The decomposition of a single compound at 349 K has a rate constant of 4.10 x 10-3 M s1. If the initial
concentration of the reactant is 1.304 M, what is the concentration of the reactant after 90.45 seconds?
(the answer should be entered with 3 significant figures; do not enter units; give answer in normal
notation-examples include 1.23 and 12.3 and 120. and -123)
Selected Answer:
Correct Answer:
0.933
0.933 ±1%

A sulfuric acid solution with a concentration of 0.189M has a pH of roughly 0.778.

A diprotic acid is sulfuric acid, Sulfurous acid. The findings of an acid-base titration can be used to calculate the values of Ka1 and Ka2. To completely neutralise diprotic acids, two hydroxide ions are needed for each molecule. Sulfuric acid, a stronger acid than Hydrogen sulfide, with a pH of 1.5 in a solution of 0.100 mol dm³.

The chemical equation for sulfuric acid dissociation is as follows:

Sulfuric acid + Water ⇌ Hydronium ion + hydrosulfite anion

Write the expression for the acid dissociation constant (Ka1) for the first dissociation:

Ka1 = [Hydronium ion[hydrosulfite anion]/[Sulfuric acid]

Substitute the given value of Ka1 (1.39×10−2) and the initial concentration of Sulfuric acid (0.189 M) into the expression for Ka1 and solve for [hydronium ion]:

1.39×10−2 = [hydronium ion][Hydrogen sulfite]/0.189

[hydronium ion] = 0.167 M

pH = -log[hydronium ion]

pH = -log(0.167)

pH = 0.778

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The right answer to the previous question and the correct observation of a chemical property is that zinc reacts with hydrochloric acid.

ZnCl2 +H2 = Zn +2HCL

Balanced equation:  

ZnCl2 + H2 Zn + 2HCL

Zinc is a chemical element, designated by the symbol Zn and the atomic number 30. When the oxidation is removed, zinc turns shiny-greyish and at room temperature turns into a somewhat brittle metal.

All living things, including people, animals, plants, and microorganisms, depend on the trace metal zinc. It is the trace metal that is present in people in the second-highest concentration after iron. Zinc is an essential nutrient for development and a key cofactor for various enzymes. A lack of zinc can lead to a variety of diseases. Deficiency can lead to diarrhoea, infection susceptibility, and slower growth.

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The equilibrium constant for the reaction is K = 0.137

We obtain the equilibrium constant considering the following equilibria and their constants:

COO(s) + H₂(g) → Co(s) + H₂O(g)    K₁ = 67

COO(s) + CO(g) → Co(s) + CO₂(g)   K₂ = 490

We write the first reaction in the forward direction because we need H₂(g) in the reactants side:

(1)     COO(s) + H₂(g) → Co(s) + H₂O(g)    K₁ = 67

Then, we write the second reaction in the reverse direction because we need CO₂(g) in the reactants side. Thus, the equilibrium constant for the reaction in the reverse direction is the reciprocal of the constant for the reaction in the forward direction (K₂):

(2)   Co(s) + CO₂(g) → COO(s) + CO(g)   K₂ = 1/490

From the addition of (1) and (2), we obtain:

COO(s) + H₂(g) → Co(s) + H₂O(g)    K₁ = 67

+

Co(s) + CO₂(g) → COO(s) + CO(g)   K₂ = 1/490

-------------------------------------------------

H₂(g) +  CO₂(g) → CO(g) + H₂O(g)

Notice that Co(s) and COO(s) are removed that appear in the same amount at both sides of the chemical equation.

Now, the equilibrium constant K for the reaction that is the sum of other two reactions is calculated as the product of the equilibrium constants, as follows:

K = K₁ x K₂ = 67 x 1/490 = 67/490 = 0.137

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Gasoline, rubber, and plastics all use alkane, alkene, and alkyne, respectively. Examples of alkanes include methane (CH4) and ethane (C2H6). Alkenes include substances like propane (C3H8) and ethene.

Alkanes are saturated hydrocarbons in nature. Saturated hydrocarbons are alkanes with only one atom in the chemical structure. The formula for an alkane is CnH2n+2. Methane, butane, propane, and ethane are the four alkanes.

The simplest alkane molecule, methane, is made up of one carbon atom and four covalently bound hydrogen atoms. The compounds were detected as the methyl compound is created when we swap out one hydrogen atom for another atom or molecule.

