The Anderson family is preparing for a family reunion they think they will need 18 juice boxes for every six children who attend how many juice boxes will they need if they are expecting 28 children

Answer:

combination!!

Answer:

D

Step-by-step explanation:

(x+7)²+(y-12)²=9

____________

Answer:

\(\text{D. }(x+7)^2+(y-12)^2=9\)

Step-by-step explanation:

The equation of a circle with radius \(r\) and center \((h, k)\) is given by:

\((x-h)^2+(y-k)^2=r^2\)

Answer:

x = 19 degrees

Step-by-step explanation:

180 - 114 = 66

180 - 66 = 114

Other triangle angle is 114 degrees

114 + 47 = 161

180 - 161 = 19

x = 19 degrees

The solution of the inequality 2(4x - 3) ≥ -3(3x) + 5x is true for all x such that its a real number bigger or equal to 0.5 (Option A: x ≥ 0.5)

If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality. Set of such values is called solution set to the considered equation or inequality.

The considered inequality is:

\(2(4x - 3) \geq -3(3x) + 5x\)

Simplifying its both sides, we get:

\(2(4x - 3) \geq -3(3x) + 5x\\8x-6\geq -9x + 5x\\8x-6 \geq -4x\)

Adding 4x on both the sides, we get:

\(8x-6+4x \geq -4x + 4x\\(8+4)x - 6 \geq 0\\12x -6 \geq 0\\\)

Adding 6 on both the sides, and dividing by 12, we get:

\(12x-6 +6 \geq 0+6\\12x \geq 6\\12x/12 \geq 6/12\\x \geq 0.5\)

(some operations like addition, subtraction, multiplication by positive real number or division by positive real number keeps the inequality relation unaltered. With the use of such operations, here we tried to get x on one side, and constants on other side).

Thus, the considered inequality is true for all the values of x which are real numbers bigger or equal to 0.5 (Option A: x ≥ 0.5)

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Answer:

12)  B.  6.1 km

13)  B.  20 cm

Step-by-step explanation:

The given diagram shows a village "V", which is 8 km on a bearing of 040° from a point O.  

The scenario is modelled as a right triangle ONV, where m∠N = 90°, m∠O = 40°, and the hypotenuse OV is 8 km.

To calculate how far the village "V" is north of O, we need to find the length of side ON, which is the side adjacent to angle O.  

To find ON, use the cosine trigonometric ratio.

\(\boxed{\begin{minipage}{9 cm}\underline{Cosine trigonometric ratio} \\\\$\sf \cos(\theta)=\dfrac{A}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

Therefore:

\(\cos 40^{\circ}=\dfrac{ON}{OV}\)

\(\cos 40^{\circ}=\dfrac{ON}{8}\)

\(ON=8\cos 40^{\circ}\)

We are given cos 40° = 0.7660. Therefore, substitute this into the equation and solve for ON:

\(ON = 8 \cdot 0.7660\)

\(ON= 6.128\)

\(ON= 6.1 \; \sf km\; (nearest\;tenth)\)

Therefore, the village "V" is 6.1 km north of O.

\(\hrulefill\)

The side lengths of a rhombus are equal in length.

The diagonals of a rhombus always bisect each other at an angle of 90°.

Therefore, the two diagonals of a rhombus create 4 congruent right triangles, where each leg is half the length of each diagonal, and the hypotenuse is the side length of the rhombus.

Given the diagonals of a rhombus are 8 cm and 6 cm, the legs of each right triangle are 4 cm and 3 cm. To find the hypotenuse (side length of the rhombus), use Pythagoras Theorem:

\(\begin{aligned}a^2+b^2&=c^2\\4^2+3^2&=c^2\\16+9&=c^2\\25&=c^2\\c&=5\end{aligned}\)

Therefore, the side length of the rhombus is 5 cm.

The perimeter of a two-dimensional shape is the distance all the way around the outside. Therefore, the perimeter of a rhombus is four times the length of one side.

\(\textsf{Perimeter}=4 \cdot 5=20\;\sf cm\)

Therefore, the perimeter of the rhombus is 20 cm.

Answer:

1) Let's use a system of linear equations to solve this problem. Let x be the cost of one adult ticket and y be the cost of one child ticket.

For the Cook family:

2x + 4y = 550

For the Ross family:

2x + 8y + 1z = 1004.50

(where z is the cost of one senior ticket)

We need one more equation to solve for the three variables. Let's assume that the cost of a senior ticket is the same as that of a child ticket:

z = y

Substitute z = y into the equation for the Ross family:

2x + 8y + y = 1004.50

2x + 9y = 1004.50

Now we have a system of two equations with two variables:

2x + 4y = 550

2x + 9y = 1004.50

Solve for x in the first equation:

2x = 550 - 4y

x = 275 - 2y

Substitute x = 275 - 2y into the second equation:

2(275 - 2y) + 9y = 1004.50

550 - 4y + 9y = 1004.50

5y = 454.50

y = 90.90

Substitute y = 90.90 into x = 275 - 2y:

x = 275 - 2(90.90) = 93.20

Therefore, one adult ticket costs $93.20 and one child/senior ticket costs $90.90.

