The first device Faraday invented based on Ørsted’s observation was the motor. What did this device do?

Answer:

1. He feels worse off.

2. His awareness of the grim situation.

Explanation:

Elie Weisel's memoir "Night" is about the persecution of the jews by the Germans during the worst genocide in world history. The events leading up to the Holocaust and the resulting after-effects through his personal experience provides one of the most prominent witness accounts of the crime.

When Weisel states that "lying down wasn't an option", he reveals how congested space was in the cabin. The "lucky ones" were able to breathe in the fresh air from the window, while the rest have to be satisfied with wherever they are. This reveals his realization of the grim situation inside the over-packed cabin, where there is hardly any space to move.

And when he said that they "never ate enough to satisfy our hunger", he presents the realization and understanding of the grim situation in the train's cabin where eating is not a luxury, but a necessity to stay alive. And for that, they know they have to "economize, to save for tomorrow" rather than just stay full once.  

Answer:

1. He feels worse off.

2. His awareness of the grim situation.

Explanation:

Hey,

If we assume that the horse is pulling a cart on a horizontal support AB (of mud).

Then,

\(\sum\overrightarrow{F_{AB}}= ||\overrightarrow{F}|| \times AB = 250 \times 10= 2,50 \times 10^3 J\)

But maybe it's reasonable to download the image, if you can.

Answer:

2.5 m/s²

Explanation:

Given,

Initial speed ( u ) = 10 m/s

Final speed ( v ) = 20 m/s

Time ( t ) = 4 seconds

To find : Acceleration ( a ) = ?

Formula : -

a = ( v - u ) / t

a = ( 20 - 10 ) / 4

= 10 / 4

= 5 / 2

a = 2.5 m/s²

Therefore,

The acceleration of the scooter is 2.5 m/s²

Given :

Velocity of bullet, \(v_b=300\ m/s\).

Mass of bullet, m = 0.005 kg.

Mass of rifle, M = 5 kg.

To Find :

The recoil velocity of the rifle.

Solution :

Since, their is no external force is acting.

So, momentum of the system will be conserved :

Initial momentum = Final momentum

m(0) + M(0) = m(300) + Mv

\(v=-\dfrac{300m}{M}\\\\v=-\dfrac{300\times 0.005}{5}\\\\v=-0.3 \ m/s\)

Therefore, recoil velocity of the rifle is 0.3 m/s.

Hence, this is the required solution.

Answer:501.67 cm²

Explanation:We can use the formula for thermal expansion:

A₂= A₁(1+αΔ T)

Where:

A₁=500 cm²( initial area at0°C)

A₂= area at80°C( what we want to find)

α= coefficient of linear thermal expansion of copper(16.8 x10^-6/° C)

Δ T= change in temperature(80°C-0°C=80°C)

Pl ugging in the values, we get:

A₂=500 cm²(1+16.8 x10^-6/° C x80°C)

A₂=500 cm²(1+0.001344)

A₂=500 cm² x1.001344

A₂=501.67 cm²

Therefore, the area of the copper sheet at80°C is approximately501.67 cm².

Answer:

C.

Explanation:

the earth has a high greavitational pull

Answer: C the person and earth

Explanation: I just answered it on a p e x

Answer:

4. F

5. F

Explanation:

jupiter constantly has hurricanes and uranus has storms often too.

lightning can move many ways including from cloud to cloud and even from ground ton sky (seriously look it up it's cool)

k is the number of standard deviations greater than one that that proportion of observations will be discovered within.

A standard deviation measures the spread of data in relation to the mean.

A low standard deviation suggests that the data is concentrated around the mean, whereas a high standard deviation shows that the data is spread.

A standard deviation near 0 suggests that data points are close to the mean, whereas a high or low standard deviation indicates that data points are above or below the mean, respectively.

The curve on top of Image 7 is more spread out and hence has a higher standard deviation, whereas the curve below is more grouped around the mean and thus has a smaller standard deviation.

