the dominant wavelength of energy emitted by the sun is question 9 options: a) shorter than that emitted by earth b) longer than that emitted by earth c) the same length as that emitted by earth

Answer:

i put cereal first

Explanation:

cereal

Kinetic energy is a type of power that a moving object or particle possesses.

An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.

A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion. The type of motion can be vibration, rotation on an axis, translation (or travel along a path from one place to another), or any combination of these.

The increase in a particle's mass above that it has at rest multiplied by the square of the speed of light is the definition of relativistic kinetic energy.

Therefore, Kinetic energy is a type of power that a moving object or particle possesses.

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The action extravaganza you are referring to, which had an Astronomical shooting ratio of 240:1 for its 120-minute running time, is "Mad Max: Fury Road."

Directed by George Miller, this film was released in 2015 and quickly became a notable entry in the action genre due to its impressive visuals, intense action sequences, and unique storytelling approach.

To achieve the spectacular results seen in the final cut of the movie, the production team captured an immense amount of footage, which then had to be meticulously edited down to the final runtime of 120 minutes. This high shooting ratio allowed the filmmakers to select the best takes and create an engaging, fast-paced narrative.

In summary, "Mad Max: Fury Road" is the action extravaganza with a shooting ratio of 240:1 for its 120-minute running time, which contributed to the film's success and solidified its status as a modern action classic.

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Answer:

During a thunderstorm, lightning is seen first and thunder is heard later on because light travels faster than sound. If you see a lightning flash but cannot hear any thunder, the thunderstorm is most likely be quite far away from you.

Jim Crow laws was the legal measure which allowed whites in southern states to keep blacks from voting after reconstruction ended.

These were the state and local laws which enforced racial segregation in the Southern part of the United States.

Due to this laws, whites in southern states kept blacks from voting after reconstruction ended.

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The centripetal acceleration at the outer edge of the tire is approximately 389 m/s²

The numerical value of the ratio of the new centripetal acceleration (an) to the old centripetal acceleration (ac) would be 4.00.

To calculate the centripetal acceleration, we can use the formula:

ac = (v²) / r

Where:

v is the velocity of the car,

r is the radius of the circular path.

Given:

v = 11.5 m/s

d = 0.68 m (diameter of the tire)

To find the radius, we divide the diameter by 2:

r = d / 2 = 0.68 m / 2 = 0.34 m

Substituting the values into the formula, we can calculate the centripetal acceleration:

ac = (v²) / r

ac = (11.5 m/s)² / 0.34 m

ac ≈ 389 m/s²

Therefore, the centripetal acceleration at the outer edge of the tire is approximately 389 m/s².

Now, let's calculate the ratio of the new centripetal acceleration (an) to the old centripetal acceleration (ac) when the car is traveling twice as fast:

When the car is traveling twice as fast, the new velocity (v') will be 2 * v:

v' = 2 * v = 2 * 11.5 m/s = 23 m/s

The radius (r) remains the same.

Using the formula for centripetal acceleration, we can find the new centripetal acceleration (an):

an = (v'²) / r

an = (23 m/s)² / 0.34 m

an ≈ 1557 m/s²

Now, let's calculate the ratio of the new centripetal acceleration (an) to the old centripetal acceleration (ac):

Ratio = an / ac

Ratio = 1557 m/s² / 389 m/s²

Ratio ≈ 4.00

Therefore, the numerical value of the ratio of the new centripetal acceleration (an) to the old centripetal acceleration (ac) would be 4.00.

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Answer:

key points:1.momentum and impulse

2.condition for conservation of momentum and why

3.how to solve collision problems

4.centre of mass

Explanation:

momentum is a vector

force of a tennis ball

for a top player,a tennis ball may leave the racket on the with a speed of 55m/s(about 120mi/h).if the ball has a mass of 0.060kg and is in contact with the racket for about 4ms(4×10)s.estimate the average force on the ball

Answer:

30m/s

Explanation:

Use the formula

V= d /t

An electron has a speed of 0.783c. Through what potential difference would the electron need to be accelerated from rest in order to reach this speed is 5.80 x 10 6 V.

