The difference of sample means of two populations is 55.4, and the standard deviation of the difference of sample means is 28.1. Which
statement is true if we are testing the null hypothesis at the 95% confidence level?

—ANSWER OPTIONS—

A The difference of the two means is significant, so the null hypothesis must be rejected.

B
The difference of the two means is significant, so the null hypothesis must be accepted.

C
The difference of the two means is not significant, so the null hypothesis must be rejected.

D
The difference of the two means is not significant, so the null hypothesis must be accepted.

During the morning rush hour, there are 6,400 junior and high school students, 3,400 adults, and 5,800 senior citizens riding the subway.

Let's assume the number of junior and high school students riding the subway during the morning rush hour is J, the number of adults is A, and the number of senior citizens is S.

From the given information, we can set up a system of equations based on the number of riders and the revenue generated.

Equation 1: J + A + S = 15,600 (total number of riders)

Equation 2: 1.04J + 2.20A + 1.04S = 32,464 (revenue equation with original ticket prices)

Equation 3: 1.24J + 2.60A + 1.04S = 38,264 (revenue equation with new ticket prices)

We can start by subtracting Equation 2 from Equation 3 to eliminate the J and S terms:

0.2J + 0.4A = 3,800

Next, we can multiply Equation 1 by 0.2 and subtract it from the above equation to eliminate the J term:

0.4A - 0.2J - 0.2A = 3,800 - 3,120

0.2A = 680

A = 680 / 0.2 = 3,400

Now, we can substitute the value of A back into Equation 1 to find the values of J and S:

J + 3,400 + S = 15,600

J + S = 15,600 - 3,400

J + S = 12,200

We have two equations with two variables (J + S = 12,200 and 1.04J + 1.04S = 12,264). By solving these equations simultaneously, we find J = 6,400 and S = 5,800.

Therefore, during the morning rush hour, there are 6,400 junior and high school students, 3,400 adults, and 5,800 senior citizens riding the subway.

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To find the number of subway riders in each category, we set up a system of equations based on the total number of passengers and the total revenue. Solving this system will give us the number of junior and high school students, adults, and senior citizens. The number of riders doesn't change with the increase of ticket prices.

To solve this problem, we set up a system of equations based on the information given in the question.

Let's denote the number of junior and high school students as J, adults as A, and senior citizens as S. We know that there's total of 15,600 passengers, so:

J + A + S = 15,600

We also know that the total revenue was $32,464. Given the ticket prices for each group, we can write:

$1.04J + $2.20A + $1.04S = $32,464

Solving this system of equations (possibly with the help of a calculator or computer software), we can find the number of riders in each category.

The number of riders for each category would only change if the number of riders changes, not the price of the tickets, so when the prices increase, the number of riders remains the same.

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Answer:

I = $650

A = $23,580

Step-by-step explanation:

First question

I = ?, P = $1000, R= 5%, T = 13

\(I = \frac{P*R*T}{100}=\frac{1000*5*13}{100}= 650\)

Therefore, interest = $650

Second...

P = $15, 000, R = 5.2%, T = 11, I = ? A= ?

\(I = \frac{P*R*T}{100}=\frac{15000*5.2*11}{100}= 8580\)

To find A, we add the principal with the interest

A = P + I = $15,000 + $8580 = $23,580

Answer:

-6

Step-by-step explanation:

one side of the equation is equaled to 4x-8 after you distribute the 2/3 so to make them equal you need a 2 on the other side 8-6 is 2

The two cars must be approximately 177.34 feet apart from each other for Spiderman to have different depression angles to each car.

To find the distance between the two cars, we can use trigonometry and the concept of similar triangles. Let's denote the distance between Spiderman and the nearest car as d1 and the distance between Spiderman and the farther car as d2.

In a right triangle formed by Spiderman, the height of the hotel, and the line of sight to the nearest car, the tangent of the depression angle (52 degrees) can be used:

tan(52) = 600 / d1

Rearranging the equation to solve for d1:

d1 = 600 / tan(52)

Similarly, in the right triangle formed by Spiderman, the height of the hotel, and the line of sight to the farther car, the tangent of the depression angle (46 degrees) can be used:

tan(46) = 600 / d2

Rearranging the equation to solve for d2:

d2 = 600 / tan(46)

Using a calculator, we can compute:

d1 ≈ 504.61 feet

d2 ≈ 681.95 feet

The distance between the two cars is the difference between d2 and d1:

Distance = d2 - d1

Plugging in the values, we have:

Distance ≈ 681.95 - 504.61

Distance ≈ 177.34 feet

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The correct value of particle's acceleration at t = 2 seconds is -1/12 m/s^2.

