The equation of the parabola is:
\(y=0.00035x^{2}\)
Compute the first order derivative of y as follows:
\(y=0.00035x^{2}\)
\(\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]\)
\(=2\cdot 0.00035x\\\\=0.0007x\)
Now, it is provided that |x | ≤ 605.
⇒ -605 ≤ x ≤ 605
Compute the arc length as follows:
\(\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx\)
\(=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\\)
Now, let
\(x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u\)
\(\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u\)
\(={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}\)
Plug in the solved integrals in Arc Length and solve as follows:
\(\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\\)
\(=1245.253707795227\\\\\approx 1245.25\)
Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Hcf of 32 and 48 pls
HCF/GCF 32 and 48
listing factor
32: 1, 2, 4, 8, 16, 32
48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
HCF: 16
prime factorization
32: 2 x 2⁴
48: 3 x 2⁴
HCF: 2⁴ = 16
Alan is growing carrots, parsnips and turnips. He has grown h carrots, 2h parsnips and 5 turnips. In total he has grown 11 vegetables. What is the value of H?
Hello !
Answer:
\( \boxed{h = 6}\)
Step-by-step explanation:
He has grown :
h carrots2h parsnips5 turnipsWe also know that in total, he has grown 11 vegetables.
We will have to solve an equation !
\(h + 2h + 5 = 11\)
\( \iff3h + 5 = 11\)
We want to isolate h.
\(3h + 5 - 5= 11 - 5 \\ \iff3h = 6 \\ \iff \frac{3h}{3} = \frac{6}{3} = 2\)
The value of h is 2.
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Subtract -13f^3+9f2+7f-16-(-8 f^3+5f^2+9f-4)
Answer:
:)\
Step-by-step explanation:
Are these answers all correct?
Answer:
Yes they are all right
Step-by-step explanation:
Answer:
Step-by-step explanation:
A lighthouse is located at (1, 2) in a coordinate system measured in miles. A sailboat starts at (–7, 8) and sails in a positive x-direction along a path that can be modeled by a quadratic function with a vertex at (2, –6). Which system of equations can be used to determine whether the boat comes within 5 miles of the lighthouse?
StartLayout Enlarged Left-Brace 1st Row (x minus 1) squared + (y minus 2) squared = 5 2nd Row y = StartFraction 14 Over 81 EndFraction (x minus 2) squared minus 6 EndLayout
StartLayout Enlarged Left-Brace 1st Row (x minus 1) squared + (y minus 2) squared = 25 2nd Row y = StartFraction 14 Over 81 EndFraction (x minus 2) squared minus 6 EndLayout
StartLayout Enlarged Left-Brace 1st Row (x minus 1) squared + (y minus 2) squared = 5 2nd Row y = Negative StartFraction 14 Over 81 EndFraction (x + 7) squared + 8 EndLayout
StartLayout Enlarged Left-Brace 1st Row (x minus 1) squared + (y minus 2) squared = 25 2nd Row y = Negative StartFraction 14 Over 81 EndFraction (x + 7) squared + 8 EndLayout
The system of equations that can be used to determine whether the boat comes within 5 miles of the lighthouse is
StartLayout Enlarged Left-Brace 1st Row (x minus 1) squared + (y minus 2) squared = 25 2nd Row y = StartFraction 14 Over 81 EndFraction (x minus 2) squared minus 6 EndLayout. Option B
This is further explained below.
What is a parabola?a curve in an open plane that is symmetrical and open at both ends and created by the intersection of a cone with a plane that is parallel to the side of the cone. Under the influence of gravity, the route taken by a projectile takes the form of a curve similar to this one.
Generally, Every single pair of equations begins with an equation representing a circle as their initial problem.
Because you are interested in finding out whether the sailboat is within 5 miles of the coordinates (1,2), you will set the radius of the circle to 5.
The calculation for a circle reveals that the square of the radius should be used. In this case, the answer is 25. So far, it seems that answers two and four are correct.
Following this, the vertex will be shown to you as (h,k) (2,-6). When we look at the equation of a parabola, we want to find a solution that has a k value of -6, so our search begins there.