The electron has a speed of 0.783c, so we first need to determine its kinetic energy using the following formula:

KE = (γ - 1) mc²

Where KE is the kinetic energy, γ is the Lorentz factor, m is the rest mass of the electron, and c is the speed of light.γ can be calculated using the following formula:

γ = 1 / sqrt (1 - (v/c) ²)

Where v is the velocity of the electron. Plugging in the values, we have:

v = 0.783c

(v/c) ² = 0.783²γ

1 / sqrt (1 - 0.783²) = 2.50

Using the rest mass of the electron, which is 0.511 Me V/c²,

we can calculate the kinetic energy as follows:

KE = (γ - 1) mc²

(2.50 - 1) 0.511

MeV/c²

c² = 0.930 MeV

Now we need to determine the potential difference required to accelerate the electron from rest to this kinetic energy. The potential energy gained by an electron accelerated through a potential difference V is given by:

PE = eV

Where e is the elementary charge. Setting PE equal to the kinetic energy, we get:

eV = KE

V = KE / e

Plugging in the values, we have:

V = (0.930 MeV) / (1.602 x 10-19 C)

5.80 x 10 6 V

The electron would need to be accelerated through a potential difference of 5.80 x 10^6 V in order to reach a speed of 0.783c.

An electron has a speed of 0.783c. Through what potential difference would the electron need to be accelerated from rest in order to reach this speed is 5.80 x 10 6 V.

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Answer:

The ball hit with 12N

Explanation:

Just took the quiz and got it right

Answer:

If the trains are moving at the same speed, the answer is A.

The clock in train B appears to be the same width and to run at the same rate. Option A is correct.

It is given that an observer on train A, which is moving close to the speed of light, views a clock in train B, which is stationary at the train station.

It is required to find how an observer would observe a clock in train B.

If a person is in a moving train, then his body is also in a state of motion with respect to the train at the same rate. When the observer observes any object that is at rest then it does not change the shape or size of an object. Also an object appears to run a=t the same rate due to the relative velocity attain by the observer's train.

Relative Motion is

Relative motion is the speed or the motion of an object with respect to the moving or the stationary object.

Thus the clock in train B appears to be the same width and to run at the same rate.

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The time constant (in ms) of the RC circuit is 3.75 ms. Hence, the correct option is  (d) 3.75 ms.

The rate of decay of the current in a charging capacitor is proportional to the current in the circuit at that time. Therefore, it takes longer for a larger current to decay than for a smaller current to decay in a charging capacitor.A capacitor is discharged through a 20.0 Ω resistor.

The discharge current decreases to 22.0% of its initial value in 1.50 ms. We can obtain the time constant of the RC circuit using the following formula:$$I=I_{o} e^{-t / \tau}$$Where, I = instantaneous current Io = initial current t = time constant R = resistance of the circuit C = capacitance of the circuit

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The time constant of the RC circuit is approximately 0.674 m s.

To determine the time constant (τ) of an RC circuit, we can use the formula:

τ = RC

Given that the discharge current decreases to 22.0% of its initial value in 1.50 m s, we can calculate the time constant as follows:

The percentage of the initial current remaining after time t is given by the equation:

I(t) =\(I_oe^{(-t/\tau)\)

Where:

I(t) = current at time t

I₀ = initial current

e = Euler's number (approximately 2.71828)

t = time

τ = time constant

We are given that the discharge current decreases to 22.0% of its initial value. Therefore, we can set up the following equation:

0.22 =\(e^{(-1.50/\tau)\)

To solve for τ, we can take the natural logarithm (ln) of both sides:

ln(0.22) = \(\frac{-1.50}{\tau}\)

Rearranging the equation to solve for τ:

τ = \(\frac{-1.50 }{ ln(0.22)}\)

Calculating this expression:

τ ≈ 0.674 m s

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A 0. 20-kg ball is attached to a vertical spring. The spring constant is 28 n/m. when released from rest, the ball will fall at a distance of x = 0.14 m   before being brought to a momentary stop by the spring.

The spring constant is the force needed to stretch or compress a spring, divided by the distance that the spring gets longer or shorter. It's used to determine stability or instability in a spring

Elastic potential energy is Potential energy stored as a result of deformation of an elastic object, such as the stretching of a spring. It is equal to the work done to stretch the spring, which depends upon the spring constant k as well as the distance stretched.

When ball is released from rest with spring , it will loose some potential energy . Hence , loss in potential energy of the ball = gain in potential energy of spring

m*g*x = 1/2 * k * \(x^{2}\)

0.20 * 9.8 * x = 1/2 * 28 * \(x^{2}\)

x = (2 * 0.20 * 9.8) / 28

x = 0.14 m

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Answer:

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.

Explanation:do you want me to explain it more??