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We must first balance the equation, we have two atoms of nitrogen and hydrogen in the reactants, so we must put the coefficient 2 on the side of the products to balance the equation. The balanced equation of the reaction will be:

Now, to find the grams of NH that will be produced, we will follow these steps:

1. We find the moles of N2 and H2 by dividing the grams by the molar mass of each element.

Molar Mass N2=28.0g/mol

Molar Mass H2=2.0g/mol

2. By stoichiometry we find out which is the limiting reactant, we see that for each mole of H2 one mole of N2 reacts, therefore, the limiting reactant will be the one with the least number of moles. The other reactant will be the excess reactant

3. We find the moles of NH using the limiting reactant.

4. We find the grams of NH by multiplying the moles by the molar mass of NH.

5. We find how much of the excess reactant is left by subtracting the initial moles minus the reacting moles.

Let's proceed with the calculations

1. Moles of N2 and H2

2. Limiting reactant

We see that there are 22.5 moles of H2 and 1.25 moles of N2. The ratio N2 to H2 is 1/1, therefore, the limiting reactant will be the one with fewer moles, since it will be consumed faster. Therefore, the limiting reactant is nitrogen.

3. Moles of NH

The ratio NH to N2(Limiting reactant) is 2/1, therefore the moles of NH produced will be:

4. Mass of NH

5. Excess of H2

The mass of H2 left over will be:

Answer: 15.0 grams of NH will be produced and the excess will be 42.5g of H2

Solution :

Millimoles of hydrocyanic acid = 225 x 0.368

                                                   = 82.8

Millimoles of potassium cyanide = 225 x 0.360

                                                   = 81

Millimoles of sodium hydroxide = 51.3

Therefore,

pOH = pKb + log [salt - C / bas + C]

        = 4.74 + log[82.8 - 51.3 / 81 + 51.3]

         = 4.102

Therefore, pH = 9.05

Answer:

if the forces among the particles that makeup the nucleus are balanced, it is stable. Stable atoms retain their form indefinitely, while unstable atoms undergo radioactive decay. Most naturally occurring atoms ate stable and do not decay. A stable atom has a net charge of 0. In other words, It has an equal number of protons and electrons.

When fossil fuels burn, several forms of energy are produced, including:

Heat energy: The primary form of energy released during fossil fuel combustion is heat. Fossil fuels contain chemical energy stored for millions of years, and when they burn, this energy is released in the form of heat. The heat energy can be harnessed for various purposes, such as heating buildings or generating steam to drive turbines.

Light energy: Burning fossil fuels can also produce light energy in the form of flames or glowing embers. This light energy is a byproduct of combustion.

Mechanical energy: Heat generated by burning fossil fuels can be converted into mechanical energy. This is typically achieved by using heat to produce steam, which drives a turbine connected to a generator. The rotating turbine converts the heat energy into mechanical energy, which is further transformed into electrical energy.

Electrical energy: Through the process described above, burning fossil fuels can ultimately generate electrical energy. The mechanical energy produced by the turbine is converted into electrical energy by the generator. Electrical energy can power various devices, appliances, industries, and infrastructure.

It's critical to note that while burning fossil fuels can produce useful forms of energy, it also results in the release of carbon dioxide and other greenhouse gases. This contributes to climate change and environmental concerns. As a result, there is a global shift towards cleaner and renewable energy sources to mitigate these negative impacts.

C. The pH stays about the same.

Answer:

C.The pH stays about the same.

Explanation:

Buffer reactions maintain stable pH of solutions.

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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The theoretical yield is the amount of copper that would be obtained if the reaction proceeded with 100% efficiency, based on the stoichiometry of the reaction and the amount of limiting reagent used.

The percentage yield of copper can be calculated using the formula:

Percentage yield = (actual yield / theoretical yield) x 100%

In this case, the actual yield is given as 0.872 g. The theoretical yield is the amount of copper that would be obtained if the reaction proceeded with 100% efficiency, based on the stoichiometry of the reaction and the amount of limiting reagent used.

In general, the percentage yield is a measure of how efficient a chemical reaction is in producing the desired product. It is calculated by comparing the actual yield obtained in the experiment to the theoretical yield that would be obtained under ideal conditions.

A high percentage yield indicates that the reaction is efficient and that the experimental setup is effective in producing the desired product. A low percentage yield indicates that there are inefficiencies or losses in the reaction, and that improvements may be needed in the experimental setup or reaction conditions.

