The current flowing through a circuit is changing at a rate of 6.00 A/s. If the circuit contains a 190.0 H inductor, what is the emf across the inductor?

Given,

On simplifying,

Thus,

Or

Thus, x=9 and x=-15

Therefore the correct answer is the third option

Impulse is equal to the change in momentum of an object. The momentum of an object is equal to its mass times its velocity.

The initial momentum of the dog is 80kg * 2m/s = 160kg*m/s.

The final momentum of the dog is 80kg * 3m/s = 240kg*m/s.

The change in momentum of the dog is 240kgm/s - 160kgm/s = 80kg*m/s.

Therefore, the impulse on the dog is 80kg*m/s.

Answer:

680.4

Explanation:

the formula is V1 over T1 is equals (=) to V2 over T2 .

and we have been given that

V1 represents 315

T1 represents 25°c

V2 is unknown and what we're finding

T2 represents 54°c

so 315×54 all over 25 ...gives you 680.4

steadily along a uniform flow tube of cross section area 20cm². The total pressure is 3x104pa and static pressure is 2.5x104 pa. Calculate the velocity of the fluid.

Answer:

17.5 m/s

Explanation:

We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.

A. We need to compute the entire cross-sectional area of the prime movers for elbow flexion and multiply it by the specific tension of muscle to get the maximum force that the elbow flexors can produce. The elbow flexors have a total cross-sectional area of 3.6 + 6.0 + 1.5 = 11.1 cm2. As a result, the elbow flexors may exert the following amount of force:

Cross-sectional area times a certain tension equals force.

Force = 333 N Force = 11.1 cm2 x 30 N/cm2

B. We must compare the torques generated by the triceps and the elbow flexors in order to determine whether the elbow will flex or extend. A muscle's torque is determined by multiplying the force it exerts by the moment arm. The moment arm is the angle at which the muscle's line of action is perpendicular to the axis of rotation.

The total torque for the elbow flexors is:

Torque equals force times moment arm

Torque equals 333 N/4 cm.

1332 N cm of torque

The total torque for the triceps is:

Torque equals force times moment arm

Torque is equal to 17.8 cm2 x 30 cm2 x 2.5 cm.

1335 N cm of torque

Since the triceps generate slightly more torque than the elbow flexors do, the elbow would extend if all of these muscles were fully engaged.

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A. To determine the maximum force that the elbow flexors can exert, we need to calculate the total cross-sectional area of the prime movers for elbow flexion, and then multiply it by the specific tension of the muscle:

The total cross-sectional area of elbow flexors = Biceps brachii + Brachialis + Brachioradialis

= 3.6 cm2 + 6.0 cm2 + 1.5 cm2

= 11.1 cm2

The maximum force that the elbow flexors can exert = Total cross-sectional area x Specific tension of muscle

= 11.1 cm2 x 30 N/cm2

= 333 N

Therefore, the maximum force that the elbow flexors can exert is 333 N.

B. To determine whether the elbow would flex or extend if all of these muscles were activated fully, we need to calculate the net torque generated by the muscles:

Net torque = (Force x Moment arm)flexors - (Force x Moment arm)triceps

Where force is the maximum force that the elbow flexors can exert (333 N), the moment arm of the elbow flexors is 4 cm, and the moment arm of the triceps is 2.5 cm.

Net torque = (333 N x 4 cm) - (333 N x 2.5 cm)

= 999 Ncm - 832.5 Ncm

= 166.5 Ncm

Since the net torque is positive (166.5 Ncm), the elbow would flex if all of these muscles were activated fully.

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Answer:

"element"= There are four basic sentence patterns based on sentence construction element

Answer:

1st one. Element

2nd one. Compound

Explanation:

Answer:

1a) Transverse wave.

1b) Ripples on the surface of water.

1c) See first attachment.

1d)  See below for explanation.

2a) Longitudinal wave.

2b) Sound waves.

2c) See second attachment.

