the change in entropy for the universe is equal to:select the correct answer below:the sum of the change in entropy for the system and the change in entropy for the surroundingsthe change in entropy for the surroundings subtracted from the change in entropy for the systemthe change in entropy for the system subtracted from the change in entropy for the surroundingsnone of the above

The velocity of the airplane is approximately 69.84 m/s.

To find the velocity of the airplane flying at a standard sea level with a density of 1.23 kg/m³, static pressure of 1.01 x  \(10^{5}\) N/m², and a pitot-static tube reading of 1.04 x  \(10^{5}\) N/m², we can use Bernoulli's equation, which is applicable for steady, incompressible, and irrotational flow.

The Bernoulli's equation is given by: P₁ + 0.5ρV₁² + ρgh = P₂ + 0.5ρV₂² + ρgh₂ Since we're considering only horizontal flight, the potential energy terms (ρgh) can be canceled out. Additionally, since the pitot-static tube measures the total pressure (dynamic pressure + static pressure), P₂ is the total pressure (1.04 x  \(10^{5}\) N/m²), and P₁ is the static pressure (1.01 x 10^5 N/m²).

The density ρ is given as 1.23 kg/m³. Now, rearrange the equation to solve for V₁ (the velocity of the airplane): V₁² = 2(P₂ - P₁) / ρ Substitute the given values: V₁² = 2(1.04 x \(10^{5}\) N/m² - 1.01 x  \(10^{5}\) N/m²) / 1.23 kg/m³ Calculate the result: V₁² = 2(3 x 10 N/m²) / 1.23 kg/m³ V₁² ≈ 4878.05 m²/s² Now, take the square root to find the velocity: V₁ = √4878.05 m²/s² ≈ 69.84 m/s

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Answer:

Explanation:

actually , the acceleration due to gravity depends on the distance from it's center of the earth.

when the distance from the earth increases , the acceleration due to gravity decreases as a result . The value of gravity in space is zero.

The main difference between metaphysical claims and pseudoscience lies in their basis and methodology. Metaphysical claims typically pertain to philosophical or spiritual matters beyond the scope of empirical observation and scientific investigation.

Pseudoscience, on the other hand, refers to claims or practices that are presented as scientific but lack scientific rigor, empirical evidence, and adherence to the scientific method. Pseudoscientific claims often use scientific-sounding language or mimic scientific practices, but they lack the essential elements of peer-reviewed research, objective evidence, and reproducibility. Pseudoscience may include unsupported theories, unfounded claims, or explanations that go against established scientific knowledge. While both metaphysical claims and pseudoscience may involve ideas that are not currently or easily testable through scientific means, the distinction lies in the methodology and approach.

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Answer:

B.

Explanation:

Intrusive and extrusive rocks are igneous rocks and marble is metamorphic, by the process of elimination, B would be the correct answer.

Answer:

answer is B

Explanation:

Answer:

D)  decreses the force  .... so the guy can land safely  :)

Explanation:

When dealing with measurements in any circuit, it is essential to follow significant figure rules to ensure accurate and precise calculations.

Significant figures help us maintain the correct number of digits in our answer to reflect the precision of the measurements we took. For instance, if we measured a resistor's resistance as 35.67 ohms, we should use four significant figures in our calculation and round our answer to the appropriate number of significant figures. If we do not follow significant figure rules, we might introduce errors and inaccuracies in our results, which can lead to incorrect conclusions. Therefore, it is critical to pay attention to significant figures and use them correctly when working with measurements in any circuit.

Any zeros with two significant digits or less. The importance of a final zero or subsequent zeros only applies to the decimal section.

The distance is 0.0301 metres.

There are now only a handful significant figure rules, Each positive integer is significant, Significant zeros are those found between two non-zero digits, Leading zeros are completely irrelevant, The trailing zeros immediately behind the decimal point are crucial. A complete number with a decimal representation's final two digits are crucial.

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Fusion only occurs under conditions of extremely high temperature, such as those found in the core of the sun, where temperatures exceed millions of degrees. In order to replicate this process on Earth, scientists use devices called tokamaks, which use magnetic fields to contain and heat plasma to the high temperatures necessary for fusion to occur.

