The area of the shaded region is 42 ft2 . What is the area of the unshaded region? A) 7 ft 2B) 21 ft2C) 42 ft2D) 84 ft2

Answer:

20%

Step-by-step explanation:

48+52=100

20 out of 100= 20

Answer:

12/12 or 1

Step-by-step explanation:

Tina baked 12 peanut butter cookies, and it is said that 12 of them had chocolate chips. So, we can make a fraction, being 12/12

Answer:

7/60 hour or 7 minutes b) 8 or 8 4/7 depending if you consider a fraction of a task is yes or no

Step-by-step explanation:

Answer:

B. No

Step-by-step explanation:

I calculated it logically

From the resulting solution, the correct linear inequality graph is Graph C.

Given the inequality equation below:

2(2x-1)+7< 13 or -2x+5 ≤ -10.​

Simplify the expression

2(2x-1)+7< 13

Expand

4x - 2 + 7 < 13

4x + 5 < 13

4x < 13 - 5

4x < 8

x < 2

For the inequality -2x+5 ≤ -10.

-2x+5 ≤ -10

-2x  ≤ -15

x  ≥ 7.5

Hence the solution to the given system of inequalities are x < 2 and x  ≥ 7.5

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Step-by-step explanation:

first choice

ggiteesxdgcJ gray y atcha

Answer:

330 miles

Step-by-step explanation:

Use the slope intercept form of a line.

y = mx + b

b will be the constant or the daily cost to rent the car.  The x is the number of miles.  The y is the total cost and the m is the cost per mile.

Vertical ine is in the form

x = a where a is a number

Horizontal line is in the fomr

y = b, where b is a number

Clearly the equatin isn't a vertical or hirzontal line.

Now, 3rd and 4th hoice evaluate:

(8,3) --- point it passes

let's plug in:

8x + 3y

8(8) + 3(3) = 0 ??? NO!!

T

This choice is not right.

Now, 4th choice:

passes through origin (0,0)

8x + 3y = 0

Now plugging in:

8(0) + 3(0)

= 0

So, this is correct.

It passes through the origin

Answer:

40%

Step-by-step explanation:

i used a calculator

The company should produce 235 units of Metakeb, 96 units of Mewesson, and 17 units of Metekem per month to use up all the available resources.

What is the Gaussian method?

The Gaussian method, also known as Gaussian elimination or row reduction, is a technique for solving systems of linear equations. It involves performing a sequence of operations on the rows of a matrix to transform it into an equivalent matrix that is in row echelon form or reduced row echelon form.

To use the Gaussian method, we need to set up a system of linear equations based on the given information. Let x, y, and z be the number of units of Metakeb, Mewesson, and Metekem produced per month, respectively. Then we have:

Machining department: 1200x + 1800y + 3000z = 1050(60)

Inspection department: 2400x + 1200y = 1160(60)

Assembly department: 600x + 3000y = 830(60)

Simplifying these equations, we get:

Machining department: 20x + 30y + 50z = 3150

Inspection department: 8x + 4y = 232

Assembly department: x + 5y = 139

Now we can use the Gaussian method to solve for x, y, and z:

Step 1: Write the augmented matrix:

| 20 30 50 | 3150 |

| 8 4 0 | 232 |

| 1 5 0 | 139 |

Step 2: Use row operations to get the matrix in row echelon form:

R2 → R2 - 4/5 R3

R1 → R1 - 20R3

| 0 -2 50 | 850 |

| 0 2 -4   | -28 |

| 1 5 0     | 139 |

R2→ -1/2 R2

R1 → R1 + R2

| 0 1 -25 | 407 |

| 0 1 -2 | 14 |

| 1 5 0 | 139 |

R1→ R1 - R2

| 0 0 -23 | 393 |

| 0 1 -2 | 14 |

| 1 5 0 | 139 |

R3→ R3 - 5R2

| 0 0 -23 | 393 |

| 0 1 -2 | 14 |

| 1 0 10 | 65 |

R1→ -1/23 R1

| 0 0 1 | -17 |

| 0 1 -2 | 14 |

| 1 0 10 | 65 |

R2 → R2 + 2R3

| 0 0 1 | -17 |

| 0 1 0 | 96 |

| 1 0 10 | 65 |

R3 → R3 - 10R1

| 0 0 1 | -17 |

| 0 1 0 | 96 |

| 1 0 0 | 235 |

Step 3: Read off the solution from the row echelon form:

z = -17

y = 96

x = 235

Therefore, the company should produce 235 units of Metakeb, 96 units of Mewesson, and 17 units of Metekem per month to use up all the available resources.

