The graph of a quadratic function with vertex (-2,-1) is shown in the figure below. Find the range and the domain. Write your answers as inequalities, using x or y as appropriate. Or, you may instead choose "empty set" or "all reals" as the answer.

Answer:

Step-by-step explanation:

Question

N

m

4

5

4

U

-

3-

Cu v

-5-4-3-2-1

2

-2

1 w

60

r

2345x

What is the domain of the function on the graph?

O all real numbers

O all real numbers greater than or equal to-2

O all real numbers greater than or equal to-5

O all real numbers greater than or equal to 0

Help please

7½ – 4/7 ×7/8

= 15/2 – 1/2

= 7

Answer:

its 7

Step-by-step explanation:

Answer:

arithmetic sequence

Step-by-step explanation:

Each new member of this sequence is less than the previous member by a fixed number, which means this is an arithmetic sequence.

The domain of the function y = √(x + 7) + 5 is all real numbers (all real numbers). Option D.

To determine the domain of the function y = √(x + 7) + 5, we need to identify the values of x for which the function is defined.

In this case, the function includes two operations: addition and square root. To ensure the function is defined, we need to consider the restrictions imposed by each operation.

The square root function (√) is defined only for non-negative real numbers. In other words, the expression inside the square root (√(x + 7)) must be greater than or equal to zero for the function to be defined.

Setting x + 7 ≥ 0, we can solve for x:

x ≥ -7

Therefore, the expression inside the square root (√(x + 7)) is defined for x values greater than or equal to -7.

Additionally, there are no restrictions on the addition operation (+5). It can be applied to all real numbers.

Combining both restrictions, we find that the function y = √(x + 7) + 5 is defined for all real numbers x, since there are no limitations or exclusions. Option D is correct.

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Based on the supply graph and demand graph shown above, the price at the point of equilibrium is $ 30.

Demand refers to quantity of a commodity that the consumers are willing to, able to purchase at a given price during a given period of time. Supply refers to quantity of a commodity that the producers are willing to, able to offer for sale at a given price during a given period of time.

Demand curve slopes downward due to inverse relationship between price and quantity demanded whereas supply curve slopes upward due to direct relationship between quantity supplied and price. When both demand and supply curve intersect with each other balance is achieved. Intersection point between demand and supply curve is known as equilibrium.

At this point when prices are equal is known as equilibrium price and when quantiy demanded or supplied are equal it is known as equilibrium quantity. When we combine the given graph. Equilibrium is achieved at a point when price is equal to $ 30 and quantity is equal to 20 units.

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Answer:

6.375

Step-by-step explanation:

8.5 percent of 7.500=6.375

Answer:

the answers are B and F since √8 x √8 = √64 which simplifies to 8.

The expression that can be used to find the area of the tiled floor is 4w² + 200w

Length = 70 Meters

Width = 30 meters

Area = length × width

= 70 × 30

= 2100

Length = 70 + 2w meters

Width = 30 + 2w meters

Area = length × width

= (70+2w) (30+2w)

= 2100 + 140w + 60w + 4w²

= 4w² + 200w + 2100

Area of the tiled floor = Area of new rectangle - area of old rectangle

= (4w² + 200w + 2100) - 2100

= 4w² + 200w + 2100 - 2100

= 4w² + 200w

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30% Is the answer ........

Using trigonometric identities, we found that sec Φ = -7/(2√10), sin Φ = 3/7, tan β = √11/5, and sin β = √11/6 for the given values of csc Φ, cot Φ, and sec β.

1. We can start by using the Pythagorean identity to find the values of sin Φ:

\(sin^2\) Φ + \(cos^2\) Φ = 1

Since csc Φ = 1/sin Φ, we can substitute and solve for sin Φ:

1/(7/3) = sin Φ

sin Φ = 3/7

Next, we can use the fact that cot Φ = cos Φ/sin Φ:

cot Φ = cos Φ/(3/7) = - (2√10)/(3)

Simplifying this expression, we get:

cos Φ = - (2√10)/(3) * (3/7) = - 2√10/7

Finally, we can use the fact that sec Φ = 1/cos Φ:

sec Φ = 1/(- 2√10/7) = -7/(2√10)

2. We can use the fact that sec β = 1/cos β to find the value of cos β:

sec β = 6/5

cos β = 5/6

Next, we can use the Pythagorean identity to find the value of sin β:

\(sin^2\) β + \(cos^2\) β = 1

sin β = √(1 - \(cos^2\) β) = √(1 - 25/36) = √(11/36) = √11/6

Finally, we can use the fact that tan β = sin β/cos β:

tan β = (√11/6)/(5/6) = √11/5

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Answer:

H0: p ≥ 0.70; HA: p < 0.70

Sample proportion = 0.625

Test statistic = -1.79

Pvalue = 0.0367

Older workers in Asia feel less fulfilled

B.)