To find the particle's velocity, we need to take the derivative of the position function with respect to time (t).

Given the position function:

s = √24 + 6t

To find the velocity, we differentiate the position function with respect to time:

v = ds/dt

Applying the power rule and chain rule for differentiation, we get:

v = (1/2) * (24 + 6t)^(-1/2) * 6

Simplifying further:

v = 3 / √(24 + 6t)

To find the velocity at t = 2 seconds, we substitute t = 2 into the velocity equation:

v = 3 / √(24 + 6(2))

v = 3 / √(24 + 12)

v = 3 / √36

v = 3 / 6

v = 1/2 m/s

So, the particle's velocity at t = 2 seconds is 1/2 m/s.

Now, let's find the particle's acceleration. Acceleration is the derivative of velocity with respect to time.

a = dv/dt

To find the acceleration, we differentiate the velocity function with respect to time:

a = d(3 / √(24 + 6t)) / dt

Applying the quotient rule and chain rule, we get:

a = -3 * (24 + 6t)^(-3/2) * 6

Simplifying further:

a = -18 / (24 + 6t)^(3/2)

To find the acceleration at t = 2 seconds, we substitute t = 2 into the acceleration equation:

a = -18 / (24 + 6(2))^(3/2)

a = -18 / (24 + 12)^(3/2)

a = -18 / 36^(3/2)

a = -18 / 36^(3/2)

a = -18 / 216

a = -1/12 m/s^2

So, the particle's acceleration at t = 2 seconds is -1/12 m/s^2.

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The value of x using trigonometric functions will be 5.66.

What are trigonometric functions?

Trigonometric functions are also known as Circular Functions can be simply defined as the functions of an angle of a triangle. It means that the relationship between the angles and sides of a triangle are given by these trigonometric functions. The basic trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant.

The angles of sine, cosine, and tangent are the primary classification of functions of trigonometry. And the three functions which are cotangent, secant and cosecant can be derived from the primary functions

Now,

In given triangle, 3rd angle will be 54 degree.

                                         (Sum of all angle in triangle=180degree)

Therefore

               sin 54=P/H  (P=Perpendicular, H=Hypotenuse)

                0.809=x/7

               x=7*0.809

              x=5.66

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Objects commonly found in a locality include residential buildings, commercial establishments, public facilities, transportation infrastructure, landmarks, natural features, utilities, street furniture, and vehicles.

The type of objects that can be found in a locality can vary greatly depending on the specific location and its surroundings. Here are some common types of objects that can be found in a locality:

Residential Buildings: Houses, apartments, condominiums, and other types of residential structures are commonly found in localities where people live.

Commercial Establishments: Localities often have various types of commercial establishments such as stores, shops, restaurants, cafes, banks, offices, and shopping centers.

Public Facilities: Localities typically have public facilities such as schools, libraries, hospitals, community centers, parks, playgrounds, and sports facilities.

Transportation Infrastructure: Localities usually have roads, sidewalks, bridges, and public transportation systems like bus stops or train stations.

Landmarks and Monuments: Some localities may have landmarks, historical sites, monuments, or cultural attractions that represent the area's heritage or significance.

Natural Features: Depending on the locality's geographical characteristics, natural features like parks, lakes, rivers, mountains, forests, or beaches can be present.

Utilities: Localities have infrastructure for utilities such as water supply systems, electrical grids, sewage systems, and telecommunications networks.

Street Furniture: Localities often have street furniture like benches, streetlights, waste bins, traffic signs, and public art installations.

Vehicles: Various types of vehicles can be found in a locality, including cars, bicycles, motorcycles, buses, trucks, and possibly other modes of transportation.

It's important to note that the objects present in a locality can significantly differ based on factors such as urban or rural setting, cultural context, economic development, and geographical location.

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The value of angle x and angle y is determined as 78⁰ and 115⁰ respectively.