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Explanation:

In scientific notation the Sun's mass is: =1.989 x 10 ^30 kg

Answer:

I think in scientific notation the Sun's mass becomes: M Sun = 1.989 x 10 30 kg. The number above the ten, called the power of ten or exponent, stands for the number of decimal places. If it is positive, as in the mass of the Sun, the decimal places are in front of the decimal point.

I hope this help you!:)

Both spring scales will display the same magnitude of force, as they are interconnected and experience the same force due to pulling.

To compare the magnitude of the forces on both spring scales after you pulled the 5 N spring scale suspended on the 10 N spring scale, please follow these steps:
1. First, attach the 5 N spring scale to the 10 N spring scale, with the 5 N scale hanging from the 10 N scale.
2. Pull the 5 N spring scale downwards to apply force on both scales.
3. Observe the readings on both spring scales.

The magnitude of the force on the 5 N spring scale will be equal to the force you applied while pulling it.

The 10 N spring scale will also experience the same magnitude of force, as it is supporting the 5 N scale and the force applied.

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Positive work is done when an object is moved in a positive direction. When an object is moving in the same direction as the force being applied, this is considered positive work. As an illustration, an object falling to the ground does so in the direction of gravity.

The work is referred to be positive work done since gravity is pushing downward in the direction of the falling object. Every force used to move an object in a particular direction constitutes work. We distinguish between positive and negative work done based on whether an object moves in the direction of the force or away from it. Work performed is considered to be 0 if there is absolutely no displacement. It is crucial to keep in mind that whereas force and displacement are both vector concepts, work is a scalar quantity.

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The k-factor for the hexagonal lattice of 1.4 cm radius natural uranium rods and graphite, with a lattice pitch of 20 cm, is approximately 0.907.

To calculate the k-factor for a hexagonal lattice of uranium rods and graphite, we need to determine the number of uranium rods within a given area and the total area of the unit cell.

1. First, let's calculate the area of the hexagonal unit cell:

The lattice pitch is given as 20 cm, which is the distance between the centers of adjacent uranium rods.

The radius of the uranium rods is 1.4 cm, so the distance between their centers is twice the radius, which is 2.8 cm.

The distance between the centers of the graphite rods will also be 2.8 cm.

Now, we can calculate the area of the hexagonal unit cell using the formula:

Area = (3√3/2) * (distance between centers)^2

Area = (3√3/2) * (2.8 cm)^2

Area ≈ 21.2 cm^2

2. Next, we need to determine the number of uranium rods within the unit cell.

The hexagonal lattice arrangement allows for 1 uranium rod at the center and 6 uranium rods surrounding it.

Total number of uranium rods in the unit cell = 1 (center) + 6 (surrounding) = 7 rods

3. Finally, we can calculate the k-factor using the formula:

k = (1 - (ρ_graphite/ρ_uranium)) * (Number of uranium rods/Area)

The density of uranium (ρ_uranium) is approximately 19.1 g/cm^3.

The density of graphite (ρ_graphite) is approximately 2.26 g/cm^3.

k = (1 - (2.26 g/cm^3 / 19.1 g/cm^3)) * (7 rods / 21.2 cm^2)

k ≈ 0.907

Therefore, the k-factor for the hexagonal lattice of 1.4 cm radius natural uranium rods and graphite, with a lattice pitch of 20 cm, is approximately 0.907.

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The average speed of the particle is 0.331 m/s.

To find the average speed of the particle, we need to first calculate the distance traveled by the particle. Since the particle travels 19 times around the circle, the distance it travels is the circumference of the circle multiplied by 19.

The circumference of the circle is given by 2πr, where r is the radius of the circle.

Circumference = 2πr = 2 x 3.14 x 10 cm = 62.8 cm

Distance traveled = 19 x Circumference = 19 x 62.8 cm = 1193.2 cm

To convert this distance to meters, we divide by 100:

Distance traveled = 1193.2 cm / 100 = 11.932 m

Now that we have the distance traveled, we can use the formula for average speed:

Average speed = distance / time

In this case, the time is given as 36 seconds.

Average speed = 11.932 m / 36 s = 0.331 m/s

Therefore, the average speed of the particle is 0.331 m/s.

