At initial temperature of 70° C, the water will expand by twice as much as it expands at 30°C initial temperature.
Thermal Expansion :
The length, width, height, or volume of the body alter when the temperature has an effect on it. In solids, where atoms are closely packed, thermal expansion is clearly visible. Please explain thermal expansion and the formulas for linear, area, and volume expansion in this article. For physics, The term "thermal expansion" refers to a material's change in length, width, height, or volume when its temperature is raised or lowered. Solids exhibit very noticeable thermal expansion due to their closely packed atoms. There are numerous uses for thermal expansion of solids in daily life.
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specific heat capicity of water is 4200Jkg-1 C-1 . what its meaning .
The specific heat capacity of water is 4,200 Joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C. Lead will warm up and cool down faster because it doesn't take much energy to change its temperature.
Un objeto pequeño que tiene una carga dd -5x10^-9C experimenta una fuerza hacia debajo de 20x10^-9 N cuando se coloca en determinado punto un campo electrico ¿cual es el campo de dicho punto?
El signo negativo indica que el campo eléctrico apunta en la dirección opuesta a la fuerza experimentada por la carga. Por lo tanto, el campo eléctrico en ese punto es de -4 N/C.
F = qE
En este caso, la carga es de -5x10^-9 C y la fuerza es de 20x10^-9 N. Por lo tanto, podemos despejar el valor del campo eléctrico:
E = F/q = (20x10^-9 N) / (-5x10^-9 C) = -4 N/C
A charge is a fundamental property of matter that describes the amount of electric energy that a particle possesses. It is a scalar quantity, meaning it has only magnitude and no direction. The charge can be either positive or negative and is measured in Coulombs (C).
Charged particles can interact with each other through electromagnetic force, which is one of the four fundamental forces of nature. Like charges repel each other while opposite charges attract. Electric fields are generated by charged particles, and the force they exert on other charged particles is proportional to the magnitude of their charges.
A charge is conserved in isolated systems, meaning that the total amount of charge in a closed system cannot be created or destroyed, but can only be transferred from one object to another.
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A 5kg box rests on a table. a 3 kg box rests on top of the 5 kg box. what is the normal force from the table?
a. 19.6 n
b. 29.4 n
c. 49 n
d. 78.4 n
==> The total mass resting on the table is (5 kg + 3 kg) = 8 kg.
==> The total weight of that mass is (8 kg) x (9.8 m/s) = 78.4 newtons
==> The boxes are stacked. So the table doesn't know if the weight on it is coming from one box, 2 boxes, 3 boxes, or 100 boxes in a stack. The table only knows that there is a downward force of 78.4 newtons on it.
==> The table stands in a Physics classroom, and it soaks up everything it hears there. It knows that every action produces an equal and opposite reaction, and that forces always occur in pairs.
Ever since the day it was only a pile of lumber out behind the hardware store in the rain, the table has known that in order to maintain the good reputation of tables all over the world, it must resist the weight of anything placed upon it with an identical upward force. This is the normal thing for all good tables to do, up to the ultimate structural limit of their materials and construction, and it is known as the "normal force".
So the table in your question provides a normal force of 78.4 newtons. (d)
What quantities appear in the first law of thermodynamics?A. force, mass, accelerationB. inertia, torque, angular momentumC. work, heat, thermal energyD. work, heat, entropy
The correct answer is C. work.
The correct answer is C. work, heat, and thermal energy appear in the first law of thermodynamics. The first law of thermodynamics, also known as the law of conservation of energy, states that energy cannot be created or destroyed but can only be transferred or converted from one form to another. In thermodynamics, the term "work" refers to the energy transferred to or from a system as a result of a force acting on it, while "heat" refers to the Due to a temperature difference, energy is transmitted between a system and its surroundings. "Thermal energy" refers to the internal energy of a system, which is the sum of its kinetic and potential energies at the molecular level. Therefore, the first law of thermodynamics relates the changes in the internal energy of a system to the energy transferred to or from the system as work or heat
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Is a computer an open or closed system
Answer:
OPEN
Explanation:
Answer:
a computer is a open system
Una carga de 4 uC penetra perpendicularmente en un campo magnetico de 0.4 T con una velocidad de 7.5x10 4 m/s. Calcular la fuerza que recibe la carga
Answer:
F_B = 0.12N
Explanation:
In order to calculate the magnetic force on the charge, you use the following formula:
\(\vec{F_B}=q\vec{v}\ X\ \vec{B}\) (1)
q: charge of the particle = 4μC = 4*10^-6 C
v: speed of the charge = 7.5*10^4 m/s
B: magnitude of the magnetic field = 0.4T
The direction of the motion of the charge is perpendicular to the direction of the magnetic field. Then, the magnitude of the magnetic force is:
\(F_B=qvBsin90\°\\\\F_B=(4*10^{-6}C)(7.5*10^4 m/s)(0.4T)=0.12N\)
The magnetic force on the charge is 0.12N
A 500-g cart moving at 2. 0 m/s on an air track elastically strikes a 1,000-g cart at rest.