For the Cook family:

2 adults + 4 children = $550

2($93.20) + 4($90.90) = $550.00

For the Ross family:

2 adults + 8 children + 1 senior = $1004.50

2($93.20) + 8($90.90) + 1($90.90) = $1004.50

2) To calculate the total admission cost for one day at Epcot center on the 8th grade trip, we need to know the number of adults that will accompany the students. Since the ratio of at least one adult for every 10 students is required, we can assume that there will be 5 adults (48 students divided by 10, rounded up to the nearest whole number) accompanying the 8th grade class.

Assuming that the same ticket prices apply for the 8th grade class as well, we can write the equation:

Total admission cost = (Number of students + Number of adults) x Cost per person

Total admission cost = (48 + 5) x Cost per person (5 adults are assumed to be accompanying the students)

Simplifying the equation, we get:

Total admission cost = 53 x Cost per person

To find the value of Cost per person, we can use the average of the costs for the Cook family and the Ross family, which is:

Average cost per person = (550.00 + 1,004.50) / (2 x 10) (total number of people in the Cook and Ross families is 10)

Average cost per person = $77.25

Substituting this value in the previous equation, we get:

Total admission cost = 53 x $77.25

Total admission cost = $4,100.25

Therefore, the total admission cost for one day at Epcot center on the 8th grade trip is $4,100.25.

Step-by-step explanation:

Answer:

the answer is the side length of ab and db

Answer: D on edge

Step-by-step explanation:

The given expression is,

10639/500+22

According to

The number of cows needed to satisfy the beef appetite would be 5263

With an average yield of 570 pounds (258.1 Kg.) of prepared beef per cow, we need to determine how many people can be fed from this amount. The number of people fed per cow can vary depending on various factors such as portion sizes and individual dietary preferences. Assuming a reasonable estimate, let's consider that one pound (0.45 Kg.) of prepared beef can feed about three people.

To find the number of cows needed to satisfy the beef appetite for New York City's population of approximately 9,000,000 people, we divide the population by the number of people fed by one cow. Thus, the calculation becomes 9,000,000 / (570 pounds x 3 people/pound).

After simplifying the equation, we get 9,000,000 / 1710 people, which equals approximately 5,263 cows. However, it's important to note that this is a rough estimate and does not consider factors such as variations in consumption patterns, distribution logistics, or other sources of meat supply. Additionally, individual dietary choices and preferences may result in different consumption rates. Therefore, this estimate serves as a general indication of the number of cows needed to satisfy the beef appetite for New York City's population.

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Answer:

-258

Step-by-step explanation:

It looks like the integral is

\(\displaystyle \int_0^1 \frac{2x - 8x^2}{1+4x} \, dx\)

Polynomial division yields

\(\dfrac{2x-8x^2}{1+4x} = -2x + 1 - \dfrac1{1+4x}\)

Now split up the integral as

\(\displaystyle \int_0^1 \left(-2x + 1 - \frac1{1+4x}\right) \, dx = \int_0^1 (1-2x) \, dx - \int_0^1 \frac{dx}{1+4x}\)

In the second integral, substitute \(u=1+4x\) and \(du=4\,dx\). Then \(x=0 \implies u=1\) and \(x=1 \implies u=5\), so

\(\displaystyle \int_0^1 \frac{dx}{1+4x} = \frac14 \int_1^5 \frac{du}u\)

and by the fundamental theorem of calculus, the integral we want evaluates to

\(\displaystyle \int_0^1 \left(-2x + 1 - \frac1{1+4x}\right) \, dx = \int_0^1 (1-2x) \, dx - \frac14 \int_1^5 \frac{du}u \\\\ = (x - x^2)\bigg|_{x=0}^{x=1} - \frac14 \ln|u| \bigg|_{u=1}^{u=5} \\\\ = \bigg((1 - 1^2) - (0 - 0^2)\bigg) - \frac14 (\ln(5) - \ln(1)) = \boxed{-\frac{\ln(5)}4}\)

When white paint is 4 quarts, then the blue paint is 6/5 quarts and when blue paint is 1 quarts, the white paint will be 10/3 quarts

The quantity of blue paint needed = \(1\frac{1}{2}\) quarts

Convert to simple fraction

\(1\frac{1}{2}\) quarts = 3/2 quarts

The quantity of white paint needed = 5 quarts

The quantity of blue paint and white paints are proportional

Then

y ∝ x

Y is the quantity of white paint and x is the blue paint

y = kx

5 = k (3/2)

k = 5 / (3/2)

k = 10/3

Then

The quantity of blue paint needed when 4 quarts of white paint

4 = (10/3)x

x = 4 / (10/3)

x = 6/5 quarts

The quantity of white paint needed when 1 quarts of blue paint

y = (10/3) × 1

y = 10/3 quarts

Hence, when white paint is 4 quarts, then the blue paint is 6/5 quarts and when blue paint is 1 quarts, the white paint will be 10/3 quarts

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The forecast for the next period using the following weights: 0.3, 2, 0.5 is Option d. 421.