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The average speed of the particle is 0.331 m/s.

To find the average speed of the particle, we need to first calculate the distance traveled by the particle. Since the particle travels 19 times around the circle, the distance it travels is the circumference of the circle multiplied by 19.

The circumference of the circle is given by 2πr, where r is the radius of the circle.

Circumference = 2πr = 2 x 3.14 x 10 cm = 62.8 cm

Distance traveled = 19 x Circumference = 19 x 62.8 cm = 1193.2 cm

To convert this distance to meters, we divide by 100:

Distance traveled = 1193.2 cm / 100 = 11.932 m

Now that we have the distance traveled, we can use the formula for average speed:

Average speed = distance / time

In this case, the time is given as 36 seconds.

Average speed = 11.932 m / 36 s = 0.331 m/s

Therefore, the average speed of the particle is 0.331 m/s.

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I think any pendulum would swing slower on the moon than it would on Earth.

The time it takes a pendulum to go through a complete back and forth swing is:

Time period = 2 π √(length/gravity)

You can see that 'gravity' is in the denominator of the fraction, so the smaller gravity gets, the longer the period gets.

To be a little bit more technical, the period is inversely proportional to the square root of gravity.

So the period for a complete swing on the moon would be  √(9.8/1.6) times as long as the complete swing of the same pendulum on Earth.

That number is roughly 2.47 .

So, for every 1 second that a pendulum takes to swing back and forth once on Earth, the same pendulum would take 2.47 seconds to do it on the moon.

Answer:

based on my opinion....

as we know that gravity in moon are less than gravity in earth.. since the force of gravity is less on the moon, the pendulum would swing slower at the same length, angle

and the frequency would be less.

I hope this helps

Answer:

Relative: meredith's birth, the planting of jasmine's tree, and the extinction of the stegosaurus

Absolute: harrison's birth, the building of jasmine house, and the extinction of the triceratops

Explanation: plato

The correct option is: (ii) the force of the rope on Pam (iii) the motion force (due to Pam's motion to the right)

There are several forces that affect the movement of an object, and these can be represented by vectors with different properties. Pam's movement is affected by forces that work in different directions, including the force of the block on Pam, the force of the rope on Pam, and the motion force (due to Pam's motion to the right).The force of the block on Pam cannot exert a force on Pam as she moves to the right because it is in the opposite direction of her movement. The block is being pulled to the left, which will cause Pam to move to the right. Therefore, it cannot exert a force on Pam. However, it does exert a force on the rope, which in turn exerts a force on Pam. The force of the rope on Pam is in the direction of Pam's movement, and it is what causes her to move to the right.

Therefore, this force is responsible for Pam's movement in the direction she is going.The motion force (due to Pam's motion to the right) also exerts a force on Pam as she moves to the right. This force is a result of the motion that Pam is undergoing, which is what causes her to continue moving in the same direction.

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Answer:

c...........................

Answer:

The force is Centripetal force

Answer:

PLS PLS PLS mark brainliest

Explanation:

The following are the environmental problems caused by the invasive algae which is known as Lyngbya.

A. It blocks the sunlight from reaching the water, thereby depriving the plants in the water from accessing it. So they won't be able to manufacture their foods and eventually die off.

B. The algae produce offensive odour like rotten egg , which drive people and other organisms away.

C. The algae prevent oxygen from entering the water, and prevent the resident organisms from making use of it, which leads to their death.

D. The algae also give off heat into the chilly spring waters.

In conclusion, the goals of the Crystal River project is to save the living organisms in the river from extinction and to make it a livable environment for them.

Answer:

) At the top v =0 and there will be a acceleration due to gravity (g) acting downward.

The correct option is C, the charge inside each of the four spheres is QA= 20 mC, QB = QC=QD = 160 mC.