What are the resulting velocities of the two carts?
The resulting velocity of the 500-g cart is 0 m/s. The resulting velocity of the 1000-g cart is 1 m/s.
A car applies a force of 36. 8 newtons for a 668-meter loop; what was the work done?.
The value of the work that was done on the car is 24.6 J.
How to calculate how much the work on the car was done?Work is an energy that move from or to one object into another object that might make the object have the displacement, or we can say work is equal to force multiply with displacement in meters. In formula form, it will be written as W = F x s. As per data given F = 36.8 N and s = 668 m. The work will be:
W = F x s
W = 36.8 x 668
W = 24,582J
Let round the work value. So, the work value will be 24.6 J
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a) When we blow air with our mouth narrow open, we feel the air cool. When the mouth
is made wide open, we feel the air warm. What are the thermodynamic processes involved in these processes? Explain. [2]
As the air is compressed, the work done on the air causes its temperature to increase.
What is Thermodynamic Process?
A thermodynamic process is a physical change that occurs in a system as it exchanges heat and/or work with its surroundings. It involves a change in one or more thermodynamic variables, such as temperature, pressure, volume, or entropy. There are four main types of thermodynamic processes: isothermal, adiabatic, isobaric, and isochoric.
When we blow air with our mouth narrow open, we feel the air cool because of the adiabatic expansion of the air. Adiabatic expansion is a thermodynamic process in which the air expands rapidly without losing or gaining any heat to or from the surroundings. As the air expands, it does work against the pressure of the surrounding atmosphere, and this work causes the temperature of the air to decrease. This is known as the Joule-Thomson effect.
On the other hand, when the mouth is made wide open, we feel the air warm because of the adiabatic compression of the air. Adiabatic compression is a thermodynamic process in which the air is compressed rapidly without losing or gaining any heat to or from the surroundings.
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Pls help
The Q : Look at your recorded results and models for both the man and the boy. How close are the coefficients of friction for the sled on ice for two runs? How confident would you feel about specifying a coefficient of kinetic friction for this sled on this ice surface, based on these results? What other variables might impact this coefficient result?
Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:
The friction coefficients are man is0.8 and for the boy is0.98, the relationship between them is 0.82 The results are very accurate after the graphical analysis. The wind is a very important factor in the calculations that is not taken into account.Second law of Newton.
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body. In the attachment we can see a free body diagram which is a schematic of the forces without the details of the bodies.
N-W = 0
fr = ma
where N is the normal, W the weight of the body, fr the friction force, m the mass and a the acceleration
The friction force is a macroscopic representation of the interactions between the two surfaces, it is given by the expression
fr = μ N
where μ is the coefficient of friction between the two surfaces.
We substitute
μ mg = m a
a = μ g
Kinematics and graphic analysis.
Kinematics study the movement of bodies, looking for relationships between position, speed and acceleration.
v= v₀ – at t
In this case they give tables and graphs with the values of time and speed, where we can see that the relationship is a straight line that has as equation
y = ax +b
Where y is the dependent variable, x is the independent variable, a is the slope, and b is the cutoff point.
If we relate the two equations:
The independent variable x → time. The dependent variable y → speed. The cutoff point b → the initial velocity. The slope (a) is:a = mug
μ = \(\frac{a}{g}\)
Using linear regression the slope and cutoff point is:
The man.
The slope is a = -0.8 m/s² and the cut-off point b= 4.86 m/s.
Let's calculate the coefficient of friction.