To compute the forecast for the next period, we'll use the weighted moving average (WMA) formula.WMA formula:

WMA = W1Yt-1 + W2Yt-2 + ... + WnYt-n

Where, WMA is the weighted moving average

W1, W2, ..., Wn are the weights (must sum to 1)

Yt-n is the demand in the n-th period before the current period

As we know Month 1 – 381, Month 2-366, and Month 3 - 348.

Weights: 0.3, 2, 0.5

We'll compute the forecast for the next period (month 4) using the data:

WMA = W1Yt-1 + W2Yt-2 + W3Yt-3WMA

= 0.3(381) + 2(366) + 0.5(348)WMA

= 114.3 + 732 + 174WMA

= 1020.3

Therefore, the forecast for the next period is 1020.3, which rounds to 421. Hence, option d is correct.

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Answer:

\(-2\frac{2}{5}\)

Step-by-step explanation:

\(\frac{-4}{5} *\frac{3}{1}\) multiply across

\(\frac{-12}{5}\) turn into mixed number

\(-2\frac{2}{5}\)

Answer:

Forty-Five equals three x minus nine.

Step-by-step explanation:

You just kind of need to say it our loud and then write what you said. :)

Answer: Forty-five equals three x minus nine.

Step-by-step explanation: 45- forty- five

                                              = equals

                                              3x- three x

                                               - minus

                                               9- nine

Together it is 45= 3x-9 is Forty-five equals three x minus nine.

Answer:

Read the explanation

Step-by-step explanation:

look at the photo

If henry can  70 words in 5 minutes and that in 8 minutes he can type 112 words the rate of change is 14.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

Henry can type 70 words in 5 minutes and that in 8 minutes he can type 112 words.

m=112-70/8-5

=42/3

=14

Hence, the rate of change is 14.

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Answer:

True

Step-by-step explanation:

Hard to explain in writing

A figure which is formed by two rays or lines that shares a common endpoint is called an angle.

The value of each variable. For the circle, the dot represents the center.

A figure which is formed by two rays or lines that shares a common endpoint is called an angle.

An arc is one of the portions of a circle. It is basically a part of the circumference of a circle.

1. The measure of ∠d is;

∠d+ 117°= 180°

∠d= 180°-117°= 63°

The measure of the ∠d is 63°.

2. The measure of ∠c is,

∠c+ 99°= 180°

∠c =180°-99° =81°

The measure of the ∠c is 81 degrees.

3. The measure of arc a is,

The inscribed angle measures half that of the arc comprising;

119° = 1/2 (99+ arc a)
236 = (99+ arc a)
arc a = 230 - 99

The measure of the arc a is 131°.

4. The measure of arc b is,

The inscribed angle measures half that of the arc comprising;

81 = 1/2 (131 + arc b)
162 = (131 + arc b)
arc b = 162 - 131

arc b = 31

The measure of arc b is 31°.

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Answer:

√47

Step-by-step explanation:

First, let's try to find the side length of the left square

Since the area is given, we just have to square root it

√17

A leg of the formed triangle is √17 and the hypotenuse is 8

To find the last leg, we'll use the Pythagorean theorem: a² + b² = c²

(√17)² + b² = 8²

17 + b² = 64

Subtract 17 from both sides

17 + b² = 64

- 17        - 17

b² = 47

Square root both sides the isolate b

√b² = √47

b = √47

Answer:

C

Step-by-step explanation:

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Answer:

1/2

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

2 divided by 2 is 1

and 4 divided by 2 is 2

1/2

Answer:

It can

Step-by-step explanation:

For example, the GCF of 44 and 22 is 22.

The required number of cases are 11 and the number of rest units are 2.

If any number a is divided by the number b then we write a/b and find the numerical values of this fraction.

Here we have given

One case = 8 units

Also we have given 90 units

If each case can accommodate 8 units and we want to calculate the overall number of cases, we must divide the number of units (8) in each case by the total number of units (90).

As you can see, we have a total of 11 cases and a 2 unit leftover after dividing by 8.

We won't be able to fill another case with 8 units, thus the remainder will be the number of additional units.

Therefore 11 cases and rest 2 units are the answers.

This is the conclusion to the answer.

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Answer:

x=5 since if anything smaller than 0 it would be an imaginary number and would not be a real output

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

the function of f(x) = √(x – 5) + 2 will have real outputs , since √(x-5) ≥ 0

=> x - 5 ≥ 0

=> x ≥ 5

so, the input value begin from 5