Fusion is a process in which two atomic nuclei combine to form a single, heavier nucleus, and this process releases a tremendous amount of energy. However, in order for fusion to occur, the nuclei must overcome the repulsive forces that exist between them due to their positive charges. These forces can only be overcome if the nuclei have sufficient energy to approach each other closely enough for the strong nuclear force, which holds the nuclei together, to take effect. At extremely high temperatures, the nuclei of atoms are in a highly energetic state and are moving very rapidly. This means that they have a greater chance of colliding with enough force to overcome the repulsive forces and fuse together. In addition, at high temperatures, the atomic nuclei are in a plasma state, which means that they have been stripped of their electrons, and are positively charged. This makes them more likely to collide with each other, as they are attracted to each other's charges. Therefore, fusion only occurs under conditions of extremely high temperature, such as those found in the core of the sun, where temperatures exceed millions of degrees. In order to replicate this process on Earth, scientists use devices called tokamaks, which use magnetic fields to contain and heat plasma to the high temperatures necessary for fusion to occur.

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To further stretch the spring from l m to L m, the work done is given by W = 0.5k (L² - l²), where k is the spring constant and l and L are the initial and final lengths respectively.

Given, it requires a force of 18 N to hold a spring stretched l m beyond its natural length.Since the work done is equal to the change in potential energy, therefore, the work required to further stretch the spring from l m to L m is given by:

W = Uf - Ui

= 0.5 k L² - 0.5 k l²

Now, we have k = F / x where F is the force required to stretch the spring by a distance x.So,

k = 18 / l

Also, the force required to stretch the spring to length L is given by:

F' = k (L - l) = 18 (L - l) / l

Therefore, the work done is given by:

W = 0.5 k (L² - l²) = 0.5 x 18 / l x (L² - l²) = 9 (L² - l²) / l

Hence, the work done to further stretch the spring from l m to L m is 9 (L² - l²) / l J.

Therefore, the work required to stretch the spring from l m to L m is given by the equation: W = 9 (L² - l²) / l.

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The difference is the first diagram experiences a gravitational force, while the second and third diagram experience electrostatic force.

The second diagram and third diagram have charged particles.

The second diagram has same charges q₁, and q₂, while the third diagram has opposite charges.

The similarity between both diagrams is that they experience electric force given as product of the charges divided by the distance between them.

F = Kq₁q₂/r²

where;

The difference between the diagrams is while the first diagram experiences gravitational force, the second and third diagram experience electrostatic force.

Force experienced by the first diagram is given as;

F = Gm₁m₂/r²

where;

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Answer:

Explanation:

Hey there!!!, there are no attached files/graphs to this question, but we can find our way and solve for the gravitational force acting on the mass

Step one:

given data

mass= 10kg

acceleration due to gravity= 9.81m/s^2

Step two:

The expression for the gravitation force is given as

Gravitational force F=mass * acceleration due to gravity

Fg=ma

substituting we have

Fg=10*9.81

Fg=98.1N

The force due to gravity exerted on the object is most nearly 100N

A).  There is a maximum altitude beyond which the aircraft cannot operate. The pressure difference between the lower and upper surfaces of the wings is zero.

The pressure difference between the lower and upper surfaces of the wings of a small jet airplane is calculated as follows; From Bernoulli's equation, the pressure difference is given by:ΔP = ½ρv2[1 - (A1/A2)]whereρ = Density of air v = Velocity of airA1 = Area of the lower surface of the wingA2 = Area of the upper surface of the wingGiven:A1 + A2 = 67.5 m2A1/A2 = 1/2ρ = 1.29 kg/m3v = 0 (horizontal flight)Substitute the given values into the equation and solve for ΔP;ΔP = ½ * 1.29 kg/m3 * 0 m/s[1 - (1/2)] = 0 Pa  

Therefore, the pressure difference between the lower and upper surfaces of the wings is zero. b) The velocity of air under the wing when the speed of air traveling over the wing is 247 m/s is calculated as follows; From Bernoulli's equation, the velocity of air under the wing is given by:v2 = v1 + 2(ΔP/ρ)wherev1 = Velocity of air over the wingΔP = Pressure difference between the lower and upper surfaces of the wingρ = Density of airGiven:v1 = 247 m/sΔP = 0 (from part a)ρ = 1.29 kg/m3Substitute the given values into the equation and solve for v2;v2 = 247 m/s

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Answer: 1 m/s

Explanation: 1 km = 1000 m (1 kilometer is equal to 1000 meters)

1 hour = 3600 seconds (1 hour is equal to 3600 seconds)

The given statement is TRUE

Iconic compounds are highly conductive when dissolved in water because the compounds hydrate ions after dissolving them in water.

Ionic compounds are a combination of metals and nonmetals, and as we know, metals are good conductors of electricity.

An ionic compound consists of two oppositely charged ions.

Water, on the other hand, is a polar solvent; the electronegativity difference between oxygen and hydrogen is high, therefore water has a positive H pole and a negative O pole (water is H2O).

And therefore when the ionic compound is dissolved in water, the opposite ions from the compound gets attracted to the poles of water and forms a unique arrangement called hydration, and therefore the iconic compounds are highly conductive when dissolved in water

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Frequency = the rate per second of a vibration constituting a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light).

The frequency is =  0.00030864 Hz

Solution -  To find the frequency of the oscillation after an intense earthquake, we need to use the formula:
Frequency (f) = 1 / Period (T)
Given that the period of the Earth's oscillation is 54 minutes, we first need to convert this to seconds:
54 minutes * 60 seconds/minute = 3240 seconds
Now, we can find the frequency:
Frequency (f) = 1 / 3240 seconds ≈ 0.00030864 Hz
the frequency of the oscillation after the intense earthquake is approximately 0.00030864 Hz.

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Answer: a physical phenomenon produced by the motion of electric charge, resulting in attractive and repulsive forces between objects.

Explanation: Magnetism is the force exerted by magnets when they attract or repel each other. Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms.

Answer:

Not all of the time, it can also depend on the strength of the magnet.

Explanation:

say you have a small very strong magnet, that might work just as well as a large but week magnet.

The matrix is ​​the set of extracellular materials that will form a certain tissue. Through this there will be a physiological integration of the cells.

In the matrix there will be different macromolecules, mainly collagen, enzymes, glycoproteins, among others which will give support to the cells that will be immersed in the matrix. It will also be involved in the process of cell multiplication and cell movement, since it will allow communication between the different cells to coordinate their cell functions.

The extracellular matrix is ​​going to be composed, broadly speaking, of two components: interstitial matrix and the basal membrane. The interstitial matrix is ​​one that will be formed by polysaccharides and fibrous proteins that gives it the characteristic to be able to cushion the compressions to which it may be subjected.

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Answer:

2,450

400

Explanation:

Pls brainliest me

Answer:

The potential energy (P.E) at the top is 392 J

The kinetic energy (K.E) at the top is 0 J

The potential energy (P.E) at the halfway point is 196 J.

The kinetic energy (K.E) at the halfway point is 196 J.

Explanation:

Given;

mass of the rock, m = 2 kg

height of the cliff, h = 20 m

speed of the rock at the halfway point, v = 14 m/s

The potential energy (P.E) and kinetic energy (K.E) when its at the top;

P.E = mgh

P.E = (2)(9.8)(20)

P.E= 392 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the top of the cliff = 0

K.E = ¹/₂(2)(0)²

K.E = 0

The potential energy (P.E) and kinetic energy (K.E) at the halfway point;

P.E = mg(¹/₂h)

P.E = (2)(9.8)(¹/₂ x 20)

P.E = 196 J

K.E = ¹/₂mv²

where;

v is velocity of the rock at the halfway point = 14 m/s

K.E = ¹/₂(2)(14)²

K.E = 196 J.

The potential energy (P.E) at the top is 392 J

The kinetic energy (K.E) at the top is 0 J

The potential energy (P.E) at the halfway point is 196 J.

The kinetic energy (K.E) at the halfway point is 196 J.

Since

mass of the rock, m = 2 kg

height of the cliff, h = 20 m

speed of the rock at the halfway point, v = 14 m/s

We know that

P.E = mgh

P.E = (2)(9.8)(20)

P.E= 392 J

Now

K.E = ¹/₂mv²

here.

v is velocity of the rock = 0

K.E = ¹/₂(2)(0)²

K.E = 0

Now

The potential energy (P.E) and kinetic energy (K.E) at the halfway point;

P.E = mg(¹/₂h)

P.E = (2)(9.8)(¹/₂ x 20)

P.E = 196 J

K.E = ¹/₂mv²

Here,

v is the velocity of the rock= 14 m/s

K.E = ¹/₂(2)(14)²

K.E = 196 J.

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The statement that the core nuclear fusion of carbon in a high-mass star is less energetic than the fusion of helium is not true.

In the core of a high-mass star, nuclear fusion occurs in several stages, starting with the fusion of hydrogen to form helium. As the star evolves and the core becomes denser and hotter, helium fusion produces carbon, and then carbon fusion produces heavier elements. The energy released by each stage of fusion is greater than the previous stage. Therefore, the statement that carbon fusion is less energetic than helium fusion is not true. In fact, carbon fusion is more energetic than helium fusion.

To accurately address this question, please provide the list of statements for me to evaluate. Once I have the list of statements, I can analyze each one and determine which statement is not true about the various stages of core nuclear fusion in a high-mass star.

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Answer:Malleability

Explanation:

Answer:

It works best when the compound is very soluble in a hot solvent, but very insoluble in the cold version of the same solvent. The compound must be a solid at room temperature.

Explanation:

Recrystallization is an appropriate technique for purification when the compound to be purified is a solid and is relatively pure to begin with.

It is also appropriate when the impurities are soluble in the solvent at room temperature and the compound to be purified is not. This allows for the impurities to be removed while the desired compound remains as a solid.

Additionally, recrystallization is appropriate when the compound has a relatively high melting point, as this prevents it from dissolving in the solvent at room temperature.

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The coefficient of static friction c for the book when θ = 60° is 0.32.

Static friction is the friction force that tries to keep an object at rest. When an object is about to move the resistance it feels at the intial is the static friction.

Given that the funtion cp·cos(θ) = p·sin(θ). Simply the function for the value of c, therefore, it can rewritten as,

\(c\cdot p\cdot \cos(\theta) = p\cdot \sin(\theta)\)

Divide both the sides by p, the mass of the book;

\(c\cdot \cos(\theta) = \sin(\theta)\)

Divide both the sides by cos(θ);

\(\dfrac{c\cdot \cos(\theta)}{\cos(\theta)} = \dfrac{\sin(\theta)}{\cos(\theta)}\\\\\\c= \dfrac{\sin(\theta)}{\cos(\theta)}\\\\\\c = \tan(\theta)\)

Further, Substitute the value of θ as 60° in the above function,

c = tan(60°)

c = 0.32

Hence, the coefficient of static friction c is 0.32.

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The complete question is:

The amount of force needed to keep a stationary object on a flat surface from moving is called static friction. If a book weighs p pounds and it is on a flat surface that is at an angle of θ degrees, the coefficient of static friction c for the book is given by the equation below.

cp cos(θ) = p. sin(θ)

Solve for c when θ = 60°

The speed of the airplane relative to the ground is the vector sum of the speed of the airplane relative to the air and the speed of the wind relative to the ground, and the direction is the angle of the resultant vector with respect to the ground.

In this case, we need to break down the velocities into their horizontal and vertical components. The horizontal component of the airplane's velocity is given by V_airplane * cos(290°), and the vertical component is V_airplane * sin(290°).

Similarly, the horizontal and vertical components of the wind's velocity are V_wind * cos(45°) and V_wind * sin(45°), respectively.

To find the resultant velocity, we add the horizontal and vertical components of the airplane's velocity to the horizontal and vertical components of the wind's velocity.

The magnitude of the resultant velocity is calculated using the Pythagorean theorem, and the direction is determined using trigonometric functions.

Therefore, to find the speed and direction of the airplane relative to the ground, we need to calculate the resultant velocity vector using the given information and trigonometric calculations.

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The Weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.

A jumbo jet can fly its whole length in 20 seconds at a certain speed and has a 284-foot length. The big jet taxied completely past a 710-foot-long hangar in 70 seconds while travelling at the same speed.

In physics, you can get average speed by dividing the total distance travelled by the total time needed to travel that distance. Speed is the rate of change in an object's position, expressed in metres per second. The rate at which an object travels a distance is considered its speed. High speed describes an object that is travelling quickly.

P should represent the plane's length in feet.

20p = (710+p)/20p = 14200+20p 50p = 14200 p = 284ft

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Answer:

t = 10 s

Explanation:

Given :

Altitude, h = 490 m

Initial velocity of a plane, u = 250 m/s

To find :

The time required for the packet to hit the ground. When it hits the ground its velocity will be 0. Let t is the required time. It can be calculated as follows :

\(t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 490}{9.8}} \\\\t=10\ s\)

So, it will take 10 s to reach the ground.

For an ideal gas, initially at a volume of 0.777778 L,  the work done by the gas during this process is mathematically given as

w=15.380613

Generally, the equation for the work done  is mathematically given as

W=p1v1invfvi

Therefore

v2=p1v1/p2

v2=9*1.0.77778/1

v2=7.00002

In conclusion

w=7.00002ln7/0.777778

w=15.380613

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