μ = \(\frac{0.8}{9.8}\)
μ = 0.082
The child.
The slope is a = -0.98 m/s² and the cut-off point b= 4.72 m/s.
We calculate the coefficient of friction.
μ = \(\frac{0.98}{9.8}\)
μ = 0.1
The relationship between the two coefficients of friction is
\(\frac{\mu_{man} }{\mu_{boy}} = \frac{0.082}{0.1}\)
\(\frac{\mu_{man}}{\mu_{boy}} = 0.82\)
The results are very exact since there are values of several points in the route and the graphical analysis gives the best possible value for all the points.
There are some variables not taken into account, one of the most important is friction with the wind and wind speed.
In conclusion using Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:
The friction coefficients are man is0.8 and for the boy is0.98, the relationship between them is 0.82 The results are very accurate after the graphical analysis. The wind is a very important factor in the calculations that is not taken into account.
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What is matrix and what is its composition?
The matrix is the set of extracellular materials that will form a certain tissue. Through this there will be a physiological integration of the cells.
What is matrix and what is it's composition?In the matrix there will be different macromolecules, mainly collagen, enzymes, glycoproteins, among others which will give support to the cells that will be immersed in the matrix. It will also be involved in the process of cell multiplication and cell movement, since it will allow communication between the different cells to coordinate their cell functions.
The extracellular matrix is going to be composed, broadly speaking, of two components: interstitial matrix and the basal membrane. The interstitial matrix is one that will be formed by polysaccharides and fibrous proteins that gives it the characteristic to be able to cushion the compressions to which it may be subjected.
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People should be more concerned about the global water budget than the local water budget.
True
Answer:
true
Explanation:
because global helps local
a jogger starts at a position of 4.0 m and moves forwards at a constant rate ending at a position of 12.0 m at a time 4.0 s later. what is the speed of the jogger?
The speed of the jogger is 2 m/s.
Speed is also known as velocity. It is the rate by which any object changes its position, from one place to another in a particular time.
Speed is a scalar quantity as it has only direction and no magnitude.
Speed can be calculated by the formula:
Speed = total distance covered/ total time taken
Given,
Start point = 4 m
End point = 12 m
Initial time = 0 seconds
Final time = 4 seconds
To find the speed of the jogger,
Total distance covered = 12 - 9 = 8 m
Total time taken = 4 - 0 = 4 seconds
Putting the values in the formula:
Speed = 8/4 = 2 m/s.
Therefore, the speed of the jogger is 2 m/s.
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Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy?
Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy would be 812.5 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
As given in the problem we have to calculate the Kinetic energy of the Jemima,
Kinetic energy = 1/2 ×mass×velocity²
=0.5×65×5²
=812.5 Joules
Thus, the kinetic energy of the Jemima would be 812.5 Joules.
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A constant horizontal F force began to act on the initially immovable body placed on a horizontal surface. After t time the force ceased to act, and after time 3t from the start of the movement the body stopped. Find the coefficient of friction between the body and the surface if the body mass is m.
Answer:
The coefficient of friction is (F/(19.6·m)
Explanation:
The given parameters are;
The force applied to the immovable body = F
The time duration the force acts = t
The time the body spends in motion = 3·t
The acceleration due to gravity, g = 9.8 m/s²
From Newton's second law of motion, we have;
The impulse of the force = F × t = m × Δv₁
Where;
Δv₁ = v₁ - 0 = v₁
The impulse applied by the force of friction, \(F_f\) is \(F_f\) × (3·t - t) = \(F_f\) × (2·t)
Given that the motion of the object is stopped by the frictional force, we have;
The impulse due to the frictional force = Momentum change = m × Δv₂ = \(F_f\) × (2·t)
Where;
Δv₂ = v₂ - 0 = v₂
Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to act, v₁, we have;
m × Δv₂ = \(F_f\) × (2·t) = m × Δv₁ = F × t
∴ \(F_f\) × (2·t) = F × t
\(F_f\) = F × t/(2·t) = F/2
The coefficient of dynamic friction, \(\mu _k\) = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)
\(\mu _k\) = (F/(19.6·m)
The coefficient of friction, \(\mu _k\) = (F/(19.6·m)
the nurse prepares a parenteral medication for a patient. for which reason should the nurse insert the needle at a 45 degree angle
The nurse should insert the needle at a 45-degree angle to ensure proper medication administration into the subcutaneous tissue.