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Therefore, the interest portion of the seventh payment is:7,000 x (1 + r + r2 + r3 + r4 + r5 + r6) / r7 - 7,000.

We have the following payments and their corresponding times of payment:At the end of year 1: $1,000At the end of year 2: $2,000At the end of year 3: $3,000At the end of year 4: $4,000At the end of year 5: $5,000At the end of year 6: $6,000At the end of year 7: $7,000

At the end of year 8: $8,000At the end of year 9: $9,000At the end of year 10: $10,000The present value of these payments is:PMT x [(1 - (1 + r)-n) / r]where PMT is the payment, r is the interest rate per year, and n is the number of years till payment.

For the first payment (end of year 1), the present value is:1,000 x [(1 - (1 + r)-1) / r]which equals

1,000 x (1 - 1 / (1 + r)) / r = 1,000 x ((1 + r - 1) / r) = 1,000

For the second payment (end of year 2), the present value is:2,000 x [(1 - (1 + r)-2) / r]which equals 2,000 x (1 - 1 / (1 + r)2) / r = 2,000 x ((1 + r - 1 / (1 + r)2) / r) = 2,000 x (1 + r) / r2

For the seventh payment (end of year 7), the present value is:

7,000 x [(1 - (1 + r)-7) / r]

which equals

7,000 x (1 - 1 / (1 + r)7) / r = 7,000 x ((1 + r - 1 / (1 + r)7) / r) = 7,000 x (1 + r + r2 + r3 + r4 + r5 + r6) / r7

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During summer vacation, Alexa read, on average, 10 pages per night. The number of pages per night Alexa averaging now is 2 pages.

A % is a quantity or ratio that, in mathematics, represents a portion of one hundred. A dimensionless relationship between two numbers can be represented in a variety of ways, such as through ratios, fractions, and decimals.

By calculating the percentage of the original Wesley is now reading, we can make the inquiry a little simpler. He is reading 20% of what he used to read rather than 80% less, for example.

Now we need to set up a proportion to solve the problem.

20% of the 10

20/100 = x/10

Cross multiply

20 x 10 = 200

200/100 = 2

He is currently reading 2 pages per night

Thus, the number of pages is 2.

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Answer: 4

This problem requires basic division. If the restaurant divided 4/5 kg of butter with 1/5 kg on each dish, you would need to compute 4/5 divided by 1/5.

4/5 ÷ 1/5

Using the "KFC" method, or Keep, Change, Flip, you would keep the first number (in this case, 4/5), change the division sign, and flip the fraction to 5/1, or 5. We now have this:

4/5 x 5

To compute this equation, you must multiply the numerators of both of the numbers together. In this case, you would compute (4x5)/5, resulting with 20/5, or 4.

You can check this answer by re-multiplying the numbers together. 1/5 kg of butter per dish, multiplied by the total amount of dishes, 4, you would result in the original 4/5 kg of butter.

Hope this helps!

Answer:

\(\Huge \boxed{{x=-1\pm \sqrt{7}}}\)

Step-by-step explanation:

x² + 2x = 6

Subtract both sides by 6.

x² + 2x - 6 = 0

ax²+bx+c=0

a=1, b=2, and c=-6

We can apply the quadratic formula.

\(\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Plug in the values.

\(\displaystyle x=\frac{-2\pm\sqrt{2^2-4(1)(-6)}}{2(1)}\)

Evaluate.