2d)  See below for explanation.

Part 2) 54 m/s

Explanation:

a)  The wave in the picture is a transverse wave.

In transverse waves, the oscillations are at right angles to the direction of wave travel.

b)  A real world example of a transverse wave is ripples on the surface of water.

c)  See first attachment.

d)  The amplitude is the maximum displacement of a point of a wave from its resting position.  It is measured by calculating the difference in height between a crest and the resting position (mid-line).

a)  The wave in the picture is a longitudinal wave.

In longitudinal waves, the oscillations are parallel to the direction of wave travel.

b)  A real world example of a longitudinal wave is sound waves.

c)  See second attachment.

d)  The amplitude is the maximum displacement of a point of a wave from its resting position.  It is measured by calculating the distance between the particles in the areas where it is compressed.

Wave Speed

\(\large\boxed{v=f \lambda}\)

where:

Given values:

Substitute the given values into the formula and solve for speed:

\(\implies v=60.0 \times 0.90\)

\(\implies v=54\;\sf m/s\)

Therefore, the speed of the wave is 54 m/s.

Answer:

1. The three main acidic gases responsible for lowering the pH of rainwater are non-metal oxides produced by the burning of fossil fuels like coal, oil and natural gas. Sulfur dioxide is produced when fossil fuels containing sulfur impurities are burned.

2. A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power. Renewable energy sources help reduce acid rain because they produce much less pollution.

3. The pH scale is logarithmic, meaning that an increase or decrease of an integer value changes the concentration by a tenfold. For example, a pH of 3 is ten times more acidic than a pH of 4.

Answer:

friction

Explanation:

when things like hair and the balloon run they loose some electrons to the other this makes onne object positive and negative causing them to attract

Answer: vitamin d

Explanation: Calcium supplements cause few, if any, side effects. However, taking too much vitamin D in the form of supplements can be harmful.

Answer:1. Using the following formula, we can calculate the kinetic energy of a 1500 kg tow-mapping truck moving at a speed of 31.0 m/s: KE is equal to 0.5 * m * v2, where m is the object's mass and v is its speed.

By entering the data, we obtain the following equation: KE = 0.5 * 1500 kg * (31.0 m/sec) * 2 = 0.5 * 1500 kg * 961 m2/sec * 2 = 723,500 J

Therefore, the 1500 kg Tow-Mater Truck's kinetic energy at 31.0 m/sec is 723,500 J.

2. To determine the height of the cliff, we use the formula: PE = mgh, where m is the mass of the base jumper, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.

Given that the base jumper has 16,800 J of potential energy, we can rearrange the formula to find h: h = PE / (m * g) = 16,800 J / (68.0 kg * 9.8 m/s^2) = 20.6 m

So, the base jumper is 20.6 meters above the base of the cliff.

Explanation:

Answer:

1.  

energy : KE = units J

mass: m = 1500m unit

velocity: v = 31v unit m/s

Answer:

KE = 720750 J

2.

energy: KE = 16800 KE unit

mass:  m = 68.0m unit

= V

Answer:

v = 22.228757209048 m/s

Answer:

Sensory memory lasts a few hundred milliseconds. (milliseconds to seconds)

Explanation:

Approximately 3.31 x \(10^{15\) electrons strike the target per second.

To determine the number of electrons per second striking the target, we can use the equation:

I = n * q

where I is the current, n is the number of electrons per second, and q is the charge of each electron.

Given that the current is 0.530 mA (milliamperes) and 1 mA is equal to 1/1000 A (amperes), we can convert the current to amperes:

I = 0.530 mA * (1/1000 A/mA) = 0.000530 A

The charge of each electron, q, is approximately equal to 1.6 x \(10^{-19\) C (coulombs).

Now we can rearrange the equation to solve for n:

n = I / q

n = 0.000530 A / (1.6 x \(10^{-19\) C)

Calculating the value:

n ≈ 3.31 x \(10^{15\) electrons per second

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Answer:

a) first class lever

Answer:

D. The net electrical charge of the Earth.

Explanation:

All the other three choices affect the gravitational force. I remember from middle school.