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The heat energy q of water can be calculated using calorimetric equation. The heat energy of water in the given reaction is, 551.76 J.This reaction is endothermic where change in heat energy is positive.

Calorimetry is an analytical technique used to determine the heat energy absorbed or evolved in a reaction. The calorimetric equation connecting the mass  m of reactant, specific heat capacity q and the temperature difference Δ T is:

q = m c  Δ T.

It is given that temperature changes from 25 to 26.2 degree celsius and mass of water is 110 g. The specific heat capacity of water is 4.18 J/g °C.

The heat energy of water is then calculated as follows:

q = 110 g ×  4.18 J/g °C × (26.2 - 25 °C)

  = 551.76 J.

Hence, the heat energy change in this reaction is 551.76 J.

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Your question is incomplete, but, your complete question probably was:

The temperature of 110 g of water rises from 25.0 C to 26.2 C when 0.10 mol of H+ is reacted with 0.10 mol of OH-. Calculate q OF water ...

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Explanation:

The 5s,5p and 5d orbitals hybridise to form seven sp3 d3 hybrid orbitals. The molecule is then formed with 7 fluorine atoms. The geometry of this molecule is pentagonal bipyramidal . Five F atoms are in one plane directed at corners of a pentagon (equatorial position), with 72º angle between them.

please Mark as brainliest and follow

Answer:

bent and trigonal planar

Explanation:

Answer:

Well no because if metals lose electrons, any non-metal sources/items gain electrons from the metal.

Answer:

Metals tend to lose electrons and non-metals tend to gain electrons, so in reactions involving these two groups, there is electron transfer from the metal to the non-metal

Explanation:

Answer:

52.4%

Explanation:

Since a simple cubic unit cell contains only 1 atom. The packing efficiency of the simple cubic cell is 52.4 %

Answer:

Explanation:

From the information given:

The Chemical equation is:

\(SO_2Cl_{2(g)} \iff SO_{2(g)} + Cl_{2(g)}\\\)

since 43.6% of the initial concentration remains at equilibrium

Then; the amount of \(SO_2Cl_2\) that is being reacted is:

= 0.543 × (100 -43.6)%

= 0.306 M

The ICE table can be computed as follows:

           \(SO_2Cl_2\)               ⇔           \(SO_{2(g)\)           +             \(Cl_{2(g)\)

I            0.543                                    0                           0

C          0.306                                 +0.306                     0.306

E           0.237                                  0.306                      0.306

\(K_c = \dfrac{[SO_2] [Cl_{2}]}{[SO_2Cl_2]}\)

\(K_c = \dfrac{0.306 \times 0.306}{0.237}\)

\(K_c = 0.995\)

Thus; the concentration at equilibrium for the species are:

\(SO_2Cl_2\)  = 0.237 M

\(SO_{(2g)\) = 0.306 M

\(Cl_{2(g)\) = 0.306 M

The burette is filled with 0.3000 M NaOH. The beaker has 25.00 mL of 0.3000 M HCl.volume of 0.3000 M NaOH was required by the titration to reach the equivalence point is 25 mL.

The equivalence point is the point where mole of each solution are equal to each other.The chemical equation is given as :

NaOH +   HCl   ---->   NaCl    +  H₂O

The molarity expression is given as :

molarity = moles / volume

moles = molarity × volume

moles = 0.300 × 0.025

moles = 0.0075 mol

number of moles of HCl = number of moles of NaOH

moles of NaOH = 0.0075 mol

volume of NaOH = moles / molarity

                            = 0.0075 / 0.300

                            = 0.25 L = 25 mL

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The process of changing the Gibbs free energy if positive is always nonspontaneous

Gibbs Free Energy is one of the thermodynamic parameters that states whether the continuity of a reaction occurs spontaneously or not spontaneously. The equilibrium composition of a reaction is determined by DG° and K. The value of G will change as the chemical composition of the reactants changes to the products.

Gibbs free energy is denoted by G and expressed in the equation G = H – TS.

Gibbs Helmholtz equation:

ΔG = ΔH − TΔS

This equation is very useful in predicting the spontaneity of a process.

So if the process of changing the Gibbs free energy if it is positive then the process is always nonspontaneous

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1 is true

2 is d 7

3 is

            1             e

            2             b

            3             d

            4             a

            5             c

Answer:

The answer should be A. Adding carbon to iron makes it tougher and stronger.

The addition of carbon atom to iron metal, enhances the property of hardness of metal.