The Charge density of sphere ρ = q/v = q / (4/3 πr^3)

ρ = 160mC / (4/3 π(8mm)^3)

Charge inside 4mm sphere => QA= ρ.V' = ρ. 4/3 π.(4mm)^3

=> QA= 160mC /  (4/3 π(8mm)^3) x 4/3 π.(4mm)^3

=>QA= 160mC . 1 / 2^3

=> QA= 160mC / 8

=> QA= 20mC

QB = QC = QD = 160mC

Charge density is the measure of the amount of electrical charge per unit of volume in a material. It is a scalar quantity and is expressed in units of Coulombs per cubic meter (C/m3). The charge density of a material is proportional to the number of electric charges present in a given volume and can be either positive or negative. It is an important physical property of materials and plays a crucial role in many electrical and electronic applications.

In materials that conduct electricity, the charge density can vary depending on the type and distribution of charges in the material. For example, in metals, the charge density is relatively uniform, while in insulators, it can be highly non-uniform. In dielectrics, the charge density is proportional to the electric field and is used to calculate the capacitance of a capacitor.

The concept of charge density is also important in the study of plasma, where the charge density can be quite high and play a major role in determining the behavior of plasma. In such cases, the electric fields produced by the charge density can significantly affect the motion of charged particles in the plasma.

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Complete Question: -

A sphere of radius 8 mm has total charge of 160 mC (milli-Coulomb) distributed uniformly over its volume. Four mathematical spheres are drawn concentric to the charged sphere, i.e., with the same center. The radius of the four spheres are (A) 4 mm; (B) 8 mm; (C) 16 mm and (D) 32 mm.

What is the charge inside each of the four spheres?

(a.) QA= 80 mC, QB = 160 mC, QC =320 mC, QD= 640 mC

(b.) QA=20 mC, QB= 80 mC, QC= 40 mC, QD=10 mC

(c.) QA= 20 mC, QB = QC=QD = 160 mC

(d.) QA= 80 mC, QB = QC=QD = 160 mC

The mass of hydrogen present is approximately 0.0213 g. The correct option is c) 0.0213 g.

To determine the mass of hydrogen present, we need to account for the partial pressure of hydrogen and subtract the contribution from the water vapor pressure.

Volume of hydrogen collected (V) = 300 mL = 0.3 L

Barometric pressure (Pbar) = 748 torr

Vapor pressure of water (Pwater) = 19 torr

The partial pressure of hydrogen (Phydrogen) can be calculated using Dalton's Law of Partial Pressures:

Phydrogen = Pbar - Pwater

Substituting the given values into the formula, we have:

Phydrogen = 748 torr - 19 torr

Now, we can use the ideal gas law to calculate the number of moles of hydrogen (n) present:

PV = nRT

where:

P is the pressure,

V is the volume,

n is the number of moles,

R is the ideal gas constant (0.0821 L·atm/mol·K),

T is the temperature in Kelvin.

To convert the temperature from Celsius to Kelvin, we add 273.15:

T = 21°C + 273.15 = 294.15 K

Rearranging the ideal gas law equation, we have:

n = PV / RT

Substituting the calculated partial pressure (Phydrogen), volume (V), and temperature (T) into the equation, we have:

n = (Phydrogen * V) / (R * T)

Finally, to calculate the mass of hydrogen (m), we use the molar mass of hydrogen (2 g/mol):

m = n * molar mass

Substituting the calculated number of moles (n) and the molar mass of hydrogen into the equation, we find the mass of hydrogen present.

The mass of hydrogen present in the 300 mL sample is approximately 0.0213 g. Therefore, the correct option is c) 0.0213 g.

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Answer:

doctor,health assistant , dentist, psychotherapist , nurse ,etc

Electrons do not orbit around the nucleus as a solid body-like planet around the Sun.

The electrons behave as a wave while orbiting around the nucleus and its position cannot be accurately determined as the position of the planets around the Sun.

Thus, the given statement is false.

In her book, The Woman’s Bible, Elizabeth Cady Stanton stated that women should behave like men and she was highly criticized by the clergies.

