The direct vaporization of a solid without passing through its liquid state is called

Answer:

C

Explanation:

A gas is a state of matter that has no fixed shape and no fixed volume gases have lower density than other states of matter such as solids and liquids.

37.5 grams of Mg is required to react with 25g of oxygen.

Magnesium metal burns in oxygen to form magnesium oxide (MgO).

Because we know that:

Magnesium has a charge of 2+, while oxygen has a charge of 2−.

The combustion of magnesium metal reacts with oxygen in the air (oxygen gas) to form magnesium oxide.

                        2Mg(s) + O₂(g) → 2MgO(s)

Number of moles of O₂ = mass/ArO₂ = 25/32 = 0.78 mol

The number of moles of Mg required to react with O₂.

Mol Mg = 2 x moles O₂

Mol Mg = 2 x 0.78

Mol Mg = 1.56 moles

The number of Mg grams needed to react with O₂ is:

Mass of Mg = ArMg x Mol

Mass of Mg =24 x 1.56

Mass of Mg = 37.5 grams

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Answer:

2.38 g of oxygen (O2).

Explanation:

What is given?

Mass of potassium chlorate (KClO3) = 6.06 g.

Molar mass of KClO3 = 122.4 g/mol.

Molar mass of oxygen (O2) = 32 g/mol.

Step-by-step solution:

First, let's state the balanced chemical equation. Remember that the decomposition of a compound produces two or more products:

Now, let's convert 6.06 g of KClO3 to moles using its molar mass:

You can see in the chemical equation that 2 moles of KClO3 produce 3 moles of O2. By doing a rule of three with this data, we obtain that:

The final step is to convert from 0.0743 moles of O2 to grams using its molar mass, like this:

The answer is that we will produce 2.38 g of oxygen (O2) from the decomposition of 6.06 g of potassium chlorate (KClO3).

When H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases (option C)

A French scientist (Chatelier) postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states that If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

According to Chatelier's principle a decrease in concentration of the products will favor the forward (right) reaction.

From the above principle, we can conclude that when H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases.

Thus, the correct answer to the question is option C

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Among the given options, the most likely to contain trans fatty acids would be partially hydrogenated vegetable oil.

Trans fatty acids are commonly found in processed foods that use partially hydrogenated oils as an ingredient. Partial hydrogenation is a process that converts liquid vegetable oils into solid or semi-solid fats, thereby increasing their shelf life and stability.

However, this process also generates trans fatty acids as a byproduct. Trans fats have been linked to various health issues, including heart disease. To make healthier choices, it is advisable to avoid products that list partially hydrogenated vegetable oil on their food labels.

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Answer:

Explanation:Matter is anything that has weight and occupies space

Answer:

1 Once proteins, fats and carbohydrates are digested, absorption takes place in the small intestine.

2 if we eat food we get energy, but if there weren't chemical reaction in your body nothing happens.

Explanation:

1 Most of the digestion occurs in the first part of the small intestine while the absorption of broken down nutrients, water, vitamins, and minerals occurs in the rest of it.

Answer:

opppopppppooppppkjjhjkgh

To express lnA1, lnA2, and lnA3 in terms of lnA0, εA,1, εA,2, and εA,3, we can use the given equations: From the equation At = A + gt + At, we can rewrite it as At - gt = A + At. Taking the natural logarithm (ln) of both sides, we have ln(At - gt) = ln(A + At).

Similarly, from the equation At = rhoAA~t−1 + ϵA,t,−1, we can rewrite it as At - rhoAA~t−1 = ϵA,t,−1. Taking the natural logarithm (ln) of both sides, we have ln(At - rhoAA~t−1) = ln(ϵA,t,−1). Now, let's express lnA1, lnA2, and lnA3 in terms of ln A0, εA,1, εA,2, and εA,3. Expressing lnA1:  

- From equation 1, we have ln(A1 - g1t) = ln(A0 + A1).