When administering a subcutaneous injection, the nurse inserts the needle at a 45-degree angle to ensure proper medication administration. This angle allows for even distribution of the medication in the subcutaneous tissue, facilitating absorption and therapeutic effect. The subcutaneous tissue has a rich blood supply, and the medication is absorbed through capillaries in this layer. The 45-degree angle ensures that the medication reaches the appropriate depth without hitting muscle or bone. It also balances effective delivery with patient comfort, minimizing pain and tissue trauma. Inserting the needle at a steeper angle could cause the medication to be delivered too deeply, potentially causing discomfort or injury. Proper injection techniques, including selecting the correct needle length and angle, are crucial for safe and accurate administration of subcutaneous medications.
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F i weigh 741 n on earth at a place where g = 9.80 m/s2 and 5320 n on the surface of another planet, what is the acceleration due to gravity on that planet?
The weight of an object is given by the formula W = mg, where W is the weight, m is the mass of the object, and g is the acceleration due to gravity. In this case, the weight on Earth is 741 N and the acceleration due to gravity on Earth is 9.80 m/s^2. The acceleration due to gravity on the other planet is approximately 70.43 m/s^2.
By rearranging the formula, we can solve for the mass of the object on Earth: m = W/g = 741 N / 9.80 m/s^2 = 75.51 kg.
Now, let's consider the weight of the object on the surface of the other planet. We know the weight is 5320 N, but we don't know the acceleration due to gravity on that planet. Let's call it g2.
Using the same formula as before, we can solve for the mass of the object on the other planet: m = W2 / g2 = 75.51 kg.
We can then rearrange the formula to solve for g2: g2 = W2 / m = 5320 N / 75.51 kg.
Calculating the value, the acceleration due to gravity on the other planet is approximately 70.43 m/s^2.
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If the mass of a 1.8 g paperclip was able to be completely converted to energy, how much energy would you obtain?
Answer:
\(E=1.62\times 10^{14}\ J\)
Explanation:
Given that,
The mass of the paperclip, m = 1.8 g = 0.0018 kg
We need to find the energy obtained. The relation between mass and energy is given by :
\(E=mc^2\)
Where
c is the speed of light
So,
\(E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J\)
So, the energy obtained is \(1.62\times 10^{14}\ J\).
this is a 3 part question6) (a) Your heart beats with a frequency of 1.45 Hz. How many beats occur in a minute? (b) If the frequency of your heartbeat increases, will the number of beats in a minute increase, decrease, or stay the same? (c) How many beats occur in a minute if the frequency increases to 1.55 Hz?
Given,
The initial frequency of the heartbeat, f₁=1.45 Hz
The increased heartbeat, f₂=1.55 Hz
The frequency of the heartbeat can be described as the number of occurence of the heartbeat per second. That is every second, the heart beats 1.45 times.
(a)
Thus for a minute, the number of the heartbeats is,
\(\begin{gathered} N_1=f_1\times60 \\ =1.45\times60=87 \end{gathered}\)Thus 87 beats occur for a minute.
(b)The increase in the frequency of the heartbeat implies the increase in the number of the heartbeat for every second. And hence the beats in a minute increase when the frequency of the heartbeat increases.
(c)
The number of the beats per minute after the increase of the frequency is,
\(\begin{gathered} N_2=f_2\times60 \\ =1.55\times60 \\ =93 \end{gathered}\)Thus after the increase in the frequency, 93 beats occur in a minute.
. Using Thevenin's theorem, determine the current through the load Ru in Figure 19-53 0. Figure 19-53 R1 R2 R3 22 kQ 22 kQ 22 kQ RL 100 kQ V C1 C2 S 3240 V 0.047 JF 0.047 MF f = 100 Hz
The current through the load resistor Ru is approximately 332.61 mA.
To determine the current through the load resistor Ru using Thevenin's theorem, we need to find the Thevenin equivalent circuit of the given circuit. The Thevenin equivalent circuit consists of a Thevenin voltage source and a Thevenin resistance.
To find the Thevenin voltage source (Vth), we need to determine the open-circuit voltage across the load resistor Ru.