The value of angle x and angle y is calculated by applying principle of angles formed by parallel lines as follows;

The value of angle adjacent x = 102⁰

The value of angle x   is calculated as;

x = 180 - 102 ( sum of angles on a straight line)

x = 78⁰

The value of angle y is calculated as follows;

y = 115⁰ (corresponding angles are equal)

Thus, the value of angle x and angle y is determined as 78⁰ and 115⁰ respectively.

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Answer:

Step-by-step explanation:

y

=

1

3

x

−

3

Use the slope-intercept form to find the slope and y-intercept

Slope:

1

3

y-intercept:

(

0

,

−

3

)

Any line can be graphed using two points. Select two

x

values, and plug them into the equation to find the corresponding

y

values.

x

y

0

−

3

3

−

2

Graph the line using the slope and the y-intercept, or the points.

Slope:

1

3

y-intercept:

(

0

,

−

3

)

x

y

0

−

3

3

−

2

image of graph

Answer:

Please do step by step)

hope I gave

4m+2

because 2mx2=4m and 1x2=2 so 4m+2

Answer: 4m + 2

gvrfcedwx

Answer:

  135°

Step-by-step explanation:

Angels are beyond value.

__

1 1/2 right angles will have the measure ...

  1.5 × 90° = 135°

Answer:a

Step-by-step explanation:

I would explain but it’s a lot of work sorry

Answer:

it's 4 because i got it right         100%

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

252 divided by 18 = 14

hope this helps! :D

Answer:

\(\displaystyle (-3,\frac{9}{2})\)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Endpoint Q(1, 6)

Endpoint R(-7, 3)

Step 2: Find Midpoint

Simply plug in your coordinates into the midpoint formula to find midpoint

the constant is the number that is multiplying the x, so in this case we get that

The function rule for g(x) is h(x) = (x - 0)² - 7.

In Mathematics, the vertex form of a quadratic function is represented by the following mathematical equation:

f(x) = a(x - h)² + k

Where:

Based on the information provided about the vertex (0, -7) and other points (-3, 2), we can determine the value of a as follows:

f(x) = a(x - h)² + k

2 = a(-3 - 0)² - 7

2 + 7 = 9a

9 = 9a

a = 1

Therefore, the required quadratic function in vertex form is given by:

h(x) = a(x - h)² + k

h(x) = (x - 0)² - 7

h(x) = x² - 7

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The values of the complex expressions are ✓(x - iy) = a - ib and x² + y² =  (a + ib)²(a - ib)²

From the question, we have the following parameters that can be used in our computation:

✓(x + iy) = a + ib

Changing the signs, we have

✓(x - iy) = a - ib

Multiply both expressions

This gives

✓(x + iy) * ✓(x - iy) =  (a + ib)(a - ib)

Square both sides

So, we have

(x + iy) * (x - iy) =  (a + ib)²(a - ib)²

This gives

x² + y² =  (a + ib)²(a - ib)²

Hence, the values of ✓(x - iy) is a - ib and x² + y² is  (a + ib)²(a - ib)²

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Answer:

given functions:

\(\sf f(x)=x^2+3x-7\)

\(\sf g(x)=3x+5\)

\(\sf h(x)=2x^2-4\)

solving steps:

(a)

\(\sf f(g(x))\)

\(\sf \sf f(3x+5)\)

\(\sf (3x+5)^2 + 3(3x+5)-7\)

\(\sf 9x^2+30x+25+9x+15-7\)

\(\sf 9x^2+39x+33\)

(b)

\(\sf h(g(x))\)

\(\sf h(3x+5)\)

\(\sf 2(3x+5)^2-4\)

\(\sf 18x^2+60x+50-4\)

\(\sf 18x^2+60x+46\)

(c)

\(\sf (h-f)(x)\)

\(\sf 2x^2-4-(x^2+3x-7)\)

\(\sf 2x^2-4-x^2-3x+7\)

\(\sf x^2-3x+3\)

(d)

\(\sf (f+g)(x)\)

\(\sf x^2 + 3x -7 +3x+5\)

\(\sf x^2+6x-2\)

Answer:

(2a^3a^4)^5 simplifies to 32a^35.