The first part of the microscope that should first be used to adjust the focus when starting with the lowest power lens would be the coarse adjustment knob.

There are two knobs in a typical light microscope with which objects on slides can be brought into focus:

The 2 knobs are used to adjust the stage to either bring it up towards the objective lens or down away from them. The coarse adjustment knob, however, moves the stage a considerable distance with each turn. The fine adjustment knob, on the other hand, only moves the stage very little with each turn.

The lowest power lenses are often short. Hence, using the coarse adjustment knob is ideal in order to quickly bring objects on slides into focus.

The fine adjustment knob comes highly recommended at high objectives because high objectives lenses are usually long and using the coarse adjustment knob can lead to a breakage of the slide by the lens.

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Answer:

Explanation:

Pooh Shiesty, that's my dawg

But Pooh, you know I'm really shiesty

You told all them O.T. ni  ggas that you really slide

Tell the truth about your gang, they really dyin'

I got my own fire, don't need security in the club

All that woofin' on the net , I thought you was a thug

They ain't got nowhere to go, I sh0t up everywhere they was

Yeah, you know who took that - from you

Come get it back in blood

Come get it back in blood

Answer:

d

Explanation:

Answer:25 seconds

Explanation: Power equals work/time or force*displacement/time.

So, in this case the force is 20N and the displacement is 500m so the work is 10,000N.

We know the power equals 0.4KW (which equals 400W). Plugging these values into the equation:

400=10,000/T

T=25s

Answer:

11900 meters

Explanation:

Use the Potential energy = mgh formula, substituting these in to get 11.1x10^6 = 95 x 9.81 x h.

Rearrange to make h the subject and the answer given is 11900 (3sig.fig.)

The maximum height to which he can climb will be 1.168 x 10⁴ meters.

The potential energy of a body is the energy of the body due it position. The potential energy always exist for two bodies which are in mutual interaction with each other for example by a force. For body a on earth, the potential energy of the body - earth system is -

E[P] = mgh

Given is a mountain climber that has a mass of 95 kg.

We can write -

Mass of climber = [M] = 95 kg

Energy gained by eating the chocolate = [E] = 11.1 MJ = 1.11 x 10⁷ joules

Assume that the height achieved achieve by the climber is [h] meters

Therefore, the potential energy gained at that height will be equal to 11 MJ

Therefore -

mgh = 1.11 x 10⁷

95 x 10 x h = 1.11 x 10⁷

95 x 10 x h = 1110 x 10⁴

h = (1110 x 10⁴)/950

h = 1.168 x 10⁴ meters

Therefore, the maximum height to which he can climb will be 1.168 x 10⁴ meters.

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Answer:

a = 16 m/s²

Explanation:

Given that,

Initial speed of a roler coaster, v₁ = 6 m/s

Final speed of a roller coaster, v₂ = 70 m/s

Time, t = 4s

We know that, acceleration of an object is equal to the rate of change of velocity. Let the acceleration be a. Its formula is given by :

\(a=\dfrac{v_2-v_1}{t}\)

or

\(v_2=v_1+at\)

The correct option is (1). Its value is equal to :

\(a=\dfrac{70-6}{4}\\\\a=16\ m/s^2\)

Its value is equal to 16 m/s².

A magnetic field is created between these two charged parallel plates. The field indicates a direction from the positive plate to the negative plate.

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Answer:-

The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other; and negatively charged objects and neutral objects attract each other.

Explanation:

Hope it is helpful...

Newton's second law allows to find the result for the friction coefficient of the street is:

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.

           ∑ F = m a

Where bold indicates vectors, m is to mass and acceleration.

In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight.