First, we can simplify the circuit by combining resistors R1, R2, and R3 in parallel. The equivalent resistance (Req) of these three resistors can be calculated as:
1/Req = 1/R1 + 1/R2 + 1/R3
1/Req = 1/22kΩ + 1/22kΩ + 1/22kΩ
1/Req = 3/22kΩ
Req = 22kΩ
Next, we can calculate the current flowing through the circuit using Ohm's law:
I = V/R = 3240V / Req
Now, we can find the voltage across the load resistor Ru by multiplying the current (I) with the resistance value of Ru:
Voc = I * Ru
The Thevenin voltage source (Vth) is equal to the open-circuit voltage (Voc) we just calculated.
To find the Thevenin resistance (Rth), we remove the load resistor Ru from the circuit and calculate the total resistance seen from its terminals.
Rth = Req
Now that we have determined the Thevenin voltage source (Vth) and the Thevenin resistance (Rth), we can proceed to calculate the current through the load resistor Ru using the Thevenin equivalent circuit
I_Load = Vth / (Rth + RL)
Substituting the given values, we have:
I_Load = Vth / (Rth + RL)
I_Load = Voc / (Req + RL)
I_Load = (I * Ru) / (Req + RL)
I_Load = (3240V / Req) * (Ru / (Req + RL))
I_Load = (3240V / (22kΩ/3)) * (Ru / ((22kΩ/3) + 100kΩ))
Now, plug in the values for Ru, Req, and RL, and calculate the current.
I_Load = (3240V / (22kΩ/3)) * (100kΩ / ((22kΩ/3) + 100kΩ))
I_Load = (3240V / (22/3)) * (100kΩ / ((22/3) + 100))
I_Load = (3240V / (22/3)) * (100kΩ / (736/3))
I_Load = (3240V * 300 / 22) * (1 / (736/3))
I_Load = (3240V * 300 / 22) * (3 / 736)
I_Load = (3240V * 300 * 3) / (22 * 736)
I_Load ≈ 332.61 mA
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You are holding a siren, and you hear a frequency of 1200 Hz from it when you are standing still. You now move directly toward a cliff wall at a speed of 1/5 the speed of sound. What frequency do you hear as an echo from the cliff wall?
Answer:
\(F_w=1000Hz\)
Explanation:
From the question we are told that:
Frequency \(F=1200\)
Speed \(V_w= \frac{1}{5}*343=>68.6m/s\)
Where speed of sound \(V_s=343m/s\)
Generally the equation for frequency that echo from the cliff wall is mathematically given by
\(F_w=\frac{V_s-V_0}{Vs+V_w}*F\)
\(F_w=\frac{343-0}{343+68.6}*1200\)
\(F_w=1000Hz\)
A motor and gearbox system is used to raise a load from the ground to the roof of a building site. The load weighs 100kg and the motor runs from a 110 volt supply and draws a current of 15 amps. If the roof is 25m above the ground, calculate:
(a) The potential energy of the load when it has been raised
(b) Theamountofelectricalenergyusedinthattime
(c) The time taken to raise the load
(d) Theaveragespeedatwhichtheloadisbeingraised
(e) Thekineticenergyoftheloadwhenitisbeingraised.
Answer:
Explanation:
Given:
m = 100 kg
U = 110 W
I = 15 A
H = 25 m
g = 10 m/s²
__________
Wp - ?
A - ?
t - ?
V - ?
Wk - ?
(a) Potential energy of the load when it is lifted
Wp = m·g·H = 100·10·25 = 25 000 J
(b) The amountofelectri calenergyusedinth at time
E = I·U = 15·110 = 1550 J·s
c) The time taken to raise the load:
t = Wp / E = 25 000 / 1550 = 16 s
(d) The average speed at which the load is being raised
V = H / t = 25 / 16 ≈ 1.6 m/s
(e) The kinetic energy of the load when it is being raised.
Wk = m·V²/2 = 100·1.6² / 2 = 128 J
schedule to graph each point of the supply curve. Connect each point with line to
a build a supply curve.
Price of bread per loaf
Quantity supplied
$4.50
$5.00
$5.50
$6.00
9887
85
$6.50
In which direction does the supply curve head? How does this show the law of
supply? (1 point)
The upward slope of the supply curve indicates that suppliers are willing to produce and supply a larger quantity of bread at higher prices, demonstrating the positive relationship between price and quantity supplied.