One such criticism came from Rev. Simon Hosack, who argued that “women should not adopt manly behavior. ”Simon Hosack, in his criticism of Elizabeth Cady Stanton’s argument that women should behave like men, believed that God made women different from men. Hosack believed that women should embrace their femininity and stop trying to behave like men. In his argument, Hosack contended that men and women had different roles to play in society, with the former being responsible for providing and protecting their families while the latter was supposed to be their nurturer.

He insisted that women should not attempt to infringe on the roles of men and that the idea that women should act like men was both illogical and dangerous. In conclusion, Simon Hosack’s reaction to Stanton’s feelings about behaving like a boy was based on his belief that men and women are created differently and that they should stick to their respective roles in society.

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The magnitude of the acceleration of the body is approximately 1.802 m/s^2 when forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other.

To determine the magnitude of the acceleration of a body when two forces act on it at a right angle, we can use the Pythagorean theorem and Newton's second law of motion.Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the vector sum of the two forces acting on the body.Using the Pythagorean theorem, we can find the magnitude of the net force. Let's call the force with magnitude 5 Newton as F1 and the force with magnitude 4 Newton as F2. The net force (Fnet) can be calculated as the square root of the sum of the squares of the individual forces: Fnet = sqrt(F1^2 + F2^2).Now we can substitute the net force into Newton's second law to find the acceleration (a). Rearranging the formula, we have a = Fnet / m.Plugging in the values, Fnet = sqrt(5^2 + 4^2) = sqrt(25 + 16) = sqrt(41) Newtons. The mass (m) is given as 4.0 kg.

Finally, the magnitude of the acceleration of the body is calculated as a = Fnet / m = sqrt(41) / 4.0 ≈ 1.802 m/s^2.

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Answer:

4.81 L

Explanation:

From the question given above, we obtained the following information:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = – 34 °C

Final Volume (V₂) =?

Next, we shall convert – 34 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = – 34 °C

T(K) = – 34 + 273

T(K) = 239 K

Thus, –34 °C is equivalent to 239 K

Finally, we shall determine the final volume of the balloon as follow:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = 239 K

Final Volume (V₂) =?

V₁ / T₁ = V₂ / T₂

6 / 298 = V₂ / 239

Cross multiply

298 × V₂ = 6 × 239

298 × V₂ = 1434

Divide both side by 298

V₂ = 1434 / 298

V₂ = 4.81 L

Thus, the volume of the balloon when it was brought outside the store was 4.81 L.

The statements which describe some of the original ideas proposed about the universe during the big bang include:

This is the theory about the formation of the universe which states that a single point began to expand which resulted in its formation.

This was as a result of observations and ideas which can be seen mentioned above.

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Answer:

B. The universe was opaque.

D. The universe was very hot and dense.

E. The universe expanded from a single point.

Explanation:

According to the law of conservation of momentum, the total momentum of a system remains constant if there are no external forces acting on the system. In this case, the system consists of the person on roller skates and the ball that is thrown.

Before the collision, the ball has momentum, and the person on roller skates is stationary. After the collision, both the ball and the person on roller skates have momentum, and they move together in the same direction.

Since the momentum of the system is conserved, the total momentum before the collision must be equal to the total momentum after the collision. Therefore, the momentum of the ball before the collision is equal to the momentum of the ball and the person on roller skates after the collision.

If we assume that the person on roller skates is much more massive than the ball, then the momentum of the person on roller skates can be neglected. In this case, the momentum of the ball before the collision is equal to the momentum of the ball and the person on roller skates after the collision.

Since the mass of the ball is much smaller than the combined mass of the ball and the person on roller skates, the speed of the ball after the collision will be much smaller than its speed before the collision. Meanwhile, the speed of the person on roller skates after the collision will be faster than their initial stationary position due to the transfer of momentum from the ball to the person on roller skates.

In summary, the speed of the ball after the collision will be slower than its initial speed, while the speed of the person on roller skates will be faster than their initial stationary position.

~~~Harsha~~~

According to the second law of Newton, the acceleration is directly proportional to the net force acting on the object:

From this formula, we can also see that the acceleration is inversely proportional to the mass: For the same force, if the mass increases, the acceleration decreases.

Therefore the correct option is d.