H0: p ≤ 0.50; HA: p > 0.50

0.58

2.35

0.0094

younger workers in Asia feel more fulfilled

Step-by-step explanation:

1.)

H0: p ≥ 0.70;

HA: p < 0.70

The test statistic :

(Phat - p) /sqrt(p(1-p)/n)

Phat = x / n = 75/120 = 0.625

1 - p = 1 - 0.7 = 0.3

(0.625-0.70) / sqrt(0.7*0.3/120)

-0.075 / 0.0418330

= - 1.79

Pvalue FROM Zscore calculator :

Pvalue = 0.0367

α = 5% = 0.05

Pvalue < α ; Reject then Null and conclude older workers in Asia feel less fulfilled than their British counterparts.

B.)

H0: p ≤ 0.50; HA: p > 0.50

Sample proportion, phat = 58% = 0.58

The test statistic :

(Phat - p) /sqrt(p(1-p)/n)

(0.58 - 0.50) / sqrt(0.58*0.42)/210)

0.08 / 0.0340587

Test statistic = 2.35

Pvalue FROM Zscore calculator :

Pvalue = 0.0094

α = 5% = 0.05

Pvalue < α ; Reject then Null and conclude younger workers in Asia feel more fulfilled than their British counterparts

The reduced price of the item will be $44.

The percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

Given that the price of an item has been reduced by 20%. The original price was $55.

The reduced price of the item will be calculated as,

Price  = 55 x ( 100% - 20 %)

Price = 55 x ( 1 - 0.2

Price = ( 55 x 0. 8 )

Price= $44

Hence, the price of the item will be $44.

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Answer:

June - August

Step-by-step explanation:

First count all of the Temperature values!

1. 40 + 45 + 58 + 69 + 78 + 88 + 92 + 90 + 82 + 70 + 57 + 45 = 814

2. now divided by the amount of months!

3. the average answer is 66 and 67!

Mmm, I'm stuck in this point! Just try June - August

But this is how you can find the average with a graph!

Answer:

62.2

Step-by-step explanation:

The order you must follow is Brackets, Division, multiplication,  subtraction.

First, you solve the expression in the brackets.

4(18)-9.8

Then you multiply since there is no division involved here.

72-9.8

And lastly, you subtract

62.2

Answer:0

Step-by-step explanation:

Answer:

11x - 46

I hope this helps!

Answer:

12(x-4)-x+4-2

12x-48-x+4-2

11x-46

a) The mean rainfall from seeded clouds exceeds 25 acre-feet is 1.99

b) As per the normal distribution, with the significance level 0.05 the rainfall is normally distributed.

c) The power of the test if the true mean rainfall is 27 acre-feet is 23.5%

d) The sample size would be required to detect a true mean rainfall of 27.5 acre-feet if we wanted the power of the test to be at least 0.9 is 28 clouds

e) The upper bound is greater than 25 acre-feet, we can support the claim that the mean rainfall from seeded clouds exceeds 25 acre-feet with a level of confidence of 99%.

a) To support a claim that mean rainfall from seeded clouds exceeds 25 acre-feet, we can perform a one-tailed hypothesis test with a significance level of α = 0.01.

Substituting the values, we get:

t = (25.96 - 25) / (4.48 / √20) = 1.99

b) To test if the rainfall is normally distributed, we can perform a normal probability plot and a Shapiro-Wilk test.

Using software, we can create a normal probability plot and perform the Shapiro-Wilk test.

The Shapiro-Wilk test also does not reject the null hypothesis that the data is normally distributed at a significance level of α = 0.05, we can assume that the rainfall data is normally distributed.

c) To compute the power of the test if the true mean rainfall is 27 acre-feet, we can perform a one-tailed hypothesis test with a significance level of α = 0.01. The null hypothesis H0 is that the mean rainfall is less than or equal to 25 acre-feet, and the alternative hypothesis Ha is that the mean rainfall is greater than 25 acre-feet.

Substituting the values, we get:

t = (25.96 - 27) / (4.48 / √20) = -1.43

Using software or a t-distribution table, we find that the probability of rejecting the null hypothesis when the true mean is 27 acre-feet is 0.235. Therefore, the power of the test is 0.235 or 23.5%.

d) To determine the sample size required to detect a true mean rainfall of 27.5 acre-feet with a power of at least 0.9, we can use power analysis.

Substituting the values, we get:

d = (27.5 - 25) / 4.48 = 0.56

Therefore, a sample size of at least 28 clouds would be required to detect a true mean rainfall of 27.5 acre-feet with a power of at least 0.9.

e) To answer the question in part (a) by constructing a one-sided confidence bound on the mean diameter, we can use a one-sided confidence interval with a level of confidence of 99%.

Substituting the values, we get:

x + tα,df * (s / √n) = 25.96 + 2.861 * (4.48 / √20) = 27.23

This means that we can be 99% confident that the true population mean rainfall from seeded clouds is greater than 27.23 acre-feet.