A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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The system will undergo simple harmonic motion in the case where the restoring force is directly proportional to the displacement (option b).

In simple harmonic motion, the restoring force acting on the system is directly proportional to the displacement from the equilibrium position. This relationship is given by Hooke's Law: F = -kx, where F is the restoring force, x is the displacement, and k is the spring constant.

Option a (F directly proportional to x²) does not correspond to simple harmonic motion because the force is proportional to the square of the displacement, which does not follow Hooke's Law.

Option c (F directly proportional to \(\frac{1}{x}\)) does not correspond to simple harmonic motion either because the force is inversely proportional to the displacement, which is not consistent with Hooke's Law.

Option d (F directly proportional to sin x) does not represent a linear relationship between the force and displacement. Simple harmonic motion requires a linear relationship, not a trigonometric one.

Therefore, only option b (F directly proportional to x) satisfies the conditions for the system to undergo simple harmonic motion.

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Answer:4

Explanation:

Trust me I'm a student

The rotational speed increases when the skater pulls her arms in because the moment of inertia decreases.

\(L = I \omega\)

Where,

\(L\) - Angular momentum

\(I\) - moment of inertia = \(mr^2\)

\(\omega\)- angular velocity

From the equation, the angular velocity of the body is inversely proportional to the moment of inertia.

When the skater pulls her arms in, the moment of inertia decrease due to a decrease in radius,

Therefore, the rotational speed increases when the skater pulls her arms in because the moment of inertia decreases.

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The distance above the ground the rock  should be dropped such that it hits the ground at 2t after it is released from rest is 4h.

The height of fall of the rock is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

g = 2h / t²

h₁ / t₁² = h₂ / t₂²

The distance above the ground the rock  should be dropped such that it hits the ground at 2t after it is released from rest is calculated as;

h₂ = ( h₁ / t₁² )(t₂²)

h₂ = ( h/t²)(2t)²

h₂ = ( h/t²)(4t²)

h₂ = 4h

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Nuclei of H1 and nuclei of H2 are the only stable nuclei oh hydrogen.

Hydrogen is the first and most basic of all elements in the universe.

Radiation is spontaneously emitted from nuclei of H3 because this isotope of hydrogen is highly radioactive as compared to other isotopes of hydrogen namely; nuclei of H1 and nuclei of H2.

The nucleus of H3 also called as tritium contains one proton and two neutrons, while the nucleus of the common isotope H-1 (protium) contains one proton and zero neutrons, and the nucleus of H-2 (deuterium) contains one proton and one neutron.

Therefore H1 and H2 have much stable nucleus as compared to nuclei of H3.

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Answer:

non contant force

Explanation:

bcoz they push or pull on object without touching them

Answer:

energy

Explanation:

Answer:

Explanation:

If the mass hangs at the end of the string and the string can support the mass and doesn't break, and the mass hangs still, that means that the tension in the string is equal to the downward pull of the mass. However, we are given the tension in Newtons and the mass needs to be in kg. So we use the equation for weight:

w = mg where w, the weight, is the same as the tension in the string. Gravity is always 9.8 in the metric system:

4.75 = m(9.8) so

m = .48 kg

Answer:

Answer: A

0.485 Kg

Explanation:

Answer: the atom is mostly empty space with a tiny, dense, positively-charged nucleus

Explanation: Rutherford's gold foil experiments involved firing positively charged alpha particles at a piece of gold/metal foil. The alpha particles that were fired at the gold foil were positively charged. Most of the time, the alpha particles would pass through the foil without any change in their trajectories, which is what was expected if JJ Thomson's plum pudding model of the atom was correct. However, occasionally the alpha particles would be deflected to some degree, and sometimes an alpha particle would bounce back directly toward the experimenter. Rutherford likened this to firing a 15-inch artillery shell at a sheet of tissue paper and the shell came back to hit you.

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Rutherford's gold foil experiment demonstrated the concept of the nucleus of the atom.What is Rutherford's gold foil experiment?

Rutherford's gold foil experiment is an experiment that was conducted by Ernest Rutherford in 1911 to determine the structure of the atom. Rutherford bombarded alpha particles at thin gold foil and noted their trajectory and path.The experiment was conducted to answer the prevailing model of the atom's structure, which was the Thomson atomic model.

According to the Thomson atomic model, the atom's positive charge is evenly distributed throughout the atom, like raisins in a pudding. Rutherford's experiment refuted this hypothesis and provided a new model that supported his findings.

