The circuit in Figure 32 includes a battery with a finite

internal resistance, . (a) Find the current flowing

through the and the resistors. (b) How much

current flows through the battery? (c) What is the potential

difference between the terminals of the battery?

The Circuit In Figure 32 Includes A Battery With A Finite Internal Resistance, . (a) Find The Current

Answers

Answer 1

The potential difference between the terminals of the battery is 4.8 V.

Internal resistance of the circuit, r = 50 Ω

The effective resistance of 4.5Ω and 1Ω and r,

Reff = 0.5 + 4.5 + 1

Reff = 6Ω

The effective resistance of 7.1Ω and 5.8Ω,

Reff = 7.1 + 5.8 = 12.9Ω

This 12.9Ω is parallel to the 3.2Ω. So,

Reff = 12.9 x 3.2/(12.9 + 3.2)

Reff = 2.56Ω

The effective resistance of 2.56Ω and 6Ω is the total resistance of the circuit.

R = 2.56 + 6 = 8.56Ω

Therefore, total current,

I = V/R = 12/6.56

I = 1.4 A

Potential across the left side, V' = 1.4 x 6

V' = 8.4 V

Potential across the right side, V'' = 12 - 8.4

V'' = 3.6 V

Therefore the potential difference = 8.4 - 3.6 = 4.8 V.

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Related Questions

Cousin Throckmorton is playing with the clothesline. One end of the clothesline is attached to a vertical post. Throcky holds the other end loosely in his hand, so that the speed of waves on the clothesline is a relatively slow 0.700 m/s . He finds several frequencies at which he can oscillate his end of the clothesline so that a light clothespin 40.0 cm from the post doesn't move. What are these frequencies?

Answers

Answer:

The  frequencies are  \(f_n = n (0.875 )\)

Explanation:

From the question we are told that

   The speed of the wave is  \(v = 0.700 \ m/s\)

   The  length of vibrating  clothesline is  \(L = 40.0 \ cm = 0.4 \ m\)

Generally the fundamental frequency is  mathematically represented as

        \(f = \frac{v}{2 L }\)

=>     \(f = \frac{ 0.700 }{2 * 0.4 }\)

=>     \(f = 0.875 \ Hz\)

Now  this other frequencies of vibration experience by the clotheslines are know as harmonics and they are obtained by integer multiple of  the fundamental frequency

So  

   The  frequencies are mathematically represented as

       \(f_n = n * f\)

=>     \(f_n = n (0.875 )\)

Where  n  =  1, 2, 3 ....

       

Hunter designs two flags for his adventure club. What is the length of the base, x, of the larger flag? enter your answer, as a decimal, in the box. X = ft.

Answers

The required length of the base of larger flag when other sides are specified is calculated to be 6.25 ft.

The given two triangles are the flags of two different sizes. The lengths of various sides are specified.

The length of the base of the larger flag is to be found out.

The given two angles in small flag are equal to the corresponding angles in the large flag.

Two flags are the similar triangles as they look proportionate.

Both triangles' edges are proportional to one another.

So, from the figure, 4/5 = 5/x

x = 25/4 = 6.25 ft

Thus, the required x on the base of bigger flag is 6.25 ft

The given question is incomplete. The figure is missing. It is attached in the figure below.

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Hunter designs two flags for his adventure club. What is the length of the base, x, of the larger flag?

Which quantity describes the gravitational force between two objects?(1 point)
Responses

A the sum of the masses of the two objects divided by the distance between them
B the product of the masses of the two objects divided by the distance between them
C the product of the masses of the two objects divided by the square of the distance between them
D the sum of the masses of the two objects divided by the square of the distance between them

Answers

The quantity that describes the gravitational force between two objects is as follows: the product of the masses of the two objects divided by the square of the distance between them (option C).

What is gravitational force?

Gravitational force is a very long-range, but relatively weak fundamental force of attraction that acts between all particles that have mass; believed to be mediated by gravitons.

It is called the gravitational force attraction because it always tries to pull masses together, it never pushes them apart.

The gravitational force of an object can be calculated using the following formula:

F = Gm1m2/r²

Where;

F = gravitational forceG = gravitational constantm1 and m2 = masses of objectr = distance between objects

Therefore, the product of the masses divided by the square of the distance is how gravitational force is calculated.

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7. Two capacitors, 5.8 µF and 2.1 µF, are connected in parallel. A 3 V DC voltage is applied across the capacitors. What would be the expected accumilative charge stored in the capacitors

Answers

Answe thanks for the freee points UwU

Explanation:

A circle loop of radius 2 m is positioned in a uniform magnetic field of magnitude 1.5 N/C so that the plane of the loop makes an angle of 65° with the magnetic field. Find the flux passing through the circle loop.

