The Chumash cosmology is divided into different worlds. How many are there? ______ a. 3 b. 7 c. 2 d. 5

Answer:

A higher amplitude means a higher frequency which means a higher energy the higher the wavelength means lower energy because its not as precise and cant reach levels small wavelengths can the sound waves that usually damage our ears are small wavelengths because of the energy applied to them

Explanation:

Answer:

Explanation:

On return to Earth, gravity once again “pulls” the blood and fluids into the abdomen and legs. The loss of blood volume, combined with atrophy of the heart and blood vessels that can occur in space, reduces the ability to regulate a drop in blood pressure that happens when we stand on Earth.

Answer:

We just know that the metal is called Vibranium.

to place something is the table   we need to know its atomic number and its mass. so if we can get that we can ans it.

Explanation:

Answer:

ummmmmwm whattt

Explanation:

wuhsnnsnsnsnms

Answer:

medicines

band-aids

aqua liquid

paracetamol

Explanation:

Extra items:

alcohol

cottons

bitadine

cotton buds

mask

\(H_2\) (hydrogen) is not a compound because it's not made of more than one element. Yes we have more than one component, but both components are of the same element H.

Something like \(CO_2\) is a compound because it's made of carbon and oxygen (specifically 1 carbon and 2 oxygen), so we have at least two different elements here.

Answer:

doppler

Explanation:

Answer:

2k25%*degrees

Explanation:

I think so

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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The horizontal force being applied by the partner is 692.8 N.

The horizontal force being applied by the partner is determined by applying Newton's second law of motion.

Mathematically, the Newton's second law of motion is given as;

F = ma

where;

The total weight of the trapeze artist can be resolved into horizontal component and vertical component.

The formula for the horizontal component of the weight of the trapeze artist is given as;

Fx = F cosθ

Wx = W cosθ

where;

Wx = ( 8 x 10² N ) x cos (30)

Wx = 692.8 N

Thus, the horizontal force applied by the partner is a function of the horizontal component of the weight of the trapeze artist.

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It will take an additional 7.33 minutes for the cake to cool from 200 degrees F to 90 degrees F after the initial 10 minutes of cooling.

To calculate how much longer it will take for the cake to cool to 90 degrees F, we need to first determine the rate at which the cake is cooling. We can do this by calculating the temperature difference between the cake and the room and dividing it by the time it takes for that temperature difference to occur.
In this case, the temperature difference between the cake and the room is 280 degrees F (350-70=280) when the cake is removed from the oven. After 10 minutes, the temperature difference is 130 degrees F (200-70=130). Therefore, the cake is cooling at a rate of 15 degrees F per minute (280-130=150 degrees F in 10 minutes; 150/10=15).
To determine how much longer it will take for the cake to cool to 90 degrees F, we need to calculate the time it takes for the temperature to drop from 200 degrees F to 90 degrees F. This is a temperature difference of 110 degrees F (200-90=110), so it will take approximately 7.33 minutes (110/15=7.33) for the cake to cool from 200 degrees F to 90 degrees F.

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The minimum gap between the automobiles is 16.9 feet, according to the supplied statement, in order to prevent a collision.

The size or extent of the displacement between two points is referred to as distance. Keep in mind that perhaps the difference between two and indeed the distance travelled between them are not the same. The length of the entire journey taken to go from one point to another is the distance travelled.

For B;

\(\begin{aligned}(\rightarrow) \quad v & =v_0+a_c t \\v_B & =60-12 t \\(\rightrightarrows) & s=s_0+v_0 t+\frac{1}{2} a_c t^2 \\s_B & =d+60 t-\frac{1}{2}(12) t^2\end{aligned}\)

For A;

\(\begin{aligned}& (\stackrel{\rightarrow}{\rightarrow}) \quad v=v_0+a_c t \\& v_A=60-15(t-0.75), \quad[t > 0.75] \\& (\text { 土 }) \quad s=s_0+v_0 t+\frac{1}{2} a_c t^2 \\& \qquad s_A=60(0.75)+60(t-0.75)-\frac{1}{2}(15)(t-0.75)^2, \quad[t > 0.74]\end{aligned}\)

Require \(V_{A} = V_{B}\) the moment of closest approach

60 - 12t = 60 - 15 ( t- 0.75)

t = 3.75 s

The worst case scenario without contact is when \(S_{A} = S_{B}\)

At t = 3.75 s, from eq. (1) and (2),

60(0.75) + 60(3.75 - 0.75) - 7.5(3.75 - 0.75)² = d + 60(3.75) = 6(3.75)²

157.5 = d + 140.62

d = 16.9 ft

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Answer:

4.8 m/s

Explanation:

For tennis ball "A", we are told that;

Initial velocity; u = 0 m/s

Distance; h = 10 m

Acceleration; a = 5 m/s²

Thus, using Newton's equation of motion, we can find time(t).

h = ut + ½at²

10 = 0 + ½(5)t²

10 = ½(5t²)

t² = 2 × 10/5

t² = 4

t = √4

t = 2 seconds

Now, this time would be the same for ball B since we are told that they reach the bottom at the same time.

Now, since ball B is thrown upwards, it means it is thrown against gravity. Thus;

h = -ut + ½gt²

10 = -2u + ½(9.8)(2²)

Where u is initial velocity of Ball B.

Thus;

10 = -2u + 19.6

2u = 19.6 - 10

2u = 9.6

u = 9.6/2

u = 4.8 m/s

Answer:

B

Explanation:

Answer:

B. scientific laws have been proven without exception under certain stated conditions.

Explanation:

Answer:

vz vc

Explanation:

v b

Explanation:

Hope it helps my lady.......

ANSWER

EXPLANATION

Parameters given:

Speed of electron, v = 4.10 * 10^3 m/s

Magnetic field, B = 1.45 T

Magnetic force, F = 1.40 * 10^(-16) N

To find the angle that the velocity of the electron makes with the magnetic field, apply the formula for magnetic force:

where θ = angle

q = electric charge = 1.6 * 10^(-19) C

Make θ the subject of the formula:

Therefore, the angle that the velocity makes is:

To find the second angle, subtract the angle from 180 degrees:

The angles are:

Based on the given data, (a)  the acceleration of the first block is 1.45 m/s² ; (b) the tension in the cord is 5.15 N

To calculate the acceleration of the first block, we know that the tension in the string is same throughout.

Let, T be the tension in the string and a be the acceleration of the system.

Then, 3.55a = T... (i) and, 2.78g - T = 2.78a... (ii)

Multiplying equation (i) by 2.78 and adding to equation (ii),

2.78g - 2.78T + 3.55a * 2.78 = 2.78a + 2.78T5.32a = 2.78g... (iii)

=> a = 2.78g/5.32 = 1.45 m/s²

Therefore, the acceleration of the first block is 1.45 m/s².

To calculate the tension in the cord, putting a = 1.45 in equation (i),

T = 3.55a= 3.55 * 1.45= 5.15 N

Therefore, the tension in the cord is 5.15 N.

Thus, the correct answers are : (a) 1.45 m/s² ; (b) 5.15 N.

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The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Distance from spot shines =  12 m away

Height of man,h=2 m tall

Speed of man +1.6 m/s,

Distance from the building = 4 m

Let the height of shadow= y,

CD=x

Height of man=2 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

As the triangle ABD and ECD are similar. The property of the similarity is found as;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)

Differentiate the above question with respect to x;

\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)

From the given conditions the man is 4 m from  the building the value of the remaining distance x is;

x=12-4

x=8 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

On putting all the values we get;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)

The speed of man when the  length of his shadow on the building decreases when he is 4 m from the building;

\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)

Hence the value of the speed for the given conditions willl be 0.6 m/sec.

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We know that substances expand with high temperatures and contract with low temperatures, therefore, the bridge will contract and the answer is b.

Answer:

hey

Explanation:

hey

Answer:

The root beer exerts a force on all sides of the ice cream. These forces are all equal and cancel each other out. Gravity pushes downward on the ice cream. ... The ice cream floats because the buoyant force is greater than the weight of the ice cream.

Explanation:

When the carbon reacts with bromine, electrons are shared between the bromine atoms and the carbon atoms to form a covalent compound. Therefore, option (C) is correct.

In a covalent compound, the formation of a covalent bond involves the mutual sharing of electrons between the two atoms that can hold all biomolecules together.

A covalent bond can be described as a chemical bond formed by sharing of electrons to form electron pairs between atoms. The stable attractive and repulsive forces between atoms are known as covalent bonding.[1] The sharing of electrons permits each atom to get the equivalent of a full valence shell and stable electronic configuration.

The carbon reacts with bromine to form the compound carbon tetrabromide CBr₄.

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Answer:

k₁ = 2πf₁/v

k₂ = 2πf₂/v

Explanation:

Since the de Broglie relation λ=h/p (1 ) and momentum, p =kℏ (2)

From (1) p = h/λ = kℏ

So,  h/λ = kℏ

Hence, k = h/ℏλ  since ℏ = h/2π and wavelength, λ = v/f, substituting these two into k, we have

k = h/[(h/2π)(v/f)]

k = 2πf/v where k = wave number, f = frequency of wave and v = velocity of wave.

Now, for the first wave number k₁, k₁ = 2πf₁/v

for the second wave number k₂, k₂ = 2πf₂/v

Answerpov:

Explanation:

Answer:

A) the initial point all energy is elastic potential and the final point all energy is kinetic

B) a bar graph the two bars have the same height and the sum of their height is the initial energy

C) two bars, one for the  kinetic energy and the other for the gravitational potential energy.

Explanation:

A) For this exercise we must use the energy conservation relations

starting point. When the spring is compressed

        Em₀ = K_e = ½ k x²

end point, at the bottom of the loop

        Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

         ½ k x² = ½ m v²

         v = \(\sqrt{ \frac{k}{m} }\)   x

In a bar graph the initial point all energy is elastic potential and the final point all energy is kinetic

B) intermediate point in a quarter of the radius

In this case we use the lower part of the loop as the starting point and the quarter part of the bow as the end point.

        Em₀ = K

         Em_f = K + U = ½ m v² + m g R

in a bar graph the two bars have the same height and the sum of their height is the initial energy

C) End point highest part of the loop

   starting point, bottom of loop

         Emo = K = ½ m v₀²

from part A of the exercise we saw that it is equal to the elastic energy of the spring

    final point. Highest part of the loop

         Emf = K + U

         Em_f = ½ m \(v_{f}^2\) + mg (2R)

where R is the radius of the loop

         Em₀ = Em_f

        1/2 m v₀² = 1/2 m v_{f}^2+ mg 2R

        v₀² = v_f^2 + 4gR

In a bar graph there are two bars, one for the  kinetic energy and the other for the gravitational potential energy. The sum of the heights of these bars is the initial energy, so the energy is transformed but not created or destroyed in the process.

Answer:.05 kg*m over s

Explanation:did the work

The angular velocity of a bicycle with initial angular velocity of 1.5 rad/s and  angular acceleration of 0.2 rad/s² can be expressed as ω(t) = 1.5 + 0.2 t

Angular velocity tells us how fast an object rotates about an axis. The formula for the angular velocity at time t, with a constant angular acceleration, is:

ω(t) = ω(0) + α . t

Where:

ω(0) = initial angular velocity

α = angular acceleration

t = t period

Parameters given in the problem:

ω(0) = 1.50 rad/s

α = 0.200 rad/s²

Plug these parameters into the formula:

ω(t) = 1.5 + 0.2 t

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Explanation:

For most temperature scales, the boiling point of water and the freezing point is used to calibrate it.

Three known temperature scales;

                               Kelvin scale              Celcius scale          Fahrenheit scale

Freezing point             273K                            0°C                        32°F

Melting point                373K                          100°C                     212°F