\(\displaystyle x=\frac{-2\pm\sqrt{4-(-24)}}{2}\)

\(\displaystyle x=\frac{-2\pm\sqrt{28}}{2}\)

\(\displaystyle x=\frac{-2\pm 2\sqrt{7}}{2}=-1 \pm \sqrt{7}\)

Answer: Edmentum and Plato

Step-by-step explanation:

Answer:

Step-by-step explanation:

volume = 1/3 π r² h

where h = 15 yd.

           r = 5 yd.

plugin values into the equation:

volume = 1/3 π r² h

            = 1/3 * π * 5² * 15

            = 392.7 yd³

Answer:

A. 392•8yd^3

Step-by-step explanation:

Answer:

110

Step-by-step explanation:

100% of 110 means all of 110, which is just 110.

Are you sure you didn't make a typo here because I'm pretty sure this wouldn't be given on a homework. Just wondering.

If we assume that the first card drawn is green and it is replaced before the second draw, then the probability of drawing two green cards in a row is 12/51, or approximately 0.235.

If we assume that the first card drawn is green and it is replaced before the second draw, then we can say that each draw is independent of the other, and the probability of drawing a green card on each draw is the same.

Let's assume that the deck of cards contains 52 cards, with 13 green cards. Since we know that the first card drawn is green, there are now 51 cards left in the deck, with 12 green cards.

The probability of drawing a green card on the second draw is 12/51, since there are 12 green cards left in the deck out of a total of 51 cards.

To find the probability of drawing two green cards in a row, we need to multiply the probability of drawing a green card on the first draw (which we assumed to be 1 since we know the first card is green) by the probability of drawing a green card on the second draw:

P(drawing two green cards) = 1 x 12/51

Simplifying this expression, we get:

P(drawing two green cards) = 12/51

Therefore, the probability of drawing two green cards is approximately 0.235.

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Answer:

9 1/3

Step-by-step explanation:

4 2/3 ÷ 2/3

=14/3 ÷ 2/4

=14/3 · 4/2

=28/3

=9 1/3

Answer:

number a should be half of 82 which is 41

for question b is two times 26 which is 52

Answer:

1.81 inches

Step-by-step explanation:

Given that,

The circumference of the largest orange in a bag is \(9\dfrac{5}{8}\ \text{inches}\) and that of smallest orange is \(7\dfrac{13}{16}\ \text{inches}\).

Difference = largest orange - smallest orange

= \(9\dfrac{5}{8}-7\dfrac{13}{16}\\\\=\dfrac{77}{8}-\dfrac{125}{16}\\\\=\dfrac{29}{16}\\\\=1.81\ \text{inches}\)

So,  difference of the circumferences of the smallest orange and the largest orange is 1.81 inches

Answer:

No it is not since there is 15 defectice parts in 2machines and there is 8 broken parts in the one machine

Hope This Helps!!!

Answer:

Step-by-step explanation:

The reading game equation is 3x + 5. That means that every day the game is for sale he will make $3. The math game is parabolic and doesn't have a slope for which to make the same statement about the amount of money made per day. Where they intersect is where the revenue for each will be the same. On the x axis we have the number of days and on the y axis we have the number of dollars. Solving them algebraically:

\(2x^2+8x+2=3x+5\) and get everything on one side and set it equal to 0:

\(2x^2+5x-3=0\) and factor that however you have learned to factor that quadratic to get:

x = 1/2, -3

The x value indicates the number of days that it would take for the revenue for the games to be the same. Since time can never be negative, we discount the value of -3 and say that it would take 1/2 of a day for the revenue for the games to be the same. As far as the graph goes, I attached a pic below. The red line is the reading game graph and the blue line is the math game parabola. We only need the first quadrant when we graph something like this because, again, days can never be negative so quadrant 2 and 3 are out where x is negative; likewise, the number of dollars will never be negative either, so quadrants 3 and 4 are out. Where those 2 graphs intersect is the number of days that the revenues are the same.

The surface integral in terms of ρ and θ ∫∫S.((6y - 5)e^(x^2))

To evaluate ∬s.curl F•nds using Stokes' Theorem, we first need to find the curl of the vector field F and then compute the surface integral over the given surface S.