Rearranging the equation, we get ln(A1 - g1t) - ln(A1) = ln(A0).
- From equation 2, we have ln(A1 - rhoAA~1−1) = ln(εA,1).

Rearranging the equation, we get ln(A1 - rhoAA~1−1) - ln(A1) = ln(εA,1).

Therefore, lnA1 = ln(A0) + ln(εA,1).

Calculating the expected values of lnA1, lnA2, and lnA3: - Taking the expected value (E) of equation 1, we have E[ln(A1 - g1t)] = E[ln(A0 + A1)]. Since g1t is constant, we can write it as E[ln(A1)] - g1t = ln(A0 + E[A1]).

Rearranging the equation, we get E[ln(A1)] = ln(A0 + E[A1]) + g1t.

- Taking the expected value (E) of equation 2, we have E[ln(A1 - rhoAA~1−1)] = E[ln(εA,1)].  Since rhoAA~1−1 is constant, we can write it as E[ln(A1)] - rhoAE[A~1−1] = ln(εA,1).

Rearranging the equation, we get E[ln(A1)] = ln(εA,1) + rhoAE[A~1−1].

Therefore, the expected value of lnA1 is given by E[lnA1] = ln(A0 + E[A1]) + g1t = ln(εA,1) + rhoAE[A~1−1]. Similarly, we can calculate the expected values of lnA2 and lnA3 using the corresponding equations and constants.
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a) To find the stopping potential, we can use the formula:

K_max = eV_s

where K_max is the maximum kinetic energy of the ejected electrons, e is the charge on an electron, and V_s is the stopping potential. We can use the fact that the energy of a photon of light is given by:

E = hc/λ

where h is Planck's constant, c is the speed of light in a vacuum, and λ is the wavelength of the light. The work function, W, is the minimum energy required to eject an electron, and is related to the threshold frequency, f_0, by:

W = hf_0 = hc/λ_0

where λ_0 is the threshold wavelength.

For potassium, the work function is given as 2.3 eV. We can convert this to joules using:

1 eV = 1.60×10^-19 J

so W = 2.3 eV x 1.60×10^-19 J/eV = 3.68×10^-19 J.

The threshold wavelength, λ_0, can be found by rearranging the formula for the energy of a photon:

λ_0 = hc/W = (6.63×10^-34 J⋅s x 3.00×10^8 m/s)/(3.68×10^-19 J) = 5.39×10^-7 m

The threshold frequency, f_0, can be found using the formula:

f_0 = c/λ_0 = 3.00×10^8 m/s / 5.39×10^-7 m = 5.57×10^14 Hz

Now we can find the energy of a photon with wavelength λ = 210 nm = 210×10^-9 m:

E = hc/λ = (6.63×10^-34 J⋅s x 3.00×10^8 m/s)/(210×10^-9 m) = 2.99 eV

To find the stopping potential, we subtract the work function from the energy of the photon:

V_s = (E - W)/e = (2.99 eV - 3.68×10^-19 J)/(1.60×10^-19 C) = -0.425 V

Rounding to two significant figures, we get:

Stopping potential = -0.43 V

b) The kinetic energy of the most energetic electrons ejected is given by:

K_max = E - W = 2.99 eV - 2.3 eV = 0.69 eV

Converting to joules, we get:

K_max = 0.69 eV x 1.60×10^-19 J/eV = 1.10×10^-19 J

c) The speed of the electrons can be found using the formula:

K_max = 1/2 mv^2

where m is the mass of an electron and v is its speed. Solving for v, we get:

v = √(2K_max/m)

The mass of an electron is 9.11×10^-31 kg, so:

v = √(2(1.10×10^-19 J)/(9.11×10^-31 kg)) = 6.61×10^5 m/s

Rounding to two significant figures, we get:

Speed of electrons = 6.6×10^5 m/s

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Answer:

The aluminium cation Al3+ which is small and highly charged; and is polarizing and bonds aluminium forms tend towards covalency.

Explanation:

Answer:

Convert 6.50 g N to g urea.

6.50 g N x (molar mass urea/2*atomic mass N) = ? g urea.

Explanation:

Hydrogenated compounds, particularly hydrogen gas (H2), are often considered as potential fuels for spark ignition engines.

Hydrogenated compounds are considered the most suitable fuels for spark ignition engines because hydrogen is a highly flammable gas with a low ignition energy and a wide flammability range. When compared to gasoline or diesel, hydrogen has a higher energy content by weight, which makes it an attractive fuel choice.

Due to increasing temperature, the chemical reaction rate also increases as the element moves from a solid to a liquid to a gas.Physical state transitions are dependent on temperature, and the rate of chemical reactions that occur as a result of these state transitions is also influenced by temperature.

At higher temperatures, the chemical reaction rate typically rises as molecules have more kinetic energy and collide with one another more frequently.

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In the periodic table, when the atomic number increases, the properties of the elements repeat regularly is the true statement.

The periodic table is a table that groups all chemical elements into groups based on their unique atomic numbers. Periods and groups, respectively, are the terms used to describe the periodic table's horizontal rows and vertical columns. The present periodic chart's inventor, Henry Moseley, claimed that "the properties of elements are periodic functions of their atomic numbers." The elements' properties are characterized by periodic patterns along groups and throughout eras, as seen by the present periodic table. The elements in the periodic table are separated into four groups, or blocks. They are components of the blocks s, p, d, and f. The categorization is based on the naming of the orbitals that take the last electron.

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Answer:

amount of gas and pressure

Answer:

\(\large \boxed{\text{3.45 L}}\)

Explanation:

We will need a balanced chemical equation with molar masses, so, let's gather all the information in one place.

Mᵣ:       122.55

           2KClO₃ ⟶ 2KCl + 3O₂

m/g:       25.5

(a) Moles of KClO₃

\(\text{Moles of KClO}_{3} =\text{25.5 g KClO}_{3} \times \dfrac{\text{1 mol KClO}_{3}}{\text{122.55 g KClO}_{3}} = \text{0.2081 mol KClO}_{3}\)

(b) Moles of O₂

The molar ratio is 3 mol O₂:2 mol KClO₃

\(\text{Moles of O$_{2}$}= \text{0.2081 mol KClO}_{3} \times \dfrac{\text{3 mol O$_{2}$}}{ \text{2 mol KClO}_{3}} = \text{0.3121 mol O$_{2}$}\)

(c) Volume of O₂

We can use the Ideal Gas Law to calculate the volume of hydrogen.

pV = nRT

T = (25.44 + 273.15) K =  298.59 K

\(\rm V = \dfrac{nRT}{p}= \dfrac{\text{0.3121 mol $\times$ 0.0821 L$\cdot$atm$\cdot$K$^{-1}$mol$^{-1}\times$ 298.59 K}}{\text{ 2.22 atm}} = \textbf{3.45 L} \\\\\text{The volume of oxygen is $\large \boxed{\textbf{3.45 L}}$}\)

Answer:

Solution:-

The balanced equation:

2KClO3 (s)  \rightarrow 2KCl (s) + 3 O2 (g)

Molar mass of KClO3 = 122.55 g/mol

Number of moles of KClO3 = (Mass of KClO3 / Molar mass of KClO3) = (25.5 g / 122.55 g/mol) = 0.2081 mol

From balanced equation, 2 mol of KClO3 produce 3 mol of O2. Or, 1 mol of KClO3 produces (3/2) mol of O2.

therefore, 0.2081 mol of KClO3 will produce = (3/2) × (0.2081) = 0.3121 mol of O2

Now, we have number of moles (n) of O2 = 0.3121 mol

Pressure (P) = 2.22 atm

Temperature (T) = 25.44°C = (273.15 + 25.44) K = 298.59 K

R (Gas constant) = 0.0821 L.atm/mol.K

Volume (V) of O2 = ?

Using the ideal gas equation,

V = nRT / P

Substituting the values in the equation, we get :

V = (0.3121 mol × 0.0821 L.atm/mol.K × 298.59 K) / (2.22 atm) = 3.45 L

Hence, the volume of O2 gas produced = 3.45 L

Explanation:

Answer:

Large leaves help plants to receive more sunlight when in tropical rainforests.

Answer:

uhhhhh not sure i cant see it

Explanation:

Answer:

2) a

3) c

explanation:

both gain from the relationship in number 2

while in number 3 one gains and one is hurt

Answer:

magnitude means absolute value, so the one that is greastest, like |-7| and |4| even id |-7| is a negative number, but it is still the one farthest away from 0, so |-7| is greater than |4|.

That is the way to find the greatest magnitude, but because I don't know your numbers so I can not answer your question, but this is the way to solve for it.

HOPE THIS HELPS!!!!!!!!!( IF IT DOES PLEASE MARK ME AS BRAINLIEST )

Answer:

First, we need to set up the equation for the ionization of HCHO2:

HCHO2 + H2O ↔ H3O+ + CHO2-

The Ka expression for this reaction is:

Ka = [H3O+][CHO2-]/[HCHO2]

We know the concentration of HCHO2 is 0.015 M, and the Ka value is 1.8 × 10^-4. We can use an ICE (initial, change, equilibrium) table to find the concentration of H3O+ and CHO2- at equilibrium:

HCHO2 + H2O ↔ H3O+ + CHO2-

I: 0.015 M 0 M 0 M 0 M

C: -x +x +x +x

E: 0.015-x x x x

Using the Ka expression, we can plug in our equilibrium concentrations (in terms of x):

1.8 × 10^-4 = x^2/(0.015-x)

Simplifying:

x^2 = 1.8 × 10^-4 (0.015-x)

x^2 = 2.7 × 10^-6 - 1.8 × 10^-4 x

Rearranging and using the quadratic formula:

x = [1.8 × 10^-4 ± sqrt((1.8 × 10^-4)^2 - 4(1)(-2.7 × 10^-6))] / 2(1)

x = 0.0136 or 0.00108

We reject the 0.0136 value, since it is greater than our initial concentration of 0.015 M. Therefore, our equilibrium concentration of H3O+ is 0.00108 M.

To find the pH, we take the negative logarithm of the H3O+ concentration:

pH = -log(0.00108) = 2.97

Therefore, the pH of a 0.015 M solution of HCHO2 is 2.97.

The main purpose of following the course of a reaction by TLC is to determine if all the starting material is converted to the product. Thin-layer chromatography (TLC) is a simple chromatographic method that helps to separate and purify the compounds from a mixture.

It is used for the qualitative analysis of organic compounds by following the course of a reaction by TLC.TLC is a quick and easy method for checking if the starting material has been completely converted to the product. The product and starting material can be separated by TLC if the product has different properties from the starting material. The result of the TLC analysis can be used to determine if the reaction is complete by comparing the Rf values of the starting material and the product. The product has a different Rf value than the starting material, making it easier to track the progress of the reaction. In conclusion, the main purpose of following the course of a reaction by TLC is to determine if all the starting material is converted to the product.

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Dependent variable - backpack produced

Independent variable -  types of cloth

Control group - backpack without cloth.

In an experiment, you have the dependent and the independent variable. The independent variable is the variable that we have to change in the experiment. The independent variable is the variable that changes as we change the values in of the independent variable.

Now, we can see that the experiment is about testing which type of cloth is best for backpacks. The independent variable in this case has to be the types of cloth while the dependent variable is the backpack produced. The control group is the backpack without cloth.

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Each water molecule is joined to Four other water molecules by Hydrogen bonds

As can be seen in the illustration on page 1 of the activity titled "The Polarity of Water" a water molecule is joined to four other water molecules by hydrogen bonds.

A hydrogen bond is an attraction between an electronegative atom carrying a single pair of electrons—the hydrogen bond acceptor—and a hydrogen atom that is covalently bonded to a more electronegative "donor" atom or group.

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The next step in the reaction mechanism is the removal of an acidic hydrogen from the carbon adjacent to the electron-deficient carbon (the carbocation) by the chloride ion. This step is known as deprotonation.

Deprotonation occurs when the chloride ion, which is a nucleophile, attacks the carbocation, which is an electrophile. The chloride ion donates its lone pair of electrons to form a new bond with the carbon, resulting in the transfer of the hydrogen atom from the carbon to the chloride ion. This forms a new molecule in which the chloride ion is now bonded to the carbon, and the hydrogen atom is released as a proton.

This deprotonation step helps stabilize the carbocation intermediate by reducing its positive charge. It also forms a new bond, completing the reaction and resulting in the formation of the final product. Overall, the deprotonation step plays a crucial role in the reaction mechanism by allowing the carbocation to react further with the chloride ion, leading to the formation of the desired product.

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The interactions that does not contribute to the tertiary structure of proteins is: a. peptide bonds

Peptide bonds are responsible for linking amino acids together to form the primary structure of proteins, while the tertiary structure is formed through interactions such as disulphide bridges (b), hydrogen bonds (c), salt bridges (d), and van der Waals interactions (e).

Proteins are the biomolecules formed by the polymerisation of the monomer i.e, amino acids. Two amino acids are linked with each other with the help of peptide bond. Peptide bond is formed between the carboxyl carbon of one amino acid and nitrogen of amino group of the other amino acid. Primary structure is the protein structure having linear sequence of amino acids held by peptide bond. Secondary structure of proteins are those structures in which intramolecular and intermolecular hydrogen bonding occurs between the primary structure of proteins. Due to intramolecular hydrogen bonding , alpha helices are formed and due to intermolecular hydrogen bonding, beta sheets are formed. Hydrogen bonding is a special type of bonding found between the hydrogen atom and the highly electronegative atom like flourine, oxygen and nitrogen.

Tertiary structure of proteins is formed when further more interactions like disulphide linkages (bonding between -SH groups) , salt bridges and van der waals interactions come into play in the protein structure . Quaternary structure of proteins are those in which more than one subunit bonds with other protein subunits.

Hence, peptide bond gives no contribution to the tertiary protein structure.

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The compounds made of the following molecules can be ordered by increasing melting point as follows: CH4 < H2O < NaCl.

1. CH_{4} (Methane) - This compound is a non-polar covalent compound, meaning that its melting point is determined by the weak dispersion forces between the molecules. Therefore, CH_{4} has the lowest melting point.
2. H_{2}O (Water) - This compound has polar covalent bonds and exhibits strong hydrogen bonding, which leads to a higher melting point than CH_{4}. However, it is still lower than the melting point of an ionic compound.
3. NaCl (Sodium Chloride) - This compound is an ionic compound, with strong electrostatic forces between the positively charged sodium ions and the negatively charged chloride ions. This results in a higher melting point than both CH_{4} and H_{2}O.
By analyzing the intermolecular forces present in CH_{4}, H_{2}O, and NaCl, we can order these compounds by increasing melting point as CH_{4} < H_{2}O < NaCl.
Considering the types of chemical bonds and intermolecular forces present in each compound (non-polar covalent bonds in CH_{4}, polar covalent bonds and hydrogen bonding in H_{2}O, and ionic bonds in NaCl), we can determine their melting points. In general, ionic compounds have the highest melting points, followed by compounds with hydrogen bonding, and finally non-polar covalent compounds. With this information, we can confidently order the compounds by increasing melting point asCH_{4} < H_{2}O < NaCl.

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Answer:

Nitrogen Trihydride

Explanation:

Ammonia is the common name of NH3. However, with this naming system, you should name it as a non-metal. Nitrogen trihydride.

Answer:

Nitrogen Trihydride

Explanation:

Answer:

the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

Explanation:

Hope this helps!