In conclusion, the system of equations that can be used to determine whether the boat comes within 5 miles of the lighthouse is
StartLayout Enlarged Left-Brace 1st Row (x minus 1) squared + (y minus 2) squared = 25 2nd Row y = StartFraction 14 Over 81 EndFraction (x minus 2) squared minus 6 EndLayout
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Answer:
b
Step-by-step explanation:
on edge
Please help!!! Thanks
Math problem
Answer:
67
Step-by-step explanation:
(5-2)180
=540
540-131-105-153-84
=67
If 125 kg of food is sufficient for 30 soldiers for 6 days, how long will the food last for 45 soldiers?
Answer:
30 = 6
45 = x
cross multiply
30x = 45*6
30x = 270
divide both sides by
30x/30 = 270/30
X = 9
9-6 = 3 days
For the right triangle below, find the measure of the angle. Round to the hundredths. (2 decimal places
Answer:
please take a picture of the triangle so I can help you.
What is the volume of the prism?
Enter your answer, as a mixed number in simplest form, in the box.
Answer:
\(115 \dfrac{1}{2}\:cm^3\)
Step-by-step explanation:
The volume of a rectangular prism is the product of each of the sides of the prism
Given the sides have lengths
\(3\dfrac{1}{2}, 6 \;and\; 5 \dfrac{1}{2} cm\)
the volume would be
\(3\dfrac{1}{2} \times 6 \times 5 \dfrac{1}{2}\)
To perform this multiplication, convert mixed fractions to improper fractions first
Use the rule that mixed fraction
\(a\dfrac{b}{c}=\dfrac{a\times \:c+b}{c}\)
\(3\dfrac{1}{2}=\dfrac{3\times 2+1}{2} = \dfrac{7}{2}\)
\(5\dfrac{1}{2}=\dfrac{5\times 2+1}{2}= \dfrac{11}{2}\)
Therefore
\(3\dfrac{1}{2}\times \:6\times \:5\dfrac{1}{2}\\\\= \dfrac{7}{2}\times \:6\times \dfrac{11}{2}\\\\= \dfrac{7}{2}\times \dfrac{6}{1}\times \dfrac{11}{2} \quad(6 = \dfrac{6}{1})\)
\(=\dfrac{7\times \:6\times \:11}{2\times \:1\times \:2}\\\\= \dfrac{462}{4}\\\)
Divide numerator and denominator by 2 to get
\(\dfrac{231}{2}\\\)
Convert improper fraction \(\dfrac{231}{2}\) to mixed fraction using quotient/remainder
\(\dfrac{231}{2} \\\\\rightarrow Quotient: 115\\\\\rightarrow Remainder = 231 - 115 \times 2 = 231 - 230 = 1\)
\(\dfrac{231}{2} = 115 \dfrac{1}{2}\)
Find f(-3) when f(x) = 4x-2x-7.
Answer:
-13
Step-by-step explanation:
f(x) = 4x-2x-7
when; f(x) = f(-3)
then, f(-3) = 4(-3) - 2(-3) - 7
= -12 + 6 - 7
= -19 + 6
= -13
Help!! Factor the common factor out of each expression
Therefore , the solution of the given problem of equation comes out to be factor is (5b)(-5b+3).
What is the equation?A formula for connecting two statements using the equal sign (=) to denote equivalence is known as a mathematical equation. A mathematical equation in algebra is a statement that proves the equality of two mathematical expressions. For instance, the formula 3x + 5 = 14 places an equal sign between the variables 3x + 5 and 14. The mathematical relationship between the two sentences on either side of a letter is established. Most of the time, the symbol serves as both the one and only variable. for instance, 2x – 4 = 2.
Here,
the two numbers' primary factors are as follows:
-25\(b^{2}\) + 15b
Common prime factors can be multiplied to determine the GCF:
=> -25\(b^{2}\) = -(5)(5) * \(b^{2}\)
=> 15b = (5)(3)b
The expression can be factored in the following fashion because the GCF is 5b:
=> -(5)(5) * \(b^{2}\) + (5)(3)b
=> (5b)(-5b+3)
Therefore , the solution of the given problem of equation comes out to be factor is (5b)(-5b+3).
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Identify terms of 25x-7
Answer:
The terms are 25x and 7
Step-by-step explanation:
3. Find BD in the following diagram.
BD=
Answer: BD = 28
Step-by-step explanation:
BC = 21, CD = 7 Given
BC + CD + BD Segment Addition Postulate
21 + 7 = BD Substitution
28 = BD Add Like Terms
Joey and Amanda were asked the following question: Is pre-image ABCDE congruent to image VWXYZ? How can you tell?
Joey said that the pre-image and image are congruent by rotating the image 90 degrees clockwise around the rotation and translating right 3 units.
Amanda said that the pre-image and image cannot be moved onto the image. A 9 -10--8--6-4-2 10 W 6 8 10 1. Who do you agree with, and why? Be sure to explain your reasoning.
please help thank you
Answer:..... amanda because her plots are bigger.
Step-by-step explanation:
what is the area of the triangle
Answer:
90units²
Step-by-step explanation:
area of a triangle= ½base *height
area = ½*12*15
area= 90units²
The speed of light is 3 x 108 m/s. If its frequency is 4.11 x 104 Hz, what's is its wavelength.
PLZZ HELP PLZZ ill give thanks n more :(
Wave length = speed / frequency
Wave length = 3x10^8 / 4.11x10^4
Wave length = 7.299x10^3nm
Write the phrase as an expression. Four less than three times a number b.
Answer:
3b - 4
Step-by-step explanation:
Answer:
3b-4
Step-by-step explanation:
I'm big brain.... can I get brainliest
HELP PLEASEEEE
find the image of the point E(-3,7) after a reflection across the line y=-x.
Answer:
(-7,3)
Step-by-step explanation:
I already did the graphing part I need help with finding the slopes and lengths.
Kindly check below.
1) Note that we need to find the slopes of the lines in order to classify that quadrilateral.
2) So, we need to find the slope of each line segment:
\(\begin{gathered} m_{UV}=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-1}{-2-(-5)}=\frac{-2}{3}=-\frac{2}{3} \\ \\ m_{VW}=\frac{2-(-1)}{3+2}=\frac{3}{5} \\ \\ m__{WX}=\frac{4-2}{1-3}=\frac{2}{-2}=-1 \\ \\ m_{XU}=\frac{4-1}{1-(-5)}=\frac{3}{6}=\frac{1}{2} \end{gathered}\)3) Now, let's find the length of all sides as requested.
\(\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ d_{UV}=\sqrt{(-2+5)^2+(-1-1)^2}=\sqrt{13}\approx3.6 \\ \\ d_{VW}=\sqrt{(3+2)^2+(2+1)^2}=\sqrt{34}\approx5.8 \\ \\ d_{WX}=\sqrt{(1-3)^2+(4-2)^2}=2\sqrt{2}\approx2.8 \\ \\ d_{XU}=\sqrt{(-5-1)^2+(1-4)^2=}\:3\sqrt{5}\:\approx6.7 \end{gathered}\)4) Finally, we can tell that quadrilateral can be best identified as a parallelogram.
Given two complementary angles, 2x and
(x+3). Find the value of x.
Answer:
29
Step-by-step explanation:
Assuming the angle measurements are in degrees, the two given expressions for the angle measures add to 90.
2x+(x+3)=90
3x+3=90
3x=87
x=29
Subtract 2w + 4 from 3w + 6 please help!!
Answer:
w+10
Step-by-step explanation:
3w+6-2w+4=w+10
Answer:
Step-by-step explanation:
x subtracted from y means y-x
2w+4 subtracted from 3w+6= (3w+6)-(2w+4)
don't forgett to diestribute invisible -1
-(2w+4)=-1(2w+4)=-2w-4
so
3w+6-2w-4=
3w-2w+6-4=
1w+2=
w+2