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Answer:

the value of q = -3

Step-by-step explanation:

The computation of the equation is shown below:

Given that

q^2 + 6q + 9 = 0

q^2 + 3q+ 3q + 9

q(q + 3) + 3(q + 3)

(q+3) (q+3)

q = -3

Hence, after solving it the value of q = -3

The required piecewise linear relations are f(x) = 4 if [0, 2), and f(x) = -2x + 8 if [2, 4).

A piecewise-defined function (also known as a piecewise function or a hybrid function) is a function defined by multiple sub-functions, each of which applies to a different interval of the main function's domain (a sub-domain).

The graph is given in the question, as shown

f(x) = 2x + 4 if [-2, 0]

This the sub-function define between the interval [-2, 0].

f(x) = 4 if [0, 2)

This the sub-function define between the interval [0, 2).

f(x) = -2x + 8 if [2, 4)

This the sub-function define between the interval [2, 4).

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\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)

The required equation is :

\(\qquad \sf  \dashrightarrow \:a \cos(bx) + k\)

Now, let's find the required values :

[distance between any successive Crest or trough]

Distance of starting position from origin = k

Now, plug in the values ~

\(\qquad \sf  \dashrightarrow \: - 4 \cos( \frac{ \pi}{3}x ) - 2\)

Functions f(x) = x² + 1 and g(x) = x – 4, the value equivalent  to f(g(10)) is, 37

Function is a relation between a set of inputs and a set of outputs which are permissible. In a function, for particular values of x we will get only a single image in y. It is denoted by f(x).

Vertical line test:-

Whenever we want to check whether a given expression is a function or not we can apply a vertical line test, in this test we check for a single image of x , we are getting a single image or more.

If we get more images then it will not be a function.

For example, let us take, y² = 4ax

y = ±√4ax

For single value of x we get two values of y

Hence, it will not be a function.

Given that,

f(x) = x² + 1

g(x) = x – 4

f(g(10)) = ?

f(g(x))  =  (x - 4)² + 1

           =  x² - 8x + 16 +1

           =   x² - 8x + 17

f(g(10)) =  10² - 8×10 + 17

            = 100 - 80 + 17

            = 37

The value of  f(g(10)) is 37

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To find the number of dimes and quarters, you have 17 dimes and 34 quarters in your pocket , when there are 51 coins in your pocket.

To solve this problem, we can set up a system of equations using the given information. Let's use "d" to represent the number of dimes and "q" to represent the number of quarters.

We know that there are 51 coins in total, so we can write the equation: d + q = 51.

We also know that the total value of the coins is $10.20, which can be expressed as 10d + 25q (since dimes are worth 10 cents and quarters are worth 25 cents). So our second equation is: 10d + 25q = 1020.

To solve this system of equations, we can use substitution or elimination. Let's use substitution:

Rearrange the first equation to solve for d: d = 51 - q.

Substitute this expression for d in the second equation: 10(51 - q) + 25q = 1020.

Simplify and solve for q: 510 - 10q + 25q = 1020.

Combine like terms: 15q = 510.

Divide both sides by 15: q = 34.

Now substitute this value back into the first equation to solve for d: d + 34 = 51.

Subtract 34 from both sides: d = 17.

Therefore, you have 17 dimes and 34 quarters.

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Answer:

10

Step-by-step explanation:13+4>а>13-4

a>9

Answer:

1312.34 yards

Step-by-step explanation:

Answer:0.12 cm 120 cm 1200 cm 120,000 cm

Answer:

r= 20 units

theeta= 46

L= 2πr* theeta/360

L

L = 160 units

The length of arc is 16.049 unit.

An "arc" in mathematics is a straight line that connects two endpoints. An arc is typically one of a circle's parts. In essence, it is a portion of a circle's circumference. A curve contains an arc.

We have,

m <STU = 46

and ST = 20 units

So, length of Arc

= 46/ 360 2πr

= 46/360 x 2 (3.14)(20)

= 16.0488 unit

Thus, the length of Arc is 16.0488 unit.

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Step-by-step explanation:

2xy+5=21

2xy+5-5=21-5

2xy=16

2xy÷2=16÷2

xy=8 or 2xy=16

Answer:

92%

Step-by-step explanation:

138 is 92% of 150

Answer:

B. 0.57 repeating

Step-by-step explanation:

Answer:

the second one, the one that is already highlighted is correct.

Step-by-step explanation:

she divided it up among them so 20 over x shows division

Answer:

Im pretty sure it's 5.25 cups of flour

Step-by-step explanation:

so we know that it takes 3 cups for 8 people and we don't know the amount for 14 people so write it as a fraction and cross multipy

For the equation

8/3=14/x

The cross product is

8*x=3*14

Solving for x

x=3×14/8

and reducing

x=5.25