Alloy is a compound which is formed by the mixture of two or more than two metals with different properties to make a new compound with better properties.

When we add carbon atom in the iron metal, it deviates the crystal lattice property of iron and makes it more harder. So, the content of carbon in the iron is directly proportional to the hardness of iron metal.

Hence, option (A) is correct i.e. hardness.

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Answer:

owa owa owa owa

Explanation:

owa owa owa owa owa owa owa

Answer:D

Explanation:

Decomposers decompose food and return it to the environment through the soil

The difference between hard alkali and soft alkali is the presence of electrons in valence shell.

Alkali is one of a class of caustic bases, such as soda, soda ash, caustic soda, potash, ammonia, and lithia, whose distinguishing peculiarities are solubility in alcohol and water.

Due to the presence of this single electron in their valence shell, alkali metals are soft in nature.

Examples of strong alkalis (lyes) include barium, sodium, ammonium, calcium, lithium, and potassium hydroxides.

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Answer:

4.42 x 10^22 molecules

Explanation:

1 mole of CO2 has 6.022 x 10^23 molecules

=> 0.0734 x 6.022 x 10^23 = 4.420148 x 10^22 or 4.42 x 10^22

The balanced chemical equation for the given reaction is:

Fe2(C2O4)3 → 2FeC2O4 + 3CO2

In this equation, we have two Fe atoms and six C atoms on both sides, and also six O atoms on both sides. To balance the equation, we can first start with the Fe atoms and balance them by adding a coefficient of 2 in front of FeC2O4:

Fe2(C2O4)3 → 2FeC2O4 + ...

Now we have two Fe atoms on both sides. Next, we can balance the C atoms by adding a coefficient of 3 in front of CO2:

Fe2(C2O4)3 → 2FeC2O4 + 3CO2

Finally, we can check that the equation is balanced by counting the number of atoms on both sides:

Fe2(C2O4)3: 2 Fe, 6 C, 12 O

2FeC2O4: 2 Fe, 6 C, 12 O

3CO2: 0 Fe, 3 C, 6 O

The number of atoms is the same on both sides, so the equation is balanced.

Answer:

2Fe(C2O4) + 2CO2 → Fe2(C2O4)3

The moles of ammonium phosphate produced by the reaction of 0. 085 mol of ammonia is 0.042 moles

The balanced chemical equation for the reaction between phosphoric acid and liquid ammonia to produce ammonium phosphate is:

2NH₃ + H₃PO₄ → (NH₄)₂HPO₄

From the balanced equation, we can see that 2 moles of ammonia react with 1 mole of phosphoric acid to produce 1 mole of ammonium phosphate.

To find the moles of ammonium phosphate produced from 0.085 moles of ammonia, we can use the mole ratio from the balanced equation:

(0.085 moles NH₃) × (1 mole (NH₄)₂HPO₄ / 2 moles NH₃) = 0.0425 moles (NH₄)₂HPO₄

Therefore, the moles of ammonium phosphate produced by the reaction of 0.085 moles of ammonia is 0.0425 moles. The answer should be rounded to the correct number of significant digits, which is 2, since the given value of ammonia has 2 significant digits.

The final answer is 0.042 moles of ammonium phosphate.

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Answer:

idk

Explanation:

idk cool pee bee mee nee hee gee fee kee

In a 784 gram pure sample of NC13, there are approximately 1.33 x 10²⁵ chlorine atoms.

To determine the number of chlorine (Cl) atoms in a given sample, we need to utilize the Avogadro's number and the molar mass of chlorine.

The molar mass of chlorine (Cl) is approximately 35.45 grams/mol. To calculate the number of moles in the sample, we divide the given mass by the molar mass:

Number of moles of Cl = Mass / Molar mass

Number of moles of Cl = 784 g / 35.45 g/mol

Number of moles of Cl ≈ 22.08 mol

According to Avogadro's number, there are 6.022 x 10²³ entities (atoms, molecules, or formula units) in 1 mole of a substance. Therefore, to find the number of chlorine atoms, we multiply the number of moles by Avogadro's number:

Number of Cl atoms = Number of moles of Cl x Avogadro's number

Number of Cl atoms = 22.08 mol x 6.022 x 10²³ atoms/mol

Number of Cl atoms ≈ 1.33 x 10²⁵ atoms

Therefore, in a 784 gram pure sample of NC13, there are approximately 1.33 x 10²⁵ chlorine atoms.

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