To graph the supply curve, we need to plot the given points and connect them with a line. The points we have are:
Price of bread per loaf: $4.50, $5.00, $5.50, $6.00, $6.50
Quantity supplied: 9887, 85
We'll use a Cartesian coordinate system with the price on the y-axis and the quantity supplied on the x-axis.
Points to plot:
($4.50, 9887)
($5.00, 85)
($5.50, 85)
($6.00, 85)
($6.50, 85)
Once we plot these points, we can connect them with a line to build the supply curve. The resulting supply curve will slope upwards from left to right.
The direction of the supply curve heading upwards from left to right shows the positive relationship between the price of bread and the quantity supplied.
According to the law of supply, as the price of a product increases, the quantity supplied also increases, ceteris paribus (assuming other factors remain constant). This is reflected in the upward slope of the supply curve.
In this case, as the price of bread per loaf increases from $4.50 to $6.50, the quantity supplied increases from 9887 loaves to 85 loaves. This relationship between price and quantity supplied is consistent with the law of supply.
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On a curved roadway of radius 95m, the speed limit is 12 m/s. What should the coefficient of static friction be between the tires and the road for the car to safely navigate the curve at the posted speed?
Please please help.
The coefficient of static friction between the tires and the road is 0.16.
What is the coefficient of kinetic friction?The coefficient of static friction between the tires and the road for the car to safely navigate the curve at the posted speed is calculated as follows;
Static friction = centripetal force
μmg = mv²/r
μ = ( v² ) / ( rg)
where;
μ is the coefficient of static frictiong is acceleration due to gravityr is the radius of the curved pathv is the maximum speed of car on the pathThe coefficient of static friction between the tires and the road is calculated as follows;
μ = ( 12² ) / ( 95 x 9.8)
μ = 0.16
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When there's a temperature difference between two objects, heat is transferred from the hotter object to the cooler one. What is the name for the state reached when they are both at the same temperature?
Answer:
The state when the two objects have reached the same temperature is known as thermal equilibrium.
A 100 kg box is on an incline of 60°
What is the frictional force if the coefficient of friction is .2?
If the coefficient of friction is.2, the frictional force is 100 N.
The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.
F = N is the equation for frictional force. Let's use the 2-kg block of wood that is resting on a table to be pushed from rest as an example. The static friction coefficient is taken into account in this situation. The static coefficient of wood is 0.5.
Calculation:F = μN
F = 2 × 100 ×cos60°
F = 200 × 1/2
F = 100 N
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In physics what do we use machines for
Answer:
hope it helps for you
Explanation:
A machine is an object or mechanical device that receives an input amount of work and transfers the energy to an output amount of work. For an ideal machine, the input work and output work are always the same. The six common simple machines are the lever, wheel and axle, pulley, inclined plane, wedge, and screw.
How were you able to increase the amount of potential the ball had?
Answer:
The potential energy can be increased by increasing the mass of the object, by varying the distance between the two objects, decreasing the kinetic energy of the molecules, by freezing, by compressing or stretching, and so on.
Explanation:
Hope this helped !
A 1,200-kilogram car traveling at 10. meters per second hits a tree and is brought to rest in 0.10 second. What is the magnitude of the average force acting on the car to bring it to rest? angle of 15.0° above the horizontal. What are the horizontal (vx) and vertical (vy) components of this velocity? the law of universal gravitation?
(a) The magnitude of the average force acting on the car to bring it to rest is 120,000 N.
(b) The horizontal (vx) and vertical (vy) components of this velocity is 9.66 m/s and 2.59 m/s respectively.
What is the average force acting on the car?
The magnitude of the force acting on the car is calculated as follows;
F = mv / t
where;
m is the mass of the carv is the speed of the cart is the time of motion of the carF = ( 1200 kg x 10 m/s ) / ( 0.1 s )
F = 120,000 N
The horizontal and vertical component of the velocity of the car is calculated as follows;
Vx = V cosθ
Vy = V sinθ
where;
θ is the direction of the speedVx = 10 m/s x cos (15) = 9.66 m/s
Vy = 10 m/s x sin (15) = 2.59 m/s
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