Step-by-step explanation:

To simplify (2a^3a^4)^5, we can use the properties of exponents which states that when we raise a power to another power, we can multiply the exponents. Therefore, we can rewrite the expression as:

(2a^3a^4)^5 = 2^5 * (a^3a^4)^5

Next, we can simplify the expression inside the parentheses by multiplying the exponents:

a^3a^4 = a^(3+4) = a^7

Substituting this into our expression, we get:

(2a^3a^4)^5 = 2^5 * (a^3a^4)^5 = 2^5 * a^35

Finally, we can simplify this expression by using the property of exponents that states that when we multiply two powers with the same base, we can add their exponents. Therefore, we can rewrite the expression as:

2^5 * a^35 = 32a^35

Therefore, (2a^3a^4)^5 simplifies to 32a^35.

The average change as a simplified mixed number would be,

⇒ 1 3/4

A fraction is a part of whole number, and a way to split up a number into equal parts. Or, A number which is expressed as a quotient is called fraction. It can be written as the form of p : q, which is equivalent to p / q.

We have to given that;

The running back for the Bulldogs football team carried the ball 7 times for a total loss of 12 1/4 yards.

Now, The average change as a simplified mixed number would be,

⇒ (12 1/4) / 7

⇒ (49/4) / 7

⇒ (49 / 4×7)

⇒ 7/4

⇒ 1 3/4

Therefore, The average change is,

⇒ 1 3/4

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Answer:

The given statement makes sense ( or is clearly true )

Step-by-step explanation:

As given ,

Siena wins each of the first two sets of a tennis tournament by winning more games than her opponent in the first set and also winning more games than her opponent in the second set. It follows that Siena won more games than her.

The sentence makes sense (or is clearly true)

Reason -

Siena and her opponent plays 2 sets of a tennis tournament.

In the first set of the tournament , Siena wins more games than her opponent, that means Siena is leading her opponent in the first set.

In the second set of the tournament , Siena wins more games than her opponent , that means Siena is leading her oponent in the second set.

From the above 2 statements of the two sets of the tournament , we can easily say that Siena won more games than her opponent overall in the first 2 sets because Siena is leading both the sets.

So the statement is making sense.

Using Maxwell's equations, we can determine the magnetic flux density. One of the Maxwell's equations is:

\(\displaystyle \nabla \times \mathbf{H} = \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t}\),

where \(\displaystyle \nabla \times \mathbf{H}\) is the curl of the magnetic field intensity \(\displaystyle \mathbf{H}\), \(\displaystyle \mathbf{J}\) is the current density, and \(\displaystyle \frac{\partial \mathbf{D}}{\partial t}\) is the time derivative of the electric displacement \(\displaystyle \mathbf{D}\).

In this problem, there is no current density (\(\displaystyle \mathbf{J} =0\)) and no time-varying electric displacement (\(\displaystyle \frac{\partial \mathbf{D}}{\partial t} =0\)). Therefore, the equation simplifies to:

\(\displaystyle \nabla \times \mathbf{H} =0\).

Taking the curl of the given magnetic field intensity \(\displaystyle \mathbf{R} =2\cos( 10^{10} t-600x)\hat{a}_{z}\, \text{Am}\):

\(\displaystyle \nabla \times \mathbf{R} =\nabla \times ( 2\cos( 10^{10} t-600x)\hat{a}_{z}) \, \text{Am}\).

Using the curl identity and applying the chain rule, we can expand the expression:

\(\displaystyle \nabla \times \mathbf{R} =\left( \frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial y} -\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial z}\right) \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Since the magnetic field intensity \(\displaystyle \mathbf{R}\) is not dependent on \(\displaystyle y\) or \(\displaystyle z\), the partial derivatives with respect to \(\displaystyle y\) and \(\displaystyle z\) are zero. Therefore, the expression further simplifies to:

\(\displaystyle \nabla \times \mathbf{R} =-\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial x} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Differentiating the cosine function with respect to \(\displaystyle x\):

\(\displaystyle \nabla \times \mathbf{R} =-2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Setting this expression equal to zero according to \(\displaystyle \nabla \times \mathbf{H} =0\):

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z =0\).

Since the equation should hold for any arbitrary values of \(\displaystyle \mathrm{d} x\), \(\displaystyle \mathrm{d} y\), and \(\displaystyle \mathrm{d} z\), we can equate the coefficient of each term to zero:

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x) =0\).

Simplifying the equation:

\(\displaystyle \sin( 10^{10} t-600x) =0\).