Answers

The flux through the circle loop of wire is determined as 7.96 N/C.m².

What is the flux passing through the circle loop?

The flux through the circle loop of wire is calculated by applying the following formula.

Ф = EA cosθ

where;

B is the magnitude of the electric  fieldA is the area of the circular loopθ is the direction of the loop

The area of the wire is calculated as follows;

A = πr²

A = π (2 m)²

A = 12.57 m²

The flux through the circle loop of wire is calculated as;

Ф = EA cosθ

Ф = 1.5 x 12.57 x cos (65)

Ф = 7.96 N/C.m²

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How does light (radiant) energy work within a complete system?

Answers

Answer:

i hop this help you :)

Explanation:

How Does Radiant Energy Work? Radiant energy moves from one place to another in the form of electromagnetic waves or electromagnetic radiation. At its most elementary level, electromagnetic waves are made up of photons, which have no mass and move at the speed of light.

Answer:

Explanation:Radiant energy is used for radiant heating. It can be generated electrically by infrared lamps, or can be absorbed from sunlight and used to heat water. The heat energy is emitted from a warm element (floor, wall, overhead panel)

The skin temperature of a person is 34o C and his body surface area is about 1.8 m2 . He is standing bare skin in a room where the air temperature is 24o C and the walls are 17o C. He is metabolizing food at a rate of 155 W, the emissivity of his skin is 0.97 and there is a 5mm thick dead layer (immobile) air next to his skin acting as an insulation. a./ at what rate his body is losing heat by conduction

Answers

Answer:

the rate at which his body is losing heat by conduction is 93.6 J/s

Explanation:

Given that;

surface area A = 1.8 m²

Skin temperature of the person Tp = 32°C = ( 34 + 273.15 ) = 307.15 K

Temperature of Air \(T_{air}\) = 24°C = ( 24 + 273.15 ) = 297.15 K

Temperature of wall \(T_{wall}\) = 17°C = ( 17 + 273.15 ) = 290.15 K

Length ( thick dead layer = 5 mm = 0.005 m

Skin emissivity = 0.97

Rate of metabolism = 155 W

rate his body is losing heat by conduction = ?

first we determine the difference in temperature between the skin and air

so

ΔT = 307.15 K - 297.15 K = 10 K

we know that; coefficient of thermal heat conductivity of air k = 0.026 W/mK

so

rate of heat loss by conduction Q/ΔT will be;

Q/ΔT = (KA/L)ΔT

so we substitute

= ( 0.026 × 1.8/ 0.005 )10

= 9.36 × 10

= 93.6 J/s

Therefore, the rate at which his body is losing heat by conduction is 93.6 J/s

please provide an explanation

please provide an explanation

Answers

The final velocity of the toy car after the collision with the wall is 2.46 m/s.

What is the final velocity of the toy car after the collision with the wall?

The final velocity of the toy car after the collision with the wall is determined from the formula of impulse and momentum.

Impulse = change in momentum

Also, impulse = force * time

change in momentum = mv - mu

where:

m is the mass = 0.25 kg

v is the final velocity = ?

u is the initial velocity = 0.86 m/s

From the graph, the force is 40 N and the time of impact is 0.01 seconds

40 * 0.01 = 0.25v - 0.25 * 0.86

0.25v = 0.615

v = 2.46 m/s

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What is the value of the magnitude of the difference of vectors A and B, |A - B|?

Answers

Answer:

Let, θ be the angle between vector a and vector b.

So, the angle between vector a and vector (-b) must be (180° - θ).

Magnitude of the difference of vectors a and b

= |a - b|

= Magnitude of the resultant of the vector sum of the vectors a and (-b)

= |{√|a|^2 + |b|^2 + 2 * |a| * |b| * cos (180° - θ)}|

= |{√|a|^2 + |b|^2 - 2 * |a| * |b| * (cos θ)}|.

Explanation:

You throw a ball upward with an initial speed of 3.0 m/s from an initial height of 1.5 m. After you throw the ball, its acceleration is 9.81 m/s downward. Taking upward to be the positive direction, write the position-time equation for the ball's motion​

Answers

Answer: An object undergoing a constant acceleration can have its motions be described by the kinematic equations. These equations relate the position of the particle, its velocity, acceleration, and time.

Explanation:

Answer:

vf^2=vo^2+2ay(y1-y0)

Explanation:

A carousel is (more or less) a disk of mass, 15,000 kg, with a radius of 6.14. What torque must be applied to create an angular acceleration of 0.0500 rad/s^2?round to 3 significant figures

(Plssss help me im suffering from severe brainrot)

A carousel is (more or less) a disk of mass, 15,000 kg, with a radius of 6.14. What torque must be applied

Answers

To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Find weather X^N plus Y^N is divisible by X - Y (y not equal to 0) or not

Answers

The expression \(X^{N} + Y^{N}\)is not divisible by X - Y (where Y is not equal to 0).

To determine whether the expression \(X^{N} + Y^{N}\) is divisible by X - Y (where Y is not equal to 0), we can use the factor theorem and the property of binomial expansion.

The factor theorem states that if a polynomial P(x) is divisible by (x - a), then P(a) equals zero. In our case, if \(X^{N} + Y^{N}\) is divisible by (X - Y), then when we substitute X = Y into the expression, the result should be zero.

Let's substitute X = Y into the expression:

\(Y^{N} + Y^{N}\)

Since \(Y^{N}\) is equivalent to \(Y^{N}\) , the expression becomes:

2(\(Y^{N}\))

We can see that the expression 2(\(Y^{N}\)) is not equal to zero unless Y is equal to zero. Therefore, if Y is not equal to zero, \(X^{N} + Y^{N}\) is not divisible by X - Y.

In summary, unless Y is equal to zero, the expression \(X^{N} + Y^{N}\) is not divisible by X - Y according to the factor theorem and the given condition.

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Describe how heat transfer occurs when you

place your hand in a sink full of hot water.

Answers

Answer:

If one places ones's hands into a sink full of hot water, heat is transferred from the hot water to the hands. Heat only flows when there is a temperature gradient, i.e when there is a difference in temperature between a hot and a cold body. Heat is always transferred from a hot body to a cold body and never the reverse in a normal system.

At the boundary of the hand and water, heat transfer is by conduction between the hot water molecules and the molecules of the hands. This heat is then further transferred to the internal body organs and body fluid through either convection or conduction. This heat transfer is maintained until both the water and the hands are at the same temperature, assuming the owner is able to withstand the heat.

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Please help I need help with these 2 questions

Please help I need help with these 2 questions

Answers

The answers 2x and b
Lava then rocks are releasing energy, I’m sorry if wrong, have a nice day!

2. Two equipotential lines are separated by a distance of 2.17 cm. If the potential values of the lines are 5.9 volts and 8.6 volts, what would the strength of the electric field between the lines be

Answers

What’s the answer? For this question?

Frank pushes with a force of 620 N on a filing cabinet with a mass of 60 g. The cabinet doesn't move.
What can be inferred?
A. There are no other forces acting on the filing cabinet.
B. The static friction force of the floor and cabinet is greater than 620 N.
C. The net force of the cabinet is greater than 620 N.
D. The friction force of the floor and cabinet is less than 620 N.
ОА
OB
Ос

Answers

Answer:

The shift from bound volumes to filing systems is a milestone in the history of classification; the contemporaneous shift to vertical filing cabinets is a ...

Explanation:

PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons

Answers

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

Why the electron number cannot be used instead?

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.​

Answers

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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When putting the ball on the tee you want half of the golf ball to be above the club be below the club be in front of the club be behind the club​

will put brainlest

Answers

5)-5 that would be 100% correct

A golf ball is a unique ball made specifically for the game of golf.

What is Gulf ball?

A golf ball must adhere to specific velocity, distance, and symmetry requirements as well as have a mass of no more than 1.620 oz (45.9 g), a diameter of no less than 1.680 inches (42.7 mm), and no more than 1.620 oz (45.9 g) in total.  

Similar to golf clubs, golf balls must pass testing and approval by The R&A and the United States Golf Association before they can be used in competitions. 

Early in the 20th century, it was discovered that dotting the ball gave the player even more control over the trajectory, flight, and spin of the ball.

Therefore, A golf ball is a unique ball made specifically for the game of golf.

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The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds 
3)Is there any time interval in which no force acts on object.Justify

The velocity time graph of an object mass 50 g is shown in figure study graph and answer1)calculate force

Answers

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Give examples of stochastic and non-stochastic effects of radiation and explain why this information is essential in our field of study

Answers

Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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what is the Vector product of A=2.00i+3.00j+1.00k and B= 1.00i -3.00j -2,00k

Answers

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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Final answer:

The vector product of A and B is -3i - 5j - 9k.

Explanation:

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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A uniform, 4.5 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. A 1.3 kg raven flying horizontally at 4.5 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction. (a) What is the angular speed of the gate just after it is struck by the unfortunate raven? (b) During the collision, why is the angular momentum conserved but not the linear momentum?

Answers

Answer:

a) Angular speed(w) = 2.02rad/sec

b) 73J ( It is Inelastic Collision)

Explanation:

Given:

Mass=45kg

Length on each side = 1.5m side which is hangs vertically from a frictionless pivot at the center of its upper edge.

We need to calculate

(a) What is the angular speed and

(b) To know why the angular momentum conserved but not the linear momentum

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

A uniform, 4.5 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless

pls helpone phyics question lots of points!

pls helpone phyics question lots of points!

Answers

Answer:

PE = 0.73J

Explanation:

Remember that in conservative spring systems,

Total energy = potential + kinetic energy.

On the y-axis lies the kinetic energy and the question asks for the potential energy.

PE + KE must always equal the same result.

In this case, KE + PE = 1

So rearranging the equation,

PE = 1 - KE

KE = 0.27 (as we can see from the graph)

Therefore,

PE = 1 - 0.27 = 0.73J

Bonus tip: The graphs of potential and kinetic energy will look the exact opposite in this case. When the KE graph is at 0J, the PE graph is at 1J and vice versa. And they always cross over at 0.5J

What height would a 4 kg book need to be to have a potential energy of
235.2 J on earth?*
need help!!

Answers

Answer:

5.99 m  = 6 m

Explanation:

PE = m*g*h

235.2 J = (4 kg)(9.81 m/s^2)(h)

h = (235.2 J)/(9.81*4)

h = 5.99 m

h = 6 m

Define "increased productivity" in terms of the number of tasks and the amount of time.

Answers

Answer:

The greater the amount of output for a given unit of input, the higher the overall productivity. Businesses generally aim to improve productivity over time to maintain competitiveness and increase the business's profitability. Individuals are familiar with the idea of productivity in their own lives.

7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.​

Answers

The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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A 3250 kg car slows down from 20.0 m/s to a stop in 5.33 s. How much force would be required to stop the car?

Answers

The force required to stop the car of mass 3250 kg is -12195.12 N.

What is force?

Force is the product of mass and acceleration.

To calculate the force required to stop the car, we use the formula below

Formula:

F = m(v-u)/t.....................Equation 1

Where:

F = Force required to stop the carm = Mass of the carv = Final speedu = Initial speedt = Time

From the question,

Given:

m = 3250 kgv = 0 m/su = 20 m/st = 5.33 s

Substitute these values into equation 1

F = 3250(0-20)/5.33F = -12195.12 N

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A 80 kg
bicyclist is coasting down a long hill that has a 5.0 ∘
slope. His cross-section area is 0.35 m2
, his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is 0.02, and the air temperature is 20∘C
.

Answers

the Speed reached by the bicyclist is given by, v = 26 m/s

What are the types of friction?

There are mainly four types of friction: static friction, sliding friction, rolling friction, and fluid friction. Friction and normal force are directly proportional to the contacting surfaces, and it doesn't depend on the hardness of the contacting surface.

Given that,

Gravitational acceleration = 9.81 m/s²

Mass of bicyclist = 80 kg

Slope(θ) = 5°

Cross-sectional area of bicyclist = 0.35 m²

μ = coefficient of rolling friction = 0.02

t = air temperature = 20 °C

Let ρ be the density of air at 20oC = 1.2041 kg/m3

ρ = 1.2041 kg/m3

We have the balancing equation:

F₁ = F₂ + F₃

where,

F₁ = component of the weight of the bicyclist down the plane,

F₂ = frictional force up the plane, and

F₃ = air drag force up the plane.

Thus, F₃ = F₁ - F₂

sinθ = sin(5°) = 0.087

cosθ = cos(5°) = 0.996

Now we will calculate the forces,

F₁ = m g sinθ = 80 kg x 9.81 m/s2 x 0.087 = 68.227 N

F₁ = 68.227 N

F₂ = μ m g cosθ = 0.02 x 80 kg x 9.81 m/s2 x 0.996 = 15.63 N

F₂ = 15.63 N

Put the values of F1 and F2 in eqn (1) and we get:

F₃ = F1 - F2

F₃ = 68.227 - 15.63

F₃ = 52.597 N

Let v be the speed reached by a bicyclist,

From the general formula of velocity:

V = ((2 xF₃ / (ρ x CD x A))1/2

v = ((2 x F₃ / (ρ x CD x A))1/2

v = ((2 x 120.78 N / (1.2041 kg/m3 x 0.85 x 0.35))1/2 = 25.97 m/s

v = 26 m/s

Therefore, the Speed reached by the bicyclist is given by, v = 26 m/s

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