        Sin θ = \(\frac{W_x}{W}\)  

        cos θ = \(\frac{W_y}{W}\) / W

        Wₓ = W sin θ

         \(W_y\)  = W cos θ

We write Newton's second law for each axis.

y-axis

         N- \(W_y\)  = 0

         N = mg cos θ

x-axis

        Wₓ - fr = ma

Since they indicate that the body goes down at a constant speed, the acceleration is zero.

         W sin θ = fr

The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.

         fr = μ N

we substitute.

          fr = μ mg cos θ

         mg sin θ = μ cos θ  

        μ = tan θ

Let's calculate.

         μ = tan 38.0

         μ = 0.78

In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:

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stone's position from the ground after:

a) .5 seconds is 56.275 m.

b) 1.0 seconds is  50.1 m.

c) 1.5 seconds is 45.475 m.

d) 2.0 seconds is 30.4 m.

Given parameters:

Height of the tower; h₀ = 60 m.

Initial velocity, u = 5 m/s.

We know that,

acceleration due to gravity, g = 9.8 m/s².

applied formula is :

h = h₀ - ( ut + 1/2gt²)

a)So, stone's position from the ground after:

.5 seconds:

h = h₀ - ( ut + 1/2gt²)

= 60m - ( 5*0.5 + 1/2*9.8*0.5²) m

= 56.275 m.

b)So, stone's position from the ground after:

1.0 seconds:

h = h₀ - ( ut + 1/2gt²)

= 60m - ( 5*1.0 + 1/2*9.8*1.0²) m

= 50.1 m.

c)So, stone's position from the ground after:

1.5 seconds:

h = h₀ - ( ut + 1/2gt²)

= 60m - ( 5*1.5 + 1/2*9.8*1.5²) m

= 45.475 m.

d)So, stone's position from the ground after:

2.0 seconds:

h = h₀ - ( ut + 1/2gt²)

= 60m - ( 5*2.0 + 1/2*9.8*2.0²) m

= 30.4 m.

Hence, different position of the stone in different time is calculated.

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The velocity of the ball before and after collision as V₁ = 41m/s and V₂ = 37m/s respectively, and the mass of the ball as m.The velocity of the bat = 37m/s (opposite direction to the ball). Therefore, the relative velocity of the ball with respect to the bat, V = V₁ - V₂= 41 - 37 = 4 m/s.The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation to the relative velocity of approach.e = V₂’ - V₁’ / V₁ - V₂, where V₂’ and V₁’ are the velocities of the ball and bat after collision.e = V₂’ / V₁ = (77 - 0.11m) / 37, V₂’ = (77 - 0.11m)  37 / 37 = 77 - 0.11m.

The velocity of the ball is u(m) = 77 - 6.87/m + 0.11m/s.Understanding:

Calculation:

Interpretation:

A ball with higher velocity can travel farther when hit with a bat. Therefore, it is always an advantage to use a heavier ball.u’(0.9) = 8.81 m⁻²/s, u’(1.5) = 5.60 m⁻²/sRate of increase of speed is u’(m).Answer:u’(0.9) ≈ 8.81 m⁻²/s, u’(1.5) ≈ 5.60 m⁻²/s.The rate at which this speed is increasing is u’(m).

Velocity is a foreign term that means speed. Speed ​​is the locking of an object every single unit of time. Acceleration or acceleration is the change in velocity in a certain unit of time. The acceleration of an object is caused by a force acting on the object, as explained in Newton's second law. The SI unit for acceleration is meters per second squared (m s−2). What is the difference between speed and pace? Velocity or speed is the quotient between the distance traveled and the time interval. Velocity or speed is a scalar quantity. Speed ​​​​or speed is the result of separation with an interval. Speed ​​or velocity is a vector quantity.

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Answer:

The equivalent series resistance of a capacitor is the internal resistance that appears in series with the capacitance of the device. Almost all capacitors exhibit this property at varying degrees depending on the construction, dielectric materials, quality, and reliability of the capacitor.

Explanation:

Hope this helps