The findings of the gold foil experiment:

Rutherford's experiment led him to conclude that the positive charge of the atom is concentrated in the nucleus, a central part of the atom. In this model, electrons orbit the nucleus, like planets orbiting the sun.

Rutherford's gold foil experiment demonstrated that the atom is made up of mostly empty space, with a small, dense, and positively charged nucleus at the center. This discovery paved the way for further research into atomic structure and the discovery of subatomic particles like protons and neutrons.

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Answer:

The bowling ball has greater kinetic energy.

Explanation:

Kinetic energy is given by:

\( K = \frac{1}{2}mv^{2} \)

Where:

m: is the mass

v: is the speed

For the bowling ball we have:

\(K = \frac{1}{2}mv^{2} = \frac{1}{2}5 kg*(6 m/s)^{2} = 90 J\)

And for the ship:

\(K = \frac{1}{2}mv^{2} = \frac{1}{2}120000 kg*(0.02 m/s)^{2} = 24 J\)

Therefore, the bowling ball has greater kinetic energy.

I hope it helps you!

The National Electric Code (NEC) identifies rigid metal conduit (RMC) as a wiring method, even though it is often referred to as galvanized rigid conduit (GRC).

If 11/2 RMC is threaded (screwed wrench-tight) together between boxes or enclosures, the maximum distance allowed between supports is 130 feet. This straight run of the conduit is almost 200 feet, so it would require additional support to ensure proper electrical performance and safety.

When determining the proper support spacing for a straight run of conduit, it is important to consider factors such as the weight of the conduit, the conductors inside, and the number of bends in the conduit. Too few supports can create sagging and tension, which can damage the insulation of the conductors and potentially cause a short circuit.

Too many supports can be costly and difficult to install. Therefore, it is important to understand the proper support spacing requirements and follow the NEC guidelines.

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Answer:

b. heat

Explanation:

Laser light has a great deal of heat energy. The correct option is B.

A laser is a device that emits light via an optical amplification process that is based on the stimulated emission of electromagnetic radiation. Light amplification by stimulated emission of radiation is an acronym for the term.

A laser generates a very narrow beam of light that can be used in a variety of technologies and instruments. Laser is an acronym that stands for Light Amplification by Stimulated Emission of Radiation.

The radiation coming from the laser light has a large amount of heat due to the presence of the electrons streamed in the form of an electromagnetic wave.

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Explanation:

Wave speed  =  (frequency)  x  (wavelength)

                      =  (266 /sec)  x  (1.3 meters)

Answer:

4 smaller disks

Explanation:

We are given;

Mass of smaller and larger disks = M

Radius of smaller disk = R

Radius of larger disk = 4R

Formula for moment of inertia about cylinder axis is:

I = ½MR²

Thus;

For small disk, I_small = ½MR²

For large disk, I_large = ½M(2R)² = 2MR²

We are told that moment of inertia of System A consists of two of the larger disks. Thus;

I_A = 2 × I_large = 2 × 2MR²

I_A = 4MR²

We are also told that System B consists of one of the larger disks and a number of the smaller disks. Thus;

I_B = I_large + n(I_small)

Where n is the number of smaller disks.

I_B = 2MR² + n(½MR²)

I_B = MR²(2 + n/2)

We are told that the moment of inertia for system A equals the moment of inertia for system B. Thus;

I_A = I_B

So;

4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

The correct option is (a) i.e. a galaxy in the local group, galaxies is likely to be oldest.

A galaxy is a collection of stars, stellar remains, interstellar gas, dust, and dark matter that are gravitationally bonded together. The name comes from the Greek word galaxias, which means "milky" and refers to the Milky Way galaxy, which houses the Solar System. Galaxies, which contain an average of 100 million stars, range in size from dwarfs, which contain fewer than 100 million stars, to supergiants, which contain 100 trillion stars, all of which orbit the galaxy's center of mass. Only a small percentage of the mass in a normal galaxy is visible in the form of stars and nebulae; the majority of the galaxy's mass is dark matter. Supermassive black holes are a typical component of galaxy centers. According on their optical shape, galaxies are classified as elliptical, spiral, or irregular. It is believed that the nuclei of many of them contain supermassive black holes. Sagittarius A*, the name of the Milky Way's primary black hole, is four million times more massive than the Sun. GN-z11 is the oldest and furthest away galaxy as of March 2016. It can be seen as having existed only 400 million years after the Big Bang and is located 32 billion light-years away from Earth.

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