The sine function is equal to zero at certain values of \(\displaystyle ( 10^{10} t-600x) \):

\(\displaystyle 10^{10} t-600x =n\pi\),

where \(\displaystyle n\) is an integer. Rearranging the equation:

\(\displaystyle x =\frac{ 10^{10} t-n\pi }{600}\).

The equation provides a relationship between \(\displaystyle x\) and \(\displaystyle t\), indicating that the magnetic field intensity is constant along lines of constant \(\displaystyle x\) and \(\displaystyle t\). Therefore, the magnetic field intensity is uniform in the given medium.

Since the magnetic flux density \(\displaystyle B\) is related to the magnetic field intensity \(\displaystyle H\) through the equation \(\displaystyle B =\mu H\), where \(\displaystyle \mu\) is the permeability of the medium, we can conclude that the magnetic flux density is also uniform in the medium.

Thus, the correct expression for the magnetic flux density in the given medium is:

\(\displaystyle B =6\cos( 10^{10} t-600x)\hat{a}_{z}\).

Answer:

Step-by-step explanation:

Answer:

Your answer would be 20 not 10

Step-by-step explanation:

trust me i took the test

Answer:

b = 8

Step-by-step explanation:

7b-20=3b+12

7b - 3b - 20 = 3b -3b + 12

4b - 20 = 12

4b - 20 + 20 = 12 +20

4b = 32

b = 8

X = 31, Y = 63 satisfy the case of 0 ≤ Y < 100 as an expression.

An algebraic expression in mathematics is an expression that consists of variables and constants and algebraic operations (addition, subtraction, etc.). Expressions are made up of concepts.

Assume Kaimi was supposed to be paid X dollars Y cents (0 ≤ Y ≤ 100)

But the teller gave him Y dollars X cents.

Thus kaimi has 100Y + X cents.

A nickel is worth 5 cents.

Hence, after buying the piece of candy for a nickel, Kaimi would be left with 100Y + X - 5 cents.

This is twice his paycheck:

⇒ 100Y + X - 5 = 2(100X + Y)

⇒ 100Y + X - 5 = 200X + 2Y

⇒ 98Y - 199X = 5

199 = 98 × 2 + 3 ⇒ 3 = 199 - 98 × 2

98 = 3 × 32 + 2 ⇒ 2 = 98 - 3 × 32

3 = 2 × 1 + 1 ⇒ 1 = 3 - 2 × 1

2 = 1 × 2 + 0 ⇒ ged(199, 98) = 1

1 = 3 - 2 × 1

= 3 - (98 - 3 × 32) × 1                [∵ 2 = 98 - 3 × 32]

= 3 - 98 × 1 + 3 × 32

= 3 × 33 - 98 × 1

= (199 - 98 × 2) × 33 - 98 × 1    [∵ 3 = 199 - 98 × 2]

= 199 × 33 - 98 × 67

⇒ 1 = 199 × 33 - 98 × 67

⇒ 5(1) = 5 (199 × 33 - 98 × 67)

⇒ 5 = 199(165) - 98(335)         [∵ 5 ×33 = 165, 5 × 67 = 335]

⇒ 199(165) - 98(335) = 5

⇒ 98(-335) - 199(-165) = 5

Hence, (X,Y) = (-165, -335) is a solution to 98Y - 199X = 5

But it is required that 0 ≤ Y < 100

Now since it is the difference of two quantities, 98Y and 199X, that is a constant, 5, either both of these quantities will increase simultaneously or both will decrease simultaneously.

Hence, either both X, Y will increase or both, X, Y will decrease.

To bring Y = -335 in the range of 0 ≤ Y < 100, it needs to be increased.

Hence, both X, Y will increase.

X will increase by the absolute value of the coefficient of Y and vice-versa. Hence, X will increase by 98 and Y will increased by 199 to give

(X, Y) = (-165 + 98, -335 +199) = (-67, -136)

Still, it is not the case that 0 ≤ Y < 100

Hence, again X will increase by 98 and Y will increase by 199 to give

(X, Y) = (-67 +98, -136 +199) = (31, 63)

Now, it is the case that 0 ≤ Y = 63 < 100

∴ X = 31, Y = 63

Note that the increasing X again by 98 and Y by 199 will violate

0 ≤ Y < 100. Hence, this is the unique solution.

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Answer:

5/4 > 5/6

Step-by-step explanation: