The average human heart beats 75 times every minute. The average horse has a heartbeat of 40 times every minute. How many times does a human heart beat in an hour? Which answer choice correctly identifies the extraneous information in this word problem?

The only true statement about the domain of the given function is:

B. f(x) is negative for all x < -5

The domain of a function is defined as the set of values that we can possibly plug into our function. This set is the x values in a function such as f(x).

Now, we are given the function as:

f(x) = \(\frac{2}{x^{2} } + 3x - 10\)

When x < -5, we have:

f(-4) = \(\frac{2}{(-4)^{2} } + 3(-4) - 10\)

f(-4) = -21.875

This suggests that for all values below x = -5 will result in negative values

When x > 2

f(3) = \(\frac{2}{3^{2} } + 3(3) - 10\)

f(3) = -0.78

Thus, it will get positive for higher values but it can also be negative as seen here.

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Without additional information about the model house, it is impossible to accurately describe the surface that Molly does not need to paint. It could be any surface that will not be visible when the model house is displayed, such as the underside of a roof, the back of a wall, or the bottom of a floor.

Now We know

\(\\ \sf\longmapsto tan30=\dfrac{7}{B}\)

\(\\ \sf\longmapsto \dfrac{1}{\sqrt{3}}=\dfrac{7}{B}\)

\(\\ \sf\longmapsto B=7\sqrt{3}\)

\(\\ \sf\longmapsto B=7(1.732)\)

\(\\ \sf\longmapsto B\approx 12\)

Now

Using pythagorean theorem

\(\\ \sf\longmapsto H^2=P^2+B^2\)

\(\\ \sf\longmapsto H^2=7^2+12^2\)

\(\\ \sf\longmapsto H^2=144+49\)

\(\\ \sf\longmapsto H^2=193\)

\(\\ \sf\longmapsto H=\sqrt{193}\)

\(\\ \sf\longmapsto H\approx 13\)

The point (1, 1/2) lie on the equation  y(x² + 1) = 1.

An ordered pair is made up of the ordinate and the abscissa of the x coordinate, with two values given in parenthesis in a certain sequence.

Pair in Order = (x, y)

x is the abscissa, the distance measure of a point from the primary axis x

y is the ordinate, the distance measure of a point from the secondary axis y

Given, A function y(x² + 1) = 1.

y = 1/(x² + 1).

When x = 1, y = 1/2.

When x = - 1, y = 1/2.

So, The points that lie on the equation y(x² + 1) = 1 is (1, 1/2).

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Answer:

o minutes5.10.15.20.25.30.35.40.45.50 minutes

Using the Chain Rule, we have: dy/dx = f'(g(x)) * g'(x) = 1 * 1 = 1.The derivative of y with respect to x is 1.

When we compose a function, it may be possible to write it in a variety of different ways. Differentiating such functions can result in different derivatives, but the Chain Rule indicates that the derivatives of the compositions should be the same regardless of how the function is written, if the function is continuous and differentiable.For instance, consider the function f(x) = sin(x²). It can be written as f(g(x)) where g(x) = x² and f(x) = sin(x). Furthermore, it can be written as f(h(x)) where h(x) = x² and f(x) = sin(x). These are both compositions of functions, but they are different compositions that lead to different derivatives.However, if the function is a composite of differentiable functions, the Chain Rule tells us that the derivative of a composite function is the derivative of the outer function multiplied by the derivative of the inner function.

To find dy/dx if y = x using the Chain Rule with y as a composite of the following functions, we must first rewrite y as a composite function: y = f(g(x)) where g(x) = x and f(x) = x. This composite function can be written in a variety of different ways, such as y = f(h(x)) where h(x) = x and f(x) = x, or y = f(k(x)) where k(x) = x and f(x) = x. However, regardless of how we write it, the Chain Rule tells us that the derivative of y is equal to the derivative of the outer function (f(x) = x) multiplied by the derivative of the inner function (g(x) = x).

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Answer:

look it up hahahahah

Step-by-step explanation:

a. Assuming no additional restrictions, there are  800 possible three-digit area codes.

b. Considering ERCs, there are  80 ERCs.

c. For the seven digits after the area code, there are \(8 \times 10^6 = 8,000,000\)  possible seven-digit phone numbers.

d. Assuming only the 0 and 1 restrictions from parts a and c, the number of possible ten-digit phone numbers is 800 \(\times\) 8,000,000 = 6,400,000,000.

a. For three-digit area codes, the first digit cannot be 0 or 1.

Assuming no additional restrictions, there are 8 possibilities for the first digit (2-9) and 10 possibilities for each of the remaining two digits (0-9). Therefore, the total number of three-digit area codes possible under this plan is \(8 \times 10 \times 10 = 800.\)

b. For an ERC (Easily Recognizable Code), the second and third digits of the area code must be the same, and the first digit cannot be 0 or 1. There are 8 possibilities for the first digit (2-9) and 10 possibilities for the third digit (0-9).

Since the second digit must be the same as the third digit, there is only 1 possibility.

Therefore, the total number of ERCs is \(8 \times 1 \times 10 = 80.\)

c. For the seven digits after the area code, the first digit of the three-digit local prefix cannot be 0 or 1.

There are 8 possibilities for the first digit (2-9) and 10 possibilities for each of the remaining six digits (0-9).

Therefore, the total number of seven-digit phone numbers possible is 8 * \(10\times 10 \times 10 \times 10 \times 10 \times 10 = 8,000,000.\)

d. Assuming only the 0 and 1 restrictions from parts a and c, the number of possible ten-digit phone numbers can be calculated by multiplying the number of possibilities for each digit position.

For the area code (part a), there are 800 possibilities.

For the seven digits after the area code (part c), there are 8,000,000 possibilities.

Therefore, the total number of ten-digit phone numbers possible is 800 * 8,000,000 = 6,400,000,000.

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The number of different combinations of k elements in a set of n elements, is:

If we want to select three players from a group of 9 students, then the amount of different teams will be given by:

Therefore, the total amount of different teams that can be selected, is:

The measure of BC is 110°

Semicircle is defined as a half circle formed by cutting the circle into two halves. It is formed when a line passes through the center and touches the two ends of the circle. This line is called the diameter of the circle.

line AB is the diameter of the circle and thus, AB gives a semi circle.

This means that, since angle Ina semi circle is 180°, the sum of AC and BC is 180°

therefore, 2x-30+x = 180°

3x = 180+30

3x = 210

divide both sides by 3

x = 210/3 = 70°

therefore BC = 2x-30

= 2×70-30

= 140-30

= 110

therefore the measure of BC is 110°

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Answer:

7

Step-by-step explanation:

\(\frac{f(6)-f(4)}{6-4}=\frac{26-12}{6-4}=7\)

324 divided into 6.846 is 47.33

The statement is given as:

324 divided into 6.846

This is represented as:

324/6.846

Using a calculator, we have:

47.3269062226

Approximate

47.33

Hence, 324 divided into 6.846 is 47.33

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Answer:

5pi/3x180grados/piradianes

900/3=300 grados

Step-by-step explanation:

Answer:

7606.62

Step-by-step explanation:

Start by finding how much you will have through the annuity. The question isn't that clear, so i will just assume it's an annuity due.

\(p(\frac{(1+i)^n-1}{i})*(1+i)\\i=.035/12= .0029166667\\n=10*12=120\\p=75 (given)\\75\frac{(1+.0029166667)^{120}-1}{.0029166667}*(1+.0029166667)= 10788.814149\\\)

Now just equate this to a time 0 payment at the same rate

\(10788.814149=(1+.0029166667)^{120}*x\\x= 7606.6228603=7606.62\)

As a quick note, if you were supposed to assume that your annuity was an annuity immediate the answer would be 7584.50.

Considering the definition of perpendicular line, the equation of the perpendicular line that passes through the point (x, y) = (3, 1) and is perpendicular to the line 2x + 3y = 12 is y= 3/2x -7/2.

A linear equation o line can be expressed in the form y = mx + b

where

Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.

In this case, the line is 2x+3y= 12. Expressed in the form y = mx + b, you get:

3y= 12 - 2x

y= (-2x +12)÷ 3

y= -2/3x +4

Since multiplying the slopes of two perpendicular lines, you get -1, and the line has a slope of -2/3, you get:

-2/3× slope perpendicular line= -1

slope perpendicular line= (-1)÷ (-2/3)

slope perpendicular line= 3/2

The line passes through the point (3, 1). Replacing in the expression for parallel line:

1= 3/2× (3) + b

1= 9/2 + b

1- 9/2 = b

-7/2= b

Finally, the equation of of perpendicular line is y= 3/2x -7/2.

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Answer:

greenn paint trust me balls

(a) The likelihood function for this sample is given by:

L(λ) = λ^2 * exp(-λ * (5 + 3 + x))

where x is the third observation, X₃, which is larger than 10.

(b) To find the MLE for λ, we take the derivative of the log-likelihood with respect to λ and set it equal to zero:

d/dλ ln(L(λ)) = 2/λ - (5 + 3 + x) = 0

Solving for λ, we find that the MLE for λ is λ = (2) / (5 + 3 + x).

Since x is greater than 10, the MLE for λ is positive and less than 2/(5 + 3 + 10) = 2/18

Therefore, the correct answer is as given above

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140.55 pounds will be sold approximately each week at the optimal price of $0.67/lb.

To find the price elasticity of demand for bananas at $0.20/lb, we need to use the formula:

According to the given data:

E(p) = -p(q'/q(p))

where q' is the derivative of q(p) with respect to p.

First, we need to find q'(p):

\(q'(p) = -225e^(1.5(5-p))\)

Then, we can plug in the values:

E(0.20) = -0.20(q'(0.20)/q(0.20))

= \(-0.20(-225e^(1.5(5-0.20)) / 100e^(1.5(5-0.20)))\)

= 2.70

Therefore, the price elasticity of demand for bananas at $0.20/lb is 2.70.

To find the price elasticity of demand for bananas at $1/lb, we can use the same formula:

E(p) = -p(q'/q(p))

First, we need to find q'(p):

\(q'(p) = -225e^(1.5(5-p))\)

Then, we can plug in the values:

E(1) = -1(q'(1)/q(1))

= \(-1(-225e^(1.5(5-1)) / 100e^(1.5(5-1)))\)

= 0.68

Therefore, the price elasticity of demand for bananas at $1/lb is 0.68.

To find the price that maximizes revenue, we need to find the value of p that makes revenue, R(p), maximum.

Revenue is given by:

R(p) = pq(p)

= \(p100e^(1.5(5-p))\)

To maximize revenue, we need to find the critical point of R(p) by taking its derivative and setting it equal to zero:

\(R'(p) = 100e^(1.5(5-p)) - 150pe^(1.5(5-p)) = 0\)

Simplifying this expression, we get:

\(2e^(1.5(5-p)) - 3pe^(1.5(5-p)) = 0\)

2 = 3p

p = 2/3

Therefore, the price that maximizes revenue is $0.67/lb.

To find the maximum revenue per week, we can plug this price back into the revenue equation:

\(R(2/3) = (2/3)*100e^(1.5(5-2/3))\)

= $167.56

Therefore, the maximum revenue per week is $167.56.

To find how many pounds will be sold each week at the optimal price of $0.67/lb, we can plug this price back into the demand equation:

\(q(2/3) = 100e^(1.5(5-2/3))\)

= 140.55

Therefore, approximately 140.55 pounds will be sold each week at the optimal price of $0.67/lb.

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Answer:

1/5, 2/9, 0/4

If a sample consists of 600 test scores, 516 of them would be at or below the 86th percentile. If a sample consists of 600 test scores, 228 of them would be at or above the 62th percentile.

A percentile is a score that compares a specific score to the scores of the other members of a group. It displays the proportion of other scores that a given score outperformed. For instance, if you have a test score of 75 and are placed in the 85th percentile, it signifies that your score is greater than those of 85% of other test takers.

Given that,

In general, 70 % of the values in a data set lie at or below the 70th percentile.

20 % of the values in a data set lie at or above the 20th percentile.

Generally percentile defines the percentage of a data set that is below or at a value that is being considered.

Hence the percentage of the values of a data set that lies below or at the 16th percentile is  16%

Also  the values of a data set that lies below or at the 24th percentile is  24%

Given a sample of 600 test scores , the number of test scores that will be at or below the 86th percentile is 86% of  600 which is mathematically represented as:

K = \(\frac{86}{100}\) × 600

K = 516 test scores

Given a sample of 600 test scores , the number number of test scores that will be above  the 62 th percentile is (100 - 62 = 38 )% of  600 which is mathematically represented as:

a = \(\frac{38}{100}\) × 600

a = 228 test scores.

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Answer:

The third option

Step-by-step explanation:

Answer:

50% decrease

Step-by-step explanation:

\(\dfrac{(V_2-V_1)}{|V_1|} \times 100\)

\(= \dfrac{(5 - 10)}{|10|} \times 100\)

\(= \dfrac{-5}{10} \times 100\)

\(= -0.5 \times 100\)

\(= -50\% \; \text{change}\)

\(= 50\% \; \text{decrease}\)

Answer: 50 i guess not sure

Step-by-step explanation: hope this helps of not i hope someone can help you ok :)

Descending: subtraction

Rises: Addition

The diver descends 100ft: Position -100 (the 0 is the sea level)

Then rises 28: Add 28 to the previous position: Position -72

...before descending another 33: Subtract 33 to the previous position:

Then, the final position is -105ft (105 ft under the sea level)

Answer:

x=112°

y=50°

Step-by-step explanation:

y=50°

x=180-50-18=112°

The Venn diagram for (D ⋃ E) ⋃ F will be the ovarlapped region of D,E and F.

To represent the sets D, E, and F in the Venn diagram, we first construct three overlapping circles. Then, beginning with the innermost operation and moving outward, we shade the regions corresponding to the set operations in the expression.

We shade the area where the circles for D and E overlap because the equation (D ⋃ E)  denotes the union of the sets D and E. All the elements in D, E, or both are represented by this area.

The union of (D ⋃ E) with F is the next step. This indicates that we darken the area where the circle for F crosses over into the area that we shaded earlier. All the components found in sets D, E, F, or any combination of these sets are represented in this region.

The final Venn diagram should include three overlapping circles, with (D ⋃ E) ⋃ F shaded in the area where all three circles overlap.

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Answer:

4x - 3 - 2x + 5 = 6 - 3x + 2 + 5x

2x + 2 = 2x + 8

2 ≠ 8, so this equation has no solutions.

Answer:

No solution

Step-by-step explanation:

Given:

\(4x-3-2x+5=6-3x+2+5x\)

rearrange terms so like terms are together

\(4x-2x-3+5=6+2-3x+5x\)

combine like terms

\(2x+2=8+2x\)

subtract 2x to both sides

\(2\neq 8\)

2 doesn't equal 8, meaning that there are 0 solutions to this problem.

Hope this helps! :)