Given vector field F = (6yz)i + (5x)j + (yz(e^(x^2)))k, let's find its curl:

∇ × F = ∂/∂x (yz(e^(x^2))) - ∂/∂y (5x) + ∂/∂z (6yz)

Taking the partial derivatives, we get:

∇ × F = (0 - 0) i + (0 - 0) j + (6y - 5)e^(x^2)

Now, let's parametrize the surface S, which is the portion of the paraboloid z = (1/4)x^2 + y^2 for 0 ≤ z ≤ 4. We can use cylindrical coordinates for this parametrization:

r(θ, ρ) = ρcos(θ)i + ρsin(θ)j + ((1/4)(ρcos(θ))^2 + (ρsin(θ))^2)k

where 0 ≤ θ ≤ 2π and 0 ≤ ρ ≤ 2.

Next, we need to find the normal vector n to the surface S. Since S is oriented upward, the normal vector points in the positive z-direction. We can normalize this vector to have unit length:

n = (∂r/∂θ) × (∂r/∂ρ)

Calculating the partial derivatives and taking the cross product, we have:

∂r/∂θ = -ρsin(θ)i + ρcos(θ)j

∂r/∂ρ = cos(θ)i + sin(θ)j + (1/2)(ρcos(θ))k

∂r/∂θ × ∂r/∂ρ = (-ρsin(θ)i + ρcos(θ)j) × (cos(θ)i + sin(θ)j + (1/2)(ρcos(θ))k)

Expanding the cross product, we get:

∂r/∂θ × ∂r/∂ρ = (ρcos(θ)(1/2)(ρcos(θ)) - (1/2)(ρcos(θ))(-ρsin(θ)))i

+ ((1/2)(ρcos(θ))sin(θ) - ρsin(θ)(1/2)(ρcos(θ)))j

+ (-ρsin(θ)cos(θ) + ρsin(θ)cos(θ))k

Simplifying further:

∂r/∂θ × ∂r/∂ρ = ρ^2cos(θ)i + ρ^2sin(θ)j

Now, we can calculate the surface integral using Stokes' Theorem:

∬s.curl F•nds = ∮c.F•dr

= ∫∫S.((∇ × F)•n) dS

Substituting the values we obtained earlier:

∫∫S.((∇ × F)•n) dS = ∫∫S.((6y - 5)e^(x^2))•(ρ^2cos(θ)i + ρ^2sin(θ)j) dS

We can now rewrite the surface integral in terms of ρ and θ:

∫∫S.((6y - 5)e^(x^2))

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Given:

Logarithmic properties:

Find: Product rule, Quotient rule, Power rule.

Sol:.

(1)

Product rule:

(2)

Quotient rule:

(3)

Power rule:

Step-by-step explanation:

Distance ran by Philip=438 miles

Distance ran by Michael=158 miles

Distance Philip run farther than Michael=(Distance ran by Philip-Distance ran by Michael)

438 miles-138miles

=280miles

Hope it helps you

ANSWER:

The 10th percentile: 27.4 pounds

The 75th percentile: 47 pounds

EXPLANATION:

Given:

42, 46, 31, 45, 49, 37, 47, 25, 50, 30, 48, 43, 35, 39, 29

To find:

The 10th and 75th percentiles

Step-by-step solution:

Step 1: Arrange the data in ascending order

25, 29, 30, 31, 35, 37, 39, 42, 43, 45, 46, 47, 48, 49, 50

Step 2: Use the percentile rank formula to determine the 10th percentile;

where;

p = the percentile

n = total number of items in the data set

where p = 10 and n = 15, we'll have;

Since the rank is not an integer, we'll go ahead and use the interpolation method as seen below;

Therefore, the 10th percentile is 27.4 pounds

Where p = 75 and n = 15, we'll have;

Since the rank is an integer, we can see that the 75th percentile is 47 pounds

Answer:

i need to see the table lol do you have a pic?

Step-by-step explanation: