The body reaches a velocity of 6 m/s. Calculate the distance travelled by the object to reach this velocity.

The car would skid 51.8% farther on wet concrete than on dry concrete.

Do it more slowly and give yourself more time to get there. Employ your low beam headlights, which also turn on your taillights, to make your car visible to drivers ahead of you and behind you. If you have fog lights, use them. Never turn on your high beams. The low, narrow vertical pattern (and vast lateral spread) of light emitted by them can be used to identify them.

d = (v² / 2μg)

where g is the acceleration brought on by gravity (9.8 m/s²), d is the distance travelled, v is the beginning velocity, which in this instance we can suppose to be zero.

D(wet) / D(dry) = [(v² / 2μ(wet)g) / (v² / 2μ(dry)g)] = μ(dry) / μ(wet)

D(wet) / D(dry) = 0.85 / 0.56 = 1.518

(D(wet) - D(dry)) / D(dry) = (1.518 - 1) × 100% = 51.8%

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In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.

Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.

The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.

The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.

Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:

mv²/r = (0.5μs)mg

Simplifying the equation, we find:

v = √(0.5μsgr)

By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.

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Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

Answer:

the units of work and energy is joule and unit of power is Watt

The substance that would be most likely to provoke a response similar to the barium dance is c. lead.

Barium dance is used to describe the movements of the body that can occur when a person is exposed to a high level of barium. Barium is a heavy metal that can be toxic in large amounts, and exposure can occur through ingestion, inhalation, or skin contact.

Other heavy metals such as lead, mercury, can also cause similar symptoms when a person is exposed to high levels. Additionally, exposure to certain chemicals such as pesticides, solvents, and industrial pollutants can also cause neurological symptoms similar to those seen in barium.

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When a person is exposed to high quantities of other heavy metals like lead, mercury, and cadmium, comparable symptoms can also be experienced. Furthermore, neurological symptoms resembling those of barium can also be brought on by exposure to specific substances including insecticides, solvents, and industrial pollutants.

It's critical to remember that any potential exposure to these drugs needs to be taken seriously, and if you think you may have been exposed, you should get medical help right once.

based on the information in the passage, which of these substances would be most likely to provoke a response similar to the barium dance

a. oxygen

b. nitrogen

c. lead

d. sulphur

Hi there!

\(\large\boxed{P = 100 kgm/s}\)

To calculate momentum, we use the formula:

P = m · v, where:

P = momentum (kgm/s)

m = mass (kg)

v = velocity (m/s)

Plug in the given values:

P = 50 · 2

P = 100 kgm/s.

The accurate statements that describe mechanical waves are: Mechanical waves require a medium , Mechanical waves transfer energy, Mechanical waves can be longitudinal or transverse, Mechanical waves can be categorized as compressional or shear waves, Mechanical waves obey the principles of reflection, refraction, and interference, Mechanical waves have measurable properties such as wavelength, frequency, and amplitude.

Mechanical waves are a type of wave that require a medium, such as a solid, liquid, or gas, to propagate. They are characterized by the transfer of energy through the oscillation or vibration of particles in the medium. Here are the accurate statements that describe mechanical waves:

1. Mechanical waves require a medium: This statement is true. Mechanical waves cannot propagate in a vacuum because they rely on the interaction of particles in a medium to transfer energy.

2. Mechanical waves transfer energy: This statement is true. Mechanical waves transport energy from one location to another as the particles of the medium vibrate or oscillate.

3. Mechanical waves can be longitudinal or transverse: This statement is true. Mechanical waves can exhibit different types of motion. In longitudinal waves, the particles of the medium oscillate parallel to the direction of wave propagation. In transverse waves, the particles oscillate perpendicular to the direction of wave propagation.

4. Mechanical waves can be categorized as compressional or shear waves: This statement is true. In a compressional wave, the particles of the medium undergo compression and rarefaction as the wave passes through. In shear waves, the particles move perpendicular to the direction of wave propagation, resulting in a sideways displacement.

5. Mechanical waves obey the principles of reflection, refraction, and interference: This statement is true. Mechanical waves can reflect off surfaces, change direction when passing through different media (refraction), and exhibit interference patterns when two or more waves interact.

6. Mechanical waves have measurable properties such as wavelength, frequency, and amplitude: This statement is true. Mechanical waves can be described by various properties. Wavelength represents the distance between two consecutive points in the wave, frequency is the number of wave cycles per unit of time, and amplitude is the maximum displacement of particles from their equilibrium position.

These statements accurately describe mechanical waves and their properties, highlighting the key characteristics of this type of wave propagation.

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Answer:

it is chemistry

Explanation:

The length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

Cells are the basic building blocks of all living things, including humans. The human body is composed of trillions of cells with  average cell diameter of 1 x 10⁻⁵ m.

The length of the total cells in the human body when all the cells are stretched out is calculated as follows;

total length of the cells = average diameter of a cell x number of cells

total length of the cells = 1 x 10⁻⁵ m x 7.5 x 10¹³

total length of the cells = 7.5 x 10⁸ m

Thus, the length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

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Answer:

\(thank \: you\)

Answer:   6.605

Explanation:

a. The magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity is 8.72 m/s^2 and 654.0 N respectively.

b.  The astronaut is experiencing 0.89 g when moving at constant angular velocity.

c. The torque that is needed to bring the centrifuge to a stop 6875 Nm.

Angular velocity is described as a pseudovector representation of how fast the angular position or orientation of an object changes with time.

The magnitude of the centripetal acceleration and force, we will use the formula: a = v^2 / r, where v is the tangential velocity and r is the radius of the centrifuge.

a = (2pi20m15.02pi/60)^2 / 20m = 8.72 m/s^2

To calculate the force, we will use the formula

F_ = ma, where m is the mass of the astronaut, 75.0 k

F_ = 75.0 kg * 8.72 m/s^2 = 654.0 N

b. To calculate  the number of g's the astronaut is experiencing when moving at constant angular velocity, we will divide the centripetal acceleration by the acceleration due to gravity, 9.8 m/s^2

8.72 m/s^2 / 9.8 m/s^2 = 0.89 g

c.

Torque = I * alpha, where I is the moment of inertia and alpha is the angular acceleration.

I = (1/2) * 5500.0 kg * 20.0m^2 = 55000 kgm^2

The angular acceleration can be found using the formula

Alpha = (change in angular velocity) / (change in time)

The change in angular velocity is 15.0 rpm - 0 rpm = 15.0 rpm and the change in time is 2.0 minutes = 120 seconds

alpha = 15.0 rpm / 120 s = 0.125 rad/s^2

Torque = 55000 kgm^2 * 0.125 rad/s^2 = 6875 Nm

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The average blood pressure in the brain will be higher than the average blood pressure in the feet. the average blood pressure in the brain will be lower than the average blood pressure in the feet.

When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain and feet of a person changes.

Similarly, when the elevator accelerates downward with the same acceleration, the blood pressure in the brain and feet of a person changes.

Let's discuss them one by one:Blood Pressure When Elevator Accelerates Upward at \(10 ms^{-2}\)

When the elevator accelerates upward at \(10 ms^{-2}\),  the blood pressure in the brain of a person increases, while the blood pressure in the feet of a person decreases.

This happens due to the gravitational force acting on the body.

Since the gravitational force on the head is greater than the gravitational force on the feet, the blood pressure in the brain increases while the blood pressure in the feet decreases.

Therefore, the average blood pressure in the brain will be higher than the average blood pressure in the feet.

Blood Pressure When Elevator Accelerates Downward at  \(10 ms^{-2}\) When the elevator accelerates downward at \(10 ms^{-2}\), the blood pressure in the brain of a person decreases, while the blood pressure in the feet of a person increases.

This also happens due to the gravitational force acting on the body. Since the gravitational force on the head is less than the gravitational force on the feet, the blood pressure in the brain decreases while the blood pressure in the feet increases.

Therefore, the average blood pressure in the brain will be lower than the average blood pressure in the feet.

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The moose runs away 57.94 meter in 7.43 second.

Acceleration is the rate at which a velocity changes over time. It qualifies as a vector quantity because it possesses both direction and magnitude. Meter/second^2 (m/s^2) is the SI unit of acceleration.

Acceleration of the moose: a = 2.1 m/s^2.

Final speed of the moose: v = 15.6 m/s.

Hence, time taken by the moose =v/a

= 15.6/2.1 second.

= 7.43 second

distance travelled by the moose = v²/2a

= 15.6²/(2×2.1) meter

= 57.94 meter.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The correct statement is Molecular collisions transfer thermal energy between the system and its surroundings. Thus, option D is correct.

The energy moves between a system of reacting substances and the surroundings by the collision of molecules. The transfer of heat or thermal energy between the system and its surroundings by the process of Conduction. Conduction is the process of transmitting the heat to the neighboring atoms or collisions by the process of collisions.

The conduction takes place more steadily in solids and liquids where the molecules are closer together. When the molecules are collided with the nearby molecules, the potential energy is converted into kinetic energy and hence the heat energy is transferred between the system and its surroundings.

Hence, Molecular collisions transfer thermal energy between the system and its surroundings. Thus, the correct option is D.

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Answer:

yes

Explanation:

Water HEATS up and turns into steam. Steam is made from HEAT. Granite can be compromised by HEAT. Lead compounds can be good insulators.

The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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Answer:

As the charge increases, the force decreases in strength

Explanation:

Experiments with electric charges have shown that if two objects each have electric charge, then they exert an electric force on each other. The magnitude of the force is linearly proportional to the net charge on each object and inversely proportional to the square of the distance between them...

Answer: The correct answer is: As the charge increases, the force increases in strength

Explanation:

Its kind of the obvious answer and other people don't know how to answer correctly. This was years ago but if anyone needs the answer today then here it is....

Answer:

5 Muscular and strength

The net force acting on the box is 5N , and it is unbalanced.

since the forces acting on the system is 7N and 2N which is opposite direction.

here given two forces ,

        f1 = 7N

        f2 = 2N

since both forces are in opposite direction ,

     Net force = f1 - f2

                      = 7N - 2N

                      = 5N

so the net force that act on the given box is 5N and unbalanced .

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Answer:

A)  4.95 m

B)  1.48225 m

Explanation:

Constant Acceleration Equations (SUVAT)

\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

\(u=9.00\quad v=9.00 \quad a=0\quad t=0.550\)

\(\begin{aligned}\textsf{Using} \quad s & = \left(\dfrac{u+v}{2}\right)t:\\\\s&= \left(\dfrac{9+9}{2}\right)(0.550)\\s&= (9)(0.550)\\ \implies s&= 4.95\:\sf m\\\end{aligned}\)

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

\(u=0\quad a=9.8\quad t=0.550\)

\(\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\s&= (0)(0.550)+\dfrac{1}{2}(9.8)(0.550)^2\\s&= 0+(4.9)(0.3025)\\\implies s&= 1.48225\:\sf m\\\end{aligned}\)

Answer:

B. period of the sound wave

Answer:

We're no strangers to love

You know the rules and so do I

A full commitment's what I'm thinking of

You wouldn't get this from any other guy

I just wanna tell you how I'm feeling

Gotta make you understand

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

We've known each other for so long

Your heart's been aching but you're too shy to say it

Inside we both know what's been going on

We know the game and we're gonna play it

And if you ask me how I'm feeling

Don't tell me you're too blind to see

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

No, I'm never gonna give you up

No, I'm never gonna let you down

No, I'll never run around and hurt you

Never, ever desert you

We've known each other for so long

Your heart's been aching but

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

No, I'm never gonna give you up

No, I'm never gonna let you down

No, I'll never run around and hurt you

I'll never, ever desert you

Explanation:

RICK ROLLED

The image distance is calculated to be 2.44 cm.

Given that, diameter of the ball is 8.9 cm

Radius of the ball = d/2 = 8.9/2 = 4.45 cm

Object distance u = 26 cm

Now let us find out the image distance using mirror formula,

1/f = 1/u + 1/v ----(1)

where, u is object distance

v is image distance

f is focal length

We know that, focal length f = r/2 = 4.45/2 = 2.23 cm

Let us substitute the values in (1),

1/v = 1/f - 1/u

1/v = 1/2.23 - 1/26

1/v = 0.45 - 0.04

1/v = 0.41

v = 2.44 cm

Thus, the image distance is calculated to be 2.44 cm.

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Answer:

Explanation:

To find the net electric flux through a closed surface, we need to apply Gauss's law:

Phi_E = Q_enclosed / epsilon_0

where Phi_E is the electric flux, Q_enclosed is the net charge enclosed by the closed surface, and epsilon_0 is the electric constant.

Let's consider a spherical closed surface of radius R enclosing the charges. We can divide the surface into two regions: inside and outside the sphere.

For the charges inside the sphere, the net charge enclosed is:

Q_enclosed = +1.00 nC - 3.00 nC = -2.00 nC

Therefore, the electric flux through the inner surface of the sphere is:

Phi_E_inside = Q_enclosed / epsilon_0 = (-2.00 nC) / epsilon_0

For the charge outside the sphere, the net charge enclosed is:

Q_enclosed = +2.00 nC

Therefore, the electric flux through the outer surface of the sphere is:

Phi_E_outside = Q_enclosed / epsilon_0 = (2.00 nC) / epsilon_0

The net electric flux through the closed surface is the sum of the electric flux through the inner and outer surfaces:

Phi_E_net = Phi_E_inside + Phi_E_outside = (-2.00 nC) / epsilon_0 + (2.00 nC) / epsilon_0

= 0

Therefore, the net electric flux through the closed surface is zero. This means that the total amount of electric field lines entering the surface is equal to the total amount of electric field lines leaving the surface. This result is consistent with Gauss's law, which states that the net electric flux through a closed surface is proportional to the net charge enclosed by the surface. In this case, since the net charge enclosed is zero, the net electric flux is also zero.

Answer:

It's d on edg

Explanation:

Answer:

she should ve the one handing out the cookies each day, to make sure each child gets only one cookie a day.